PLEASE HELP ME IM TIMED

Answer and Explanation in one:

In physics, potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors. So basically, you could possibly demonstrate with a variety of examples. One example may be just sitting on a table, waiting to get rolled off. I know it sounds silly, so here's another example. You are holding a bow and arrow, you pull back the arrow, aiming at the target. You are holding the arrow, filling it with potential energy. When it is let go, it is kinetic energy, the act of an object in motion, slowly riding of it's potential energy.

Answer:

The thrust is  [tex]F = 7828.3 \  N [/tex]

Explanation:

From the question we are told that

   The speed of the jet aircraft is  [tex]v = 214 \ m/s[/tex]

    The rate at which the engine takes in air is [tex]\^ Q = 115 \ kg/s[/tex]

    The rate  at which the engine burns fuel is  [tex]\r m = 2.53 \ kg/s[/tex]

    The speed of the exhaust gases is  [tex]u = 276 \ m/s[/tex]

Generally the thrust of the engine is mathematically represented as

      [tex]F =[ \^ Q * ( u - v )] + (\r m * u)[/tex]

=>   [tex]F =[ 115 * ( 276  -  214 )]  + (2.53 * 276)[/tex]

=>   [tex]F = 7828.3 \  N [/tex]

Answer:

1.2N

Explanation:

f=m×a

m=3kg

a=.4m/s/s

3×.4=1.2

kg×m/s/s = N

Answer:

C. seismographs

Explanation:

Theirs another name for seismographs but c is correct

Answer:

What I put- This will affect animals, the earth, and could affect future generations. Plastic also gets into the oceans causing sea creaters die by eating it.

Sample Answer- Problems that arise from the unavailability of natural resources and from environmental hazards will affect the generations that follow us.

Explanation:

Answer:

This will affect animals, the earth, and could affect future generations. Plastic also gets into the oceans causing sea creaters die by eating it.

Explanation:

The lawnmower accelerates in the positive horizontal direction, so that the net horizontal force is, by Newton's second law,

(70 N) cos(-50°) = m (1.8 m/s²)

where m is the mass of the lawnmower. Solve for m :

m = ((70 N) cos(-50°)) / (1.8 m/s²)

m ≈ 25 kg

The lawnmower presumably doesn't get lifted off the ground, so that the net vertical force is 0. If n is the magnitude of the normal force, then by Newton's second law,

n - m g + (70 N) sin(-50°) = 0

n = m g + (70 N) sin(50°)

n = (25 kg) (9.8 m/s²) + (70 N) sin(50°)

n ≈ 300 N

Answer:

Weight. Recall that the acceleration of a free-falling object near Earth's surface is approximately g=9.80m/s2 g = 9.80 m/s 2 . The force causing this acceleration is called the weight of the object, and from Newton's second law, it has the value mg.

Explanation:

Answer:

115°c

Explanation:

°c=k-273

388-273=115

Answer:

How much power is used if 350J of work is done when pushing a box for 5 seconds.

Explanation:

the answer is 70watts

Answer:I think it would start moving

Explanation:

Answer:

White dwarf

Explanation:

Answer:

70200J

Explanation:

k.E = 1/2mv^2

K.E = 1/2(3900)(6)^2

Answer:

speed = distance/time

Explanation:

speed = 150/30

speed =5m/s

you were running fast .....5m/s is a good speed

Answer:

Buoyant force = 3.0 N

The object will not float.

Explanation:

Apparent weight of a body immersed in water is the actual weight of object minus buoyant force

Given in the question that;

Weight of object in air = 7.0 N

Apparent weight of object = 4.0 N

4.0 N = 7.0 N - Buoyant force

Buoyant force = 7.0 - 4.0 = 3.0 N

In this case, the buoyant force is less than weight of the object thus the object will sink.

Answer:

Im not a 100 percent sure but i thinks it za A

Explanation:

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 0.25 × 4000

We have the final answer as

Hope this helps you

as the surface  area increases the rate of reaction  also increases.

Explanation:

Answer:

A.) The rate is faster.

C.) 28 Seconds

Answer:

An average net force of 5200 N is needed to stop the car

Explanation:

Cinematics and Dynamics

Cinematics describes the variables involved in the movement without dealing with its causes. There are four main concepts in cinematics: Velocity (or its scalar equivalent, the speed), acceleration, time, and displacement (or the scalar equivalent, distance).

The acceleration can be calculated by:

[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]

The initial speed is vo=28 m/s, it stops (vf=0) in t=10.5 seconds, thus the acceleration is:

[tex]\displaystyle a=\frac{0-28}{10.5}[/tex]

[tex]a = -2.67~m/s^2[/tex]

The acceleration is negative because the car loses speed.

Knowing the mass of the car m=1950 Kg, we can calculate the net force required to stop the car by using the formula:

F = m.a =1950*2.67

F = 5200 N

An average net force of 5200 N is needed to stop the car

Answer:

Electrical energy

Explanation:

Answer:

8

Explanation:

240 divided by 30 = 8

Answer:

The speed of the completed train is 0.0[tex]\bar 6[/tex] m/s

The direction of the completed train is South

Explanation:

The given parameters are;

The mass of the locomotive, m₁ = 125,000 kg

The initial speed of the locomotive, v₁ = 1.0 m/s

The mass of the gondola cars, m₂ = 1,750,000 kg

The initial sped of the gondola cars, v₂ = 0

Let v₃ represents the speed of the completed train. From the principle of conservation of linear momentum, we have;

m₁·v₁ + m₂·v₂ = (m₁ + m₂)×v₃

Substituting the known values, gives;

125,000 × 1.0 + 1,750,000 × 0 = (125,000 + 1,750,000) × v₃

∴ v₃ = (125,000 × 1.0 + 1,750,000 × 0)/(125,000 + 1,750,000) = 1/15 = 0.0[tex]\bar 6[/tex]

v₃ = 0.0[tex]\bar 6[/tex] m/s

The speed of the completed train = 0.0[tex]\bar 6[/tex] m/s

The direction of the completed train = The direction of the locomotive = South.

Answer: Samantha has the largest centripetal acceleration of 2.4 m/s^2. Maria has only 1.69 m/s^2.

Explanation:

Answer:

Explanation:

a)

Firstly to calculate the total mass of the can before the metal was lowered we need to add the mass of the eureka can and the mass of the water in the can. We don't know the mass of the water but we can easily find if we know the volume of the can. In order to calculate the volume we would have to multiply the area of the cross section by the height. So we do the following.

100[tex]cm^{2}[/tex] x 10cm = 1000[tex]cm^{3}[/tex]

Now in order to find the mass that water has in this case we have to multiply the water's density by the volume, and so we get....

[tex]\frac{1g}{cm^{3} }[/tex] x 1000[tex]cm^{3}[/tex] = 1000g or 1kg

Knowing this, we now can calculate the total mass of the can before the metal was lowered, by adding the mass of the water to the mass of the can. So we get....

1000g + 100g = 1100g or 1.1kg

b)

The volume of the water that over flowed will be equal to the volume of the metal piece (since when we add the metal piece, the metal piece will force out the same volume of water as itself, to understand this more deeply you can read the about "Archimedes principle"). Knowing this we just have to calculate the volume of the metal piece an that will be the answer. So this time in order to find volume we will have to divide the total mass of the metal piece by its density. So we get....

20g ÷ [tex]\frac{8g}{cm^{3} }[/tex] = 2.5 [tex]cm^{3}[/tex]

c)

Now to find out the total mass of the can after the metal piece was lowered we would have to add the mass of the can itself, mass of the water inside the can, and the mass of the metal piece. We know the mass of the can, and the metal piece but we don't know the mass of the water because when we lowered the metal piece some of the water overflowed, and as a result the mass of the water changed. So now we just have to find the mass of the water in the can keeping in mind the fact that 2.5[tex]cm^{3}[/tex] overflowed. So now we the same process as in number a) just with a few adjustments.

[tex]\frac{1g}{cm^{3} }[/tex] x (1000[tex]cm^{3}[/tex] - 2.5[tex]cm^{3}[/tex]) = 997.5g

So now that we know the mass of the water in the can after we added the metal piece we can add all the three masses together (the mass of the can. the mass of the water, and the mass of the metal piece) and get the answer.

100g + 997.5g + 20g = 1117.5g or 1.1175kg

Answer:

C

Explanation:

Sedimentary rocks are the product of

1) weathering of preexisting rocks,

2) transport of the weathering products,

3) deposition of the material

4) compaction (two rocks pushed together)

5) cementation of the sediment to form a rock.

Answer:

Most potential energy: A

Most kinetic energy: D

Explanation:

Kinetic Energy is the type of energy an object has due to its state of motion. It's proportional to the square of the speed.

The equation for the kinetic energy is:

[tex]\displaystyle K=\frac{1}{2}mv^2[/tex]

Where:

m = mass of the object

v = speed at which the object moves

The gravitational potential energy is the energy stored in an object because of its height h in a gravitational field.

It can be calculated with the equation:

U=m.g.h

The point where the object has the most potential energy is that where it has more height. It corresponds to point A.

When the object is at zero height, all of its potential energy was transformed to kinetic, thus the point where the kinetic energy is D.

Most potential energy: A

Most kinetic energy: D

Answer:

potentail enegry at point a and kinetic enegy at point c

Explanation:

i did this i fourth grade please mark brainlist

Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 0.85 × 19 = 16.15

We have the final answer as

Hope this helps you

Answer:

The value is  [tex]f = 0.05 \ Hz[/tex]

Explanation:

From the question we are told that

     The mass of the car is  [tex]m = 615 \ kg[/tex]

      The period of the circular motion is  [tex]T = 20 \ s[/tex]

      The radius  is [tex]r = 80 \ m/s[/tex]

Generally the frequency of the circular motion is  

       [tex]f = \frac{1}{T }[/tex]

=>    [tex]f = \frac{1}{ 20 }[/tex]

=>    [tex]f = 0.05 \ Hz[/tex]