Please answer all questions and show work for each step and each part (part A, part b, part c)
*50 points*

Answer:

i guess not similar....

Step-by-step explanation:

Answer:

sin3t*cos(s)*cos(t)+sin3t*sin(s)*sin(t).

Step-by-step explanation:

sin3t*cos(s-t);

1) cos(s-t)=cos(s)cost+sin(s)sint; then

2) sin3t*cos(s-t)=sin3t*cos(s)*cos(t)+sin3t*sin(s)*sin(t).

A. true

B. false

C. false

D. false

hope it helps

have a good day :)

Using the histogram, it is found that the percentage of simulations is the average for group A at least 1.6 higher than the average for group B is given by:

A: 1.

An histogram is a graph that shows the number of times each element of x was observed.

In this problem, the histogram shows that out of the 100 simulations, only 1 had a difference of at least 1.6, as the bin corresponding to [1.6, 2] has value of 1 and the bins to the right of this have values of 0.

Hence, the percentage is given by:

P = 1/100 x 100% = 1%.

Which means that option A is correct.

More can be learned about histograms at https://brainly.com/question/25836450

Step-by-step explanation:

[tex] \frac{1}{3x} + \frac{7}{ {x}^{2} } + \frac{x + 2}{x} [/tex]

[tex] \frac{x}{ {3x}^{2} } + \frac{21}{3 {x}^{2} } + \frac{3 {x}^{2} + 6x}{3 {x}^{2} } [/tex]

[tex] \frac{ {3x}^{2} + 7x + 21 }{ {3x}^{2} } [/tex]

Choice D

The box-and-whisker plot that displays the five-number summary of the given data is: option B.

A box-and-whisker plot displays the five-number summary of a data, which includes, the min and max values, medain, upper and lwoer quartiles.

To draw a box-and-whisker plot, find the five-number summary of the data, 31, 12, 8, 25, 23, 17, 20, 13:

Therefore, the box-and-whisker plot that displays the five-number summary of the given data is: option B.

Learn more about box-and-whisker plot on:

https://brainly.com/question/12343132

Answer:

20+5(x-2) im pretty sure

Step-by-step explanation:

Answer:

-3

Step-by-step explanation:

It's a lot of work, I'm not typing that into here

Answer:

47.

Step-by-step explanation:

1) the rule:

[tex]f_{avr}=\frac{1}{b-a} \int\limits^b_a {f(x)} \, dx ,[/tex]

where a;b are 0 and 12, f(x)=x²-1.

2) according to the rule above:

[tex]f_{avr}=\frac{1}{12-0} \int\limits^{12}_0 {(x^2-1)} \, dx=\frac{1}{12}(\frac{x^3}{3}-x)|^{12}_0=48-1=47.[/tex]

Step-by-step explanation:

but that is really, really simple.

is the problem that you don't know what a perimeter is ?

a perimeter is the whole distance you have to "walk", if you would "go" around the whole object.

that means you would have to go along every side until you reach the starting point again.

therefore, the perimeter is simply the sum of all side lengths.

P = 8.6 + 3.1 + 6.67 + 5.37 = 23.74 yds

the height does not play any role in this (but it would be important to calculate the area).

I don't understand these huge numbers you have there in the " P =" line.

where are they coming from ? in any case they have nothing to do with this quadrilateral.

Answer:

  d.  2 to 1

Step-by-step explanation:

The ratio of wavelengths will be inversely proportional to the number of them that are found in any given distance.

__

If the same distance shows 3.5 wavelenths of one function and 7 wavelengths of another, the ratio of wavelengths is ...

  7 : 3.5 = 2 : 1

Answer:

A.

Step-by-step explanation:

B and C seem to stray away from what the question originally asked.

Answer:

the answer is B ( offer proof by example in answering interview questions)

Step-by-step explanation:

hope this helps:)

ed 2023

Answer:

1 tsp of oil = 4 g

Step-by-step explanation:

1 Tbsp of syrup = 5 tsp of oil

2 tsp of oil = 1 Tbsp of syrup - 12 g

2 tsp of oil = 5 tsp of oil - 12 g

-3 tsp of oil = -12 g

1 tsp of oil = 4 g

We know that, the area of a square with side being s, is given by s², so if we here assume our side of square whose area is (16/36) sq. foot being s, so we will be having :

[tex]{:\implies \quad \sf s^{2}=\dfrac{16}{36}}[/tex]

[tex]{:\implies \quad \sf s=\pm \sqrt{\dfrac{16}{36}}}[/tex]

But, as length can never be -ve, so we will be taking only +ve length, and if we solve further for s, it will yield ;

[tex]{:\implies \quad \sf s=\sqrt{\dfrac{16}{36}}}[/tex]

[tex]{:\implies \quad \sf s=\dfrac{\sqrt{16}}{\sqrt{36}}}[/tex]

[tex]{:\implies \quad \sf s=\dfrac46}[/tex]

[tex]{:\implies \quad \boxed{\bf{s=\dfrac{4}{6}=\dfrac{2}{3}}}}[/tex]

Well, you might be thinking that (2/3)² willn't give (16/36) rather it will give (4/9), so for this, I'm telling that (2/3) ≈ 0.66666...7 and (4/6) ≈ 0.66666...7, so it's just the same thing and also, (16/36) and (4/9) are just too the same thing, dividing the numerator and denominator of (16/36) will just lead to (4/9) as same as (2/3)²

Answer: D

Step-by-step explanation:

The function is continuous. There are no discontinuities, or sharp bends in the curve where the slope is undefined. It extends to negative infinity and goes on to positive infinity. A matter of fact, it looks like a graph of x^2 shifted by a few coordinates. The function therefore is constantly increasing from negative infinity to positive infinity. The function never decreases

Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.

[tex]\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\begin{cases} h=0\\ k=0\\ a=2\\ c=4 \end{cases}\implies \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{b^2} \\\\\\ c^2=a^2+b^2\implies 4^2=2^2+b^2\implies 16=4+b^2\implies \underline{12=b^2} \\\\\\ \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{12}\implies \boxed{\cfrac{x^2}{4}-\cfrac{y^2}{12}}[/tex]

Answer:

1/13

Step-by-step explanation:

There are 2 red 5's in a standard 52-card deck ( a red 5 of hearts and a red 5 of diamonds ) and then there are 2 black 6's in a 52-card deck ( a black 6 of clubs and a black 6 of spades )

So in total there are 4 cards that we want out of 52.

So the probability of getting a red five or a black six is 4/52 or 1/13

Answer:

Step-by-step explanation:

This is an or question. You can choose either one; both are possible and the smaller probability add.

Red 5: 2/52

There are 26 red cards. 2 of them are 5s (diamonds / hearts). You are still drawing from a complete pack of 52

Black 6: 2 / 52

There are 26 black cards. 2 of them are 6s (Clubs / spades). You are still drawing from a complete pack of 52

2/52 + 2/52 = 4/52

Divide top and bottom by 4

4/4 // 52 /4

1 / 13

Answer: 1/13 or 0.077

Answer:

B

Step-by-step explanation:

Group like them

such that the coefficient stands alone

by subtracting both sides by 9.5

Answer:

[tex]V=763.407[/tex] yd^3

Step-by-step explanation:

Formula for volume of right circular cylinder.

[tex]V=\pi r^{2}*6[/tex]

[tex]r=\frac{d}{2}[/tex]

We are given the diameter (d) and the height (h).

First solve for r.

[tex]r=\frac{18}{2}[/tex]

[tex]r=9[/tex]

Now we have everything we need to find the volume. Plug in r into the volume formula.

[tex]V=\pi *9^{2} *3[/tex]

[tex]V=763.407[/tex] yd^3

Answer:

1/7

Step-by-step explanation:

hope this helps x have a great day

Step-by-step explanation:

M=?

=$104.45-$11

=93.45

$93.45÷0.07

=1335

He used 1335 minutes in month

Answer:

I think its 40

Step-by-step explanation:

Answer:

48

Step-by-step explanation:

Got it right on the assignment.

Hope this helps!!

Answer:

I think the answer is <1 and <4 are supplementary angles

Answer:

v = 10 yd

Step-by-step explanation:

the area (A) of a triangle is calculated as

A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the perpendicular height )

here b = 10 , h = v and A = 50 , then

[tex]\frac{1}{2}[/tex] × 10v = 50

5v = 50 ( divide both sides by 5 )

v = 10

Answer:

The perimeter of an 30 inch wide = 20inches wide bro

Step-by-step explanation:

[tex]\dfrac{d}{dx} \csc(5x)\\\\=-\csc(5x) \cdot \cot (5x) \cdot \dfrac{d}{dx} (5x)\\\\=-5\csc(5x) \cdot \cot(5x)[/tex]