100 points for anyone who solves this :)
Eric traveled to three cities on a single highway. The distance from his original location to the first city was 100 miles more than the distance from the first city to the second city. The distance from the second city to the third city was 10 miles less than the distance from the first city to the second city. If the distance from his original location to the first city and the distance from the second city to the third city were the same, what was the total distance Eric traveled?

Answer:

Well think about it, the key words there are more than and less than so if he traveled let's say from his house until the first city that's 100 miles for the first one and then they say that he traveled 10 miles less than the distance from the first city until the second city. The total distance is 280 because if you read the very last sentence it says that from the original distance from the first city is about 100 miles and then it says if the the distance from the second city to the third city was the same that means that the equation goes like this: (90*2)+100 and in order to get this correctly you must do P.E.M.D.A.S which is parenthesis, exponents, multiplying, dividing, adding and subtracting so there you go.  

Answer:

Well think about it, the key words there are more than and less than so if he traveled let's say from his house until the first city that's 100 miles for the first one and then they say that he traveled 10 miles less than the distance from the first city until the second city. The total distance is 280 because if you read the very last sentence it says that from the original distance from the first city is about 100 miles and then it says if the the distance from the second city to the third city was the same that means that the equation goes like this: (90*2)+100 and in order to get this correctly you must do P.E.M.D.A.S which is parenthesis, exponents, multiplying, dividing, adding and subtracting so there you go.  

Step-by-step explanation:

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Will wanted to solve the problem
468
÷
12
468
÷
12
using partial quotients.

Which of the methods could be used to find the quotient? Select all that apply.

A.
Subtract (
10
×
12
10
×
12
) from 468 to get 348. Subtract (
3
×
12
3
×
12
) from 348 to get 312. Subtract (
9
×
12
9
×
12
) from 292.

B.
Subtract (
30
×
12
30
×
12
) from 468 to get 108. Subtract (
9
×
12
9
×
12
) from 108.

C.
Subtract (
20
×
12
20
×
12
) from 468 to get 228. Subtract (
10
×
12
10
×
12
) from 228 to get 108. Subtract (
3
×
12
3
×
12
) from 108 to get 72. Subtract (
6
×
12
6
×
12
) from 72.

D.
Subtract (
30
×
12
30
×
12
) from 468 to get 108. Subtract (
4
×
12
4
×
12
) from 108 to get 60. Subtract (
4
×
12
4
×
12
) from 60.

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Plane B: y = -800t + 28,000
Plane C: y = -200t +13,500
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Container A has 1600 ml of water and is leaking 12 ml per minute.

Container B has 2000 ml and is leaking 20 ml per minute.

Let m represest the number of minutes the contains are leaking.


How many minutes, m, will it take for the two containers to have the same amount of water

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which phrase describes the solution set for this function?

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A.) two complex solutions
B.) one real solution
C.) two real solutions
D.) one real solution and one complex solution

Evaluate the expression when c=4 and d=8.
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Given f(x) and g(x) = f(x) + k, use the graph to determine the value of k.
10
9
8
7
g(x)
6
3
f(x)

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What would be the nearest thousand in this Equation 7277

Use <, > or = to compare:
55
7.874007874...