Answer:(x+5)(x-2) I Dont know what a special product is sry
Step-by-step explanation:
A frog starts jumping from the middle of a circular pond.
The pond is 12 metres across, from one side to the other.
43
The frog always jumps half the distance left to the edge of the pond.
How far is the frog from the edge after 3 jumps?
Answer:
Step-by-step explanation:
Remark
You could do this simply by taking 3 jumps, without using a formula. That would work as well, but I think it is easier just to make 3 jumps.
Jump One
The frog starts out 6 meters from an edge. (He/she starts at the middle). The frog makes 1 jump.
He lands 3 meters (1/2 the distance) from the edge.
Jump Two
He jumps in such a way that he is 1/2 the distance from the edge. So far he is 3 meters away. His jump puts him 1 1/2 meters from the edge.
Jump Three
The frog makes one last jump. It is 1 1/2 meters from the edge. The third jump takes it 1/2 * 3/2 = 3/4 a meter away from the edge.
Answer: 3/4 of a meter from the edge.
Expand and simplify (x+6)(x−11)
Answer:
x^2 - 5x - 66
Step-by-step explanation:
1. Distrubute the x to the x and -11 so you will get x^2 - 11x
2. Distrubute the 6 to x and -11 and you get 6x - 66
3. Combine like terms (x^2 - 11x + 6x - 66) you will get x^2 - 5x - 66
PLEASE HELP TAKING TEST RN what are the midline, amplitude, period of this function?
Answer:
midine y=2
amplitude -3
period 5pie
please answer these for me! Right answers only. Thanks
Answer:
For all of these triangles apply the formula;
A = BH x 1/2
Where 'B' represents the base, 'H' stands for the height, and 1/2 just means to divide the product of the two lengths (base x height) by 2.
1.
Base = 9.1
Height = 31.2
Plug into formula:
A = BH x 1/2
A = 9.1(31.2) x 1/2
A = 283.92 x 1/2
A = 283.92/2
A = 141.96 square centimetres.
2.
Base = 5
Height = 3 3/4 which can be considered 3.75
Plug into formula:
A = BH x 1/2
A = 5(3.75) x 1/2
A = 18.75 x 1/2
A = 18.75/2
A = 9.375 square kilometres.
3.
Base = 2.4
Height = 3.2
Plug into formula:
A = BH x 1/2
A = 2.4(3.2) x 1/2
A = 7.68 x 1/2
A = 7.68/2
A = 3.84 square inches.
4.
Base = 11
Height = 60
Plug into formula:
A = BH x 1/2
A = 11(60) x 1/2
A = 660 x 1/2
A = 660/2
A = 330 square millimetres.
5.
Base = 10
Height = 13 1/2 which can be considered 13.5
Plug into formula:
A = BH x 1/2
A = 10(13.5) x 1/2
A = 135 x 1/2
A = 135/2
A = 67.5 square feet.
Answer:
1. 141.96 cm²
2. 9⅜ km²
3. 3.84 in
4. 10.39mm
5. 66.67 ft
Step-by-step explanation:
Formula of Area of Triangle : ½ × base × height
1. = ½ × 9.1 × 31.2
= 9.1 × 15.6
= 141.96 cm²
2. = ½ × 3¾ × 5
= ½ × 15/4 × 5
= 15/8 × 5
= 75/8 = 9⅜ km²
3. = ½ × 3.2 × 2.4
= 3.84 in
4. = tan c = AB/BC
c = tan -¹ (AB/BC)
c = tan -¹ (60/11)
c = 79.61
A = 90 - 79.61 = 10.39mm
5. = ½ × 13⅓ × 10ft
= 66.666 ≈ 66.67 ft
PLEASE MARK ME AS BRAINLIEST AND HAVE A NICE DAY :)
Michael has $1,059.35 in his checking account. He is going to spend $466.43 on a new television, and he will spend the rest on speakers that cost $43.00 each. Which of the following inequalities would determine the maximum number of speakers, x, Michael can buy without spending more money than he has in his account?
A.
$466.43 < $43.00x + $1,059.35
B.
$1,059.35 < $43.00x + $1,059.35
C.
$466.43 + $43.00 + x < $1,059.35
D.
$43.00x + $466.43 < $1,059.35
Answer:
D. $43.00x + $466.43 < $1,059.35
Step-by-step explanation:
He has $1,059.35.
The amount of speakers he buys is x.
Each speaker is $43.00, and he is buying one television, which is $466.43.
All of the speakers he buys and(+) the television must be less than $1,059.35 because that's all he has. It cannot be more, which is why the equation is $43.00x + $466.43 < $1,059.35.
Hope this helps!
Answer:
D
Step-by-step explanation:
its $43 each and he wants to buy more than one so that means thats x
that marks out C
so 43.00x +466.43 is less than 1,059.35
I really feel like one of them should have less than/greater than or equal to sign but without I think its D
What is the absolute value of -|-4| ?
Answer:
- 4
Step-by-step explanation:
the absolute value function always give a positive result , that is
| - a | = | a | = a
then
- | - 4 | = - | 4 | = - 4
A mobile set after allowing a discount of 10% on its marked price, was sold at a gain of 20%,Had it been sold after allowing 20% discount,there would have been a profit Rs.350. Find the cost price and marked price of the mobile set.
Answer:
Let x be the cost price.
Let y be the marked price
Gain = 20%
Then , sale price = 120/100 * x = 1.2x
Now , sale price is after 10% discount from marked price.
Hence , marked price, y = 1.2x/90 * 100 =
y * 0.9 = x * 1.2
Now, with 20% discount, sale price = y * 80/100 = 0.8y
Now, profit = 0.8y — x
Now, 0.8y — x = 350
0.8 * x * 1.2/0.9 — x = 350
1.0667x — x = 350
Hence, x = 350/0.0667= Rs.5250
Hence marked price = (5250 + 350) * 100/80 = Rs.7000
What is the period of rotation of the wheel for which the height of a rider (in feet) above the ground after riding the wheel for t seconds dunce passing the farthest right position on the wheel given by h(t)=60+45 sin (30t)?
According to the given sine function, it is found that the period of rotation is of 0.21 seconds.
What is the period of a sine function?Suppose a sine function modeled by:
[tex]y = A\sin{[B(x + c)]}[/tex]
The period is given by:
[tex]P = \frac{2\pi}{B}[/tex].
In this problem, the function is:
h(t)=60+45 sin (30t).
The vertical shift and the amplitude do not interfer in the period, hence B = 30 and:
[tex]P = \frac{2\pi}{30} = 0.21[/tex]
The period of rotation is of 0.21 seconds.
More can be learned about the period of a sine function at https://brainly.com/question/16818112
Without using a calculator, order the following expressions from least to greatest.
11/3, square root 20, square root 17
Answer:
[tex]\displaystyle \large{\frac{11}{3} < \sqrt{17} < \sqrt{20}}[/tex]
Step-by-step explanation:
( 1 ) 11/3
[tex]\displaystyle \large{\frac{11}{3}}[/tex] can be converted to mixed fractions to [tex]\displaystyle \large{3\frac{2}{3}}[/tex]
Therefore, 11/3 is at least around 3, almost 4. It could be more than 3.5 by approximation but not exactly 4.
( 2 ) √20
[tex]\displaystyle \large{\sqrt{20}=\sqrt{5\cdot 4}}\\\displaystyle \large{\sqrt{20}=\sqrt{5\cdot 2\cdot 2}}\\\displaystyle \large{\sqrt{20}=2\sqrt{5}}[/tex]
We know that [tex]\displaystyle \large{\sqrt{4}=2}[/tex] so [tex]\displaystyle \large{\sqrt{5} > \sqrt{4}}[/tex] which means approximately, [tex]\displaystyle \large{\sqrt{20}}[/tex] can be either at least 4.3 up to 4.4
( 3 ) √17
We know that [tex]\displaystyle \large{\sqrt{16} = 4}[/tex] so [tex]\displaystyle \large{\sqrt{17}}[/tex] can be at least 4.1 up to 4.2, but it’s obvious that the square root of 17 is less than square root of 20 since [tex]\displaystyle \large{\sqrt{a} > \sqrt{b}}[/tex] for a > b
Hence, from least to greatest:
[tex]\displaystyle \large{\frac{11}{3} < \sqrt{17} < \sqrt{20}}[/tex]
Out of 1200 students in a school , 24% were girls . How may boys were there?
Answer:
912
Step-by-step explanation:
number of girls :
[tex]1200\times \frac{24}{100} =12\times 24=288[/tex]
number of boys :
1 200-288 = 912
Find the value of A+B
5/x²+6x+8 = A/x+2 + B/x+4
Step-by-step explanation:
[tex] \frac{5}{ {x }^{2} + 6x + 8} = \frac{a}{x + 2} + \frac{b}{x + 4} \\ factorizing \: the \: denominator \: of \: the \: first \: term \\ {x}^{2} + 6x + 8 \\ {x}^{2} + 4x + 2x + 8 \\ ( {x}^{2} + 4x)( + 2x + 8) \\ x(x + 4) + 2(x + 4) \\( x + 2)(x + 4) \\ \\ \\ \\ \frac{5}{(x + 2)(x + 4)} = \frac{a}{x + 2} + \frac{b}{x + 4 } \\ multiplying \: by \: the \: lcm = (x + 2)(x + 4) \\ 5 = a(x + 4) + b(x + 2) \\ put \: x = - 4 \\ 5 = a( - 4 + 4) + b( - 4 + 2) \\ 5 = a(0) + b( - 2) \\ 5 = 0 - 2b \\ 5 = - 2b \\ b = \frac{5}{ - 2} \\ b = - 2 \ \frac{1}{2} \\ substituting \: b = - 2 \frac{1}{2} and \: put \: x = - 2 \\ 5 = a( - 2 + 4) + b( - 2 + 2) \\ 5 = a(2) + b(0) \\ 5 = 2a \\ a = 2 \frac{1}{2} \\ a + b = 2 \frac{1}{2} + ( - 2 \frac{1}{2} ) \\ 2 \frac{1}{2} - 2 \frac{1}{2} \\ a + b = 0[/tex]
Write the statements of the following algebraic expressions!
A- a+1
B- q-9
C- 3y+7
D- x/3+9
E- 3x+10
Answer:
See below ↓↓↓↓↓
Step-by-step explanation:
A - the sum of a number 'a' and 1B - the difference between a number 'q' and 9C - 7 plus the product of a number 'y' and 3D - 9 plus the quotient of a number 'x' and 3E - 10 plus the product of a number 'x' and 3= 1 more than a number (a)
B- q-9= q less than 9
C- 3y+7= 3 times y added to 7
D- x/3+9= a number (x) divided by 3 more than 9
E- 3x+10= 3 times x added to 10
Write a real world problem that can be presented by the equation y + 20 = 85
Find the length of the third side. If necessary, round to the nearest tenth.
9
13
Answer:
15.8
I think there is a part of the question missing (the triangle is a right triangle)
hope this helps
+let me know if you need an explanation
Tyger spends 25 minutes studying mathematics, 35 minutes studying science and 40 minutes studying history. What percentage of his time is spend studying science?
Answer:
35%
Step-by-step explanation:
First, we add :)
25 + 35 + 40 = 100
Now we divide :)
35/100 = 0.35 = 35%
Have an amazing day!!
Please rate and mark brainliest!!
Answer:
30%
Step-by-step explanation:
You Do it
PLS HELP
it is the last question ignore the lesson and pg number ;)
Answer:
the last answer is -1 :))))))
what is the Median of the numbers 45, 40, 47, 50, 45, 49, 40, 46?
Answer: 45
Step-by-step explanation:
The Median is the Middle # in the set.
I hope this helps!
Convert equation to standard form
18) y+1=4/5(x-5)
Answer:
4x - 5y = 25
Step-by-step explanation:
quick qustion the answer is at the tip of my tong but I cant seem to get it right what is 100 divided by 2
Answer:
50
Step-by-step explanation:
100/2=50
Answer:
100 divided by 2 is 50
Step-by-step explanation:
i just did it in my head
In a square, the diagonals...
a. bisect the angles
b. are perpendicular
c. are congruent
d. all of the above
Answer:
all the above.
your welcome
Solve the word problem below.
Jane took out $135 from her checking account. If Jane now has a balance of $650 in her
account, how much did Jane have in the account before she took out any money?
Step 1: If x represents the variable in the word problem above, explain what the variable should
represent.
Step 2: Write an equation to model the situation.
Step 3: Solve the equation and write your answer in sentence form. Show your work.
Answer:
x = the amount of money Jane had before she took out any
x - 135 = 650
x = 785
Step-by-step explanation:
Let x = the amount of money Jane had before she took out any
Set up the equation
x - 135 = 650
To solve the equation, we must add 135 on both sides to cancel the -135 on the left side of the equal sign.
x - 135 = 650
x = 785
I hope this helps and please mark me as brainliest!
10 + X/3 = 13 what does The X Equal to?
[tex] \Large{\boxed{\sf x = 9}} [/tex]
[tex] \\ [/tex]
Explanation:Given equation:
[tex] \sf 10 + \dfrac{x}{3} = 13 [/tex]
[tex] \\ [/tex]
Subtract 10 from both sides:
[tex] \sf 10 + \dfrac{x}{3} - 10 = 13 - 10 \\ \\ \sf \dfrac{x}{3} = 3 [/tex]
[tex] \\ [/tex]
Multiply both sides by 3:
[tex] \sf 3 \times \dfrac{x}{3} = 3 \times 3 \\ \\ \\ \boxed{\boxed{\sf x = 9}} [/tex]
[tex] \\ \\ [/tex]
▪️Learn more about equations here:
↣https://brainly.com/question/19225782
Answer:
X = 9Step-by-step explanation:
In this question we have provided an equation that is 10 + X/3 = 13 . And we're asked to find the value of X .
Solution : -
[tex] \longmapsto \qquad \: 10 + \dfrac{X}{3} = 13[/tex]
Step 1 : Multiplying with 3 on both sides :
[tex]\longmapsto \qquad \:(10 + \dfrac{X}{3} ) \times 3=13\times3[/tex]
Now by using distributive property multiplying 3 with 10 as well as X/3 :
[tex] \longmapsto \qquad \: (10 \times 3) + ( \dfrac{X}{ \cancel{3}} \times \cancel{3}) = 13 \times 3[/tex]
On calculating further , We get :
[tex] \longmapsto \qquad \: 30 + X = 39[/tex]
Step 2 : Subtracting with 30 on both sides :
[tex] \longmapsto \qquad \: \cancel{30} + X - \cancel{30} = 39 - 30[/tex]
On calculating further , We get :
[tex] \longmapsto \qquad \: \purple {\underline{{\boxed{\frak{X= 9}}}}}[/tex]
Henceforth, value of X is 9 .Verifying : -
Now we are checking whether our answer is correct or wrong by substituting values of x in given equation . So ,
10 + X/3 = 1310 + 9/3 = 1310 + 3 = 1313 = 13L.H.S = R.H.SHence , Verified .Therefore , our value for x is correct .
#Keep LearningThe lengths of the sides of triangle ABC are represented in terms of the variable m, where m > 6.
AB = m – 2
BC = m + 4
AC = m
List the angles from smallest to largest.
angle
, angle
, angle
✔ A
.
Answer:
m(C)<m(B)<m(A).
Step-by-step explanation:
1) according to the condition the shortest side is AB, the longest side is BC, the middle is AC. Then
2) the smallest angle is BCA (or C), the middle angle is ABC (or B), the largest angle is BAC (or A).
The list of the angles from smallest to largest are C, B and A.
Given that a triangle has side measurements represented in terms of the variable m, where m > 6.
AB = m - 2
BC = m + 4
AC = m
We need to list the angles from smallest to largest.
Since none of the sides are equal, therefore it is a scalene triangle.
Let us consider m = 6.
Then,
AB = m - 2
AB = 6 - 2
AB = 4
BC = m + 4
BC = 6+4
BC = 10
AC = m
AC = 6
It means that the longest side is BC, the medium side is AC and the shortest side is AB.
We know that the longest side of a triangle corresponds to the largest angle and vise versa.
Therefore,
The smallest angle is angle C.
The medium angle is angle B.
The largest angle is angle A
Learn more about Triangles click;
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Determine which postulate or theorem can be used to prove that ABC = DCB.
Answer:
I believe it is B
Step-by-step explanation:
it has somewhat some thing to do with the lines at BC it's had to put in words
The postulate or theorem can be used to prove that ΔABC ≅ ΔDCB is ASA.
The correct option is A.
What is Congruency?Congruency is a concept in geometry that refers to the equality of shape and size between two or more geometric figures. When two figures are congruent, it means that they have exactly the same shape and size, and their corresponding sides and angles are equal.
In ΔABC and ΔDCB
<BAC= <BDC (given)
<BCA= <DBC(given)
CB = CB (common)
So, by ASA criteria ΔABC ≅ ΔDCB.
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7 + -2.9 step by step explanation and a answer plsss help!
+ - makes a minus
+ + make a plus
-- makes a plus
7.0 - 2.9 = 4.1
Hope this helps!
Identify the graphed linear equation.
A: y=2x +2
B: y=2x +3
C: y=3x +2
D: y=3x +3
Answer:
B: y = 2x + 3
Step-by-step explanation:
The 2x is the slope, and the 3 is the y-intercept
The y-intercept is kinda like how far the slope is from zero, but it can only be applied to the y-axis.
The slope is... well... the slope-- like how steep it is. If a slope is 2/1, like in the graph, it will go higher 2 units every 1 unit across. Or, if the slope is 1/4: The slope will go 1 unit higher every 4 units
is (1,9) included in the graph p=3m+6
Find the area of the following triangle. Show each of the math steps that you use to find the area. Then explain how to go about finding the area of this particular triangle (explain each one of the steps that you showed with your math).
Right angled triangle
Base=B=2.4cmHeight=H=1.8cmArea:-
[tex]\\ \rm\rightarrowtail \dfrac{1}{2}BH[/tex]
[tex]\\ \rm\rightarrowtail \dfrac{1}{2}(2.4)(1.8)[/tex]
[tex]\\ \rm\rightarrowtail 1.2(1.8)[/tex]
[tex]\\ \rm\rightarrowtail 2.16cm^2[/tex]
can anyone help me solve this problem? (b^2 j^2) ^3 (b^5 j^5 ) ^4
Cara computes the mean and variance for the set 87, 46, 90, 78, and 89. She finds the mean to be 78. Her steps for finding the variance are shown below. Variance squared = StartFraction (87 minus 78) squared + (46 minus 78) squared + (90 minus 78) squared + (78 minus 78) squared + (89 minus 78) squared Over 5 EndFraction Variance squared = StartFraction (9) squared minus (32) squared +
BACK
Answer:
The answer is 274
Step-by-step explanation:
Given;Cara computes the mean and variance for the set 87, 46, 90, 78, and 89. She finds the mean to be 78.To Find;Variance:-Now,
Definition of Variance:
Variance is the value of the squared variation of the random variable from its mean value, in probability and statistics.So,
[tex] \frac{ {(87 - 78)}^{2} + ( {46 - 78)}^{2} + (90 - 78) {}^{2} + ({78 - 78)}^{2} + ( {89 - 78)}^{2} } {5} [/tex]
[tex]Var(X) \: = \frac{1370}{5} = 274 \\ [/tex]
Thus, The variance of the sequence is 274.