Answer:
See below
Explanation:
Assuming no resistance
DISTANCE = 1/2 a t^2
443 = 1/2 (9.81)t^2 Shows t = 9.5 seconds
Write 2 uses of centripetal force.
Pushing or pulling an object that is not already moving can make that object start to move?
TRUE
OR
FALSE ?
According to the research, the correct option is true. The statement "Pushing or pulling an object that is not already moving can make that object start to move" is true.
What is motion?It is about the change of position starting from a reference system from which it is observed that an object experiences.
In this sense, it is related to the displacement of a body and is produced by an imbalance between the forces that act on it, that is, the application of a force modifies the state of rest or the direction of movement.
Therefore, we can conclude that motion is the state of bodies when they change position caused by an effect acting on the bodies called force.
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To prevent water pollution, a factory proposes pumping its wastes into the ground instead of into a river. Would you support this proposal? Why or why not?
how do the kinetic energy of each of the following objects compare to one another? i. object of mass 3 kg traveling at constant velocity of 4 m/s in the x x direction ii. object of mass 1 kg traveling at constant velocity of 8 m/s in the x x direction iii. object of mass 3 kg traveling at constant velocity of 3 m/s in the x x direction and -3 m/s in the y y direction
The kinetic energy of each of the following objects compare to one another as: II > I > III
As we know the kinetic energy is follows as:
K.E. = 1/2m[tex]v^{2}[/tex]
(i) Object 1
mass = 3kg
velocity = 4m/s
K.E. = 1/2m[tex]v^{2}[/tex]
K.E. = 1/2×3×4×4
K.E. = 24J
(ii) Object 2
mass = 1kg
velocity = 8m/s
K.E. = 1/2m[tex]v^{2}[/tex]
K.E. = 1/2×1×8×8
K.E. = 32J
(iii) Object 3
mass = 3kg
velocity = -3m/s
K.E. = 1/2m[tex]v^{2}[/tex]
K.E. = 1/2×3×(-3)×(-3)
K.E. = 13.5J
Therefore, the kinetic energy of each of the following objects compare to one another as: II > I > III
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PLEASE ANSWER ASAP!
On average, there is enough wind in the UK each year to supply all of the UK's electricity needs.
Explain why the UK may still need power stations that use fuel to generate electricity.
(2 marks)
Explanation:
Unplanned maintenance at nuclear plants and lower than average wind speeds mean the country is currently relying on gas-powered stations to generate about half its electricity
The UK depends on power stations due to the more efficiency of energy production in them.
Even though UK has an enough wind supply over each year to meet the electric needs of UK, they still need power stations that use fuel to generate electricity.
This is because of the challenges created in the maintenance and implementation of wind plants in the UK.
The wind turbines have a higher cost for maintenance, compared to that of power stations. The ideal wind sites in the UK are mostly located in remote areas, so that it becomes more difficult for the implementation of wind plants. Also the lower average wind speed causes less production in the electricity through them. As a result, the UK still depends on power stations for the electric needs.
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If you had access to a personal DNA machine, what would you analyze and why?
If I had access to a personal DNA machine, I would analyze my ancestry and my health condition.
Just for curiosity you can compare your DNA to your parents DNA to find whose trait you received the most. Through DNA testing one can find where their ancestors lived and which group of people they interacted with.
In terms of analyzing DNA for health condition one can identify if they have any genetic diseases and it can also be used to identify cancer in its early stages so that it can be cured. It can also be used to identify the diseases an unborn fetus might inherit.
Therefore, if I had access to a personal DNA machine, I would analyze my ancestry and my health condition.
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three different-mass projectiles are launched at different angles of elevation from the top of a building. each particle has the same initial kinetic energy. which particle has the greatest kinetic energy just as it impacts with the ground?
The correct option is b. The one with the lowest mass.
An object's kinetic energy is determined by
k=1/2mv^2
where
m is the object's mass.
v is the object's speed.
The three missiles in this puzzle have varying masses but the same beginning kinetic energy.
The three projectiles will all have the same kinetic energy when they hit the ground because mechanical energy is conserved, assuming there is no air resistance (because the potential energy that they have lost is the same, since they have been launched from the same height, and they reach the same final altitude, the ground).
hence,
K1=k2=k3
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Please help and explain will mark brainiest!!!
The particles or energy in a transverse wave travel up and down, perpendicular to the direction of the wave travel.
What is electromagnetic wave?
Electromagnetic waves are type of wave that do not require material medium for their propagation.
This type of waves travels in vacuum or in open medium.
Examples of electromagnetic waves include the follows;
Gamma raysx-raysultraviolet raysvisible lightinfra redmicro wavessound wavesElectromagnetic waves are known as transverse waves due to their mode of propagation.
In transverse wave, the particles of the medium travels perpendicular to their mode of vibration.
Thus, the particles or energy in a transverse wave travel up and down, perpendicular to the direction of the wave travel.
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How could these electronegativity values benefit you in analyzing data from the Curiosity rover?
It is to be noted that electronegativity will assist the analyst in the determination of the nature of the interactions between the elements discovered by the Curiosity Rover.
What is Electronegativity?The electronegativity values of two bound atoms indicate whether a bond is nonpolar or polar covalent, as determined by the bonding atoms' properties.
Electronegativity is a measurement of an atom's proclivity to attract electrons (or electron density) toward itself.
Electrons in a polar covalent bond are moved toward the more electronegative atom; consequently, the atom with the partial negative charge is the more electronegative atom. The bigger the electronegativity difference, the more polarized the electron arrangement and the larger the atoms' partial charges.
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a person throws a ball at an angle of 30 o with the horizontal with a velocity of 32 m/s. as the ball is thrown, a second person is running past the thrower at a constant velocity. at what velocity must this second person run so that she may catch the ball as it hits the ground?
If the second player moved horizontally, the speed he must maintain to catch the ball is 27.67 m/s.
What is the range of the projectile (ball)?
The range of the projectile is the maximum horizontal distance travelled by the ball.
R = (u²sin(2θ)) / (g)
where;
u is the initial velocityθ is the angle of projectiong is acceleration due to gravityR = (32² x sin(2 x 30) ) / (9.8)
R = 90.49 m
The time of motion of the ball is calculated as follows;
R = uₓt
where;
uₓ is the horizontal component of the velocityR = ucosθ(t)
t = R/ucosθ
t = (90.49) / (32 cos30)
t = 3.27 seconds
If the second player moved horizontally, the speed he must maintain to catch the ball is calculated as;
R = Ut
U = R/t
U = (90.49) / (3.27)
U = 27.67 m/s
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Question
Draw the outlines of two cars, one
with a streamlined shape to reduce air
resistance, and one whose shape is not
streamlined. Explain why one may be
able to go faster than the other.
Because of this, race cars have streamlined bodies that enable them to go at significantly higher speeds.
Briefing:As there is less surface area to push the air against, the streamlined designed car will be able to cut through the air and produce less drag or resistance. They move slowly, as opposed to autos, which are not streamlined. Because of this, race cars have streamlined bodies that enable them to go at significantly higher speeds.
What is air resistance and how it can be reduced?In order to push against the force of the air, objects must be streamlined. Trains are made to move quickly between destinations because of their streamlined form. Even people, like swimmers, can attempt to be streamlined.
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a wire with diameter 2.0 mm and length of 10 m is made of an unknown material. the wire has a resistance of 4.2 ohm. calculate the resistance of a wire with a 1.6 mm diameter and 20 m length made of the same material
The resistance of a wire with a 1.6 mm diameter and 20 m length made of the same material is 3.14×10⁻⁷Ω−m.
What does "resistance" mean?Electrical resistance of a conductor with a unit cross-sectional area and unit length is called resistivity. Resistivity is a distinctive attribute of any material that may be used to compare different materials based on how well they conduct electric currents. Low conductivity is indicated by high resistance.
Given,
l= 10m= 1000mm
d= 2mm
∴radius(r)= 20.2 =0.1mm
R=10Ω
To find,
Resistivity(ρ)
ρ=R /l A
where,
R= Resistance
l= Length of wire
A= Cross sectional area of wire
Cross sectional area of cylinder (A)=Πr²
A= π×(0.1)²
A=0.0314mm²
ρ=10(10000.0341)
ρ=0.000314Ω−mm
ρ≃3.14×10⁻⁷Ω−m
So, the resistivity of the material is equal to 3.14×10⁻⁷Ω−m.
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Reflect on the claims and the evidence you examined today. At this point, which claim do you think is best supported by the evidence?
Claim 1: There is frozen water in tank 2, which is blocking some of the oxygen from going into tank 3.
Claim 1: , There is frozen water in tank 2, which is blocking some of the oxygen from going into tank 3.
Claim 2: Some of the liquid oxygen evaporated in tank 3.
Claim 2:, Some of the liquid oxygen evaporated in tank 3.
Claim 3: Some of the oxygen didn’t condense in tank 2.
Claim 3:, Some of the oxygen didn’t condense in tank 2.
In the space below, explain your claim choice using the evidence you discussed today.
Claim 2: Some of the liquid oxygen evaporated in tank 3 is the claim with the most proof based on the experiment with liquid oxygen and nitrogen.
In the propellant systems of missiles and rockets, liquid oxygen is employed as an oxidant for liquid fuels. In addition to acetylene and other fuel gases, oxygen is frequently used in the metal industry for metal cutting, welding, scarfing, hardening, cleaning, and melting.Therefore, the reason of above statement can be explained as, that nitrogen has a lower boiling point than oxygen, the liquid nitrogen and oxygen mixture in tank 3 is slightly heated to allow nitrogen to escape. However, as gas particles can evaporate at a temperature below their boiling point provided they have enough energy, some oxygen might have escaped simultaneously when the boiling produced sufficient energy.
Thus the claim 2 is suitable option of this evidence.
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you are given a 1/5 model of a car that normally runs at 30 mph. what wind tunnel speed should you use to test the car? (assume kinematic viscosity does not change and )
The wind tunnel speed that must be used to test the car 1 / 5 model of a car that normally runs at 30 mph is 150 mph
Re = u L / ν
Re = Reynold's number
u = Flow speed
L = Characteristic linear dimension
ν = Kinematic viscosity
ν[tex]_{p}[/tex] = 1.516 * [tex]10^{-5}[/tex] m² / s
ν[tex]_{p}[/tex] = ν[tex]_{m}[/tex] = 1.516 * [tex]10^{-5}[/tex] m² / s
L[tex]_{m}[/tex] = L[tex]_{p}[/tex] / 5
u[tex]_{p}[/tex] = 30 mph
Re[tex]_{m}[/tex] = u[tex]_{m}[/tex] L[tex]_{p}[/tex] / 5 * 1.516 * [tex]10^{-5}[/tex]
Re[tex]_{p}[/tex] = 30 L[tex]_{p}[/tex] / 1.516 * [tex]10^{-5}[/tex]
In tunnel,
Re[tex]_{m}[/tex] = Re[tex]_{p}[/tex]
u[tex]_{m}[/tex] L[tex]_{p}[/tex] / 5 * 1.516 * [tex]10^{-5}[/tex] = 30 L[tex]_{p}[/tex] / 5 * 1.516 * [tex]10^{-5}[/tex]
u[tex]_{m}[/tex] = 30 * 5
u[tex]_{m}[/tex] = 150 mph
Therefore, the wind tunnel speed that must be used to test the car is 150 mph
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2. A freight train traveling with a velocity of −4.0 m/s begins backing into a train yard. If the train’s average acceleration is −0.25 m/s2, what is the train’s velocity after 14s?
According to the given statement is the train’s velocity after 14s is -7.5 m/s.
What is defined as velocity?The path of a body or entity's movement is determined by its velocity. In its basic form, velocity is a scalar quantity. In definition, velocity is a vector quantity. It is the speed where at ’s dimensional. It is the migration change rate.
Briefing:Initial velocity of the train, u = -4.0 m/s
Acceleration of the train, a = -0.25 m/s²
Time of motion of the train, t = 14 s
The following formula is used to determine the train's final speed:
v = u + at
v is the final velocity of the train
v = -4.0 + (-0.25 x 14)
v = -4.0 - 3.5
v = -7.5 m/s
Therefore, the train velocity of the train is -7.5 m/s.
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What will be the next step in our sun's life cycle?A. white dwarf B. red giantC. supernovaD. black hole
ANSWER:
B. red giant
STEP-BY-STEP EXPLANATION:
The Sun is currently a main sequence star and will remain so for another 5 billion years. It will then expand and cool down to become a red giant, after which it will contract and heat up again to become a white dwarf.
Therefore, the correct answer is: B. red giant
a comet is in an elliptical orbit around the sun. its closest approach to the sun is a distance of 4.5 multiply 1010 m (inside the orbit of mercury), at which point its speed is 8.9 multiply 104 m/s. its farthest distance from the sun is far beyond the orbit of pluto. what is its speed when it is 6 multiply 1012 m from the sun? (this is the approximate distance of pluto from the sun.) speed
An elliptical orbit of a comet around the sun. The Pluton orbit is far from the sun's farthest distance. 51109.88 m/s is the speed when it is 6 x 1012 m from the sun.
given data
Vi=9.2104m/s is the comet's speed at d1=4.51010m.
When d2=61012m, the speed will be Vf.
Since there is no work done by the environment and the system's starting and final energies are equal, we can use:
[tex]E_{f}=E_{i}+W\\K_{f}+U_{f}=K_{i}+U_{i}+0\\1/2mv_{f}^{2}+\frac{-GMm}{d_{2}}=1/2mv_{i}^{2}+\frac{-GMm}{d_{i}} \\v_{f}=\sqrt{v_{i}^2+2GMm[1/d_{2}-1/d_{1}]}[/tex]
Substitute the given values to find final velocity Vf
So
[tex]v_{f}=\sqrt{(9.2*10^{4}m/s )^2+2(6.7*10^{-11})(1.98*10^{30})[1/6*10^{12}-1/4.5*10^{10}]} \\[/tex]
[tex]v_{f}[/tex]=51109.88m/s
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if i were to drop an egg off a cliff, it begins to acceleration toward the ground, until it hits the ground and splattered. is momentum conserved in this situation?
Based on the principle of momentum, the momentum of the egg falling from a cliff and which shatters on hitting the ground is conserved.
What is momentum?Momentum is the product of the mass and the velocity of a compound.
Momentum, p = mass * velocity
Momentum is a vector quantity and its unit is kgm/s.
According to the principle of the conservation of momentum, in a system of colliding bodies, the momentum before the collision and the momentum after collision is conserved or equal.
Therefore, the momentum of the egg in the given scenario is conserved.
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What is the focal length of a concave lens that forms an image with a xi value of -10.0 cm when an object is 35.0 cm from the lens?
Answer:
1 / f = 1 / object + 1 / image = 1 / 35 - 1 / 10 thin lens equation
f = o * i / (o + i)
f = -10 * 35 / (-10 + 35) = -350 / 25 = -14 cm
a four-wheeled tractor whose operating weight is 47,877 lb is pulled up a road whose slipe is 3.5% at a unifrom speed. if the average tension in the towing cable is 4,860 lb, what is the rolling resistance of the road?
The rolling resistance of the road is 203.02lb per ton
R=P/W where W=47877lb/(2000lb/ton)=23.985 ton
R=4860lb/23.985ton
R=203.02lb per ton.
Rolling resistance, occasionally known as rolling friction or rolling drag, is the pressure resisting the movement when a frame rolls on a surface. Its miles are mainly caused by non-elastic consequences; that is, no longer all of the energy needed for deformation of the wheel, roadbed, and so on., is recovered when the stress is removed.
Tire rolling resistance is the power that your vehicle needs to send to your tires to hold movement at a steady velocity over a surface. In other words, it is the effort required to maintain a tire rolling. the principal contributor to rolling resistance is the process known as hysteresis.
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a satellite used in a cellular telephone network has a mass of 2440 kg and is in a circular orbit at a height of 660 km above the surface of the earth. part a what is the gravitational force fgrav on the satellite? take the gravitational constant to be g
Gravitational constant to be G = 6.67×10−11 N⋅m2/kg2 , the mass of the earth to be me = 5.97×1024 kg , and the radius of the Earth to be re = 6.38×106 m then Gravitational force Fgrav on the satellite is 19383.7 N
Given value for constant Gravitational G = 6.67 x 10-11 N.m²/kg²
Earth mass is M = 5.97 x 1024
Mass of the satellite m = 2440
Earth's radius RE = 6.38 x 106 m
Height of the satellite from the surface of the Earth = H = 700 km = 700 x 103 m = 0.7 x 106 m
Radius of the satellite = R
R = RE + H
R = 6.38x106 + 0.7x106
R = 7.08 x 106 m
Gravitational force of Earth on the satellite = Fg
F, GMm R2
F,= (6.67 * 10-11)(5.97* 104) (2440) (7.08 * 106)2
Fg = 19383.7 N
Free-fall acceleration at the surface of the Earth = g = 9.8 m/s2
Weight of the satellite at the surface of the Earth = W
W = mg
W = (2440)(9.8)
W = 23912 N
Ratio of the gravitational force on the satellite to it's weight on the surface = P
P = Fg/W
p= 19383/23912
P = 0.8106
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Help please and thank you
Based on the data in the chart, it can be concluded that as mass increases, so does thermal energy, because the thermal energy of a substance is highly dependent on its temperature and mass.
What is Thermal energy?Thermal energy always moves from a higher temperature area to a lower temperature area. When a block of ice comes into contact with a colder substance, such as liquid nitrogen or dry ice, thermal energy moves from the ice to the colder substance.
Because mass measures the amount of material in a sample, thermal energy is determined by the mass and temperature of the object. The more significant the mass of the object, the more particles there are in the model, and the more significant the thermal energy.
Thermal energy is the energy contained in the motion and vibration of its molecules.
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during a snowball fight two balls with masses of 0.30 and 0.70 kg, respectively, are thrown in such a manner that they meet head-on and combine to form a single mass. the magnitude of initial velocity for each is 12.0 m/s. what is the speed of the 1.0-kg mass immediately after collision?
Velocity can be defined as the rate at which something moves in a specific direction.as the speed of a car driving north on a highway or the pace at which a rocket takes off.Because the velocity vector is scalar, its absolute value magnitude will always equal the motion's speed.
Solve the problem ?
The direction of a body or object's movement is defined by its velocity.In its basic form, speed is a scalar quantity.In essence, velocity is a vector quantity.It is the speed at which distance changes.It is the displacement change rate. Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path.In other words, velocity is a vector, whereas speed is a scalar value. 10.4 m/sGiven that the weight of the first snowball, m1, is 0.3 kg, and the weight of the second snowball, m2, is 0.7 kgu = I2.0 m/s is the magnitude of the starting velocity for both masses.The magnitude of starting momentum is equal to the magnitude of final momentum, according to the formula for the conservation of linear momentum.V(m1 + m2) = m1u1 + m2u2.
0.3 * 12.0 + 0.7 * 10.4 = V(3.0 + 7.28)
3.0+ 7.28 = V(1) (1)
10.28 = V
The 0.3 mass and 0.7 kg mass are added to create the 1 kg mass
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The 0.3 mass and 0.7 kg mass are added to create the 1 kg mass.
What is Velocity?The velocity of a body or object determines its direction of motion. Speed is a scalar quantity in its most fundamental form. Velocity is essentially a vector quantity. It is the rate of change in distance. The displacement change rate is the issue.Speed is the rate at which an object travels along a path over time, whereas velocity is the speed and direction of an item's motion.In other words, speed is a scalar value, but velocity is a vector.10.4 m/sGiven that the first snowball, m1, weighs 0.3 kg, and the second snowball, m2, weighs 0.7 kg, the beginning velocities of both masses are equal at u = I2.0 m/s.
V(m1 + m2) = m1u1 + m2u2.
0.3 * 12.0 + 0.7 * 10.4 = V(3.0 + 7.28)
3.0+ 7.28 = V(1) (1)
10.28 = V
The 0.3 mass and 0.7 kg mass are added to create the 1 kg mass.
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A jet taxiing down the runway receives word that it must return to the gate. The jet is traveling 43. 0 m/s when the pilot receives the message. What is the acceleration of the plane if it takes the pilot 7. 69 s to bring the plane to a halt?
The acceleration of the plane is: -5.59 m/s²
The formula for uniformly varied rectilinear motion (UVRM) and procedure that we will use to solve this exercise is:
a = (vf - vi) /t
Where:
vf = final velocityvi = initial velocitya = accelerationt= timeInformation about the problem:
vi = 43.0 m/svf= 0 m/st = 7.69 sa = ?Applying the acceleration formula we have:
a = (vf - vi) /t
a = (0 m/s - 43.0 m/s) /7.69 s
a = (-43.0 m/s) /7.69 s
a = -5.59 m/s²
What is acceleration?It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2
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which is the best definition of pitch
Answer:
a black or dark viscous substance obtained as a residue in the distillation of organic materials and especially tars
Explanation:
How are an electromagnetic wave’s wavelength and frequency related to the wave’s period of oscillation?.
a cherry pie in a 8.50 in diameter plate is placed upon a rotating tray. then, the tray is rotated such that the rim of the pie plate moves through a distance of 308 in. express the angular distance that the pie plate has moved through in revolutions, radians, and degrees.
The angular distance should be
In revolution, θ = 11.53 revolution.
In radian = θ = 72.40 rad.
In degree θ = 4150.8°.
Calculation of the angular distance:
Since
Pie diameter = 8.50 in
So, the circumference of the pie should be
P = πd = 8.50π in
And, rim of the pie rotates 308 in,
So,
1 Revolution of the pie is 8.50π in,
So, for 308 it should be
= 308 in / 8.50π in revolution
=11.53 revolution
Now in the case when when we have to find distance in radians:
1 revolution is 2πrad
So,
11.53 revolution = 11.53 × 2π = 72.40 rad.
And also, 1 revolution is 360°
So,
11.53 revolution = 11.53 × 360 = 4150.8°
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PLEASE HELP ASAP!!! A high school athlete is in the weight room training for wrestling season. He is trying to bench press a bar loaded with 100
kg. How much force must he exert to lift the loaded bar and overcome the force of gravity?
Remember that a= 9.8 m/s² (1 point)
O 10.2 N
O 9800 N
O 980 N
109.8 N
Answer:
980N
Explanation:
100kg times 9.8m/s2
The force the high school athlete must exert to lift the loaded bar of mass 100 kg and overcome the force of gravity is 980 N
F = m a
F = Force
m = Mass
a = Acceleration
m = 100 kg
a = 9.8 m / s²
F = 100 * 9.8
F = 980 N
The equation used to solve the given problem is derived from the Newton's second law of motion. The law states that the force is the rate of change of momentum.
Therefore, the force the high school athlete must exert is 980 N
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An electrified rod attracts pieces of paper. After a while these pieces fly away! Why?
Answer: The paper prices fall off due to repulsive forces.
Explanation: When an electrified or charged object is brought near an uncharged object, it causes the electrons of the uncharged object to move as electrons are free movable particles. The electron leave behind the atoms. The uncharged object becomes ionized.
Here the pieces of paper may fall off because it becomes de-ionized by surrounding air particles. While the pieces are attached to the rod, surrounding air particles may provide or take away electrons and make the pieces become neutral again
Mr. Mangan now sees a hoard of zombies running toward him. There are toomany for him to fight, so he makes a run for it. Starting from rest andaccelerating at a rate of 7 m/s2, he reaches a final velocity of 25 m/s. Howmuch time did it take for him to reach his final velocity?
Given data
*The given initial velocity is u = 0 m/s
*The given acceleration is a = 7 m/s^2
*The given final velocity is v = 25 m/s
The formula for the time taken to reach his final velocity is given by the kinematic equation of motion as
[tex]\begin{gathered} v=u+at \\ t=\frac{v-u}{a} \end{gathered}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} t=\frac{25-0}{7} \\ =3.57\text{ s} \end{gathered}[/tex]Thus, the time taken to reach his final velocity is t = 3.57 s