The concentration of C₂H₅OH in the resulting solution is 1.332 M.
given that :
mass of C₂H₅OH = 30.7 g
molar mass =46.07 g/mol
volume = 500 ml = 0.5 L
number of moles can be calculated by the following formula :
number of moles = mass / molar mass
no. of moles = 30.7 g / 46.07 g/mol
no. of moles = 0.666 mol
now, the concentration of C₂H₅OH :
Molarity = no. of mole / volumes in l
Molarity = 0.666 / 0.5
Molarity = 1.332 M
Thus, If 30.7 g of C₂H₅OH (MM = 46.07 g/mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, The concentration of C₂H₅OH in the resulting solution is 1.332 M.
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Howmany Mol MnO3areproducedwhen 4.30 kg of O2completelyreactsaccordingtothebalancedchemicalreaction:2Mn(s)+3O₂(g)→2MnO₃(s)Answer as equation
Answer:
89.58 moles of MnO3 are produced.
Explanation:
1st) From the balanced reaction we know that the relation between O2 and MnO3 is that 3 moles of O2 produces 2 moles of MnO3.
2nd) To build the equation, we must build a path from the given value of 4.30kg of O2 to moles of MnO3. So, it is important to figure out the relations that we need to build the equation.
The order to build the equation is:
• Start with, the given value of ,4.30kg of O2,.
,• We need to convert kg to grams, so we need the realtion between kg and g: ,1kg=1000g,.
,• To convert the grams of oxygen to moles, we need to use the molar mass of O2: ,32g/1mol,.
,• We need to use the relation between O2 and MnO3 from the balanced equation: ,3 moles of O2, produces, 2 moles of MnO3,.
[tex]4.30kg\text{ O}_2*\frac{1000g}{1kg}*\frac{1mol\text{ O}_2}{32g\text{ O}_2}*\frac{2moles\text{ MnO}_3}{3moles\text{ O}_2}=89.58moles\text{ MnO}_3[/tex]So, 89.58 moles of MnO3 are produced.
HELP ASAP PLEASE. A legend is a traditional story that explains something in real life. Sometimes they are accepted as true, but sometimes they are fantastical and just plain fun. There are many legends that surround the North Star explaining its creation as well as why it is stationary.
Take some time to research some of the legends of the North Star. After you have had a chance to read several of them, create your own fantastical story of the North Star. It can be how it came to be or explain why it is stationary.
A legend of the North star goes as follows:
Once upon a time, when God was creating the universe, the curious star Tam once he learned that God was humans on earth, he began visiting humans. He became fond of one human. But each time he had to return to the sky, the human could not see him again. Therefore, he decided to remain stationary so that the human can always locate him.What is the North Star?The North star is a star that sits directly above the North pole of the earth. It is also known as Polaris.
The North star is especially significant in that the North star is an ever-present star in the skies. It neither rises nor sets unlike other stars in the skies.
Because of this special feature of the North star, it serves as a guiding beacon in the skies for travelers. Also, several legends have been told about the North star.
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Terrance found a small hair on the victim’s shirt. What type of evidence does this BEST represent?
A.
trace evidence
B.
biological evidence
C.
ammunitions evidence
D.
impression evidence
Answer:
Biological evidence, since it was a hair, which forms part of the human
General nucleus and electron attraction explained
General nucleus and electron attraction explained
We can say this:
The net positive charge from the nucleus (remember that protons are in the nucleus) that an electron can feel attraction from, is the effective nuclear charge. The core electrons (electrons are on shells around the nucleus) are said to shield the valence electrons from the full attractive forces of the pro
What is the specific heat capacity of methanol (C) if it takes 7,490 joules of energy to heat 50.0 grams from 10.0 0C to 80.0 0C?
The formula for calculating the amount of heat energy absorbed is given as:
[tex]Q=mc\triangle t[/tex]Given the following
• mass m = 50.0g
,• Heat energy Q = 7490 Joules
,• change in temperature = 80 -10= 70 degrees celsius
Substitute
[tex]\begin{gathered} 7490=50\times c\times70 \\ c=\frac{7490}{3500} \\ c=2.14J\text{/}g^oC \end{gathered}[/tex]Hence the specific heat capacity of methanol is 2.14J/gC
a sample of argon has a volume of 4.95 L and the pressure is 0.92 atm if the final temperature is 30 C the final volume is 5.7 L and the final pressure is .092 atm what was the initial temperature of the argon
The initial temperature of the argon is 2678 K
Given that,
Initial volume (V1) = 4.95 L
Initial pressure (P1) = 0.92 atm
Final temperature (T2) = 30 C = 303.15 K
Final volume (V2) = 5.7 L
Final pressure (P2) = 0.092 atm
We need to find the Initial temperature of the argon represented as T1
We Know that, In ideal gas law: PV = nRT
It can be written as, P1V1 / T1 = P2V2 / T2
(0.92 * 4.95) / T1 = (0.092 * 5.7) / 303.15
4.554 / T1 = 0.5244 / 303.15
4.554 / T1 = 0.0017
T1 = 4.554 / 0.0017
T1 = 2678 K
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I keep getting 37.5 KPA but apparently that isn't the answer can anyone help?
ANSWER
The pressure of the gas is 281.25 mmHg
EXPLANATION
Given that;
The initial pressure of the gas is 75 mmHg
The intial temperature of the gas is 80K
The final temperature of the gas is 27 degrees Celcius
Follow the steps below to find the final pressure of the gas
Step 1; Convert the final temperature to degrees kelvin
[tex]\text{ T K = t}\degree C\text{ + 273.15}[/tex][tex]\begin{gathered} \text{ T K = 27 + 273.15} \\ \text{ T K = 300.15K} \end{gathered}[/tex]Step 2; Apply the Gay Lussac's law
[tex]\text{ }\frac{\text{ P1}}{\text{ T1}}\text{ = }\frac{\text{ P2}}{\text{ T2}}[/tex][tex]\begin{gathered} \text{ }\frac{\text{ 75}}{\text{ 80}}\text{ = }\frac{\text{ P2}}{\text{ 300.15}} \\ \text{ cross multiply} \\ \text{ 75 }\times\text{ 300.15 = P2 }\times\text{ 80} \\ 22511.25\text{ = 80 P2} \\ \text{ Divide both sides by 80} \\ \text{ P2 = }\frac{\text{ 22511.25}}{\text{ 80}} \\ \text{ P2 = 281.25mmHg} \end{gathered}[/tex]Write the two half-reactions that occur in this electroplating process. Be sure to include the states of the elements or ions.
Answer:
Explanation:
As the cell has a copper strip like the anode and a coin or nail (we can consider this like it is nickel) like the cathode, we can write both half-reactions:
• Copper half-reaction,:
[tex]Cu_{(s)}\leftrightarrows Cu_{(aq)}^{2+}+2e^-[/tex]In the copper anode, the oxidation reaction takes place. This is the positive terminal.
• Nickel half-reaction,:
[tex]Ni_{(aq)}^{2+}+2e^-\leftrightarrows Ni_{(s)}[/tex]In the nickel cathode, the reduction reaction takes place. This is the negative terminal.
The direction of the electron flow always go from the anode to the cathode.
What volume of Cl2 gas, measured at 688 torr and 36 °C, is required to form 22 g of NaCl?Express your answer using two significant figures.
ANSWER
Volume of the gas 5.3L
EXPLANATION;
Given that
The pressure of the chlorine gas is 688 torr
The temperature of the chlorine gas is 36 degrees Celcius
The mass of NaCl is 22 grams
Follow the steps below to find the volume of chlorine gas
Step 1; Write a balanced equation for the reaction
[tex]\text{ 2Na + Cl}_2\text{ }\rightarrow\text{ 2NaCl}[/tex]In the above reaction, 2 moles of Na react with 1 mole of chlorine to form 2 moles of NaCl
Step 2; Find the number of moles of NaCl using the below formula
[tex]\text{ mole = }\frac{\text{ mass}}{\text{ molar mass}}[/tex]Recall, that the molar mass of NaCl is 58.44 g/mol
[tex]\begin{gathered} \text{ mole = }\frac{22}{\text{ 58.44}} \\ \text{ moles = 0.376 mole} \end{gathered}[/tex]Step 3; Find the number of moles of Cl2 using a stoichiometry ratio
Let x represents the number of moles of Cl2
[tex]\begin{gathered} 1\text{ mole Cl}_2\text{ }\rightarrow\text{ 2 moles NaCl} \\ \text{ x moles Cl}_2\rightarrow\text{ 0.376 moles NaCl} \\ \text{ cross multiply} \\ \text{ x moles Cl}_2\text{ }\times2\text{ moles NaCl }=\text{ 1 mole Cl}_2\text{ }\times\text{ 0.376 mole NaCl} \\ \text{ Isolate x} \\ \text{ x = }\frac{\text{ 1 mole Cl}_2\times0.376moles\cancel{NaCl}}{2moles\cancel{NaCl}} \\ \\ \text{ x = }\frac{1\text{ }\times\text{ 0.376}}{2} \\ x\text{ = }\frac{0.376}{2} \\ \text{ x = 0.188 mol} \end{gathered}[/tex]The number of moles of Cl2 is 0.188 mol
Step 4; Find the volume of the gas using the ideal gas equation
[tex]\text{ PV = nRT}[/tex]Convert the temperature to degree kelvin
[tex]\begin{gathered} \text{ t = 36}\degree C \\ \text{ T = 36 + 273.15} \\ \text{ T = 309.15 K} \end{gathered}[/tex]Step 5; Find the volume of the gas
[tex]\begin{gathered} \text{ PV = nRT} \\ \text{ Recall, that R = 62.363 L. torr mol}^{-1}K^{-1} \\ \text{ 688}\times\text{ V =}^{\text{ }}0.188\text{ x 62.636 }\times\text{ 309.15} \\ \text{ 688 V = 3624. 500} \\ V\text{ = }\frac{\text{ 3645, 500}}{688} \\ \text{ v = 5.3 L} \end{gathered}[/tex]Therefore, volume of the gas 5.3L
What is a molecular equation and what is this question asking please help?
In this question, we have a reaction between silver nitrate and potassium chloride, which will have the following chemical formula and also the following product:
AgNO3 (aq) + KCl (aq) --> AgCl (s) + KNO3 (aq)
Now we need to identify the ions that are components of the precipitate that was formed in this reaction
A precipitate is a product of a reaction that is not soluble in water in the conditions given in the reaction, therefore the precipitate will be a solid product of the reaction. The solid of the reaction is AgCl, therefore this is the precipitate
Now the ions that compose AgCl are Ag+ and Cl-, the answer will be the 3rd option
Select the structure that correspondsto the molecule name:ethylmethylamineA.NHB. CH3CH₂NHCH3C. both
Ethylmethylamine is a secondary amine, that has one ethyl group attached to the amine group and one methyl group, which is a also attached to the amine group.
It is represented by:
Nevertheless it can be represented by CH3CH2NHCH3.
It means that the correct answer is c. Both.
If the volume is 15 and the mass of water is 14.9 what is the density
Answer:
0.9933
(Text Text Text)
Perform the followingmathematical operation, andreport the answer to thecorrect number of significantfigures.
To find out how many significant numbers there are in a number we can rely on a few rules:
1. Non-zero digits are always significant
2. Any zeros between non-zero digits are significant
3. Final zeros or trailing zeros are significant if they come after the non-zero numbers in a decimal number situation
Example: .500 and .632000
In this question, we have:
0.0016/0.849 = 0.0019, this is the correct value with the correct number of significant figures
Calculate the volume of 0.875 mol/dm3 NaOH solution needed to make up a 100.0 ml of a diluted solution with a concentration of 0.235 mol/dm3 NaOH.
The volume of 0.875 mol/dm³ NaOH solution needed to make up a 100.0 ml of a diluted solution with a concentration of 0.235 mol/dm³ NaOH is 73.15 mL.
Given that :
molarity M1 = 0.875 mol/ dm³
M2 = 0.235 mol/ dm³
volume V2 = 100mL
using the formula , we get
M1 V1 = M2 V2
substituting the values in the formula we get :
0.875 × V1 = 0.235 × 100 mL
V1 = 26.857 mL
the volume added = V2 - V1 = 100 mL - 26.85 = 73.15
Thus, The volume of 0.875 mol/dm³ NaOH solution needed to make up a 100.0 ml of a diluted solution with a concentration of 0.235 mol/dm³ NaOH is 73.15 mL.
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What is the enthalpy change for the following reaction: C3H8(g) + 5O2 (g) --> 3CO2 (g) + 4H2O (l)ΔHof C3H8 (g) = -103.8 kJΔHof CO2 (g) = -393.5 kJΔHof H20 (l) = -285.8 kJ
The answer is -2219.9 kJ/mol
9 mol of A how many moles of C are formed upon complete reaction of
Answer:
C = 9 mol
Explanation:
Reaction: A + 2B ---> C
We want to find the moles of C.
Given: moles of A = 9 mol.
To solve this problem we will need to use stoichiometry.
A is the limiting reagent because it has a coefficient of 1 and B has a coefficient of 2.
The molar ratio between A and C is 1:1 therefore for every 9 moles of A that react, 9 moles of C will be produced.
If 42.6 grams of Al reacts completely with O2 and 57.8 grams of Al2O3 produced, what is the % yield of Al2O3for the reaction? 4Al + 3O2 --------> 2Al2O3Group of answer choices22.3%65.9%55.7%75.2%71.8%
Step 1
Data provided:
The reaction: 4Al + 3O2 => 2Al2O3 (balanced)
The limiting reactant Al (it is said that Al reacts completely)
Mass of Al = 42.6 g
The actual yield = 57.8 g Al2O3
-----------------------
Step 2
Data needed: the molar mass of Al (26.9 g/mol) and Al2O3 (101.9 g/mol)
The theoretical yield:
4 x 26.9 g Al ------- 2 x 101.9 g Al2O3
42.6 g Al ------- X = 80.7 g Al2O3 = theoretical yield
---------------------
Step 3
% yield = (actual yield/theoretical yield) x 100 = (57.8 g/80.7 g) x 100 = 71.6 %
(this is the closest value for one of the options, 71.8 %)
Answer: 71.8 %
Match each colored row or group on the table to the family of elements it represents.Green (2nd column)Red (1st column)Purple (two rows below the rest of table)Blue (3rd to 12th columns)?Alkali metals?Alkaline earth metals?Transition metals?Lanthanides and actinides
Green column - Alkaline earth metals
Red column - Alkali metals
Purple column - Lanthanides and actinides
Blue column - Transition metals
Explanations:
The red block are made up of group 1 elements and these elements are known as Alkali metals.
The green column are the group 2 elements in the periodic table and are known as the Alkali earth metals.
For the blue columns, they are element from group 3 to 10 and they are known as the transition metals.
For the purple column, they are Lanthanides and actinides
8) Identify which is the proton acceptor (base) in this following reaction:
HCI + H20 -> CH + H30+
O HCI
O H20
O H30+
O cl
The proton acceptor (base) in this following reaction is H₃0⁺
Here given reaction is
HCI + H₂O → CH + H₃O⁺
A proton is a subatomic particle found in the nucleus of every atom so in that reaction H₃0⁺ is the proton acceptor because protonic acid is the proton donor H⁺ so H₃0⁺ must be bronsted acid and OH⁻ because it accept the proton is a therefore a bronsted base and a lewis acid is by definition an electron pair acceptor and a lewis base is an electron pair donor
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I dont understand how to find the one with smallest atomic radiusa. Calciumb. Cobaltc. potassiumd NickelI think its last one but why
Answer:
d. Nickel
Explanation:
The atomic radius is a periodic property, that is, we can see how it varies in the Periodic Table of Elements.
Atomic radius increases by a column (group) from top to bottom, and increases by a row (period) from right to left.
We can see the variation of atomic radius and the location of the given atoms in the following drawing:
Since K (potassium), Ca (calcium), Co (cobalt) and Ni (nickel) are located in the same row (period), to identify which one has the smallest atomic radius, we have to analyze the increase in horizontal atomic radius.
So, the Ni atom has the smallest atomic radius (because it is located more to the right compared to the other atoms in the same row) and K atom has the largest atomic radius.
Andrew wants to become a certified forensic pathologist. What is MOST likely to be true about his path to achieve this goal?
A.
It is fairly easy and doesn’t take a long time.
B.
There is no required residency or clinical fellowship.
C.
It requires a medical degree like a regular doctor.
D.
There are no schools that are currently offering this training.
Answer:
A
Explanation:
it is easy and doesn't take a long time
Humans have been smelting ore for thousands of years. Ancient humans smelted ore to make all but which of the following
Answer
wiring
Explanation
Ancient humans did make jewelry, weapons and tools by smoltering ore, however, they did not make wires, hence there was no electricity in many mnay years ago.
What is the concentration of A pill weighing 325mg containing 22mg Mg
Step 1 - Understanding percentual concentration
To express the concentration of a substance as a percentual concentration, we just need to divide its mass by the total mass:
[tex]concentration\text{ in \% = }\frac{m_{substance}}{m_{total}}\times100[/tex]Step 2 - Calculating the concentration in the pill
We want to calculate the concentration of Mg in the pill. Therefore, we'll divide its mass by the total mass of the pill:
[tex]concentration\text{ of Mg =}\frac{22mg}{325mg}\times100=6.8\text{ \%}[/tex]Answer: the concentration of Mg in the pill is 6.8%
11.A substance that is corrosive and that conducts electricity in water can be classified as which of the following?Select one:a. An acid only.b. A base only.c. Either an acid or a base.d. Neither an acid or a base.
Answer
acids and bases are both corrosive furthermore both will conduct electricity depending on the strength of the acid or base
C is the correct option
Read each question carefully and choose the letter of the best answer.
This element is nonmetal and appears in the periodic table.
The number that represents the position of the elements is called, the atomic number, it also represents the number of protons = numbers of electrons an atom has.
Answer: D. the atomic number
You randomly fina a brick labeled platinum! You get really excited because you look it up and find that platinum is worth $31.86 per gram.then density of platinum is 21.45 g/mL. You measure the volume and it’s 150 cm3 or 150.0mL. How much should the brick weigh if it’s is really platinum? And how much money would the brick be work
Step 1
Density is defined as:
D = mass of the platinum brick/volume of the platinum brick
D = m/V
------------------
Step 2
Information provided:
D = 21.45 g/mL
V = 150.0 mL
m = unknown
Price per grams of Pt = 31.86 $/g of Pt
Symbol for platinum = Pt (please, look at the periodic table)
-----------------
Step 3
How much should the brick weigh if it’s is really platinum?
From D = m/V
=> D x V = m
=> 21.45 g/mL x 150.0 mL = 3218 g approx.
------
And how much money?
3218 g of Pt x 31.86 $/g of Pt = $99,660 approx.
Answer:
3218 g
$99,660
Calculate the enthalpy of combustion (kJ/mol) of methyl linoleate (C₁₉H₃₄O₂), an important component of many biodiesel fuels made from corn oil and methanol, given the following standard enthalpies of formation: CO₂(g) = -393.5 kJ/mol H₂O(l) = -285.8 kJ/mol C₁₉H₃₄O₂(l) = -645.7 kJ/mol
Answer:
Explanation: 2 C19H34O2(l) + 53 O2(g) ==> 38 CO2(g) + 34 H2O(l) ... balanced equation
∆Hcombustion
∆H = ∑∆Hf products - ∑∆Hf reactants
∆H = [(38 x -393.5) + (34 x -285.8)] - (2 x -645.7) = (-14,953 + -9717) - (-1291)
∆H = -24,670 + 1291
∆H = 25,961 kJ
(be sure to check the math)
A student finds two green powders that look the same. He wants to figure out if the two powders are the same or different substances. Which of the following is
the best method to use?
I temperature of each powder
Mix the two green powders together and then test the properties.
A student finds two green powders that look the same he wants to figure out if the two powders are the same or different substances then mix the two green powders together and then test the properties
A powder is a dry bulk solid composed of many very fine particles that may flow freely when shaken or tilted and to figure out unknown two mixture powder are same or different then student want to mix the two green powders together and then test the properties because of properties student the two unknown powder are to be determined
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determine the mass (in grams) of c4h10 that is required to produce 14.7 g co2
According to the stoichiometry, 4.85 g of propane is required to produce 14.7 g carbon dioxide.
What is stoichiometry?
It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.
Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.
In the given problem as per balanced equation of combustion of propane 2 molecules of propane produce 8 molecules of carbon dioxide.That is, 116.24 g of propane produces 352.08 g of carbon dioxide.
∴14.7 g of carbon dioxide is produced by, 14.7×116.24/352.08=4.85 g of propane.
Thus, 4.85 g of propane is required to produce 14.7 g of carbon dioxide.
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Propane (C3H8) is a component of natural gas and is used in domestic cooking and heating. It burns according to the following reaction:
C3H8 + O2 → CO2 + H2O
a. Balance the equation representing the combustion of propane in air.
b. How many grams of carbon dioxide can be produced by burning 20.0 pounds of propane, the typical size of a BBG grill propane tank?
Assume that oxygen is the excess reagent in this reaction.
A. The balanced equation for the reaction is given as
C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O
B. The mass (in grams) of carbon dioxide that can be produced by burning 20.0 pounds of propane is 27216.49 g
A. Balance equation
The balanced equation for the combustion of propane is:
C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O
B. How to determin the mass (in grams) of CO₂ produced
The mass (in grams) of CO₂ produced from the reaction can be obtained as follow:
Molar mass of C₃H₈ = (12 × 3) +(8 × 1) = 44 g/molMass of C₃H₈ from the balanced equation = 44 × 1 = 44 g = 44 / 453.592 = 0.097 poundMolar mass of CO₂ = 12 + (16 × 2) = 44 g/molMass of CO₂ from the balanced equation = 3 × 44 = 132 gFrom the balanced equation above,
0.097 pound of C₃H₈ reacted to produce 132 g of CO₂
Therefore,
20 pound of C₃H₈ will react to produce = (20 × 132) / 0.097 = 27216.49 g of CO₂
Thus, the mass of CO₂ produced is 27216.49 g
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