Yo I need to bring up my math grade bad so
4x-5y>20
(please show it graphed already, and step by step, NO LINKS

Answer:

Step-by-step explanation:

[tex]Sin \ 23^ \circ = \dfrac{opposite \ side}{hypotenuse}\\\\[/tex]

[tex]\sf 0.3907 = \dfrac{ x}{7}\\\\\\0.3907*7 =x[/tex]

x = 2.7

Answer:

x = 2.7  to nearest tenth.

Step-by-step explanation:

sin 23 = x / 7

x = 7 sin 23

x = 2.735

Answer:

-a^2-a+12

Step-by-step explanation:

Answer:

Option C.

[tex]-a^{2}-a+12[/tex]

Step-by-step explanation:

1.  Distributive multiply

[tex]-a*(a+4)+3*(a+4)[/tex]

2.  Distributive multiply

[tex]-a*a-a*4+3*(a+4)[/tex]

3.  Multiply terms to exponential form

[tex](-1) *a^{2}-a*4+3*(a+4)[/tex]

4.  Multiply constants

[tex]-a^{2}-4*a+3*(a+4)[/tex]

5.  Distributive multiply

[tex]-a^{2}-4a+(3*a+3*4)[/tex]

6.  Multiply constants

[tex]-a^{2}-4a+(3a+12)[/tex]

7.  Reorder terms

[tex]-a^{2} -4a+(12+3a)[/tex]

8.  Add terms

[tex]-a^{2}-a+12[/tex]

Answer: 25

Step-by-step explanation:

As both left side is same

There is no solutions .

Answer:

no solutions

Step-by-step explanation:

Given equations:

Rewrite the given equations to make y the subject:

Equation 1

[tex]-x+y=8[/tex]

[tex]\implies y=x+8[/tex]

Equation 2

[tex]2x-2y=-14[/tex]

[tex]\implies 2y=2x+14[/tex]

[tex]\implies y=x+7[/tex]

Slope-intercept form of a linear equation:  [tex]y=mx+b[/tex]

(where m is the slope and b is the y-intercept)

As both equations have the same slope, the lines are parallel and therefore there is no solution to the system of equations as the lines do not intersect.

Answer:

3(x+z+y)=k

Step-by-step explanation:

Answer:

8.09

rounded to the nearest tenth ; 8.1

Step-by-step explanation:

Mean is adding all the data together than dividing by the number of data points

7.9 + 7.8 =

15.7 + 7.7 =

23.4 + 8.8 =

32.2 + 9.2 =

41.4 + 8.7 =

50.1 + 7.3 =

57.4 + 8.0 =

65.4 + 7.9 =

73.3 + 7.6 =

80.9

80.9 / 10 = 8.09

rounded to the nearest tenth = 8.1

Option (4) all real numbers greater than or equal to -3

Step-by-step explanation:

Domain: Domain of function is defined by the x-values (Input values) on the graph.

Range: Range of a function is defined by the y-values (output values) on the graph.

x-values are starting from (-3) to infinity.

Therefore, domain of the function will be all real numbers greater than equal to (-3). Option (4) will be the answer.

The domain of the function are all real numbers greater than or equal to -3.

A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.

Given is a graph, we need to find domain of the function on the graph,

Domain is the set of all possible inputs or x-values, for which the given function is defined.

The given graph is defined form -3 to positive infinity. The point -3 included in the set of input because there is a closed circle at x=-3.

So, domain of the function are all real numbers greater than or equal to –3.

Hence, the domain of the function are all real numbers greater than or equal to -3.

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Answer:

0.75 feet

Step-by-step explanation:

Let's picture a right triangle, where :

Let the height of the ladder be x.

Answer:

0.748 ft (nearest thousandth)

Step-by-step explanation:

Use the tan trig ratio:

[tex]\tan(\theta)=\dfrac{O}{A}[/tex]

where:

Given:

[tex]\implies \tan(14)=\dfrac{x}{3}[/tex]

[tex]\implies x=3\tan(14)[/tex]

[tex]\implies x=0.7479840085...[/tex]

Therefore, the ladder reaches up the wall 0.748 ft (nearest thousandth)

Ratios are written as fractions or in the form a:b.  The  pump should be programmed to deliver 133mL/hr

Ratios are written as fractions or in the form a:b.

According to the question, An IV piggyback (IVPB) of 10,000 units/100 mL is to be given over 45 minutes.

We are to determine the number of mL to be given in 60 minutes (1 hr)

100mL = 45 minutes

x mL = 60 minutes

Take the ratio

100/x = 45/60

Cross multiply

45x = 6000

x = 6000/45
x = 133mL/hr

Hence the  pump should be programmed to deliver 133mL/hr

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One of the strategies that would eliminate a variable in the system of equations is by subtracting both equations to eliminate the variable "x"

System of equations consists of a different set of equations with unknown variables.

Given the system of equations

2x+3y=-5

2x-3y=10

Since the coefficient of x from both equations are the same, we will subtract both equations to eliminate the variable "x"

(2x-2x)+(3y+3y) = -5 + 10
6y  = 5

Hence we can conclude that one of the strategies that would eliminate a variable in the system of equations is by subtracting both equations to eliminate the variable "x"

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Answer:

x = 8, y = 6/√3.

Step-by-step explanation:

The smaller triangle and the larger triangle are similar.

4 / 4√3 = (x - 6) / y

1/√3  =  (x - 6) / y

Also

y/6 = 1/√3

⇒ √3y = 6

⇒ y = 6/√3

Substitute for y in the first equation:

1/√3  =  (x - 6) / 6/√3

⇒ 1/√3 * 6/√3 = x - 6

⇒ x - 6 = 2

⇒ x = 8

Answer:

Part A

Let d = number of dogs

Let c = number of cats

Given:

⇒ d + c = 165

Given:

⇒ c = 2d - 24

Part B

Substitute  c = 2d - 24  into  d + c = 165  and solve for d:

⇒ d + 2d - 24 = 165

⇒ 3d - 24 = 165

⇒ 3d = 189

⇒ d = 63

Substitute found value of d into  d + c = 165  and solve for c:

⇒ 63 + c = 165

⇒ c = 102

Therefore, 63 dogs and 102 cats are adopted in the shelter.

Answer:

5

Step-by-step explanation:

Simplification:

[tex]\sqrt{2^3-7} + |-4|[/tex]

[tex]\sqrt{1} + 4[/tex]

1 + 4

5

Answer:

Step-by-step explanation:

The student used the commutative property of addtion on the right hand side, which is correct because reordering the addends doesn't affect the value of the expression.

The student used additive commutative property for the first step.

According to this property, when two numbers or integers are added, the sum remains the same even if we change the order of numbers/integers. This property is also applicable in the case of multiplication. It can be represented as; a + b = b + a.

The student used a + b = b + a

3a + b = 2 + 7 - 5a = 2 - 5a + 7

Because add two numbers, exchange the position of the addend, and sum of them remain same.

This is a additive commutative property.

Hence, the student used additive commutative property for the first step.

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Answer:

[tex]x= \dfrac 45[/tex]

Step by step explanation:

[tex]-2(20x+2) = -36\\\\\implies 20x +2 = \dfrac{-36}{-2} = 18\\\\\implies 20x = 18 - 2=16\\\\\implies x = \dfrac{16}{20}=\dfrac{4}5[/tex]

Answer:

2.924

Step-by-step explanation:

First you'll solve the parenthesis:

...- (5.5-5.5)

...-(0)

Now solve the equation:

[tex]\sqrt[3]{5^{2} - 0}[/tex]

[tex]\sqrt[3]{25}[/tex]

Now solve fully

I hope this helps :)

Answer:

the answer is 3 times the square root of 27

Step-by-step explanation:

Answer: ✨So I divided. 120 by 15 and got 8. I then multiplied it by 20 and got 160 bouquets✨

Step-by-step explanation: Still stuck? Get 1-on-1 help from an expert tutor now.

Answer:

The shaded region of A is 12.5% of the area of B.

Step-by-step explanation:

Although the side of square A is 50% of the side of square B, if you think about things logically here square A is only 25%of square B. Therefore the shaded area HAS to be half of 25% making the answer 12.5%

Answer:

12.5%

Step-by-step explanation:

Since it given that the length of the sie of a square A is 50% of the  length of the side of square B. As well as given us the question we need to find the answer to which is:

Express the area of the shaded region of square A as a percentage of the area of square B.

What we need:

Area of shaded region of Square A as a % of Area of Square B

Now we can solve but first :

Let "b" be the side length of Square B

Let "a" be the side length of Square A

As well as:

It given side length of Square A (a) = 50% (1/2) of side length of Square B (b), therefore we have,

a = ½b

Area of a square = s², where s is the  side length

Area of Square A = (½b)² = b²/4

Area of Square B = b²

Finding the area of the shaded region of the Square A = ½ of area of Square A.

Area of shaded region of Square A = ½*(b²/4) = b²/8

Expressing the area of the shaded portion of square A as a percentage of are of Square B:

Area of shaded portion of Square A ÷ Area of Square B × 100%

Solving:

⇒ [tex]\frac{\frac{b^2}{8}}{b^2}\times100[/tex]

⇒[tex]\frac{b^2}{8}\times\frac{1}{b^2}\times100[/tex]

⇒ [tex]\frac{b^2\times1}{8\timesb^2}\times100[/tex]

⇒ [tex]\frac{b^2}{8\times b^2}\times100[/tex]

⇒ [tex]\frac{1}{8}\times100=12.5[/tex]

Base on the solving above we can conclude that:

The area of the shaded region of Square A is 12.5% of the area of Square B.

~[DiscordUser]~

The statute generates statistical data that is generally cited to support findings is the Truth in Lending Act.

It should be noted that a statistical data simply means factual information that are recorded for analysis purpose.

In this case, the statute generates statistical data that is generally cited to support findings is the Truth in Lending Act. It helps protect unfair credit billing and card practices.

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Step-by-step explanation:

Displacement = 576 m

Time taken = 32s

Now

[tex]average \: speed = \frac{distance \: travelled}{time \: taken} \\ = \frac{576}{32} \\ = 18 m/s[/tex]

Answer:

18.1

Step-by-step explanation:

All radii of a circle are congruent (same length), which means if we draw in a radius from the center to the end of the 16.3, it would be the same length of x.

Now we can use sa very simple theorem.... the pythagorean therom!

[tex]7.9^{2} + 16.3^{2} = x^{2} \\62.41 + 265.69 = x^{2} \\328.1 = x^{2} \\18.1 = x[/tex](rounded)

I hope this helps you.

Answer:

From what I can actually read:

Step-by-step explanation:

289 x 76= 21946

25 x 68= 1700

36 x 75= 2700

200 x 60= 12000

200 x 70= 14000

683 x 18= 12294

548 x 63= 34524

629 x 8= 5032

529 x 37= 19537

548 x 63= 34524

100 x 10= 1000

551 x 64= 35264

456 x 12= 5472

42 x 8= 336

68 x 14= 952

And it dosen't matter if you have a multi- numberd equation, because either way you can use a calculator to do the math. and a trick for multiplying by 10 or 100 or 1000: is lets say you have 5 x 1000, instead of doing any math just multiply 1 x 5= 5 then add 3 zero's because 1000 has 3 zeros. You can do this with any number like 10,100,1000,10000 ; you could go on forever.

Answer:

(0,0)

Step-by-step explanation:

x value of vertex = -b/2a

ax^2+bx+c

-2x^2+0x+0 sinc you have no value of b & c in your quadratic function

-b = 0

2a = (2)(-2)

-b/2a = (0/-4) = 0

x value of the vertex = 0

plug 0 in for all values of x in the function to find y coordinate value

-2(0)^2 = 0

(x,y) = (0,0)

Answer:

Sample Space = {(ABC), (ACB), (BAC), (BCA), (CAB), (CBA)}

= 6

Instances when A is besides C {(ACB),( BAC),( BCA), ( CAB)}

=4

P( A is besides C)= 4/6

Answer:

53 units

Step-by-step explanation:

Let [tex](x_1,y_1)\rightarrow(8,3)[/tex] and [tex](x_2,y_2)\rightarrow(53,31)[/tex] to use the distance formula:

[tex]d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\\\d=\sqrt{(31-3)^2+(53-8)^2}\\\\d=\sqrt{(28)^2+(45)^2}\\\\d=\sqrt{784+2025}\\\\d=\sqrt{2809}\\\\d=53[/tex]

Thus, the distance between the two points is 53 units

Answer:

5/7.

Step-by-step explanation:

The rise = 5 and the corresponding run si 7.

Answer:

5/7

Step-by-step explanation:

so we start at the point (0,0). the slope is essentially

Rise/Run

so in this graph we see a point of (7,5)

the rise was 5 along the y axis and the run was 7 along the x axis.

so 5/7 is correct

Answer:

6a=42

Step-by-step explanation:

This equation would be used to find a because we don't know how many assists are for each match. And multiplying the a by the 6 games would be equivalent to 42 assists for the entire match.