why did the ball move the same distance when it was on the flatbed truck that accelerated 0.2 m/s?
The relative velocity of the ball with respect to the truck is same as that of the truck with respect to the ball at equal time.
What is relative velocity?The relative velocity of an object is the velocity of the object observed with respect to rest frame of another object.
Distance traveled by the objectThe distance traveled by each object is determined from the prouduct of velocity and time of motion.
d = vt
where;
v is velocityt is timeThus, if the ball moved the same distance when it was on the flat bed truck, then the relative velocity of the ball with respect to the truck is same as that of the truck with respect to the ball at equal time.
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A point charge q = -6.0nC is located at the origin. The electric field (in N/C) vector at the point x = -8.0m, y= +1.5m is?
Answer:
Explanation:
The position between point charge q to x = -8.0 m and y = 1.5 m is:
[tex]r=\sqrt{x^{2}+y^{2}}=\sqrt{(-8)^{2}+(1.5)^{2}}=\sqrt{66.25}\approx 8.13[/tex] meter
Then the magnitude of the electric field E is:
[tex]E=\frac{1}{4\pi\epsilon_{o}} \frac{q}{r^{2}}=(9\times 10^{9}) \frac{6.0\times 10^{-9}}{66.25}\approx 0.81 N/C[/tex]
For the vector of E:
[tex]\tan\theta=\frac{1.5}{-8}=-0.1875 \rightarrow \theta = -10.61^{0}[/tex]
[tex]E_{x}=E\cos (-10.16)=(0.81)(0.984)=0.79704 N/C[/tex]
[tex]E_{y}=E\sin\theta = -0.81(0.184)=-0.14904 N/C[/tex]
[tex]\vec{E}=0.79704\hat{i}-0.14904\hat{j}[/tex] in N/C
An output gear has 10 teeth and an input gear has 40 teeth. What is the mechanical advantage of this gear combination?
Answer:
4
Explanation:
We know that :
Mechanical Advantage = Input / OutputSolving
MA = Input / OutputMA = 40 / 10MA = 4A 3 Hz wave has a wavelength of 0.4 m. Calculate the speed of the wave (in m/s).
The speed of the wave with the given frequency and wavelength is 1.2m/s.
Given the data in the question;
Wavelength of the wave; [tex]\lambda = 0.4m[/tex]Frequency; [tex]f = 3Hz = 3s^{-1}[/tex]Speed of the wave; [tex]v = \ ?[/tex]WavelengthWavelength is the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.
It is expressed as;
[tex]\lambda = \frac{v}{f}[/tex]
Where v is velocity/speed and f is frequency.
Now, we can easily get the speed of the wave by substituting our given values into the expression above.
[tex]\lambda = \frac{v}{f} \\\\0.4m = \frac{v}{3s^{-1}}\\ \\v = 0.4m * 3s^{-1}\\\\v = 1.2ms^{-1}\\\\v = 1.2m/s[/tex]
Therefore, the speed of the wave with the given frequency and wavelength is 1.2m/s.
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how did we compensate for friction
A body is piloted at a point. A force of 10 N is applied at a distance of 30 cm from the pivot. Find the amount of force about the pivot .
Question :-
A Body is Pivoted at a Point. A Force of 10 N is Applied at a Distance of 30 cm from the Pivot. Find the Amount of Force about the Pivot.Answer :-
Amount of Force is 3 Nm .Explanation :-
As per the provided information in the given question, The Force is given as 10 Newton . The Distance is given as 30 cm [ 0.3 m ] . And, we have been asked to calculate the Amount of Force .
For calculating the Force , we will use the Formula :-
[tex] \bigstar \: \: \: \boxed{ \: \sf {Moment \: of \: Force \: = \: Force \: \times \: Distance} \: } [/tex]
Therefore , by Substituting the given values in the above Formula :-
[tex] \dag \: \: \: \sf {Moment \: of \: Force \: = \: Force \: \times \: Distance} [/tex]
[tex] \longmapsto \: \: \: \sf {Moment \: of \: Force \: = \: 10 \: \times \: 0.3} [/tex]
[tex] \longmapsto \: \: \: \textbf {\textsf {Moment \: of \: Force \: = \: 3}} [/tex]
Hence :-
Amount of Force = 0.3 Nm .[tex] \underline {\rule {185pt}{4pt}} [/tex]
A Rich has been hooked and is puilling on the line as shown in the figure below.
RO
18
If the pole makes an angle of 25° with the horizontal, the distance between the point where the line is attached to the pole and the anglers hand is L. 2.45 m, and the fish
pulls on the line such that the tension in the line is T-166 Nat an angle 35.0 below the horizontal, determine the magnitude (in N.m) of the torque exerted by the fish
about an axis perpendicular to the page and passing through the angler's hand.
Nm
For the magnitude in N.m of the torque exerted by the fish about an axis perpendicular to the page and passing through the angler's hand is mathematically given as
Z = 360.33Nm
What is the magnitude in N.m of the torque exerted by the fish about an axis perpendicular to the page and passing through the angler's hand?
Generally, the equation for the Torque is mathematically given as
Z = force x perpendicular distance
Z = Tcos30° x L
Z = 166(0.886) x 2.45
Z = 360.33Nm
In conclusion s the magnitude in N.m of the torque exerted by the fish about an axis perpendicular to the page and passing through the angler's hand
Z = 360.33Nm
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.. In the reaction 238 92U ---- X + 2 4 He, the particle represented by X is . answer choices . 234 90 Th. 234 92 U. 238 93 Np. 242 94Pu. ... Which conditions are required
My question
• Complete the following reaction:
238 92U = ______ + ________ + 4 2He
…Is this the same question as the answer
Answer:
234 90 +energy
Explanation:
because alpha decrease by 4 2helium
2. How long would it take a car to reach 50 m/s if they accelerated at a constant rate of 5.44
m/s?? Assume the car begins at rest.
9.19 seconds (2dp)
Given:
v = 50m/s
u = 0 m/s
a = 5.44 m/s
t = ?
Substitute values into the equation v = u + at
v = u + at
50 = 0 + 5.44 x t
t = 50/5.44
t = 9.19 seconds
Time is in seconds as the velocity and acceleration are in metres per second instead of kilometres per hour
The sound intensity at a distance of 19 m from a noisy generator is measured to be 0.24 W/m2. What is the sound intensity at a distance of 27 m from the generator
Answer:
0.1111 W/m²
Explanation:
If all other parameters are constant, sound intensity is inversely proportional to the square of the distance of the sound. That is,
I ∝ (1/r²)
I = k/r²
Since k can be the constant of proportionality. k = Ir²
We can write this relation as
I₁ × r₁² = I₂ × r₂²
I₁ = 0.25 W/m²
r₁ = 16 m
I₂ = ?
r₂ = 24 m
0.25 × 16² = I₂ × 24²
I₂ = (0.25 × 16²)/24²
I₂ = 0.1111 W/m²
A atom in its ground state contains 18 electrons. how many of these electrons are in orbital l=0 values?
A dragster's top acceleration is 60 m/s.
If it accelerates for 3 seconds from the
starting line, how fast will it be going?
Answer:
very fast
Explanation:
A charged particle moves in a uniform magnetic field of 0.775 T
with a period of 4.79×10−6 s.
Find its charge-to-mass ratio ||/.
Hi there!
Recall that a charge that enters a magnetic field while moving experiences a magnetic force that causes it to enter a state of uniform circular motion.
We know the following (For a point charge):
[tex]F_B = qv B[/tex]
q = Charge (C)
v = velocity (m/s)
B = Magnetic field (T)
Fb= Magnetic force (N)
The equation for centripetal force:
[tex]F_c = \frac{mv^2}{r}[/tex]
m = mass (kg)
v = velocity (m/s)
r = radius (m)
Fc = Centripetal force (N)
Since we are given its period:
[tex]T = \frac{2\pi r}{v}\\\\v = \frac{2\pi r}{T}[/tex]
Plug this expression into the above equations. Since the magnetic force equals the centripetal force, set them equal to each other and simplify.
[tex]q\frac{2\pi r}{T} B = \frac{m}{r}(\frac{2\pi r}{T})^2[/tex]
Cancel out the expression.
[tex]qB = \frac{m}{r} (\frac{2\pi r}{T})[/tex]
Cancel out 'r'.
[tex]qB = \frac{2\pi m}{T}[/tex]
Now, we can simplify as necessary to find a value for 'q' over 'm':
[tex]\frac{q}{m} = \frac{2\pi }{TB} = \frac{2\pi }{(4.79 \times 10^{-6})(0.775)} = \boxed{1692554.464}[/tex]
Thus, the charge is 1.693 ×10⁶ times larger than its mass.
Is water Wet or Dry. Explain.
Explanation:
Water is wet, in the sense of being a liquid which flows easily, because its viscosity is low, which is because its molecules are rather loosely joined together.
Answer:
Liquid water is not itself wet, but can make other solid materials wet.
Wetness is the ability of a liquid to adhere to the surface of a solid, so when we say that something is wet, we mean that the liquid is sticking to the surface of a material.
Whether an object is wet or dry depends on a balance between cohesive and adhesive forces. Cohesive forces are attractive forces within the liquid that cause the molecules in the liquid to prefer to stick together. Cohesive forces are also responsible for surface tension. If the cohesive forces are very strong, then the liquid molecules really like to stay close together and they won't spread out on the surface of an object very much. On the contrary, adhesive forces are the attractive forces between the liquid and the surface of the material. If the adhesive forces are strong, then the liquid will try and spread out onto the surface as much as possible. So how wet a surface is depends on the balance between these two forces. If the adhesive forces (liquid-solid) are bigger than the cohesive forces (liquid-liquid), we say the material becomes wet, and the liquid tends to spread out to maximize contact with the surface. On the other hand, if the adhesive forces (liquid-solid) are smaller than the cohesive forces (liquid-liquid), we say the material is dry, and the liquid tends to bead-up into a spherical drop and tries to minimize the contact with the surface.
Water actually has pretty high cohesive forces due to hydrogen bonding, and so is not as good at wetting surfaces as some liquids such as acetone or alcohols. However, water does wet certain surfaces like glass for example. Adding detergents can make water better at wetting by lowering the cohesive forces . Water resistant materials such as Gore-tex fabric is made of material that is hydrophobic (water repellent) and so the cohesive forces within the water (liquid-liquid) are much stronger than the adhesive force (liquid-solid) and water tends to bead-up on the outside of the material and you stay dry.
You ride your bike north for 100 m at a constant speed of 5 m/Your acceleration is…
Answer:
our acceleration is 0 because there is a constant speed..
a = final speed - initial speed / time
final speed = initial speed ( since speed is constant)
therefore acceleration is 0
A rocket weighing 220,000 N is taking off from Earth with a total thrust of
500,000 N at an angle of 20 degrees, as shown in the image below. What is
the approximate vertical component of the net force that is moving the rocket
away from Earth?
20°
Vertical
Component
of Net Force
Thrust
500,000 N
Weight
220,000 N
The vertical component of the net force that is moving the rocket away from Earth is determined as 171,010.1 N.
Vertical component of the lift force
The vertical component of the net force that is moving the rocket away from Earth is determined as follows;
Fy = Fsinθ
where;
F is applied forceθ is the angle of inclinationFy = 500,000 x sin(20)
Fy = 171,010.1 N
Thus, the vertical component of the net force that is moving the rocket away from Earth is determined as 171,010.1 N.
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Answer:
250,000
Explanation:
7. A steel band exerts a horizontal force of 80.0 N on a tooth
at point B in Figure 7.3. What is the torque on the root of
the tooth about point A?
Gum
48.0°
A
F
1.20 cm
The torque experienced by the root of the tooth about point A when the steel band exerts the given force is 0.713 Nm.
Torque about point AThe torque experienced by the root of the tooth about point A is calculated as follows;
τ = rFsinθ
where;
F is applied forcer is the perpendicular distanceτ = (0.012) x (80) x (sin 48)
τ = 0.713 Nm
Thus, the torque experienced by the root of the tooth about point A when the steel band exerts the given force is 0.713 Nm.
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Two blocks are connected to identical ideal springs and are oscillating on a horizontal frictionless surface. Block A has mass m, and its motion is represented by the graph of position as a function of time shown above on the left. Block B’s motion is represented above on the right. Which of the following statements comparing
block B to block A is correct?
(A) Because block B covers more distance per cycle than block A, block B takes more time to complete each
cycle.
(B) Because the spring attached to block B is initially stretched a greater distance, the spring constant is smaller
and therefore block B has a slower average speed than block A does.
(C) Because block B has more mass, it has a slower average speed than block A does.
(D) Because block B has more mass, its acceleration is smaller than that of block A at any given displacement
from the equilibrium position.
Hi there!
We can begin by identifying key characteristics of both graphs.
Graph A.
Looking at the graph, we can see that the maximum distance (amplitude) is 10 cm (0.1 m). Additionally, its period (T) is 2 seconds (one full cycle).
We also know that:
[tex]T = 2\pi \sqrt{\frac{m}{k}}[/tex]
We can use this equation to compare with the other graph. Notice how the period does NOT depend on how far the spring is stretched. We can eliminate choice A for this reason.
Graph B.
The amplitude is 20 cm (0.2 m), and each period is 4 seconds.
We can now eliminate choice B because the springs are identical, so their spring constants are equal. Distance stretched has no impact on the spring constant.
For the other choices, we must look at forces and work.
Recall that:
Spring potential energy = [tex]\frac{1}{2}kx^2[/tex]
Kinetic energy = [tex]\frac{1}{2}mv^2[/tex]
Using the work-energy theorem:
[tex]\frac{1}{2}kx^2 = \frac{1}{2}mv^2[/tex]
Even if the mass of Block B is greater, its displacement is larger than that of Block A. Since displacement is squared in this equation, it would have a greater effect on the speed. Thus, Choice C is incorrect.
Using Hooke's Law:
[tex]\Sigma F = -kx\\\\ma = -kx\\[/tex]
[tex]a = \frac{-kx}{m}[/tex]
If the mass is greater, the acceleration will be smaller. Choice D is correct.
find the half life of a radioactive natural which decays to 6.25% of it's original no. of nuclei in 50 seconds.
Answer:
After 1 decay it has .9375 of its value left
.9375^n = 1/2
What is the value of n (number of decays)
n log .9375 = -.693
n =.693 / .0645 = 10.7
After 10.7 periods of 50 sec it will have 1/2 of its original nuclei left
1/2 life = 10.7 * 50 sec = 537 sec = 8.95 min
✓ 4.) A certain molecule has an energy-level diagram for its vibrational energy in
which two levels are 0.0141eV apart. Find the wavelength of the emitted
line for the molecule as it falls from one of these levels to the other. [h
6.63 x 10-34 kgm s-?, C = 3 x 108ms-1, lev = 1.602 x 10^-19j
Answer:
Explanation:
You can use [tex]\Delta E=\frac{\hbar c}{\lambda} \rightarrow \lambda =\frac{\hbar c}{E} = \frac{1240 eV.nm}{0.0141 eV} \approx 87943.26[/tex] in nm.
Here the hc = 1240 eV.nm in eV and nanometer unit.
Two pendula are shown in the figure. Each consists of a solid ball with uniform density and has a mass M. They are each suspended from the ceiling with massless rod as shown in the figure. The ball on the left pendulum is very small. The ball of the right pendulum has radius 1/2 L.
Find the period T of the right pendulum for small displacements in s.
The period (T) of the right pendulum for small displacements in s is equal to 1.49 seconds.
How to calculate the period (T).Mathematically, the time taken by this pendulum to undergo a small displacement is given by this formula:
[tex]T=2\pi \sqrt{\frac{L}{g} }[/tex]
Where:
L is the length.g is the acceleration due to gravity.Scientific data:
Acceleration due to gravity (g) = 9.8 m/s².
Assuming a randomized variable for the length of the rope to be 1.2 meter. Also, we know that the right pendulum has a radius of 1/2L.
1/2L = L/2
L/2 = 1.1/2
L/2 = 0.55 meter.
Substituting the parameters into the formula, we have;
[tex]T=2\times 3.142 \sqrt{\frac{0.55}{9.8} }\\\\T=6.284 \times \sqrt{0.0561} \\\\T=6.284 \times 0.2369[/tex]
T = 1.49 seconds.
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Calculate the speed of sound in a string that has a tension of 100 N and a linear mass density of 0.0001 kg/m
Which of the following examples of the streets Newton second law of motion
Explanation:
Newton’s second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.
A wave has a frequency of 5hz and a wave speed of 25m/s what is the wavelength?
25 m
5 m
25 m/s
125 m
PLEASE HELP I WILL MARK BRAINLIEST
A 0.14 kg baseball is dropped from rest. It has a momentum of 0.78 kg.m/s just before it lands on the ground. For what amount of time was the ball in the air?
Answer:
0.568
Explanation:
velocity = -9.8 (t) + Vo
Vo= 0 so v= 9.8(t)
Momentum = mass x velocity
v * 0.14 kg = 0.78 kg m/s
v = 5.571 m/sec
v= 9.8(t) , so substituting v we get , 5.571 = 9.8 * t
t = 5.571/9.8 = 0.568 seconds
A fish uses its tail fin to push against the water. The water is pushed backward, in the fish is pushed for it. Is it Newton's first law of motion, Newton's second law of motion, or Newton's third law of motion?
Answer:
it is Newton's third law of motion?
Hope This Helps
What should you do with electrical cells and batteries that no longer work
Answer:
Yes, single-use batteries are now made of common metals deemed non-hazardous by the federal government and can be disposed of in your regular trash in all states except California, where it is illegal to throw away all types of batteries.
The Empire State Building is about 381m high. If you threw a baseball downward at 25 m/s from the top of the building how fast would it be traveling just before it landed?
Answer:
Explanation:
You can use that [tex]v = v_{o}+gt[/tex] or [tex]v^{2}=v_{o}^{2}+2gh=(25)^{2}+(2)(10)(381)=8245 \rightarrow v \approx 90.8[/tex] m/s.
A town is considering building a biodiesel power plant that would burn a biomass to generate electricity. Which of the following correctly lists an advantage and a disadvantage of this project?
Advantage: it could get rid of some unwanted waste. Disadvantage it would emit pollution into the air.
Advantage: it reduces dependence on fossil fuels. Disadvantage: it would create new jobs for the area.
Advantage: it produces carbon dioxide, Disadvantage: building the power plant would be expensive.
Advantage: it would use existing garbage and agricultural waste. Disadvantage: there is no way to use the power created.
Answer:
Advantage: it could get rid of some unwanted waste. Disadvantage: it would emit pollution into the air.
Which points in the diagram would have Spring tides?
points A and B
points A and C
points C and D
points B and D
Answer:
If the Sun was on the left side of the diagram it would be points A and C
Explanation:
Spring tides are when the Sun, Earth, and Moon are aligned together. Neap tides occur when when the Sun, Earth, and Moon are forming a right angle.
Answer:
C and d mark mwe braliest
Explanation: