multiplication problem

Answer:

6x+7=13

2/3x+8= 8.66

Step-by-step explanation:

calculator and rule with a compass

Answer:

3.6% or B quack quack quack quack

The unemployment percentage is 3.6 percent. Therefore, option B is the correct answer.

Percentage is defined as a given part or amount in every hundred. It is a fraction with 100 as the denominator and is represented by the symbol "%".

Given that, the labor force is 740 workers, but 27 are unemployed.

Here, percentage = 27/740 ×100

= 2700/740

= 3.6%

Therefore, option B is the correct answer.

To learn more about the percentage visit:

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[tex]~~~~~~ \textit{Savings Earned Amount} \\\\ S=P\left(1+r\right)^{t} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$14500\\ r=rate\to 7.5\%\to \frac{7.5}{100}\dotfill &0.075\\ t=years\dotfill &5 \end{cases} \\\\\\ S=14500\left(1+0.075\right)^{5}\implies S=14500(1.075)^5\implies A\approx 20816.63[/tex]

Answer:

1. 20 km/hr (60km / 3h)

2. 70 m/hr (170m / 2h)

3. 6.5 hr (260cm / 40km)

4. 4.5 s (72cm / 16cm)

5. 184 km (46km * 4h)

Step-by-step explanation:

We'll use d = distance, t = time, s = speed.

Speed over time can be found by dividing distance by time

s = d / t

We can take this formula and manipulate it to find either distance or time if we know two of the values. Keeping in mind division and multiplication cancel each other.

If we wanted to find d for instance we can multiply both sides by t to get

s * t = d

For time we can divide both sides of the above formula by s to get

t = d / s

Answer:

1. 20 km/h

2. 70 m/h

3. 6.5 h

4. 4.5 s

5. 184 km

Step-by-step explanation:

For first two questions, you can use the following formula:

[tex]\displaystyle \large{s = \frac{d}{t}}[/tex]

I denote ‘s’ be speed, ‘d’ be distance and ‘t’ be time. Some books may use ‘v’ for speed instead of ‘s’ but I use ‘s’ variable instead so it makes the equation easier to memorize.

Therefore, speed = distance/time

( 1 ) The first question is given both distance be 60 km and time be 3 hours. Therefore:

[tex]\displaystyle \large{s=\frac{60}{3}}\\\displaystyle \large{s=20 \ \ \sf{km / h}}[/tex]

So for the first question, the speed is 20 km/h

( 2 ) The second is given both distance be 140 m and time be 2 hours. Therefore:

[tex]\displaystyle \large{s=\frac{140}{2}}\\\displaystyle \large{s=70 \ \ \sf{m / h}}[/tex]

Therefore, speed is 70 m/h

For the third and four questions, we will be finding time. From the speed formula:

[tex]\displaystyle \large{s=\frac{d}{t}}[/tex]

Multiply both sides by t.

[tex]\displaystyle \large{st=d}[/tex]

Divide both sides by s.

[tex]\displaystyle \large{t=\frac{d}{s}}[/tex]

Therefore, time = distance/speed

( 3 ) The question is given speed be 40 km/h and distance be 260 km. Therefore:

[tex]\displaystyle \large{t=\frac{260}{40}}\\\displaystyle \large{t=\frac{13}{2} \ \ \sf{h}}\\\displaystyle \large{t = 6\frac{1}{2} \ \ \sf{h}}\\\displaystyle \large{t= 6.5 \ \ \sf{h}}[/tex]

Therefore, time is 6.5 h

( 4 ) The question is given speed be 16 cm/s and distance be 72 cm. Therefore:

[tex]\displaystyle \large{t=\frac{72}{16}}\\\displaystyle \large{t=\frac{9}{2} \ \ \sf{s}}\\\displaystyle \large{t=4\frac{1}{2} \ \ \sf{s}}\\\displaystyle \large{t=4.5 \ \ \sf{s}}[/tex]

Therefore, time is 4.5 s

For the last question, we have to find distance. From the speed formula:

[tex]\displaystyle \large{s=\frac{d}{t}}[/tex]

Multiply both sides by t.

[tex]\displaystyle \large{st=d}\\\displaystyle \large{d=st}[/tex]

Therefore, distance = speed * time

( 5 ) The question is given time be 4 hours and speed be 46 km/h. Therefore:

[tex]\displaystyle \large{d=46 \cdot 4}\\\displaystyle \large{ d=184 \ \ \sf{km}}[/tex]

Therefore, distance is 184 km.

Answer:

Pt A: D. Pt B: D

Step-by-step explanation:

You can multiply 5x2 which easily equals 10. 6x6 equals 36 and you cannot multiply anything other than one and itself for 7, 13, 23, or 67. for part B, you can multiply 4x 11 to equal 44 and you can multiply 9x5 to equal 45 so it would be composite

44 and 45 are composite numbers.

A prime number has only two factors, itself and one.

A composite number has at least three factors, and sometimes a lot more.

1.  Prime:7, 13, 23, 67

Composite:10, 36, 55

As, 7, 13, 23 and 67 have only two factors : one and number itself

and 10, 36, 55 have more than 2 factors like 2.

2. 44 and 45 both have more than 2 factors.

Learn more about this concept here:

https://brainly.com/question/303182

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Answer:

9 and 21

Step-by-step explanation:

First we can write the factors of 108:

1,108

2,54

3,36

4,27

6,18

9,12        - these 2 numbers add up to 21 so these 2 numbers is our answer.

Answer:

12 and 9

[tex]108 / 12 = 9[/tex]

[tex]9 * 12 = 108[/tex]

________________________________________________________

We learned alternative ways to find the sum and product of a number using a similar method.

Questions related to the topic? Ask me in the comments box.

Answer: Stacy: 30 Naomi: 18

Step-by-step explanation:

Stacy- ratio of oat to blueberry is 6:2 we want to find x:10

10 is 5 times 2, and whatever you do to the bottom you have to do to the top, and 6 times 5 is 30

Naomi- ratio of oat to blueberry is 9:5 we want to find x:10

The 10 is 2 times 5, and whatever you do to the bottom you have to do to the top, and 9 times 2 is 18

Answer:

2.054

Step-by-step explanation:

put the value of x in f(x)

Answer:

The answer is 156cm^2

Step-by-step explanation:

Solution:

The shape given is a trapezium.

The area of the green region = Area of the outer trapezium - Area of the inner trapezium.

[tex]Area\: of\:a\:trapezium\:=\frac{1}{2}\:(a+b)h[/tex]

[tex]Where\: a,b\:are\:the\:bases,\:h=height[/tex]

[tex]For,\:outer\:trapezium,[/tex]

[tex]a=10cm,\:b=14cm,h=16cm[/tex]

[tex]Area\:of\:the\:outer\:trapezium=\frac{1}{2}\:(10+14)16[/tex]

[tex]=\frac{1}{2}(24)(16)=192cm^{2}[/tex]

[tex]For\:inner\:trapezium,[/tex]

[tex]a=3cm,b=6cm,h=8cm[/tex]

[tex]Area\:of\:the\:inner\:trapezium=\frac{1}{2}(3+6)8[/tex]

[tex]=\frac{1}{2}(9)(8)=36cm^{2}[/tex]

[tex]193cm^{2}-36cm^{2}[/tex]

[tex]=156cm^{2}[/tex]

The answer is 156cm^2



Answer:

[tex]Hi!~I~am~beinggreat78~and~I~will~help~you.\\[/tex]

To solve problems, you first must find the source of the conflict, and attempt to let the situation play out, or use a strategy yourself. To solve math problems, go by PEMDAS.

With this strategy, PEMDAS, you can solve math problems quickly, and like a pro!

Answer:

20/4=c

Step-by-step explanation:

You can tell that that is the right answer, because 20-4=c means that each person would get 16 cards, and if you multiply that by 4(the amount of people that are playing) It's way more than 20 cards, so you know that 20/4=c is the right answer. Hope that helped;)

Answer:

1728 ft³

Step-by-step explanation:

Lower part:

volume = 19 ft × 12 ft × 6 ft = 1368 ft³

Upper part:

volume = 10 ft × 12 ft × 3 ft = 360 ft³

Total Volume = 1728 ft³

ray is x years old

Ron is x+y years old

in 5 years ron will be 5 years older than now, so x+y+5 years old

 orAnswer:

x - x + y + 5 - 5 = y  or   x + y - x = y

Step-by-step explanation:

The difference now,

x + y - x = y

The difference in 5 years,

(x + y + 5) - (x + 5) = x - x + y + 5 - 5

x - x + y + 5 - 5 = y

The difference in their ages never changes

Answer: X+Y+5

Step-by-step explanation:

There is no single answer you have to write an equation.

Answer:

The area of rectangle is 77 sq ft.

Answer: 77 sq ft

Step-by-step explanation:

height: 6-2=4 units

length: 9-3=6 units

4×6=24

-> 24 units

Answer:

Sunday

Step-by-step explanation:

Friday  

[(13.5 + 8.5) ÷ 2] = [(22) ÷ 2] = 22 ÷ 2 = 11 miles

Saturday

[18 − (2 × 4)] = 18 - (8) = 18 - 8 =  10 miles

Sunday

[20 − (5 − 3)] = 20 - (2) = 18 miles

18 > 11 > 10

Then She rode her bicycle the most on Sunday

Try:

Rereading your lessons, getting help from your tutor or others.

Answer:

Sundays

Hope this helps and don't forget to hit the thanks button! <3

Written by: RiBu

Answer:

J=118

L=62

M=62

Step-by-step explanation:

In an isoseles trapezoid, the top angles are congruent to each other and the bottom angles are congruent to each other. Opposite angles are supplementary, and all angles together add up to 360.

Note that √((1 - x)/x) is defined only as long as 0 < x ≤ 1.

Consider a right triangle with reference angle θ such that

[tex]\cot(\theta) = \sqrt{\dfrac{1-x}x}[/tex]

In other words, on an appropriate domain,

[tex]\theta = \cot^{-1}\left(\sqrt{\dfrac{1-x}x}\right)[/tex]

In such a triangle, you would find that

[tex]\sin(\theta) = \sqrt x[/tex]

so f(x) reduces a bit to

[tex]f(x) = \cos\left(2 \tan^{-1}(\sqrt x)\right)[/tex]

Now consider another triangle with reference angle ɸ such that

[tex]\tan(\phi) = \sqrt x \implies \phi = \tan^{-1}(\sqrt x)[/tex]

In this triangle, you would find

[tex]\cos(\phi) = \dfrac1{\sqrt{1+x}}[/tex]

Recalling the double angle identity for cosine, it follows that

[tex]f(x) = \cos(2\phi) = 2 \cos^2(\phi) - 1 = \dfrac{1-x}{1+x}[/tex]

Differentiating with respect to x yields

[tex]f'(x) = -\dfrac2{(1+x)^2}[/tex]

while

[tex]f(x)^2 = \dfrac{(1-x)^2}{(1+x)^2}[/tex]

It follows that

[tex]f'(x)(x-1)^2 - 2f(x)^2 = 0[/tex]

so B is the correct choice.

Answer:

9,-10

Step-by-step explanation:

Let u be a number.

[tex]u + {u}^{2} = 90[/tex]

[tex]u {}^{2} + u - 90 = 0[/tex]

[tex](u + 10)(u - 9) = 0[/tex]

[tex]u = - 10[/tex]

or

[tex]u = 9[/tex]

9, -10

Step-by-step explanation:

as the graphic shows, we are dealing with a special rhombus : a square.

this is proven by the fact that the angle on one side of the diagonal at the corner is 45°. so, the other side must be 45° too, and so we have 90° angles at the corners.

what is not clear to me is : what is 6 cm long ? a half-diameter, or the whole diameter ?

I assume the half-diameter.

what the graphic is trying to suggest is that we have 4 little right-angled triangles that are also isoceles triangles (their legs are equally long).

every leg is 6 cm long (based on my assumption above).

because they are right-angled, the area of each of these little triangles is leg×leg/2

6×6/2 = 18 cm²

we have 4 triangles, so the total area is

4×18 = 72 cm²

if 6 cm stands for the whole diagonal after all, then the only change is the length of the legs, which would be then 6/2 = 3 cm.

then we would have

3×3/2 = 4.5 cm² for a single triangle

and

4×4.5 = 18 cm² for the whole area.

Hello!

_____

The quotient of two numbers means we divide one number by another number.

Example :-

The quotient of 6 and a number:-

6÷x

According to the example above, the algebraic expression looks like so:-

69÷x

Hope everything is clear; if you need any explanation/clarification, kindly let me know, and I will comment and/or edit my answer :)

Answer:

5.56 ft

Step-by-step explanation:

30.48 cm per foot

170 cm ÷ 30.48 cm/ft = 5.56 ft

Hope this helps!

Answer:

GH = 15

Step-by-step explanation:

In a trapezoid, the length of the median is one-half the sum of the lengths of the bases. Therefore:

[tex]9x - 3 = \frac{1}{2} (19 + 5x + 1)[/tex]

[tex]18x - 6 = 5x + 20[/tex]

[tex]13x = 26[/tex]

[tex]x = 2[/tex]

[tex]9(2) - 3 = 18 - 3 = 15[/tex]

Answer:

They were out side for 21 minutes

Step-by-step explanation:

you just add 11:43 and add 21 minutes  to it and you get 12:04

Answer:

25

Step-by-step explanation:

5 > x/5

5 × 5 > (x/5) × 5

25 > x

The total balance in Raul's account after 40 years when he retires is $65,714.90.

The formula that can be used to determine the balance of the accout is: monthly amount saved x annuity factor.

Annuity factor = {[(1+r)^n] - 1} / r

Where:

$100 x [(1.00125^480) - 1 ] / 0.00125 = $65,714.90

Here is the complete question:

Raul is a saver. He sets aside $100 per month during his career of 40 years to prepare for retirement. He does not like the idea of investing because he prefers to minimize his risk as much as possible, so he puts his money in a savings account which earns 1.5% interest per year. What is the balance in the account after 40 years?

To learn more about annuites, please check: https://brainly.com/question/24108530

Answer: See below

Step-by-step explanation:

Question 3:

[tex]a) \ $S=1$ \ yields \ $(1,3)$ \\ \\b) \ $S=3$ \ yields \ $(3,1)$ \\ \\ c) \ $x(\sqrt{10})=\sqrt{10}$ \\ \\d) $y(\sqrt{10}+\sqrt{5})=1$ \\ \\e) $x(2)=2$ \\ \\f) $y(2,5)=1$ \\[/tex]

Challenge:

[tex]\begin{aligned}&x(s)=s \quad ,s \in[0,4] \\&y(s)=\left\{\begin{array}{cc}3 s & , s \in[0,1] \\5-2 s &, s \in[1,2] \\1 & s \in[2,4]\end{array}\right.\end{aligned}[/tex]