7. A volcanic island arc is formed when

7. A Volcanic Island Arc Is Formed When

Answers

Answer 1
A I believe ^^^^^^ luck!!!

Related Questions

.A water tank has dimensions
of 6m x 4m x 4m. Find the pressure exerted by
water at the base of dam when it is half
filled. ( Density of water - 1000 kg/ m2,
acceleration
due to to gravity is 9.8m/s2

Answers

Answer:

9800Nm⁻²

Explanation:

Given parameters:

Dimensions of the water tank = 6m x 4m x 4m

Density of water  = 1000kgm⁻³

Gravity  = 9.8m/s²  

Unknown:

Pressure exerted by the water at the base of the dam  = ?

Solution:

The pressure exerted by the water is given as:

  Pressure  = density of water x acceleration due to gravity x height of water

The height of the water here is half = 1m

   

Pressure  = 1000 x 9.8 x 1 = 9800Nm⁻²

which unit would be most
suitable for its scale?

Answers

Answer:

down below

Explanation:

for a scale, kg is used, as well as grams

for force, newtons is used

Which two life functions of animals help maintain the water cycle by recycling water back into the environment?

Answers

Answer:

Respiration and excretion

Explanation:

Respiration. When animals breathe, their lungs release water vapour to the atmosphere.

Animals excrete water by respiration and by passing urine.

Estimate the volume of each ball. Use the formula

where V is the volume and r is the radius. Record the volumes in Table A of your Student Guide.
What is the estimated volume of the table tennis ball?
cm3
What is the estimated volume of the golf ball?
cm3

Answers

The given question is incomplete. The complete question is:

Estimate the volume of each ball. Use the formula [tex]v=\frac{4\pi\times r^3}{3}[/tex] where v is the volume and r is the radius. record the volume in table A of your student guide. The radius of the tennis ball is 2.1 cm and the radius of thr golf ball is 2.0 cm. What is the estimated volume of the table tennis ball in [tex]cm^3 [/tex] What is the estimated volume of the golf ball in

Answer: Volume of the tennis ball is [tex]38.8cm^3[/tex] and  Volume of the golf ball is [tex]33.5cm^3[/tex]

Explanation:

We have to find the Volume of tennis ball and golf ball by using the formula [tex]v=\frac{4\pi\times r^3}{3}[/tex]

Radius of the tennis ball = 2.1 cm

Radius  of the golf ball =2.0 cm.

Putting the value of radius in the formula , we get:

Volume of the tennis ball =  [tex]\frac{4\times 3.14\times (2.1cm)^3}{3} =38.8cm^3[/tex]

Volume of the golf ball =   [tex]\frac{4\times 3.14\times (2.0cm)^3}{3} =33.5cm^3[/tex]

Volume of the tennis ball is [tex]38.8cm^3[/tex] and  Volume of the golf ball is [tex]33.5cm^3[/tex]

it's  38.8 and 33.5 hope this helps

a train has an initial velocity of 44m/s and an accelaration of _4m/s calculate its velocity​

Answers

Answer:

It's 4m/s

Explanation:

V = u _ at, at u = 44m/s

44 + [-4]10

4m/s

How much work is done if a force of 20 N is used to move an object 6 meters​

Answers

Explanation:

W=f×d

=20×6

w=120 joule

Help, please! Thank you for your kind gesture

Answers

Answer:

The last option.

Explanation:

Since you are going down, the gravitational potential energy would go down too. Thus, the gravitational potential energy decreases.

Since the gravitational potential energy is converted to kinetic energy when you move down, there is an increase in kinetic energy.

Answer:

The fourth option

Explanation:

Marina walked 2km in half an hour, what was her average speed during her walk?

Answers

Answer:

4km/hr

Explanation:

1. How much work is done in lifting an 8-kg box
from the floor to a height of 2m above the
floor?

Answers

Answer:

156.8 Joules

Explanation:

Work = Force x Displacement

Displacement = 2m

Force (force of gravity) = mass x acceleration due to gravity =  8Kg x 9.8m/s^2

= 78.4N

Work = FxD

Work = 78.4 N x 2m

Work = 156.8 N·m  OR 156.8 Joules

The amount of work done in lifting this box is equal to 156.8 Joules.

Given the following data:

Mass = 8 kilograms.Displacement = 2 meters.

Scientific data:

Acceleration due to gravity = 9.8 [tex]m/s^2[/tex]

To calculate the amount of work that is done in lifting this box:

How to calculate work done.

Mathematically, the work done by a person is calculated by using this formula:

[tex]Work\;done = Fd = mgd[/tex]

Where:

F is the force.d is the displacement.m is the mass.

Substituting the given parameters into the formula, we have;

[tex]Work\;done = 8 \times 9.8 \times 2[/tex]

Work done = 156.8 Joules.

Read more on work done here: https://brainly.com/question/25573309

The driver of a 1.5 x 103 kg car is traveling east at 10 m/s and increases its speed to 30 m/s east over 15 seconds. What was the change in momentum of the car? Kgm/s

Answers

Answer:

30,000kgm/s

Explanation:

Change in momentum is expressed as;

Change in momentum = mass × change in velocity

∆M = m∆v

Mass m = 1.5×10³kg = 1500kg

∆v = 30-10 =20m/s

Substitute into the formula

Change in momentum = 1500(20)

Change in momentum = 30,000kgm/s

A pickle sits 8.0 cm from the center of a circular, rotating platter. The platter rotates such
that the pickle's tangential speed is 4.8 cm/s. What is the pickle's centripetal
acceleration?
(A) 0.36 cm/s
(B) 0.60 cm/s2
(C) 1.2 cm/s2
(D) 2.9 cm/s2
(E) 5.8 cm/s2

Answers

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

Two billiard balls of equal mass collide. Ball 1 is initially moving at 0.43 m/s to the left, and ball 2 is initially at rest. Which of the following sets of final velocities does not describe an inelastic collision between the balls?


A. Ball 1 at 0.12 m/s left, Ball 2 at 0.31 m/s left

B. Ball 1 at 0.21 m/s left, Ball 2 at 0.22 m/s left

C. Ball 1 at 0.10 m/s left, ball 2 at 0.33 m/s left

D. Ball 1 at rest, ball 2 at 0.43 m/s left

Answers

The answer should be (B)

Answer: B

"Ball 1 at 0.21 m/s left, Ball 2 at 0.22 m/s left"

Compare between Convex lens and concave lens

Answers

Answer:

A convex lens or converging lens focuses the light rays to a specific point whereas a concave lens or diverging lens diverges the light rays. When these lenses are combined, they produce sharper images. Most of the eyeglass lenses use combinations of convex and concave lenses.

At the height of 800 meters, a skydiver falls from an airplane flying horizontally at 40 m/sec. What is the horizontal distance of the skydivers travel before they "hit" the ground?

Answers

Answer:

The horizontal distance traveled by the skydiver is 510.8 m.

Explanation:

Given;

height of fall, h = 800 m

initial velocity of the airplane, u = 40 m/s

The time to fall to the ground is calculated as;

[tex]t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2 \times 800}{9.81} }\\\\t = 12.77 \ s[/tex]

The horizontal distance or range of the motion is calculated as;

R = ut

R = 40 m/s x 12.77 s

R = 510.8 m

Therefore, the horizontal distance traveled by the skydiver is 510.8 m.

Write a message to Mr. Chang explaining why the groundwater heating system will warm the school more than the water heater system. Use evidence to support your claim. For each piece of evidence you use, explain how the evidence supports your claim.

Answers

Answer:

For, heating purposes more the quantity of  water more will be the heating. Clearly, underground heating would have more water and hence, it will have edge over the  water heater system.

Moreover, for things at the same temperature, the thing with more molecules has more total kinetic energy (thermal energy) than the thing with fewer molecules. The groundwater heating system uses heat from the heat stored naturally in groundwater or aquifers. Thus, saving the cost of power required to heat in normal water heater.

Explanation:

The groundwater heating system will warm the school more than the water heater system due to the fact that it uses more water more than the other system.

Based on the complete question, it should be noted that the addition of energy leads to an increase in motion which results in the rise in temperature.

The groundwater heating system will warm the school more than the water heater system due to the fact that it uses more water more than the other system even though its water isn't as warm as in the other system.

Read related link on:

https://brainly.com/question/20116115

ANSWER QUICK 30 POINTS
What force controls the movement of the planets around the sun, holds together stars grouped in galaxies, and galaxies grouped in clusters? Thoroughly explain your answer, making sure to include an example and describe how this force keeps planets in orbit. Make sure to write at least 3-5 sentences and proper conventions (spelling, grammar, punctuation, etc.) to respond. Put all answers in your own words

Answers

Answer:

Gravity controls the movement of the planets around the sun, holds together stars grouped in galaxies, and galaxies grouped in clusters.  The Universal Law of Gravitation depends on two things.  First it depends on mass of each object  and the second factor is the distance between two objects.  If the mass of one object is Larger, the gravitational pull towards it will be larger  and the smaller distance, the larger the gravitational pull will be between the objects. Therefore the Larger planets have more moon and the inner planets have less.

Explanation:

Hi!! Does anyone know this answer? :D

Answers

Answer:

Im not fully corrrect but I would say C

Explanation:

On Earth, a spring stretches by 5.0 cm when a mass of 3.0 kg is suspended from one end.
The gravitational field strength on the Moon is
1/6 of that on Earth.
Which mass, on the Moon, would stretch the spring by the same extension?

Reasons too :(
igcse physics

Answers

Answer:

Mass = 18.0 kg

Explanation:

From Hooke's law,

F = ke

where: F is the force, k is the spring constant and e is the extension.

But, F = mg

So that,

mg = ke

On the Earth, let the gravitational force be 10 m/[tex]s^{2}[/tex].

3.0 x 10 = k x 5.0

30 = 5k

⇒ k = [tex]\frac{30}{5}[/tex] ................ 1

On the Moon, the gravitational force is [tex]\frac{1}{6}[/tex] of that on the Earth.

m x [tex]\frac{10}{6}[/tex] = k x 5.0

[tex]\frac{10m}{6}[/tex] = 5k

⇒ k = [tex]\frac{10m}{30}[/tex] ............. 2

Equating 1 and 2, we have;

[tex]\frac{30}{5}[/tex]  = [tex]\frac{10m}{30}[/tex]

m = [tex]\frac{900}{50}[/tex]

    = 18.0

m = 18.0 kg

The mass required to produce the same extension on the Moon is 18 kg.

Answer:

18 kg

Explanation:

weight (N) = mass (kg) × gravitational acceleration (m/s²)force (N) = k (spring constant) × extension (m)

On Earth, acceleration of gravity is 10 m/s²

weight = 3.0 (kg) × 10 (m/s²)weight = 30 (N)

Since weight is a force, the force is 30 N. The value of spring constant is unknown

30 (N) = k × 5 (m)k = 6 (m/N)

Spring constant is 6. Now let's find the mass on the Moon

mass (kg) × gravitational acceleration (m/s²) = k (spring constant) × extension (m)

Gravitational acceleration of the moon is 1/6 of that on Earth. Earth's g = 10, so Moon's g = 10/6

m × 10/6 = 6 × 5m = 30/(10/6)m = 18

The mass is 18 kg

A horizontal pole is attached to the side of a building. There is a pivot P at the wall and a chain is connected from the end of the pole to a point higher up the wall. There is a tension force F in the chain. What is the moment of the force F about the pivot P?

Answers

Answer:

Fscos63

Explanation:

Given that a horizontal pole is attached to the side of a building. There is a pivot P at the wall and a chain is connected from the end of the pole to a point higher up the wall. There is a tension force F in the chain. What is the moment of the force F about the pivot P?

Taking the moment from the pivot point P, that means the moment at point p = 0

Then, if we consider the weight mg of the pole, according to the principle of equilibrium : sum of the upward forces equal to the sum of the downward forces.

Therefore, mg = Fsinø ....... (1)

Also, taking moment at point P

Let the length of the pole = s

The length of the weight of the pole = 1/2 S

Fscosø = mgs/2

The distance s will cancel out

2Fcosø = mg ...... (3)

Substitute mg in equation 1 into equation 3

2fcosø = fsinø

F will cancel out

Tanø = 2

Ø = tan^-1(2)

Ø = 63.4 degree

The moment of force F about pivot point P will be

Moment = force × distance

Moment = Fcos63 × S

Moment = Fscos63

A car traveled 1,215 km West from El Paso to Dallas in 13.5 hours. What was its velocity? A: 90 m/s west B. 90km/h C. .09km/h West D. 90km/h West

Answers

Answer:

B. 90km/hr

Explanation:

The formula for finding velocity =

Displacement/time

The displacement of the car has been given to be = 1215 km West

Time it took to go from Dallas to Paso = 13.5 hours

Then velocity = 1215/13.5

= 90

Therefore velocity = 90km/hour

Option B is the correct answer to this question.

Thank you!

what is projectile. what is projectile motion​

Answers

Projectile:

The projectile is any object thrown into space upon which the only acting force is gravity. In other words, the primary force acting on a projectile is gravity. This doesn’t necessarily mean that the other forces do not act on it, just that their effect is minimal compared to gravity. The path followed by a projectile is known as a trajectory. A baseball batted or thrown and the instant the bullet exits the barrel of a gun are all examples of the projectile.

Projectile Motion:

When a particle is thrown obliquely near the earth’s surface, it moves along a curved path under constant acceleration that is directed towards the center of the earth (we assume that the particle remains close to the surface of the earth). The path of such a particle is called a projectile and the motion is called projectile motion. Air resistance to the motion of the body is to be assumed absent in projectile motion.

In a Projectile Motion, there are two simultaneous independent rectilinear motions:

Along the x-axis: uniform velocity, responsible for the horizontal (forward) motion of the particle.

Along y-axis: uniform acceleration, responsible for the vertical (downwards) motion of the particle.

Accelerations in the horizontal projectile motion and vertical projectile motion of a particle: When a particle is projected in the air with some speed, the only force acting on it during its time in the air is the acceleration due to gravity (g). This acceleration acts vertically downward. There is no acceleration in the horizontal direction, which means that the velocity of the particle in the horizontal direction remains constant.

[tex]\sf~~~~~~~~~~~~~~~{\red{\underbrace{\underline{\green{projectile~motion}}}}}[/tex]

Projectile motion is a form of motion in which object or particle is thrown near earth's surface and it moves along a curved path under the action of gravity only.

A lift travelling up to the top floor of the Empire State building with a mass of 4200kg and a kinetic energy of 4116J. Find the velocity

Answers

Answer:

1.4 m/s

Explanation:

The velocity can be found by using the formula

[tex]v = \sqrt{ \frac{2k}{m} } \\ [/tex]

k is the kinetic energy

m is the mass

From the question we have

[tex]v = \sqrt{ \frac{2 \times 4116}{4200} } \\ = 1.4[/tex]

We have the final answer as

1.4 m/s

Hope this helps you

Answer:

The speed of the lift is 1.4 m/s

Explanation:

Kinetic Energy

Is the type of energy of an object due to its motion. It's proportional to the square of the speed and the mass.

The equation for the kinetic energy is:

[tex]\displaystyle K=\frac{1}{2}mv^2[/tex]

Where:

m = mass of the object

v = speed at which the object moves

The kinetic energy is expressed in Joules (J)

It's given the mass of the lift as m=4,200 kg and its kinetic energy K=4,116 J. To calculate the speed (magnitude of velocity), we solve the formula for v as follows:

[tex]\displaystyle v=\sqrt{\frac{2k}{m}}[/tex]

[tex]\displaystyle v=\sqrt{\frac{2*4,116}{4,200}}[/tex]

[tex]\displaystyle v=\sqrt{1.96}[/tex]

v = 1.4 m/s

The speed of the lift is 1.4 m/s

If the boy travelled 2 meters to the right and 4 meters to the left what is the total distance that he travelled?


4 m


-4 m


6 m


2 m

Answers

Answer:

6m

Explanation:

2+4=6

if i am not mistaken i think i would say 6 meters

If Minnie the Mouse starts moving at 2m/s and increases her velocity to 4m/s because she is being chased, what is heracceleration if the time is 2 seconds?

Answers

Answer:

1m/s²

Explanation:

Given parameters:

Initial velocity  = 2m/s

Final velocity  = 4m/s

Time of chase  = 2s

Unknown:

Acceleration = ?

Solution:

Acceleration is the rate of change of velocity with time;

 A = [tex]\frac{v - u }{t}[/tex]  

A is the acceleration

v is the final velocity

u is the initial velocity

t is the time taken

      A  = [tex]\frac{4 - 2}{2}[/tex]   = 1m/s²

What state of matter can easily be compressed (squeezed into a much smaller space)? *
gases
solids
solids, liquids, and gases
liquids

Answers

Answer:

gases.

Explanation:

gases have the highest volume. if you compress (increase pressure) a gas, the volume decreases and it will take up less space as a liquid, and if you compress more, the liquid will become a solid.

additionally info: this is generally true, but as you get into more difficult subjects, this rule does not hold. for example, some substances cannot obtain a certain phase of matter when they are a certain temperature and or pressure. but that could be way more out of this questions league.

please answerrr asapp tyty Laura goes for cycle from her house to the post office 4km away how long did it take for Laura to reach the post office

Answers

Answer:

See the answer below

Explanation:

The time Laura took to reach the post office would depend on the speed of cycling.

We know that;

 speed = [tex]\frac{distance}{time}[/tex]

hence,

time = [tex]\frac{distance}{speed}[/tex]

Since the distance from Laura's house to the post office is 4 km, the equation becomes;

time = [tex]\frac{4}{speed}[/tex]

Just ensure that the speed is in km per hour, minute, or seconds in order to obtain the time in hours, minutes, or seconds respectively.

Please help i will give brainliest

Answers

Answer:

Answers below--

Explanation:

1. F/Force

2.H/Contact force

3.A/Non-contact force

4.C/electric force

5.D/gravity

6.I(i)/magnetic force

7.J/kilogram

8.G/newton

9.B/friction

10.E/lubricant

Question 17 of 25
A sound wave from a brass bell passes through the air with a
wavelength of 3.5 m. When the sound wave originated in the
brass bell, its wavelength was 47 m. If the sound wave has a
constant frequency of 100 Hz, what was its speed as it
traveled through the brass bell? (The equation for wave speed
is v= f*1.)
A. 3,500 m/s
B. 4,700 m/s
C. 350 m/s
D. 470 m/s

Answers

Answer:

The speed of the wave as it travelled through the brass bell is;

B. 4,700 m/s

Explanation:

The given parameters are;

The wavelength of the sound wave produced from the brass bell, [tex]\lambda _{(air)}[/tex]  = 3.5 m

The wavelength of the wave in the brass bell, [tex]\lambda _{(brass \ bell)}[/tex]  = 47 m

The frequency of the wave in the brass bell, f = 100 Hz

The given equation for wave speed, v = f × λ

Therefore, the speed of the wave as it travelled through the brass bell, [tex]v _{(brass \ bell)}[/tex], is given as follows;

[tex]v _{(brass \ bell)}[/tex] = f × [tex]\lambda _{(brass \ bell)}[/tex] = 100 Hz × 47 m = 4,700 m/s  

The speed of the wave as it travelled through the brass bell =  [tex]v _{(brass \ bell)}[/tex] = 4,700 m/s

Answer:

B.) 4700 m/s

Explanation:

How many moons are in our solar system?

Answers

200 moons bro bro!!!!

What is the volume of a liquid in a 50 mL cup?
A. 50mL
B. 10mL
C. There is not enough information to answer this question.

Answers

Answer:

there is not enough information

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