KellyConnect
Cameron Moore
Customer: "I just purchased 9 products from you at $44.00 each. I just realized my
company offers a 20% discount on all of your products. Can you tell me what my new
total should be?"

The areas of the square pyramid are the amount of space on it

The given parameters are:

Base (b) = 12 cm

Slant height (l) = 12.8 cm

The lateral surface area is calculated using:

L = 2bl

So, we have:

L = 2 * 12 * 12.8

Evaluate the product

L = 307.2

This is calculated using:

T = L + b^2

So, we have:

T = 307.2 + 12^2

Evaluate

T = 451.2

Hence, the total surface area is 451.2 square cm

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Answer: TThere is no picture

Step-by-step explanation:

The frequency count that should be recorded for the soup category is 6.

Subtraction is the process of taking one number away from another number. The sign used to represent subtraction is -.

The frequency count on the table should be equal to the number of students. Thus, in order to determine the frequency count for the soup category, subtract 22 from the total frequency count.

The frequency count for the soup category = 22 - (5 + 8 + 2 + 1 ) = 6

To learn more about subtraction, please check: https://brainly.com/question/915789

[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$530000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years \end{cases} \\\\\\ A=530000\left(1+\frac{0.04}{4}\right)^{4\cdot t}\implies A=530000(1.01)^{4t} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{after 12 years}}{t=12}\implies A=530000(1.01)^{4(12)}\implies A=530000(1.01)^{48} \\\\\\ A\approx 854479.82~\hfill \underset{\textit{interest in the account}}{\stackrel{854479.82~~ - ~~530000}{\approx 324479.82}}[/tex]

Answer:

Soln:

Step-by-step explanation:

Here,

Base(b) =9

Opposite/Perpendicular (p)= x

Hypotenus (h) = 24

We know,

(p)^2 = (h)^2 - (b)^2

(x)^2 = (24)^2 - (9)^2

x^2 = 576 - 81

x^2 = 495

x = root under 495

Answer:

1- 22.2486  2- No

Step-by-step explanation:
1:

[tex]b = \sqrt{ c^{2}- a^{2}[/tex]

C is the hypotenuse, or longest side of the triangle (24).

A is the one length we have besides the hypotenuse(9).

[tex]b = \sqrt{ 24^{2}- 9^{2}[/tex]

b = 22.2486

2:
No, because if it was a Pythagorean triple, it would follow the equation [tex]a^{2} +b^{2} =c^{2}[/tex].

[tex]9^{2} + 22.2485^{2} \neq 24^{2}[/tex].

Answer:

D.  1  1/2 feet

Step-by-step explanation:

Multiply the numbers to find the length of wire used.

Correct choice is D

Answer:

The distance is 20 units

Step-by-step explanation:

Answer: here

Step-by-step explanation:

−21−24

Answer: negative 21 Negative 224

-21-24

Answer:

3.6 m/h

Step-by-step explanation:

Distance (d) = 9 Km

Time (t) = 2.5 hour

Speed ( s )

Speed = Distance / Time

s = d / t

s = 9 / 2.5

s = 90 / 25

s = 18 / 5

s = 3.6 Km/h

The surface area of the right prism with an isosceles triangle base is 720 inches squared.

surface area = bh + l(x + y + z)

where

Therefore,

b = 24 inches

h = 5 inches

x = 13 inches

y = 13 inches

z = 24 inches

l = 12 inches

Surface area = 24 × 5 + 12(13 + 13 + 24)

Surface area = 120 + 12(50)

Surface area = 120 + 600

Surface area = 720 inches²

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Answer:

get a book from shop and draw with ruler and write the numbers too

The town should be located 13.4 units from each other

The formula for calculating the distance between two points is expressed as:
√(x2-x1)²+(y2-y1)²

The midpoint of two coordinates is expressed as:
[tex]m(x, y)=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )[/tex]

Substitute the given coordinate

[tex]m(x, y)=(\frac{3+15}{2}, \frac{1+7}{2} )\\m(x,y)=(9,4)[/tex]

Hence the town should be located at coordinate (9, 4)

Calculate the distance

D =  √(15-3)²+(7-1)²

D =  √(12)²+(6)²

D = 13.4units

Hene the town should be located 13.4 units from each other

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Answer:

  sh.299,449.72

Step-by-step explanation:

The future value of an ordinary annuity with annual payments P earning interest rate r compounded annually for t years is ...

  FV = P((1+r)^t -1)/r

For the given numbers, the future value is ...

  FV = sh.25000(1.07^9 -1)/0.07 ≈ sh.299,449.72

Answer:

[tex]x= \dfrac 72, ~~y= -2[/tex]

Step by step explanation:

[tex]4x+5y=4~~~...(i)\\\\2x-y=9~~~...(ii)\\\\\text{Multiply eq (ii) by 2 to isolate x:}\\\\4x-2y=18~~~.....(iii)\\\\(iii)-(i):\\\\4x-2y-4x-5y=18-4\\\\\implies -7y=14\\\\\implies y = -\dfrac{14}7 = -2\\\\\text{Substitute}~ y=-2~ \text{in equation (iii):}\\\\4x-2(-2) = 18\\\\\implies 4x +4 = 18\\\\\implies 4x = 18-4\\\\\implies 4x = 14\\\\\implies x = \dfrac{14}4 = \dfrac 72\\\\\text{Hence}~ (x,y) =\left(\dfrac 72 , -2 \right)[/tex]

Step-by-step explanation:

4x+5y=4 (equation 1)

2x-y=9 (equation2)

solving equation 1 and 2 and multiplying equation 2 by 2

4x+5y=4

4x-2y=18

- + -

________

7y= -14

y= -2

putting the value of y in equation 2

2x-y=9

2x+2=9

2x=7

x=3.5

Answer:

there would be around 40,000 colony of bats

There to be about 13,286,025 bats in the colony after 12 years if the growth rate remains constant.

An exponential function's curve is created by a pattern of data called exponential growth, which exhibits higher increases over time.

y = a(1+r)ˣ,

where a is the initial population and r is the rate in decimals and x is the time period.

To solve this problem, we need to use the formula for exponential growth:

N = N₀ (1 + r)ˣ

where:

N is the final number of bats after x years

N₀ is the initial number of bats

r is the annual growth rate (expressed as a decimal)

x is the number of years.

We can use the information given in the problem to find the values of N0, r, and t for the first two time periods:

For the first 4 years:

2025 = N₀(1 + r)⁴

For the next 2 years (6 years in total):

18225 = N₀ (1 + r)⁶

To solve for N₀ and r, we can divide the second equation by the first equation:

18225/2025 = (N₀ (1 + r)⁶) / (N₀(1 + r)⁴)

9 = (1 + r)²

Taking the square root of both sides, we get:

1 + r = 3

r = 2 (since r is expressed as a decimal)

Now that we know r, we can use either of the two original equations to find N₀. Let's use the first equation:

2025 = N₀(1 + 2)⁴

2025 = N₀(81)

N₀ = 25

So the initial number of bats was 25, and the annual growth rate is 200% (or 2 as a decimal).

Now we can use the formula to find the number of bats after 12 years:

N = 25 (1 + 2)¹²

N = 25 (531441)

N = 13,286,025

Therefore, we can expect there to be about 13,286,025 bats in the colony after 12 years if the growth rate remains constant.

To learn more about exponential growth;

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#SPJ7

The median, upper and lower quartiles of the data set are:

Lower Quartile = 46

Median = 49

Upper Quartile = 90

The center value or middle value of a data set is the median.

Upper quartile (Q3) is the center or middle data point of the second half of a data set.

Upper quartile (Q3) is the center or middle data point of the second half of a data set.

Order the data set given as:

32, 46, 49, 49, 77, 90, 96

Lower Quartile = 32, (46), 49, 49, 77, 90, 96 = 46

Median = 32, 46, 49, (49,) 77, 90, 96 = 49

Upper Quartile = 32, 46, 49, 49, 77, (90,) 96 = 90

Learn more about the Median, Upper and Lower Quartiles on:

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Answer:

  yes; 2 m = 200 cm

Step-by-step explanation:

The SI prefix "centi-" signifies 1/100. That is 300 cm = 300/100 m = 3 m.

If the ceiling is 3 meters high, a sculpture that is 2 meters tall will have no difficulty fitting into the room.

Answer:

A rectangle with sides lengths 4cm and 6cm and a rectangle with side lengths 2cm and 12 cm...

The mode is 78

Mode: The digit that has been repeated the most in a specific data.

To determine the mode of the data, let's arrange the data in ascending order.

Arranging the data in ascending form, we get:

In the ascending data, we can see that: (Refer to underlined and bolded text)

Since 78 has been repeated the most, 78 is the mode of the data.

The twenty units of potatoes illustrates the measure of central tendency  and probability

Start by sorting the dataset:

0.19; 0.28; 0.55;

0.62; 0.68; 0.77;

0.88; 0.89; 0.98;

0.99; 1.11; 1.22;

1.22; 1.22; 1.33;

1.44; 1.48; 1.68;

1.77; 1.99

The highest occuring element is 1.22 with a frequency of 3

The two middle elements are 0.99 and 1.11.

The mean of these two middle elements is: 0.5 * (0.99 + 1.11) = 1.05

The mean of the whole dataset is:

Mean = (0.19+ 0.28+ 0.55+ 0.62+ 0.68+ 0.77+ 0.88+ 0.89+ 0.98+ 0.99+ 1.11+ 1.22+1.22+ 1.22+ 1.33+ 1.44+ 1.48+ 1.68+1.77+1.99)/20

Mean = 1.06

Hence, the modal weight is 1.22, the mean is 1.06, and the median is 1.05

(a) at least 1.1 kg

There are 10 potatoes that weigh at least 1.1 kg.

So, the probability is:

P = 10/20

P = 0.5

(b) more than 3.5kg

There are 0 potatoes that weigh more than 3.5 kg.

So, the probability is:

P = 0/20

P = 0

(c) below 0.50kg

There are 2 potatoes that weigh below 0.50 kg.

So, the probability is:

P = 2/20

P = 0.1

The Variance of the weight.

This is calculated as:

Var = [tex]\sum[/tex](x - mean)^2/n

This gives

Var = [(0.19 - 1.06)^2 + (0.28 - 1.06)^2 + (0.55 - 1.06)^2 + (0.62 - 1.06)^2 + (0.68 - 1.06)^2 + (0.77 - 1.06)^2 + (0.88 - 1.06)^2 + (0.89 - 1.06)^2 + (0.98 - 1.06)^2 + (0.99 - 1.06)^2 + (1.11 - 1.06)^2 + (1.22 - 1.06)^2 + (1.22 - 1.06)^2 + (1.22 - 1.06)^2 + (1.33 - 1.06)^2 + (1.44 - 1.06)^2 + (1.48 - 1.06)^2 + (1.68 - 1.06)^2 + (1.77 - 1.06)^2 + (1.99 - 1.06)^2]/20

Evaluate

Var = 0.22

This means that:

The expectation of the squared deviation of the random variable from the mean is 0.22 kg

Read more about measure of central tendency at:

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Answer:

0.22 kg

Step-by-step explanation:

Answer:

$600

Step-by-step explanation:

This can be modeled as an exponential equation.

General form of an exponential function: [tex]y=ab^x[/tex]

where:

Therefore:

[tex]\implies 75=a(0.5)^3[/tex]

[tex]\implies 75=0.125a[/tex]

[tex]\implies a=\dfrac{75}{0.125}[/tex]

[tex]\implies a=600[/tex]

Therefore, the computer initially cost $600.

Answer:

12 cups

Step-by-step explanation:

The ratio he uses is

2 parts strong coffee

3 parts milk

Let's say he makes a recipe exactly like the amounts of the ratio.

2 cups strong coffee

3 cups milk

Total: 2 cups + 3 cups = 5 cups

He wants to make 30 cups, so 5 cups is not enough.

Let's double the amounts of the recipe keeping the same ratio of 2 to 3.

2 × 2 = 4 cups strong coffee

3 × 2 = 6 cups milk

Total: 4 cups + 6 cups = 10 cups

He wants to make 30 cups, so 10 cups is not enough.

We can keep on going up by multiplying the numbers in the ratio by larger numbers, but there is a quicker way.

We need to multiply both numbers in the ratio by a number, let's call it x, so that when both numbers in the ratio are multiplled by x, and the ingredients are added, we end up with 30 cups.

Multiply both numbers in the ratio by x.

2x cups of strong coffee

3x cups of milk

Now add: the total amount will be 5x cups

We want 30 cups, so

5x = 30

Solve for x.

x = 30/5 = 6

x, the multiplier we need is 6.

2x cups strong coffee = 2(6) cups = 12 cups

3x cups milk = 3(6) cups = 18 cups

Answer: 12 cups

Answer:

5/6

Step-by-step explanation:

since there already is a common denominator all you have to do is add the numerators

Answer:

hopefully this helps :] 16th line down I think

Answer:

15

Step-by-step explanation:

hope this helps

Answer:

s = [tex]\frac{1}{3}[/tex]

Step-by-step explanation:

s = ut + [tex]\frac{1}{2}[/tex] at² ( substitute the given values into the equation )

s = ( 3 × [tex]\frac{1}{3}[/tex] ) + ( [tex]\frac{1}{2}[/tex] × - 12 × ([tex]\frac{1}{3}[/tex] )² )

  = 1 + (- 6 × [tex]\frac{1}{9}[/tex] )

  = 1 + ( - [tex]\frac{2}{3}[/tex] )

  = 1 - [tex]\frac{2}{3}[/tex]

  = [tex]\frac{1}{3}[/tex]

Answer:

[tex] \hookrightarrow \: u = 3 || \: a = - 12 \: || t = \frac{1}{3} \\ \hookrightarrow \: s = ut + \frac{1}{2} a {t}^{2} \\ \hookrightarrow \: s =3 \times \frac{1}{3} + \frac{1}{2} \times - 12 \times (\frac{1}{3} )^{2} \\ \hookrightarrow \: s =1 - \frac{2}{3} \\ \hookrightarrow \: s = \frac{1}{3} [/tex]

Answer:

15% interest

Step-by-step explanation:

because it's 15 out of 100 so that would be 15%

Answer: About 800 thousand

The more accurate value is 807,528 but this is also an approximation.

=======================================================

Work Shown:

[tex]t = \text{number of years since the year 2000}[/tex]

[tex]P_0 = \text{population (in millions) in the year 2000}[/tex]

[tex]P = P_0(1.2)^t\\\\5 = P_0(1.2)^{10}\\\\5 \approx P_0*6.1917364224\\\\P_0 \approx \frac{5}{6.1917364224}\\\\P_0 \approx 0.80752791444922\\\\P_0 \approx 0.807528\\\\[/tex]

That's the rough population of wild pigs (in millions) for the year 2000.

Multiply by [tex]10^6[/tex] to get it in terms of units instead.

[tex]0.807528\times10^6 = 807,528[/tex]

There were roughly 800 thousand wild pigs in the year 2000.