.
Fill in the blanks to find the difference in the expressions.
-2x+5
8
A
A x2+
С
X
B x +
11
x +4
X +3
x2 + 7x +
D

Step-by-step explanation:

The graphs are not give but the graph looks like the above picture.

The cost per page is $1.5 and 38 pages of the book will cost $57

Data;

To solve this question, we have to know the cost of one page of the book.

In the first scenario, 20 pages cost $30, let's find the cost of one page here.

[tex]20 page = \$30\\1 page = x\\x = \frac{30}{20}\\x = 1.5[/tex]

We can confirm our answer here by testing with the second scenario;

[tex]32 page = \$48\\1page = y\\y = \frac{48}{32} = 1.5[/tex]

Now can say that one page of the book cost $1.5, let's divide 57 by this to determine the number of pages

[tex]z = \frac{57}{1.5} \\z = 38[/tex]

From the calculations above, 38 pages of the book will cost $57.

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B is the right answer

I hope it will help you

Answer:

For 3 pounds, 3 ÷ 1/8 = 54

For 7 pounds, 7 ÷ 1/8 = 56

Answer:

The answer is 4x² – x – 4 = 0

Step-by-step explanation:

Where,

So, one quadratic polynomial satisfying is given condition is 4x² – x – 4 = 0

Sum of zeroes = 1/4

Product of zeros = 1

Remember this formula

x² – (α + β)x + αβ

x² – 1/4x + 1

4x² – x – 4 = 0

Thus, The quadratic polynomial is

4x² – x – 4 = 0.

The union of X and Y is {a,e,i,o,u}, the intersection of X and Z is {i,o} and the intersection of all the three is {o}.

The ordered pair is the pair of two numbers which represented in a manner that it provides a particular order.

In an order pair, the first term indicates the x-coordinate, while the second term indicate the y coordinates. The ordered pair are written in close bracket in the following way.

[tex](x,y)[/tex]

The given set is U(a,e,i,o,u), in which,

[tex]X=(a,i,o)\\Y=(o,e,u)\\Z=(i,o,u)[/tex]

For the union, write all the terms of  X and Y set.

[tex]X\cup Y=(a,e,i,o,u)[/tex]

For the intersection, write all the common terms of  X and Z set.

[tex]X\cap Z=(i,o)[/tex]

For the intersection, write all the common terms of  X , Y and Z set.

[tex]X\cap Y\cap Z=(o)[/tex]

Hence, the union of X and Y is {a,e,i,o,u}, the intersection of X and Z is {i,o} and the intersection of all the three is {o}.

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Step-by-step explanation:

Jacinta is completely right while Tess made a mistake on the 3rd step.

she mistakenly plugged in the y value as X, and plugged in the X value as y.

so Tess is incorrect

Answer:

See attached image.

Step-by-step explanation:

Answer:

[tex]\sf y=-\dfrac12x+2[/tex]

Step-by-step explanation:

y-intercept is when x = 0, so (0, 2)

x-intercept is when y = 0, so (4, 0)

[tex]\sf slope=\dfrac{change\:in\:y}{change\:in\:x}=\dfrac{0-2}{4-0}=-\dfrac12[/tex]

Slope-intercept form of linear equation:  [tex]\sf y=mx+b[/tex]

(where m is the slope and b is the y-intercept)

Given:

[tex]\sf \implies y=-\dfrac12x+2[/tex]

Answer:

  30°

Step-by-step explanation:

The angle sum theorem tells you the sum of angles in any triangle is 180°. A right triangle has one angle that is 90°, so the sum of the remaining two acute angles is 180° -90° = 90°. That is, the acute angles in a right triangle are complementary.

__

The other acute angle is ...

  90° -60° = 30°

The equation y = |x-3| + |x+2| - |x-5| is an absolute value equation

The equivalent equation of y = |x-3| + |x+2| - |x-5|  if -2 < x < 3 is y = x

The equation is given as:

y = |x-3| + |x+2| - |x-5|

The condition is given as:

if -2 < x < 3

Split and solve each term of the absolute value equation.

|x-3| = -(x - 3) = 3 - x....... because x < 3

|x+2| = x + 2 because -2 < x

|x-5| = -(x - 5) = 5 - x....... because x < 5

So, we have:

y = |x-3| + |x+2| - |x-5|

This gives

y = (3 - x) + (x + 2) - (5 - x)

Open the brackets

y = 3 - x + x + 2 - 5 + x

Evaluate the like terms

y = x

Hence, the equivalent equation of y = |x-3| + |x+2| - |x-5|  if -2 < x < 3 is y = x

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7 3/4 pounds contains 124 ounces

8 ounces = 0.5 pound

X ounces = 1 pound

X = 8 / 0.5 = 16 ounces

7 3/4 = 7.75

7.75 contains = 7.75 * 16

= 124 ounces

There are 3 odd numbers on the die so the theoretical probably of getting odd is 3/6 = 1/2

Samantha that rolled the die 4 times and got odd every time so her experimental probability was 4/4 = 1

Jeanie rolled the die 16 times and got 6 odds for an experimental probability of 6/16 = 3/8

3/8 is closer to 1/2

Answer: C. Jeanie’s

Step-by-step explanation:

\begin{gathered}x^2 + y^2 + 17 = 138\\x^2 + y^2 = 138 - 17\\x^2 + y^2 = 121\\x^2 + y^2 = 11^2\\Radius = 11\end{gathered}

x

2

+y

2

+17=138

x

2

+y

2

=138−17

x

2

+y

2

=121

x

2

+y

2

=11

2

Radius=11

Answer:

1

Step-by-step explanation:

65.751 = 6 x 10 + 5 x 1 + 7 x 1/10 + 5 x 1/100 + 1 x 1/1,000

6 x 10 = 60

5 x 1 = 5

7 x 1/10 = 0.7

5 x 1/100 = 0.05

1 x 1/1000 = 0.001

60 + 5 + 0.7 + 0.05 + 0.001 = 65.751

(0,3) - The y-int, after you can just add 5 to the y-coord for each added 1 to the x-coord.

(1,8)

(2,13)

(3,18)

(4,23)

(5,28)

Answer:

Step-by-step explanation:

red shirt: 10%

green shirt: 20%

not choosing white 10%

not chosing black 20%

where orange shirt???

Answer:

208.3

Step-by-step explanation:

Since the numbers are decreasing as multiples, its a geometric progression.

[tex]S_{n}=\frac{a(1-r^{n} )}{1-r} ; r\neq 1 \ and\ r \ is\ less\ than\ 1\\common\ ratio=\frac{20}{50}=\frac{2}{5}\\ S_{10}=\frac{125(1-(2/5)^{10} )}{1-(2/5)} \\=208.3[/tex]

Answer: median: 5

mode: 5.4

Range: 9

Step-by-step explanation:

Median: middle of the numbers

Mode: Add them all together and divide by number of terms

Range: Most minus least

This is made easy if you know the Laplace transform pair

[tex]u(t - c) y(t - c) \mapsto e^{-cs} Y(s)[/tex]

where u(t) is the Heaviside step function and Y(s) is the Laplace transform of y(t).

We rewrite f, g, and h in terms of u :

[tex]f(x) = (x^2+2x+1) (u(x) - u(x-3)) + e^{-5x} u(x-3)[/tex]

[tex]g(x) = \sin(3x) (u(x-5) - u(x-10))[/tex]

[tex]h(x) = (u(x) - u(x-4)) + 2(u(x-4)-u(x-8)) + 3 (u(x-8)-u(x-16))[/tex]

and we also rearrange terms to get the right shift in argument:

[tex]f(x) = (x^2+2x+1) u(x) - ((x-3)^2+8(x-3)+16) u(x-3) + e^{-15} e^{-5(x-3)} u(x-3)[/tex]

[tex]g(x) = [\cos(15) \sin(3(x-5)) + \sin(15) \cos(3(x-5))] u(x-5) \\\\ ~~~~~~~~~~- [\cos(30) \sin(3(x-10)) + \sin(30) \cos(3(x-10))] u(x - 10)[/tex]

[tex]h(x) = u(x) + u(x-4) + u(x-8) - 3 u(x - 16)[/tex]

Now we can apply the known transform pair, along with

[tex]x^n \mapsto \dfrac{n!}{s^{n+1}}[/tex]

[tex]e^{ax} \mapsto \dfrac1{s-a}[/tex]

[tex]\sin(ax) \mapsto \dfrac{a}{s^2+a^2}[/tex]

[tex]\cos(ax) \mapsto \dfrac{s}{s^2+a^2}[/tex]

The transforms of f, g, and h are then

[tex]F(s) = e^{-s} \left(\dfrac2{s^3} + \dfrac2{s^2} + \dfrac1s\right) - e^{-3s} \left(\dfrac2{s^3} + \dfrac8{s^2} + \dfrac{16}s\right) + \dfrac{e^{-15} e^{-3s}}{s + 5} \\\\ = \boxed{e^{-s} \left(\dfrac2{s^3} + \dfrac2{s^2} + \dfrac1s\right) - e^{-3s} \left(\dfrac2{s^3} + \dfrac8{s^2} + \dfrac{16}s\right) + \dfrac{e^{-3(s+5)}}{s + 5}}[/tex]

[tex]G(s) = \dfrac{3\cos(15) e^{-5s}}{s^2+9} + \dfrac{s \sin(15) e^{-5s}}{s^2+9} - \dfrac{3\cos(30)e^{-10s}}{s^2+9} - \dfrac{s \sin(30) e^{-10s}}{s^2+9} \\\\ ~~~~~~~ = \dfrac{3(\cos(15)-\cos(30)) + s(\sin(15) - \sin(30))}{s^2+9} \\\\ ~~~~~~~ = \boxed{\dfrac{6\sin\left(\frac{45}2\right)\sin\left(\frac{15}2\right) - 2s \cos\left(\frac{45}2\right)\sin\left(\frac{15}2\right)}{s^2+9}}[/tex]

[tex]H(s) = \boxed{\dfrac{e^{-s} + e^{-4s} + e^{-8s} - 3 e^{-16s}}s}[/tex]

Answer:  0.2066

Step-by-step explanation:

Probability of Rebecka selecting a poodle = 5/11

Probability of Aaron selecting a poodle = 5/11

Both select one puppy at random with replacement, so their choices are independent.

Thus, probability that both select a poodle = [tex](5/11)\times(5/11)[/tex]

[tex]= 25/121 \approx 0.2066 \ $or 20.66\%[/tex]

The frequency distribution table shows the distribution of the rice consumed by the families

From the question, we have the interval to be:

Interval = 6

Start by calculating the range

Range = Highest - Least

This gives

Range = 60 - 20

Range = 40

Calculate the class width

Width = Range/Interval

This gives

Width = 40/6

Width = 7

So, the classes are: 20 - 26, 27 - 33, 34 - 40, 41 - 47, 48 - 54 and 55 - 61

Using the above classes, we have the following frequency distribution table.

Class Frequency

20 - 26 6

27 - 33 3

34 - 40 7

41 - 47 4

48 - 54 3

55 - 61 4

From the above Frequency Distribution Table, the interval with the highest frequency is 34 - 40

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Answer:

Step-by-step explanation:

Drinks:

Answer: 8

Answer: hii

There are no values of x

that make the equation true.

Step-by-step explanation:

No solution.

hopefully this helps you.

- Matthew

Answer:

We need the line plot in order to solve the questions.

Step-by-step explanation:

Answer:

  see attached

Step-by-step explanation:

An amortization schedule is conveniently prepared using a spreadsheet. It has the formula built in for computing the payment value.

__

The amount of the payment going to interest is the product of the outstanding balance and the monthly interest rate (=6%/12). In the attached, the amount of interest due is rounded to cents. The remaining amount of the payment reduces the outstanding balance.

The attachment shows the payment calculation and the amortization schedule for the first 5 payments.

Answer: cone

Step-by-step explanation:

The bottom figure is a cylinder. A cylinder is basically a rectangle wrapped around two circles.

The top figure is a cone. A cone’s net looks like a triangle with a curved base wrapped around a circle. If you don’t believe the top figure is a cone, think about what ice cream cones look like. The top figure is a cone.

The expression 3.25(g-1) + 2.75(3) by Jason and his friends is a linear expression

The expression is given as:

3.25(g-1) + 2.75(3)

The above expression means that:

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