Work out the number of boys and girls in the class.
in class 8m, there are 27 pupils. there are twice as many boys as girls. find the number of boys and girls

Answer: 0.0139358  

Step-by-step explanation: 999,999,999,999,999,999,999,999,999,999,999% sure!

x=37.5

if you need an explanation i can type it in the comments

Answer:

10:48 pm will be your answer

Function: y = 5 sin (2(x))+ 12

Find y-intercept:

y = 5 sin 2(0)+ 12

y = 12

​[tex]\sf Y\:Intercepts}:\:\left(0,\:12\right)[/tex]

→ Formula for maximum: M = A + |B|

Maximum:

12 + |5|

17

When y = 17

[tex]\rightarrow \sf 17 = 5 sin (2(x))+ 12[/tex]

[tex]\rightarrow \sf \sf 5 sin (2(x)) = 5[/tex]

[tex]\rightarrow \sf sin (2(x)) = 1[/tex]

[tex]\rightarrow \sf 2x = sin^{-1}(1)[/tex]

[tex]\rightarrow \sf 2x = 90^{\circ \:}, \ \ 450^{\circ \:}[/tex]

[tex]\rightarrow \sf x = 45^{\circ \:}, \ \ 225^{\circ \:}[/tex]

maximum: ( 45° , 17 ), (225° , 17), .....

==========================================================

→  Formula for minimum: m = A ‐ |B|

Minimum:

12 - |5|

7

When y = 7

[tex]\rightarrow \sf 7 = 5 sin (2(x))+ 12[/tex]

[tex]\rightarrow \sf 5 sin (2(x)) = -5[/tex]

[tex]\rightarrow \sf 2(x) = sin^{-1}(-1)[/tex]

[tex]\rightarrow \sf x = -45^{\circ \:} , \ \ 135^{\circ \:}[/tex]

minimum: ( -45°,7), (135°, 7), .....

Repeat the same process for finding more values on the x-axis, or just follow the trend of the curve from the points found and sketch the graph easily.

[tex]\sf Domain\:\left(-\infty \: < x < \infty )[/tex]

[tex]\sf Range : 7\le \:f\left(x\right)\le \:17[/tex]

Sketched below:

Explanation:

There are many approaches you can take. Perhaps one of the easiest is to show the sides of the rhombus are all the same length. This can be done several ways. Here are a couple of them.

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A square has degree 4 rotational symmetry, so will map to itself when rotated by any multiple of 90°. This means the midpoints of adjacent sides will map to themselves, and any segment joining the midpoints of adjacent sides will map to itself. When segments map to themselves, they are congruent, hence the four sides of EFGH are congruent, and the figure is a rhombus.

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The sides of a square are the same length and all corner angles are right angles. Midpoints of the sides divide the sides into congruent parts, so all of the segments PF, FQ, QG, GR, and so on are congruent. This means all of the triangles PFE, QGF, RHG, and SEH are congruent by the LL postulate. Corresponding sides of congruent triangles are congruent, so the sides of EFGH are congruent, and the figure is a rhombus.

Answers:

5.) [tex]\displaystyle \pm{1\frac{2}{3}}[/tex]

4.) [tex]\displaystyle 2[/tex]

3.) [tex]\displaystyle \pm{1\frac{2}{3}}[/tex]

2.) [tex]\displaystyle 2[/tex]

1.) [tex]\displaystyle \pm{2}[/tex]

Step-by-step explanations:

5.) [tex]\displaystyle \frac{\sqrt{75}}{\sqrt{27}} \hookrightarrow \sqrt{2\frac{7}{9}} \hookrightarrow \frac{\pm{5\sqrt{3}}}{\pm{3\sqrt{3}}} \\ \\ \boxed{\pm{1\frac{2}{3}}}[/tex]

4.) [tex]\displaystyle \frac{\sqrt[5]{96}}{\sqrt[5]{3}} \hookrightarrow \sqrt[5]{32} \hookrightarrow \frac{2\sqrt[5]{3}}{\sqrt[5]{3}} \\ \\ \boxed{2}[/tex]

3.) [tex]\displaystyle \frac{\sqrt{125}}{\sqrt{45}} \hookrightarrow \sqrt{2\frac{7}{9}} \hookrightarrow \frac{\pm{5\sqrt{5}}}{\pm{3\sqrt{5}}} \\ \\ \boxed{\pm{1\frac{2}{3}}}[/tex]

2.) [tex]\displaystyle \frac{\sqrt[3]{24}}{\sqrt[3]{3}} \hookrightarrow \sqrt[3]{8} \hookrightarrow \frac{2\sqrt[3]{3}}{\sqrt[3]{3}} \\ \\ \boxed{2}[/tex]

1.) [tex]\displaystyle \frac{\sqrt{8}}{\sqrt{2}} \hookrightarrow \sqrt{4} \hookrightarrow \frac{\pm{2\sqrt{2}}}{\pm{\sqrt{2}}} \\ \\ \boxed{\pm{2}}[/tex]

I am joyous to assist you at any time.

Answer:

A

Step-by-step explanation:

The zeros are the roots or x-intercepts

They are located at coordinate points (0, 0) and (6, 0)

This means the answer is A

Hope it makes sense!

Answer:

A. x = 0 and x = 6

Step-by-step explanation:

So, the zeroes of a quadratic are the parts of it that touch the x-axis. When you find those parts, take their x value and you will get the zero.

So, in this parabola, it touches the x-axis at (0, 0) and (6, 0).

The x-values of these are 0 and 6, respectively.

Answer:

Step-by-step explanation:

Put the values of x to the equation y = 2x + 2 and calculate the value of y:

x = 2

y = 2 · 2 + 2 = 4 + 2 = 6

x = 5

y = 2 · 5 + 2 = 10 + 2 = 12

x = 6

y = 2 · 6 + 2 = 12 + 2 = 14

x = 8

y = 2 · 8 + 2 = 16 + 2 = 18

Answer:

( - y - 3 , - x - 1 )

Step-by-step explanation:

( x , y ) ----> ( - y , x ) ----> ( - y - 3 , x + 1 ) ----> ( - y - 3 , - x - 1 )

Step-by-step explanation:

Large Jar 540g for 2.16

540/2.16 = 250

(Always divide by the smallest ratio)

= 250g per 1£

Small Jar 360g for 1.37

360/1.37=262.77g

= 262.77g per 1£

Small Jar is the best value for money, more grams, same price.

Answer:

Add 5 to both sides

Step-by-step explanation:

x-5=16

+5  +5

x=21

Answer:

Addition

Step-by-step explanation:

x - 5 = 16

x - 5 + 5 = 16 + 5

x = 21

Answer:

The last one

Step-by-step explanation:

Look at A and A'

It moved 4 units to the right and 1 unit down

The same with B, B' and C, C'

Answer:

3.75?

Step-by-step explanation:

I dont know if this is what youre looking for but I guess?

Answer:

(2, -1)

Step-by-step explanation:

x = 2, y = −1

Answer:

Answer is 138

Step-by-step explanation:

I took the test and it was 138

Answer:

(2,11 2/3)  or (2,(35/3))

Step-by-step explanation:

5x-3y=-25

For x = 2:  

5(2)-3y=-25

10-3y=-25

-3y=-35

y = (35/3) or 11 2/3

(2,11 2/3)

Answer:

X = -2

Y= 5

You use:

5x-3(5)=-25

and

5(-2)-3y=-25

Answer:

[tex]\sf \dfrac{x}{8}-22[/tex]

Explanation:

[tex]\rightarrow \sf \left(\dfrac{7}{8}x-4\right)-3\left(\dfrac{1}{4}x+6\right)[/tex]

remove parenthesis

[tex]\sf \rightarrow \dfrac{7}{8}x-4-\dfrac{3x}{4}-18[/tex]

expand

[tex]\rightarrow \sf \dfrac{7x}{8}-\dfrac{3x}{4}-22[/tex]

simplify

[tex]\rightarrow \sf \dfrac{x}{8}-22[/tex]

Answer:

[tex]\frac18x-22[/tex]

Step-by-step explanation:

Given expression:

[tex](\frac78x-4)-3(\frac14x+6)[/tex]

Expand:

[tex]\implies \frac78x-4-\frac34x-18[/tex]

Gather like terms:

[tex]\implies \frac78x-\frac34x-4-18[/tex]

Change 3/4 into eighths:

[tex]\implies \frac78x-\frac68x-4-18[/tex]

Combine like terms:

[tex]\implies \frac18x-22[/tex]

Answer:

please rate and mark as brainlest.

Step-by-step explanation:

(i) 1/20

(ii)

a.708.22

b.8635.4

c.147.392

please rate and mark as brainlest.

The required values are :

[tex]\qquad \sf  \dashrightarrow \:x = 4[/tex]

and

[tex]\qquad \sf  \dashrightarrow \:y = 1[/tex]

Check the attachment for solution ~

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The total harvested area is 232 acres .

To determine the number of acres harvested, we simply have to divide the bushels of soybean by the crop yield.

Mathematically we can write it as,

The total land area = bushels of soybean / bushels per acre

Substituting the known values,

[tex]Total land area = 9396 / 40.5 = 232[/tex]

Therefore, 232 acres were harvested.

To learn more about the area visit:

https://brainly.com/question/25292087

Answer:The total harvested area is 232 acres

Step-by-step explanation:

Answer:

2 that's what soup calculated says

The perimeter of the isosceles right triangle comes to be 6+3√2.

Given that the length of one leg of an isosceles right triangle = 3 ft

A right-angle triangle having sides other than hypotenuse equal to each other is called an isosceles right triangle.

So, The length of the other leg of an isosceles right triangle = 3 ft

From Pythagoras theorem

Hypotenuse²=Perpendicular²+Base²

So, in the given isosceles right triangle

Hypotenuse²=Leg 1²+Leg2²

Leg 1=Leg2 = 3 feet

Hypotenuse² =  3²+3²

Hypotenuse = 3√2 ft.

So, the perimeter of the triangle = 3+3+ 3√2

The perimeter of the triangle =6+3√2

Therefore, The perimeter of the isosceles right triangle comes to be 6+3√2.

To get more about the right triangle visit:

https://brainly.com/question/22364396

Answer:

6 + 3 StartRoot 2 EndRoot ft

Step-by-step explanation:

Edge2022

Answer:

amplitude = 2

Step-by-step explanation:

the amplitude is the distance from the x- axis(midline ) to the maximum value , that is

amplitude = 2

[tex]\qquad \qquad \huge \pink {\sf{☁Answer☁}} \\ \\ [/tex]

Option B ( 2 ) ✓

OR,

[tex] \sf{amplitude = distance \: from \: undisturbed \: position \div centre \: line \: to \: through \: or \: peak \: }[/tex]

[tex]\purple{\rule{15mm}{2.9pt}} \red{\rule18mm{2.5pt}} \orange{ \rule18mm{2.5pt}}[/tex]

[tex]\sf{\:мѕнαcкεя\: ♪...}[/tex]

Answer:

A. 2086 yd²

Step-by-step explanation:

SA = 2lw + 2wh + 2lh
SA = 2*17*20 + 2*20*19 + 2*17*19
SA = 680 + 760 + 646
SA = 2086
Hope this helps :)

The approximate decimal value of tan(α) is -3.274, α intersects the unit circle at point (-0.292, 0.956)

A circle is the locus of a point such that its distance from a fixed point (center) is always constant.

A unit circle is a circle with a unit radius.

Given that:

The terminal side of angle α intersects the unit circle at point (-0.292, 0.956).

Hence:

tan(α) = (0.956 / -0.292) = -3.274

The approximate decimal value of tan(α) is -3.274, α intersects the unit circle at point (-0.292, 0.956)

Find out more on unit circle at: https://brainly.com/question/23989157

The central angle (127 degrees) is the angle at point K

The measures of JL and JML are 127 and 233 degrees, respectively

From the complete question, we have:

JL = 127 degrees.

The sum of angles at a point is 360 degrees

So, we have:

JML + 127 = 360

Subtract 127 from both sides

JML = 233

Hence, the measures of JL and JML are 127 and 233 degrees, respectively

Read more about circles and arcs at:

https://brainly.com/question/25305793

Answer:

8 (or 8.4)

Step-by-step explanation:

First, the problem states the words: Distinct and positive.

That means that the smallest number we can use is 0.

We can make 10 blanks for 10 numbers for us to fill in.

_ _ _ _ _ _ _ _ _ _

Since 10 is an even number, and the median is not one single number, it will be the middle of the two numbers.

In this case, our two numbers are the 5th and 6th blank.

Any two numbers can be used, as long as they are the same actual value from 10.

Let us first put in the numbers we can, which are the numbers before the two middle blanks.

0,1,2,3, _ _ _ _ _ _

To find the median between two numbers, we can do:

(a+b) divided by 2 = median

We can use the smallest following number, 4. Then the 6th number will have to be 16 for 10 to be in the middle.

Also try the largest possible number for the 5th blank, 9. Then the 6th number will be 11.

4+16 and 9+11 both equal 20, and 20 divided by 2 is 10. So both of these work.

Now let's place the other numbers in for these two equations.

0,1,2,3,4,16,17,18,19,20

0,1,2,3,9,11,12,13,14,15

If we add the numbers of each together, we get:

0,1,2,3,4,16,17,18,19,20=100

0,1,2,3,9,11,12,13,14,15= 80

If we now divide each sum by 10 (to find the average) we get:

10

8

Since both of these were the most we could go, one with the 5th number as small as possible and one with the 5th number as large as possible.

Since the smaller answer we got was 8, the answer must be 8.

(I believe 0 is a positive integer because it doesn't carry a negative sign. If 0 is not a positive integer, the answer is 8.4. Use the same process