Why is it difficult for "weightless" astronauts in space to know whether they are right side up or upside down?

Answers

Answer 1

Answer:

There is no upside down/rightside up.

Explanation:

It's hard for astronauts to tell whether they are up or down because gravity tells you which way is down. For example, on Earth you would be able to point down, towards Earth's core. But someone on the opposite side of Earth pointing down would be pointing the opposite direction, but still towards Earth's core. "Down" is really the direction gravity is pulling you in. So if there's not enough gravity to pull you in a direction you don't really have a down. So unless they can see their surroundings to see which way is "up" relatively, it would be impossible to know whether they are rightside up/upside down.


Related Questions

in the following equation, a is acceleration, m is mass, v is velocity, r is radius, t is time, is an angle, and c is a constant. a=c mv2sin0/rtif this equation is valid, which of the following could be the units of c?a.s/kgb.m/s2c.m2/sd.kg/me.kg m/s2

Answers

The units of c are: [c] = m²/s³. The answer is b.

The given equation is a = cmv²sinθ/rt, where a is acceleration, m is mass, v is velocity, r is radius, t is time, θ is an angle, and c is a constant.

To determine the units of c, we can analyze the units of each term in the equation and then determine the units of c such that the units of the equation are consistent.

Units of each term in the equation are:

a: m/s²

m: kg

v: m/s

r: m

t: s

sinθ: dimensionless

Substituting these units in the given equation, we get:

[m/s²] = [c] x [kg] x [m/s]² x [dimensionless] / [m] x [s]

Simplifying the above equation, we get:

[c] = [m/s²] x [m] x [s] / [kg] x [m/s]² x [dimensionless]

Therefore, the units of c are:

[c] = m²/s³

Hence, option (b) m²/s³ could be the units of c.

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