Answer:
the answer is d , sundiata!
Step-by-step explanation:
the
Give the name (monomial, binomial, trinomial etc.) and degree of the polynomial 3x^2 + x^2 +x
The name of the provided polynomial equation is trinomial and the degree of the polynomial is 2.
What is polynomial?Polynomial equations is the expression in which the highest power of the unknown variable is n (n is real number).
Types of polynomial equation on the basis of number of terms:
Monomial-Monomial is the polynomial which has only a single term, such as ax, bz.Binomial-Binomial is the polynomial which has only two terms, which are not similar, such as ax+c, bz+d.Trinomial--Trinomial is the polynomial which has only three terms, which are not similar.The given expression is,
[tex]3x^2 + x^2 +x[/tex]
The equation has one variable and 3 terms in it. Thus, this a trinomial. The highest power of this expression is 2. Thus, its degree is 2Hence, the name of the provided polynomial equation is trinomial and the degree of the polynomial is 2.
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A Mathematics paper consists of 12 questions of which not more than ten are to be answered. Given that the number of candidates who answer ten questions is equal to the number of candidates who answer nine questions only. Find the probability that a candidate chosen at random from among these two sets of candidates will have selected questions 1, 2 and 3 if all the questions have the same chance of being selected.
The probability that a candidate chosen at random from among these two sets of candidates will have selected questions 1, 2 and 3 is 0.4179.
How to calculate probability?The probability that a candidate chosen at random from among these two sets of candidates will have selected questions 1, 2 and 3 will ba calculated thus:
= [(9C6 /12C9) × 1/2] + [(9C7)/12C10) × 1/2]
= 42/220 + 18/66
= 0.1909 + 0.2727
= 0.4179
In conclusion, the probability is 0.4179.
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.nxmdmxmxmdmmddmm mcmcmfmfmcmxmcmc fnnffn
Answer:
what do you want to ask brother...
Step-by-step explanation:
or you post this by mistake.....
Please help
(Also show work) and its volume not SA
Answer:
75 inches cubed
Step-by-step explanation:
V=lwh
2 1/2 = 2.5
4 = 4
7 1/2 = 7.5
2.5 x 4 x 7.5=75
75 cubic inches
Find the volume of the given figure. Round to the nearest tenth. Enter only the number, the
units have been given.
5.1 in
5.9 in
6 in
3.4 in
Volume =
in
Answer:
111.3 cubic inches
Step-by-step explanation:
The dimensions of the rectangular prism are 5.9 x 3.4 x 5.1
volume = length x width x height
V = 5.9 x 3.4 x 5.3
V = 102.306
The dimesnsions of the triangular prism are 3.4 x 5.9 x ?
to find the missing length, 6 - 5.1 = 0.9
3.4 x 5.9 x 0.9
Volume = (3.4 x 5.9 x 0.9)/2
V = 18.054/2
V = 9.027
Add the volumes together
102.306 + 9.027 = 111.333
Round
111.3
can please someone help me with more of these asap
Answer: 75.36
Step-by-step explanation: Lenght of arc=2nr
=2nx12in
=75.36
lenght of arc of sector=120/360x75.36
=25.12
You plan to go snowboarding. The resort charges $15 an hour in addition to $25 to rent a board. Write an equation that represents the cost to go snowboarding for the day. You have 100.00 to spend that day how many hours can you snowboard?
Answer:
6 Hours
Explanation:
Linear Equation: mx+b=y
x variable: Hour
Hourly Fee: $15(x)
(Initial) Rent Fee: $25
Balance: $100
Equation:
15x+25=100
15x+25-25=100-25 -- Separate the constant terms from the x by subtracting 25 from both sides.
15x=100
15x/15=100/15 -- Isolate the x variable by dividing 15 from both sides.
x=6.6.. -- Round down to 6 (not 7) because you can't afford to snowboard for 7 hours with less than $15.
x=6 Hours
answer: 6 hours
Step-by-step explanation:
I did this on a paper
Super easy, find the area! 7th grade math
[tex] \: [/tex]
Step-by-step explanation:
It is given that, the height of a triangle is 3cm, and its base is 3cm and we are to find the area of triangle.
[tex] \: [/tex]
To find the area of the triangle, we have to know this formula :
[tex]\\ {\longrightarrow \pmb{\frak {\qquad Area_{(Triangle)} = \: \frac{1}{2} \times Base \times Height \:}}} \\ \\ [/tex]
Now, substituting the values in the formula :
[tex]{\longrightarrow \pmb{\sf {\qquad Area_{(Triangle)} = \: \frac{1}{2} \times 3 \times 3 \:}}} \\ \\ [/tex]
[tex]{\longrightarrow \pmb{\sf {\qquad Area_{(Triangle)} = \: \frac{1}{2} \times 9 \:}}} \\ \\ [/tex]
[tex]{\longrightarrow \pmb{\sf {\qquad Area_{(Triangle)} = \: \frac{9}{2} \:}}} \\ \\ [/tex]
[tex]{\longrightarrow \pmb{\frak {\qquad Area_{(Triangle)} = \: 4.5 \:}}} \\ \\ [/tex]
Therefore,
The area of the triangle is 4.5 cm² .Answer:
4.5cm^2
Step-by-step explanation:
Find area of a square 3*3=9
Half of a square is 9/2=4.5
30 points
The length of the shorter leg of a 30-60-90 Special Right Triangle is 6 cm long. How long is the hypotenuse of the triangle?
Question 2 options:
12 cm
62–√ cm
63–√ cm
6 cm
Answer:
Your answer would be 12cm
Step-by-step explanation:
I just take a quiz and got it right.
The maximum acceptable level of a certain toxic chemical in vegetables has been set at 0.4
parts per million (ppm). A consumer health group measured the level of the chemical in a
random sample of tomatoes obtained from one producer.
The levels, in ppm, are shown below.
0.31 0.47 0.19 0.72 0.56
0.91 0.29 0.83 0.49 0.28
0.31 0.46 0.25 0.34 0.17
0.58 0.19 0.26 0.47 0.81
Does the data provide sufficient evidence to support the claim that the mean level of the
chemical in tomatoes from this producer is greater than the recommended level of 0.4 ppm?
Use a 0.05 significance level to test the claim that these sample levels come from a population
with a mean greater than 0.4 ppm. Use the P-value method of testing hypotheses. Assume that
the standard deviation of levels of the chemical in all such tomatoes is 0.21 ppm.
Choose the correct null and alternative hypotheses associated with this experiment.
Null hypothesis (H0): The mean level of the chemical in tomatoes from this producer is equal to or less than the recommended level of 0.4 ppm.
Given that, the maximum acceptable level of a certain toxic chemical in vegetables has been set at 0.4 parts per million (ppm).
Alternative hypothesis (H1): The mean level of the chemical in tomatoes from this producer is greater than the recommended level of 0.4 ppm.
To test the claim, we will use a one-tailed hypothesis test with a significance level of 0.05. The test statistic is calculated by subtracting the mean of the sample from the mean of the population, and dividing the result by the standard deviation of the population.
Test statistic = (Sample mean - Population mean) / Standard deviation of population
Test statistic = (0.465 - 0.4) / 0.21
Test statistic = 2.38
Since the test statistic is positive, we can reject the null hypothesis. The P-value for this test statistic is 0.0095, which is less than 0.05.
Therefore, the data provides sufficient evidence to support the claim that the mean level of the chemical in tomatoes from this producer is greater than the recommended level of 0.4 ppm.
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A man earns Rs.9600 and he saves Rs.2400 in a month.What percentage does he spends?
Given Information :-
⠀⠀
A man earns rs. 9600He saves Rs. 2400⠀
To Find :-
⠀
The percentage of amount he spends⠀
Solution :-
⠀
To find the percentage of expenditure, we must know how much amount does he really spend, thus :
⠀
➥ Expenditure = Earnings - Savings
➥ Expenditure = Rs. 9600 - Rs. 2400
➥ Expenditure = Rs. 7200
⠀
Now, we can find the percentage,
⠀
[tex] \sf \hookrightarrow Percentage_{expenditure} = \dfrac{Expenditure}{Earnings} \times 100 \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \frac{7200}{9600} \times 100 \qquad \: \: \: \: \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \frac{72 \cancel{00}}{96 \cancel{00}} \times 100 \qquad \quad \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \frac{ \cancel{72}}{ \cancel{96}} \times 100 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \cancel \frac{3}{4} \times 100 \qquad \qquad \: \: \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = 0.75 \times 100 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \underline{ \boxed{ \orange {\frak{75\%}}}} \: \star \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ [/tex]
Thus, the percentage of his expenditure is 75%.
⠀
[tex] \underline { \rule{227pt}{2pt}}[/tex]
⠀
Answer:
5%
Step-by-step explanation:
Earns= Rs 640
Spends= Rs 608
Saves= (Rs 640 - Rs 608) =Rs 32
therefore, 32/640x100
Mr. Balderas is 65 years old. He
deposited $150 into a savings
account when he was 18 years
old. The account earned 6.75%
compound interest annually.
What is the total amount in the
savings account at this point in
time?
The total amount of money in Mr Baldera's savings account at this point in time is $3231.33.
What is the total amount of money in the account?
The formula that can be used to determine the future value with annual compounding is:
FV = P (1 + r)^n
FV = Future value P = Present value R = interest rate N = number of years : 65 - 18 = 47150 x (1.0674)^47 = $3231.33.
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in one year the water level of a lake change is b -3/8 in the water level of the lake continue to change at this rate for 7 years how many inches will the water level of the lake have changed
Answer:
-21/8 or -2 5/8
Step-by-step explanation:
The lake change is the same for all 7 years so you can subtract -3/8 seven times.
-3/8-3/8-3/8-3/8-3/8-3/8-3/8 = -21/8
as a mixed number it's -2 5/8
Solve 21 & 22 give explanation
Step-by-step explanation:
question no. 21 answer
8 units
[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]
Distance = 13 units[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]
By using Distance formula ~
[tex]\qquad❖ \: \sf \: \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} } [/tex]
[tex]\qquad❖ \: \sf \: \sqrt{ ( - 8 - ( - 8)) {}^{2} + ( - 8 - 5) {}^{2} } [/tex]
[tex]\qquad❖ \: \sf \: \sqrt{0 + ( - 13) {}^{2} } [/tex]
[tex]\qquad❖ \: \sf \: \sqrt{169} [/tex]
[tex]\qquad❖ \: \sf \:13 \: \: units[/tex]
[tex] \qquad \large \sf {Conclusion} : [/tex]
The distance between the points is 13 units
Fit two 1/8 pieces together.What larger fraction pieces do they match?
Answer: 1/4
Step-by-step explanation: 1/8 plus 1/8 is 2/8. it can be simplified to 1/4
*50 POINTS* Pls HELP. ANSWER THE QUESTION IN THE PIC!
Answer:
D
Step-by-step explanation:
Here's why I think it's D.
y = x + 44 is the equation the car wash owner uses
x represents the number of days
y represents the number of cars (washed)
so if we plug in one of the given numbers (from the chart)
example:
Day 2 Numbers of Cars Washed 44
2 will represent the "number of days" also known as x
44 will represent the "number of cars" also known as y
so if we plug in those values to the equation the car wash owner uses
y = x + 44, it doesn't match
__________________________________
(44) = 2 + (44)
44 [tex]\neq[/tex] 46
Therefore, I believe the answer is D
Answer:
D
Step-by-step explanation:
It is not a good fit for the dataThere should equal number of points below and above the x-axis in the residual plotThe given equation : y = x + 44 does not match the given dataWhat is the name given to a polynomial with 10 terms
Answer:
It should be called A decic polynomial
Step-by-step explanation:
find square root of
[tex]244[/tex]
Answer:
15.6204994
Step-by-step explanation:
[tex]15.6204994^{2} = 244\\so\\\sqrt{244} = 15.6204994[/tex]
hope this helps!
(бх -Зу = 9
Solve y=2x-5
-
Answer:
6x-3(2x-5)=9
6x-6x+15=9
15=9
no sollution
[tex] \displaystyle\red{ \sf\lim_{x \to {0}^{ + } }\frac{1}{ {sin}^{2}x } \int _{ \frac{x}{2} }^{x} {sin}^{ - 1} t \: dt}[/tex]
Use L'Hopital's rule twice:
[tex]\displaystyle \lim_{x\to0^+} \frac1{\sin^2(x)} \int_{\frac x2}^x \sin^{-1}(t) \, dt = \lim_{x\to0^+} \frac1{\sin^2(x)} \left(\int_0^x \sin^{-1}(t) \, dt - \int_0^{\frac x2} \sin^{-1}(t) \, dt\right) \\\\ = \lim_{x\to0^+} \frac{\sin^{-1}(x) - \frac12 \sin^{-1}\left(\frac x2\right)}{2\sin(x)\cos(x)} ~~~~~~~~~~ (LHR) \\\\ = \lim_{x\to0^+} \frac{2\sin^{-1}(x) - \sin^{-1}\left(\frac x2\right)}{2\sin(2x)} \\\\ = \lim_{x\to0^+} \frac{\frac2{\sqrt{1-x^2}} - \frac1{2\sqrt{1-\frac{x^2}4}}}{4\cos(2x)} ~~~~~~~~~~ (LHR) \\\\ = \lim_{x\to0^+} \frac{\frac2{\sqrt{1-x^2}} - \frac1{\sqrt{4-x^2}}}{4\cos(2x)}[/tex]
The remaining limand is continuous at x = 0, and the limit is
[tex]\displaystyle \lim_{x\to0^+} \frac1{\sin^2(x)} \int_{\frac x2}^x \sin^{-1}(t) \, dt = \frac{2-\frac12}4 = \boxed{\frac38}[/tex]
What’s the circumference of circles
[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]
Let's find the circumference of given circle ~
Circumference :
[tex]\qquad \tt\dashrightarrow \:c =2 \pi r[/tex]
where,
r = radius = 3 ydnow, let's calculate circumference ~
[tex]\qquad \tt \dashrightarrow \:c = 2 \times \pi \times 3[/tex]
[tex]\qquad \tt \dashrightarrow \:c = 6 \pi \: \: yd[/tex]
Now, let's plug in approximate value of pi :
[tex]\qquad \tt \dashrightarrow \:c = 6 \times 3.14 \: \: [/tex]
[tex]\qquad \tt \dashrightarrow \:c = 18.84 \: \: yd[/tex]
In a history class, 30 students were asked about other courses that they were enrolled in: 20 said they were taking math, 22 were taking English and 26 students were in either math or English. a) How many students are taking both math and English b) How many are in neither c) What percent of the students are taking math but not English
16 students take both maths and english, 4 students took neither and 15.38% of the students are taking math but not English
What is probability?Probability is the likelihood of occurrence of an event. It is given by:
Probability = number of occurrence / total possible outcomes.
Let x represent the number of students that took both maths and english, hence:
Number of students taking only maths = 20 - x
Number of students taking only english = 22 - x
26 = 20 - x + (22 - x) + x
42 - x = 26
x = 16
b) Those who took neither = 30 - 26 = 4
c) those taking only math = 20 - 16 = 4.
Percentage = (4/26) * 100 = 15.38%
16 students take both maths and english, 4 students took neither and 15.38% of the students are taking math but not English
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What’s the area of this only answer if you know the answer if its correct I’ll give brainliest
Answer:
Area is 24 unit ²
Step-by-step explanation:
Given :-
Hypotenuse :- 10unitsBase:- 8unitsHeight:- 6unitsTo find:-
Area of triangleSolution:-
We know , The formula for finding area of triangle is 1/2×b×h
putting the known values ,
Area = 1/2 × 8 × 6 unit²
Area = 24 unit²
solve this arithmetic Progression
So, here in part a), we are given n terms (no specific no. of terms given), so no. of terms = n , also, the common difference is defined as the difference between the next term to a specific term and the term, i.e [tex]{\bf{d=a_{n}-a_{n-1}}}[/tex], where d is the common difference, so here d = 49 - 45 = 4
Also, here the last term is 49 let say it the nth term, as no number of terms are given, so using the Arithmetic Progression formula, we can write as ;
[tex]{:\implies \quad \sf a+(n-1)d=49}[/tex]
[tex]{:\implies \quad \sf a+(n-1)4=49}[/tex]
[tex]{:\implies \quad \sf a+4n-4=49}[/tex]
[tex]{:\implies \quad \sf a=49+4-4n=\boxed{\bf{53-4n}}}[/tex]
Now, as we assumed there are n terms, so using the sum formula, we can have ;
[tex]{:\implies \quad \sf S_{n}=\dfrac{n}{2}(a+a_{n})}[/tex]
[tex]{:\implies \quad \sf S_{n}=\dfrac{n}{2}(53-4n+49)}[/tex]
[tex]{:\implies \quad \sf S_{n}=\dfrac{n}{2}(102-4n)}[/tex]
[tex]{:\implies \quad \sf S_{n}=n(56-2n)=\boxed{\bf{-2n^{2}+56n}}}[/tex]
Now, for part b) we are given a geometric progression with first term = a = 1, common ratio = r = (3/1) = 3, and no. of terms = n = 6, so now putting all values in the sum formula we will have;
[tex]{:\implies \quad \sf S_{6}=\dfrac{1\{1-(3)^{6}\}}{1-3}}[/tex]
[tex]{:\implies \quad \sf S_{6}=\dfrac{1-729}{-2}}[/tex]
[tex]{:\implies \quad \sf S_{6}=\dfrac{-728}{-2}=\boxed{\bf{364}}}[/tex]
If 65% of a number is 234 and 10% of the same number is 36, find 75% of that number
65%= 234
100%= 234÷65×100
100%= 360
75%= 360÷100×75
75%= 270
help for (40 points) this is a k 12 thing
Answer:
4240 in²
rectangle prism area: 2(wl+hl+hw)
=======
area:
2*(20*36+25*36+25*20)4240 in²FIGURE ABCD BELOW IS A QUADRILATERAL. WHAT IS THE VALUE OF X ?
A. 15
B. 40
C. 45
D. 65
Answer:
x = 45
Step-by-step explanation:
Note that:
The sum of the interior angles of a quadrilateral is 360°.
Angle: ADC+BAD+ABC+BCD = 360°
Thus, Substitute ∠ABC = 3x, ∠BAD = (2x-5) , ∠ ADC = (x+15), ∠ BCD = 80 turn into ADC+BAD+ABC+BCD = 360° :
Also known as :
(x+15) +(2x-5) + 3x+80=360
Solving for x
Add the numbers
x + 90+2x+3x=360
Combine like terms
6x + 90=360
subtract 90 from both sides
6x = 270
x = 45
Hence the value of x = 45
Kavinsky
Answer:
C. 45
Step-by-step explanation:
1) Sum of the interior angles of any shape:
(n - 2) x 180, where n is the number of vertices of a shape. In this case, we have 4 vertices.
= (4 - 2) x 180
= 2 x 180
= 360°
2) Add all the given values equating to 360.
2x - 5 + 3x + 80 + x + 15 = 360
6x + 90 = 360
6x = 360 - 90
6x = 270
x = 270/6
x = 45
Which is the best example of an out-of-pocket cost?
A. A claim
B. A benefit
C. A deductible
D. A repair estimate
A best example of an out-of-pocket cost is: C. A deductible.
What is an Out-of-Pocket Cost?An out-of-pocket cost can be described as a cost you pay from your own personal reserve, which may include coinsurance, deductibles, copays, and some services covered by an individual's health plan.
Out-of-pocket cost may be reimbursed.
Thus, a best example of an out-of-pocket cost is: C. A deductible.
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Answer: C. A deductible
Step-by-step explanation:
write equivalent expressions 3(x-6)
Answer:
3(x-6)=3x-18
Step-by-step explanation:
If y - 18 = 14, what is the value of 3(y + 5)?
Answer:
y-18=14
add 18 on both sides
y=32
plug that into the equation below
3(Y+5)
3(32+5)
add 32 and 5
3(37)
multiply
3
....
3 x 37 = 111