At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis and the radius of a chamber r= 0.387 m
Given
Mass of the person m = 70.2 kg
speed v = 3.09 m/s
Force F = 560N
-------------------------------------------
We have the formula for the force is given by
F = ( mv2) /r
The radius of the chamber is given b y
r = ( mv2) /F
= ( ( 70.2 kg)(3.09 m/)2) /(560N)
r=0.387 m
A circle's or a sphere's radius is the distance along a line connecting its centre and perimeter. From any point on the circle's or sphere's circumference to the centre, the radius' length is constant. Its length is halved by its diameter. The radius is a line segment connecting the centre of a circle or sphere to its perimeter or boundary in geometry.You'll require more effort as you reduce the radius because you're dividing by a lower force.
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an 81-kg baseball player slides into second base. the coefficient of kinetic friction between the player and the ground is 0.49. (a) what is the magnitude of the frictional force? (b) if the player comes to rest after 1.6 s, what was his initial velocity?
a) The magnitude of the frictional force= -µ mg = 0.49*81*9.8 = 389 N
b)The player comes to rest after 1.6 s, his initial velocity Vi = 7.68 m/s
Acceleration due to friction = - µ g = - 4.80 m/s^2.
V = V0 + at
V = 0
a = - 4.802 m/s^2
t = 1.6 s
V0 = V - at = 0 + 4.8*1.6 = 7.68 m/s
the acceleration of the player due to frictional force is given as
a = f/m = 388.96 /81 = 4.8 m/s2
final velocity = Vf = 0
time = t = 1.6 sec
using the formula
Vf = Vi + at (Vi = initial velocity)
Vi = Vf - at
Vi = 0 - (-4.8) (1.6) (a = -4.8 since player is slowing down)
Vi = 7.68 m/s
A force known as friction exists between two surfaces that are sliding or attempting to glide over one another. Friction, for instance, makes it challenging to push a book across the floor. The direction in which an object moves or attempts to move is always the direction in which friction operates. When anything moves faster or slower in a straight line, it is said to have been acceleration. Because the direction is constantly changing, even motion on a circle accelerates at a constant pace.
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a pellet gun fires ten 3.0 g pellets per second with a speed of 400 m/s. the pellets are stopped by a rigid wall. what is the magnitude of the average force on the wall from the stream of pellets?
In the diagram below, two of the three rays used to find the image position are shown. Which of the following best describes the third (missing) ray?A.A ray incident parallel to the axis refracts outward, as if it came from the focus on the left hand side.B.A ray incident through the vertex continues through the lens without refracting.C.A ray incident parallel to the axis refracts so that it passes through the focus on the right hand side.D.A ray incident on a path that would take it through the right focus refracts parallel to the axis.
Answer:
C. A ray incident parallel to the axis refracts so that it passes through the focus on the right hand side
Explanation:
The third ray is the blue ray in the following figure
Therefore, the third ray is a ray parallel to the axis that refracts and passes through the focus of the right side.
So, the answer is:
C. A ray incident parallel to the axis refracts so that it passes through the focus on the right hand side
A particle’s position along the x-axis is described by the functionx(t) = A t + B t2,where t is in seconds, x is in meters, and the constants A and B are given below.Randomized VariablesA = -4.9 m/sB = 6.9 m/s2q. Enter expression interms of A,B, t for the velocity of the particle as a function of time? What time will the velocity be zero?
Given,
The position function is, x(t)=At+bt²
A=-4.9 m/s
B=6.9 m/s²
The velocity is described as the rate of change if the displacement with time.
That is, the velocity is the time derivative of the displacement.
Therefore on differentiating the given function with respect to the time, we get the expression for the velocity.
i.e.,
[tex]\begin{gathered} v(t)=\frac{d(At+Bt^2)}{dt} \\ =A+2Bt \end{gathered}[/tex]Therefore the expression for the velocity is A+2Bt
To know at what time the velocity will be zero,
[tex]A+Bt=0[/tex]On simplifying the above equation,
[tex]t=\frac{-A}{B}[/tex]On substituting the known values in the above equation,
[tex]t=\frac{-(-4.9\text{ )}}{6.9}=0.71\text{ s}[/tex]Therefore the velocity will be zero at 0.71 s
9. a supply plane needs to drop a package of food to scientists working on a glacier inalaska. the plane flies 100 m above the glacier at a speed of 150 m/s. how far short of the target should it drop the package?
[tex]X=150m/s * 4.518s =677.63m[/tex] far short of the target it will drop the package.
How far short of the target should it drop the package?First we can find the total time in order to reach the ground using the following kinematic formula:
[tex]y_{f} =y_{i}+v_{iy}+ \frac{1}{2} gt^{2}[/tex]
And replacing we have:
[tex]-100 =0+0- \frac{1}{2} (9.8)t^{2}[/tex]
And solving for t we got:
[tex]t=\sqrt{ \frac{2* (-100)}{-9.8} }=4.518 s[/tex]
And now we can find the final distance on the x axis using the formula:
[tex]D = Vxt[/tex]
The velocity on x not changes and is the same plane speed [tex]Vx=150m/s[/tex] , if we replace we got:
[tex]X=150m/s * 4.518s =677.63m[/tex]
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name two powers of the president
Answer:
The President can issue executive orders, which direct executive officers or clarify and further existing laws.
The President also has the power to extend pardons and clemencies for federal crimes.
Explanation:
if the speed of a car is increased by 65%, by what factor will its minimum braking distance be increased, assuming all else is the same? ignore the driver's reaction time.
If the speed of the car is increased by 65%, the stopping distance of the car will be increased by 272.25%.
Let us say, the car is moving with velocity U, the stopping time of the car is T and the stopping distance of the block is d,
Now, we should use the equation of motion,
U²-V² =2aD
Where,
U is initial velocity,
V is final velocity,
D is the stopping distance,
a is the acceleration.
We know, at the final velocity will be zero,
So,
U² = 2aD
U =√(2aD)
Now, if the speed is increased by 65%, let us say the stopping distance becomes D'.
So,
U+65%U = √(2aD')
165U/100 = √(2aD')
Now, putting U = √(2aD),
165√(2aD)/100 = √(2aD')
(1.65)²D = D'
D' = 2.7225D
Now,
∆D = D' - D/D × 100
∆D = 2.7225 × 100
∆D = 272.25%
So, the stopping distance increased by 272.25%.
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Instructions:Draw a speed graph in the box that matches thefollowing scenario:A runner jogged 40m at a slow pace for 40seconds. She then stopped for 40 seconds to gea drink of water. After that, she sped up and ran60m more in 20 seconds.Tip:y axis - total of 100 mx axis - total of 100 s
Given data:
1) Runner jogged 40 m at a slow pace for 40 sec.
2) Stopped for 40 sec.
3) Again funs for 60 m in 20 sec.
5. An object travels with constant speed through 1km for one minutes and 20 seconds and accelerates with 0.125m/s² for 20 seconds, what is the total displacement? A) 1250 m B) 275 m C) 1275 m D) 1225m
Answer:
C) Total displacement = 1275 m or 1.275 km
Explanation:
We'll break this into two parts:
1) Displacement during constant speed, and
2) Displacement during the acceleration phase.
Constant Speed
The displacement for this segment is already stated: 1 km. But the information includes the time, which will allow us to calculate the speed of travel. We'll need this for the next phase of acceleration.
Distance = Speed x Time
Speed = Distance/Time
Time = 1 minute + 20 sec, or 80 sec.
Speed = 1 km/80 sec
Speed = 0.0125 km/sec
Since we'll be using meters (not km) in the next step, convert 0.0125 km/sec to m/sec with a conversion factor:
(0.0125 km/sec)*(1000m/1 km) = 12.5 m/sec
Acceleration Phase
The obect is moving at a speed of 12.5 m/sec (from above) and then accelerates at a rate of 0.125 m/sec^2 for 20 seconds.
The distance (s) an object travels during this acceleration (a) is gven by:
s = vi*t + (1/2)a*t^2,
where vi is the initial velocity (12.5 m/sec in this case), a is the acceleration (0.125 m/sec^2), and t is the time (20 seconds).
s = (12.5 m/sec)(20 sec) + (1/2)(0.125 m/sec^2)*(20 sec)^2
s = 275 meters
Now add the two distances:
1) Constant Speed Phase = 1000 m
2) Acceleration Phase = 275 m
Total displacement = 1275 m or 1.275 km
complete the table=x =0 2 3 4 6 8 y=30 27 24
Answer: (x=1 y=30) (x=2 y=27) (x=3 y=24) (x=4 y=21) (x=5 y=18) (x=6 y=15) (x=7 y=12) (x=8 y=9) (x=9 y=6) (x=10 y=3) etc its going down by 3 so 30-3=27 27-3=24 24-3=21 etc
hope i helped
Explanation:
A man is pulling on a rope with a force of 44 N
directed at an angle of 63◦
to the horizontal.
What is the x-component of this force?
Answer in units of N.
Answer:
20 N
Explanation:
Vertical component will be 44 sin 63
HORIZONTAL component is 44 cos 63 N = 19.97 =~ 20 N
Whoever answers asap gets marked Brainliest! A hockey puck with a mass of 0.12 kg is traveling across the ice at a velocity of 150 m/s downfield. What is the momentum of the hockey puck?
P = 18 N
P = 18 kg * m/s
P = 8 * 10 - 4 kg * m/s
M = 18 kg * m/s
Answer:
Explanation:
Momentum = m * v = .12 * 150 = 18 kg m/s
How far could you speed walk in 90 seconds based on your speed for the 10 meter trail
Answer:
Explanation:
Given,
Time ( t ) = 90 seconds
Distance ( d ) = 10 meter
To find : Speed ( v ) = ?
Formula : -
v = d/t
v = 10/90
v = 1/9 m/s ( meters per second )
Hence,
1/9 m/s is the speed walk in 90 seconds for the 10 meter trail.
a 2.6 m diameter penstock carries water at a velocity of 7m/s to an 80% efficient hydroelectricity generation facility in west virginia that produces 12 mw. another 2.275 m diameter penstock carries water at a velocity of 3 m/s to a 74% efficient hydroelectric generation facility in arkansas that produces 9 mw. what is the ratio of the heads of arkansas' reservoir to west virginia's reservoir?
The ratio of the heads of arkansas' reservoir to west virginia's reservoir is 1813 : 1120
Consider the West virginia reservoir,
To calculate the head of the virginia reservoir, we will use
φ = P / nρgh ...(1)
where φ is the flow rate, P is the power generated, n is efficiency, ρ is the density of water, g is the acceleration due to gravity and h is the head.
Given that flow rate is 7 m/s, power generated is 12 mw, 80% is the efficiency.
We know that density of water is 1000 [tex]kg/m^{3}[/tex] and acceleration due to gravity is 9.8 [tex]m/s^{2}[/tex]
By using equation (1)
h = P / φnρg
h = [tex]\frac{12}{7 * \frac{80}{100} * 1000*9.8 }[/tex]
h = 13440
Similarly, the head of the arkansas reservoir will be
Given that flow rate is 3 m/s, power generated is 9 mw, 74% is the efficiency.
h = P / φnρg
h = [tex]\frac{9}{3 * \frac{74}{100} * 1000*9.8 }[/tex]
h = 21756
Now, the ratio of the heads of arkansas' reservoir to west virginia's reservoir is
= (heads of arkansas) / (head of the virginia)
= 21756 / 13440
= 1813 : 1120
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On his trip from home to school, Noah Omwerk drives along three streets after exiting the driveway. He drives 1.85 miles south, 2.43 miles east, and 0.35 miles north. Determine the magnitude of Noah's resultant displacement. And the angle from East to South.
The resultant displacement of Noah from the question is 2.9 miles.
What is the resultant displacement?The displacement is a vector quantity. Recall that a vector quantity is going to posses both a magnitude and a direction as we can see. This implies that the result of the vector which is the single vector that has the combines effect in magnitude and direction as all the vectors put together would be obtained by a geometric rather than an algebraic method. We now have to apply the rules that are used to obtain the resultant vector in each of the cases that does apply here.
We are now told that he drives 1.85 miles south, 2.43 miles east, and 0.35 miles north. The resultant of the vector in the North - South direction is; 1.85 miles - 0.35 miles = 1.5 miles.
Then the general resultant vector is obtained from;
R = √(1.5)^2 + (2.43)^2
R = 2.9 miles
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A tennis ball moves 22 meters southward, then 12 meters northward, then 16 meters southward, and finally 34 meters northward
The resultant displacement of the tennis ball is 8 m northward.
What is displacement?
The displacement of an object is the change in the position of the object. The displacement of an object describes the shortest point between the final and initial position of an object.
The displacement of the tennis ball is calculated as follows;
d = (12 m north + 34 m north) - (22 m south + 16 m south)
d = (46 m north) - (38 m south)
d = 8 m northward
Thus, the resultant displacement of the tennis ball for the given motion is 8 m northward.
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The compete question is below:
A tennis ball moves 22 meters southward, then 12 meters northward, then 16 meters southward, and finally 34 meters northward. find the resultant displacement of the tennis ball.
After every movement in north and south direction multiple times, the displacement of the tennis ball is 8 meters in north direction.
What is displacement?The definition of displacement is the modification of an object's position. It has a direction and magnitude and is a vector quantity. It is shown as an arrow that travels from the initial location to the conclusion.
According to the question, the tennis ball moves 22 meters in south direction then it moves towards north and travels for 12 meters again it turns to south and covers 16 meters and at last it covers 34 meters in the north direction.
d = (12 m + 34 m ) north direction - (22 m + 16 m ) south direction
d = 8 meters in north direction.
Hence, the total displacement done by the tennis ball is 8 meters in the north direction.
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after driving a portion of the route, the taptap is fully loaded with a total of 27 people including the driver, with an average mass of 70 kgkg per person. in addition, there are three 15- kgkg goats, five 3- kgkg chickens, and a total of 25 kgkg of bananas on their way to the market. assume that the springs have somehow not yet compressed to their maximum amount. how much are the springs compressed? enter the compression numerically in meters using two significant figures. view available hint(s)
When something, like a spring, is stretched, the added length is referred to as its extension.According to Hooke's law, as long as the limit of proportionality is not crossed, a spring's extension is directly proportionate to the force exerted.
Solve the problem ?
The ends of an extension spring connect to two devices.The hooks and loops on the extension springs store and compress energy.An extension spring delivers return force to connected mechanisms via hooks or loops.The no-load position is where tightly wrapped extension springs normally rest. Total mass refers to the combined weight of the shell, its structural and support equipment, and the heaviest load that may be conveyed.The spring's compression at the specified weight is 0.80cm.
"Your inquiry is incomplete because it appears to be lacking the information below,"
The taptap's spring has a k value of 2.4 104 N/m.
the settings provided;
Each of the 27 people weighs 69 kg.
Each of the three goats weighs 15 kg.
Each of the five hens weighs 3 kg.
The weight of the bananas is 25 kg
The taptap's total mass, which includes every passenger, is computed as;
the people's combined mass is 27 x 70 or 1960 kg.
The goats' combined mass is 3 x 15 =45 kg.
The birds' combined mass is equal to 5 x 3 = 15 kg.
The bananas weigh a total of 25 kilograms
The extension of the spring
= 1960×9.8/2.4×104
= 19208/24000
= 0.80 cm
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two power lines, each 300 m in length, run parallel to each other with a separation of 23 cm . part a if the lines carry parallel currents of 130 a , what is the magnitude of the magnetic force each exerts on the other? express your answer using two significant figures.
The magnitude of the magnetic force each exerts on the other is 4.41 N.
The magnitude of the magnetic force depends on the current through the wire, the length of the wire, and the radius of separation. It can be written as
F = μ₀ . I1 . I2 . L / (2π . a)
where F is a magnetic force, μ₀ is vacuum permeability (4π x 10¯⁷ H/m), I1 and I2 is current through the wire, L is the length of the wire and a is the radius of the wire.
From the question above, the given parameters are
L = 300 m
a = 23 cm = 0.23 m
I1 = I2 = 130 A
By substituting the parameters, we can calculate the magnetic force
F = μ₀ . I1 . I2 . L / (2π . a)
F = 4π x 10¯⁷ . 130 . 130 . 300 / (2π . 0.23)
F = 4.41 N
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a thin, horizontal, 10-cm-diameter copper plate is charged to 3.5 nc. if the electrons are uniformly distributed on the surface, what are the strength and direction of the electric field
While negative point charges always move in the direction of the opposing electric field, positive point charges always move in the other direction. An electric field is a vector quantity. They cannot be added directly, but they can be vectorially inserted.
What are the electric field's strength and direction?A physical field called an electric field surrounds electrically charged particles and attracts or repels all other charged particles nearby. It can also refer to the physical field surrounding a system of charged particles.
While negative point charges always move in the direction of the opposing electric field, positive point charges always move in the other direction. An electric field is a vector quantity.
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A truck is traveling at a constant velocity of 30 m/s. How long will it take to travel 1000 meters?
A truck is traveling at a constant velocity of 30 m/s. It will take the time to travel 1000 meters is (t)=33.33 S.
What is velocity?The velocity means the ratio of distance and time. Mathematically it means the distance divided by time. It can be measured in m/s and cm/s.
How can we calculate the time?To calculate the time we are using thee formula here is,
S=vt
Or, t=S/v
Here we are given,
S = The covered distance of the car = 1000 m
v= The velocity of the car. = 30 m/s.
We have to calculate the time taken by truck = t
Now we put the values in the above equation, we get
t=S/v
Or, t=1000/30
Or, t=33.33 S
From the calculation we can say that, It will take the time to travel 1000 meters is (t)=33.33 S.
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now assume that a satellite of mass mmm is orbiting the earth at a distance rrr from the center of the earth with speed vevev e . a satellite of mass 2m2m2m is orbiting mars, also at a distance rrr from the center of mars, with a speed vmvmv m . what is the ratio tmte
The ratio between centripetal force of satellite b and satellite a is 2vm²/ ve².
We need to know about centripetal force to solve this problem. When an object moves in a circular motion, the object is experiencing centripetal force. The magnitude of centripetal force is
Fc = m . v²/R
where Fc is the centripetal force, m is mass, v is velocity and R is the radius.
From the question, we know that
ma = m
mb = 2m
va = ve
vb = vm
ra = rb = r
Find the centripetal force ratio
Fcb / Fca = (mb . vb²/Rb) / (ma . va²/Ra)
Fcb / Fca = (2m . vm²/r) / (m . ve²/r)
Fcb / Fca = 2 . vm²/ ve²
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A meteorite is found to contain two isotopes of element x, x-12, and x-14. Experimental analysis determined 95% of the element is isotope x-12, whereas 5% of the element is isotope x-14. What is the average atomic mass of element x?.
Considering the definition isotopes and atomic mass of an element, the average atomic mass of element x is 12.1
Definition of isotopeThe same chemical element can have the same atomic numbers, but the number of neutrons is different. These atoms are called isotopes of the element.
Definition of atomic massThe atomic masses of chemical elements are calculated as the weighted average of the masses of the different isotopes of each element, taking into account the relative abundance of each of them.
Atomic mass of the element in this caseIn this case, you know:
Isotope x-12 is 95% abundant (the atomic mass is 12).Isotope x-14 is 5% abundant (the atomic mass is 14).The average mass of the element x can be calculated as:
average mass of element x=12 amu×0.95 + 14 amu×0.05
average mass of element x= 12.1 amu
Finally, the atomic mass of the element x is 12.1.
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a lighthouse is located on a small island 5 km away from the nearest point p on a straight shoreline and its light makes seven revolutions per minute. how fast (in km/min) is the beam of light moving along the shoreline when it is 1 km from p? (round your answer to one decimal place.)
188.4 km/min is the beam of light moving along the shoreline.
The lighthouse is 5 km far away from the nearest Point P on a straight shoreline. This is often radius of the encirclement of the beam of light moving at 7 rpm.
At 7 rpm, One Circumference of the sunshine takes 70/7 = 10 seconds 2πr is= 2.π.5 km in 10 seconds or
In one second the beam covers 10π/10 = π km or 3.14 km/s.
Now, if the purpose P is 1 km away from the lighthouse, the Radius is reduced to 1 from 5 km,
Consequently The Angular displacement would remain the identical but the speed would be slower for one circumference i.e. 2πr in 10 seconds.
Or one second= (2π.1)/10
= .628π km
= π/10
= 3.14 km/s
By converting km/s into km/min
The answer will be = 188.4 km/min.
188.4 km/min fast (in km/min) is the beam of light moving along the shoreline when it is 1 km from point P.
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The potential energy of a roller coaster is 50 joules. The kinetic energy of the same coaster is 50 joules. What is the mechanical energy of the coaster?.
A roller coaster's mechanical energy is equal to 100 Joules if its P.E. and K.E. are each 50 Joules.
As a result, the roller coaster has a mechanical energy of 100 Joules.
explanation?
50 Joules is the potential energy of a roller coaster.
A roller coaster has kinetic energy of 50 Joules.
In order to determine the roller coaster's mechanical energy:
The entire amount of potential energy (P.E.) and kinetic energy (K.E.) that an object or body possesses is known as mechanical energy.
(ME)=50+50
Mathematically, the formula for mechanical energy states that it is equal to 100 joules when the given values are substituted.
As a result, the roller coaster has a mechanical energy of 100 Joules.
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Hey surveyor is drawing property lines . He draws one line that is 25.0 m long and is 20° south of west.  how long is the western component of the vector he has drawn?
Answer:
23.5 m
Explanation:
25 m * cos 20 =23.5 m
A 4 coulombs charged particle experiences an electric force of 200 N when placed at point P in an electric field. The magnitude of the electric field at point P is :
a) 5 N/C
b) 800 N/C
c) 0.02 N/C
d) 50 N/C
(d) 50N/C
The magnitude of the electric field at point 'P' is 50N/C.
It is derived from the basic concepts of Electrostatics. Coulomb's Law is the basis of relations in Electrostatics. It resembles Newton's Law of Gravitation.
Using the relation between Electric force, charge, and Electric field:
F = qE
F = 200N; q = 4C200 = (4)E
E = 50N/C
It is widely used in the calculation of Electric Force and Electric Field. The S.I. Unit of the Electric Force is Newton. The S.I. Unit of the Electric Field is N/C. The S.I. Unit of charge is Coulomb.
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Which answer best describes "displacement"?
A. Displacement is a vector quality showing total length of an area traveled by a particular object.
B. Displacement is a scalar quantity which accounts for how far away an object is after a period of time has elapsed from its initial starting point.
C. Displacement is a scalar quality showing total length of an area traveled by a particular object.
D. Displacement is neither a vector nor scalar quantity, which accounts for how far away an object is after a period of time has elapsed from its initial starting point.
Answer: The answer is the letter
A
Explanation:
Because displacement Its a vector and the letter A says than displacement is a vector quality showing total length of an area traveled by a particular object.
Answer:
(Question 1) Which answer best describes displacement?
(Answer) Displacement is a vector quality showing total length of an area traveled by a particular object.
(Question 2) Kelley is playing pool and hits the cue into the nine ball, which is directly in the center of the pool table. The nine ball travels a total of 7 meters before stopping, 1 meter to the left of the initial starting point of the nine ball. Which sentence reflects the correct statement regarding distance and displacement when considering the motion of the nine ball?
(Answer) The nine ball traveled a distance of 7 meters and was displaced by 1 meter.
(Question 3) What is velocity?
(Answer) Velocity is a vector quantity that tells the distance an object has traveled over a period of time.
(Question 4) Imagine a time-position graph where the velocity of an object is constant. What will be observed on the graph concerning the slope of the line segment as well as the velocity of the object?
(Answer) The slope of the line is equal to zero and the object will be stationary.
(Question 5) Select the option that best summarizes the reason for the use of position-time graphs when studying physical science.
(Answer) The position-time graphs show the relationship between the position of an object (shown on the y-axis) and the time (shown on the x-axis) to show velocity.
Explanation:
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one steel ball and one aluminum ball are the same size but the steel ball weighs twice as much as the other. the balls are dropped from the roof of a single-story building at the same instant of time. the time it takes the balls to reach the ground below will be:
It is same for both the balls. Due to the fact that balls fall freely regardless of their weight, both metallic balls take the same amount of time to reach the ground.
When two identically sized objects are dropped from a certain height, they will fall with gravitational acceleration (g). The weight of the objects will not affect how long it takes them to reach the ground. The density of the medium in which an object is dropped affects how long it takes for each object to travel there. Due to the influence of gravity and the same medium, we can therefore infer that both metal balls will take the same amount of time to reach the ground (air). Experiments have been conducted in vacuum rooms and show that when the balls are released from the top of the store, the acceleration of attraction to the floor is gravity and it has a value of 9.8 meters/square second regardless of its weight.
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How is the amplitude of a
longitudinal wave measured?
A. the distance between two rarefactions
B. the distance between two compressions
C. It is measured by how close together or spread
apart the compressions and rarefactions are.
a flat coil of wire consisting of 17 turns, each with an area of 50 cm2, is positioned perpendicularly to a uniform magnetic field that increases its magnitude at a constant rate from 3 t to 6 t in 2.0 s. what is the magnitude of the emf (in volts) induced in the coil? your answer should be a number with two decimal places, do not include the unit.
The magnitude of electromotive force is 0.13 volt.
We need to know about the electromotive force of induction to solve this problem. The emf induction appears when there is any change in magnetic flux. The magnitude of emf can be determined by
ε = N dΦ / dt
where N is coil turns, ε is electromotive force, dΦ is change in magnetic flux and dt is time interval.
From the question above, the parameters given are
B1 = 3T
B2 = 6T
dt = 2 s
N = 17
A = 50 cm² = 5 x 10¯³ m²
Find the change in magnetic flux
dΦ = (Φ2 - Φ1)
dΦ = (B2 . A - B1 . A)
dΦ = A (B2 - B1)
dΦ = 5 x 10¯³(6 - 3)
dΦ = 15 x 10¯³ Tm²
By substituting the given parameters, we can calculate electromotive force
ε = N . dΦ / dt
ε = 17 . 15 x 10¯³ / 2
ε = 0.13 volt
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