Which ones are linear and nonlinear?

NEED ASAP
RIGHT ANSWER WILL GET MARKED AS BRAINLIEST

Answer:

It's C or the third option.

Step-by-step explanation: Edge 2021

Answer:

C.

Explaination:

just did on edge 2021

Answer:

The greatest common factor of 4 and 19 is 1

Step-by-step explanation:

Answer:

Greatest common factor of 4 and 19 is 1

Answer:

Step-by-step explanation:

0

Answer:

Yes

Step-by-step explanation:

Lol

Answer:

x= 75°

because 180°-105°=75°

Answer:

Step-by-step explanation:

well, every hour she drives, she loses 2 gallons. so when she was 2 hours in, she was at 8 gallons, when she was 1 hour in, she was at 10 gallons, and when she started, she was at 12 gallons.

Answer:

I pretty sure its C. OD-2) = 18

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

(✓x)^5

(x^1/2)^5

x^5/2

Answer:

4:3

16:12

Step-by-step explanation:

Both of those numbers can be multiplied or divided to equal 8:6

Answer:

1 solution

Step-by-step explanation:

4x + 5 = 6(x+3) - 20 - 2x

4x + 5 = 6x + 18 - 20 - 2x

4x + 5 = 4x -2

X = 3 therefore, there is only one solution

Answer:

6 [tex]\frac{1}{2}[/tex]

Step-by-step explanation:

you are adding 3 1/4 to 3 1/4 which is 6 2/4 or 6 1/2

or you can multiply 13/4 by 2 to get 26/4 or 13/2 which, again, is 6 1/2

Answer:

The difference of weight is [tex]2[/tex] pounds.

Step-by-step explanation:

Given:  The line plots shows the weights of [tex]9[/tex] grapefruits

To find: The difference in the total weight of all the [tex]1\frac{1}{2} lb[/tex]  grapefruits and the total weight of all the [tex]1 \frac{1}{4}lb[/tex] grapefruits.  

Firstly, we need to convert the given mixed fractions as following:

[tex]1\frac{1}{2} lb=\frac{2+1}{2}=\frac{3}{2}lb[/tex]

[tex]1\frac{1}{4} lb=\frac{4+1}{4}=\frac{5}{4}lb[/tex]

Now, we know that,

Point diagrams divide a sample into different classes, and allow to observe the frequencies of each class.

In this case, the different weights of the grapefruit constitute the classes. From a sample of 10 grapefruit, some will weigh  others weigh.

We need to observe the dot diagram to know how many  grapefruit we have of weight [tex]\frac{3}{2} lb[/tex] and how many  grapefruit we have of weight [tex]\frac{5}{4} lb[/tex]. In other words, we need to know, in the diagram, how many points there are about class of  [tex]\frac{3}{2} lb[/tex] and how many points there are about class of   [tex]\frac{5}{4} lb[/tex].

Then, the total difference between all grapefruit of  pounds and all grapefruit of pounds is calculated as follows:

[tex]x (1\frac{1}{2} ) - y (1\frac{1}{4} ) = Z[/tex]

Where

[tex]Z[/tex]: Weight difference

[tex]x[/tex]: Quantity of [tex]1\frac{1}{2} lb[/tex]  grapefruit

[tex]y[/tex]: Quantity of [tex]1\frac{1}{4}lb[/tex] grapefruit

Suppose that of the [tex]10[/tex] total grapefruits, [tex]3[/tex] of them weigh [tex]1\frac{1}{2} lb[/tex]  and [tex]2[/tex] of them weigh [tex]1 \frac{1}{4}[/tex]  pounds. This is: [tex]x=3[/tex] and [tex]y=2[/tex]

Now,

[tex]3(\frac{3}{2} )-2(\frac{5}{4} )[/tex]              

[tex]=\frac{9}{2} -\frac{5}{2}[/tex]                    

[tex]=\frac{4}{2}[/tex]            

[tex]=2[/tex]

Hence, for this case, the difference of weight is [tex]2[/tex] pounds.

Answer:

3 in a half miles

Step-by-step explanation:

Answer:

6 and 4

Is the answer

Answer:

It would be the 1st answer, y= 3/2x + 2.

Step-by-step explanation:

The intersection on the Y axis determins the "+2". To find the slope, it is always x/y. It rises 3, and runs 2. Hope this helps

Answer:

It is 3 because it is both in red and blue and that is the only section that shows it’s in both

Answer:3

Answer:

Call the line (d): y = ax + b

(d) intersects the vertical axis at the point where the intersection is 3 ⇒x = 0, y = 3 Instead of (d) we have: b = 3

(d) intersects the horizontal axis at the point where the coordinate is -1 ⇒x = −1, y = 0 Instead of (d) we have: −a + b = 0

Replace into b = 3 into -a + b = 0 we have: −a + 3 = 0⇔a = 3

So the equation for the line is y = 3x + 3

Step-by-step explanation:

Answer:

Number of tickets sold in advance = 310

Number of tickets sold  at the door = 340

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

For the school play, the advance tickets cost $3, while tickets at the door cost $5. Thirty more tickets were sold at the door than in advance, and $2630 was collected. How many of each kind of ticket were sold?

The explation of the answer is now given as follows:

Let a represents number of tickets sold in advance. Therefore, we have:

a = number of tickets sold in advance at $3 each

a + 30 = number of tickets sold  at the door at $5 each

The total amount collected can be represented by this equation:

3a + 5(a + 30) = 2630

Solving for a, wee have:

3a + 5a + 150 = 2630

8a = 2630 - 150

8a = 2,480

a = 2,480 / 8

a = 310

Therefore, this implies:

Number of tickets sold in advance = 310

Number of tickets sold  at the door = a + 30 = 310 + 30 = 340

Answer:

60%of 850

60×850÷100

=510

Answer:

x+3=5 is the answer you're looking for.

Answer:

x+3=5

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

z/4 - 11 = -9

z/4 = 2

z = 8

Answer:

[tex]y=\frac{11}{2}x-10[/tex]

Step-by-step explanation:

Answer: y= 11/2 x - 10

Step-by-step explanation: I think

Answer:

60

Step-by-step explanation:

The answer is 15 cm

39 cm, 15 cm, 36 cm

Answer: i think A(t)=30000−550(t−1)

Step-by-step explanation: