Slove for p 14 = -(p - 8)

Answers

Answer 1

Solve:

[tex]\begin{gathered} 14=-(p-8) \\ -14=p-8 \\ -14+8=p \\ p=-14+8 \\ p=-6 \end{gathered}[/tex]

p=-6


Related Questions

at the casino Robert has currently lost 72$ he plays another game during which he loses 35$ find the total amount of money Robert has lost

Answers

we know that

Robert has currently lost 72$

he plays another game during which he loses 35$

to find out the total money Robert has lost, adds the amount 1 plus the amount 2

so

72+35=$107

Money in a particular savings account increases by 6% after a year. How much money will be in the account after one year if the initial amount is $125?

Answers

[tex]\begin{gathered} \text{Initial amount}\Rightarrow P=\text{ \$125} \\ \text{Rate}\Rightarrow6\text{ \%} \\ \text{Year}\Rightarrow1year \\ So\text{ the interest is } \\ I=\frac{\text{PRT}}{100} \\ I=\frac{125\times6\times1}{100} \\ I=7.5\text{ \$} \\ \text{Amount after 1 year in account} \\ \text{Amount}=P+I \\ \text{Amount}=125+7.5 \\ \text{Amount}=132.5\text{ \$} \end{gathered}[/tex]

need help assap look at file attached

Answers

Answer:

length is 27, width is 9

Step-by-step explanation:

72/4= 18

2x27+ 2x9 = 54 + 18 = 72

EFG IS dilated with scale factor of 4 to create triangle E’F’G’ the measure of angle F’ is 53 degrees what is the measurement of angle F

Answers

The measurement of ∠ F = 53 °.

Given,

Triangle EFG is dilated with a scale factor of 4 to create Δ E ' F ' G ' .

The measure of ∠ F ' is 53 °.

To find the measurement of angle F.

We know that a dilation creates similar figures i.e. it preserves the measure of angles.

Therefore,  if Triangle EFG is dilated  to form Δ E ' F ' G ', then the measure of ∠ F' = measure of ∠ F   [Corresponding angles remains same]

⇒ The measure of ∠ F' = measure of ∠ F  = 53 °

Hence, The measurement of ∠ F = 53 °.

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What are the values of n in the following equation? Select all that apply. 4n + 2 = 34

Answers

The given equation is

[tex]4x+2=34[/tex]

First, we subtract 2 from each side

[tex]\begin{gathered} 4x+2-2=34-2 \\ 4x=32 \end{gathered}[/tex]

Then, we divide the equation by 4

[tex]\begin{gathered} \frac{4x}{4}=\frac{32}{4} \\ x=8 \end{gathered}[/tex]Hence, the answer is x = 8.

Solve the system of equations using the elimination method. Note that the method of elimination may be referred to as the addition method. (If there is no solution, enter NO SOLUTION.)0.2x + 0.7y = 2.20.9x − 0.2y = 3.2(x, y) =

Answers

To solve the system of equations

[tex]\begin{gathered} 0.2x+0.7y=2.2 \\ 0.9x-0.2y=3.2 \end{gathered}[/tex]

we need to make the coefficients of one of the variables opposite, that is, they need to have the same value with different sign; let's do this with the y variable, so let's multiply the second equation by 0.7 and the first equation by 0.2; then we have:

[tex]\begin{gathered} 0.04x+0.14y=0.44 \\ 0.63x-0.14y=2.24 \end{gathered}[/tex]

Now we add the equations and solve the resulting equation for x:

[tex]\begin{gathered} 0.04x+0.14y+0.63x-0.14y=0.44+2.24 \\ 1.64x=2.68 \\ x=\frac{2.68}{0.67} \\ x=4 \end{gathered}[/tex]

Now that we have the value of x we plug it in one of the original equations and solve for y:

[tex]\begin{gathered} 0.2(4)+0.7y=2.2 \\ 0.8+0.7y=2.2 \\ 0.7y=2.2-0.8 \\ 0.7y=1.4 \\ y=\frac{1.4}{0.7} \\ y=2 \end{gathered}[/tex]

Therefore, the solution of the system of equation is (4,2)

AB has endpoint A(-3,-5) and midpoint M(2,-1).Find the coordinate (x,y) of B.

Answers

By definition, the formula to find a Midpoint is:

[tex]M=(\frac{x_1+x_2}{2}+\frac{y_2-y_1}{2})[/tex]

Where the coordinates of the first point are:

[tex](x_1,y_1)[/tex]

And the coordinates of the second point is:

[tex](x_2,y_2)[/tex]

Let be the coordinates of the Midpoint:

[tex](x_M,y_M)[/tex]

In this case, knowing coordinates of the point A and the Midpoint, you can set up the following equations:

- Equation 1:

[tex]x_M=\frac{x_A+x_B}{2}[/tex]

- Equation 2:

[tex]y_M=\frac{y_A+y_B}{2}[/tex]

Choose the Equation 1, substiutute values and solve for x-coordinate of the endpoint B:

[tex]\begin{gathered} x_M=\frac{x_A+x_B}{2} \\ \\ 2=\frac{-3+x_B}{2} \\ \\ (2)(2)=-3+x_B \\ 4+3=x_B \\ x_B=7 \end{gathered}[/tex]

Now choose the Equation 2 and solve for the y-coordinate of the point B:

[tex]\begin{gathered} y_M=\frac{y_A+y_B}{2} \\ \\ -1=\frac{-5+y_B}{2} \\ \\ (-1)(2)=-5+y_B \\ -2+5=y_B \\ y_B=3 \end{gathered}[/tex]

Therefore, the coordinates of P are:

[tex]B(7,3)[/tex]

Angel Corporation produces calculators selling for $25.99. Its unit cost is $18.95. Assuming a fixed cost of $80,960, what is the breakeven point in units?

Answers

The breakeven point is 11,500, meaning that if the sell that number of units, the profit will be zero.

How to get the breakeven point?

Here we know that the unit price is $25.99, so if they sell x units, the revenue is

R(x) = $25.99*x

And the cost per unit is $18.95, plus a fixed cost of $80,960

Then the cost of x units is:

C(x) = $80,960 + $18.95*x

The breakeven point is the value of x such that the cost is equal to the revenue, so we need to solve:

$25.99*x = $80,960 + $18.95*x

$25.99*x - $18.95*x =  $80,960

$7.04*x =  $80,960

x = $80,960/%7.04 = 11,500

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A store is having a sale to celebrate President’s Day. Every item in the store is advertised as one- fourth off the original price. If an item is marked with a sale price of , what was its original price?

Answers

If the discount is one fourth off, it means the discount is 1/4 = 25% of the original price, so the final price will be 75% or 3/4 of the original price.

In order to find the original price, we just need to divide the final price by 3/4, this way we "remove" the discount.

For example, if the sale price is $75, the original price would be:

[tex]\text{original price}=\frac{75}{\frac{3}{4}}=75\cdot\frac{4}{3}=25\cdot4=100[/tex]

So for a sale price of $75, the original price would be $100.

In general, for a discount of x%, the original price (given the sale price) can be calculated as:

[tex]\text{original price}=\frac{\text{sale price}}{1-\frac{x}{100}}[/tex]

A set of 12 data points is given above. Which of thefollowing is true of these data?

Answers

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given data

[tex]\lbrace14.9,21.1,21.2,8.4,14.5,5.9,7.6,10.0,4.8,3.2,28.7,29.5\rbrace[/tex]

STEP 2: Find the mean ofthe data

[tex]\begin{gathered} The\:arithemtic\:mean\:\left(average\right)\:is\:the\:sum\:of\:the\:values\:in\:the\:set\:divided\:by\:the\:number\:of\:elements\:in\:that\:set. \\ \mathrm{If\:our\:data\:set\:contains\:the\:values\:}a_1,\:\ldots \:,\:a_n\mathrm{\:\left(n\:elements\right)\:then\:the\:average}=\frac{1}{n}\sum _{i=1}^na_i\: \\ Sum=169.8 \\ n=12 \\ mean=\frac{169.8}{12} \\ mean=14.15 \end{gathered}[/tex]

STEP 3: Find the median

[tex]\begin{gathered} \mathrm{The\:median\:is\:the\:value\:separating\:the\:higher\:half\:of\:the\:data\:set,\:from\:the\:lower\:half.} \\ \:the\:number\:of\:terms\:is\:odd,\:then\:the\:median\:is\:the\:middle\:element\:of\:the\:sorted\:set \\ If\:the\:number\:of\:terms\:\:is\:even,\:then\:the\:median\:is\:the\:arithmetic\:mean\:of\:the\:two\:middle\:elements\:of\:the\:sorted\:set \\ \\ \mathrm{Arrange\:the\:terms\:in\:ascending\:order} \\ 3.2,\:4.8,\:5.9,\:7.6,\:8.4,\:10,\:14.5,\:14.9,\:21.1,\:21.2,\:28.7,\:29.5 \\ median=12.25 \end{gathered}[/tex]

Hence, it can be seen here that the mean is larger than median.

STEP 4: Find the Interquartile range

[tex]\begin{gathered} The\:interquartile\:range\:is\:the\:difference\:of\:the\:first\:and\:third\:quartiles \\ First\text{ Quartile}=6.75 \\ Third\text{ quartile}=21.15 \\ IQR=14.4 \end{gathered}[/tex]

STEP 5: Find the standard deviation

[tex]\begin{gathered} \mathrm{The\:standard\:deviation,\:}\sigma \left(X\right)\mathrm{,\:is\:the\:square\:root\:of\:the\:variance:\quad }\sigma \left(X\right)=\sqrt{\frac{\sum _{i=1}^n\left(x_i-\bar{x}\right)^2}{n-1}} \\ Standard\text{ deviation}=9.11836 \end{gathered}[/tex]

Hence, it can be seen from above that the interquartile range is larger than the standard deviation.

STEP 6: Find the range

[tex]\begin{gathered} \mathrm{The\:range\:of\:the\:data\:is\:the\:difference\:between\:the\:maximum\:and\:the\:minimum\:of\:the\:data\:set} \\ Minimum=3.2 \\ Maximum=29.5 \\ Range=26.3 \end{gathered}[/tex]

STEP 7: Fnd the variance

[tex]\begin{gathered} \mathrm{The\:sample\:variance\:measures\:how\:much\:the\:data\:is\:spread\:out\:in\:the\:sample.} \\ \mathrm{For\:a\:data\:set\:}x_1,\:\ldots \:,\:x_n\mathrm{\:\left(n\:elements\right)\:with\:an\:average}\:\bar{x}\mathrm{,\:}Var\left(X\right)=\sum _{i=1}^n\frac{\left(x_i-\bar{x}\right)^2}{n-1} \\ Variance=83.14454 \end{gathered}[/tex]

Hence, it can be seen that the range is not larger than the variance.

Therefore, the answer is I and II only.

Triangle MNO has its vertices at the following coordinates:M(2, 2) N(-1,3) O(1,5)Give the coordinates of the image triangle M'N'O' after a 90° counterclockwise rotation about the origin.

Answers

The counter clockwise rotation of any point X(x,y) about origin results in change of coordinates as,

[tex]X(x,y)\rightarrow X^{\prime}(-y,x)[/tex]

Determine the coordinates of the vertices of the triangle M'N'O'.

[tex]M(2,2)\rightarrow M^{\prime}(-2,2)[/tex][tex]N(-1,3)\rightarrow(-3,-1)[/tex][tex]O(1,5)\rightarrow(-5,1)[/tex]

So coordinates of triangle M'N'O' are;

M'(-2,2)

N'(-3,-1)

O'(-5,1)

a large community college has professors and lectures. total number of facility members is 228. the school reported that they had five professors for every 14 lectures. how many of each type of faculty member does the community college employee?

Answers

a large community college has professors and lectures. total number of facility members is 228. the school reported that they had five professors for every 14 lectures. how many of each type of faculty member does the community college employee? ​

Let

x -----> number of professors

y ----> number of lectures

we have that

x+y=228

x=228-y -------> equation A

x/y=5/14

x=(5/14)y ------> equation B

equate equation A and equation B

228-y=(5/14)y

solve for y

(5/14)y+y=228

(19/14)y=228

y=228*14/19

y=168

Find the value of x

x=228-168=60

therefore

number of professors is 60number of lectures is 168

For questions 5&6 find F -1(x), the inverse of F(x)

Answers

To find the inverse function, we can follow the next steps:

First Function

1. Replace x with y as follows:

[tex]y=3x+7\Rightarrow x=3y+7[/tex]

2. Solve the resulting equation for y. Subtract 7 from both sides of the equation:

[tex]x-7=3y+7-7\Rightarrow x-7=3y[/tex]

3. Divide both sides of the equation by 3:

[tex]\frac{(x-7)}{3}=\frac{3}{3}y\Rightarrow y=\frac{(x-7)}{3}=\frac{1}{3}(x-7)=\frac{x}{3}-\frac{7}{3}[/tex]Second Function

We need to repeat the process to obtain the inverse of this function:

1. Replace x with y:

[tex]y=8x\Rightarrow x=8y[/tex]

2. Solve for y. Divide both sides by 8:

[tex]\frac{x}{8}=\frac{8}{8}y\Rightarrow y=\frac{x}{8}[/tex]

In summary, we have that the inverse functions are:

For function

[tex]y=3x+7[/tex]

The inverse function is:

[tex]y=F^{-1}^{}(x)=\frac{(x-7)}{3}[/tex]

And, for the function

[tex]y=8x[/tex]

The inverse function is:

[tex]y=f^{-1}(x)=\frac{1}{8}x[/tex]

X + 2y = 3x = 5Enter your answer as a point using parenthesis and a comma. Do not use any spaces in youranswer.If there are no solutions, type "no solutions." If there are infinitely many solutions, type"infinitely many."Answer:

Answers

[tex]\begin{gathered} x+2y=3 \\ 5+2y=3 \\ 5+2y-5=3-5 \\ 2y=-2 \\ \frac{2y}{2}=-\frac{2}{2} \\ y=-1 \end{gathered}[/tex]

thats the explanation

answer is : (5, -1)

Josh's grocery bill is $56.00 and the sales tax in his state is 7% how much extra does he have to pay? I assume 125?

Answers

Given:

Josh's grocery bill is $56.00

The sales tax in his state is 7%

[tex]\begin{gathered} \text{Extra money he have to pay=56}\times\frac{7}{100} \\ \text{Extra money he have to pay=}\frac{392}{100} \\ \text{Extra money he have to pay= \$3.92} \end{gathered}[/tex]

On total Josh has to pay $59.92

Josh has to pay extra money as tax is $3.92

Subtracting algorithm

Answers

Using subtracting algorithm, we have 69,000 - 42,547 = 26,453 and 152,681 - 34,820 = 117,861.

According to the question,

We have the following expressions:

_ _ , 0 0 0

-4 2, _ _ _

_________

2 6 , 4 5 3

Now, we will first solve this.

The spaces has to be filed with the digits from 0 to 9  and in both the questions, no digit has to be repeated.

Now, we will solve it from the right hand side.

(Note that we will solve each row that is we will solve vertically.)

0 is given, then we have blank, and in result we have 3.

It is clear that no number can be subtracted from 0. So, we have to regroup it from other digits. So, it will be 10.

Now, 10-3 = 7

So, this blank will be 7.

Now, come to next one.

We have 0 and a blank and then 5 in the result.

Now, it should be 9 because 1 was taken away from it.

So, 9-5 = 4

This blank has to be filled with 4.

Now, we will solve next one.

We have 0, a blank and then 4 in the result.

Now, this 0 will make 9.

9-4 = 5

This blank has to be filled with 5.

Now, we have a blank, 2 and 6 in the result.

1 has been carried from this digit.

So, we have:

6+2+1 = 9

This blank has to be filled with 9.

Next, we have a blank, 4 and 2 in the result.

4+2 = 6

This has to be filled with 6.

Now, we will solve the second question like this.

_ 5 2, 6 8 1

-   _ 4, _ _ _

__________

    1 1 7, 8 6 1

Now, moving from right to left vertically:

We have 1, a blank and 1 in the result.

1-1 = 0

Blank = 0

We have 8, a blank and 6 in the result.

8-6 = 2

Blank = 2

We have 6, a blank and 8 in the result.

Now, 8 can not be subtracted from 6. So, it has to be 16.

16-8 = 8

Blank = 8

Now, next one is complete.

So, we have next one.

We have 5, a blank and 1 in the result.

We will subtract 1 from 4 because 1 was carried away from 5.

4-1 = 3

Blank = 3

Now, we have a blank and 1 in the result.

Blank = 1

Hence, the answers would be  69,000 - 42,547 = 26,453 and 152,681 - 34,820 = 117,861.

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Henry had a batting average of 0.341 last season (out of 1000 at-bats, he had 341 hits). Given that thisbatting average will stay the same this year, answer the following questions,What is the probabilitythat his first hit willoccur within his first 5at-bats? Answer choice. 0.654. 0.765. 0.821. 0.876

Answers

The probability of a successful batting is 0.341; we need to find the probability of at least 1 hit within the first 5 at-bats; thus,

[tex]P(Hit)=1-P(NoHit)[/tex]

Therefore, we need to calculate the probability of not hitting the ball within the first 5 at-bats.

The binomial distribution states that

[tex]\begin{gathered} P(X=k)=(nBinomialk)p^k(1-p)^{n-k} \\ n\rightarrow\text{ total number of trials} \\ k\rightarrow\text{ number of successful trials} \\ p\rightarrow\text{ probability of a successful trial} \end{gathered}[/tex]

Thus, in our case,

[tex]P(k=0)=(5Binomial0)(0.341)^0(0.659)^5=1*1*0.124287...[/tex]

Then,

[tex]P(Hit)=1-0.124287...\approx0.876[/tex]Therefore, the answer is 0.876

Select from the drop-down menus to correctly complete each statement.

The opposite of −358 is on the
Choose...
side of zero on a number line as −358. The opposite of 429is on the
Choose...
side of zero on a number line as 429.

Answers

The opposite of −3 5/8 is on the opposite side of zero on a number line as −3 5/8 . The opposite of 4 2/9 is on the opposite side of zero on a number line as 4 2/9 .

What is a number line?

A number line is a type of graph with a graduated straight line which contains both positive and negative numbers that are typically placed at equal intervals along its length.

What are opposites?

In Mathematics, opposites simply refers to numbers that are located on opposite sides of zero (0) on any number line. Additionally, opposites generally have the same distance from zero (0) on any given number line.

In conclusion, -3 5/8 is a number that is located on the opposite side of zero (0) on a number line while 4 2/9 is a number that is also located on the opposite side of zero (0) on a number line.

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Complete Question:

Select from the drop-down menus to correctly complete each statement. The opposite of −3 5/8 is on the ______ side of zero on a number line as −3 5/8 . The opposite of 4 2/9 is on the ______ side of zero on a number line as 4 2/9 .

What is the equation of the line that passes through points (1,-19) and (-2,-7)?

Answers

This problem is about linear equations. We need to find the equation of the line w

What is the reference angle for 289°? A. 71° B. 19° C. 11° D. 89°

Answers

Given:

Angle θ=289°.

For angles from 270° to 360°, the reference angle can be calculated by subtracting the given angle from 360° .

The reference angle of θ can be calculated as:

[tex]\begin{gathered} 360\degree-\theta=360\degree-289\degree \\ =71\degree \end{gathered}[/tex]

Therefore, reference angle of 289° is 71°.

Devonte is growing a rose. Today the rose is 5 cm high. The rose grow$ 1.5 cm per day. Write a linear equation that represents the helght of the rose (y) after (2) days. How tall will the rose be after 20 days?

Answers

The equation of a line in slope-intercept form, is:

[tex]y=mx+b[/tex]

Where m represents the slope of the line (rate of change), and b represents the y-intercept of the line (initial value).

Since the rose grows 1.5 cm per day, then the rate of change is 1.5:

[tex]m=1.5[/tex]

Since today the rose is 5cm high, then the initial value is 5:

[tex]b=5[/tex]

Then, the height of the rose after x days is:

[tex]y=1.5x+5[/tex]

To find the height of the rose after 20 days, substitute x=20:

[tex]\begin{gathered} y=1.5(20)+5 \\ =30+5 \\ =35 \end{gathered}[/tex]

Then, the height of the rose after 20 days is 35 cm.

Draw a graph, and label and scale both axes. Plot the points (-2, 3) and (1, -5), clearly labeling them.

Answers

Answer:

Explanation:

First, we draw the graph, label the x and y-axis. Then we plot the points given.

To plot the point (-2, 3), we first move to units to the left from the origin and the 3 units up as sketched below

Similarly for (1, -5), we have

We moved one unit to the right and 5 units down.

To find the slope, we take the vertical distance and the horizontal distance and then the slope will be

slope vertical distance / horizontal distance

Therefore the slope is

[tex]Slope=-\frac{8}{3}[/tex]

need help with this problem, find the length of the darkened arc. C is the center of the circle

Answers

Notice that the central angle measures 138 degrees, We have a property of the circle that says that the measure of a central angle is equal to the arc between its sides.

Therefore, the arc measures 138 degrees

Find S13 of the arithmetic sequence below.
1/4, 1/2, 3/4, 1, …

Answers

Sum of arithmetic progression is given as 91/4

What is arithmetic progression?

An arithmetic sequence or progression is defined as a sequence of numbers in which for every pair of consecutive terms, the second number is obtained by adding a fixed number to the first one.

What is Sum of arithmetic progression?

The sum of the first n terms can be calculated if the first term, common difference and the total terms are known. The formula for the arithmetic progression sum is explained below:

Consider an AP consisting “n” terms.

Sn = n/2[2a + (n − 1) × d]

Given, a = 1/4, n = 13

d = 1/2-1/4 = 1/4

formula for sum is given by

Sn = n/2[2a+(n-1)d]

Substitute the values, we get

S13 = 13/2[2(1/4)+12(1/4)]

=13/2(1/2+3)

=13/2(7/2)

=91/4

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1. A jar contains 5 red marbles numbered 1 to 5 and 6 blue marbles numbered 1 to 6. A marble is drawn at random from the jar. Find the probability that the marble is blue or odd-numbered.

Answers

We will use the following formula:

[tex]P(A\cup B)=P(A)+P(B)-P(A\cap B).[/tex]

First, we compute the probability that we get a blue marble:

[tex]P(\text{Blue)}=\frac{6}{5+6}=\frac{6}{11}\text{.}[/tex]

Now, we compute the probability of getting an odd-numbered marble:

[tex]P(\text{odd-num)}=\frac{6}{11}\text{.}[/tex]

Finally, the probability that we draw a blue and odd-numbered marble is:

[tex]P(\text{blue and odd)=}\frac{3}{11}.[/tex]

Answer: The probability that the marble is blue or odd-numbered is:

[tex]\begin{gathered} P(\text{blue or odd)=P(blue)+P(odd-num)-P(blue and odd)=}\frac{6}{11}+\frac{6}{11}-\frac{3}{11}=\frac{9}{11}. \\ P(\text{blue or odd)}=\frac{9}{11}\text{.} \end{gathered}[/tex]

1. A table is 2 feet wide. It is 6 times as long as it is wide. Table= A-Label the diagram with the dimensions of the table.B-find the perimeter of the table

Answers

Width(w) = 2 feet

Length (L)= 6w = 6(2) = 12 feet

a. Table = 2 x 12

b: Perimeter of a rectangle:

P = 2w+ 2L = 2(2)+2(12) = 4+24 = 28 feet

Solve equation for x. 5x^2 - 4x =6

Answers

Answer:

Step-by-step explanation:

use the quadratic formula

5x^2-4x-6

4+-[tex]\sqrt{16+120}[/tex] all over 10

4+-[tex]2\sqrt{34}[/tex]/10

2+-[tex]\sqrt{34}[/tex]/5

D

find 2x:3y if x:y = 2:5

Answers

4 : 15

Explanation:[tex]\begin{gathered} \text{x : y = 2: 5} \\ \frac{x}{y}\text{ = }\frac{2}{5} \\ \\ 2x\text{ : 3y = ?} \end{gathered}[/tex][tex]\begin{gathered} 2x\colon\text{ 3y = }\frac{2x}{3y} \\ 2x\colon3y\text{ = }\frac{2}{3}\times\frac{x}{y} \end{gathered}[/tex][tex]\begin{gathered} \text{substitute for x/y in 2x:3y} \\ \frac{2}{3}\times\frac{x}{y}\text{ =}\frac{2}{3}\times\frac{2}{5} \\ =\text{ }\frac{4}{15} \\ \\ \text{Hence, 2x:3y = }\frac{4}{15} \\ or \\ 4\colon15 \end{gathered}[/tex]

For each ordered pair, determine whether it is a solution to 4x - 5y = -13.Is it a solution?x$(x, y)YesNo(-7, -3)(3, -4)OO(-2, 1)oO(6, 7)0

Answers

The equation is 4x - 5y = -13.

Substitute -7 for x and -3 for y in the equation to check whether ordered pair is solution of the equation.

[tex]\begin{gathered} 4\cdot(-7)-5\cdot(-3)=-13 \\ -28+15=-13 \\ -13=-13 \end{gathered}[/tex]

The ordered pair satisfy the equation so point (-7,-3) is solution of equation.

Substitute 3 for x and -4 for y in the equation to check whether ordered pair is solution of the equation.

[tex]\begin{gathered} 4\cdot3-5\cdot(-4)=-13 \\ 12+20=-13 \\ 32\ne-13 \end{gathered}[/tex]

The ordered pair not satisfy the equation. So point (3,-4) is not a solution of the equation.

Substitute -2 for x and 1 for y in the equation to check whether ordered pair is solution of the equation.

[tex]\begin{gathered} 4\cdot(-2)-5\cdot1=-13 \\ -8-5=-13 \\ -13=-13 \end{gathered}[/tex]

The ordered pair satisfy the equation. So point (-2,1) is solution of equation.

Substitute 6 for x and 7 for y in the equation to check whether ordered pair is solution of the equation.

[tex]\begin{gathered} 4\cdot6-5\cdot7=-13 \\ 24-35=-13 \\ -11\ne-13 \end{gathered}[/tex]

The orderedpair not satisfy the equation. So point (6,7) is not a solution of the equation.

PLEASE HELP: Which of the following are identities? Check all that apply. A. (sin x + cos x)^2 = 1 + sin 2x B. sin 3x - sinx/ cos3x + cosx = tan xC. sin 6x = 2 sin3x cos3x D. sin 3x/sin x cos x = 4 cos x - sec x

Answers

Answer:

All the options are correct

Explanations:

A quick and smart way is to substitute a value for x in each of the options and verify if the right hand side equals the left hand side

Let x = 30

A) (sin x + cos x)² = 1 + sin 2x

(sin 30 + cos 30)² = 1.866

1 + sin 2(30) = 1.866

Therefore (sin x + cos x)² = 1 + sin 2x

B)

[tex]\begin{gathered} \frac{\sin3x-\sin x}{\cos3x+\cos x}=\tan x \\ \frac{\sin3(30)-\sin30}{\cos3(30)+\cos30}=0.577 \\ \tan \text{ 30 = 0.577} \end{gathered}[/tex]

Therefore:

[tex]\frac{\sin3x-\sin x}{\cos3x+\cos x}=\tan x[/tex]

C) sin 6x = 2 sin3x cos3x

sin 6(30) = 0

2 sin3(30) cos3(30) = 0

Therefore sin 6x = 2 sin3x cos3x

This can also be justified by sin2A = 2sinAcosA

D.

[tex]\frac{\sin3x}{\sin x\cos x}=\text{ 4}\cos x-\sec x[/tex][tex]\begin{gathered} \frac{\sin 3(30)}{\sin 30\cos 30}=\text{ 2.31} \\ 4\cos 30-\sec 30=\text{ }2.31 \end{gathered}[/tex]

Options A to D are correct

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