A 10 kg box is pulled across a level floor, where the coefficient of kinetic friction is 0. 35. What horizontal force is required for an acceleration of 2. 0 m/s2?

The ratio u/u0 : 1/2

As the distance is doubled and the battery is connected, we know that Capacitance is given by:   [tex]C= \frac{\epsilon_0 A}{d}[/tex]

As the distance between the plate is doubled, C will become: [tex]C= \frac{\epsilon_0 A}{2d} = \frac{C}{2}[/tex]

Now, as the battery is connected, Voltage will remain constant, therefore Charge Q will become:   [tex]Q=\frac{CV}{2}[/tex]

The energy before doubling the distance between the plates was, U0 :

[tex]U_0 = \frac{1}{2}QV = \frac{1}{2}CV^2[/tex]

After doubling the distance, the Energy will become U:

[tex]U = \frac{1}{2}QV = \frac{1}{4}CV^2[/tex]

Therefore, the ratio will be:

                           [tex]\frac{U}{U_0} = \frac{\frac{1}{2}CV^2}{\frac{1}{4}CV^2} = \frac{1}{2}[/tex]

A capacitor is a bipolar electrical device that can store energy in the form of an electrical charge. It consists of two electrical conductors  separated by a distance. The space between the conductors can be filled with a vacuum or  an insulating material known as a dielectric. The ability of a capacitor to store charges is called capacitance. Capacitors store energy by keeping opposite charges away from each other. The simplest model of a capacitor is a parallel plate, which consists of two metal plates with a gap between them. However, different types of capacitors are manufactured in different shapes, styles, lengths, circumferences and materials.

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As a result of the law of  conservation of momentum, the man will acquire a speed of 3 .  10⁻³ m/s

The law of conservation of momentum states thta:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Where:

u₁ , u₂ = initial velocity of object 1 and object 2

v₁ , v₂ = final velocity of object 1 and object 2

Since both the man and the shove are initially at rest, hence u₁ , u₂ = 0.

Therefore,

m₁v₁ + m₂v₂ = 0

Parameters given:

m₁ = 95 kg

m₂ = 74 gram =  74 . 10⁻³ kg

v₂ = 4 m/s

Plug these parameters into the equation:

95 . v₁ + 74 . 10⁻³ . 4 = 0

v₁ = 3 .  10⁻³ m/s

Hence, the man acquire a speed of 3 .  10⁻³ m/s, which is very small.

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Answer:

false

Explanation:

the time period is for a whole cycle of the wave, so peak-to-peak on an oscilloscope trace.

The velocity of the car is 46.48 m/s.

What is velocity?

velocity is directional speed of a object in motion as an induction of it's rate of change in position observed from a particular frame of reference and as measured by a particular standard of time.

Sol- The linear momentum of a body is defined as the product of its mass and its velocity, given by-

P = mv

According to the question the momentum of the truck is-

Pr=2250×25 kgm /s

Pr=56250 kgm/s

Now we can see the momentum of the car and the truck must be same that is Pc=Pr

1210×v =56250 kgm/s

v= 56250/1210

v= 46.48 m/s

Thus the velocity of the car is 46.48m/s .

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A car with a mass of 1,060.0 kg accelerates from 0 to 88.0 km/h in 10.0 sec .The net force (in n) on the car during its deceleration is F = 7812.5 N.

Given

m= 1000 kg

u= 0 m/s

V = 90 km/h = 25m/s

t = 10 sec

a)by equation of motion :

v = u+at

25 = 0+ ax10

a = 2.5 m/c2

( b )By newton's law;

F= m*a

F=100X 2.5

F =2500N

( C )

u= 25m/s

V = 0

S = 40m

by equation of motion ;

v² = u²+2as

0=25²+80a

a=-7.8125 m/s²

by newton's law

F= m*a

F= 1000X 7.8125

F = 7812. 5N

A higher level motion control operation than velocity control is the control of acceleration and deceleration. Given that torque is the result of inertia and rate of altered speed, the system's forces will be affected by the rate of acceleration or deceleration. Any force calculation of this kind must take into account the actuator's or motor's inertia because it can significantly affect the torque needed. Control performance will also be impacted by the acceleration or deceleration profiles used. A motor needs linear acceleration in order to transition smoothly from one velocity to the next until the desired speed is reached. The rates of change, on the other hand, depend on both position and velocity when acceleration follows a non-linear, curved profile.

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a) The amount of work done is equal to the amount of energy used.

b) Power is the rate of energy use/work done .

c) The greater the work done. The greater the power needed.

d)  The two factors that affect the amount of work done are force and displacement .

 Energy is the ability to perform work. Work and energy are related in that an increase in work results in an increase in energy, and vice versa. Power is defined as the rate at which work is completed or the amount of work completed per unit of time. Power is also defined as the rate at which  energy is supplied to the system.

Power depends mainly on the amount of work done as well as the time  taken by the body to perform the work.

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Answer:

Potential energy

Explanation: Potential energy is represented as a stored energy.

It is 24 pi fast area of oil sick increasing when the radius is 60m.

This question we are given the rate of change is the radius T. R. D. T. Is equal to two m per minute. And we know that the area since we're talking about the radius theory of the seco which is pi R squared. And our D A t. R. Would be the first derivative of A. That will be two pi R. And our D A D. T. Would be equal to T. A. T. R. Multiplied by the era T. T. And already we can plug in our numbers. Here we have two pi R. A. Multiplied by two and we get four pi hi and this season meters squared per minute.

Now we want to find the value of our rate of change of area with time At R. A. is equal to 56. And therefore our D. A. T. T. At our escort 56 is equal to four pi my play by 56. And here we get 224 pi square meters per minute. This is our answer to part A no for part B. We are giving that At time is equal to zero is equal to zero. And our rate of change of radius the time is still equal to two meters per minute and Therefore from 0 to 3 we have a tiara Is equal to two d. T. And we integrate Both sides from 0 to 3. So on the left hand side we have our era on the right hand side we have to t From 0 to 3 and here we get six So our radius is six m.

Therefore our D a t t will be a quarter full pie. Sarah it R is equal to six and Plugging. In our 6th year. We have four pay And our era is six. We get 24 pi in this season square meters per minute. That's it. We had them.

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Answer:

The speed and direction of motion can be changed by applying force on an object and thus a force can bring a change in the state of motion of an object.

The orbital speed of the second satellite with same centripetal force is 2.1 x 10⁴ m/s.

We need to know about centripetal force to solve this problem. The centripetal force is a force caused by moving objects in a circular motion. The magnitude of the centripetal force depends on tangential speed, mass and radius. It can be written as

Fc = m . v² / r

where Fc is the centripetal force, m is mass, v is tangential speed and r is the radius.

From the question above, we know that

Fc 1 = Fc 2 = Fc

m1 = m2 = m

v1 = 1.31 x 10⁴ m/s

r1 = 3.88 x 10⁶ m

r2 = 9.96 x 10⁶ m

Hence, the ratio of centripetal force is

Fc2 / Fc1 = (m2 . v2² / r2) / (m1 . v1² / r1)

v1² / r1 = v2² / r2

(1.31 x 10⁴)² / 3.88 x 10⁶ = v2² / 9.96 x 10⁶

v2² = 4.41 x 10⁸

v2 = 2.1 x 10⁴ m/s

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The final speed of the rocket, given it started with a speed of 120 m/s and slows down at a rate of 22 m/s² for 4 seconds is 208 m/s

From the question given above, the following parameters were obtained:

The final speed of the rocket can be obtained as follow:

v = u + at

v = 120 + (22 × 4)

Clear bracket

v = 120 + 88

v = 208 m/s

Thus, we can conclude from the calculation above that the final speed of the rocket is 208 m/s

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Answer: D. 24.5 N

Explanation:

Fgrav = mg

Fgrav = 2.5(9.8)

Fgrav = 24.5 N

Formulas for projectile motion:

Maximum height of projectile, h = [tex](u sin(\alpha )^{2}[/tex] / 2g

Horizontal range of projectile, R = [tex]u^{2}[/tex] sin(2α) / g

where u is the initial velocity, α is the angle of projection, and g is the acceleration due to gravity.

Given:

Angle of projection, α = 64°

Maximum height of projectile, h = 34 m.

To find: Initial velocity (u), and horizontal distance travelled (R).

Rearrange 'h' equation for 'u',

u sin(α) = [tex]\sqrt{2gh}[/tex]

⇒ u = [tex]\frac{\sqrt{2gh} }{sin(\alpha )}[/tex]

Substitute given values.

⇒ u = [tex]\sqrt{2*(9.8m/s^{2}*34m }[/tex] / sin(64°)

⇒ u = 25.81 / 0.899 m/s

∴ u = 28.71 m/s

This is the velocity with which the ball was thrown.

The distance travelled by the ball can be calculated by using the equation,

R = [tex]u^{2}[/tex] sin(2α) / g

Substitute the given values.

⇒ R = ([tex]28.71^{2}[/tex]× sin (2×64°)) / 9.8

⇒ R = 649.53 / 9.8

∴ R = 66.27 m.

This is the distance travelled by the ball.

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θ = 0.0090 degree is the angle does the water surface make with the horizontal

At a radius of 12.5 cm from the center, or r = 13.5 cm, a tiny container of water is positioned on a rotating carousel within a microwave oven.

Time for every rotation is 7.15 seconds.

Fc=mrω^2

Fc=mr(2 π/T^2)^2

Fc=m12.5x10^-2(2 π/7.45)^2.....(1)

Gravitational force is caused by:

Fg=mg

Fg=mx9.8........(2)

Letθ is the angle between the water's surface and the horizontal be. Equations (1) and (2) can be used to compute it as follows:

tanθ=Fc/Fg

tanθ=m12.5x10^-2(2 π/7.45)^2/mx9.8

tanθ=0.0090

θ=0.0090 degree

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Answer: The angle between the water's surface and the horizontal is = 0.0090 degrees.

Explanation: The angle between the water's surface and the horizontal is = 0.0090 degrees.

A little container of water is placed on a revolving carousel within a microwave oven at a radius of 12.5 cm from the center, or r = 13.5 cm.

7.15 seconds pass throughout each revolution.

Fc=mrω^2

Fc=mr(2 π/T^2)^2

Fc=m12.5x10^-2(2 π/7.45)^2....(1) (1)

There is a gravitational force because of:

Fg=mg

Fg=mx9.8........(2)

Take as an example the angle formed by the water's surface and the horizontal. It can be calculated using Equations (1) and (2) as follows:

tanθ=Fc/Fg

tan = (m12.5x10-2(2 /7.45)/mx9.8)

tanθ=0.0090

0.09 degrees.

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The equation for calculating the electrical force between two charges is: F = Kq₁q₂ / d²

Considering the options given in the question, we can obtain the equation for calculating electrical force as shown.

Coulomb's law states as follow:

F = Kq₁q₂ / d²

Where

With the above equation, we can easily determine the force between two charges.

For example find the force between two charges of charge 1 C and 2 C which are 1.5 m apart.

We can obtain the force as follow:

F = Kq₁q₂ / d²

F = (9×10⁹ × 1 × 2) / (1.5)²

F = 18×10⁹ / 2.25

F = 8×10⁹ N

Thus, we can see clearly that the equation F = Kq₁q₂ / d² can be use to calculate the force between t two charges.

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The magnitude of the resulting spring force when the material is stretched from its equilibrium position is -0.02522 N.

The spring force is a spring or a stretchy material is given by the formula,

F = -1/2Kx²

Where z

F is the spring force,

K is the spring constant,

x is the compression or extension in the material,

The negative sign represent that the force is restoring in nature.

We know, in our case,

The extension in the material is 2.71cm.

1 cm = 1/100m

So,

2.71 cm = 2.71/100m

The spring constant is 68.7N/m.

Now, putting all the values,

F = 1/2Kx²

F = -1/2(68.6)(2.71/100)²

F = -0.02522N.

So, the spring force is 0.02522N.

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Velocity is the rate at which an object changes position.

___________________________________________

Velocity is a vector quantity that refers to "the rate at which an object changes its position."

Hope this helps!

Want to learn more? Visit below for more information about velocity.

Look up "Speed versus Velocity" at The Physics Classroom.com

Answer:5110.2 joule

Explanation:Weight of the crate:- 8.35 x 102 N

Height to which the forklift lift the crate:- 6.0 M

Work done by the forklift=F.d

F=Gravitational Force =m.g

d=height=h

Work w=m.g.h

m.g=8.35 x 102 N

h=6.0 M

w=8.35x102N x 6.0M

w=5110.2NM

w=5110.2joule

In consideration of Henry's law the molar mass of organic compound is 0.24 grams.

What is molar mass?

The mass of a sample of a chemical compound divided by the quantity, or number of moles in the sample, measured in moles, is known as the molar mass of that compound. What is the mass of water in grammes and how much Equis paper with a 12.5% sodium chloride content weighs at 55 degrees Celsius, according to Sol-One of three? His issue informs us that pure water has a specific gravity of 118 torr at 55 degrees Celsius. Therefore, the first task at hand is to determine the mole fraction of, I suppose, the thermal fractions of both water and sodium chloride.

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They will go off in opposite directions with the same force.

What is Newton's third law?

Newton's third law states that if object A exerts a force on object B, then object B must apply a force to object A that is equal in magnitude and directed in the opposite direction. This law illustrates a symmetry in nature whereby forces always occur in pairs and whereby no body can exert a force without also being subjected to one.

Newton's Third Law states that for every action, there is an equal but opposite reaction. If two people are standing on a scooter and push off each other (following the Law), it should come to the conclusion that they could go off in opposite with the same force.

Person is exiting for (describe in Newton's third law) against the wall that then has an effect on the person pushing them bac

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If a person standing on a scooter board pushes off of a wall, what happens? Can this

situation be explained in terms of Newton's Third Law (action-reaction)?

The distance travelled by Arthur is 7 km and his displacement is 5 km.

The distance travelled by Arthur during the entire motion is determined by summing the entire path covered during the motion.

Distance = 3 km + 4 km

Distance = 7 km

The displacement of Arthur during the entire motion is obtained by calculating the length of the shortest path between the initial and final position.

d = √(a² + b)

where;

d = √(3² + 4²)

d = 5 km

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One hypothesis for planetary differentiation is the process through which various layers with diverse chemical and/or physical features arise.

A planet's trajectory around a star, a natural satellite's path around a planet, or an artificial satellite's course around a space object or place, such as a planet, moon, asteroid, or Lagrange point, are examples of orbits in celestial mechanics.

A spacecraft, planet, moon, star, or other object travels on a curved route called an orbit when it is dragged by the gravity of another object.

The force of gravity is what pulls objects with mass in space. An orbit is a path an object follows as it travels around a certain location in space, such as the Moon's orbit of the Earth.

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The root square method of the gas at 273 K is given as 493.15 for N2 and 461.3 for O2

We have to know that the root square method is dependent on the direct proportionality to the square root of absolute temperature as well as inverse of molar mass.

We have 1 j = 1 kgm²/s²

Vrms = √3rt/Mm

R = gas constant

T = temperature = 273

Mm is the molar mass

The molar mass of N₂ is = 0.02800 kg / mol

The mo;lar mass of o₂ = 0.03200 kg / mol

We have to solve first for N₂

= √3 (8.32447 * 273 / 0.028000

= √243,198.247

= 493.15

For 02

Vrms = √3 * 8.31447 * 273  / 0.03200

= √212798.466

= 461.3

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Two protons and two neutrons are both present in the particle that an unstable nucleus releases.

The nuclear process known as  "alpha decay" results in the parent nucleus emitting an alpha particle. The alpha particle, represented by the Greek letter and physically similar to the helium atom's nucleus, is made up of two protons and two neutrons.

What statement about deterioration is true? It brings down the atomic number of the nuclide by 2. The daughter nuclide, which frequently doesn't undergo further decay since the parent nuclide is unstable, is created during radioactive decay.

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Since the magnetic force and velocity are orthogonal, the velocity only changes in direction but not in magnitude . Circular motion is the end consequence. The force is in the opposite direction from the right-hand rule and has a negative charge.

Uniform In circular motion, an object moves in two dimensions with a constant speed in a fixed circular direction; however, because the object's direction changes at every point, the velocity also changes, and the direction at each point is always the tangent.

In physics, magnetic force is referred to as an object's maximal size and direction. Both vector and scalar values use magnetic force as a common factor. We understand that by definition

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Answer: The velocity simply changes in direction, not magnitude, as the magnetic force and velocity are orthogonal.

Explanation: The velocity simply changes in direction, not magnitude, as the magnetic force and velocity are orthogonal. The resultant motion is circular. The force has a negative charge and is directed in the opposite direction from the right-hand rule.

Uniform In a circular motion, an item moves in two dimensions with a constant speed in a fixed circular direction; yet, because the object's direction varies at each point, the velocity also alters, and the direction at each point is consistently the tangent.

As an object's maximum size and direction, the magnetic force is referred to in physics. Magnetic force is a factor that is present in both scalar and vector values. We comprehend that by nature.

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Coefficient 2  should be placed in front of HCl to balance  the given chemical equation.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

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The mass of the rock with a kinetic energy of 113J and a speed of 6.2m/s is approximately 5.88 kilograms.

Kinetic energy is simply the energy a body possesses due to its motion;

It is expressed as;

K.E = 1/2 × m × v²

Given the data in the question;

To determine the mass of the rock, plug the given values into the Kinetic energy formular and solve for m.

K.E = 1/2 × m × v²

113kgm²/s² = 1/2 × m × ( 6.2m/s )²

113kgm²/s² = 1/2 × m × 38.44m²/s²

113kgm²/s² = m × 19.22m²/s²

m = 113kgm²/s² / 19.22m²/s²

m = 5.88kg

Therefore, the mass of the rock is 5.88 kilograms.

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The components of the final displacement (in m), from  the initial to final point, along the north and west directions is given as:

88m west and 50m north

The displacement of an object is a vector whose length is the shortest distance from the initial to the final position of a point P undergoing motion.

we will find the components of each vector in x and y:

For Vector 1:

Fx = 52m

Fy = 0m

for  Vector 2:

Fx = 40m*cos31.1

Fy = 40m * cos 31.1

For  Vector 3:

Fx = 0m

Fy = 25m

we will then find the components of the final displacement acting in x and y:

For west direction:

Rx = 52m + 40m*cos31.1 + 0

Rx = 90m

For north direction:

Ry = 0 + 40m*sin31.1 + 25m

Ry = 12m.

In conclusion, displacement is a vector quantity that refers to how far out of place an object is. Displacement is known to be  the object's overall change in position.

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The vertical component of the velocity after the given interval of time will be:

B: -9.8 m/s

D: -19.6 m/s

F: -29.4 m/s

H: -39.2 m/s

A projectile can be described as any object upon which the only force is gravity. The projectile travels with a parabolic trajectory because of the influence of gravity. No horizontal forces are acting upon projectiles so there is no horizontal acceleration.

The horizontal velocity of a projectile is constant and the vertical acceleration is caused by gravity. The vertical component of the velocity of a projectile changes by 9.8 m/s each second while the horizontal motion of a projectile is independent of its vertical motion.

Given, the initial horizontal velocity, vₓ = 18 m/s

The initial vertical velocity, Vy = 0 m/s

The time interval = 1 sec

The vertical component of the velocity is calculated as;

[tex]V_y = V_{0y} -gt[/tex]

[tex]V_y = 0- (9.8) (1)\\V_y = -9.8 m/s[/tex]

The vertical component when t = 2 sec and horizontal velocity, Vx = 18 m/s

[tex]V_y = 0- (9.8) (2)\\V_y = -19.6 m/s[/tex]

The vertical component of velocity when t = 3sec:

[tex]V_y = 0- (9.8) (3)\\V_y = -29.4 m/s[/tex]

The vertical component of velocity when t = 4sec:

[tex]V_y = 0- (9.8) (4)\\V_y = -39.2 m/s[/tex]

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a) The motion of the motorcyclist is a uniform motion

b) The distance is 600 m

c) The speed is 20 m/s.

We now that motion has to do with the change in the position of an object with time. In this case, we have the graph that described the motion of the motorcyclist . It is clear that the distance is increasing in equal amounts, in equal time intervals thus this is a uniform motion.

Looking at the graph, we can see that the motorcyclist covers 600 meters of distance within 30 seconds.

We can obtain the speed as the ratio of the distance to the time or the slope of the graph. Hence the speed is obtained from;

Speed = distance / time

Using the slope concept;

[tex]y_{2} - y_{1} /x_{2} - x_{1}[/tex]

= 600 - 0/30 - 0

= 20 m/s

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