1. At age 65 when you retire, you have (future value) $202,531.69 from the IRA.
2. The total interest earned on the monthly investment of $95 at 6.25% for 40 years is $156,931.69.
How is the future value determined?The future value, which represents the compounded value of the monthly investments, can be computed using the FV formula or an online finance calculator as follows:
Number of years = 40 (65 - 25)
N (# of periods) = 480 months (40 x 12)
I/Y (Interest per year) = 6.25%
PV (Present Value) = $0
PMT (Periodic Payment) = $95
Results:
Future Value (FV) = $202,531.69
Sum of all periodic payments = $45,600 ($95 x 480 months)
Total Interest = $156,931.69
Thus, the future value of the monthly investment is $202,531.69 with an interest of $156,931.69.
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The owner of a movie theater was countingthe money from 1 day's ticket sales. He knewthat a total of 150 tickets were sold. Adulttickets cost $7.50 each and children's ticketscost $4.75 each. If the total receipts for theday were $891.25, how many of each kind ofticket were sold?
65 adult's ticket and 85 children's ticket was sold
Explanation:Let the number of tickets for children = x
Let the number of adults ticket = y
Total tickets = 150
x + y = 150 ....equation 1
The cost of tickets per child = $4.75
The cost of tickets per adult = $7.50
Total revenue from tickets = $891.25
Total revenue from tickets = The cost of tickets per child × number of children ticket +
The cost of tickets per adult * number of adults ticket
891.75 = 4.75(x) + 7.5(y)
891.75 = 4.75x + 7.5y ...equation 2
x + y = 150 ....equation 1
891.75 = 4.75x + 7.5y ...equation 2
Using substitution method by making x the subject of formula in equation 1:
x = 150 - y
Substitute for x in equation 2:
891.25 = 4.75(150 - y) + 7.5y
891.25 = 712.5 - 4.75y + 7.5y
891.25 = 712.5 + 2.75y
891.25 - 712.5 = 2.75y
178.75 = 2.75y
y = 178.75/2.75
y = 65
Substitute for x in equation 1:
x + 65 = 150
x = 150 - 65
x = 85
Hence, 65 adult's ticket and 85 children's ticket was sold
The expression (222)(x?) is equivalent to z What is the value of p?
SOLUTION;
Step 1:
[tex]undefined[/tex]Circumference of a circleThe radius of a circle measures 16 m. What is the circumference of the circle?Use 3.14 for, and do not round your answer. Be sure to include the correct unit in your answer.
Solution:
Given:
[tex]\text{radius of a circle, r = 16m}[/tex]The circumference (C) of a circle is given by;
[tex]\begin{gathered} C=2\pi r \\ \text{where;} \\ C\text{ is the circumference of the circle} \\ r\text{ is the radius} \end{gathered}[/tex]Hence,
[tex]\begin{gathered} r=16m \\ \pi=3.14 \\ C=\text{?} \end{gathered}[/tex]Thus,
[tex]\begin{gathered} C=2\pi r \\ C=2\times3.14\times16 \\ C=100.48m \end{gathered}[/tex]Therefore, the circumference of the circle is 100.48m
The answers available are SSS SAS CPCTC and definition of congruence
Solution
The diagram below will be of help
From the above, we have two sides to be equal and an angle to be equal
Therefore, the answer Side, Angle, Side (SAS)
hello im stuck on this hw problem and need help ty
The amount of money that Abdul is going to donate to the City Youth Fund is denoted by x, and the amount of money that Abdul is going to donate to the Educational Growth Foundation is denoted by y.
Since Abdul will donate up to $500, the sum of those amounts must be less or equal to 500.
[tex]x+y\leq500[/tex]It is not possible to donate less than zero, therefore, we also have the following constrains
[tex]\begin{gathered} x\geq0 \\ y\geq0 \end{gathered}[/tex]Abdul wants the amount of money donated to the Educational Growth Foundation to be at least 4 times the amount of money donated to the City Youth Fund, therefore, we have our final constrain
[tex]4x\leq y[/tex]Combining those four regions, the solution is their interception, which is
y 4 7(x-6)
x-intercept:
y-intercept:
PLEASE ANSWER FAST.
Answer: y-4=7(x-6)
x-intercept(s): (38/7,0)
y-intercept(s): (0,−38)
I believe this is right hope this helps
Step-by-step explanation:
the equation 5x+7=4x+8+x-1 is true for all real numbers substitute a few real numbers for x to see that this is so and then try solving the equation
The equation 5x+7 = 4x+8+x-1 is true for all real numbers.
Solution for the equation is 5x + 7 = 5x + 7.
Given,
The equation; 5x+7 = 4x+8+x-1
We have to find the solution for this equation.
Here,
5x + 7 = 4x + 8 + x - 1 = 5x + 7
The equation is true for all real numbers;
Lets check;
x = 65 x 6+7 = 4 x 6 + 8 + 6 - 1
30 + 7 = 24 + 13
37 = 37
x = 155 x 15 + 7 = 4 x 15 + 8 + 15 - 1
75 + 7 = 60 + 22
82 = 82
That is,
The equation 5x + 7 = 4x + 8 + x - 1 is true for all real numbers.
The solution for the equation is 5x + 7 = 5x + 7.
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A triangular road sign has a base of 30 inches and a height of 40 inches. What is it’s area?
Answer:
600ft
Step-by-step explanation:
Because a triangle is half of a rectangle, the area can be found by taking the base times height and dividing by 2.
A = (b * h)/2
A = (40 * 30)/2
A = 1200/2
A = 600ft
6. ΔABC is mapped onto ΔA'B'C' by a dilation at D. Complete the statement: The dilation of 4/3 is _____. a. a reduction b. an enlargement
Dilation involves adjusting the size of an object or a figure, without altering its shape.
The object can be increased or decreased depending on its scale factor.
A scale factor less than 1 results in a figure of reduced dimensions whereas, a scale factor greater than 1 results in a figure or an object of enlarged dimensions.
In the ΔABC, a dilation of 4/3, which is greater than 1, will thus result into an enlargement.
The correct option is B.
PLEASE HELP I WILL MARK BRAINLIEST!!Which of the following equations is a linear function?A) 2x + 3y = 6B) y = x^2 + 1C) y=x^3D) x^2 + y^2 = 9
Given data:
The given sets of equations.
The polynomial in which degree of the variable is 1 is said to be linear expression.
The first option 2x+3y=6 is only linear function.
Thus, the option (A) is correct.
3) An experiment is designed to compare the average salaries in a particular Position in two competing companies. The null hypothesis is assumed to be that there is no difference in the average salaries of empoty employees in a particular position in the two companies. What is the alternative hypothesis?
Given:
There are two competing companies.
Required:
We need to find the alternative hypothesis
Explanation:
If the null hypothesis assumes equal average salaries (i.e. no difference), then the alternative can take on three cases:
A)
One mean is greater than the other
B)
One mean smaller than the other
C)
The means are not equal
Now here A and B sound the same, so I shoukd be more precise,
In 2001, Rodney Hampton earned $75,200 as a self-employed worker. He also earned $41,350 as an employee. How much FICA tax did he pay for both earnings? Note:Self-employed tax rate is 15.3% and the employee tax rate is 7.65%.$14,668.88$14,577.25$14,324.09$14,225.50None of these choices are correct.
Step 1: Rodney Hampton earned $75,200 as a self-employed worker
% tax rate for self employed = 15.3%
[tex]\begin{gathered} =15.3\text{ \% of \$75200} \\ =\frac{15.3}{100}\text{ x \$75200} \\ =11505.6 \\ =\text{ \$11505.6} \end{gathered}[/tex]Step 2: Rodney Hampton earned $41,350 as a employee worker
%tax rate for employee = 7.65%
[tex]\begin{gathered} =\text{ 7.65\% of \$41350} \\ =\text{ }\frac{7.65}{100}\text{ x \$41350} \\ =\text{ 3163.3} \\ =\text{ \$3163.3} \end{gathered}[/tex]Step 3: FICA tax paid for both earnings = $11505.6 + $3163.3
= $14668.875
=$14668.88
Hence FICA tax paid for both earnings = $14668.88
Find the equation for thefollowing parabola.Vertex (0,0)Focus (2, 0)A. 2x^2 = yB. y^2 = 8x2C. X^2 = ByD. y^2 = 8x
To answer this question we need the equation of a parabola that uses the distance from the focus to the vertex.
This formula is,
[tex]4p(y-k)=(x-h)^2[/tex]where,
p is the distance from the focus to the vertex, and the point (h,k) is the vertex.
[tex]\begin{gathered} \text{focus (2,0)} \\ \text{Threrefore} \\ p=2 \end{gathered}[/tex][tex]\begin{gathered} \text{vertex (0 , 0)} \\ \text{Therefore,} \\ h=0 \\ k=0 \end{gathered}[/tex]Let us now substitute the data into the equation of the parabola,
[tex]\begin{gathered} 4\times2(y-0)=(x-0)^2 \\ 4\times2(y)=x^2 \\ 8y=x^2 \end{gathered}[/tex]Hence, the equation for the parabola is, x² = 8y.
Option C is the correct answer.
A figure is made up of a triangle and a square. The square andthe triangle have the same base of 9 inches. The triangle has aheight of 7 inches, what is the total area of the figure?
To solve the exercise, it is helpful first to draw the situation that the statement describes:
The total area of the figure will be
[tex]A_{\text{total}}=A_{\text{square}}+A_{\text{triangle}}[/tex]Then, we can calculate the area of the square using the following formula:
[tex]\begin{gathered} A_{\text{square}}=s\cdot s \\ \text{ Where s is one side of the square} \end{gathered}[/tex]So, we have:
[tex]\begin{gathered} s=9in \\ A_{\text{square}}=s\cdot s \\ A_{\text{square}}=9in\cdot9in \\ \boldsymbol{A}_{\boldsymbol{square}}\boldsymbol{=81in}^{\boldsymbol{2}} \end{gathered}[/tex]Now, we can calculate the area of the triangle using the following formula:
[tex]\begin{gathered} A_{\text{triangle}}=\frac{b\cdot h}{2} \\ \text{ Where b is the base and} \\ h\text{ is the height of the triangle} \end{gathered}[/tex]So, we have:
[tex]\begin{gathered} b=9in \\ h=7in \\ A_{\text{triangle}}=\frac{b\cdot h}{2} \\ A_{\text{triangle}}=\frac{9in\cdot7in}{2} \\ A_{\text{triangle}}=\frac{63in^2}{2} \\ \boldsymbol{A}_{\boldsymbol{triangle}}\boldsymbol{=31.5in}^{\boldsymbol{2}} \end{gathered}[/tex]Finally, we calculate the total area of the figure
[tex]\begin{gathered} A_{\text{total}}=A_{\text{square}}+A_{\text{triangle}} \\ A_{\text{total}}=81in^2+31.5in^2 \\ \boldsymbol{A}_{\boldsymbol{total}}\boldsymbol{=112.5in}^{\boldsymbol{2}} \end{gathered}[/tex]Therefore, the total area of the figure is 112.5 square inches, and the correct answer is option C.
Which number line shows the correct solution to 4y - 82-20 ? H 4 -3 -2 -1 0 1 2 3 4 5 HHH O > & -3 -2 -1 0 1 2 3 4 5 HH H -4 -3 -2 -1 0 1 1 2 3 4 5 H → -3 -2 -1 0 1 2 3 4 5
To find which of the lines represent the solution we first need to solve the inequality:
[tex]\begin{gathered} -4y-8\ge-20 \\ -8+20\ge4y \\ 12\ge4y \\ \frac{12}{4}\ge y \\ 3\ge y \end{gathered}[/tex]the last line is equivalent as:
[tex]y\leq3[/tex]Now that we have the solution we can look at the line that represents it. The solution tells us that y is less or equal to 3, this means that the solutions are to the left of the number 3. Now, since the inequality is not an exact one that means that the 3 is also a solution, which also means that the circle over the 3 has to be a solid one.
With this in mind we conclude that the line representing the solution is the third option.
Haven’t done this type of math before could use some help:)
Third row:
The balance stays the same as the previous row ($337.52).
We have 12 days between 9/7 and 9/18, so we can calculate the product/sum as:
[tex]S=12\cdot337.52=4050.24[/tex]NOTE: the product/sum will be used to calculate the average balance for the month.
Fifth row:
The balance stays the same as the previous row ($399.78).
We have 11 days between 9/20 and 9/30.
Then, the product/sum is:
[tex]S=399.78\cdot11=4397.58[/tex]Total:
The total product/sum is:
[tex]S_{\text{Total}}=1937.60+337.52+4050.24+399.78+4397.58=11122.72[/tex]Average daily balance:
We can take the total product/sum and divide by the total amount of days.
[tex]\text{average daily balance}=\frac{11122.72}{30}=370.76[/tex]Finance charge:
[tex]\text{ finance charge}=\frac{1.25}{100}\cdot370.76=4.63[/tex]New balance:
[tex]\begin{gathered} \text{New balance = previous balance - payment/credits + finance charge + new purchases} \\ \text{New balance = }387.52-50+4.63+62.26=404.41 \end{gathered}[/tex]The new balance is $404.41.
Sharon's house, the library, and Lisa's house are all on the same straight road. Sharon has to ride her bike 1 3/5 miles to get from her house to the library and another 2 3/4 miles to get from the library to Lisa's house. How far does Sharon live from Lisa? Explain how you got your answer.
Sharon lives [tex]4\frac{7}{20}[/tex] miles away from Lisa .
In the question ,
it is given that
distance between Sharon and Library is [tex]1\frac{3}{5}[/tex] miles .
distance between Library to Lisa's house is [tex]2\frac{3}{4}[/tex] miles .
So according to the question
distance between Sharon's house and Lisa's house = (distance between Sharon and Library) + (distance between Library to Lisa's house) .
On substituting the values from above ,
we get ,
distance between Sharon's house and Lisa's house = [tex]1\frac{3}{5}[/tex] + [tex]2\frac{3}{4}[/tex]
= (5+3)/5 + (8+3)/4
= 8/5 + 11/4
taking LCM as 20 and solving further we get
= 32/20 + 55/20
= 87/20
= [tex]4\frac{7}{20}[/tex]
Therefore , Sharon lives [tex]4\frac{7}{20}[/tex] miles away from Lisa .
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Multiply. (−5 2/5)⋅3 7/10. −19 49/50. −15 7/25. −9 1/10. -1 7/10
To perform this multiplication, first, we have to transform the mixed numbers into fractions as follows:
[tex]-5\frac{2}{5}=-\frac{5\cdot5+2}{5}=-\frac{27}{5}[/tex][tex]3\frac{7}{10}=\frac{3\cdot10+7}{10}=\frac{37}{10}[/tex]Substituting these values into the multiplication, we get:
[tex]\begin{gathered} (-5\frac{2}{5})\cdot3\frac{7}{10}= \\ =(-\frac{27}{5})\cdot\frac{37}{10}= \\ =-\frac{27\cdot37}{5\cdot10}= \\ =-\frac{999}{50} \end{gathered}[/tex]This result can be expressed as a mixed number as follows:
[tex]-\frac{999}{50}=-\frac{950+49}{50}=-(\frac{950}{50}+\frac{49}{50})=-(19+\frac{49}{50})=-19\frac{49}{50}[/tex]
Terry invested $2,200 in the stock market for 2 years. If the investment earned 12%, how muchmoney did Terry earn in 2 years?
We will have that $2200 represent the 100%, then how much money does 12% represent.
In order to solve for the ammount of money we multiply the invested ammount ($2200) times the percentage we want to know (12%) and divide it by 100%, that is:
[tex]m=\frac{2200\cdot12}{100}\Rightarrow m=264[/tex]Here we can see, he earned $264 in those 2 years.
Two numbers sum to 61. Twice the first subtracted from the second is 1. Find the numbers.
Which of the following is a valid application of the distributive property?
A. 5.2+3=5 (2+3)
B. 5 2+3=5 (2) +5. (3)
ONeither A nor B
OB only
O A only
O Both A and B
5 2+3=5 (2) +5. (3) is a valid application of the distributive property.
What is a distributive property?
According to this property, multiplying the sum of two or more addends by a number will give the same result as multiplying each addend individually by the number and then adding the products together.
Given that,
A. 5.2+3=5 (2+3)
B. 5 2+3=5 (2) +5. (3)
Distributive property
a*(b+c) = a*b+a*c
In option A the RHS part is not correct.
In option B both part is correct.
5*(2+3)= 5*2+5*3
5*5 = 10+15
25 = 25
LHS = RHS
Hence, Option B is correct.
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Algebra Find the value(s) of the variables in each kite.
56º,34º
1) A kite is a quadrilateral that according to the following theorem:
2) And examining that picture, we can tell that the angle labeled as 8x is congruent to its opposite counterpart.
3) In addition to this, but not less important that bigger diagonal bisects that the other pair of opposite angles. So we can sketch the following
So we can pick one triangle and write out the following according to the Triangle sum theorem:
[tex]\begin{gathered} 8x+(5x-1)+90=180 \\ 8x+5x-1+90=180 \\ 13x+89=180 \\ 13x=180-89 \\ \frac{13x}{13}=\frac{91}{13} \\ x=7 \end{gathered}[/tex]4) Finally, let's plug into each one the quantity of x and get the measure of those angles:
Segment RS is translated by (x+1, y-2) and then reflected over the x-axis. The resulting segment R" S" has coordinates R" (7,3) and
S" (2,7). What are the coordinates of the segment RS?
can someone pls help meee
The coordinates of segment RS are obtained as R(6, -1) and S(1, -5) for the given translation.
What is termed as the reflection over the axis?The line of reflection is the point at which the image satisfy the axis of reflection. There are two kinds of reflections: x-axis reflections and y-axis reflections. Vertical reflections are reflections that cross the x-axis. Horizontal reflections are reflections that cross the y-axis.For the given question;
Segment RS is translated by (x+1, y-2).
Then, the image formed is again reflected over the x-axis to form R" S" has coordinates R" (7,3) and S" (2,7).
To find the measure of R and S, first find the x -axis reflection of R" S".
R" (7,3) = R'(7, -3)and S" (2,7) = S'(2, -7)As, RS was translated by (x+1, y-2).
Then, subtract 1 and add 2 to its coordinates.
R'(7, -3) = R (7 - 1, -3 + 2) = R(6, -1)S'(2, -7) = S(2- 1, -7 + 2 ) = S(1, -5)Thus, the coordinates of segment RS are obtained as R(6, -1) and S(1, -5).
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Choose the scenarios that demonstrate a proportional relationship for each person's income.
Millie works at a car wash and earns $17.00 per car she washes.
Bryce has a cleaning service and charges $25.00 plus $12.50 per hour.
Carla makes sandwiches at her job and earns $7.85 per hour.
Tino is a waiter and makes $3.98 per hour plus tips.
Choose the scenarios that demonstrate a proportional relationship for each person's income.
Millie works at a car wash and earns $17.00 per car she washes.
Bryce has a cleaning service and charges $25.00 plus $12.50 per hour.
Carla makes sandwiches at her job and earns $7.85 per hour.
Tino is a waiter and makes $3.98 per hour plus tips.
1. Caitlyn is going away to college and will need to rent a truck to helpmove. The cost of the truck is $35 plus $0.79 per mile. If her collegeis 85 miles away and she budgeted $100 for the rental, will she haveenough money?
1. Caitlyn is going away to college and will need to rent a truck to help
move. The cost of the truck is $35 plus $0.79 per mile. If her college
is 85 miles away and she budgeted $100 for the rental, will she have
enough money?
we know that
The equation in slope intercept form of this situation is
y=mx+b
where
m=$0.79 per mile
b=$35
y -----> is the total cost
x -----> the number of miles
so
y=0.79x+35
so
For x=85 miles
substitute
y=0.79(85)=35
y=$102.15
we have that
102.15 > 100
therefore
she not have enough moneyThe sides of triangle ABC are: AB = 6 cm,BC = 12 cm, AC = 10cm. K, M and P arethe midpoints of the sides AB, BC and AC respectivelyare the midpoints of the sides and the midpoints of the sides. Calculate the perimeter of KMP.
Answer: By inspecting the triangle we can come up with the following relationships, using the proportionality:
[tex]\begin{gathered} \frac{12}{10}=\frac{6}{x}\rightarrow(1) \\ \frac{12}{6}=\frac{6}{y}\rightarrow(2) \\ \frac{6}{12}=\frac{3}{z}\rightarrow(3) \end{gathered}[/tex]Solving the three equations, (1) (2) and (3) gives the answer for x,y,z which are the three sides of the smaller triangle, the steps are as follows:
[tex]\begin{gathered} x=KM=5 \\ y=MP=3 \\ z=KP=6 \end{gathered}[/tex]Therefore the perimeter is as follows:
[tex]\begin{gathered} P=x+y+x=5+3+6=14 \\ P_{(KMP)}=14 \end{gathered}[/tex]i need help with this asap please check work when done
Given the parent function
[tex]y=\cos x[/tex]From the graph,
The range of the function is best modelled by the interval
Comparing the function with general equation of the cosine function,
[tex]B=1[/tex]The formula for the period is,
[tex]T=\frac{2\pi}{B}[/tex]There
A periodic deposit is made into an annuity with the given terms. Find how much the annuity will hold at the end of the specified amount of time. Round your answer to the nearest dollar.Regular deposit:$1300Interest rate:4.2%FrequencyannuallyTime:17 yearsFuture value: $
SOLUTION
We will use the formula
[tex]FV=P\lbrack\frac{(1+r)^n-1}{r}\rbrack[/tex]Where FV represents the future value annuity
P = Periodic payment = 1300
r = interest rate = 4.2% = 0.042
n = number of periods = 17 years.
So we have
[tex]\begin{gathered} FV=P\lbrack\frac{(1+r)^n-1}{r}\rbrack \\ FV=1300\lbrack\frac{(1+0.042)^{17}-1}{0.042}\rbrack \\ FV=1300\lbrack\frac{(1.042)^{17}-1}{0.042}\rbrack \\ FV=31,341.485 \end{gathered}[/tex]Hence, the answer becomes $31,341 to the nearest dollar
Hi, can you help me answer this question please, thank you!
From the problem we have
[tex]\begin{gathered} n_1=50 \\ n_2=30 \\ \bar{x_1}=2.31 \\ \bar{x_2}=2.02 \\ s_1=0.89 \\ s_2=0.61 \end{gathered}[/tex]We replace in t
[tex]\begin{gathered} t=\frac{(2.31-2.02)}{\sqrt[]{\frac{(0.89)^2_{}}{50_{}}+\frac{(0.61)^2_{}}{30_{}}_{}}} \\ t=\frac{0.29}{\sqrt[]{0.028245_{}_{}}} \\ t=1.725 \\ t=1.73 \end{gathered}[/tex]The answer is t=1.73A point is chosen at random in the square shown below. Find the probability that the point is in the shaded circular region. Each side of the square is 6in, and the radius of the circle is 3in.Use the value 3.14 for π. Round your answer to the nearest hundredth.
We will have the following:
First, we determine the area of the square and of the shaded region, that is:
[tex]\begin{gathered} A_s=6in^2\Rightarrow A_s=36in^2 \\ \\ A_c=\pi(3)^2\Rightarrow A_c=9\pi in^2 \end{gathered}[/tex]Now, we will have that the probability will be of:
[tex]P=\frac{9\pi}{36}\Rightarrow P=\frac{\pi}{4}\Rightarrow P\approx0.79[/tex]So, the probability is approximately 79%.