Answer:
[tex] \red{ \rule{1pt}{500000pt}}[/tex] [tex] \red{ \rule{1pt}{500000pt}}[/tex]
Explanation:
Difine Ripple Factor
-,- ty!!
Answer:
The answer is in the picture above.
-What is the potential energy at point A?
-What is the kinetic energy at point A?
-What is the kinetic energy at point B?
-What is the potential energy at point D?
-What is the kinetic energy at point D?
Answer:
1560520156Explanation:
Assuming there is no friction or other force involved, recall that energy is conserved in a system as long as no external force acts on the system.
Using the data from point C, we can find out that the total energy of the system is 156 because [tex]E = K+Pe[/tex].
Since at point A the object doesn't move, it has Kinetic energy of 0, because [tex]K=\frac{1}{2} mv^2[/tex], therefore [tex]0=\frac{1}{2} m0^2[/tex]. However at point A it has maximum Potential energy, because [tex]Pe=mgh[/tex].
At point B, we can find the Kinetic energy by using [tex]E = K+Pe[/tex]. Substitute values:
[tex]156=104+K\\52=K[/tex]
At point D, the object has maximum kinetic energy and no potential energy, therefore it's the opposite of point A.
Calculate the power developed by a 68.0 kg athlete who, in 20.0 seconds. runs up stairs that have a vertical height of 8.00 m
Potential energy:-
mgh68(8)(10)680(8)5440JNow
time=t=20sSo
Power:-
PE/t5440/20272WA rocket designed to place small payloads into orbit is carried to an altitude of 12.0 km above sea level by a converted airliner. When the airliner is flying in a straight line at a constant speed of 850 km/h, the rocket is dropped. After the drop, the airliner maintains the same altitude and speed and continues to fly in a straight line. The rocket falls for a brief time, after which its rocket motor turns on. Once its rocket motor is on, the combined effects of thrust and gravity give the rocket a constant acceleration of magnitude 3.00g directed at an angle of 30.0° above the horizontal. For reasons of safety, the rocket should be at least 1.00 km in front of the airliner when it climbs through the airliner’s altitude. Your job is to determine the minimum time that the rocket must fall before its engine starts. You can ignore air resistance. Your answer should include (i) a diagram showing the flight paths of both the rocket and the airliner, labeled at several points with vectors for their velocities and accelerations; (ii) an x-t graph showing the motions of both the rocket and the airliner; and (iii) a y-t graph showing the motions of both the rocket and the airliner. In the diagram and the graphs, indicate when the rocket is dropped, when the rocket motor turns on, and when the rocket climbs through the altitude of the airliner.
Answer:
Explanation:
A rocket designed to place small payloads into orbit is carried to an altitude of 12.0 km above sea level by a converted airliner. When the airliner is flying in a straight line at a constant speed of 850 km/h, the rocket is dropped. After the drop, the airliner maintains the same altitude and speed and continues to fly in a straight line. The rocket falls for a brief time, after which its rocket motor turns on. Once its rocket motor is on, the combined effects of thrust and gravity give the rocket a constant acceleration of magnitude 3.00g directed at an angle of 30.0° above the horizontal. For reasons of safety, the rocket should be at least 1.00 km in front of the airliner when it climbs through the airliner’s altitude. Your job is to determine the minimum time that the rocket must fall before its engine starts. You can ignore air resistance. Your answer should include (i) a diagram showing the flight paths of both the rocket and the airliner, labeled at several points with vectors for their velocities and accelerations; (ii) an x-t graph showing the motions of both the rocket and the airliner; and (iii) a y-t graph showing the motions of both the rocket and the airliner. In the diagram and the graphs, indicate when the rocket is dropped, when the rocket motor turns on, and when the rocket climbs through the altitude of the airliner.
Mrs. dela Vega had 27 students in her class last year and this year she had 30 students in her math class. What is the percent of difference?
Calculate the frequency of a sound wave produced when a tennis racquet string is plucked. The tension of the string is 274 N, the mass of the string is 28 kg and the length of the string is 0.74 m.
Answer:
Explanation:
The velocity of sound from the plucked string in the tennis racquet is:
[tex]v=\sqrt{\frac{FL}{m}}=\sqrt{\frac{274(0.74)}{28}}\approx 2.69 ms^{-1}[/tex]
Then the frequency will be:
[tex]f=\frac{v}{2L}=\frac{2.69}{2(0.74)}\approx 1.81 Hz[/tex]
Question 5 of 25
Which of the following statements are true of thermal energy and kinetic
energy?
Check all that apply.
A. Kinetic energy is the energy of motion of each molecule or atom.
B. Thermal energy is the energy of motion of all the molecules or
atoms.
C. Kinetic energy is the energy of motion of all the molecules or
atoms.
D. Thermal energy is the energy of motion of each molécule or atom.
SUBMIT
PREVIOUS
Answer:
i think B is the answer of the question
Answer: The answer is B and A
Explanation:
Two horses pull horizontally on ropes attached to a stump. The two forces Fu and F2 that they apply to the stump are such that the net (resultant) force R has a magnitude equal to that of Fu and makes an angle of 90° with Fu. Let F1 = 1300 N and R = 1300 N also. Find the magnitude of F and its direction (relative to Fi)
For two horses pull horizontally on ropes attached to a stump, the magnitude of F and its direction is mathematically given as
F=1711 N
dF= 135 degrees
What is the magnitude of F and its direction?
Generally, the equation for the components of F1 is mathematically given as
For The x axis
1210 - F2x = 0
F2x = 1210
For the y axis
F2y = R
F2y = 1210
In conclusion
F = sqrt(2)*1210
F=1711 N
Fopt the direction of F2
dF= 90 + 45
dF= 135 degrees
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A positive charge +Q is moving to the right and experiences a vertical (upward) magnetic force. In which direction is the magnetic field?
O into the screen
O upward
O out of the screen
O to the left
O to the right
Answer:
out of the screen
Explanation:
because charge +Q is already moving upward
1. A drag racer accelerates from rest at 18ft/sec^2. How long does it take to acquire a speed of 60mph? What is required?
2. A contestant ran a 100-m dash in 10.6sec. What was his speed a) In feet per second and b) in miles per hr?
(1) The time taken for the drag racer to accelerate is 4.89 s
(2) The speed of the contestant (a) in feet per second is 30.89 ft/s (b) in miles per hr is 21.12 miles per hr.
(1) To calculate the time required to accelerate 18 ft/sec² from rest to a velocity of 60 mph, we use the formula below.
Formula:
t = (v-u)/a........... Equation 1Where:
t = timev = Final velocityu = initial velocitya = acceleration.From the question,
Given:
a = 18 ft/sec² = (18×0.3048) = 5.4864 m/s²v = 60 mph = (60×0.44704) = 26.82 m/su = 0 m/s ( from rest)Substitute these values into equation 1
t = (26.82-0)/5.4864t = 4.89 seconds(2) To calculate the speed of the contestant, we use the formula below
Formula:
s = d/t............ Equation 1Where:
s = speed of the contestantd = distancet = time.From the question,
Given:
d = 100 mt = 10.6 sSubstitute these values into equation 1
s = 100/10.6s = 9.43 m/s(a) In feet = (9.43/0.3048) = 30.94 ft/s
(b) in miles per hr = (9.43×2.24) = 21.12 miles per hr
Hence, (1) The time taken for the drag racer to accelerate is 4.89 s (2) The speed of the contestant (a) in feet per second is 30.89 ft/s (b) in miles per hr is 21.12 miles per hr.
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why do fennec fox have big ears? explain why in big detail!
Answer:
Explanation:
The fennec may be the world's smallest fox, but it sports outlandishly large ears! In fact, relative to body size, it has the largest ears of any member of the canid family. It uses those big ears to listen for sounds of prey in the sand. The ears also help dispel body heat to keep the fox cool.
List the chemicals and apparatus
Answer:
Beaker
Graduated Cylinders
Volumetric flask
Test tube
Funnel
A 0.5 kg turntable with a radius of 15 cm is rotating 78 times per minute.
A. What is the angular momentum of the turntable?
B. A 100 gram bar which is as long as the diameter of the turntable is dropped on the
turntable such that the bar is rotating about its center. What is the new angular velocity of the turntable-bar system?
C. In order to stop the turntable and bar in just one rotation, how much force must be applied to the edge of the turntable (assuming the force is applied perpendicular to the radius)?
Answer:
c
Explanation:
4. The period of the sound wave produced by a 440 Hz tuning fork is
Answer:
.002273 seconds
Explanation:
1/f = period
1/ 440 c/s = .002273 seconds
A scientist decreases the wavelength of the light used in a double-slit experiment and keeps every other aspect the same. What will be true
about the new interference pattern seen on the screen compared to the original interference pattern? (point)
O The spacing between the bright fringes will increase.
O The spacing between the dark fringes will remain the sam
same.
O The spacing between the bright fringes will decrease.
O The spacing between the dark fringes will increase.
A scientist decreases the wavelength of the light used in a double-slit experiment and keeps every other aspect the same. The new interference pattern seen on the screen compared to the original interference pattern is the spacing between the bright fringes will increase. Thus, the correct option is A.
What is Interference pattern?Interference is the net effect of the combination of two or more wave forms or trains which are moving on intersecting or coincident paths in a medium. The effect of this pattern is that of the addition of the amplitudes of the individual waves at each point which are affected by more than one wave in the medium.
A scientist when decreases the wavelength of the light used in a double-slit experiment and it keeps every other aspect of the wave the same. The new interference pattern seen on the screen as compared to the original interference pattern is that the spacing between the bright fringes will increase.
Therefore, the correct option is A.
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Spring
The pulling force acting on an object is 350.0 N. It also is being affected by a 50.0 N
kinetic friction force. As a result, its acceleration is 3.0 m/s?, what is its mass?
A. 67 kg
B. 83 kg
C. 100 kg
D. 600 kg
E. 0.0 kg
If the gravitational force of the Farth nulling you"down" in th
Answer:
100 kg
Explanation:
Net force = 350 - 50 = 300 N
F= ma
300 N = m * 3 m/s^2
100 kg = mass
A wave is sent back and forth along a rope 4 m long with a mass of 0.6 kg by exerting a force a force of 30 N. Calculate the linear mass density of the rope (in kg/m).
The linear mass density of the rope in the given motion of the wave is 0.15 kg/m.
Linear mass density of the ropeThe linear mass density of the rope in the given motion of the wave is determined by dividing the mass of the rope with the length of the entire rope.
The linear mass density of the rope is calculated as follows;
μ = m/L
μ = 0.6 kg / 4 m
μ = 0.15 kg/m
Thus, the linear mass density of the rope in the given motion of the wave is 0.15 kg/m.
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Burns are a particular safety hazard when handling
Answer:
flammable liquids
Explanation:when it catches on fire your going to get burned.hope this helps.
Select all the correct answers.
A worker is holding a filled gas cylinder still. Which two sentences are true about the energy of the filled gas cylinder?
it has no energy because it's being held still.
It has gravitational potential energy because of its height
Its atoms and molecules have thermal energy.
0 It has motion energy because it will fall if let go.
its kinetic energy is being converted to potential energy.
Answer:
It has gravitational energy because of its height above some reference point.
It also contains thermal energy due to the motion of the contained atoms and molecules.
Answer:
b and c :)
Explanation:
A uniformly charged insulating rod is bent into the shape of a semicircle of radius R = 5 cm. If the rod has a total charge of Q = 3.10-9C, find the magnitude and direction of the electric field at O, the center of the circle.
Hi there!
We can begin by using Coulomb's Law:
[tex]E = \frac{kq}{r^2}[/tex]
k = Coulomb's Constant (8.99 × 10⁹ Nm²/C²)
E = Electric field strength (N/C)
r = distance from point (m)
q = charge (C)
Since this is a continuous charge, we must use calculus.
We can express this as the following:
[tex]q = \lambda L[/tex]
λ = Linear charge density (C/m)
L = Length of rod (m)
Now, since this is an arc, L = s (arc length). Additionally, we must find the differential elements of each:
[tex]dq = \lambda ds\\\\dq = \lambda rd\theta[/tex]
Our new equation is:
[tex]dE = \frac{kdq}{r^2}\\\\dE = \frac{k\lambda rd\theta}{r^2}[/tex]
However, we will only take the cosine component of the electric field since the vertical components will cancel out. (Electric fields are a vector). Therefore:
[tex]dE = \frac{k\lambda rd\theta}{r^2}cos\theta\\\\dE = \frac{k\lambda}{r}cos\theta d\theta[/tex]
Integrate. For a semicircle, the bounds will be from -π/2 to π/2.
[tex]E = \frac{k\lambda}{r}\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}}} {cos\theta} \, d\theta\\\\E = \frac{k\lambda}{r}sin\theta\left \|{\frac{\pi}{2}} \atop {-\frac{\pi}{2}}} \right. \\\\E = \frac{k\lambda}{r}(1 - (-1)) = \frac{2k\lambda}{r}[/tex]
We need to solve for λ, which is Q/ L:
[tex]\lambda = \frac{3.10 \times 10^{-9} C}{\pi (0.05)} = 1.9735 \times 10^{-8} \frac{C}{m}[/tex]
Now, plug and solve for the electric field strength:
[tex]E = \frac{2(8.99\times 10^9)(1.9735\times 10^{-8})}{0.05} = \boxed{7096.783 \frac{N}{C}}[/tex]
**A diagram was not provided, but if the hemisphere's focus was to the right, the electric field would be to the right, and etcetera.
A 75-W light bulb is turned on. It has an operating voltage of 120 V. (A)How much current flows through the bulb? (B)What is the resistance of the bulb? (C)How much energy is used each second?
Required Answer:
Given:
Power (P) = 75 W Voltage (V) = 120 V(A)
As we know that,
I = P/V↠ Current = 75/120
↠ Current = 0.625 A
(B)
R = V/IHere,
R is resistanceV is Voltage, and I is current↠ Resistance = 120/0.625
↠ Resistance = 192 Ω
(C)
Energy = P × tHere,
P is power T is time↠ Energy = 75 × 1
↠ Energy = 75 J
A 2 kg solid disk with a radius of 0.22 m has a tangential force of 300N applied to it.
a) What is the torque acting on the disk?
b) What is the moment of inertia of the disk?
c) What angular acceleration is produced by the torque?
d) If the disk starts from rest and the acceleration is constant for 3.0s, what is the angular velocity of the disk at the end of 3.0s?
e) Through what angle in radians has the disk rotated during this time?
(a) The torque acting on the disk is 66 Nm.
(b) The moment of inertia of the disk is 0.05 kgm².
(c) The angular acceleration is produced by the torque is 1,320 rad/s².
(d) The final angular velocity of the disk is 3,960 rad/s.
(e) The angle of rotation of the disk is 5,940 rad.
Torque acting on the diskThe torque acting on the disk is calculated as follows;
τ = Fr
τ = 300 x 0.22
τ = 66 Nm
Moment of inertiaThe moment of inertia of a solid disk is calculated as follows;
I = ¹/₂MR²
I = ¹/₂ x 2 x (0.22)²
I = 0.05 kgm²
Angular acceleration of the diskThe angular acceleration of the disk is calculated as follows;
τ = Iα
[tex]\alpha = \frac{\tau }{I} \\\\\alpha = \frac{66}{0.05} \\\\\alpha = 1,320 \ rad/s^2[/tex]
Angular velocity of the disk after 3 sωf = ωi + αt
ωf = 0 + (1320 x 3)
ωf = 3,960 rad/s
Angle of rotation of the diskωf² = ωi²+ 2αθ
(3,960)² = 0 + 2(1320)θ
θ = (3,960²) / (2 x 1320)
θ = 5,940 rad
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What season would Texas be having at point D?
Answer:
Almost winter so fall
Explanation:
Hope this helps! Please let me know if you want me to elaborate more or think my answer is incorrect. Brainliest would be MUCH appreciated. Have a wonderful day!
What is the wavelength of the wave pictured above?
Answer:
its counting by 4 the multi 4,8,12,16
a true statement of
kinetic theory
Answer:
real kinetic theory means that kinetic energy
How Does a Broken Bone Heal? Interactivity. Please i need the answer soon.
Answer:
The body develops a blood clot over the fractured bone in the first few days of a fracture to protect it and deliver the requisite cells for healing. Then, around the fractured bone, a field of healing tissue grows. This is referred to as a callus.
Explanation:
Answer:
Bone heals by making cartilage to temporarily plug the hole created by the break. This is then replaced by new bone. Many people think of bones as being solid, rigid, and structural. Bone is, of course, key to keeping our bodies upright, but it is also a highly dynamic and active organ
Explanation:
As water is cooled, its density increases until it reaches about
O A. 25° C
B. -2° C
O c. 4°C
O D.O°C
Answer:
4 degrees C
Explanation:
this is just a 'known'
a boat travels 500 m down a strait river. if starts from the rest accelerates uniformly to a velocity of 5m/s. how long does this take?
PLSSSS HELPPPPP NOWWW!!!!!
• (-/1 Points) DETAILS OSCOLPHYS2016 9.5.WA.040.
MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER
A supertanker uses a windlass (a type of winch) like the one shown in the figure below to hoist its 21,200-kg anchor. Determine the force that must be exerted on the
outside wheel to lift the anchor at constant speed, neglecting friction and assuming the anchor is out of the water.
IN
doorg
-0.45 m
- 1.5m
The force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.
Force exerted outside the wheelThe force exerted on the outside of the wheel can be determined by applying the principle of conservation of angular momentum as shown below.
∑τ = 0
Let the distance traveled by the load = 1.5 mLet the radius of the wheel or position of the force = 0.45 m∑τ = R(mg) - r(F)
rF = R(mg)
0.45F = 1.5(21,200 x 9.8)
F = 6.925 x 10⁵ N.
Thus, the force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.
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theshold frequency ???
Answer:
The threshold frequency is defined as the minimum frequency of the incident radiation below which photoelectric emission or emission of electrons is not possible. The threshold frequency refers to the frequency of light that will cause an electron to dislodge emit from the surface of the metal.