help pleaseeeeeeee this is harddddddddddddddddd

Answer:

who is William afton family?

Answer:

Answer:

\sf (x+14)^2+(y+5)^2=149(x+14)2+(y+5)2=149

Step-by-step explanation:

Standard equation of a circle:  \sf (x-a)^2+(y-b)^2=r^2(x−a)2+(y−b)2=r2

(where (a, b) is the center and r is the radius of the circle)

Substitute the given center (-14, -5) into the equation:

\sf \implies (x-(-14))^2+(y-(-5))^2=r^2⟹(x−(−14))2+(y−(−5))2=r2

\sf \implies (x+14)^2+(y+5)^2=r^2⟹(x+14)2+(y+5)2=r2

Now substitute the point (-7, 5) into the equation to find r²:

\sf \implies ((-7)+14)^2+(5+5)^2=r^2⟹((−7)+14)2+(5+5)2=r2

\sf \implies (7)^2+(10)^2=r^2⟹(7)2+(10)2=r2

\sf \implies 149=r^2⟹149=r2

Final equation:

\sf (x+14)^2+(y+5)^2=149(x+14)2+(y+5)2=149

Step-by-step explanation:

In a recent poll, 50 teenagers were asked do they exercise regularly. 35% of them said they do exercise regularly? What is the random Variable?

Answer:

the more you will pay in interest cost

Linear equations are usually organized in slope-intercept form, which looks like this:

[tex]y=mx+b[/tex]

To find the equation of a line in slope-intercept form:

We're given:

First, plug the given slope into the slope-intercept form equation:

[tex]y=mx+b\\\\y=\dfrac{1}{2}x+b[/tex]

Now, determine the y-intercept.

[tex]y=\dfrac{1}{2}x+b[/tex]

⇒ Plug in the given point (4,1) and solve for b:

[tex]1=\dfrac{1}{2}(4)+b\\1=2+b\\b=-1[/tex]

⇒ Therefore, the y-intercept is -1. Plug this back into our original equation:

[tex]y=\dfrac{1}{2}x-1[/tex]

[tex]y=\dfrac{1}{2}x-1[/tex]

Answer:

5 [tex]\frac{5}{8}[/tex]

Step-by-step explanation:

[tex]\frac{1}{4} = \frac{2}{8}[/tex]

[tex]\frac{2}{8} + 5\frac{3}{8}[/tex]

Your solution is:

5 [tex]\frac{5}{8}[/tex]

Presumably, both δ and ρ represent density of some object. Considering the context, ρ is likely a function of 3 variables, ρ = ρ(x, y, z). Then the mass of the sphere with the prescribed density δ(x, y, z) = k ρ(x, y, z) is

[tex]\displaystyle \iiint_B k \rho(x,y,z) \, dx\, dy\, dz[/tex]

where B is the set

[tex]B = \left\{(x,y,z) ~ : ~ x^2+y^2+z^2 \le 7^2\right\}[/tex]

If you have all the details at hand, you can compute the integral by converting to spherical coordinates, substituting

[tex]\begin{cases}x = u \cos(v) \sin(w) \\ y = u \sin(v) \sin(w) \\ z = u \cos(w)\end{cases} \text{ and } dx\,dy\,dz = u^2 \sin(w) \, du \, dv \, dw[/tex]

The integral then transforms to

[tex]\displaystyle k \int_0^{2\pi} \int_0^\pi \int_0^7 \rho(u\cos(v)\sin(w),u\sin(v)\sin(w),u\cos(w)) \, u^2 \sin(w) \, du \, dw \, dv[/tex]

Without any additional information, there's not much more to say...

Answer:

52

Step-by-step explanation:

a-8x =4-8×-6

=4-(-48)= 4+48=52

Answer:

blank = 0.23

Step-by-step explanation:

to do this you can divide both sides by 100

23/100 is 0.23

blank = 0.23

Answer:

0.23 or 23/100

Step-by-step explanation:

1) Start by setting up an equation

We'll say that x represents the blank.

100x = 23

2) Solve

100x = 23

Divide both sides by 100

x = 0.23 or 23/100

Answer:

[tex]Probability = \frac{4}{9} [/tex]

Given:

The die was rolled twice having six sides,

To find:

probability of getting a number greater than 2 =?

solution:

The probability of getting a number greater than 2 on single roll =

[tex] \frac{4}{6} = \frac{2}{3} [/tex]

Similarly on second roll the probability would be

[tex] \frac{2}{3} [/tex]

Since two events are occurring together, the total probability of finding number greater than 2 in both rolls =

[tex] \frac{2}{3} \times \frac{2}{3} = \frac{4}{9} [/tex]

Thanks for joining brainly community!

I think it's an= 13.5 - 2.5n

[tex]a_n=13.5-2.5n[/tex]

[tex]11,\ 8.5,\ 6,\ 3.5,\ 1...[/tex]

[tex]So\ d=8.5-11=b-8.5=3.5-6=1-3.5[/tex]

       [tex]=-2.5[/tex]

[tex]And\ a_1=\parallel \left\{Anithmetic\ \left.\ sequence\right\}\right.[/tex]

[tex]so\ a_n=a_1+d(n-1)[/tex]
         [tex]=11-2.5(n-1)[/tex]
         [tex]=13.5-2.5n[/tex]

[tex]The\ answer:a_n=13.5-2.5n[/tex]

I hope this helps you

:)

Answer:

3n+6

Step-by-step explanation:

"3 times the quantity n" = 3 * n = 3n

3n+6

Answer:

x = 50 degrees

Step-by-step explanation:

all the angles of a triangle add up to 180

a right angle is ninety degrees

90 + the 40 degrees on the top is 130 degrees

180 - 130 is 50

x = 50

Answer:

[tex] \: [/tex]

Step-by-step explanation:

Before finding the value of x, we must know this first.

[tex] \\ \longrightarrow \qquad { \underline{ \boxed{ \pmb{ \frak{Sum \: of \: all \: \: angles_{(Triangle)} = 180 {}^{ \circ} }}}}} \: \: \bigstar \\ \\ [/tex]

This is a right angled triangle so,

[tex] \\ \longrightarrow \qquad { { { \pmb{ \sf{ \angle \: 1 +\angle \: 2 + \angle \: 3= {180}^{ \circ} }}}}} \\ \\ [/tex]

[tex]\longrightarrow \qquad { { { \pmb{ \sf{ x^{ \circ} + {90}^{ \circ} + {40}^{ \circ} = {180}^{ \circ} }}}}} \\ \\ [/tex]

Adding like terms we get :

[tex] \\ \longrightarrow \qquad { { { \pmb{ \sf{ x^{ \circ} + {130}^{ \circ} = {180}^{ \circ} }}}}} \\ \\ [/tex]

Subtracting 130° from both sides :

[tex] \\ \longrightarrow \qquad { { { \pmb{ \sf{ x^{ \circ} + {130}^{ \circ} - {130}^{ \circ} = {180}^{ \circ}- {130}^{ \circ}}}}}} \\ \\ [/tex]

[tex]\longrightarrow \qquad { \underline { \boxed{ \pmb{ \frak{ x^{ \circ} = {50}^{ \circ}}}}}} \: \: \bigstar\\ \\ [/tex]

Therefore,

[tex]\cfrac{42}{70}~~ = ~~\cfrac{u}{55}\implies \cfrac{(14)3}{(14)5}~~ = ~~\cfrac{u}{55}\implies \cfrac{3}{5}=\cfrac{u}{55}\implies \cfrac{3(55)}{5}=u \\\\\\ 3\cdot \cfrac{55}{5}=u \implies 3\cdot 11=u\implies 33=u[/tex]

practice harder and harder you will get what you want

Answer:

164,340

Step-by-step explanation:

[tex]120n+160500\\120(32)+160500\\3840+160500\\164340[/tex]

Put n=32

Answer:

x = 15

Step-by-step explanation:

Since m and n are parallel to the line t.

Then (7x - 10) + (6x - 5) = 180° supplementary angles for a linear pair.

(7x - 10) + (6x - 5) = 180°

13x -15 = 180°

13x = 195°

x = 15

Plug x into the angles to solve for angle.

(7x - 10)

(7*15 - 10) = 105 - 10 = 95°

(6x - 5) =

(6*15 - 5) = 90 - 5 = 85°

Answer:

C. (x , y) ----> (y , - x)

hope this helps :)

Answer:

scale factor = 6

Step-by-step explanation:

the scale factor is the ratio of corresponding sides, shape B to shape A

base of shape A = 1 , base of shape B = 6 , then

scale factor = [tex]\frac{6}{1}[/tex] = 6

After finding the ratio of their corresponding sides of triangles the scale factor we get is 6.

The difference in scale between an original item's scale and a new object that is its representation but is larger or smaller is known as a scale factor.

From figure

For small triangle:

base = 1 units

For large triangle:

base = 6 units

Now the scale factor = ratio of adjacent sides

Scale factor = (Base of large triangle)/(Base of small triangle)

Scale factor = 6/1

Scale factor = 6

Hence,

The scale factor is 6.

To learn more about the triangle visit;

brainly.com/question/1058720

#SPJ4

Answer:

w=2

Step-by-step explanation:

Step-by-step explanation:

first simplified by dividing both sides by -5.

then, at

w - 5 = -3

add 5 to both sides.

and we get

w = 2

Answer:

Answer given below in the following pictures.

I hope my answer helps you.

Answer:

360 naira hope its help

Step-by-step explanation:

brainliest me

Answer:

86.28 degrees

Step-by-step explanation:

Angle between vectors is

[tex] \cos(x) = \frac{cross \: product}{magnitudes \: multiplied} [/tex]

The cross product is

[tex]4 + 0 - 3 = 1[/tex]

The magnitudes of first vector is

[tex] \sqrt{1 {}^{2} + 2 {}^{2} + 3 {}^{2} } = \sqrt{14} [/tex]

The second vector magnitude is

[tex] \sqrt{17} [/tex]

So the magnitudes multiplied is

[tex] \sqrt{14} \times \sqrt{17} = \sqrt{238} [/tex]

So our equation will be

[tex] \cos(x) = \frac{1}{ \sqrt{238} } [/tex]

[tex]x = \cos {}^{ - 1} ( \frac{1}{ \sqrt{238} } ) [/tex]

X is about 86.28 degrees

Answer:

2 7/24

Step-by-step explanation:

First we have to add the gallons of two cow of each owner:

Hank's cows: 4 3/4 + 4 1/8

Add the whole numbers:

4 + 4 = 8

Now for 3/4 and 1/8

Find common

6/8 + 1/8

= 7/8

Put together :

8 7/8

Debra's cows: 5 1/2 + 5 2/3

Add the whole number

5 + 5 = 10

Now for 1/2 and 2/3

3/6 + 4/6

1 1/6

10 + 1 1/6

= 11 1/6

Since now we know that:

Hank - 8 7/8

Debra - 11 1/6

we can solve the question:

How many more gallons of milk did Debra's two cows produce on that compared to Hank's two cows?

Solution:

11 1/6 - 8 7/8

Subtract whole number

11 - 8 = 3

Now for 1/6 and 7/8

4/24 - 21/24

4-21/24

-17/24

2 7/24

~lenvy~

Answer:

2 7/24

Step-by-step explanation:

Hank Cows:

4 3/4 and 4 1/8

Debra Cows:

5 1/2 and 5 2/3

To find the difference between Hank cows and Debra cows..

we first have to add both cows together:

4 3/4 + 4 1/8 = 8 7/8  {Hank}

5 1/2 + 5 2/3 = 11 1/6  {Debra}

Since now we know Hank and Debra total gallons of milk we can solve and find out the difference.

11 1/6 - 8 7/8 = 2 7/24

Hence, Debra have 2 7/24 more gallons of milk than Hank.

[RevyBreeze]

Answer:

________________________________________________________

Multiply all numbers by the multiplier, the smaller number, and then use any extra digits you carry, bringing you to the ten thousands place.

________________________________________________________

Ask me in the comments box, I can help.

Answer:

a

Step-by-step explanation:

absolute value means the distance from 0 and it has to be a positive number so the answer has to be a

Step-by-step explanation:

did you meant 6log_10? *text because it need to be 20 characters*

Answer:

18log_5x

Step-by-step explanation:

log(a^b) = b·log(a)

6log_(5)x^(3) =

6(3log_5x)

18log_5x

https://brainly.com/question/12671040

https://brainly.com/question/16913208

[tex]\sin 30^{\circ} = \dfrac{LJ}{8\sqrt 2}\\\\\implies LJ = 8\sqrt 2 \sin 30^{\circ} =8\sqrt 2 \cdot \dfrac 12 = 4\sqrt 2\\\\ \text{Now,}\\\sin 45^{\circ} = \dfrac{LM}{LJ} \\\\\implies LM = \sin 45^{\circ} LJ\\\\\implies x = \dfrac 1{\sqrt 2} \cdot 4\sqrt 2 = 4 ~~ units.[/tex]

Answer:

x = 4

Explanation:

[tex]\sf sin(x)= \dfrac{opposite}{hypotensue}[/tex]

Solve for LJ:

[tex]\hookrightarrow \sf sin(30) = \dfrac{LJ}{8\sqrt{2} }[/tex]

[tex]\hookrightarrow \sf sin(30)*8\sqrt{2} ={LJ}[/tex]

[tex]\hookrightarrow \sf {LJ} = 4\sqrt{2}[/tex]

Solve for LM:

[tex]\hookrightarrow \sf \sf sin(45)= \dfrac{LM}{4\sqrt{2} }[/tex]

[tex]\hookrightarrow \sf \sf sin(45)*4\sqrt{2} = {LM}[/tex]

[tex]\hookrightarrow \sf {LM} = 4[/tex]