In this lab, you observed how pollutants affected the ________


of water. You also modeled and observed how pollution affected freshwater sources, including surface water and the water in the _________

Answer: See below

Step-by-step explanation:

a) There is a correlation between the number of employees in the plant and the number of products produced yearly. Specifically, a positive correlation exists because, as we can see on the table, as the number of employees increases, the number of products also increases. And the rate of increase is constant.

b) Let the function be: y = mx + b

When x = 0; y = 120

So:

120 = 0 + c

c = 120

Now the slope:

[tex]\text { Slope }=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{200-120}{10-0}=\frac{80}{10}=8[/tex]

Therefore, the equation that best fits the data is y = 8x + 120

c) The slope in the function represents the constant rate of change, meaning that as the number of employees increases by 1, the number of products produced monthly increases by 20. While the y-intercept of the plot, which is 120, indicates the constant number of products, that is to say, when there are no employees, there are still 120 products.

Answer:

84.78cube.yd

Step-by-step explanation:

Volume of cylinder= πr^2h

Answer:

15

Step-by-step explanation:

if 2x-10=12 then

2x=22 so

X=11

X+4= 15

Answer:

15

Step-by-step explanation:

1. we find what x is by finding out the first equation:

2x - 10 = 12

Add 10 to both sides (it cancels out on the first side)

-10 + 10 = 0 (cancels out)

12 + 10 = 22

2x = 22

Now we divide both sides by 2 to get x alone

22 divided by 2 = 11

X = 11

2. Now we can solve the equation x + 4:

Just fill in x, which as we solved, is 11

x + 4 = 11 + 4 = 15

Therefore, the value of x + 4 is 15.

Answer:

Delta does not have a relative extreme in the equation, so it is variable y It can not be true

Step-by-step explanation:

[tex]s = 5x + 3y[/tex]

There is an answer

The rest of the equation that has no substituted delta is not true, so the prime variables have relative extremes.

Answer:

[tex]A_{Circle} \approx 39.24\: units^2[/tex]

Step-by-step explanation:

Square ABCD is inscribed in a circle with center P such that BC = 5 units.

BD will be diagonal of the square as well as diameter of the circle.

[tex]BD = BC\times\sqrt 2[/tex]

[tex]\implies BD = 5\sqrt 2[/tex]

-> Diameter of the circle [tex](d) = 5\sqrt 2[/tex]

-> Radius of the circle [tex](r) = 2.5\sqrt 2=3.535\: units[/tex]

[tex]A_{Circle} =\pi(r)^2[/tex]

[tex]\implies A_{Circle} =3.14(3.535)^2[/tex]

[tex]\implies A_{Circle} =3.14(3.535)^2[/tex]

[tex]\implies A_{Circle} =39.2381465[/tex]

[tex]\implies A_{Circle} \approx 39.24\: units^2[/tex]

Answer:

0.92 cm

Step-by-step explanation:

Do not pick 0.920 as it is the same as 0.92 but 0.92 is always the preferable option

The accurate measurement for the length of the green box is indeed 0.92 cm.

To measure the length of the green box accurately, we must carefully analyze the given image. By comparing the green box to the provided scale, we can deduce the correct measurement.

Upon examination, the green box appears to span almost the entirety of the "0.1 cm" scale division and extends slightly beyond it. Given that the box reaches around 9 divisions on the scale, it is reasonable to deduce that its length is 0.92 cm. This is because it's covering 9 divisions of 0.1 cm each, and considering the small extension.

Hence, the accurate measurement for the length of the green box is indeed 0.92 cm. This value takes into account its coverage of 0.9 cm (9 divisions) and a slight extension, aligning with the provided options.

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#SPJ3

The function D represents the cost is  $175  for of x towels.

For the first 20 towels, the equation is simply 5x.

The 5 is the cost per towel ($5) times the number of towels sold up to and including 20 towels.

Replace x by 20 in given expression  we get the maximum cost

So the maximum cost of those 20 towels is $5 (20)=$100.

Looking at towels 21 and greater, the price drops to $3 each. Putting this in a formula,

Therefore we get,

3(x-20)+100

Which is $3 for the cost per towel, (x-20) since it starts with towel number 21, and +100 for the cost of the first 20 towels.

Let's try it for 45 towels using the formula

3 (45-20)+ 100

=3(25) + 100

=75+ 100

= $175

The function D represents the cost is  $175  for of x towels.

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Answer:

d

Step-by-step explanation:

edge 2022

Question 1: Area of the base

          ⇒ Area of a Triangle --> [tex]\frac{1}{2}*(base)*(height)[/tex]

                ⇒ Area = [tex]\frac{1}{2} * 6 * 8 = 3 * 8 =[/tex] 24 square kilometers

Question 2: Height of Pyramid

          ⇒ Height = 12 km

          ⇒ [tex]\frac{1}{3} *24 * 12 = 8 * 12[/tex] = 96 cubic kilometers

Hope that helps!

Answer:

13.75 is your answer

Step-by-step explanation:

find area of whole triangle 5.5*7*1/2=19.25

Find area of blank spot 5.5*2*1/2=5.5

Subtract 19.25-5.5=13.75

Answer:

a

Step-by-step explanation:

the solution to the system is at the point of intersection of the linear equations.

the lines intersect at (- 4, 3 )

then solution is (- 4, 3 )

We conclude that z-score = 0.0005 which is less than 5%.

To calculate the z-statistic,

We must first calculate the standard error.

Standard error is standard deviation divided by the square root of the population.

[tex]standard error=\frac{standard deviation }{\sqrt{population} }[/tex]

In this case, it is equal to 1.81.

The z-score is defined the distance from the sample to the population mean in units of standard error.

z = (26 – 20)/1.81 = 3.31

Therefore we conclude that  z-score = 0.0005 which is less than 5%.

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Answer:

each of the drinks are $3

Step-by-step explanation:

10 d d d /19 d=3


hope it help

Answer:

$3

Step-by-step explanation:

pizza-p

drink-d

p+3d=19

p=$10

10+3 (d)=19

3 (d)=19-10

3 (d)=9

d=9÷3

d=$3

[tex]\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ A=250(1 + 0.16)^{t}\implies A=250(1.16)^t \\\\[-0.35em] ~\dotfill[/tex]

[tex]A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\dotfill &1000\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ 1000=250(1.16)^t\implies \cfrac{1000}{250}=1.16^t\implies 4=1.16^t \\\\\\ \log(4)=\log(1.16^t)\implies \log(4)=t\log(1.16) \\\\\\ \cfrac{\log(4)}{\log(1.16)}=t\implies \stackrel{\textit{about 9 years and 4 months}}{9.34\approx t}[/tex]

The probability helps us to know the chances of an event occurring. The probability of event n occurring is 0.3.

The probability helps us to know the chances of an event occurring.

[tex]\rm{Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]

We know that for two independent events the probability of the two events occurring simultaneously is written as,

[tex]P(A \cap B) = P(A)\cdot P(B)[/tex]

Now, as we know the probability of event m occurring also we know the probability of both events occurring simultaneously, therefore, the probability of event n occurring can be written as,

[tex]P(A \cap B) = P(A)\cdot P(B)\\\\P(m \cap n) = P(m)\cdot P(n)\\\\0.138 = 0.46 \times P(n)\\\\P(n) = 0.3[/tex]

Hence, the probability of event n occurring is 0.3.

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[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \:40 + x + 25 = 180[/tex]

[tex]\qquad \sf  \dashrightarrow \:x + 65 = 180[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 180 - 65[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 115[/tex]

I hope you understood the procedure, please let me know if you have any doubts

The Laplace transform of the non-homogeneous second order differential equation is [tex]\mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}[/tex].

A Laplace transform is a frequency-based algebraic substitution method used to determine the solutions of differential equations in a quick and efficient manner.

In this question we shall use the following Laplace transforms:

[tex]\mathcal {L} \{f(t) + g(t)\} = \mathcal {L} \{f(t)\} + \mathcal {L}\{g(t)\}[/tex]   (1)

[tex]\mathcal {L} \{\alpha\cdot f(t)\} = \alpha\cdot \mathcal {L} \{f(t)\}[/tex]   (2)

[tex]\mathcal{L} \left\{y^{(n)} \right\} = s^{n}\cdot \matcal {L}\{f(t)\}-s^{n-1}\cdot y(0) -...-y^{(n)}(0)[/tex]   (3)

[tex]\mathcal {L} \{e^{-a\cdot t}\} = \frac{1}{s+a}[/tex]   (4)

Now we proceed to derive an expression fo the Laplace transform of the solution of the differential equation:

[tex]y'' -5\cdot y' = 8\cdot e^{4\cdot t}-4\cdot e^{-t}[/tex]

[tex]s^{2}\cdot \mathcal {L}\{f(t)\}-5\cdot y(0) - y'(0) - 5\cdot s \cdot \mathcal {L} \{f(t)\} +5\cdot y(0) = \frac{8}{s-4}-\frac{4}{s+1}[/tex]

[tex]\mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}[/tex]

The Laplace transform of the non-homogeneous second order differential equation is [tex]\mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}[/tex]. [tex]\blacksquare[/tex]

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The Laplace transform Y'' − 5y' = 8e4t − 4e−t when y(0) = 1, y'(0) = −1 for f(t) = 8e4t − 4e−t would be  [tex]\frac{4(s+6)}{s.(s-4)(s+1).(s-5)} + \frac{1}{s} - \frac{1}{s.(s-5)}[/tex].

A Laplace transform is a frequency-based algebraic substitution method used to determine the solutions of differential equations quickly and efficiently.

The Laplace transform

L[ f(t) + g(t) ] = Lf(t) + Lg(t)

Also,

L [[tex]y^{n}[/tex]] = [tex]s^{n} . L[ f(t) ] - s^{n-1} .y(0) .....y^{n}(0)[/tex]

We have

Y'' − 5y' = 8 . e^4t − 4 . e−t

[tex]s^{2} . L[ f(t) ] - 5. y(0)- y'(0) .....y^{n}(0)[/tex]

y(0) = 1, y'(0) = −1  

for f(t) = 8e4t − 4e−t.

= [tex]\frac{8}{s-4} - \frac{4}{s+1}[/tex]

L [f(t)] = [tex]\frac{4(s+6)}{s.(s-4)(s+1).(s-5)} + \frac{1}{s} - \frac{1}{s.(s-5)}[/tex]

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Using it's concept, it is found that the domain and range of the function are given by:

D: [–4, ∞) and R: [0, ∞)

In this problem, the function is:

[tex]g(x) = \sqrt{x + 4}[/tex]

The square root function does not exist for negative values, hence the domain is represented by:

[tex]x + 4 \geq 0 \rightarrow x \geq -4[/tex]

The range of the square root function is [tex]x \geq 0[/tex], which remains the same as there are no vertical translations.

Hence the correct option is given by:

D: [–4, ∞) and R: [0, ∞)

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Answer: C) D: [–4, ∞) and R: [0, ∞)

Step-by-step explanation:

Answer:

$1.5

Step-by-step explanation:

12 x 1.75 + 6c = 30

21 + 6c = 30

6c = 30 - 21

6c = 9

c = 9/6

c = 1.5

Answer:

do face reveal

Step-by-step explanation:

we don't talk about bruno

Answer:

160 000

Step-by-step explanation:

400 000 - 240 000 = 160 000

Answer:

39

Step-by-step explanation:

you can set a proportion

84/156 = 21/x

when u solve for x u get 39

Answer:

Step-by-step explanation:

29-9=20

9-(-11)=20

50×-20=-1000

-1000+29=-971

Answer:

78.42

Step-by-step explanation:

[tex]1.06(24.99 + 48.99)[/tex]

[tex]1.06 \times 73.98 = 78.42[/tex]

Answer:

Add 509 and 476; The Roman Era lasted for a total of 985 years from 509 B.C to 476 A.D.

Step-by-step explanation:

Answer:

3/2

use a calculator to try it on your own

do the 1/4 - 4/9 (4/2/3-11/12) first

then times 9/17

then plus 1/1/8

at last divide by 9/16

Answer:

exuse me but i dont see the questions

Step-by-step explanation:

Answer:

I think the answers is 27, just add all of those squares.

The amount of money that you will need to pay them back after the 6 months is $2,070.

Given the following data:

Interest rate = 7% = 0.07.

Simple interest = $2000.

Time = 6 months.

Conversion:

12 months = 1 year.

6 months = 0.5 year.

Mathematically, simple interest is given by this formula:

[tex]I=PRT[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]I=2000 \times 0.07 \times 0.5[/tex]

I = $70.

Amount to be paid;

[tex]A=I+P\\\\\A=70+2000[/tex]

A = $2,070.

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Answer:

1. Find the circumference, then multiply that by 120 turns.

Formula for circumference;

C = 2πr

But, we need to find the radius which is 1/2(half) of the diameter, so,

D/2 = R

D = Diameter

R = Radius

20/2 = 10 is the radius.

Plug in values now:-

C = 2(3.14) x 10

C = 6.28 x 10

C = 62.8 is the circumference, now we multiply this by 120 to get the total amount of centimetres it'll go.

62.8(120)

= 7,536 cm it'll go.

2. Find the circumference, then multiply that by 750 turns/revolutions.

C = 2πr

Find radius,

D/2 = R

50/2 = 25 is the radius.

Plug in values now:-

C = 2(3.14) x 25

C = 6.28 x 25

C = 157 cm it'll go.

3. Same thing, find circumference then compare values.

Given that radius is 10,

Use the formula for circumference;

C = 2πr

Replace values:-

C = 2(3.14) x 10

C = 6.28 x 10

C = 62.8 cm is the circumference of the first circle.

Now the second circle, (use same formula)

C = 2πr

Find radius,

D/2 = R

10/2 = 5 is the radius.

Replace values:-

C = 2(3.14) x 5

C = 6.28 x 5

C = 31.4 cm is the circumference for the second circle.

Now subtract the second circle's circumference from the first:

62.8 - 31.4

= 31.4, 31.4 cm is how much greater the second circle is than the first.

4 - 5. Find circumference, (using circumference formula)

C = 2πr

Find radius,

D/2 = R

760/2 = 380

Replace values:-

C = 2(3.14) x 380

C = 6.28 x 380

C = 2,386.4 km is the distance he'll travel.

If he wants to travel around it with 2,000 km, he'll need to travel at least once.

Answer:

[tex]\boxed{\text{Slope = 5}}[/tex]

[tex]\boxed{\text{y-intercept = 1}}[/tex]

Step-by-step explanation:

To find the slope of the line, we must pick any two points on the line. Using those two points, we will calculate the Rise and the Run. Then, we will use the slope formula (Rise/Run) to find the slope. The y-intercept is the intersection of the point on the y-axis.

[tex]\text{My chosen points: (0,1) and (1,6)}[/tex]

[tex]\text{Rise = 5; Run = 1}[/tex]

≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡

[tex]\text{Slope}= \dfrac{\text{Rise}}{\text{Run}}[/tex]

➡ [tex]\bold{Slope = \frac{5}{1} = \underline{5}} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [\text{Rise = 5; Run = 1}][/tex]

[tex]\underline{........................................................................................................................}[/tex]

[tex]\text{Intersection on y-axis:} \ (0,1)[/tex]

➡ [tex]\text{y-intercept} \rightarrow (0,\bold{ 1}) \rightarrow \bold{\underline{{1}}}}[/tex]

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