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Answer:
Explanation:
Related Questions
4y - 6 = 2y + 8how to solve this equation
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To solve this equation, we need to collect like terms
To collect like terms, we bring the terms similar to each other to the same side
In this case, the value having y will be brought to same side of the equation
Kindly note that if we are bringing a particular value over the equality sign, then the sign of the value has to change
This means if negative, it becomes positive and if positive, it becomes negative
Proceeding, we have
4y - 2y = 8 + 6
2y = 14
divide both sides by 2
2y/2 = 14/2
y = 7
The value of y in this equation is 7
1) A car is traveling down a highway at a constant speed, described by the equation d = 65t, where d represents the distance, in miles, that the car travels at this speed in t hours. a) What does the 65 tell us in this situation? b) How many miles does the car travel in 1.5 hours? Show your work. c) How long does it take the car to travel 26 miles at this speed? Show you
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The equation d = 65t
represents the distance (d) the car travels at a 65 mile speed in t hours
a. 65 tells us the speed at which the car travels
b. If the car travels in 1.5 hrs, then
d = 65(1.5)
= 97.5 milestone.
c. To travel 26 miles, we have d = 26
26 = 65t
t = 26/65
= 0.35 (approximately)
A recent study conducted by a health statistics center found that 27% of households in a certain country had no landline service. This raised concerns about the accuracy of certain surveys, as they depend on random-digit dialing to households via landlines. Pick five households from this country at random. What is the probability that at least one of them does not have a landline _________
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We are going to use Binomial Probability Distribution
Probability that they have no landline = q = 27/100 = 0.27
Probability that they have landline = p = 1 - 0.27 = 0.73
Now, to find the probability that at least one of them does not have a landline, we have to find the probability that all the five have a landline first.
So let's find the probability that all the five have a landline:
[tex]\begin{gathered} P(X=x)=^nC_xp^xq^{n-x} \\ ^5C_5(0.73)^5(0.27)^{5-5} \\ P(X\text{ = 5) = }0.2073 \end{gathered}[/tex]So the probability that all the five have a landline = 20.73%
Now is the time to find the probability that at least one of them does not have a landline:
P(at least one has no landline) = 1 - P(All have landline)
= 1 - 0.2073
= 0.7927
So the probability that at least one of them does not have a landline = 79.27%
That's all Please
clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. before treatment 19 subjects had a mean wake time of 100.0 min after treatment the 19 subjects had a mean wake time of 71.6 min and a standard deviation of 20.4 min assume that the 19 sample value appears to be from a normally distributed population and construct a 99% confidence interval estimate of the mean wake time for a population with drug treatment what does the result suggest about the wake time of 100.0 min before the treatment does the drug appears to be effective
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We have to calculate a 99% confidence interval for the mean.
The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.
The sample mean is M=71.6.
The sample size is N=19.
When σ is not known, s divided by the square root of N is used as an estimate of σM:
[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{20.4}{\sqrt{19}}=\dfrac{20.4}{4.359}=4.68[/tex]The degrees of freedom for this sample size are:
[tex]df=n-1=19-1=18[/tex]The t-value for a 99% confidence interval and 18 degrees of freedom is t=2.878.
The margin of error (MOE) can be calculated as:
[tex]MOE=t\cdot s_M=2.878\cdot4.68=13.471[/tex]Then, the lower and upper bounds of the confidence interval are:
[tex]\begin{gathered} LL=M-t\cdot s_M=71.6-13.471=58.129 \\ UL=M+t\cdot s_M=71.6+13.471=85.071 \end{gathered}[/tex]The 99% confidence interval for the mean is (58.129, 85.071). This interval does not include the value 100, so we can conclude that there is statistical evidence that the treatment reduces the mean wake time.
White the inequality shows by the shaded region in the graph with the boundary line y=x/3-5
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From the given figure
Since the line is a dashed line, then
The sign of inequality does not have equal (< OR > )
Since the shading area is down the line, then
The sign of inequality should be smaller than (<)
Then the inequality is
[tex]y<\frac{x}{3}-5[/tex]The area of Bryce is 71.5 sq units.what is the area of abcd?
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Solution
Step 1:
Area of BXYC = 71.5 square units
Step 2:
The area of ABCD is twice the area of BXYC
Step 3:
[tex]\begin{gathered} \text{Area of ABCD = 2 }\times\text{ Area of BXYC} \\ Area\text{ of ABCD = 2 }\times\text{ 71.5} \\ Area\text{ of ABCD = 143 square units} \end{gathered}[/tex]Had someone explain it and I didn’t get it still
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From the question:
Let f(x) = 2x² + 2x - 8
g(x) = √x - 2
We are aske to write f(g(x))
f(x) = 2x² + 2x - 8, g(x) = √x - 2
g(x) = √x - 2
= f(√x - 2)
f(√x - 2): 2x + 2√x - 2 - 12
f(g(x)) = 2x - 12 + 2√x - 2.
x^2 = 16, therefore x = 4.
Is this a valid conclusion? If not, give a counterexample.
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5. Graph the function f (x) = 3sin (2x) + 1 Be sure to identify the midline, period, and amplitude.
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Given that f(x) = 3 sin (2x) + 1
Given that : a sin (bx + c ) + d
let a = amplitude,
Midline is the that runs between the maximum and minimum value
[tex]\begin{gathered} \text{ Since, amplitude = 3} \\ \text{the graph is shifted 1 unit in positive y - coordinate} \\ \text{Maximum value = 3 - 1 = 2} \\ \text{ minimum value = -3 - 1 = -4} \\ \text{Midline is the center of (2, - 4)} \\ \text{Midline = }\frac{\text{2 - 4}}{2} \\ \text{midline = -1} \end{gathered}[/tex]Period is calculated as
[tex]\begin{gathered} \text{period = }\frac{2\pi}{|b|} \\ \\ \text{b = 2} \\ \text{Period = }\frac{2\pi}{2} \\ \text{Period = }\pi\text{second} \end{gathered}[/tex]Frequency = 1 / period
[tex]\text{frequency = }\frac{1}{\pi}\text{ Hz}[/tex]HELP!! My question isUsing the formula below, solve when s is 3The formula is A = 6s² and I need to know the steps on how to solve it please help! I really dont understand and my teacher is not at school to help me
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The given expression : A = 6s²
Substitute s = 3 in the given expression
A = 6s²
A = 6(3)²
as : 3² = 3 x 3
3² = 9
A = 6 x 9
A = 54
Answer : A = 54
Find the links of the sides of these special triangles
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From the triangle, we express the tangent of 60° as:
[tex]\tan 60\degree=\frac{Z}{7}[/tex]But tan(60°) = √(3), then:
[tex]\begin{gathered} \frac{Z}{7}=\sqrt[]{3} \\ \Rightarrow Z=7\sqrt[]{3}\text{ ft} \end{gathered}[/tex]Y + 41 = 67 solve y using one step equation
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Answer:
Y = 26
Step by step explanation:
[tex]y\text{ + 41 = 67}[/tex]
Then we pass the 41 to substract.
[tex]y\text{ = 67 - 41 = 26}[/tex]A baker paid $15.05 for flour at a store that sells flour for $0.86 per pound.
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Solution:
Given that a store sells flour for $0.86 per pound, this implies that
[tex]1\text{ lb}\Rightarrow\$0.86[/tex]Given that a baker paid $15.05, let y represent the amount of flour the baker bought.
Thus,
[tex]y\text{ lb}\Rightarrow\$15.05[/tex]To solve for y,
[tex]\begin{gathered} 1\text{lb}\operatorname{\Rightarrow}\operatorname{\$}0.86 \\ y\text{ lb}\Rightarrow\$15.05 \\ cross-multiply, \\ y\text{ lb = }\frac{\$\text{15.05}}{\$0.86}\times1\text{ lb} \\ =17.5\text{ lb} \end{gathered}[/tex]Hence, the baker bought 17.5 lb of flour.
At 3:00 PM a man 138 cm tall casts a shadow 145 cm long. At the same time, a tall building nearby casts a shadow 188 m long. How tall is the building? Give your answer in meters. (You may need the fact that 100 cm = 1 m.)
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A tall man(138cm) casts a shadow of 145cm
A building nearby casts a shadow of 188m
Using the information you have to determine the height of the building.
First step is to convert the units of the height of the man and the length of his shadow from cm to meters:
100cm=1m
So 145cm=1.45m
And 138co=1.38m
Now that the measurements are expressed in the same units you can determine the height shadow ratio of the man and use it to calculate the height of the bulding.
[tex]\frac{\text{height}}{\text{shadow}}=\frac{1.38}{1.45}[/tex]Compare this ratio with the ratio between the heigth/shadow ratio of the building to determine the heigth of the building.
Said height will be symbolized as "x"
[tex]\begin{gathered} \frac{1.38}{1.45}=\frac{x}{188} \\ x=(\frac{1.38}{1.45})188 \\ x=178.92m \end{gathered}[/tex]The building is 178.92m
Illustrate the ratio 7:3 using 'X' for 7 and 'y for 3
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Given the ratio:
7:3
To illustrate the ratio above using x for 7 and y for 3, we have:
All you need to do is to replace 7 with x and replace 3 with y
7 : 3 ==> x : y
ANSWER:
x : y
The polynomial expression x(3x^2+25)(10x^2+4x+6), where x is in inches, can be used to mod the number of cubic inches of cement that will be needed for a new porch. The cement contractor used 2 for the value of x.
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Since x is given in cubic inches, let's split the expression like this:
[tex]\begin{gathered} h=height=x \\ w=width=(3x^2+25) \\ l=length=(10x^2+4x+6) \end{gathered}[/tex]For x = 2:
[tex]\begin{gathered} h=2in \\ w=3(2)^2+25=37in \\ l=10(2)^2+4(2)+6=54in \end{gathered}[/tex]A study determined that 9% of children under 18 years of age live with their father only. Find the probability that at most 2 persons selected at random from 12 children under18 years of age lived with their father onlyThe probability that at most 2 children live with their father only is(Do not round until the final answer. Then round to the nearest thousandth as needed)
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Step 1: Write out the formula for binomial distribution
[tex]P(x)=^nC_x\times p^x\times q^{n-x}[/tex]Where
[tex]\begin{gathered} p\Rightarrow\text{probability of success} \\ q\Rightarrow\text{probability of failure} \\ n\Rightarrow\text{ number of trails } \\ x\Rightarrow\text{ number of success required} \end{gathered}[/tex]Step 2: State out the parameters needed in the formula to find the probabilty
[tex]\begin{gathered} p=9\text{ \%=}\frac{9}{100}=0.09 \\ q=1-p=1-0.09=0.91 \\ n=12 \\ x\Rightarrow\le2\Rightarrow0,1,2 \end{gathered}[/tex]Step 3: The probability that at most 2 children live with their father only can be described as;
[tex]P(x\le2)=P(0)+P(1)+P(2)[/tex]Step 4: Find the probability of each number of successes required
[tex]\begin{gathered} P(0)=^{12}C_0\times(0.09)^0\times(0.91)^{12-0} \\ P(0)=1\times1\times0.322475487=0.322475487 \end{gathered}[/tex][tex]\begin{gathered} P(1)=^{12}C_1\times(0.09)^1\times(0.91)^{12-1} \\ =^{12}C_1\times(0.09)^1\times(0.91)^{11} \\ =12\times0.09\times0.354368667=0.38271816 \end{gathered}[/tex][tex]\begin{gathered} P(2)=^{12}C_2\times(0.09)^2\times(0.91)^{12-2} \\ =^{12}C_2\times(0.09)^2\times(0.91)^{10} \\ =66\times0.0081\times0.389416118=0.208181856 \end{gathered}[/tex]Step 5: Add all the number of successess required
[tex]\begin{gathered} P(x\le2)=0.322475487+0.38271816+0.208181856 \\ =0.913375503 \\ \approx0.913 \end{gathered}[/tex]Hence, the probability that at most 2 children live with their father only is 0.913
Hello. I think I have this one correct but I'm not 100% sure. Would you mind helping me work this through?
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1) To better set the measurements in that picture, we need to consider that parallel line segments in this picture have the same measurements.
2) Based on that, we can look at that picture this way:
And set the following equation, given that Perimeter is the sum of all lengths of a polygon:
[tex]\begin{gathered} P=2+2+1+2+3+3+1+1+1+1+4+3 \\ P=24\:cm \end{gathered}[/tex]Fowler has a collection of marbles of different sizes and colors. Big Small Red 9 9 Green 14 9 Purple 9 6 Blue 0 10 What is the probability that a randomly selected marble is not red or is not small? Simplify any fractions.
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From the given table, the following are observed:
No. of marbles that are not red and not small = No. of Big Green and Big Purple
= 14 + 9
= 23 Marbles
Total number of marbles = 9 + 14 + 9 + 9 + 9 + 6 + 10 = 66 Marbles
We get,
[tex]\text{ Probability of getting a marble that is not red or not small = }\frac{\text{ 23 Marbles}}{66\text{ Marbles}}[/tex][tex]\text{ = }\frac{23}{66}[/tex]We can no longer simplify 23/66. Therefore, 23/66 is the answer.
A tutoring service charges an initial consultation fee of $50 plus $25 for each tutoringsession.A. Write an equation that determines the total cost of tutoring services (y) based on thenumber of tutoring sessions (x).B. If a student decides to purchase 8 tutoring sessions, what will be his total cost?c. If a student had a total cost of $200, how many tutoring sessions did he attend?EditVioInsertFormatThols Table
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A. y = 50 + 25x
B. number of session (x) = 8
Substitute x= 8 in the equation y= 50 + 25x
y = 50 + 25( 8 )= 50 + 200 = $250
The total cost for 8 tutoring sessions is $250
C. y = $200
x= ?
y = 50 + 25x
200 = 50 + 25x
200 - 50 = 25x
150 = 25x
Dividing through by 25
x = 150/25 =6
He attended 6 tutoring sessions
Is x5 + x2 + x a polynomial? Explain why or why not.
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A polynomial is a mathematical expression formed by variables and coefficients, that involves only the operations of addition, subtraction, multiplication and non-negative integer exponentiation of variables.
The expression:
[tex]x^5+x^2+x[/tex]Is formed by the addition of three terms, each consisting of the variable x raised to a positive integer quantity. Therefore, the given expression is a polynomial.
A loan is paid off in 15 years with a total of $192,000. It had a 4% interest rate that compounded monthly.
What was the principal?
Round your answer to the nearest cent and do not include the dollar sign. Do not round at any other point in the solving process; only round your answer.
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The principal amount with the given parameters if $165.
Given that, Amount = $192,000, Time period = 15 years and Rate of interest = 4%.
What is the compound interest?Compound interest is the interest on savings calculated on both the initial principal and the accumulated interest from previous periods.
The formula used to find the compound interest = [tex]A=P(1+\frac{r}{100} )^{nt}[/tex]
Now, [tex]192,000=P(1+\frac{4}{100} )^{15\times 12}[/tex]
⇒ [tex]P=\frac{192,000}{(1.04)^{180}}[/tex]
⇒ P = $164.93
≈ $165
Therefore, the principal amount with the given parameters if $165.
To learn more about the compound interest visit:
https://brainly.com/question/14295570.
#SPJ1
Answer:
Step-by-step explanation:
Use the compound interest formula and substitute the values given: $192,000=P(1+.0412)12(15). Simplify using order of operations: $192,000=P(1+.0412)180
P=192,000(1+.0412)180
P≈$105477.02
Write and solve the equation that has been modeled below.
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Solution
[tex]\begin{gathered} x+x+1+1+1+1+1+1+1=1+1+1+1+1+1+1+1+1 \\ 2x+7=9 \\ \text{Separate similar terms} \\ 2x=9-7 \\ 2x=2 \\ \text{Divide both sides by 2} \\ \frac{2x}{2}=\frac{2}{2} \\ \\ x=1 \end{gathered}[/tex]The final answer
[tex]x=1[/tex]Triangle HFG is similar to triangle RPQ. Find the value of x. Find the length of HG.
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Answer:
• x=1
,• HG=8 units
Explanation:
If triangles HFG and RPQ are similar, the ratios of their corresponding sides are:
[tex]\frac{HF}{RP}=\frac{HG}{RQ}=\frac{FG}{PQ}[/tex]Substitute the given values:
[tex]\frac{4}{2}=\frac{6x+2}{x+3}=\frac{6}{3}[/tex]First, we solve for x:
[tex]\begin{gathered} \frac{4}{2}=\frac{6x+2}{x+3} \\ 2=\frac{6x+2}{x+3} \\ 2(x+3)=6x+2 \\ 2x+6=6x+2 \\ 6-2=6x-2x \\ 4=4x \\ x=1 \end{gathered}[/tex]Finally, calculate the length of HG.
[tex]\begin{gathered} HG=6x+2 \\ =6(1)+2 \\ =8\text{ units} \end{gathered}[/tex]f(x) = square root of x - 5. find f^-1 (x) and it’s domain
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Given:
f(x) = root x - 5
Rewrite the function using y,
[tex]y=\sqrt[]{x}-5[/tex]Now, interchange the position of x and y in the function,
[tex]x=\sqrt[]{y}-5[/tex]Isolate the dependent variable
[tex]\begin{gathered} \sqrt[]{y}=x+5 \\ y=(x+5)^2 \end{gathered}[/tex]Therefore,
[tex]f^{-1}(x)=(x+5)^2[/tex]And the domain is minus infinity to infinity
[tex]\begin{gathered} f^{-1}(x)=(x+5)^2 \\ \text{Domain}=(-\infty,\infty) \end{gathered}[/tex]4 boxes of crayons cost $12.50 How much would 16 boxes cost? (Show work) Thank you!
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Answer:
$50.08
Step-by-step explanation:
Find the unit rate.
[tex]\frac{12.50}{4}[/tex] Each box cost $3.125. We cannot have .125 cents, so round up to 3.13
3.13 x 16 = $50.08
Which equation has at least one solution? Mark all that app A. 2x-1= 2 B. 3 y + 1) = 3y 1 C. 5p - (3 + p) = 6p + 1 D. 4/5m=1-1/5m E. 10 +0.5w =1/2w - 10 F. 4a + 3(a - 2) = 8a - (6 + a) Answer Choices:
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Let's check the options
A.
2x - 1 = 2
2x= 3
x= 3/2=1.5
option A has atleast one solution
B
3y+ 1 = 3y
option B has no solution
C.
5p - (3 + p) = 6p + 1
5p - 3 - p = 6p + 1
4p - 6p = 1 + 3
-2p = 4
p =-2
option C has atleast one solution
D.
4/5 m = 1- 1/5 m
4/5 m + 1/5m = 1
1m = 1
m = 1
Option D has atleast one solution
E.
10 + 0.5w = 1/2w - 10
0.5 w - 1/2 w = -10 - 10
option E has no solution
F.
4a + 3(a-2) = 8a - (6+a)
4a +3a - 6 = 8a -6 - a
7a -6 = 7a - 6
option F has many solution. Hence it also has atleast one solution
Therefore;
option A, C, D and F has atleast one solution
Perform the following matrix row operation and write the new one.
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Given: A matrix
[tex]\begin{bmatrix}{1} & {-3} & {2} \\ {3} & {9} & {5} \\ {} & & {}\end{bmatrix}[/tex]Required: To perform the following matrix row operation
[tex]-3R_1+R_2[/tex]Explanation: The operation is to be applied on the first row of the given matrix. Hence the second row will be same as that of the initial matrix.
The elements of the first row are first multiplied by 3 and then added with second row to give the required matrix.
Hence,
[tex]\begin{bmatrix}{-3+3} & {9+9} & {-6+5} \\ {3} & {9} & {5} \\ {} & {} & {}\end{bmatrix}[/tex]which gives
[tex]\begin{bmatrix}{0} & {18} & {-1} \\ {3} & {9} & {5} \\ {} & {} & {}\end{bmatrix}[/tex]Final Answer: The required matrix is
[tex]\begin{bmatrix}{0} & {18} & {-1} \\ {3} & {9} & {5} \\ {} & {} & {}\end{bmatrix}[/tex]Which of the following tables shows a uniform probability model?
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The answer is the third choice
Where all probability are equal
Give me a rhombus ABCD with BC =25 and BD= 30 find AC and the area of ABCD
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300 u²
1) Let's start by sketching out this:
2) Since a Rhombus have 4 congruent sides, then we can state that 4 sides are 25 units, and we need to find out the other Diagonal (AC)
Applying the Pythagorean Theorem, to Triangle COD
a² =b² +c²
25² = 15² +c²
625 = 225 + c² subtract 225 from both sides
625-225 = c²
400 = c²
√c² =√400
c =20
2.2) Now, we can calculate the area, applying the formula for the area of a rhombus (the product of its diagonals).
[tex]\begin{gathered} A=\frac{D\cdot d}{2} \\ A=\frac{40\cdot30}{2} \\ A=\frac{1200}{2} \\ A\text{ = 600} \end{gathered}[/tex]3) Hence, the answer is 300 u²