Which of the following could be the measure of the angle below?

On a coordinate plane, a horizontal straight line is on the x-axis from negative 4 to positive 4.
–180°
–120°
140°
510°

The equation of line is y = -3x + 2

An equation for two variables is a mathematical statement that relates two variables, typically represented by x and y, using mathematical symbols and operations such as addition, subtraction, multiplication, and division.

To find the equation of the line that passes through the given points (2, -4), (3, -7), (4, -10), and (5, -13), we can use the slope-intercept form of the equation of a line:

y = mx + b, where slope of the line is m and y-intercept is b.

First, let's find the slope of the line using two of the points, say (2, -4) and (3, -7). The slope, m, is given by:

m = [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

= (-7 - (-4)) / (3 - 2)

= -3

we know the slope, we can use one of the points, say (2, -4), and the slope to find the y-intercept, b. Use the slope intercept to form the equation of a line:

y = mx + b, and substitute in the slope and coordinates of one of the points:

-4 = (-3)(2) + b

Simplifying this equation, we get:

b = -4 + 6

= 2

Therefore, the equation of the line that passes through the given points (2, -4), (3, -7), (4, -10), and (5, -13) is: y = -3x + 2

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Answer:

Step-by-step explanation:

The distance AC is approximately 6.47 km, the bearing of A from C is approximately 313.8°, and the area of triangle ABC is approximately 14.8 km².

To solve this problem, we can use the law of cosines to find the length of AC and the law of sines to find the angle at A.

First, we can use the given information to draw a diagram and label the angles and sides:

       C

      / \

     /   \

 5 /     \ 7

   /       \

  /         \

A /___θ_____\ B

From the given information, we know that:

AB = 7 km

BC = 5 km

∠ABC = 100° (since ∠ABD = 180° - 30° - 70° = 80° and ∠DBC = 180° - 280° = 100°)

Using the law of cosines, we can find the length of AC:

AC^2 = AB^2 + BC^2 - 2ABBCcos(∠ABC)

AC^2 = 7^2 + 5^2 - 2(7)(5)cos(100°)

AC^2 ≈ 41.84

AC ≈ 6.47 km

Next, we can use the law of sines to find the angle at A:

sin(∠CAB)/AC = sin(∠ABC)/AB

sin(∠CAB)/6.47 = sin(100°)/7

sin(∠CAB) ≈ 0.276

∠CAB ≈ 16.2°

To find the bearing of A from C, we can use the fact that the bearing is the angle measured clockwise from north. Since ∠CAB is acute and the bearing of B from A is 30° east of north, the bearing of A from C is:

360° - (30° + ∠CAB) ≈ 313.8°

Finally, to find the area of triangle ABC, we can use the formula:

Area = (1/2)ABBCsin(∠ABC)

Substituting the given values, we get:

Area = (1/2)(7)(5)sin(100°)

Area ≈ 14.8 km²

Therefore, the distance AC is approximately 6.47 km, the bearing of A from C is approximately 313.8°, and the area of triangle ABC is approximately 14.8 km².

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The solution of the system of equation is (3, 5) and (–4, 12) [option A]

The given system of equations is:

x + y = 8

y = x² – 4

To solve for x and y, we can substitute the second equation into the first equation for y:

x + (x² - 4) = 8

Simplifying, we get:

x² + x - 12 = 0

Now we can use the quadratic formula to solve for x:

x = (-b ± √(b² - 4ac)) / 2a

where a = 1, b = 1, and c = -12

x = (-1 ± √(1² - 4(1)(-12))) / 2(1)

x = (-1 ± √(1 + 48)) / 2

x = (-1 ± 7) / 2

Solving for x gives us two possible values: x = 3 or x = -4.

To find the corresponding values of y for each value of x, we can substitute them into either of the original equations. Using y = x² - 4:

When x = 3, y = 3² - 4 = 5

When x = -4, y = (-4)² - 4 = 12

Therefore, the solution to the system of equations is (3, 5) and (-4, 12), which is answer choice (a).

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The assumptions include:

1. The observations are normally distributed.

2 The observertions are independent.

Test hypotheses include the null hypothesis that the anxiety level is same before after the course and the alternative hypothesis that the anxiety level derveases after taking the course.

The standard deviation is 1.1475. The value of to will be:

= -1.125 / (1.1475 / √16)

= 3.9212

Based on the p value, it should be noted that the null hypothesis is rejected.

In conclusion, the anxiety level decrease after the students take the course.

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Before you took this course, you probably heard many stories about Statistics courses. Oftentimes parents of students have had bad experiences with Statistics courses and pass on their anxieties to their children. To test whether actually taking AP Statistics decreases students' anxieties about Statistics, an AP Statistics instructor gave a test to rate student anxiety at the beginning and end of his course.

Anxiety levels were measured on a scale of 0-10. Here are the data for 16 randomly chosen students from a class of 180 students:

Do the data indicate that anxiety levels about Statistics decreases after students take AP Statistics? Test an appropriate hypothesis and state your conclusion.

The lines having linear equation y=4x+1 and y=2x-1 intersect at the point (-1, -3).

What is a linear equation, exactly?

A linear equation is an algebraic equation of the first degree that describes a line in a two-dimensional plane. It is an equation of the form y = mx + b, where x and y are variables, m is the slope of the line, and b is the y-intercept. The slope represents the rate of change of y with respect to x, while the y-intercept represents the point at which the line crosses the y-axis

Now,

To find the point of intersection between the lines y=4x+1 and y=2x-1, we can set the two equations equal to each other or we can graph these and find the intersection point.

1.

4x+1 = 2x-1

Simplifying this equation, we get:

2x = -2

x = -1

Now, we can substitute this value of x into either equation to find the corresponding value of y:

y = 4x+1 = 4(-1)+1 = -3

Therefore,

               the lines y=4x+1 and y=2x-1 intersect at the point (-1, -3).

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Answer:

41

Step-by-step explanation:

a^2+b^2=c^2

So...

40^2+9^2=1681

√1681=41

= 5x = 5(12) = 60 sandwiches, the number of ham sandwiches. Tina makes 60 ham sandwiches.

First, we need to find the total number of each type of sandwich that Tina makes:

3/8 of the sandwiches are tuna, so the number of tuna sandwiches

= 3/8 x 480

= 180 sandwiches

35% of the sandwiches are beef, so the number of beef sandwiches

= 35% x 480

= 0.35 x 480

= 168 sandwiches

The remaining sandwiches must be ham and cheese sandwiches. Let's call the number of ham sandwiches "h" and the number of cheese sandwiches "c". We know that h:c = 5:6, which means that h = 5x and c = 6x for some common factor x. The total number of sandwiches is 480, so:

h + c = 480 - 180 - 168

h + c = 132

Substituting h = 5x and c = 6x, we get:

5x + 6x = 132                              

11x = 132

x = 12

Therefore, the number of ham sandwiches = 5x = 5(12) = 60 sandwiches. Tina makes 60 ham sandwiches.

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Answer:

3*C

Step-by-step explanation:

We can Frame an equation, taking the previous temperature as "x" and adding 2 by every hour.

Previous Temprature + 2 = New Temprature

Therefore by this equation:

at 8AM , the Temperature is -5 + 2 = -3*c
at 9AM , the Temperature is -3 + 2 = -1*c
at 10 AM, the Temperature is -1 + 2 = 1*c


Therefore at 11AM , the Temperature will be 1 + 2 = 3*c

Hope it helps.

Answer: 45 ml/h

Step-by-step explanation: that is  s/t graph

read in any point on the part of graph  distance , and divide

it with time .

95:2 hours,  

Answer: o find the maximum value of the objective function F=5x+2y and the values of x and y for which it occurs, we need to graph the constraints and determine the feasible region. Then, we can evaluate the objective function at the vertices of the feasible region to find the maximum value.

First, we will graph the constraints x+2y<6 and 2x+y<6. To do this, we can rewrite the inequalities as equations and graph the corresponding lines:

x+2y=6 (solid line)

2x+y=6 (dashed line)

Next, we need to determine which side of each line satisfies the inequality. To do this, we can choose a point on one side of each line and substitute its coordinates into the inequality. If the inequality is true, then that side of the line satisfies the inequality. If not, then the other side satisfies the inequality.

For example, let's choose the point (0,0) as a test point for the inequality x+2y<6:

0+2(0)<6

This is true, so the side of the line on which (0,0) lies satisfies the inequality. Similarly, we can choose the point (0,0) as a test point for the inequality 2x+y<6:

2(0)+0<6

This is also true, so the side of the line on which (0,0) lies satisfies the inequality.

Now, we can shade in the feasible region, which is the region of the graph that satisfies all of the constraints. It is the region bounded by the two lines and the axes, and it is shown in the figure below:

lua

   |              .

   |            .

   |          .

 3 |        .

   |      .

   |    .

 2 |  .

   |.

   ----------------

     0  1  2  3  4  5  6

The vertices of the feasible region are (0,3), (2,2), and (3,0). To find the maximum value of the objective function, we evaluate it at each vertex:

F(0,3) = 5(0) + 2(3) = 6

F(2,2) = 5(2) + 2(2) = 14

F(3,0) = 5(3) + 2(0) = 15

Therefore, the maximum value of the objective function is 15, and it occurs when x=3 and y=0.

enjoy (:

A. Yes, because the rate of change is a constant $70 per year. We can observe that the amount owed increases by $70 for every year that passes.

This is due to the simple interest rate of 7% per year, which means that the boy owes an additional 7% of the original amount ($1000) each year. Thus, the  the amount owed after one year is $1000 + 0.07($1000) = $1070, after two years it is $1000 + 2(0.07($1000)) = $1140, and so on. $70  is the change rate per year.

B. It will be no due to the change rate is $0 per year in 2nd and 3rd years.

This statement is false because, as we calculated in part A, the rate of change is constant at $70 per year. Therefore, the amount owed will increase by $70 even during the second and third years, as long as the boy has not made any payments towards the loan.

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The properties of the least squares line are that the intercept represents the estimated base appraised value for any house in East Meadow, and the slope represents the estimated increase in appraised value for each additional room in the house.

The properties of the least squares line, ? = 74.80 + 19.72x, are as follows:
1. The intercept, ?0, is 74.80. This represents the estimated base appraised value for any house in East Meadow, regardless of the number of rooms. However, there is no practical interpretation for this value, since a house with 0 rooms is nonsensical.

2. The slope, ?1, is 19.72. This represents the estimated increase in appraised value for each additional room in the house. For each additional room in the house, we estimate the appraised value to increase $19,720.

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Answer:

(4,-5)

Step-by-step explanation:

(x,y)  → (-x, -y)

(-4,5) → (4,-5)

Helping in the name of Jesus.

The polygon has 12 sides and each angle has a measure of 30°.

The border of a Susan B. Anthony dollar is in the shape of a regular polygon. A regular polygon is a polygon with equal sides and equal angles. To calculate the number of sides and measure of the angles, the formula for finding the measure of the interior angles of a regular polygon is used. The formula is (n-2)180/n where n is the number of sides. For the Susan B. Anthony dollar, the number of sides is 12, so the measure of the interior angles is (12-2)180/12 = 30°. Therefore, the polygon has 12 sides and each angle has a measure of 30°, rounded to the nearest degree.

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When f(x) is divided by x-3 is 27 , then what is the value of k is -3

Remainder Theοrem is an apprοach οf Euclidean divisiοn οf pοlynοmials. Accοrding tο this theοrem, if we divide a pοlynοmial P (x) by a factοr ( x – a); that isn’t essentially an element οf the pοlynοmial; yοu will find a smaller pοlynοmial alοng with a remainder.

When f(x) is divided by x - 3, the remainder is 27, which means that

f(3) = 27.

We can use this fact tο sοlve fοr k as fοllοws:

f(x) = x³ + kx + 9

f(3) = 27

Substituting x = 3 intο the expressiοn fοr f(x), we get:

f(3) = 3³ + k(3) + 9 = 27

Simplifying the left side, we get:

27 + 3k + 9 = 27

Cοmbining like terms, we get:

3k + 36 = 27

Subtracting 36 frοm bοth sides, we get:

3k = -9

Dividing bοth sides by 3, we get:

k = -3

Therefοre, the value οf k is -3.

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Step-by-step explanation:

The area with the highest inches receives most rainfall 1¼

The area with the lowest inches received lowest rainfall 1/8

1¼ location will have highest frequency using the ⅛line plot. There are 10 of ⅛ in 1¼

Add all the inches

1/8 + 3/8 +1/8 + 1/8 + 3/4+ 3/4 + 1/4 + 1¼ + 1/4 +1

6/8 + 2¼ + 1

6/8 + 3¼

6/8 + 13/4 = 32/8

Total rain = 4inches

The equation of the line shown is y = 1x + 9.

An equation is a statement of equality between two expressions. It is typically expressed in mathematical notation, with the left side of the equation equal to the right side. Equations are used to describe how two values are related, and can be used to solve problems or predict outcomes. Equations can be used in any field of study, from physics to economics.

The equation of the line shown can be found by using the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope and b is the y-intercept. In this case, the slope is m = (10 - 9)/(10 - 0) = 1.

The y-intercept is b = 9, as this is the point at which the line crosses the y-axis. Therefore, the equation of the line shown is y = 1x + 9.

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Complete questions as follows-
this is happening do proper format and calculation
Find the equation of the line shown.
y
10
S87654321
9
0 1 2 3 4 5 6 7 8 9 10
X

1. Use properties of logarithms with the given approximations to evaluate the expression. Use log2=0.693 and/or log6=1.792 to find log12.

Answer: log12 = log6 + log2 = 1.792 + 0.693 = 2.485.

2. Complete parts (a) and (b).

a. Write the inverse of y=8x in logarithmic form.

Answer: log8(y) = x.

b. Graph y=8x and its inverse and discuss the symmetry of their graphs.

Answer: The graph of y=8x and its inverse will have the same shape, but it will be flipped across the line y = x. This is known as the symmetry of their graphs.

3. 2log215 EVALUATE Use properties of logarithms with the given approximations to evaluate the expression. log3≈0.477 and log5≈0.699. Use one or both of these values to evaluate log27. Write as a single logarithm. Assume that variables represent positive numbers. 5log2x+2log2z

Answer: log27 = log5 + log3 = 0.477 + 0.699 = 1.176.

4. On the basis of data for the years 1918 through 1997, the expected life span of people in a country can be described by the function f(x) = 12.576ln x + 17.088 years, where x is the number of years from 1905 to the person's birth year. What does this model estimate the life span to be for people born in 1941?

Answer: This model estimates that the life span for people born in 1941 is 70.698 years.

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The probability of rolling a 1 and spinning section A on the spinner is 1/24.

To find the probability of rolling a 1 and spinning section A on the spinner, we need to first determine the total number of possible outcomes for the experiment. The number cube has 6 possible outcomes, and the spinner has 4 possible outcomes. Therefore, the total number of possible outcomes for the experiment is 6 x 4 = 24.

Next, we need to determine the number of outcomes that meet the criteria of rolling a 1 and spinning section A. Rolling a 1 has a probability of 1/6, and spinning section A has a probability of 1/4.

The probability of both events occurring simultaneously is the product of the two probabilities, which is (1/6) x (1/4) = 1/24.

This means that out of the 24 possible outcomes, only one outcome will result in rolling a 1 and spinning section A on the spinner.

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Complete Question:

A number cube numbered (1, 2, 3, 4, 5, 6)  is rolled and a spinner with 4 sections (A, B, C, D) is spun. Find the probability of P(1 and A).

Answer:

vfejwbjelkn

Step-by-step explanation:

According to the question the exponential function that goes through the two points is: [tex]y = 4(9^x).[/tex]

Given,

We must first determine the values of a and b before we can build an exponential function with the form y = abx that passes through the points (0,4) and (2,324).

Using the point (0,4), we have:

4 = ab^0

4 = a(1)

a = 4

Using the point (2,324), we have:

324 = 4b^2

b^2 = 81

b = 9 (since b must be positive)

So the exponential function that goes through the two points is:

y = 4(9^x)

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The trinomial( consists three different terms), 2x² + 13x + 6, has a linear factor of (x + 6) and the linear factor of (x+6) is equals to a (2x+1).

We have, a trinomial 2x² + 13x + 6 has a linear factor of x + 6 and we have to determine that linear factor of (x + 6). To determine the linear factor of (x + 6) either dividing the trinomial by (x+6) or factorization of this trinomial. Factoring a trinomial means expanding an equation into the product of two or more binomials. Here, middle term of trinomial, b = 13

last term, c = 6

Using spliting middle term method for factorization, 2x²+ 13x + 6 = 2x² + 12x + x + 6

=> 2x² + 13x + 6 = 2x( x + 6) + 1(x + 6 )

Common factor from binomials,

=> 2x² + 13x + 6 = (x + 6)(2x + 1)

Thus, the linear factor of (x+6) is (2x +1).

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Throughout his innings, Kohli scored 432 runs in total.. Rohit scored 422 runs and Rahul scored 427 runs. In total, they scored 442 runs.

Kohli, Rohit and Rahul are three of the greatest batsmen in Indian cricket. In a match, they scored 442 runs in total.Rohit scored the most runs (422 total),. Kohli scored 10 runs less than Rohit, making his total score 432 runs. Rahul was the third highest scorer, with 5 runs more than Rohit, making his total score 427 runs. This shows the great batting prowess of the three batsmen and how they were able to score a combined 442 runs between them. This goes to show the great talent and skill that the three players possess and how they are able to make such a great contribution to their team's total score.

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The value of x is 25 using Pythagoras theorem.

A pοint where twο lines meet prοduces an angle.

The breadth οf the "οpening" between these twο rays is referred tο as a "angle". It is depicted by the figure.

Radians, a unit οf circularity οr rοtatiοn, and degrees are twο cοmmοn units used tο describe angles.

By cοnnecting twο rays at their ends, οne can make an angle in geοmetry. The sides οr limbs οf the angle are what are meant by these rays.

The limbs and the vertex are the twο main parts οf an angle.

The cοmmοn terminal οf the twο beams is the shared vertex.

Pythagοras theοrem,

perpendicular²= hypοtenuse² + base²

Find the hypotenuse of lower triangle

c² = 15² + 9²

c = [tex]\sqrt{15^2 + 8^2}[/tex]

c = 17

Now, c is the base altitude of upper triangle

So

x² = [tex]\sqrt{20^2 + 15^2}[/tex]

x = 25

Thus, the value of x is 25 using Pythagoras theorem.

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Answer:

no one can solve that because how you spelled it but good luck

Answer:

y= -2 when x is 0,y= -10 where x is 1 and y= -18 where x is 2

Step-by-step explanation:

when you equate x to 0 then you substitute to the equation give which is y+8x= -2, the same thing applies to the next numbers which is 1 and 2. to show it will look like is suppose to be in the form like when x is 0 it will be y+8(0)= -2

which will solve to get y+0=-2

which is the same as y=-2

Answer:

12

Step-by-step explanation:

p(x) = 2(-3x+5)+2(x+4)

Substitution :

p(2) = 2(-3(2) +5) + 2(2+5)
= 2(-6 + 5) + 2 (7)
= 2(-1) + 2(7)
= -2 + 14
= 12

Answer:

[tex]\dfrac{dy}{dx}=-\dfrac{52x\left(3x^{37}y-1\right) }{4x^{39}+9y^8}[/tex]

Step-by-step explanation:

Note: I will provide links with descriptions/steps to each of the rules used in this differential equation at the bottom of this answer.

Given

[tex]-26x^2+4x^{39} y+y^9=-21[/tex]

Find [tex]\dfrac{dy}{dx}[/tex]

Differentiate the left side of the equation.

[tex]\dfrac{d}{dx}\left(-26x^2+4x^{39}y+y^9\right)= \dfrac{d}{dx}\left(-21\right)[/tex]

Focus the left side of the equation.                                                         Apply the Sum Rule for derivatives.

[tex]\dfrac{d}{dx} \left[-26x^2\right]+\dfrac{d}{dx} \left[4x^{39}y\right]+\dfrac{d}{dx} \left[y^9\right][/tex]

Lets evaluate each derivative.

1.   Evaluate [tex]\frac{d}{dx} \left[-26x^2\right][/tex]

Differentiate using the Power Rule for derivatives.

[tex]\dfrac{d}{dx} \left[-26x^2\right]=2*26x^{2-1}[/tex]

Simplify.

[tex]2*-26x^{2-1}\\-52x^{2-1}\\-52x[/tex]

2.   Evaluate [tex]\frac{d}{dx} \left[4x^{39}y \right][/tex]

Differentiate using the Product Rule for derivatives.

[tex]4\left(x^{39}\dfrac{d}{dx}\left[y\right]+y\dfrac{d}{dx}\left[x^{39}\right]\right)[/tex]

Rewrite  [tex]\dfrac{d}{dx}\left[y\right][/tex] as [tex]y'[/tex]

[tex]4\left(x^{39}y'+y\dfrac{d}{dx}\left[x^{39}\right]\right)[/tex]

Differentiate using the Power Rule for derivatives.

[tex]4\left(x^{39}y'+y\left(39x^{39-1} \right)\right)[/tex]

Simplify.

[tex]4\left(x^{39}y'+39yx^{38} \right)[/tex]

3.   Evaluate [tex]\frac{d}{dx} \left[y^9\right][/tex]

Differentiate using the Chain Rule for derivatives.

[tex]9y^8\dfrac{d}{dx} \left[y\right][/tex]

Rewrite  [tex]\dfrac{d}{dx}\left[y\right][/tex] as [tex]y'[/tex]

[tex]9y^8y'[/tex]

Add up all of the derivatives then simplify.

[tex]-52x+4\left(x^{39}y'+39yx^{38} \right)+9y^8y'[/tex]

[tex]-52x+4\left(x^{39}y'\right)+4\left(39yx^{38} \right)+9y^8y'[/tex]

[tex]-52x+4x^{39}y'+156yx^{38}+9y^8y'[/tex]

[tex]4x^{39}y'+156x^{38}y+9y^8y'-52x[/tex]

Focus the right side of the equation.

[tex]\dfrac{d}{dx}\left(-21\right)[/tex]

Since [tex]-21[/tex] is constant with respect to [tex]x[/tex] , the derivative of [tex]-21[/tex] with respect to [tex]x[/tex] is 0 .

Now we have

[tex]4x^{39}y'+156x^{38}y+9y^8y'-52x=0[/tex]

Finally lets solve for [tex]y'[/tex].

Subtract [tex]156x^{38}y[/tex] from both sides of the equation.

[tex]4x^{39}y'+9y^8y'-52x=-156x^{38}y[/tex]

Add [tex]52x[/tex] to both sides of the equation.

[tex]4x^{39}y'+9y^8y'=-156x^{38}y+52x[/tex]

Factor [tex]y'[/tex] out of [tex]4x^{39}y'[/tex]

[tex]y'\left(4x^{39}\right) +9y^8y'=-156x^{38}y+52x[/tex]

Factor [tex]y'[/tex] out of [tex]9y^8y'[/tex]

[tex]y'\left(4x^{39}\right)+y'\left(9y^8\right)=-156x^{38}y+52x[/tex]

Factor [tex]y'[/tex] out of [tex]y'\left(4x^{39}\right)+y'\left(9y^8\right)[/tex]

[tex]y'\left(4x^{39}+9y^8\right)+=-156x^{38}y+52x[/tex]

Divide each term by [tex]4x^{39}+9y^8[/tex]

[tex]\dfrac{y'\left(4x^{39}+9y^8\right)}{4x^{39}+9y^8} =\dfrac{-156x^{38}y}{4x^{39}+9y^8} +\dfrac{52x}{4x^{39}+9y^8}[/tex]

Cancel the common factor of [tex]4x^{39}+9y^8[/tex] on the left side of the equation.

[tex]y'=\dfrac{-156x^{38}y}{4x^{39}+9y^8} +\dfrac{52x}{4x^{39}+9y^8}[/tex]

Combine the numerators over the common denominator.

[tex]y'=\dfrac{-156x^{38}y+52x}{4x^{39}+9y^8}[/tex]

Factor [tex]52x[/tex] out of [tex]-156x^{38}y+52x[/tex] and simplify.

[tex]y'=\dfrac{52x\left(-3x^{37}y\right)+52x}{4x^{39}+9y^8}[/tex]

[tex]y'=\dfrac{52x\left(-3x^{37}y\right)+52x(1)}{4x^{39}+9y^8}[/tex]

[tex]y'=\dfrac{52x\left(-3x^{37}y+1\right) }{4x^{39}+9y^8}[/tex]

[tex]y'=-\dfrac{52x\left(3x^{37}y-1\right) }{4x^{39}+9y^8}[/tex]

Rewrite [tex]y'[/tex] as [tex]\dfrac{dy}{dx}[/tex].

[tex]\dfrac{dy}{dx}=-\dfrac{52x\left(3x^{37}y-1\right) }{4x^{39}+9y^8}[/tex]

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