You ride your bike north for 100 m at a constant speed of 5 m/Your acceleration is…

Answers

Answer 1

Answer:

our acceleration is 0 because there is a constant speed..

a = final speed - initial speed / time

final speed = initial speed ( since speed is constant)

therefore acceleration is 0


Related Questions

2. Box A has 2x the mass of Box B. Compare the inertia of the 2 bodies.

Answers

Box A has 2x the mass of Box B so Box A has more inertia as compared to Box B.

Relationship between inertia and mass

More the mass of an object, there is more inertia of the body. Thus, if mass of two bodies is same their inertia will also be same. Hence, inertia of A and B will be same as mass of both A and B are same.

So we can conclude that Box A has 2x the mass of Box B so Box A has more inertia as compared to Box B.

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Why is there two π in the formula of a mathematical pendulum (T=2π √l/g)?

Answers

Answer:

The π is from the initial formula of period T=2π/omega

A karate expert breaks a stack of bricks with his bare hand. If the force applied is 520 newtons and the impact time is 5.0 × 10 seconds, what is the value of impulse
A.
0.26 newton seconds
B.
0.58 newton seconds
C.
1.82 newton seconds
D.
2.20 newton seconds

Answers

Maybe the question is :

A karate expert breaks a stack of bricks with his bare hand. If the force applied is 520 newtons and the impact time is [tex] \sf{5.0 \times 10^{-4}} [/tex] seconds, what is the value of impulse ?

So, the value of impulse is (A). 0.26 newton seconds.

Introduction

Hi ! Here, I will help you about the impulse. Impulse is described as a quantity which expresses the integral of the amount force respect to time. The amount of impulse will be proportional to the amount of force or time (the greater  value of the force or the value of time, the value of impuls is greater too). The relationship between impulse, force, and time is expressed in this equation :

[tex] \boxed{sf{\bold{I = F \times \Delta t}}} [/tex]

With the following condition:

I = impulse that occurs (N.s)F = force that given (N)[tex] \sf{\Delta t} [/tex] = interval of the time (s)

Problem SolvingWe know that :F = force that given = 520 N[tex] \sf{\Delta t} [/tex] = interval of the time = [tex] \sf{5.0 \times 10^{-4} \: s}[/tex]

What was asked :

I = impulse that occurs = ... N.s

Step by step :

[tex] \sf{I = F \times \Delta t} [/tex]

[tex] \sf{I = 520 \times (5.0 \times 10^{-4}} [/tex]

[tex] \sf{I = 2,600 \times 10^{-4}} [/tex]

[tex] \sf{I = 2.60 \times 10^3 \times 10^{-4}} [/tex]

[tex] \sf{I = 2.60 \times 10^{3 + (-4)}} [/tex]

[tex] \sf{I = 2.60 \times 10^{-1} = \boxed{0.26 \: N.s}} [/tex]

Conclusion :

So, the value of impulse is (A). 0.26 newton seconds

The density of lead is 30.2g/cm^3.what is the value in kilograms per meter cube?

Answers

Answer:
11300 kgm3

Hope this helps

What is refractive index?​

Answers

[tex] \huge \mathbb \red{HEY \: THERE ♡}[/tex]

Refractive Index:

The ratio of the sine of angle of incidence to the sine of angle of refraction in case of lens for light of a given colour and given pair of media is constant.

Note** It is also called Snell's Law of Refraction. [tex] \mathsf \orange{\frac{sine \: i}{sine \: r} = constant}[/tex]

[tex] \huge \mathbb\pink{HOPE \: IT \: HELPS}[/tex]

Yesterday you walked 20 meters to the right from your house to the bus stop, which took you 20 seconds. You waited at the bus stop for 1 minute before realizing you forgot your Mathematics homework at home. You ran back to your house in 5 seconds. It took you 10 seconds to find your homework, and then you ran back to the bus stop in 5 seconds just in time to catch the bus. What was your average velocity for the entire period of motion?



a.
0.2 m/s


b.
1 m/s

c.
100 m/s

d.
20 m/s

Answers

average velocity= tot displacement/total time

avg v = 20/(20+60+5+10+5)=20/100=0.2 m/s

true or false
a)we should play inside our classroom..........
b)curd is made from milk........
c) wa.........t.............​

Answers

Answer:

a) we should play inside our classroom

Explanation:

Lactose intolerance does not mean a kid is allergic to milk, but they will probably feel bad after drinking milk or eating dairy products

A toy car, with mass of 6 Kg, is pushed with a force of 10 N. If the toy car is in the grass with a coefficient of friction of 0.1 then what is the acceleration?

How far does it get pushed in 10 s?

Answers

Fy=ma

Fn-mg=ma
Fn-6(10)=6a
Fn=6a+60

Fx=ma

10-Ff=ma
10-(Fn)(0.1)=6a
0.1Fn=-6a+10
Fn=-6a+10/0.1

(substitute)
-6a+10/0.1=6a+60
-6a+10=0.6a+6
-6.6a=-4
a≈0.61m/s^2

Use Kinematics to find x in 10s

x=Vt+1/2at^2
x=0+1/2(0.61)(10)^2
x≈30.3m

I hate physics :p hope this is accurate

a boat travels 500 m down a strait river. if starts from the rest accelerates uniformly to a velocity of 5m/s. how long does this take?
PLSSSS HELPPPPP NOWWW!!!!!

Answers

Answer: 200 seconds

Explanation:
Initial Velocity = 0 m/s
Final Velocity = 5 m/s
Displacement = 500 m

Average Velocity = (Vo + Vf) / 2
(0 + 5) / 2 = 2.5

Time = Displacement / Average Velocity
Time = 500 / 2.5 = 200

2 moles of a monatomic ideal gas is placed under a piston in a cylindrical container. The piston can move freely up and down without friction and its diameter is 20 cm. A 50 kg weight i placed on the top of the piston. The initial temperature of the gas is 0°C. A. Calculate the absolute pressure in the container. B. Calculate the volume of the gas. D. Calculate the amount of work done by the gas during its expansion.​

Answers

The absolute pressure in the container when the monatomic ideal gas is placed under a piston is 1.17 × 10⁵ pa

How to calculate pressure?

The absolute pressure in the container will be:

= Po + mg/A

= 1.013 × 10⁵ + (50 × 9.8)/(π × 0.1²)

= 1.17 × 10⁵ pa

The volume of the gas will be:

= nRT/P

= 2 × 8 × 3.14 × (0 + 273)/(1.17 × 10⁵)

= 0.0388m³

The amount of work done by the gas during its expansion will be:

= 1.17 × 10⁵ × (0.053 - 0.0388)

= 1661J

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a true statement of
kinetic theory

Answers

Answer:

real kinetic theory means that kinetic energy

Question 3 of 10
Which statement describes the law of conservation of energy?
A. Energy can only change from nuclear energy to chemical energy
B. There is only one form of energy.
C. The total energy in a system can only increase.
D. When an energy transformation happens, no energy is destroyed
or created.

Answers

D. When an energy transformation happens, no energy is destroyed or created.
This is the correct answer because the law of conservation of energy is energy cannot be created nor destroyed

Answer: D

Explanation: not A because energy can also change from chemical to mechanical or nuclear to mechanical. Not B because there are many types of energy eg, mechanical, nuclear, chemical... Not C because The total energy of a system is constant(conservation of energy).

-What is the potential energy at point A?

-What is the kinetic energy at point A?

-What is the kinetic energy at point B?

-What is the potential energy at point D?

-What is the kinetic energy at point D?

Answers

Answer:

1560520156

Explanation:

Assuming there is no friction or other force involved, recall that energy is conserved in a system as long as no external force acts on the system.

Using the data from point C, we can find out that the total energy of the system is 156 because  [tex]E = K+Pe[/tex].

Since at point A the object doesn't move, it has Kinetic energy of 0, because [tex]K=\frac{1}{2} mv^2[/tex], therefore [tex]0=\frac{1}{2} m0^2[/tex]. However at point A it has maximum Potential energy, because [tex]Pe=mgh[/tex].

At point B, we can find the Kinetic energy by using [tex]E = K+Pe[/tex]. Substitute values:

[tex]156=104+K\\52=K[/tex]

At point D, the object has maximum kinetic energy and no potential energy, therefore it's the opposite of point A.

15C of charge flow through the filament of a light bulb in 22 seconds. What is the strength of the current in the filament?

Answers

Answer:

Current(I)= charge(q)/time

I=15/22

I=0.680.68A

Explanation:

Current is flow of charge per unit time. Always make sure the time is in seconds. istthe

The surface of a lake has an area of 15.5 km2. What is the area of the lake in m2?

Answers

Answer:

1.55 x 10⁷ m²

Explanation:

Unit conversion

km² → m² 1 km² = 10⁶ m²

Solving

15.5 km² = 10⁶ x 15.5 m²155 x 10⁵ m²1.55 x 10⁷ m²

Difine Ripple Factor
-,- ty!!​

Answers

Answer:

The answer is in the picture above.

Two children are playing tetherball, in which a ball at the end of a cord spins around a pole. After a really good hit, the ball makes three complete revolutions in 2.0 s. What is the angular speed of the ball?

Answers

Answer:

3 pi R / s     or   9.42 R/s    or  540 degrees/sec

Explanation:

Ball covers 2 pi radians each rotation

2 pi * 3 R / 2  s =   3 pi R / s

the angular speed of the ball is 3 pi R / s     or   9.42 R/s    or  540 degrees/sec

What is angular speed ?

Angular speed can be defined as the measures of speed of how fast the central angle of a rotating body changes with respect to time

Angular speed mainly implies how quickly the rotation of an object occur means it is described as the change in the angle of the object per unit of time.

To calculate the speed of a rotational motion the angular speed value need to be known, hence  The angular speeds formula is used to calculate the distance traveled by an object in terms of rotation and revolutions per unit of time.

The unit of angular speed of an object is radian per second and Both angular speed, angular velocity are determined by using the same formula, angular velocity is  vector quantity which describes both magnitude and direction.

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What season would Texas be having at point D?

Answers

Answer:

Almost winter so fall

Explanation:

Hope this helps! Please let me know if you want me to elaborate more or think my answer is incorrect. Brainliest would be MUCH appreciated. Have a wonderful day!

A uniformly charged insulating rod is bent into the shape of a semicircle of radius R = 5 cm. If the rod has a total charge of Q = 3.10-9C, find the magnitude and direction of the electric field at O, the center of the circle.

Answers

Hi there!

We can begin by using Coulomb's Law:

[tex]E = \frac{kq}{r^2}[/tex]

k = Coulomb's Constant (8.99 × 10⁹ Nm²/C²)

E = Electric field strength (N/C)
r = distance from point (m)

q = charge (C)

Since this is a continuous charge, we must use calculus.

We can express this as the following:
[tex]q = \lambda L[/tex]

λ = Linear charge density (C/m)

L = Length of rod (m)

Now, since this is an arc, L = s (arc length). Additionally, we must find the differential elements of each:
[tex]dq = \lambda ds\\\\dq = \lambda rd\theta[/tex]

Our new equation is:
[tex]dE = \frac{kdq}{r^2}\\\\dE = \frac{k\lambda rd\theta}{r^2}[/tex]

However, we will only take the cosine component of the electric field since the vertical components will cancel out. (Electric fields are a vector). Therefore:
[tex]dE = \frac{k\lambda rd\theta}{r^2}cos\theta\\\\dE = \frac{k\lambda}{r}cos\theta d\theta[/tex]

Integrate. For a semicircle, the bounds will be from -π/2 to π/2.

[tex]E = \frac{k\lambda}{r}\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}}} {cos\theta} \, d\theta\\\\E = \frac{k\lambda}{r}sin\theta\left \|{\frac{\pi}{2}} \atop {-\frac{\pi}{2}}} \right. \\\\E = \frac{k\lambda}{r}(1 - (-1)) = \frac{2k\lambda}{r}[/tex]

We need to solve for λ, which is Q/ L:
[tex]\lambda = \frac{3.10 \times 10^{-9} C}{\pi (0.05)} = 1.9735 \times 10^{-8} \frac{C}{m}[/tex]

Now, plug and solve for the electric field strength:
[tex]E = \frac{2(8.99\times 10^9)(1.9735\times 10^{-8})}{0.05} = \boxed{7096.783 \frac{N}{C}}[/tex]

**A diagram was not provided, but if the hemisphere's focus was to the right, the electric field would be to the right, and etcetera.

A 75-W light bulb is turned on. It has an operating voltage of 120 V. (A)How much current flows through the bulb? (B)What is the resistance of the bulb? (C)How much energy is used each second?

Answers

Required Answer:

Given:

Power (P) = 75 W Voltage (V) = 120 V

(A)

As we know that,

I = P/V

↠ Current = 75/120

↠ Current = 0.625 A

(B)

R = V/I

Here,

R is resistanceV is Voltage, and I is current

↠ Resistance = 120/0.625

↠ Resistance = 192 Ω

(C)

Energy = P × t

Here,

P is power T is time

↠ Energy = 75 × 1

↠ Energy = 75 J

If electromagnetic radiation acted like particles in the double-slit experiment, what would be observed? (1 point)

O A series of light and dark bands would appear on the screen.

O Two bright bands would appear on the screen in line with the slits.

O The screen would remain dark because no radiation would reach the screen.

O One bright band would appear in the center of the screen.

Answers

If electromagnetic radiation acted like particles in the double-slit experiment, we would observe one bright band would appear in the center of the screen.

Bahavior of particles in double-slit experiment

In a double-slit experiment, single particles, such as photons, pass one at a time through a screen containing two slits.

The photons behave like wave and the constructive interfernce of the waves of these photons will generate a high amplitude wave seen as a bright band in the center of the screen.

Thus, if electromagnetic radiation acted like particles in the double-slit experiment, we would observe one bright band would appear in the center of the screen.

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Spring
The pulling force acting on an object is 350.0 N. It also is being affected by a 50.0 N
kinetic friction force. As a result, its acceleration is 3.0 m/s?, what is its mass?
A. 67 kg
B. 83 kg
C. 100 kg
D. 600 kg
E. 0.0 kg
If the gravitational force of the Farth nulling you"down" in th

Answers

Answer:

100 kg

Explanation:

Net force = 350 - 50 = 300 N

F= ma

300 N  = m * 3 m/s^2

100 kg = mass

Conceptual Example 14 provides useful background for this problem. A playground carousel is free to rotate about its center on frictionless bearings, and air resistance is negligible. The carousel itself (without riders) has a moment of inertia of 105 kg·m2. When one person is standing at a distance of 1.57 m from the center, the carousel has an angular velocity of 0.512 rad/s. However, as this person moves inward to a point located 0.507 m from the center, the angular velocity increases to 0.795 rad/s. What is the person's mass?

Answers

For one person standing at a distance of 1.57 m from the center, the carousel has an angular velocity of 0.512 rad/s, the person's mass  is mathematically given as

m = 24.2 kg

What is the person's mass?

Generally, the equation for the conservation  angular momentum  is mathematically given as

(I + m * r0^2) * w0 = (I + m * r^2) * w^2

Therefore

(105 + m * 1.78^2) * 0.517 = (105 + m * 0.524^2) * 0.841

m = 24.2 kg

In conclusion, the mass  

m = 24.2 kg

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A man is pushing a large box with a force of 44 newtons. He slides over a floor that has a sliding frictional force of 12 Newtons. What is the acceleration?

Answers

I’m sorry I was not texting lol but 12 subduing and I got a phone call back to you later on for your birthday 17 wyd

give an example of the 4 steps of the scientific method

Answers

Answer:

1) asking a question about something you observe, 2) doing background research to learn what is already known about the topic, 3) constructing a hypothesis, 4) experimenting to test the hypothesis

Answer:

1) make an observation that describes a problem - see something you can fix or improve and try to describe the problem like which type of vegetables does rabbit like

2) create a hypothesis - What do you think will happen - If the rabbit eat the lettuce than .........

3) test the hypothesis - Do your experiment with the variables and follow the procedures

4) draw conclusions and refine the hypothesis - see if your hypothesis was correct - In conclusion my hypothesis was not correct because.......

Mrs. dela Vega had 27 students in her class last year and this year she had 30 students in her math class. What is the percent of difference?

Answers

The class grew by (30-27) = 3 students.

3 is (3/27) = 1/9 of its original size.

The class grew by 1/9 or 11.1 % .

(a) In Coulomb scattering of 7.50-MeV protons by a target of 'Li, what is the energy of the elastically scattered protons at 90°? (b) What is the energy of the inelastically scattered protons at 90° when the 'Li is left in its first excited state (0.477 MeV)?

Answers

Answer:

First the charge is given 7.50×10^-6

Explanation:

so that we have

[tex]90 [/tex]

so that their is no cross sectional area of this angle

then the direction is one is left and other one is right so thats my hint

What is the magnetic flux going through a coil with 0.065 m2 area if the intensity of the magnetic field is 0.114 T.

Answers

Hi there!

[tex]\Phi _B = \int B \cdot dA[/tex]

φ = Magnetic Flux (Wb or Tm²)
B = Magnetic field strength (T)
A = Area (m²)

This equation includes a dot product, so this can be rewritten as:

[tex]\Phi _B = B A cos\theta[/tex]

In this instance, the field is parallel to the area, so cos(0) = 1.

Calculate the magnetic flux by plugging in the given values.

[tex]\Phi _B = BA = 0.114 * 0.065 = \boxed{0.00741 Wb}[/tex]

What are the essential components of successfully competing in the field events:


Power, technique, and timing


Power, speed, and strength


Technique, flexibility, and speed


None of the above

Answers

Answer:

Power, technique, and timing

Explanation:

I just did the quiz and it was correct!! Hope this helps!

A single coil of wire, with a radius of 0.13 m is rotated in a uniform magnetic field such that the angle between the field vector and the area vector obeys θ=ωt. If the strength of the field is 3.746 T, and the angular frequency is 524.7 rad/s, what is the induced emf in the loop at t=1.16 s?

Answers

The magnitude of emf induced in the single coil of wire rotated in the uniform magnetic field is 0.171 V.


Induced emf

The emf induced in the loop is determined by applying Faraday's law of electromagnetic induction.

emf = N(dФ/dt)

where;

N is number of turns of the wireФ is magnetic flux

Ф = BA

where;

B is magnetic field strengthA is the area of the loop

emf = NBA/t

A = πr²

A = π x (0.13)²

A = 0.053 m²

emf = NBA/t

emf = (1 x 3.746 x 0.053)/(1.16)

emf = 0.171 V

Thus, the magnitude of emf induced in the single coil of wire is 0.171 V.

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Government requires that cigarette manufacturers include on cigarette packages awarning from the surgeon general that smoking causes diseases such as lung cancer Jordan is making a scale model of the Hanging Gardens of Babylon, one of the seven wonders of the ancient world. The actual gardens were said to be 24.4 meters tall. Jordan uses a scale of 1 cm = 0.5 m.To the nearest tenth of a centimeter, what should be the height of Jordans model?A. 12.2 cmB. 24.4 cmC. 48.8 cmD. 122.0 cm