A. The sun has enough mass to attract the planets. is the correct statement for the given question.
What are planets?A planet is a celestial body that revolves in an orbit around the Sun, planet has sufficient mass for self-gravity to overcome rigid body forces. It has space around its orbit to revolve around the sun. A gas Giant is a planet composed mainly of gas. Super-Earth is a rocky planet that is larger than Earth.
Neptune-like planets that are about the size of Neptune. A terrestrial is a rocky world that is outside our solar system. The basic reason the planets revolve around the Sun is the gravity of the Sun that keeps them in their orbits. As the Moon orbits the Earth because of the Earth's gravitational pull and the Earth orbits the Sun because of the Sun's gravitational pull.
So we can conclude that the planets orbit the Sun because the sun has enough mass to attract the planets.
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a 80.0 kg ice hockey player hits a 0.150 kg puck, giving the puck a velocity of 47.0 m/s. if both are initially at rest and if the ice is frictionless, how far (in m) does the player recoil in the time it takes the puck to reach the goal 18.0 m away?
As a result of the law of conservation of momentum, the man will recoil as far as 0.034 m.
The law of conservation of momentum:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Where:
u₁ , u₂ = initial velocity of object 1 and object 2
v₁ , v₂ = final velocity of object 1 and object 2
Since both the player and the puck are initially at rest, hence u₁ = 0, u₂ = 0.
Therefore,
m₁v₁ + m₂v₂ = 0
Parameters given:
m₁ = 80 kg
m₂ = 0.150 kg
v₂ = 47 m/s
Plug the parameters into the equation,
80 . v₁ + 0.15 . 47 = 0
v₁ = - 0.088 m/s
Time the puck reach 18 m goal:
t = distance / velocity = 18 / 47 = 0.38 s
The player will recoil:
distance = velocity x t = 0.088 x 0.38 = 0.034 m = 3.4 cm
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supppose object a has double the specific heat and triple the mass of object b. if the same amount of heat is applied to both objects, how will the temperature changes of a be related to the temperature change of b?
The given problem is related to the calorimetry. The definition of calorimetry states that, "Calorimetry is the science of determining the change in energy of a system by measuring the heat exchange of the system with the surroundings". According to this, the temperature change of A will be one sixth of the temperature change of B. Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
So, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
Temperature change of A related to the temperature change of B
In this case, for object A:
QA = cA× mA× (ΔT)A
and for object B:
QB = cB× mB× (ΔT)B
You know:
Object A has double the specific heat of object B. ⇒ cA= 2× cB
Object A has triple the mass of object B. ⇒ mA= 3× mB
If the same amount of heat is applied to both objects ⇒ QA= QB
Then:
cA× mA× (ΔT)A= QB = cB× mB× (ΔT)B
2× cB × 3× mB× (ΔT)A= cB× mB× (ΔT)B
Solving:
6× cB × mB× (ΔT)A= cB× mB× (ΔT)B
(ΔT)A= (cB× mB× (ΔT)B) ÷ (6× cB × mB)
(ΔT)A= (ΔT)B
Finally, the temperature change of A will be one sixth of the temperature change of B.
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A student learns that a certain comet in the solar system is considered a short-period comet. Based on this knowledge, what is the student most justified in concluding?.
Based on this knowledge,he is most justified in concluding that the originates between the Sun and the asteroid belt.
Comets are frozen leftovers from the formation of the solar system composed of dust, rock, and ices. They variety from a few miles to tens of miles wide, however as they orbit in the direction of the sun, they warmth up and spew gases and dirt right into a sparkling head that can be large than a planet. This cloth bureaucracy a tail that stretches thousands and thousands of miles.
Asteroids lack the magnetic area and atmosphere that shield us on earth from harm. Living internal an asteroid is one way to defend your self from harmful radiation, it is expected that by tunneling 100 meters deep beneath an asteroid, people would be sufficiently shielded from radiation.
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A horizontal rope is attached from a truck to a 1475-kg car. As the truck tows the car on a horizontal straight road, the rope will break if the tension is greater than 2551 N. Ignoring friction, what is the maximum possible acceleration of the truck if the rope does not break?
Given data
*The given mass of the car is m = 1475 kg
*The maximum tension is T = 2551 N
The formula for the maximum possible acceleration of the truck is given by Newton's second law as
[tex]\begin{gathered} T=ma_{\max } \\ a_{\max }=\frac{T}{m} \end{gathered}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} a_{\max }=\frac{2551}{1475} \\ =1.72m/s^2 \end{gathered}[/tex]Hence, the maximum possible acceleration of the truck is a_max = 1.72 m/s^2
a car is traveling at on a horizontal highway. if the coefficient of kinetic friction between road and tires on a rainy day is , what is the minimum distance (in m) in which the car will stop?
The minimum distance in which car will stop is 256m.
What is distance?
distance is the length of the space between two points.
distance is a numerical or its the occasionally qualitative measurement of how to far apart objects or points .
Sol-here we can apply Newton’s second law to the car of to determine of the maximum static friction to the force acting on the car:
€Fy=ma^y+ n-mg=0
Fs≤us mg
This maximum magnitude of static friction acts so long as the tires roll without skidding.
€Fx=ma^x-----> -fs=ma
The maximum acceleration is
a=-u^s g
The initial and final conditions are- xi=0, vi=50.0mi/h =22.4 m/s and vf =0.Then,
v^2=v^2+2a(xf-xi)---->v^2
f i I
Xf=(22.4m/s)^2/2(0.100)(9.80m/s^2)=256
Thus through the minimum distance in which car will stop is 256m.
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alex throws a 0.25-kg rubber ball down onto the floor. the ball's speed just before impact is 4.5 m/s, and just after is 2.9 m/s. what is the change in the magnitude of the ball's momentum?
If Alex throws a 0.25-kg rubber ball down onto the floor, the ball's speed just before impact is 4.5 m/s, and just after is 2.9 m/s.The change in the magnitude of the ball's momentum is 1.85 [tex]kg \frac{m}{s}[/tex]
Calculation
Change in momentum= [tex]mv_{1} -mv_{2}[/tex]
where, m is mass of the object, m= 0.25 kg
[tex]v_{1}[/tex] is velocity before collision, [tex]v_{1}[/tex] = 4.5 m/s
[tex]v_{2}[/tex] is velocity after collision, [tex]v_{2}[/tex] = 2.9 m/s
therefore, [tex]mv_{1} -mv_{2} =m(v_{1}-v_{2} )[/tex]
⇒0.25(4.5-(-2.9)) = 0.25(4.5 + 2.9) = 0.25* 2.4
= 1.85 [tex]kg\frac{m}{s}[/tex]
What is momentum?The definition of momentum is "mass in motion." Since every item has mass, if it is moving, it must have momentum because its mass is in motion. The amount of motion and the speed of the motion are the two factors that determine how much momentum an item possesses. The factors mass and velocity affect momentum. According to an equation, an object's momentum is determined by multiplying its mass by its velocity.Momentum = mass * velocityMass times velocity would be the units for momentum. The kg*m/s is the common metric unit for momentum.To learn more about momentum, refer to https://brainly.com/question/402617
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you press a book perpendicularly against a vertical wall with a force of 27 n . the coefficient of static friction is 0.70 between your hand and the book and 0.50 between the book and the wall. what is the maximum book mass you can hold this way and keep from slipping?
1.926kg is the maximum book mass you can hold this way and keep from slipping.
This book with 27 N, so Normal rection force N = 27N.
let mass of brook = m Kg
here gravitational force acting downwards which tend book to more downwards and frictional force moving is acting vertically upwards to held
frictional force a must be equal to gravitational force here frictional force
fr = μN
so for body to be rest fr = mg
μN = mx 9.81
m = μN / 9.81
here maximum value of coefficient static friction μ = 0.70
m = 0.70x 27/9.81
m = 1.926kg
What is frictional force?
Friction is the force that opposes motion when the surface of one object comes into contact with the surface of another. The mechanical advantage of the machine is reduced by friction, in other words, the ratio of power to input decreases due to friction. A car uses a quarter of its energy to limit friction. However, the friction of the tires also allows the car to stay on the road, and the friction of the clutch allows it to drive. From matches to machines and molecular structures, friction is one of the most important phenomena in the physical world.
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A bus traveling at a speed of 50 km/h has a momentum of 180,345
kg.m/s. What is the mass of the bus?
The mass of the truck is 12,974.4kg .
Describe bulk in plain terms.As a measure of inertia, which is a fundamental characteristic of all matter, mass is used in physics. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force.
An object's mass is what?Measures a substance's resistance to acceleration in physics. A measure of an object's mass is roughly equivalent to counting the atoms that make up the object. The kilogram serves as the fundamental mass unit. Mass multiplied by the gravitational acceleration equals weight.
50km/h =50×5/18 m/s= 13.88 = 13.9
momentum (p)=180,345 kg.m/s
P=mv
180,345= m X 13.9
m = 180345/13.9
m = 12,974.46
m = 12,974.4
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7. Using Analogies Explain how the behavior
of popcorn in a popcorn popper can be used
as an analogy for the motion of gas particles.
The relative motion of gaseous particles increases with increase in the temperature of the gas molecules just like the motion of popcorn in a popper increases when heat is applied to the popper.
What is kinetic theory of gas?The kinetic theory of gases or matter states that matter consists of tiny particles which are constant motion, colliding with one another and with walls of the containing vessels.
Just like a popcorn in a popcorn popper pops when heat is applied to the popper, gases contained in a cylinder increases their speed when they acquire more kinetic energy as the temperature of the cylinder increases.
Thus, the motion of gas particles depends on the temperature of the containing vessel so also does the random motion of popcorn depends on the temperature of the popper.
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a lighthouse is located on a small island 4 km away from the nearest point p on a straight shoreline and its light makes two revolutions per minute. how fast is the beam of light moving along the shoreline when it is 1 km from p? (round your answer to one decimal place.)
The speed of the beam of light moving along the shoreline when it is 1 km from p 62.83 km/min revolution.
A revolution is the motion of 1 object around a center or some other object, a forceful overthrow of a government by using the people, or any sudden or grand trade. An example of revolution is the movement of the earth around the solar.
dθ/dt = 3 rev/min
= 3×2π = 6π rad/min
tanθ = x/3
[tex]\frac{d}{dt}[/tex] tanθ = [tex]\frac{d}{dt}[/tex] (x/3)
sec²θ dθ/dt = 1/3 dx/dt
dx/dt = 3sec²θdθ/dt
At x = 1km; tanθ =x/3 =1/3
sec²θ = 1 + tan²θ = 1+(1/3)²
sec²θ =10/9
dx/dt = 3sec²θ dθ/dt
dx/dt = 3×10/9×6π
dx/dt = 62.83 km/min
Hence, the beam of light along the shoreline when it is 1 km away from point P is 62.83 km/min
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From the bob’s frame while it is in uniform circular motion what is the direction and magnitude of the inertial force it feels?.
Radially outward is both the direction and magnitude of the inertial force. as it is moving uniformly in a circle, from the bob's frame. Radially emanating from the source of the charge is an electric field that is positively charged.
Radially outward means This is so because an electric field is produced when a positive charge is forced by the field. The electric field pulls the positive charge with a force that is directed away from the charge's origin. It is called Radially outward.
In physics, magnitude is referred to as an object's maximal size and direction. Both vector and scalar values use magnitude as a common factor. We know that scalar quantities are those that have magnitude and nothing else by definition.
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024 (part 1 of 3) 10.0 points
A 4.0 kg block is pushed 1.0 m at a constant
velocity up a vertical wall by a constant force
applied at an angle of 30.0
◦ with the horizontal, as shown in the figure.
The acceleration of gravity is 9.81 m/s
2
.
1 m
30◦
4 kg
F
Drawing not to scale.
If the coefficient of kinetic friction between
the block and the wall is 0.40, find
a) the work done by the force on the block.
Answer in units of J.
The work done on the force on the block is 23.516J
We are given that,
The mass of the block = m= 4.0 kg
The vertical component of the wall at an angle = sinθ = sin 30°
The horizontal component of the wall at an angle = cosθ = cos30°
The acceleration due to gravity = g = 9.81 m/s²
The coefficient of kinetic friction between the block and the wall= μ=0.40
So that to calculate the work done by the force on the block can be given by the expression, for vertical and horizontal component
Wf = Fycosθ
The Wf is the work done by the force Fy (on y-axis) on the block by the horizontal component,
Wf = Fxsinθ
The Wf is the work done by the force Fx (on x-axis) on the block by the vertical component,
Net Fy = sinθ N -mg =0
Net Fx = 0
Therefore, the work done by the force on the block can be assumed by above equations,
Wf = (mgdsinθ)/(sinθ - μcosθ)
Wf = (4.0kg)(1.0m)(9.81m/s²)/sin30° -(0.40)cos30°
Wf = 33.981/1.445 J
Wf = 23.516J
Thus , the work done by the force on the block would be 23.516J
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6. Force is being applied to a rotating disk at an angle of 90 degrees to itsradial line. How does the torque change if...
Torque Formula:
T = d * F * sin angle
a) if the force is doubled, torque is doubled ( directly proportional)
For example, if force is 2 N, and distance is 2 m ,
T= 2*2* sin 90 = 4 Nm
If force is doubled:
T= 2*4 * sin90 = 8 Nm
b) If the distance of the center of rotation is doubled , Torque is also doubled ( same as "a")
c) If angle decreases 45° (90 - 45 = 45 )
T= 2*2*sin45 = 2.82 Nm
Torque also decreases
lighting produces a maximum air temperature of the order of 104 k, whereas a nuclear explosion produces the temperature of the order of 107 k. find at what wavelength the radiation from these sources is maximal.
At wavelength 2.898 x 10^-7 m radiation is maximum in UV region and at wavelength 2.898x 10^-10 meter in X ray region.
What is wavelength and at what wavelength the radiation from these sources is maximal?Wavelength is the measure of distance or the length of given material either in a vaccum or a medium.Now this question is asking about wavelength of the randiation from the sources.Given is the temperatures of lightning and nuclear explosion be 104K, and 107 K respectively.Applying weins displacemnt law lambda=b/T we will get the value as 2.898 x 10^-7 and 2.898 x 10^-10 meters respectively to be the wavelength.To know more about wavelength visit:
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If the mass of a system is halved (m’=m/2) and the net force acting on it is doubled (F’=2F), then its acceleration would be:* 7 points unchanged (x1) halved (x0.5) quartered (x0.25) doubled (x2) quadrupled (x4)
Given:
The mass of the system is m' =m/2
The net force acting on it is F' = 2F
To find the acceleration.
Explanation:
The acceleration will be
[tex]\begin{gathered} a^{\prime}=\frac{F^{\prime}}{m^{\prime}} \\ =\frac{2F}{\frac{m}{2}} \\ =\frac{4F}{m} \\ a^{\prime}=4a \end{gathered}[/tex]Thus, the acceleration would be quadrupled(x4).
Please help me quickly
g an angry rhino with a mass of 3000 kg charges directly toward you with a speed of 5.00 m/s. before you start running, as a distraction, you throw a 0.180 kg rubber ball directly at the rhino with a speed of 6.89 m/s. determine the speed of the ball (in m/s) after it bounces back elastically toward you.
Answer:
Duck to avoid the ball and dodge the rhino’s attack and then try and climb the nearest tree. Hope that helps.
Explanation:
For me I’d say it’d be instinct for the answer.
a swan on a lake gets airborne by flapping its wings and running on top of the water. (a) if the swan must reach a velocity of 5.80 m/s to take off and it accelerates from rest at an average rate of 0.305 m/s2, how far (in m) will it travel before becoming airborne?
The swan will travel 55.15 m during uniform motion before becoming airbone.
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
vo = 0 m/s
vt = 5.8 m/s
a = 0.305 m/s²
By using the second equation, we can calculate the distance before becoming airbone
vt² = vo² + 2a . s
5.8² = 0² + 2 . 0.305 . s
0.61s = 33.64
s = 55.15 m
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a cats purple crinkle ball toy of mass 20g is throwwn straight up in the air with an initial speed of 4m/s. assume in this problem that air grad is negligible. what is the kinetic energy of the ball as it leaves the hand?
When the ball leaves the hand, it's kinetic energy is 160 Joules.
The kinetic energy of object is due to its virtue of motion. So, as the ball leaves the hand, it is in motion. The formula representing kinetic energy is: K.E. = 1/2×m×v², where K.E. is kinetic energy, m is mass and v is velocity.
Keep the values in formula to find the kinetic energy of the ball.
K.E. = 1/2×20×4²
Taking square on Right Hand Side of the equation
K.E. = 1/2×20×16
Performing multiplication and division on Right Hand Side of the equation
K.E. = 160 Joules
Thus, kinetic energy of ball is 160 Joules.
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4. for the experimental runs you made, calculate the expected acceleration using the expression you found with newtons second law of motion and the specific masses used. compare the figures with your experimental results. are the experimental acceleration values low or high? why?
As the mass of an object is increased, the acceleration of the object is decreased.
According to Newton's second law, an object's acceleration is determined by its mass and the net force that is acting on it. The body's acceleration is inversely related to its mass and directly proportional to the net force acting on it. This implies that as the force applied to an item increases, so does the object's acceleration. Similar to how an object's acceleration decreases as its mass increases, so do its mass.
As per Newton's second law of motion:
f = ma ------ (1)
f = (Δp) / t ⇒ Rate of change of momentum
f = (mu - mv) / t = [m(u - v)] / t ----- (2)
From equation (1) and equation (2) we get:
[m(u-v)] / t = ma
a = (u - v) / t
The experimental acceleration value will be less than the theoretical acceleration value. because it is impossible to sustain a constant rate of velocity change for an extended period of time. The difference between practical and theoretical acceleration will therefore be smaller.
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What are three modern inventions that could not have been invented without the earlier contributions of sir isaac newton?.
Answer:
there are the three basic
first law also called the law of inertia
the second one is the second law of motion and its equation is
F = ma
where m is the mass and a is the acceleration
its SI units are mass is kg and Acceleration is m/[tex]s^{2}[/tex]
the third law is called the action-reaction law
also the law of gravitation in which we survive our own earth-like plane due to the basic concept of the law of gravitation because the idea of gravitation is deal with this important law
F=GmMe/[tex]R^{2}[/tex]
The G value is 6.673*10^-11
m is the mass of an object
Me is the mass of the earth in our case we consider the object and the earth.
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What is the magnitude of the x-component of force ?
ANSWER
EXPLANATION
If force F keeps the object in equilibrium
Answer:
See below
Explanation:
Find the x components of all of the forces shown, add them together, the x-component of the force F will be exactly opposite ( same magnitude but 180 degrees different)
30 cos 55 + 40 cos 205 + 50 cos 320 = 19.26 <====x component sum of all of the forces shown
F (the x component of ) will be Either - 19.26 At zero degrees
Or 19.26 at 180 degrees
dan left the white house and drove toward the recycling plant at an average speed of 40 km/h. rob left some time later driving in the same direction at an average speed of 48 km/h. after driving for five hours rob caught up with dan. how long did dan drive before rob caught up?
Dan drove for 6 hours before catching up with Rob who left his home sometime later than Dan.
Dan left the white house and drove toward the recycling plant at an average speed of 40 km/h. Let d1 be Dan's start in km.
Rob left some time later driving in the same direction at an average speed of 48 km/h. Let d2 be rob's start in km.
Let t1 be the time between dan and rob's leaving.
After Rob leaves, Dan travels around 40×5 =200km.
During the same time, rob travels a distance of
48×5=240km
d1= 240-200
= 40 km
t1 = 40/40 = 1
So Dan traveled 1 more hour, which means he traveled for 6 hours.
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the simplest design for a radio/microwave transmitter antenna is a vertical conducting rod about one quarter-wavelength long. a mobile-phone manufacturer wants to build such an antenna into a gsm-900 (900 mhz) phone. how small can the phone be?
The phone can be 8.35cm small.
Frequency is the variety of occurrences of a repeating occasion in line with a unit of time. it is also from time to time referred to as temporal frequency to emphasize the assessment of spatial frequency, and regular frequency to emphasize the evaluation of angular frequency.
Frequency is an expression of ways regularly a periodic wave shape or signal repeats itself at a given amplitude. it is able to be expressed in hertz (Hz), kilohertz (kHz), megahertz (MHz), and so on.
Frequency is a vital parameter used in technological know-how and engineering to specify the temporal rate of trade discovered in oscillatory and periodic phenomena, such as mechanical vibrations, audio alerts (sound), radio waves, and mild.
GSM 900 band corresponds to a wavelength (\lambda) of
λ= c/f
where c is the speed of light and frequency is f which is 900 MHz
This gives \lambda=33.4cm
Antenna length L=\lambda/4=8.35cm
So the phone should at least be 8.35cm long.
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in a simple electric circuit, ohm's law states that , where v is the voltage in volts, i is the current in amperes, and r is the resistance in ohms. assume that, as the battery wears out, the voltage decreases at 0.03 volts per second and, as the resistor heats up, the resistance is increasing at 0.03 ohms per second. when the resistance is 400 ohms and the current is 0.04 amperes, at what rate is the current changing?
Current is dwindling at 0.125 , where v is the voltage in volts, i is the current in amperes, and r is the resistance in ohms
Voltage = Current * Resistance ,
The Ohm's law is given by
V = IR eq. 1
Where V is the voltage across Resistance R and I is the current flowing through the Resistance R
Taking outgrowth of eq. 1 with respect to time t yields
dV/ dt = I * dR/ dt dI/ dt * R
dI/ dt * R = - I * dR/ dt dV/ dt
dI/ dt = (- I * dR/ dt dV/ dt)/ R eq. 2
Now substitute the given values into eq. 2
dI/ dt = (-0.02 *0.04(-0.02)) 300
dI/ dt = (-0.0008-0.02)/ 300
dI/ dt = -0.0208/ 300
Charge will go via the external circuit if the two conditions of an electrical circuit are satisfied. Flow of charge is appertained to as a current. In this case, the word" current" simply means that" charge is moving," indicating that commodity is taking place in the cables. The physical property of current, still, may be measured and quantified. The quantum of charge that moves past a point on a circuit at a given time is called current as a physical volume. The quantum of charge Q travelling through a line's cross section in a given quantum of time, as shown in the illustration below, can be measured to determine the current in a circuit.
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The lift reaches a steady upward speed.
State the value of the force exerted on the woman by the floor at this steady
speed.
please quick
The value of force exerted on the women will be normal of the lift in positive x direction .
Acceleration is defined as change of velocity divided by time.
Since lift is moving upward at a steady speed , that means no change of speed has been taken place . hence no acceleration.
There is no external acceleration acting on the lift . Hence there will be two forces, one is the force of gravity and the other is upward normal force from the elevator.
N = mg if the elevator is at rest or moving at constant velocity
The value of force exerted on the women will be normal of the lift in positive x direction
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1. The subatomic particle with no electrical charge is the
2. The subatomic particle with a positive charge is the
3. The subatomic particle with a negative charge is the
4. There are the same number of these two particles in an atom
&
5. The atomic number is the same as the number of
To understand the questions, one should know the structure of an atom.
An atom is made up of some subatomic particles. These particles are positively charged, negatively charged and neutral particles.
The positive and negative charged particles neutralize the atom and the neutral subatomic particles are neutrons.
The answer to the questions are as follows:
1. The subatomic particle with no electrical charge is the "neutron".
2. The subatomic particle with a positive charge is the "proton".
3. The subatomic particle with a negative charge is the "electrons".
4. There are the same number of these two particles in an atom are "electrons" & "protons".
5. The atomic number is the same as the number of "protons" in an atom.
To sum up, an atom has different particles such as protons, electrons and neutrons. With protons being the positively charged, electrons are negatively charged and neutrons are neutral. Neutrons and protons are found in the nucleus and the electrons are spread around the nucleus.
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a 14- kg monkey climbs up a massless rope that runs over a frictionless tree limb and back down to a 28- kg package on the ground. what is the magnitude of the least acceleration the monkey must have if it is to lift the package of the ground?
The magnitude of the least acceleration the monkey must have if it is to lift the package off the ground: is 9.8 m/[tex]s^2[/tex]
From free body diagram,
The minimum acceleration of the monkey of mass (m) to lift the package off the ground is
[tex]m_{1}a_{min} = m_2g -m_1g\\a_{min} = \frac{m_2 - m_1}{m_1} g \\a_{min} = \frac{28 - 14}{14} 9.8 m/s^2 \\ \\a_{min} = 9.8 m/s^2 \\\\\\[/tex]
What is Mass?Mass is the amount of matter in a physical body. It also measures the body's inertia, the resistance to acceleration when a net force is applied. The mass of an object also determines its gravitational force on other objects. The basic SI unit of mass is the kilogram. Mass is best understood as the amount of matter in any object or body. Everything we see around us has mass. For example, a table, a chair, a bed, a football, a glass, and even air have mass.
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A student throws a rock upwards. The rock reaches a maximum height 2.4 seconds after it is released.
How fast was the rock thrown?
The rock reaches a maximum height in 2.4 seconds which implies the rock was thrown at a speed of 24m/s.
Let:
'u' be the initial velocity of rock thrownThe upward direction is considered as '+'veUsing the First equation of motion:
v = u + at
0 = u + (-10)(2.4)
0 = u + (- 24)
u = 24m/s
The First equation of motion establishes a relation between velocities and time. With the provided information, the most suitable equation which can be used to derive the answer is the First equation of motion.
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the combination of crumple zones and air bags and seat belts might increase the distance over which a person stops in a collision to as much as 1.00 mm . what is the force exerted on a 65.0- kgkg driver who decelerates from 18.0 m/sm/s to rest over a distance of 1.00 mm ?
From Newton's second law of motion,
F = ma
We know m = 65 kg. Next, we have to find a through this formula:
v² = v₀² + 2ad
0² = (18 m/s)² + 2(a)(1 m)
Solving for a,
a = -162 m/s²
So,
F = (65 kg)(-162 m/s²) = -10,530 Newtons.
A crumpled zone in the front of the car gradually slows the car down and increases the braking time. A safety cell is a rigid cage that prevents passengers from becoming trapped. Inside the car seat belts and airbags prevent the driver from hitting the windshield steering wheel and dashboard.
Crumple zones are typically found in the front and rear of a vehicle and are designed to crumple and crush under high-force impacts. The Crumple Zone transfers a portion of the vehicle's kinetic energy during impact to a controlled crash while maintaining the integrity of the occupant cell.
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