Solution
- This is a Binomial probability question. The formula for Binomial probability is:
[tex]\begin{gathered} P(r)=\sum\text{ }^nC_rp^rq^{n-r} \\ where, \\ n=The\text{ total number of trials} \\ r=\text{ The number of successful trials\lparen where answer is correct\rparen} \\ p=\text{ The probability of success \lparen The probability of getting a question } \\ right) \end{gathered}[/tex]- We have been given:
[tex]\begin{gathered} n=7 \\ \text{ since there can only be two answers, it means that the} \\ \text{ probability of getting a question correct is:} \\ p=\frac{1}{2} \\ q=1-p=\frac{1}{2} \\ \\ \text{ The probability of getting at least 1 question wrong means the } \\ probability\text{ of getting 1, 2, 3, 4, 5, 6, or 7 question wrong.} \\ \\ \text{ Instead of calculating all these probabilities, we can simply say} \\ P(1)+P(2)+P(3)+P(4)+P(5)+P(6)+P(7)=1-P(0) \end{gathered}[/tex]- Thus, we have:
[tex]\begin{gathered} P(0)=^7C_0(\frac{1}{2})^0(\frac{1}{2})^7 \\ P(0)=\frac{1}{128} \\ \\ 1-P(0)=1-\frac{1}{128}=\frac{127}{128} \end{gathered}[/tex]Final Answer
The answer is
[tex]\frac{127}{128}[/tex]P(A) = 1/4 P(A n B) = 1/12 P(AUB) = 13/24 Find P(B) c 21/24 5/24 O O O 3/8 11/24
Okay, here we have this:
Considering that P(AUB)=P(A)+P(B)-P(AintersectionB), we obtain that:
P(B)=P(AUB)-P(A)+P(AnB)
P(B)=(13/24)-(1/4)+(1/12)
P(B)=3/8
Finally we obtain that P(B) is equal to 3/8.
An analyst notices that a CEO has consistently achieved 25% growth in profits from one year to the next. The CEO's company currently has annual profits of $870,000. If the trend continues, what will the annual profits be in 6 years?
The currennt annual profit of the company is $ 870,000.
The growth percentage is 25%.
The annual profit of the company in the 6 years can be determined,
[tex]\begin{gathered} \text{Annual Profit=870000(1+}\frac{25}{100})^6 \\ =870000(\frac{5}{4})^6 \\ =3318786.62 \end{gathered}[/tex]Thus, the aanyal profits after 6 years will be $ 3318786.62
reduce to lowest term.5p+5q/4p+4q
Explanation
[tex]\frac{5p+5q}{4p+4q}[/tex]Step 1
factorize
[tex]\begin{gathered} 5p+5q\rightarrow5\text{ is a common factor, so}\rightarrow5(p+q) \\ 4p+4q\rightarrow4\text{ is a common factor, so}\rightarrow4(p+q) \end{gathered}[/tex]hence, the expression would be
[tex]\begin{gathered} \frac{5p+5q}{4p+4q}=\frac{5(p+q)}{4(p+q)} \\ \frac{5(p+q)}{4(p+q)} \end{gathered}[/tex]Step 2
now, we can see there is the same factor in numerator and denominator (p+q), so it can be eliminated.
[tex]\begin{gathered} \frac{5(p+q)}{4(p+q)}=\frac{5}{4} \\ \frac{5}{4} \end{gathered}[/tex]therefore, the answer is
[tex]\frac{5}{4}[/tex]I hope this helps you
Tiffany works at a lawnmower store.Part AA portion of Tiffany's monthly salary is based on commission. She earns 21% of everything she sells. This month she sold $27,000 worth of lawnmowers. Howmuch was her sales commission this month?Part BThe store purchased one riding lawn mower for $1,500 and sold it for $2025. What percentage was the markup for the mower?PartTiffany earns $15 per hour. The store offers her a raise-a 2% increase per hour. After the raise, how much will Tiffany make per hour?
1) Gathering the data
Part A
Tiffany's Commission: 21%
Sales Revenue: 27,000
2) In this case, we can figure out how much has she earned by doing this:
[tex]27,000\text{ }\times0.21=5,670[/tex]Part B)
$1,500
$ 2,025
We can solve it in 2 steps. Firstly let's find the equivalence of 2025 in percentage.
1500-------100%
2025- ----x
1500x = 202500
x=202500/1500
x =135%
Now we need to subtract from 100%. 135%-100%= 35%
So the percentage (markup) was 35%. That lawnmower was sold 35% above the price.
Part C)
$15 per hour
2% per hour (0.02)
In this, case we need a simple calculation multiplying that 15 by (1 +0.02)
15 x ( 1 +0.02)
15 x (1.02)
15.3
After the raise, Tiffany earns $15.30 per hour
hi, can you please explain mistake made on one side the other side the correct work with the answer thanks
Notice that:
[tex]3x-3x\ne x,[/tex]therefore the mistake is the last step.
Now, all the work of the student is correct up to:
[tex]undefined[/tex]Find the equation of the line perpendicular to the line y=-1, going through the points (-5,4) using the formula y-y1=m(x-x1)
We are asked to determine the equation of a line that is perpendicular to the line:
[tex]y=-1[/tex]This is the equation of a horizontal line therefore a perpendicular line is a vertical line. Therefore, it must have the form:
[tex]x=k[/tex]The value of "k" is determined by a point "x" where the line passes. Since the line passes through the point (-5, 4), this means that the equation of the line is:
[tex]x=-5[/tex]And thus we have determined the equation of the perpendicular line.
What Is the inverse of.. (ignore pencil writing) -matrices- (there may be more than one answer
To find the inverse of the matrix, first let's find the determinant:
[tex]\begin{gathered} |A|\text{ = 3(2) - 5(1)} \\ |A|\text{ = 6 - 5} \\ |A|\text{ = 1} \end{gathered}[/tex]Then, we'll find the Adjunct of the matrix:
[tex]\begin{gathered} \begin{bmatrix}{3} & {5} & {} \\ {1} & {2} & {} \\ {} & {} & {}\end{bmatrix}\text{ : interchange }3\text{ and 2. negate 1 and 5} \\ \text{Adjunct = }\begin{bmatrix}{2} & {-5} & {} \\ {-1} & {3} & {} \\ {} & {} & {}\end{bmatrix} \end{gathered}[/tex][tex]\begin{gathered} In\text{verse of the matrix = }\frac{1}{|A|}\times\text{ adjunct} \\ A^{-1}\text{ = }\frac{1}{1}(\begin{bmatrix}{2} & {-5} & {} \\ {-1} & {3} & {} \\ {} & {} & {}\end{bmatrix}) \\ A^{-1}\text{ =}\begin{bmatrix}{2} & {-5} & {} \\ {-1} & {3} & {} \\ {} & {} & {}\end{bmatrix}\text{ (option B)} \\ \end{gathered}[/tex]Amanda y Pedro realizaron queques iguales, Lurdes se comió 2/4 partes, Amanda 2/3 y Pedro 3/4, quien comió menos?
Which of the following statements follows from (x - 3)2 = 7? ox2 +9=7 Ox-3=1 / OX-3 = +49 NEXT QUESTION O ASK FOR HELP
So, given the equation:
We could take the square root to both sides of the equation to obtain that:
So the correct option is B.
X Y2 146 4211 77Find the constant of proportionality (r) in the equation y=rx.
From the question
We are given the equation
[tex]y=rx[/tex]We are to find r given that
When x = 2, y = 14
When x = 6, y = 42
When x = 11, y = 77
Substituting the first value, x = 2, y = 14 into the equation we get
[tex]14=r\times2[/tex]Solving for r we get
[tex]\begin{gathered} r=\frac{14}{2} \\ r=7 \end{gathered}[/tex]This is true for all values of x and y
Hence, r
Using the GCF you found in Part B, rewrite 72 + 81 as two factors. One factor is the GCF and the other is the sum of two numbers that do not have a common factor. Show your work.
The factors of 72 and 81 are
[tex]\begin{gathered} 72=2^3\cdot3^2 \\ 81=3^4 \end{gathered}[/tex]Therefore, their GCF is equal to 3^2=9
Then,
[tex]72+81=9\cdot8+9\cdot9=9(8+9)[/tex]The answer is 9(8+9).
The factors of 8 and 9 are
[tex]\begin{gathered} 8\to2,4,8 \\ 9\to3,9 \end{gathered}[/tex]the following table shows student test scores on the first two tests in into three chemistry class. If a student scored a 74 on his first test, make a prediction for his score on the second test . Assume the regression equation is appropriate for prediction. Round your answer to two decimal places if necessary
68.29
ExplanationIf we locate each point (x, y) on the plane we will obtain the following graph:
We can approximate the resulting figure to a straight line:
In order to discover the equation of this line we use a linear regression calculator and enter the values as follows:
The calculator gives as the following equation as an approximation:
ŷ = 0.82X + 7.61
Using this equation we can predict the score of the second test of the exam using the score of the first test.
On this case, we want to make a prediction for a score on the second test if a student scored a 74 on his first test.
This means, we want to find ŷ when X=74. Let's replace it on the equation:
[tex]\begin{gathered} ŷ=0.82X+7.61 \\ \downarrow \\ ŷ=0.82\cdot74+7.61 \\ ŷ=68.29 \end{gathered}[/tex]That is why we can say that the student will have 68.29 as his score on the second test.
Use the Distributive Property to solve the equation 2/3 (9a + 6) = 23.8
Distributive property tell us how to solve expressions in the form a(b+c), it says:
a(b+c)=ab+ac
Then,
[tex]\begin{gathered} \frac{2}{3}(9a+6)=23.8 \\ \frac{18a}{3}+\frac{12}{3}=23.8 \\ 6a+4=23.8 \\ 6a=23.8-4 \\ a=\frac{19.8}{6}=3.3 \end{gathered}[/tex]64XOA. VZ is the smallest side.OB. vz is the longest side.OC. XV is the smallest side.OD. XV is the longest side.5759Z
SOLUTION
The triangle XYZ shown below :
The angle with the longest side is said to be the angle with the largest angle:
The largest angle faces the longest side
Hence the Option B is t
[tex]YZ=x=longest\text{ side}[/tex]use the angle shown to determine if the line are parallel
If the lines were parallel then
angle H would be corresponding to angle L and then
[tex]\measuredangle H\cong\measuredangle Z.[/tex]Since angles H and Z are a linear pair then if the lines were parallel angle H, Z and L would have to be right angles. Since the problem never states that those angles are right angles, then the lines are not necessarily parallel.
Answer: No.
in chess, the knight (the piece shaped like a horse) moves in an L pattern.
Answer:
That is true but still remember that playing the knight at the start can be very useful.
Find the next two terms in this sequence. 1 3 7 15 [?] 2'4'8' 16' T'I
We will solve as follows:
*First: We identify the pattern, that is:
[tex]\frac{3}{4}-\frac{1}{2}=\frac{1}{4}[/tex][tex]\frac{7}{8}-\frac{3}{4}=\frac{1}{8}[/tex][tex]\frac{15}{16}-\frac{7}{8}=\frac{1}{16}[/tex]From this, we can see tat the pattern follows the rule:
[tex](\frac{1}{2})^{n+1}[/tex]So, the next terms of the sequence will be:
[tex]\frac{15}{16}+(\frac{1}{2})^{4+1}=\frac{31}{32}[/tex]And the next one is:
[tex]\frac{31}{32}+(\frac{1}{2})^{5+1}=\frac{63}{64}[/tex]And those are the next two terms of the sequence.
The unit rate for peaches is $2.00 per pound. The unit rate for grapes is $2.50 perpound. If you had $10 to spend, would you be able to buy a greater weight ofpeaches or of grapes? Explain your answer.
According to the problem, the total amount of money we have is $10.
Additionally, we know that the cost of peaches is $2 per pound, and the cost for grapes is $2.50 per pound.
Notice that the cost for grapes is greater than the cost for peaches, that means we'll by fewer pounds of grapes with $10 than for peaches.
For example, if we buy peaches, it would be
[tex]\frac{10}{2}=5[/tex]This means we would be able to buy 5 pounds of peaches.
But, for grapes
[tex]\frac{10}{2.50}=4[/tex]Which means we can by only 4 pounds of grapes.
Therefore, we would be able to buy a greater amount of peaches than grapes.which ordered pair is a solution of 6X + 7 < 21
Substitute 2 for x and 1 for in the inequality to verify that ordered pair satisfy the inequality or not.
[tex]\begin{gathered} 6\cdot2+7\cdot1<21 \\ 12+7<21 \\ 19<21 \end{gathered}[/tex]The inequality is trus so point (2,1) satisfy the inequality.
Substitute 4 for x and 1 for y in the inequality to verify that ordered pair satisfy the inequality or not.
[tex]undefined[/tex]If the ratio of KL to JK is 2.7. and JL = 162, find JK
KL / JK = 2:7
JL = 162
JK = ?
JL = KL + JK = 162 KL = 2 JK = 7
KL / JK = 2.7
KL = 162 - JK
Substitution
(162 - JK) / JK = 2.7
Solve for JK
162 - JK = 2.7 JK
162 = 2.7 JK + JK
162 = 3.7 JK
JK = 162 / 3.7
JK = 43.8
A straight line is 180 degrees. Find the value of X.
Given a straight line angle = 180
So, the angles (9x-100) and (40-x) are supplementary angles
So,
[tex](9x-100)+(40-x)=180[/tex]Solve for x:
[tex]\begin{gathered} (9x-x)+(40-100)=180 \\ 8x-60=180 \\ 8x=180+60 \\ 8x=240 \\ x=\frac{240}{8}=30 \end{gathered}[/tex]So, the answer will be x = 30
Can you help me solve the domain of this math word problem?
the domain refers to all possible values of x in the function.
since a negative time does not make sense, the smallest value of the domain is zero
on the other hand, the problem indicates that the model is considered accurate up to 100,000 years, therefore that would be the largest value of t
in conclusion, the domain of the function A(t) is
[tex]\lbrack0,100000\rbrack[/tex][ 0 , 100,000 ]
Margie uses 36 inches of lace to make one pillow. She makes 24 pillows for the school fair. How many total inches of lace does Margie use on the pillows?
Margie used a total of 264 inches of lace for the 24 pillows
How to calculate the total inches of lace used ?
Margie used 36 inches of lace for one pillow
She needs to make 24 pillows
The total inches of lace that was used for the 24 pillows can be calculated as follows
= 36 × 24
= 864
Hence Margie used 864 inches of lace for 24 pillows
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Answer:
4
Step-by-step explanation:
4
4
4
4
Is y = 8 a solution to the inequality below?
Answer:
Yes
Step-by-step explanation:
136/8 = 17
17 +3 = 20
20 is less than or equal to 123 so 8 does work as a solution
What two variables can you define to write an equation to match this scenario?x = number of minutes for fruit cans and y = number of minutes for vegetable cansx = total number of minutes and y = total number of cansx = number of minutes for fruit and y = total number of cansx = total number of minutes and y = number of minutes for vegetables
An equation to correctly match this scenario would have to include both separate products. The current order which is 384 cans of food, includes both fruits and vegetables, and therefore any expression that does not include them both would give a wrong answer and the order would not be properly met.
The correct scenario is;
[tex]\begin{gathered} x=Number\text{ of minutes for fruit cans} \\ y=\text{Number of minutes for vegetable cans} \end{gathered}[/tex]This way you can produce both at a maximum without overproducing one and underproducing the other.
The length of time (T) in seconds it takes the pendulum of a clock to swing through one compete cycle is givenby the formulaT= 2T✔️L/32 Where L is the length, in feet, of the pendulum, and is pie approximately 22/7. How long must the pendulum be of one complete cycle takes 2 seconds? Answer as a fraction or round to at least 2 decimal places.The pendulum must be__ feet.
we have the formula
[tex]T=2\pi\sqrt{\frac{L}{32}}[/tex]For T=2 seconds
substitute in the given formula
[tex]\begin{gathered} 2=2\pi\sqrt{\frac{L}{32}} \\ \\ 1=\frac{22}{7}\sqrt{\frac{L}{32}} \\ \\ squared\text{ both sides} \\ \\ (\frac{7}{22})^2=\frac{L}{32} \\ \\ L=\frac{7^2*32}{22^2} \\ \\ L=3.24\text{ ft} \end{gathered}[/tex]Factor the expression using the GCF. 11. 24 - 9 12. 14x + 63
Recall that the GCF of two ( or more numbers) is the highest number that divides exactly the two numbers.
11.- Notice that:
[tex]\begin{gathered} 24=3\cdot8, \\ 9=3\cdot3. \end{gathered}[/tex]Therefore:
[tex]9-24=3(8-3)\text{.}[/tex]12.- Notice that.
[tex]\begin{gathered} 14x=7\cdot2x, \\ 63=7\cdot9. \end{gathered}[/tex]Therefore:
[tex]14x+63=7(2x+9)\text{.}[/tex]Answer:
11.-
[tex]3(8-3)\text{.}[/tex]
12.-
[tex]7(2x+9)\text{.}[/tex]
For the following function, briefly describe how the graph can be obtained from the graph of a basic logarithmic function. Then, graph the function and state the domain and the vertical asymptote. f(x) = 7 - In x Describe how the graph of f(x) can be obtained from the graph of a basic logarithmic function. The graph of f(x) = 7 - In x is a transformation of the graph of f(x) = In x by a reflection across the and then a translation units. Use the graphing tool to graph the equation.
Answer
1) Graph is shown below in the 'Explanation'.
2) Domain: x > 0
In interval notation,
Domain: (0, ∞)
3) Vertical asymptote: x = 0
Horizontal asymptote: y = 7
4) The transformations required to turn f(x) = In x into f(x) = 7 - In x include
A reflection of f(x) = In x about the x-axis.
Then, this reflected image is then translated 7 units upwards.
Explanation
The graph of function is attached below
For the domain and asymptote,
Domain
The domain of a function refers to the values of the independent variable (x), where the dependent variable [y or f(x)] or the function has a corresponding real value. The domain is simply the values of x for which the output also exists. It is the region around the x-axis that the graph of the function spans.
We know that the logarithm of a number only exists if the number is positive.
So,
Domain: x > 0
In interval notation,
Domain: (0, ∞)
Asymptote
Asymptotes are the points on either the x-axis or the y-axis where the graph of the function doesn't touch.
They are usually denoted by broken lines.
For this question, we know that the value of f(x) cannot go beyond f(x) = 7 and x = 0
Vertical asymptote: x = 0
Horizontal asymptote: y = 7
For the transformation
When a function f(x) is translated horizontally along the x-axis by a units, the new function is represented as
f(x + a) when the translation is by a units to the left.
f(x - a) when the translation is by a units to the right.
When a function f(x) is translated vertically along the y-axis by b units, the new function is represented as
f(x) + b when the translation is by b units upwards.
f(x) - b when the translation is by b units downwards.
So, if the original function is
f(x) = In x
f(x) = -In x
This reflects the original function about the x-axis.
Then,
f(x) = 7 - In x
This translates the reflected function by 7 units upwards.
Please someone can help me please #1
Complete the following Division
Quotient of 96, 55, 84 and 63 is 12, 11, 14 and 21 respectively
What is Division?
One of the four fundamental arithmetic operations, or how numbers are combined to create new numbers, is division. The other operations are multiplication, addition, and subtraction.
1) 96
Divisor = 8
96 / 8
= 12
Quotient = 12
2) 55
Divisor = 5
55 / 5
= 11
Quotient = 11
3) 84
Divisor = 6
84 / 6
= 14
Quotient = 14
4) 63
Divisor = 3
63 / 3
= 21
Quotient = 21
Hence , Quotient of 96, 55, 84 and 63 is 12, 11, 14 and 21 respectively
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