Which two limbic system structures are especially associated with forming new memories?
A. the thalamus and the hypothalamus
B. the thalamus and cerebellum
C. the hypothalamus and the substantia nigra
D. the hippocampus and amygdala

Answer:

Explanation:

F = mg

F = 75(9.8)

F = 735 N

Answer:

You can't use energy conservation when mass is removed. This has required energy that you are not taking into account.

Answer:

because some time it dose not need to be i equation becasue it is not need

Explanation:

Hi there!

We can use the conservation of energy:

Ei = Ef

The initial energy involves kinetic energy while the final energy involves maximum elastic potential energy, so:

1/2mv² = 1/2kx²

We can cancel out the 1/2s for ease of solving:

mv² = kx²

Plug in given values to solve for x:

√(mv²/k) = x

√(5.7)(12²)/(150)) = x

x = 2.339 m

Answer:

15kg

(i actually did this)

Explanation:

k12

hope this helped!

i hope you ace it!

Answer: B) 5g

I took the 4.11 Unit Test: Nutrition quiz.

it tells you that it has a lot of force

Answer:

Since I couldn't find the other answers to the same question, I wrote the wrong answer to help ya'll get the sample response. So here's from Edge

Explanation:

Sample Response: If KE = 0, the pendulum is not moving. At the top of the swing, the pendulum must stop for a brief moment.

Answer:

omg this is hard

Explanation:

Yes it is lol

50 mL of water have to poured to the glass bottle of 100 g to increase the stretching of the spring from 1.8 cm to 2.7 cm.

A spring can hang when it loads a weight. The stretching of spring is the change in length of the spring end from its initial length.  Spring balance works with the principle of Hooks law.

The stretching is made by the elasticity of the spring which make it in a wave like motion.

Given that the glass bottle with 100 g weight when loaded on the spring scale, it will stretch down to 1.8 cm. Then the weight required to make a stretch of 2.7 cm is calculated as follows:

weight required  = (100 g × 1.8 cm) /2.7 cm

                            = 150 g.

A total of 150 g is needed to stretch into 2.7 cm. Thus we have to add 50 g of water to the glass weighing 100 g . 50 g is equivalent to 50 ml, since density of water is 1 g/L.

Hence, 50 ml of water should be poured to the glass.

To find more about spring scale, refer the link below:

https://brainly.com/question/2568071

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Answer:

5 912 500 000 000 = 5.91x10^12 miles

Explanation:

The first thing we need to do is convert the light year distance to kilometres, since we have the kilometre to mile conversion. There are 1000m in a kilometre, so we need to divide the light year value that we have by 1000, giving us 9.46x10^12 km for 1 light year.

Now that we have our value in kilometres, we simply need to divide it by 1.6 to get it in miles. Doing so gives us 5 912 500 000 000 miles, or 5.91x10^12 miles.

Hope that made sense, and let me know if you have any further questions!

Answer:

d = √(6² + 8²) = 10 km

Explanation:

displacement is a vector and subject to vector addition.

Answer:

8. Friction

9. Net force

Explanation:

Hope this helps you. Have a nice day. :)

Answer:

A. They travel faster in a solid than other mediums

Explanation:

Sound waves travel faster in solids because the density of solids is higher than that of liquids which means that the particles are closer together and sound can be transmitted more easily.

Answer:

2.5 × 10-⁴¹ Ns

Explanation:

Impulse

I = F × t

I = 5000 N × 5 × 10-⁴⁵ s

I = 25 × 10-⁴² Ns

I = 2.5 × 10-⁴¹ Ns

#LearnWithEXO

Answer:

ummm I didn't understand the question

Answer:

155÷8.5

=18.235294117647

Average Velocity

v = s/t

v = 300 km/(1 hour + 40/60 hour)

v = 300 km/(1.66 hour)

v = 180 km/hour

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Answer:

C. 640

Explanation:

The minimum force would occur in a frictionless environment and act parallel to any abutting surface.

F = ma = 160(4) = 640 N

Answer:

binoculars

Explanation: I am taking astronomy

Answer: B) binoculars just took the test

Explanation:

[tex]\\ \sf\longmapsto W=Fd[/tex]

[tex]\\ \sf\longmapsto d=\dfrac{W}{F}[/tex]

[tex]\\ \sf\longmapsto d=\dfrac{9}{12}=0.72m[/tex]

Answer:

Anne pushed a cart by 12 N.

● Force = 12 N

Work done is 9 J

● Work = 9 J

=> Work = Force × distance

[tex]=> distance = \frac{work}{force} [/tex]

[tex]=> distance = \frac{9}{2} [/tex]

[tex]=> distance = 0.72m[/tex]

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Answer:

d.

50 m

Explanation:

v² = u² + 2as

s = (v² - u²) / 2a

s =(25² - 0²) / (2(6.25))

s = 50 m

Answer:

graph b

Explanation:

Answer:

D-it's never acceptable to ignore rules and etiquette

Explanation:

We should know that it's never acceptable to ignore rules and etiquette.

The rules of etiquette in sports are the rules of the sports that have been document by the various sports federations.

We should know that it's never acceptable to ignore rules and etiquette. These will make the the sports a lawless act and full of chaos.

Learn more about etiquette in sports:https://brainly.com/question/979191

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Explanation:

I will definitely explain you if you follow me please

Answer:2.02s

Explanation:

At the y component, the tract of the ball is free falling body. The initial velocity at y component is 0 m/s.

Height = 1/2 * g * t^2

20 = 1/2 * 9.8 * t^2

t = (20 * 2 / 9.8)^1/2, t = 2.02s

Explanation:

What are you searching for?

Potential energy?

Answer:

3018.4

Explanation:

So this velocity just before reaching the ground, the final equals square root of two times G times H. So gs 9.8 m per second squared H is 2.8 m. So it gives the velocity of 7.41 m per second squared. That's the velocity right before touching the ground. So to find the impulse required to come to rest here, we just do mass times the velocity minus zero. So zero is the final momentum, final velocity zero. So that makes the final momentum zero. So we multiply the mass with the velocity before touching the ground and after. And subject zero. That's the momentum after touching the ground. So we multiply mass 55 kg. At 7.41 velocity we got 407.45.  kilograms meters per second of impulse. we know that the force will be larger for stiff stiff flex compared to bend flex. Because the stiff flex. Bring the object to rest in a short amount of time and distance. So in part C, that's calculate for stiff flex. The stopping distance, Delta Y. Is 0.1 m. This one centimeter. So we can calculate the acceleration of the body when it comes to rest.  From the moment it touches the ground.  equals v squared over two times Delta Y. So  we use the square is 54.88. The 7.41 square divided by two times 0.01 gives us an explosion of 2744 m/s square. So you multiply this acceleration by the mass to get the force so force equals mass times acceleration gives us a large force,  159 20 newtons. Then for bent legs, repeat the same process with a different delta Y, delta Y of 200.5 m. So that's 50 centimeters and calculate acceleration the same process. Just use a different value of delta Y. And we get as much smaller acceleration 54.88 m per second square. And the force experience would just be mass times acceleration. That gives us 3018.4 newton's a lot smaller than for stiff flex.