You have 723 ml of 3.99 M HCl. Using a volumetric pipet, you take 326 ml of that solution and dilute it to 976 ml in a volumetric flask. Now you take 100.00 ml of that solution and dilute it to 119 ml in a volumetric flask. What is the concentration of hydrochloric acid in the final solution

Answer:

72.04g Ti and 7.75g Na

Explanation:

1.505 mol Ti x (47.87g/1 mol) = 72.04g Ti

0.337 mol Na x (22.99g/1 mol) = 7.75g Na

72.04g Ti and 7.75g Na mass in grams of these samples.

Molecular mass can be determined by the measure of mass related to a molecule which is otherwise called as atomic weight, means the mass of every atom present in the molecule.

For example, water have 2 hydrogen atoms and 1 oxygen atom, the molecular mass of water is equals to  the normal atomic mass of hydrogen increased by two or more the atomic mass of oxygen.

molecular mass can be controlled by many factors like Mass Spectrometry which is used to decide the mass of little molecule which is otherwise called as monoisotopic mass.

It can also be controlled by Hydrodynamic Strategy requires calibration and  determine the relative atomic weight; Static Light Scattering where the  Molecular weight is determined from the measure of light dispersed utilizing the Zimm technique.

So, 1.505 mol Ti x (47.87g/1 mol) = 72.04g Ti

0.337 mol Na x (22.99g/1 mol) = 7.75g Na, hence the answer is 72.04g Ti and 7.75g Na

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a. acceleration

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Answer:

Psol = 433 torr

The solution is not ideal and the solution deviates from Raoult's law in a positive manner

Explanation:

The vapout pressure of a solution can be obtained using Raoult's law:

Psol = P°A* XA + P°B*XB

Where Psol is vapour pressure of solution

P° is vapour pressure of pure substance

X is mole fraction

As we have vapour pressure of pure carbon disulfide and acetone we need to find mole fraction of each compound to solve the vapour pressure of the solution:

Moles carbon disulfide:

3.95g CS₂ * (1mol / 76.13g) = 0.05188 moles

Moles acetone:

2.43g acetone * (1mol / 58.08g) = 0.04184 moles

Mole fraction of CS₂:

0.05188 moles / (0.05188mol + 0.04184mol) =

0.5536

Mole fraction acetone:

1 = X(CS₂) + X(Acetone)

X(Acetone) = 1 - 0.5536 = 0.4464

Solving for vapour pressure of the solution:

Psol = 515torr*0.5536 + 332torr*0.4464

As the experimental vapor pressure was 645torr > 433 torr (Theoretical vapor pressure), the solution is not ideal and the solution deviates from Raoult's law in a positive manner

Answer:

Explanation:

# moles that exist in 1.9 X 10 23 =

             =  # of atoms/# of Avogadro 's num

             =    1.9 X 10 23 / 6.02x10 23

              = 0.266 mole of Pb

now we calculate the mass

   mass of lead = # mol x m.wt

                       =    0.266 X 106.4

                       = 28.30 gram

Explanation:

Sometimes, a solution contains more dissolved solute than is normally possible. This type of solution is said to be supersaturated. A saturated solution can become supersaturated if more solute is added while the temperature is raised.

hope it will help u ✌️

Answer:

yes, they were

Explanation:

The history of the metric system began in the Age of Enlightenment with notions of length and weighttaken from natural ones, and decimal multiples and fractions of them. The system became the standard of France and Europe in half a century. Other dimensions with unity ratios[Note 1] were added, and it went on to be adopted by the world.

Answer:

Idk

Explanation:

Find the gallons needed by dividing total miles by miles per gallon:

4700/41 = 114.634 gallons

Multiply the gallons needed by price per gallon:

114.634 x 2.79 = $319.83 Total

Round the answer as needed.

If gallons were rounded to 115 gallons total cost would be $320.85

$ 434.40

41 miles ............ 1 gallon

4700 miles .......x gallon

x = 4700×1/41 = 114.63 gallons

114.63 gallons×$3.79 ≈  $ 434.40

Factors that raise pH in a swimming pool. 1. Natural pH Rise: Carbon Dioxide Loss. The chemistry of pH sounds a lot more complicated than it is. In short, the less CO 2 in solution, the ... 2. Sanitizers and their pH Impact. 3. pH and alkalinity adjustment chemicals.

Answer:

(a) 0.779 mol Cr₂O₃

(b) 118 g Cr₂O₃

Explanation:

Step 1: Convert 156 g Cr₂S₃ to moles

Cr Molar Mass - 52.00 g/mol × 2 = 104.00 g/mol

S Molar Mass - 32.07 g/mol × 3 = 96.21 g/mol

156 g Cr₂S₃ ÷ 200.21 g/mol = 0.779182 mol Cr₂S₃

Step 2: Find conversion from Cr₂S₃ to Cr₂O₃

1 mol Cr₂S₃ equals 1 mol Cr₂O₃

Step 3: Use Dimensional Analysis

0.779182 mol Cr₂S₃ · [tex]\frac{1 \hspace{2} mol \hspace{2} Cr_2O_3}{1 \hspace{2} mol \hspace{2} Cr_2S_3}[/tex] = 0.779182 mol Cr₂O₃

0.779182 mol Cr₂O₃ ≈ 0.779 mol Cr₂O₃ (3 significant figures)

Step 4: Convert moles to grams

Cr Molar Mass - 52.00 g/mol × 2 = 104.00 g/mol

O Molar Mass - 16.00 g/mol × 3 = 48.00 g/mol

0.779182 mol Cr₂O₃ · 152.00 g/mol = 118.436 g Cr₂O₃

118.436 g Cr₂O₃ ≈ 118 g Cr₂O₃ (3 significant figures)

Answer:

36690

Explanation:

Answer:

The equilibrium will shift to the right producing more Ag⁺ and CO₃²⁻

Explanation:

In the equilibrium:

Ag₂CO₃(s) ⇄ 2Ag⁺(aq) + CO₃²⁻(aq)

The change in concentration of Ag⁺ or CO₃²⁻ will shift the equilibrium

The addition of HCl(aq) (Dissociates in H⁺ and Cl⁻ ions) produce the formation of AgCl. The reaction is:

Ag⁺(aq) + Cl⁻(aq) ⇄ AgCl(s)

That means the addition of HCl decrease concentration of Ag⁺.

Based on LeChatelier's principle: As the Ag⁺ decreases, the equilibrium will decrease amount of Ag₂CO₃ producing more Ag⁺ and CO₃²⁻. That is:

Answer:

It means the chemical entity is a radical

Explanation:

When we talk of unsaturation, we are referring to the number of pi-bonds in a chemical entity. The alkane, alkene and alkyne organic family are used to as common examples to explain the term unsaturation.

While alkynes have 3 bonds, it must be understood that they have 2 pi bonds only and as such their degree of saturation is two.

In the case of an alkene, there is only one single pi bond and as such the degree of unsaturation is 1.

Now in this case, we have a fractional 0.5 degree of unsaturation alongside the 3 to make a total of 3.5. So what’s the issue here?

The fractional part shows that the chemical entity we are dealing with here is a radical. While the integer 3 shows that there are 3 pi-bonds, the half pi bond remaining tells us that there is a missing electron on one of the atoms involved in the chemical bonding and as such, the 1/2 extra degree of unsaturation tends to tell us this.

Kindly recall that a radical is a chemical entity within which we have at the least an unpaired electron.

"Is the Moon's gravitational force affecting the tides on Earth?"

A substance that cannot be converted into another substance is known as an element. Each type of atom that makes up an element is unique. The correct option is A.

A substance whose atoms all contain the same number of protons is said to constitute an element; alternatively, all the atoms of a certain element must contain the same number of protons. Chemical reactions cannot degrade elements since they are the simplest chemical forms.

A compound is created when two or more components join chemically in a predetermined mass ratio.

Thus the correct option is A.

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Answer:

See the answer

1) 15.0 g of water is heated from 5 °C up to 37 °C. How much energy is absorbed by the water? (The specific heat of liquid water is 4.184 J/g°C.)

2)How many joules of energy is required to bring a five-pound (1 pound = 454 g) bag of ice from its freezer temperature at -20.0°C up to 0°C? The specific heat of ice is 2.10 J/g×°C.

3) A 50.0 mg tissue sample is taken from a patient for diagnosis. While waiting for testing, the sample is stored in a -80.0°C freezer. How much energy is released when the sample is cooled from 20.0°C down to the freezer temperature? You may assume the specific heat of the tissue sample is 3.47 J/g×K.

It would be volume.

Volume is not an intensive property because it does change as the amount of substance increases or decreases. The rest of the properties are constant no matter the amount of substance.

Answer:

Volume

Look at the guy above me, okay-- they're smarter then me-

Answer:

Yes, it is possible.

Explanation:

A diprotic acid is an acid that can release two protons. That's why it is called diprotic.

Monoprotic → Release one proton, for example Formic acid HCOOH

Triprotic → Releases three protons, for example H₃PO₄

Polyprotic → Release many protons, for example EDTA

it is a weak acid.

In the first equilibrum, it release proton, and the second is released in the second equilibrium. So the first equilibrium will have a Ka1

H₂A  +  H₂O  ⇄  H₃O⁺  +  HA⁻                Ka₁

HA⁻  +  H₂O  ⇄  H₃O⁺  +  A⁻²               Ka₂

The HA⁻ will work as an amphoterous because, it can be a base or an acid, according to this:

HA⁻   +  H₂O  ⇄  H₃O⁺   + A⁻²      Ka₂

HA⁻   +  H₂O  ⇄  OH⁻   + H₂A       Kb₂

Answer:

Explanation:

silicon has highest ionization energy ionization energy increases from left to right in a period because electron are added to same shell and increase in added electron shield each other poorly from the nuclear attraction

Explanation:

27 °0 bc that how it is so this is the answer

Answer:

[tex]m=173.58g[/tex]

Explanation:

Hello,

In this case, since the density is the ratio of the mass and volume:

[tex]\rho =\frac{m}{V}[/tex]

For the given density and volume, the correct mass which fills the given volume is:

[tex]m=\rho *V=0.789g/mL*220mL\\\\m=173.58g[/tex]

Best regards.

Answer:

C) cation, loses, anion, gains

Explanation:

Lithium is a metal from Group 1, so it has 1 valence electron. Thus, it loses 1 electron to complete its octet and form the cation Li⁺.

Oxygen is a nonmetal from Group 16, so it has 6 valence electrons. Thus, it gains 2 electrons to complete its octet and form the anion O²⁻.

In the reaction between Li and O, there is a transfer of electrons making an ionic bond. In the bond, lithium would be a cation because it loses an electron, and oxygen would be an anion because it gains 2 electrons.

Answer:brainly

Explanation:

absolutely brainly

full of help and knowledge

Answer:

a. 2-heptanone is more reactive than 4-heptanone

b. chloromethyl phenyl ketone is more reactive than bromomethyl phenyl ketone

Explanation:

The reactivity of the carbonyl compound (ketone ) is affected by the steric effect. The steric effect is a hindrance that occurs in the structure or reactivity of a molecule, which is affected by the physical size and the proximity of the adjacent parts of the molecule.

Between 2-heptanone or 4-heptanone, 2-heptanone is more reactive than 4-heptanone. This is because 2-heptanone is less affected by the steric hindrance, unlike the 4-heptanone.

Similarly, the reactivity of the carbonyl compound (ketone) is also affected by the polarity on the carbon compound, which is associated with how electronegative the substituent attached is to the carbonyl compound. From the periodic table, the electronegativity of the Halogen family decreases down the group. Therefore chlorine is more electronegative than bromine.

As such, chloromethyl phenyl ketone is more reactive than bromomethyl phenyl ketone.

Answer:

a) YES ( Basis : F=100kg/h)

b) composition mass fraction in the bottom stream

(Xm)B = 0.25

(Xp)B = 0.1

(Xw)B = 0.65

Explanation:

a)

Can you set a basis of calculation in this problem? Why or why not?

Yes we can set a basis if calculation in this problem.

A good basis makes the calculation more easier. the problem are given in weight  basis so we can choose basis of feed rate of 100kg/h

BASIS : 100kg/h

b)

given that;

mass flow rate of M in the feeds Mf = 0.55*F = 0.55*100 = 55kg/h

mass flow rate of p in the feeds Pf = 0.05*F = 0.05*100 = 5kg/h

mass flow rate of W in the feeds Pf = 0.40*F = 0.40*100 = 40kg/h

Now Balance

F = T + B

( but T=B)

so F = T + T = 2T

B = T = 50kg/h

TOP

mass flow rate of M in the top Mt = 0.85*T = 0.85*50 = 42.5 KG/H

mass flow rate of P in the top Pt = 0kg/h

mass flow rate of W in the top Wt = 0.15*T = 0.15*50 = 7.5kg/h

balance on M

Mf = Mt + Mb

Mb = Mf - Mt = 55kg/h - 42.5kg/h = 12.5kg/h

Balance on P

Pf = Pb + Pt

Pb = Pf - Pt = 5kg/h - 0kg/h = 5kg/h

Balance on W

Wf = Wt + Wb

Wb = Wf - Wt = 40kg/h - 7.5kg/h = 32.5kg/h

So bottom composition

mass fraction of M in Bottom XmB = Mb/B = (12.5kg/g) / (50kg/h) = 0.25

mass fraction of P in Bottom XpB = Pb/B = (5kg/g) / (50kg/h) = 0.1

mass fraction of W in Bottom XwB = Wb/B = (32.5kg/g) / (50kg/h) = 0.65

Answer:

no it cant

Explanation:

The SI unit of temperature is the kelvin (K), which spans the same temperature change as the degree Celsius. The Kelvin scale is a thermodynamic scale, meaning that its zero point is at absolute zero rather than the freezing point of water. The second reference point for this scale as it is currently defined is the triple point of water, which is a unique point on the phase diagram of water (a specific combination of pressure and temperature) where ice, liquid water and water vapor are all in equilibrium. The triple point is assigned the temperature of 273.16 K.

The old centigrade scale used the freezing and boiling temperatures of water as its reference points, with one degree centigrade equal to 1/100 of the temperature span between the freezing and boiling points of water. The definition of the Kelvin scale was chosen to make the kelvin the same size as the centigrade degree.

The Celsius scale is defined in terms of the Kelvin scale but is equivalent to the old centigrade scale, which it replaces. It is convenient for reporting weather and cooking temperatures and so on, but is not particularly useful for scientific purposes. For instance, the behavior of gases which approximate ideal gases is such that at zero degrees C they experience a volume change of 1/273 for a one degree change in temperature. This observation provided one of the first indications for the value of absolute zero.

When using the ideal gas law:

PV = nRT

where P is pressure

V is volume

n is the quantity of gas in moles

R is a constant

T is the temperature

it is necessary to use a thermodynamic scale, usually Kelvin.

Another thermodynamic scale, the Rankine scale, has a relationship to the Fahrenheit temperature scale analogous to that between the Kelvin and Celsius scales.