JAVA
Write a Java program that gets a one-dimensional integer array and return the count of unique elements in the array. You will write a method numUnique() that takes in the array and returns the count.
For example,
Enter the number of elements you want to store:
8
Enter the elements of the array: 4 2 3 1 2 3 2 1 Original array length: 8
Array elements are: 4 2 3 1 2 3 2 1 The number of unique elements is: 4
One way to find similar elements would be to use nested loops and/or multiple arrays. But there's a nifty trick we can use: sort the array and then check for adjacent elements. For example, in the example above the original array is:
4 2 3 1 2 3 2 1
Sorted, this array will be:
1 1 2 2 2 3 3 4
Now we can compare elements next to each other. Let's start with array[i] where i is 0, our first unique value (i.e., the value 1). If its successor, array[i+1] is the same, then we wouldn't count it since it's not unique. We'd continue this process of comparing adjacent values until we've processed the entire array.
Use Arrays (import java.util.Arrays)--that class we used before with its .toString() method. Look up how to use its .sort() method.

Answers

Answer 1

This program first takes user input to create the integer array, then calls the numUnique() method to count unique elements.

Here's a Java program that uses the numUnique() method to count the unique elements in a given one-dimensional integer array:

```java
import java.util.Arrays;
import java.util.Scanner;

public class UniqueElements {
   public static void main(String[] args) {
       Scanner input = new Scanner(System.in);
       System.out.println("Enter the number of elements you want to store:");
       int n = input.nextInt();

       int[] array = new int[n];
       System.out.println("Enter the elements of the array:");
       for (int i = 0; i < n; i++) {
           array[i] = input.nextInt();
       }
       input.close();

       System.out.println("Original array length: " + n);
       System.out.println("Array elements are: " + Arrays.toString(array));
       System.out.println("The number of unique elements is: " + numUnique(array));
   }

   public static int numUnique(int[] array) {
       Arrays.sort(array);
       int uniqueCount = 1;
       for (int i = 1; i < array.length; i++) {
           if (array[i] != array[i - 1]) {
               uniqueCount++;
           }
       }
       return uniqueCount;
   }
}
```

Inside the numUnique() method, the array is sorted using Arrays.sort(), and then adjacent elements are compared to determine the count of unique elements.

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Answers

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