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Find x and y values that make both y = 2x – 5 Y=-2/3x+ 3 true.
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Answer:
See below ↓
Step-by-step explanation:
Let's find the x and y values.
Step 1 : Equate the y expressions.
The two equations have given different values for yTherefore by equating them, we can solve for x2x - 5 = -2/3x + 3Step 2 : Convert fractions in the equation to whole numbers.
The value -2/3 is a fractionWe can make it a whole number if multiply throughout by the value of its denominator ⇒ 33(2x - 5) = 3(-2/3x + 3)6x - 15 = -2x + 9Step 3 : Bring x terms to one side and constant terms to the other.
6x + 2x = 9 + 158x = 24x = 3Step 4 : Solve for y by plugging the value of x into one of the given equations.
y = 2(3) - 5y = 6 - 5y = 1Please help
Simplify:
Answer:
-9 3/4a+10 2/5
Step-by-step explanation:
-12 * 5/6a = -10a
-12 * -7/8 = 10 1/2
1/14 * 3 1/2a = 1/4 a
1/14 * -1 2/5 = -1/10
Put it together: -10a + 10 1/2 + 1/4a - 1/10
-10a+1/4a = -9 3/4a
10 1/2-1/10= 10 2/5
-9 3/4a + 10 2/5
A cylinder has a height of 19 meters and a radius of 10 meters. What is its volume? Use ≈ 3.14 and round your answer to the nearest hundredth
Answer:
Pi times radius to the power of two times the height
Step-by-step explanation
i gave you the formula now solve
Logan and Rita each open a savings
account with a deposit of $8,100. Logan's
account pays 5% simple interest annually.
Rita's account pays 5% interest
compounded annually. If Logan and Rita
make no deposits or withdrawals over the
next 4 years, what will be the difference in
their account balances?
Answer: 134. 89 $
Step-by-step explanation: Dina wishes to 1000$ deposit into an investment account and then withdraw the total in the account in five years. She has the choice of two different accounts. Blue Star account: interest is earned at an annual interest rate of 6.13% compounded weekly (52 weeks in a year). Red Star account: interest is earned at an annual interest rate of 5.95% compounded continuously. Which investment account - Blue Star or Red Star - will result in the greatest total at the end of five years? What is the total after five years for this account? How much more is it than the total for the other account?
show that the function F(x)=x3 +2x is odd. show all work and explain
a function is odd if f(-x) = - f(x)
f(x) = x³ + 2x
and
f(-x) = (-x)³ + 2 * (-x) = - x³ - 2x = - (x³+2x) = - f(x)
Answer:
Step-by-step explanation:
tlk here
Determine the type of symmetry of r=-7+ 2cos3ø from the equation, if any. Make sure to confirm graphically. Symmetric with respect to the:
A) pole
B) none of these
C)line /2
D) polar axis
well, hmmm to check for polar symmetry, hmmm say we simply replace the value for either "r" or "θ" or both in the original equation, if the equation rendered is the same as the original, there you have it, symmetry, so let's do that.
[tex]\underline{\textit{testing for symmetry to the }\frac{\pi }{2}~line\qquad \qquad r=-r~~,~~\theta =-\theta } \\\\\\ r=-7+2cos(3\theta )\implies (-r)=-7+2cos[3(-\theta )]\implies -r=-7+2cos(-3\theta ) \\\\\\ \stackrel{symmetry~identity}{-r=-7+2\stackrel{\downarrow }{cos(3\theta )}}\implies r=7-2cos(3\theta )\impliedby \textit{woopsie, no dice} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\underline{\textit{testing for symmetry to the polar axis}\qquad \qquad \theta =-\theta} \\\\\\ r=-7+2cos(3\theta )\implies r=-7+2cos[3(-\theta )]\implies r=-7+2cos(-3\theta ) \\\\\\ \stackrel{symmetry~identity}{r=-7+2\stackrel{\downarrow }{cos(3\theta )}}\impliedby \textit{low and behold\qquad \Large \checkmark}[/tex]
now, we could run a test for "the pole" or namely the origin by simply changin r = -r, however we already know where the symmetry is, so no need.
Check the picture below.
how many feet is the answer?
Answer:
The Inch To Feet Calculator is available online here for free at BYJU'S. One inch is equal to 0.083333 feet. One foot is equal to 12 inches.
Step-by-step explanation:
What is the MAD of this data ? Round to the nearest hundredth. 7, 14, 15, 9, 11, 14, 11, 10, 17
Step 1 :
Find the mean of the data :
(2+4+6+8) / 4 = 20/4 = 5
Step 2 :
Find the distance between each data and mean.
Distance between 2 and 5 is 3
Distance between 4 and 5 is 1
Distance between 6 and 5 is 1
Distance between 8 and 5 is 3
Step 3 :
Add all the distances :
3+1+1+3 = 8
Step 4 :
Divide it by the number of data :
8 / 4 = 2
2 is the average absolute deviation.
So hence, your answer is 2.67"The beautiful thing about learning is that no one can take it away from YOU"
B.B.King
Find the x- and y-intercepts of y=−x/2−1.
Step-by-step explanation:
y = -x/2 - 1
the y-intercept is right there : -1.
it is the y-value when x = 0
the point of y-intercept is therefore (0, -1).
the x-intercept is the other way around. it is the x- value when y = 0.
0 = -x/2 - 1
1 = -x/2
-2 = x
the point of x-intercept is therefore (-2, 0)
Find the volume of the triangular prism? (PLEASE HELP ILL MARK BRAINLIEST)
Answer:
▲ Base and height. This is the basic volume equation of a triangular prism: Volume = 0.5 * Base * Height * Length. ...
◣ Right triangle. Probably the most popular type of prism! ...
▲ 3 sides. Volume = 0.25 * √( (a+b+c) * (-a+b+c) * (a-b+c) * (a+b-c) ) * Length.
Step-by-step explanation:
Please helpppppppppppppp <3
Answer:
Part 1: -10, -5, 0, 8 Part 2: -3/2, -15%, 0.80, 143%, 2 1/4
Step-by-step explanation:
Part 1: The lower the number, the lower the temperature
Part 2: Convert the fractions into decimals
2 1/4 = 2.25
-15% = -0.15
143% = 1.43
-3/2 = -1.5
0.80 = 0.80
The order from least to greatest is -3/2, -15%, 0.80, 143%, 2 1/4
Hope this helps :)
how do i solve (2[tex](\frac{2}{3} r^{2} s^{7} )^{2} * (\frac{1}{6} r^{3}s)[/tex]
Answer:
5x+1=7
Step-by-step explanation:
High-efficiency particulate air (HEPA) filters are designed to remove which sized particles from the environment? 0.1 microns or smaller a) b) 0.3 microns or larger O c) 0.1 microns or larger d) 0.3 microns or smaller
Answer:
(b) 0.3 microns or larger
Step-by-step explanation:
A particle of size 0.3 microns is judged to be the most penetrating particle size. So, a rating for the filtering of those particles will be a worst-case rating. For particles of any other size, the filter will perform better than for 0.3 micron particles. HEPA filters are rated based on their performance with particles ...
0.3 microns or larger
Find the midpoint of AB A(-1,2) B(0,-14)
Answer:
given ,
two points A ( -1 , 2 ) and B ( 0 , -14 )
to find - coordinates of midpoint of A and B______________________________________
[tex]\fbox\pink{Solution -}[/tex]
let the midpoint be P ( x , y )
using midpoint formula ,
[tex]P(x,y) = ( \frac{ x_{1} + x_{2} }{2} , \frac{ y_{1} + y_{2} }{2} ) \\ \\ P(x,y) = ( \frac{ - 1 + 0}{2} , \frac{2 + ( - 14)}{2} ) \\ \\ (x,y) = ( \frac{ - 1}{2} , \frac{ - 12}{2} ) \\ \\ x = \frac{ - 1}{2} \\ \\ y = \frac{ - 12}{2} => - 6[/tex]
thus ,
the coordinates of the midpoint are
[tex]\red{P( \frac{ - 1}{2} , - 6)} \\ \\ or \\ \\ \red{P( -0.5 , - 6 )} [/tex]
hope helpful :D
Answer:
Step-by-step explanation:
A(-1,2) x₁ = -1 & y₁ = 2
B(0 ,-14) x₂ = 0 & y₂ = -14
[tex]\text{ \sf Midpoint = $\left(\dfrac{x_{1}+x_{2}}{2} ,\dfrac{y_{1}+y_{2}}{2}\right)$ }[/tex]
[tex]= \left (\dfrac{-1+0}{2} ,\dfrac{2+[-14]}{2} \right) \\\\\\=\left(\dfrac{-1}{2}, \dfrac{-12}{2}\right)\\\\\\=\left( -0.5 , -6 \right)[/tex]
What effect does changing the function f(x)=3sin(x)+1to the function g(x)=3sin(x/4)+2 have on the graph of f(x)?
The graph is compressed vertically by a factor of 4 and shifted right 1 unit.
The graph is stretched horizontally by a factor of 4 and shifted up 1 unit.
The graph is stretched vertically by a factor of 4 and shifted down 1 unit.
The graph is compressed horizontally by a factor of 4 and shifted left 1 unit.
Answer:
The graph is stretched horizontally by a factor of 4 and shifted up 1 unit
Step-by-step explanation:
The effect of transforming the function is (b) The graph is stretched horizontally by a factor of 4 and shifted up 1 unit
How to interpret the transformations of the functions?The functions are given as:
f(x) = 3sin(x)+1
g(x) = 3sin(x/4)+2
Start by stretching the function f(x) horizontally by a scale factor of 4.
So, we have:
f'(x) = 3sin(x/4) + 1
Next, shift the function f'(x) upward by 1 unit.
So, we have:
f'(x) = 3sin(x/4) + 1 + 1
Evaluate the sum
f'(x) = 3sin(x/4) + 2
Rewrite as:
g(x) = 3sin(x/4) + 2
Hence, the effect of transforming the function is (b) The graph is stretched horizontally by a factor of 4 and shifted up 1 unit
Read more about function transformation at:
https://brainly.com/question/17586310
Math Correct answers only please!!
Put question number with correct letter (ex: 1:a, 2:c, 3:d....etc)
Answer:
See below for answers and explanations
Step-by-step explanation:
Problem 1
Rewrite and add each vector:
[tex]p=\langle40cos70^\circ,40sin70^\circ\rangle\\q=\langle50cos270^\circ,50sin270^\circ\rangle\\r=\langle60cos235^\circ,60sin235^\circ\rangle\\p+q+r=\langle40cos70^\circ+50cos270^\circ+60cos235^\circ,40sin70^\circ+50sin270^\circ+60sin235^\circ\rangle\\p+q+r\approx\langle-20.73,-61.56\rangle[/tex]
Find the magnitude of the resulting vector:
[tex]||p+q+r||=\sqrt{x^2+y^2}\\||p+q+r||=\sqrt{(-20.73)^2+(-61.56)^2}\\||p+q+r||\approx64.96[/tex]
Therefore, the best answer is D) 64.959
Problem 2
Think of the vectors like this:
[tex]t=\langle7cos240^\circ,7sin240^\circ\rangle\\u=\langle10cos30^\circ,10sin30^\circ\rangle\\v=\langle15cos310^\circ,15sin310^\circ\rangle[/tex]
By adding the vectors, we have:
[tex]t+u+v=\langle7cos240^\circ+10cos30^\circ+15cos310^\circ,7sin240^\circ+10sin30^\circ+15sin310^\circ\rangle\\t+u+v\approx\langle14.8,-12.55\rangle[/tex]
Since the direction of a vector is [tex]\theta=tan^{-1}(\frac{y}{x})[/tex], we have:
[tex]\theta=tan^{-1}(\frac{y}{x})\\\theta=tan^{-1}(\frac{-12.55}{14.8})\\\theta\approx-40.3^\circ[/tex]
Don't forget to take into account that the resulting vector is in Quadrant IV since the horizontal component is positive and the vertical component is negative, so we will add 360° to our angle to get the result:
[tex]\theta=360^\circ+(-40.3)^\circ\\\theta=319.7^\circ[/tex]
Therefore, the best answer is D) 320°
Problem 3
Again, rewrite the vectors and add them:
[tex]u=\langle30cos70^\circ,30sin70^\circ\rangle\\v=\langle40cos220^\circ,40sin220^\circ\rangle\\u+v=\langle30cos70^\circ+40cos220^\circ,30sin70^\circ+40sin220^\circ\rangle\\u+v\approx\langle-20.38,2.48\rangle[/tex]
Using the direction formula:
[tex]\theta=tan^{-1}(\frac{y}{x})\\\theta=tan^{-1}(\frac{2.48}{-20.38})\\\theta\approx-6.94^\circ[/tex]
As the vector is located in Quadrant II, we need to add 180° to our angle:
[tex]\theta=180^\circ+(-6.94)^\circ\\\theta=173.06^\circ[/tex]
Therefore, the best answer is D) 173°
Problem 4
Using scalar multiplication:
[tex]-3u=-3\langle35,-12\rangle=\langle-105,36\rangle[/tex]
Find the magnitude of the resulting vector:
[tex]||-3u||=\sqrt{x^2+y^2}\\||-3u||=\sqrt{(-105)^2+(36)^2}\\||-3u||=111[/tex]
Find the direction of the resulting vector:
[tex]\theta=tan^{-1}(\frac{y}{x})\\\theta=tan^{-1}(\frac{36}{-105})\\\theta\approx-18.92^\circ[/tex]
As the vector is located in Quadrant II, we need to add 180° to our angle:
[tex]\theta=180^\circ+(-18.92)^\circ\\\theta=161.08^\circ[/tex]
Therefore, the best answer is C) 111; 161°
Problem 5
Using scalar multiplication:
[tex]5v=5\langle25cos40^\circ,25sin40^\circ\rangle=\langle125cos40^\circ,125sin40^\circ\rangle[/tex]
Since the direction of the angle doesn't change in scalar multiplication, it only affects the magnitude, so the magnitude of the resulting vector would be [tex]||5v||=125[/tex], making the correct answer C) 125; 200°
Which set shows an average of 4?
A) A
B) B
C) A and B
D) none of the above
Answer:
B
Step-by-step explanation:
A) 1 + 1 + 1 + 1 = 4
4 / 4 = 1
B) 4 + 4 = 8
8 / 2 = 4
Answer: B
Step-by-step explanation:
find x correct to 2 decimal places
Answer:
Step-by-step explanation:
find the equation of the line that passes through point a and b
Answer:
y=2x-1
Step-by-step explanation:
Find the scale factor and ratio of perimeters for a pair of similar octagons with areas 9 ft^2 and 16 ft ^2 .
Answer:
3/4 ratio
Step-by-step explanation:
This is the answer
pls help me how do they get 9 7/5 = 10 2/5 ( its in the example number 1) plss help me i don't know :⊂
Answer:
INSTRUCTION FOLLOWED: write the sum as a mixed number where the fractional number is less than one.5/5 out of the 7/5 make ONE whole while 2/5 is left over.
The ONE whole is added to nine to make 10 and the remaining 2/5 is also added to the 10 hence 9 7/5 = 10 2/5
Step-by-step explanation:
INSTRUCTION FOLLOWED: write the sum as a mixed number where the fractional number is less than one.5/5 out of the 7/5 make ONE whole while 2/5 is left over.
The ONE whole is added to nine to make 10 and the remaining 2/5 is also added to the 10 hence 9 7/5 = 10 2/5
how to express 1 cm as a fraction of 1 meter in decimal form
[tex]\qquad\qquad\huge\underline{{\sf Answer}}♫[/tex]
Let's see ~
Remember : value of 1 meter = 100 centimeters
[tex]\qquad \sf \dashrightarrow \:1 \: m = 100 \: cm[/tex]
[tex]\qquad \sf \dashrightarrow \:1 \: cm = \frac{1}{100} \: m[/tex]
[tex]\qquad \sf \dashrightarrow \:1 \: cm = 0.01 \: m[/tex]
・ ．━━━━━━━†━━━━━━━━━．・
As we know
100cm=1mSo
turn down to fraction
[tex]\\ \rm\rightarrowtail \dfrac{1}{100}[/tex]
Turn to decimal
[tex]\\ \rm\rightarrowtail 0.01m[/tex]
Describe and correct the error in using the percent proportion to answer the question below
“6 is 6.25% of what number”
Using proportions, it is found that the error was treating the 100% value as a percent(100) instead of a decimal 1, hence the correct value is of 96.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three.
In this problem, we have that 100% = 1 of the number is w, while 6 is equals to 6.25% = 0.0625. Hence the rule of three is given by:
1 - w
0.0625 - 6
Applying cross multiplication:
0.0625w = 6.
w = 6/0.0625
w = 96.
The error was treating the 100% value as a percent(100) instead of a decimal 1, hence the correct value is of 96.
More can be learned about proportions at https://brainly.com/question/24372153
A cone has a hight of 18 meters and a radius of 10 meters what is its volume use 3.14
[tex]\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=10\\ h=18 \end{cases}\implies V=\cfrac{\pi (10)^2(18)}{3}\implies \stackrel{using~\pi =3.14}{V=1884}[/tex]
Stuart and Francisco designed a black rocket and a white rocket during an aerospace class. Both rockets were launched after class. During the launch, Stuart and Francisco recorded data of their rockets trajectories. Stuart modeled the black rockets distance from the ground, in feet, x seconds after it was launched with the graph. Francisco modeled the white rockets distance from the ground, in feet, x seconds after it was launched with the function g(x)= -16x^2 + 50x +7 . Both wanted to know what the greatest distance was from the ground for each rocket. Stuart obtained that his rockets greatest distance from the ground was [Drop down 1] while Francisco obtained a greatest distance of [Drop down 2].
We will see that for Stuart the maximum height is 30ft, and for Francisco it is 46.0625 ft
How to get the greatest distance from the ground?In the case of Stuart it is simple, as we have a graph, we just need to see the largest y-value on the graph. We can see that it is y = 30, then for Stuart, the largest distance from the ground is 30ft.
In the case of Francisco, we need to find the maximum of:
g(x)= -16x^2 + 50x +7
Notice that this is a quadratic of negative leading coefficient, so the maximum is at the vertex.
x = -50/(2*-16) = 25/16
Evaluating the function in 25/16 we get:
g(25/16) = -16*(25/16)^2 + 50*(25/16) +7 = 46.0625 ft
If you want to learn more about quadratic functions, you can read:
https://brainly.com/question/1214333
Need Help Asap!!
[tex] \: \: \: \: [/tex]
[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]
Let's check I the given pairs of triangles are congruent or not ~
problem 1[tex]\qquad \sf \dashrightarrow \:ABC \cong FED[/tex]
These triangles are congruent by SSS congruency, as it's three sides are equal.
・ ．━━━━━━━†━━━━━━━━━．・
problem 2[tex]\qquad \sf \dashrightarrow \:LMN \not \cong PQO[/tex]
・ ．━━━━━━━†━━━━━━━━━．・
These triangles are not congruent because they don't fulfill any congruency criteria.
problem 3[tex]\qquad \sf \dashrightarrow \: XVW \cong YZA [/tex]
These triangles are congruent by AAS congruency criteria, since two angles and one of the side is common.
・ ．━━━━━━━†━━━━━━━━━．・
problem 4[tex]\qquad \sf \dashrightarrow \: GHI \not \cong IJG [/tex]
These triangles are not congruent because they don't fulfill any criteria.
・ ．━━━━━━━†━━━━━━━━━．・
problem 5[tex]\qquad \sf \dashrightarrow \: PQR\cong QPO[/tex]
These triangles are congruent by SSS congruency, as it's two sides are equal and one side is common.
・ ．━━━━━━━†━━━━━━━━━．・
problem 6[tex]\qquad \sf \dashrightarrow \: JIK \cong HIG [/tex]
These triangles are congruent by SAS congruency, since two sides and Angle between them are equal.
・ ．━━━━━━━†━━━━━━━━━．・
Problem 7These given triangles are congruent by SSS congruency, because they have two equal sides and one common side in there.
・ ．━━━━━━━†━━━━━━━━━．・
problem 8[tex]\qquad \sf \dashrightarrow \: BCD \cong FED [/tex]
These triangles are congruent by ASA congruency, because they have one pair equal angles, one pair of vertical opposite angles (they are equal) and a side between them equal.
・ ．━━━━━━━†━━━━━━━━━．・
problem 9[tex]\qquad \sf \dashrightarrow \: LKM \cong LNM [/tex]
These given triangles are congruent by SSS congruency, because they have two equal sides and one common side in there.
➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖
What is the explict rule for the geometric sequence? 9,6,4, 8/3 Enter your answer in the box. an=
Answer:
an = 9(⅔)^(n-1)
Step-by-step explanation:
The formula for explicit is: An = a1(r)^(n-1)
multiply (−3/4b^2)(−6a^2b^5)
Step-by-step explanation:
(−3/4b^2)(−6a^2b^5)
= 9 a²b³
100 Points and Brainly.
Graph The equation: y=(-x)-6
Gibberish for points WILL NOT be tolerated.
Please, if you can, try to make the mark ON the picture I have provided, in red.
function : y = (-x) - 6
Find x-intercept :
(-x) - 6 = 0(-x) = 6x = -6Find y-intercept :
y = (-0) - 6 y = -6mark these two points on both the axis and draw a straight linear graph.
passes coordinates : (0, -6), (-6, 0)
[tex]\\ \rm\rightarrowtail y=-x-6[/tex]
Take some point s
(1,-7)(2,-8)(3,-9)Graph it
This is the question
Check the picture below, so the lines look more or less like so, so the shape that we'll be getting will be the shape of a bowl with a hole in it, thus we'll use the washer method.
the way I use to get the larger Radius is simply using the "area under the curve" method, namely f(x) - g(x), where g(x) in this case is the axis of rotation.
so to get "R" and "r" we can get it by
[tex]\stackrel{y = 1}{(1)}~~ - ~~\stackrel{\stackrel{\textit{axis of rotation}}{y = -3}}{(-3)}\implies 1+3\implies \stackrel{R}{4} \\\\\\ \stackrel{y = \ln(x)}{\ln(x)}~~ - ~~\stackrel{\stackrel{\textit{axis of rotation}}{y = -3}}{(-3)}\implies \stackrel{r}{ln(x)+3} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{R^2}{(4)^2}~~ - ~~\stackrel{r^2}{[\ln(x)+3]^2}\implies 16~~ - ~~[\ln^2(x)+6\ln(x)+9] \\\\\\ \ln^2(x)+6\ln(x)+7~\hfill \boxed{\displaystyle\int~[\ln^2(x)+6\ln(x)+7]dx}[/tex]