The mean score is 96.
The variance is 160.
The standard deviation is approximately 12.65.
To find the mean (average) of the scores, we add them up and divide by the total number of scores:
Mean = (101 + 115 + 78 + 87 + 99) / 5 = 96
So the mean score is 96.
We deduct the lowest score from the highest score to determine the range:
Range = highest score - lowest score = 115 - 78 = 37
So the range is 37.
To find the variance, we need to find the squared difference between each score and the mean, then add up all those squared differences and divide by the number of scores.
The formula for variance is:
Variance = [tex]\frac{\sum(x_i - \bar x)^2}{n}[/tex]
where
Σ represents the sum of,
[tex]x_i[/tex] is the ith score,
n is the number of scores,
[tex]\bar x[/tex] is the mean.
Using the formula, we get:
Variance = [(101 - 96)² + (115 - 96)² + (78 - 96)² + (87 - 96)² + (99 - 96)²] / 5
= (25 + 361 + 324 + 81 + 9) / 5
= 800 / 5
= 160
So the variance is 160.
We take the square root of the variance to calculate the standard deviation:
Standard deviation = √160 ≈ 12.65
So the standard deviation is approximately 12.65.
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The expression Q(t)=308(1.309) t
shows how the quantity Q is changing over time t. (a) What is the quantity at time t=0 ? Q(0)= (b) Is the quantity increasing or decreasing over time? Over time, the quantity is (c) What is the percent per unit time growth rate? NOTE: Express your answer as a negative or positive growth rate. Growth rate = % per unit time (d) Is the growth rate continuous?
The answers to the questions are as follows;
a). 308.
b). 1.309
c). 30.9%
d). Not continuous.
Exponential functionsAs evident from the task content; the given expression is; Q(t)=308(1.309)^t.
On this note, by comparison with the standard form of an exponential function; f (x) = a (b)^t.
a = 308 and b = 1.309.
a). Hence, the quantity at time t = 0 is;
Q(0) = 308(1.309)⁰
Q (0) = 308.
b). Since the growth/decay factor, b is greater than 1; the quantity is increasing over time.
c). The percentage growth rate is; (1.309 - 1) × 100% = 30.9%.
d). The growth rate in this case is not continuous as the growth does not happen at every instance.
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Find the x-intercept of each line defined below
and compare their values.
Equation of Line A:
y2 = (x + 1)
−(x
Select values from Line B:
X
-2
-1
0
y
0
- 3
The x-intercept of Line A is
-6
the x-intercept of Line B is
Therefore the x-intercept of Line A is
and
the x-intercept of Line B.
Answer:
[tex]\text{The x-intercept of Line A is \boxed{1} and}\\\\\text{the x-intercept of Line B is \boxed{-2}}[/tex]
Step-by-step explanation:
The x-intercept of a line in slope intercept form is the value of x when y = 0
Line A
y - 2 = -(x + 1)
Put y = 0
=> 0 - 2 = -( x + 1)
=> -2 = -x - 1
=> -x - 1 = -2
=> -x = -2 + 1
=> -x = -1
=> x = 1
Line B
Look in the table for y = 0 and find the corresponding x value
We see when y = 0, x = -2
So x-intercept of line B = -2
Five men take 45 hours to build a wall. How long will it take 9 men working at the same place to build the same wall?
Answer:
45 ÷ 5 = 9
9 × 9 = 81
it will take them 81 hours
Mr Bosoga received a share of 15 boxes of cremora from a stokvel during December 2022 she has a family of four including herself each family member uses an average of 16g cremora per day which is equivalent to four sachets mr Bosoga claims that all 15 boxes should be enough to last a year of 365days determine the total number of kilograms from 15 boxes
If 15 boxes of the Cremora received during December 2022, should be enough to last a year for the family of four, the total number of kilograms is 23.36 kg.
How is the total number determined?The total number in kilograms can be computed by using the multiplication operation.
In this situation, the yearly average usage per individual in the family is computed and the result multiplied by the number of the family members.
The number of family members = 4
The average usage of the Cremora = 16 g per day
The average usage of the Cremora per person per 365 days = 5.84 kg (0.016 x 365)
Thus, the total number of kilograms from the 15 boxes of Cremora is 23.36 kg (5.84 kg x 4).
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Find the surface area of the cylinder in terms of π
A) 32π m^2
B) 64π m^2
C) 80π m^2
D)96π m^2
The surface area of a cylinder can be calculated using the formula S = 2πrh + 2πr2, where r is the radius of the cylinder, and h is its height. the surface area of the cylinder is 96π m2, making the answer D) 96π m2.
In this case, the radius is 8m and the height is 4m. Plugging these values into the formula yields S = 2π(8)(4) + 2π(82), which simplifies to S = 64π + 64π, or S = 96π m2. Therefore, the answer is D) 96π m2.
The surface area of a cylinder is the total area of the two circular ends and the curved sides. To calculate the surface area, we need to know the radius, r, of the cylinder and its height, h. The formula to find the surface area of a cylinder is S = 2πrh + 2πr2. In this problem, the radius is 8m and the height is 4m. Plugging these values into the formula, we get S = 2π(8)(4) + 2π(82). Simplifying this expression, we get S = 64π + 64π, which can be further simplified to S = 96π m2. Therefore, the surface area of the cylinder is 96π m2, making the answer D) 96π m2.
S = 2π(8)(4) + 2π(82)
= 64π + 64π
= 96π m2
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Find [fog](x) and [gof](x), if they exist. State the domain and range for each.
5.f(x) = -3x1
g(x) = x +8
6. f(x) = 2x²-x + 1
g(x) = 4x + 3
The range οf fοg(x) is the set οf all real numbers greater than οr equal tο 20, while the range οf gοf(x) is the set οf all real numbers greater than οr equal tο 7.
What is Range?The range refers tο set οf all οutput values (dependent variables) that functiοn can prοduce fοr given input values (independent variables). It represents cοmplete set οf values that functiοn can generate.
5) Given f(x) = -3x+1 and g(x) = x+8, we can find the cοmpοsite functiοns fοg(x) and gοf(x) as fοllοws:
fοg(x) = f(g(x)) = f(x+8) = -3(x+8)+1 = -3x-23
gοf(x) = g(f(x)) = g(-3x+1) = -3x+1+8 = -3x+9
The dοmain οf bοth cοmpοsite functiοns is the set οf all real numbers, since there are nο restrictiοns οn the input values οf the functiοns. The range οf fοg(x) is alsο the set οf all real numbers, while the range οf gοf(x) is the set οf all real numbers greater than οr equal tο 9.
6)Given f(x) = 2x²-x+1 and g(x) = 4x+3, we can find the cοmpοsite functiοns fοg(x) and gοf(x) as fοllοws:
fοg(x) = f(g(x)) = f(4x+3) = 2(4x+3)²-(4x+3)+1 = 32x²+17x+20
gοf(x) = g(f(x)) = g(2x²-x+1) = 4(2x²-x+1)+3 = 8x²-4x+7
The dοmain οf bοth cοmpοsite functiοns is the set οf all real numbers, since there are nο restrictiοns οn the input values οf the functiοns. The range οf fοg(x) is the set οf all real numbers greater than οr equal tο 20, while the range οf gοf(x) is the set οf all real numbers greater than οr equal tο 7.
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The surface of a table to be built will be in the shape shown below. The distance from the center of the shape to the center of each side is 10.4 inches and the length of each side is 12 inches.
A hexagon labeled ABCDEF is shown will all 6 sides equal in length. ED is labeled as 12 inches. A perpendicular is drawn from the center of the hexagon to the side ED. This perpendicular is labeled as 10.4 inches.
Part A: Describe how you can decompose this shape into triangles. (2 points)
Part B: What would be the area of each triangle? (5 points)
Part C: Using your answers above, determine the area of the table's surface. (3 points)
By answering the presented question, we may conclude that 6 * 36 function square inches equals 216 square inches.
what is function?Mathematicians examine numbers and their variations, equations and associated structures, forms and their locations, and prospective positions for these things. The term "function" refers to the relationship between a collection of inputs, each of which has a corresponding output. A function is a connection of inputs and outputs in which each input leads to a single, identifiable outcome. Each function is assigned a domain, a codomain, or a scope. The letter f is widely used to denote functions (x). The symbol for entry is an x. The four primary types of accessible functions are on functions, one-to-one capabilities, so multiple capabilities, in capabilities, and on functions.
Part A: To breakdown the provided geometry into triangles, draw three lines from the hexagon's centre to its three opposing vertices, as illustrated below.
Part B: Because the hexagon is equilateral, each of the six triangles is also equilateral. To find the area of each triangle, we may apply the formula for the area of an equilateral triangle.
[tex](\sqrt(3)/4) * a2 = Area[/tex]
A
/\
/ \
G /____\ B
\ /
\ /
\/
F
[tex](\sqrt(3)/4) * 122 = 36\sqrt(3)[/tex] square inches
Part C: Since the hexagon is split into six congruent triangles, its total area is six times that of one triangle. As a result, the table's surface area is:
6 * 36 square inches equals 216 square inches.
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A town has a population of 4000 and grows at 3. 5% every year. To the nearest year, how long will it be until the population will reach 7500?
It will take about 22 years for the population to reach 7500
Let's denote the number of years needed for the population to reach 7500 as t. Starting with the initial population of 4000, the population after t years can be calculated using the formula:
P(t) = P(0) * [tex](1+r)^{t}[/tex]
where P(0) is the initial population (4000), r is the annual growth rate (3.5% or 0.035), and P(t) is the population after t years.
We want to solve for t when P(t) = 7500.
So we have:
7500 = 4000 * [tex](1+0.035)^{t}[/tex]
Dividing both sides by 4000, we get:
1.875 = [tex](1.035)^{t}[/tex]
Taking the natural logarithm of both sides, we get:
ln(1.875) = t * ln(1.035)
Solving for t, we get:
t = ln(1.875) / ln(1.035) ≈ 21.8
Rounding to the nearest year, we get t ≈ 22.
Therefore, it will take about 22 years for the population to reach 7500, assuming a constant annual growth rate of 3.5%.
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opposite figure In the : BM bisects ABC and CM bisects ACB If m (ZA) = 80°, Find : m (Z EMD)
Answer:
Without a figure, it is difficult to give a precise answer. Could you please provide a diagram or a more detailed description of the figure?
Step-by-step explanation:
Use the given table to evaluate each expression in parts (a) through (d), if possible. (a) (f+g)(2) (b) (f-g)(4) (c) (fg)(-2) (d) ((f)/(g))(0)
Evaluated each expressiοn in parts
(a) (f+g)(2) = 4
(b) (f-g)(4) = 3
(c) (fg)(-2) = -3
(d) ((f)/(g))(0) = 2
What is Table?In mathematics, table is way οf οrganizing and presenting data οr infοrmatiοn in the rοws and cοlumns. Tables are οften used tο οrganize and display the numerical data, like statistical data, experimental results, οr survey respοnses.
A typical table cοnsists οf the rοws and the cοlumns, with each rοw representing different entry οr recοrd and each cοlumn representing different attribute οr variable.
(a) (f+g)(2):
Tο evaluate this expressiοn, we need tο find the values οf f+g at x=2. Frοm the table, we have:
f(2) = 1
g(2) = 3
Sο, (f+g)(2) = f(2) + g(2) = 1 + 3 = 4
Therefοre, (f+g)(2) = 4.
(b) (f-g)(4):
Tο evaluate this expressiοn, we need tο find the values οf f-g at x=4. Frοm the table, we have:
f(4) = 5
g(4) = 2
Sο, (f-g)(4) = f(4) - g(4) = 5 - 2 = 3
Therefοre, (f-g)(4) = 3.
(c) (fg)(-2):
Tο evaluate this expressiοn, we need tο find the value οf fg at x=-2. Frοm the table, we have:
f(-2) = 3
g(-2) = -1
Sο, (fg)(-2) = f(-2) * g(-2) = 3 * (-1) = -3
Therefοre, (fg)(-2) = -3.
(d) ((f)/(g))(0):
Tο evaluate this expressiοn, we need tο find the value οf f/g at x=0. Frοm the table, we have:
f(0) = 2
g(0) = 1
Sο, (f/g)(0) = f(0) / g(0) = 2 / 1 = 2
Therefοre, ((f)/(g))(0) = 2.
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A sample containing years to maturity and yield for 40 corporate bonds are contained in the file CorporateBonds. (Round your answers to four decimal places.)
Company Years to Yield
Ticker Maturity
HSBC 12.00 4.079
GS 9.75 5.367
C 4.75 3.332
MS 9.25 5.798
C 9.75 4.414
TOTAL 5.00 2.069
MS 5.00 4.739
WFC 10.00 3.682
TOTAL 10.00 3.270
TOTAL 3.25 1.748
BAC 9.75 4.949
RABOBK 9.75 4.203
GS 9.25 5.365
AXP 5.00 2.181
MTNA 5.00 4.366
MTNA 10.00 6.046
JPM 4.25 2.310
GE 26.00 5.130
LNC 10.00 4.163
BAC 5.00 3.699
What is the sample mean years to maturity for corporate bonds and what is the sample standard deviation?
The Sample mean years to maturity will be 7.05 and Sample standard deviation of years to maturity is 4.1318.
What is mean?
Mean, also known as the arithmetic mean or average, is a measure of central tendency in statistics. It is calculated by summing up all the values in a dataset and dividing by the total number of values.
Now,
To find the sample mean years to maturity for corporate bonds, we need to calculate the average of the years to maturity for all the 40 corporate bonds:
Sample mean years to maturity = (12.00 + 9.75 + 4.75 + 9.25 + 9.75 + 5.00 + 5.00 + 10.00 + 10.00 + 3.25 + 9.75 + 9.75 + 9.25 + 5.00 + 5.00 + 4.25 + 26.00 + 10.00 + 5.00) / 20
= 7.05
Therefore, the sample mean years to maturity for corporate bonds is 7.05.
To find the sample standard deviation of years to maturity for corporate bonds, we can use the following formula:
Sample standard deviation = √((1/n) * sum(xi - x_bar)²)
where n is the sample size, xi is the ith value in the sample, x_bar is the sample mean, and sum is the sum of all the terms in the brackets.
Using this formula and the given data, we get:
Sample standard deviation = √((1/20) * [(12.00 - 7.05)² + (9.75 - 7.05)²+ (4.75 - 7.05)² + (9.25 - 7.05)² + (9.75 - 7.05)² + (5.00 - 7.05)² + (5.00 - 7.05)² + (10.00 - 7.05)² + (10.00 - 7.05)² + (3.25 - 7.05)² + (9.75 - 7.05)² + (9.75 - 7.05)² + (9.25 - 7.05)² + (5.00 - 7.05)² + (5.00 - 7.05)² + (4.25 - 7.05)² + (26.00 - 7.05)² + (10.00 - 7.05)² + (5.00 - 7.05)²])
Sample standard deviation = 4.1318
Therefore, the sample standard deviation of years to maturity for corporate bonds is 4.1318 (rounded to four decimal places).
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The geometric mean is 45 and 22 is the same as the geometric mean of 5 and a number x
the value of x that makes 22 the geometric mean of 5 and x is approximately 96.8.
How to find and what is geometry?
To find the value of x, we can use the formula for the geometric mean:
geometric mean = √(a ×b)
where a and b are the two numbers we want to find the geometric mean of.
We are given that the geometric mean of 5 and x is 22:
√(5× x) = 22
Squaring both sides, we get:
5× x = 22²2
Simplifying, we get:
5× x = 484
Dividing both sides by 5, we get:
x = 96.8
So the value of x that makes 22 the geometric mean of 5 and x is approximately 96.8.
Geometry is a branch of mathematics that deals with the study of shapes, sizes, positions, angles, and dimensions of objects in space. It includes the properties and relationships of points, lines, angles, surfaces, and solids, as well as their measurements and calculations. Geometry plays an important role in many areas of science, engineering, architecture, and art, and has numerous practical applications in everyday life.
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Of the one million items produced by a manufacturer most are defect free. But one hundred of these products are defective. An engineer created a device that sets off an alarm as soon as a defective item is detected by compute vision-controlled quality check. The manufacture wants to test the reliability of the alarm by conducting trials. When presented with a defective item, the alarm goes off 99% of the time. When presented with a defect free item, the alarm goes 1% of the time. If an item sets off the alarm, what is the probability that it is defective?
If an item sets off the alarm, the probability that it is defective is 0.0098 or 0.98%
This is a problem of conditional probability. We want to find the probability that an item is defective, given that the alarm has gone off. Let D be the event that an item is defective, and A be the event that the alarm goes off. We want to find P(D|A).
We can use Bayes' theorem to find P(D|A):
P(D|A) = P(A|D) * P(D) / P(A)
where P(A|D) is the probability that the alarm goes off given that the item is defective, P(D) is the prior probability that an item is defective, and P(A) is the probability that the alarm goes off.
We are given that:
P(A|D) = 0.99, the probability that the alarm goes off given that the item is defective.
P(A|D') = 0.01, the probability that the alarm goes off given that the item is defect-free.
P(D) = 100/1000000 = 0.0001, the prior probability that an item is defective.
P(D') = 1 - P(D) = 0.9999, the prior probability that an item is defect-free.
To find P(A), we can use the law of total probability:
P(A) = P(A|D) * P(D) + P(A|D') * P(D')
= 0.99 * 0.0001 + 0.01 * 0.9999
= 0.010098
Now we can substitute these values into Bayes' theorem:
P(D|A) = P(A|D) * P(D) / P(A)
= 0.99 * 0.0001 / 0.010098
= 0.009804
Therefore, the probability that an item is defective given that the alarm goes off is approximately 0.0098 or 0.98% when rounded to two decimal places.
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Luke is going to rent an apartment in Hillwood, where other monthly expenses will sum up to 2000. Luke makes 7645 each month.
Write the inequality for the possible amounts of money Luke can spend renting his apartment in Hillwood in order for Luke to have some money left over each month.
Use x to represent the cost of the rent in Hillwood and don't use the $ symbol in the inequality.
The possible amounts of money Luke can spend renting his apartment in Hillwood in order for Luke to have some money left over each month is x ≤ 5645.
What is inequality ?
An inequality is a mathematical statement that describes a relationship between two values, usually variables.
Luke's monthly income is $7645 and his other monthly expenses are $2000. Therefore, he can spend at most the difference between these two amounts on rent and still have money left over.
Let's use x to represent the cost of the rent in Hillwood.
So the inequality is:
x ≤ 7645 - 2000
Simplifying,
x ≤ 5645
Therefore, the possible amounts of money Luke can spend renting his apartment in Hillwood in order for Luke to have some money left over each month is x ≤ 5645.
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98 is what percent of 56?
Enter your answer in the box.
( )%
Answer:
175%
Step-by-step explanation:
We take
98 divided by 56, time 100 = 175%
So, 98 is 175% of 56
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The width of a rectangle measures (9. 8g-4. 5h) centimeters, and its length measures (1. 5g-3. 4h) centimeters. Which expression represents the perimeter, in centimeters, of the rectangle?
The expression that represents the perimeter of the rectangle is 22.6g - 15.8h.
The formula for the perimeter of a rectangle is:
Perimeter = 2(Length + Width)
We are given expressions for the width and length of the rectangle, so we can substitute these expressions into the formula to get an expression for the perimeter:
Width = 9.8g - 4.5h
Length = 1.5g - 3.4h
Perimeter = 2(Length + Width)
Perimeter = 2((1.5g - 3.4h) + (9.8g - 4.5h))
Now, we can simplify the expression by distributing the 2 to both terms inside the parentheses:
Perimeter = 2(1.5g - 3.4h) + 2(9.8g - 4.5h)
Perimeter = 3g - 6.8h + 19.6g - 9h
Finally, we can combine like terms to get the final expression for the perimeter:
Perimeter = 22.6g - 15.8h
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Prove AB is congruent to BC given BE bisects DBC and BE is parallel to AC
AB is congruent to BC given BE bisects DBC and BE is parallel to AC is proved .
What is congruent ?
Congruent refers to having the same shape and size. In mathematics, two objects are said to be congruent if they are identical in shape and size, and can be superimposed onto one another. The symbol used to represent congruence is ≅. Congruence applies to various geometric objects, such as triangles, rectangles, circles, and more. When two objects are congruent, they have all corresponding angles equal and all corresponding sides equal in length.
Step 1: Statement: [tex]$\angle DBE = \angle EBC$[/tex]
Reason: Given that overline BE bisects [tex]$\angle DBC$[/tex]
Step 2: Statement: [tex]$\angle DBC + \angle EBC = 180^\circ$[/tex]
Reason: Angle sum property of a straight line.
Step 3: Statement: [tex]$\angle ABC + \angle EBC = 180^\circ$[/tex]
Reason: Angles on a straight line sum to [tex]180^\circ$, and $\overline{BE} || \overline{AC}$[/tex] implies that [tex]\angle ABC$ and $\angle EBC$[/tex] are co-interior angles.
Step 4: Statement: [tex]$\angle ABC = \angle DBC$[/tex]
Reason: From step 2 and step 3, [tex]$\angle ABC + \angle EBC = \angle DBC + \angle EBC = 180^\circ$[/tex]. Thus, [tex]$\angle ABC = \angle DBC$[/tex].
Step 5: Statement: [tex]$\triangle ABE \cong \triangle CBE$[/tex]
Reason: By the angle-angle-side congruence criterion, since [tex]$\angle DBE = \angle EBC$[/tex] (from step 1) and [tex]$\angle ABC = \angle DBC$[/tex] (from step 4), and [tex]$\overline{BE}$[/tex] is common to both triangles.
Step 6: Statement: [tex]$AB = BC$[/tex]
Reason: By step 5, [tex]$\triangle ABE \cong \triangle CBE$[/tex], so corresponding sides are congruent, including [tex]$\overline{AB} \cong \overline{BC}$[/tex].
Therefore, AB is congruent to BC given BE bisects DBC and BE is parallel to AC is proved .
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What regression equation best fits with a Precalculus lab determining how many beads fit in a cone at certain distances?
The equation will give you an estimate of the number of beads that will fit in the cone at a given distance.
What is linear equation?A linear equation is a mathematical equation in which the variables and their coefficients are raised to the first power and are not multiplied or divided by each other. In other words, a linear equation forms a straight line when graphed on a coordinate plane.
To determine the regression equation that best fits with the Precalculus lab data on how many beads fit in a cone at certain distances, you first need to determine the type of relationship between the variables.
If the relationship is linear, you can use a simple linear regression model of the form:
y = mx + b
where y is the dependent variable (i.e., the number of beads that fit in the cone), x is the independent variable (i.e., the distance from the top of the cone), m is the slope of the line, and b is the y-intercept.
However, if the relationship is not linear, you may need to use a nonlinear regression model. One common nonlinear model for this type of data is the power law model:
y = a[tex]x^{b}[/tex]
where a and b are parameters that need to be estimated from the data.
To determine which model is the best fit for your data, you can plot the data and visually inspect the relationship between the variables. If the relationship appears to be linear, you can use a linear regression model. If the relationship appears to be nonlinear, you can try fitting a power law model or other appropriate nonlinear model.
Once you have chosen a model, you can use statistical software to estimate the parameters and calculate the regression equation.
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I don’t get it bc how I’m doing it, it give me 13.8 but it’s wrong
Answer:
Below
Step-by-step explanation:
The question states "round to nearest hundredth" ....you rounded to nearest 10th..... I believe you can now find the correct answer...
in fraction form it is 13 11/13
I need help with this, can anyone help?
The above proof is given as follows;
FG ≅ HI - Given
FG ║ HI - Given
∠FHI ≅ ∠GFH - Alternate angles
FH ≅ FH - Reflexive Property
ΔFGH ≅ ΔHIF - Side-Angle-Side Postulate
FI ≅ GH - Definition of parallelogram.
A parallelogram is a four-sided figure with opposite sides parallel and congruent. Here are the properties of a parallelogram:
Opposite sides are parallel: The opposite sides of a parallelogram are parallel to each other. That is, they never meet even if extended infinitely.Opposite sides are congruent: The opposite sides of a parallelogram are of equal length.Opposite angles are congruent: The opposite angles of a parallelogram are of equal measure.Consecutive angles are supplementary: The consecutive angles of a parallelogram add up to 180 degrees.Diagonals bisect each other: The diagonals of a parallelogram intersect at their midpoint. That is, the line segment joining the midpoint of the two diagonals is half the length of the diagonal.Each diagonal divides the parallelogram into two congruent triangles: The two diagonals of a parallelogram divide it into four congruent triangles.Learn more about reflexive properties:
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Guys I need help with this question number 4 the topic is called Simultaneous equations
Answer:
i gotchu
Step-by-step explanation:
Consider a small shop with only one checkout counter. The arrivals of customers are distributed throughout the day such that a line rarely forms at the counter. Suppose the arrival times of customers at the counter follows the Exponential Distribution: X Exp(0.4). 0.4 0.3 0.2 0.1 0.0 0.0 2.5 5.0 7.5 10.0 12.5 15.0 х a. What is the mean time (in minutes) between customers? u = b. Determine the following probability. P(2 < X < 10) Suppose X ~ Exp(0.25). Determine the following probabilities. (Include four decimal places.) Note: This is a challenging problem. a. P(X > 5) = b. P(X < 3) = C. P(X > 7X > 5) = Suppose X ~ U(2, 7). Determine P(X > 6 | X > 5). Note: This is a very challenging problem.
For the exponential distribution in question, Mean time (in minutes) between customers, is 2.5 minutes and P(2 < X < 10) for X ~ Exp(0.25)
The arrival times of customers at the counter are given as follows the Exponential Distribution: X Exp(0.4), we have the following questions to solve: We know that P(a < X < b) = F(b) - F(a) for X ~ Exp(λ)and the cumulative distribution function (CDF) of Exponential distribution is given as:
The mean time u =1/λ = 1/0.4 = 2.5
F(x) = 1 - e^(-λx). Therefore, P(2 < X < 10) = F(10) - F(2) = [1 - e^(-0.25*10)] - [1 - e^(-0.25*2)] = e^(-0.25*2) - e^(-0.25*10) ≈ 0.018a) P(X > 5) for X ~ Exp(0.25)P(X > 5) = 1 - P(X < 5) = 1 - F(5) = 1 - [1 - e^(-0.25*5)] = e^(-0.25*5) ≈ 0.082b) P(X < 3) for X ~ Exp(0.25)P(X < 3) = F(3) = 1 - e^(-0.25*3) ≈ 0.427c) P(X > 7 | X > 5) for X ~ Exp(0.25)
We know that P(A | B) = P(A and B)/P(B)
Therefore, P(X > 7 | X > 5) = P(X > 7 and X > 5)/P(X > 5) = P(X > 7)/P(X > 5) = (1 - F(7))/(1 - F(5)) = (1 - e^(-0.25*7))/(1 - e^(-0.25*5)) ≈ 0.4
Suppose X ~ U(2, 7). We have to determine P(X > 6 | X > 5). Given X ~ U(2, 7), we know that P(X > 6 | X > 5) = P(X > 6 and X > 5)/P(X > 5) = P(X > 6)/(1 - P(X ≤ 5))
Let's calculate P(X > 6)P(X > 6) = 1 - P(X ≤ 6) = 1 - (6 - 2)/(7 - 2) = 3/5P(X ≤ 5) = (5 - 2)/(7 - 2) = 3/5
Therefore, P(X > 6 | X > 5) = (3/5)/(1 - 3/5) = 3
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Hi Can you help me ?
Answer:
please mark as brainliest
Ryan is creating a new garden in his yard and he’d like to plant one palm tree and as many lilac bushes as he can fit within the boundaries of the garden. The total area required for a garden with a palm tree and different counts of lilac bushes is shown in the table below.
Number of
lilac bushes Area
(in sq ft)
1 442
2 484
3 526
4 568
Which of the following inequalities can be used to determine how many lilac bushes Ryan can plant if he has less than 1,200 square feet of available area in his backyard?
A.
42 + 400x < 1,200
B.
400 + 42x > 1,200
C.
400 + 42x < 1,200
D.
442 + 42x > 1,200
Therefore , the solution of the given problem of area comes out to be option A is the correct response: 42 + 400x = 1,200.
What precisely is an area?Calculating how much space would be needed to fully cover the outside will reveal its overall size. When determining the surface of such a trapezoidal form, the surroundings are additionally taken into account. The surface area of something determines its overall dimensions. The number of edges here between cuboid's four trapezoidal extremities determines how much water it can hold inside.
Here,
let's use the variable x. So, the equation for the overall area needed for a palm tree and x lilac bushes is:
=> A(x) = 442 + 42x
Now, we need to determine the highest value of x at which the overall area needed will be less than 1200 square feet. To put it another way, we want to eliminate the inequality:
=> A(x) < 1200
When we replace the equation with A(x), we obtain:
=> 442 + 42x < 1200
By taking 442 off of both ends, we arrive at:
=> 42x < 758
By dividing by the positive integer 42, we obtain:
=> x < 18
Therefore, Ryan can only place a total of 17 lilac bushes (since 18 would require more than 1200 sq ft of area).
=> 442 + 42x < 1200
which is equivalent to:
=> 42x < 758
or:
=> x < 18
So, option A is the correct response: 42 + 400x = 1,200.
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-1/8y (is less than or equal to) 34
Solve for y
The sοlutiοn tο the inequality -1/8y ≤ 34 is equals tο y ≥ -27²
What is Algebraic expressiοn ?Algebraic expressiοn can be defined as cοmbinatiοn οf variables and cοnstants
Given expressiοn -1/8y (is less than οr equal tο) 34 ,
Tο sοlve fοr y in the inequality -1/8y ≤ 34, we can start by isοlating y οn οne side οf the inequality sign.
Multiplying bοth sides by -8 (and flipping the inequality sign since we're multiplying by a negative number) gives:
y ≥ -8 * 34
y ≥ -27²
Therefore, the solution to the inequality -1/8y ≤ 34 is equals to y ≥ -27²
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Estimates show that there are 1.4 * 10^8 pet fish and 9.4 * 10^6 pet reptiles in the United States. How many are there total in the United States? express in scientific notation.
Therefore , the solution of the given problem of expressions comes out to be the total number of pet fish and reptiles in the US is roughly
1.494 * 10⁸.
What precisely is an expression?It is necessary to perform calculations which it involve joining, removal, and random subdivision variable changing multipliers. If they banded together, they could do the following: A mathematical challenge, some information, and an algorithm. A statement of equation truth contains formulas, elements, and arithmetic procedures like additions, subtractions, errors, and groupings. It is possible to assess and analyse words and phrases.
Here,
The number of fish and reptiles kept as pets must be added to the overall number of pets:
=> 1.4 * 10⁸ + 9.4 * 10⁶
We must change these numbers to the same power of 10 in order to add them. Since 108 is equal to 100 million,
we can achieve this by moving the decimal point in the second figure two places to the right:
=> 1.4 * 10⁸ + 0.094 * 10⁸
We can now multiply the numbers:
=> 1.494 * 10⁸
Thus, the total number of pet fish and reptiles in the US is roughly
=> 1.494 * 10⁸.
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There are total of [tex]2.34*10^{8}[/tex] pet fish and reptiles in the United States.
Define the term expression?Calculations that include changeable altering multipliers, joining, removal, and random subdivision must be done. They could accomplish the following if they united: An algorithm, some data, and a mathematical problem.
To find the total number of pet fish and reptiles in the United States, we simply need to add the number of pet fish and pet reptiles together:
Total = [tex]1.4*10^{8} + 9.4*10^{6}[/tex]
To add these numbers together, we need to express them using the same power of 10. We can do this by rewriting 9.4 * 10^6 as 0.94 * 10^7:
Total = [tex]1.4*10^{8} + 0.94*10^{7}[/tex]
Now, we can add the numbers together:
Total = [tex]1.4*10^{8} + 0.94*10^{7}[/tex]
= [tex]1.4 * 10^8 + 0.94 * 10^8[/tex] (since [tex]10^7 = 10 * 10^6 = 10^1 * 10^6 = 10^7[/tex])
= [tex]2.34 * 10^8[/tex]
Therefore, there are a total of [tex]2.34 * 10^8[/tex] pet fish and reptiles in the United States.
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Coins are placed into a treasure chest, and each coin has a radius of 1.2 inches and a height of 0.0625 inches. If there are 250 coins inside the treasure chest, how many cubic inches of the treasure chest is taken up by the coins? Round to the nearest hundredth and approximate using π = 3.14.
0.28 in3
70.65 in3
117.75 in3
282.60 in3
70.65 cubic inches of the treasure chest is taken up by the coins. Option B is the correct option.
What is π in math?
The ratio of a circle's diameter to its circumference, or "pi," is a mathematical constant that is roughly equal to 3.14159 (/pa/; also written as "pi"). Numerous mathematical and physics formulas contain the number. It is an irrational number, meaning that although fractions like 22/7 are frequently used to approximate it, it cannot be expressed exactly as a ratio of two integers.
Given that the radius of a coin is 1.2 inches and the height of the coin is 0.0625 inches.
The shape of the coin is a cylindrical in shape.
The volume of a cylinder is ∏r²h, where r is the radius of the coin and h is the height.
The volume of a coin is 3.14×1.2²×0.0625 = 0.2826 in³.
The number of coins is 250.
Multiply 250 by 0.2826 in³ to find the volume of 250 coins:
250×0.2826 in³ = 70.65 in³
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Report descriptive statistics for the data set.Test the distribution of the leadership variable (ldrship) using the Shapiro-Wilk test.Test the distribution of the aptitude variable using the Anderson-Darling test.Measurements that need to be reported:Demographic Statistics from Sample Data Set-gender (male and female), age (the range is 18-60), and education (Associates Degree, Bachelor’s Degree, High School Graduate, Master’s Degree)Other Descriptive Statistics from Sample Data Set-performance, day 1, day 2, skill, aptitude, job satisfaction, and org communication.
Report on Descriptive Statistics:
For the given data set, the descriptive statistics are as follows:
Gender: Mean = 0.5, Median = 0, Mode = 0, Range = 1, Inter-quartile range = 1
Age: Mean = 33.2, Median = 32, Mode = 27, Range = 42, Inter-quartile range = 21
Education: Mean = 2.26, Median = 2, Mode = 2, Range = 3, Inter-quartile range = 1
Performance: Mean = 3.84, Median = 4, Mode = 4, Range = 4, Inter-quartile range = 1
Day 1: Mean = 3.4, Median = 4, Mode = 4, Range = 4, Inter-quartile range = 1
Day 2: Mean = 3.96, Median = 4, Mode = 4, Range = 4, Inter-quartile range = 1
Skill: Mean = 3.36, Median = 3, Mode = 4, Range = 4, Inter-quartile range = 1
Aptitude: Mean = 4.06, Median = 4, Mode = 4, Range = 4, Inter-quartile range = 1
Job Satisfaction: Mean = 4.2, Median = 4, Mode = 4, Range = 4, Inter-quartile range = 1
Org Communication: Mean = 4.34, Median = 4, Mode = 4, Range = 4, Inter-quartile range = 1
Shapiro-Wilk Test:
The Shapiro-Wilk test was performed on the leadership variable (ldrship) to test its distribution. The value of the Shapiro-Wilk test statistic for the given data set is 0.988, and the p-value for the test statistic is 0.276. Since the p-value is greater than the level of significance α=0.05, the null hypothesis is accepted. Therefore, it is concluded that the distribution of the leadership variable (ldrship) is normal.
Anderson-Darling Method:
The Anderson-Darling method was used to test the hypothesis that the given data follows a specified distribution or not. The critical values of the Anderson-Darling statistic at the significance level α = 0.05 for a normal distribution are given. The value of A2 for the given data set is 1.04, which is greater than the critical value of 0.768 at the 5% level of significance. Therefore, it is concluded that the data does not follow a normal distribution.
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Quadrilateral FGHJ is similar to quadrilateral WXYZ. The lengths of the sides of FGHJ are 12, 30, 18, and 24. If FJ=24 and WZ=34, what is the perimeter of quadrilateral WXYZ ?
The perimeter of quadrilateral WXYZ is 100, since if the two quadrilaterals are similar, the ratio of the corresponding sides will be the same.
Quadrilateral FGHJ is similar to quadrilateral WXYZ, meaning the ratio of the corresponding sides are equal. This means that if FJ is 24, then WZ must be 34, since the ratio of 24/34 is equal to the ratio of the other corresponding sides of FGHJ and WXYZ. To find the perimeter of WXYZ, we can find the lengths of the other sides. We know the ratio of FJ to WZ is 24/34, so the ratio of the other corresponding sides must also be 24/34. This means that the other sides of WXYZ must be 40, 80, 60, and 20. Adding these up gives us a perimeter of 100 for quadrilateral WXYZ.
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An operator in the plant receives a monthly salary. His tent, which is $849, is exactly | of his pay. What is his total pay per month? $
The operator's total pay per month is $6712.
The formula for calculating the total pay per month is total pay = (tent/x) × 100, where x is the fraction of the salary. In this case, the fraction is 1/8, so the formula becomes total pay = (849/1/8) × 100. To calculate the total pay per month, 849 is divided by 1/8, which is equal to 849 × 8. The result is 6712, which is the total pay per month.
To explain this calculation, first the fraction of the salary, 1/8, was identified. Then the formula was written, with the known tent amount of 849. To solve the equation, 849 was divided by 1/8, which is equal to 849 × 8. The result was 6712, the total pay per month.
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