How much work, , must be done on a system to decrease its volume from 19.0 L to 11.0 L by exerting a constant pressure of 6.0 atm?

w = ________ kJ

Decay of Uranium-238 produces gamma radiaton whereas decay of thorium-234 releases beta radiation.

In the decay of U-238, two gamma rays of different energies are emitted in addition to the alpha particle while on the other hand, in the decay of thorium-234 , beta rays are emitted.

So we can conclude that decay of Uranium-238 produces gamma radiaton whereas decay of thorium-234 releases beta radiation.

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Answer:

c. energy from splitting energy

Explanation:

Temperature and pressure control the phase of a substance. A phase diagram is a graph of pressure versus temperature that shows in which phase a substance exists under different conditions of temperature and pressure. A phase diagram typically has three regions, each representing a different phase, and three curves that separate each phase.

In a phase diagram, the three regions correspond to the three common phases of matter: solid, liquid, and gas. The curves that separate each phase are known as phase boundaries or phase transition lines. These curves represent the conditions (specific combinations of pressure and temperature) at which phase transitions occur, such as melting (solid to liquid), boiling (liquid to gas), or sublimation (solid to gas).

Each phase boundary on the phase diagram represents the equilibrium between two phases, and the triple point, where all three phase boundaries intersect, represents the conditions where all three phases coexist in equilibrium.

Phase diagrams are essential tools in understanding the behavior of substances under different temperature and pressure conditions and are used in various fields, including chemistry, physics, and materials science. They provide valuable information about the stability and existence of different phases and the conditions under which phase transitions occur.

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Answer:

B

Explanation:

By finding how quickly the ice pathes melt you are able to tell how well the salt dissolves in water (ice is the solid form of H2O). Different types of salts will melt the ice at different speeds.

This is also the only answer choice that correlates with melting points so :)

Answer:

c

Explanation:

lol

Answer: Smelling salts and oxygen are introduced into a metal catalyst-containing tube (platinum). Typically warmed to get the reaction started. The alkali is then oxidized to produce nitric oxide.

Answer:

The Ostwald process is a chemical process used for making nitric acid. Wilhelm Ostwald developed the process, and he patented it in 1902. The Ostwald process is a mainstay of the modern chemical industry, and it provides the main raw material for the most common type of fertilizer production

Explanation:

The first stage of the Ostwald process involves the catalytic oxidation of ammonia into nitric oxide, using platinum as the catalyst. The nitric oxide is then transferred to a different oxidizing tower, where it is oxidized into nitrogen dioxide

Explanation:

hello

the answer is b

O or oxygen has 16 molar mass and C or carbon has 12

so CO2 or carbon dioxide=(2×O)+C=(2×16)+12=46

For a [Cd2+]=0.00190 M and [Au3+]=0.788 M conc, the cell potential  is mathematically given as

Ecell=1.98V

Generally, the equation for the  Chemical reaction is mathematically given as

Cd2+(aq) + 2e – → Cd(s)

Au3+(aq) + 3e– → Au(s)

Therefore

Ecell=Ecell-0,0582/nlog

Therefore

Ecell=Ered-Eoxy

Ecell=1.498-(-0.403)

Ecell=1.901

In conclusion

Ecell=1,901-0,0592/6log(0,0016/0.88)^2

Ecell=1.98V

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Answer:

[tex]\fbox{c = - 4.01 \: joule/g°C}[/tex]

Step by step explanation:

Given:

Mass of given sample (m) = 2.50 g

Initial temperature (T1) = 25°C

Final temperature (T2) = 20°C

Heat Energy Q = 12 cal

To find:

[tex]Specific \: Heat \: c = \: ?[/tex]

Solution:

We know that,

Specific heat of any substance is directly proportional to the mass and change in temperature.

Represented by equation,

[tex]Q = mc \triangle T[/tex]

Where,

Q = Heat Energy

m = mass of given sample

c = specific heat

∆T = change in temperature

Substituting corresponding values,

[tex]Q = mc \triangle T \\ 12 = 2.5\times c \times (20-25) \\ c = \frac{12}{2.5 \times ( - 5)} \\ c = - 0.96 \: cal/g°C \\ [/tex]

We also know that,

[tex]1 \: cal = 4.184 \: joules[/tex]

multiplying above answer by 4.184,

[tex]c = - 0.96 \times 4.184 \\ \fbox{c = - 4.01 \: joule/g°C}[/tex]

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Answer:

b.exothermic and entropy is decreasing

Answer:

the image is not clear....

Answer:

You gain sodium basically through the food you eat and lose it basically by excretion through urine,sweat

1129.9 grams of rock salt, NaCl needs to be added to a 3.78 kg of ice, to get the temperature to drop to -19C .

Freezing point depression refers to a property of solutions where addition of a solute lowers the normal freezing point of the solvent.

The Blagden's Law given as the equation above is used to determine the freezing point depression of ice:

where;

For NaCl, i = 2

Kf for water/ice = 1.86 °C kg/mol

molalityof NaCl = (mass/molar mass

l)/kg of ice

molar mass of NaCl = 58.5

mass of ice = 3.78 kg

Let molality of NaCl = m

ΔT = 19 °C

Substituting the values:

19 = 2 x 1.86 °C kg/mol x m

m = 5.11 mol/kg

mass of NaCl = 5.11 × 3.78 × 58.5

mass of NaCl = 1129.9 g

Therefore, the mass in grams of rock salt, NaCl that needs to be added to a 3.78 kg of ice, to get the temperature to drop to -19C is 1129.9 g

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Answer:

car hornsss

Explanation:

they loud asl

Answer:

A

Explanation:

it can occur between two hydrogen bonds

Answer:

If temperature stays the same, the amount of carbon dioxide dissolved in the ocean would increase.

Explanation:

The carbon dioxide in the air ([tex]{\rm CO_{2}}\, (g)[/tex]) and the carbon dioxide dissolved in the ocean ([tex]{\rm CO_{2}}\, (aq)[/tex]) are in a solution equilibrium:

[tex]{\rm CO_{2}}\, (g) \rightleftharpoons {\rm CO_{2}}\, (aq)[/tex].

Assume that the concentration of carbon dioxide in the air ([tex]{\rm CO_{2}}\, (g)[/tex]) increased while temperature stayed the same.

By Le Ch[tex]^{}[/tex]atelier's Principle, the solution equilibrium [tex]{\rm CO_{2}}\, (g) \rightleftharpoons {\rm CO_{2}}\, (aq)[/tex] would shift to offset this increase in [tex]{\rm CO_{2}}\, (g)[/tex] concentration. Specifically, this equilibrium would reduce the amont of [tex]{\rm CO_{2}}\, (g)\![/tex] in the system by converting more atmospheric [tex]{\rm CO_{2}}\, (g)\!\![/tex] to [tex]{\rm CO_{2}}\, (aq)\![/tex] dissolved in the ocean. Therefore, the concentration of [tex]{\rm CO_{2}}\, (aq)\!\![/tex] dissolved in the ocean would increase.

Answer:

D

Explanation:

Took the test!

Gluons act as exchange particles and are known as gauge bosons. They are involved in the forces within the atom as a strong nuclear force that binds the nucleus. Thus, option D is correct.

A strong nuclear force is a type of interaction that is present inside the atom and involves the nucleus. They bind the quarks to make the neutron and the proton, sub-atomic particles.

The strong nuclear force holds the atomic nucleus together and depends on the spin but not the charge. These forces are due to the interaction between the gluons and are stronger than the chemical bonds. The exchange of the mesons results in nucleons that lead to a strong nuclear force.

Therefore, option D. the gluons are responsible for the strong nuclear forces that bind the nucleus.

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Answer:

Lim reag = NO        .07 mole of O2 left over

Explanation:

From the equation, you need twice as many moles of NO as O2

  2 x moles O2 =     2 * .503 moles = 1.06 moles of NO needed....you do not have enough so this is the limiting reagent    O2 will be left over

    1/2 * .866 = .433  moles of O2 used    .503 - .433 = .07  mole O2 leftover

The volume, in Liters, that would be required to obtain 0.500 moles of Br ions from 1.40 M FeBr2 will be 0.36 L

Recall that:

Molarity = mole/volume

In this case, molarity = 1.40 M and moles = 0.500 moles

Thus:

Volume = mole/molarity = 0.500/1.40 = 0.36 L

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Answer:

0.109

Explanation:

0.4-0.291=0.109

If the length of a string increases 2 times but the mass of the string remains constant, the original density  will be multiplied by a factor  mathematically given as

v=1.414 times

Generally, the equation for the  volume is mathematically given as

v = sqt(TL/m)

Where

density = mass/length

Therefore

[tex]v2/v1 = \sqrt{L2/L1}[/tex]

[tex]v2/v1 = \sqrt{2}[/tex]

In conclusion,v ratio will give us

v=1.414 times

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Answer:

Explanation:

In The RGB color model, colors are described in numerical codes which are written in brackets and separated by commas.

RGB model is a color ( additive ) which enables the addition of  RED, Green and Blue colors  which are the primary colors of light in various ways to produce different colors.

In RGB model the RGB values gets to display different colors when used on different devices hence it can not be described as a reference point for RED, Green and Blue colors.

Hence we can conclude that In The RGB color model, colors are described in numerical codes which are written in brackets and separated by commas.

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Attached below is the GIZMO image

The purpose of both mitosis and meiosis is to increase the number or population of cells in the body.

Mitosis produces two diploid (2n) cells that are identical to the original parent cell whereas meiosis produces four haploid (n) cells that are different from the original parent cell.

Mitosis occurs in somatic cells whereas meiosis occurs in reproductive cells.

So we can conclude that the purpose of both mitosis and meiosis is to increase the number or population of cells in the body.

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Answer:

the sun i think because the sun has the greatest gravitational pull

The false statement from the above is that: Temporary charge imbalances in the molecules lead to London dispersion forces.

Generally, the factors which affects the London dispersion forces a dispersion force are as follows:

However, London dispersion forces simply refers to a sort of temporary attractive force formed when electrons in two adjacent atoms occupy positions that make the atoms form dipoles.

So therefore, temporary charge imbalances in the molecules lead to London dispersion forces is a false statement

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