Which equation has a vertex at (0, 5) and focus of (three-halves, 5)?

x = three-halves (y minus 5) squared
x = negative three-halves (y minus 5) squared
x = StartFraction 1 Over 6 EndFraction (y minus 5) squared
x = negative StartFraction 1 Over 6 EndFraction (y minus 5) squared

Answer: C

Answer:

if 5=70

  2=?

cross multiply=28

add  70+28=98          

Step-by-step explanation:

Answer:

x=6/5 and x=-(1/2)

Step-by-step explanation:

[tex]f(x) = 10x^3-37x^2+15x+18\\f(x) = \frac{(5x-6)(2x+1)(x-3)}{(x-3)}\\ f(x) = (5x-6)(2x+1)[/tex]

To find the zeros, we set f(x) = 0 for both factors

[tex]5x-6=0\\5x=6\\x=6/5[/tex]

[tex]2x+1=0\\2x=-1\\x=-1/2[/tex]

Therefore the zero's of f(x) are x = 6/5 and x= -(1/2)

Using vector concepts, it is found that the correct option regarding the magnitude and the tail is given by:

9.2 units, 49.4° north of west

To find them, we subtract the end coordinate by the start coordinate, hence:

RS = S - R = (-2, 1) - (4,-6) = (-6,7).

The magnitude is given by the square root of the sum of the squares of each coordinate, hence:

[tex]|RS| = \sqrt{(-6)^2 + 7^2} = \sqrt{85} = 9.2[/tex]

Considering a xy graph, the vector is decaying, that is, moving north of west, hence the correct option is:

9.2 units, 49.4° north of west

More can be learned about vectors at brainly.com/question/24606590

The force needed to keep the cart at rest is 149.022 pounds

Given Data

The force needed to keep the cart at rest is the vertical component of the resultant force, hence we have

Fy = Mg sin θ

Substituting our given data we have

Fy = 200 sin 40

Fy = 200 *0.74511

Fy = 149.022 pounds

Learn more about force here:

https://brainly.com/question/12970081

Answer:

128.558

Step-by-step explanation:

Answer:

79-22=57.

Your answer is correct. You also have to fill in the second one (B)

Answer:

79-22=57

Step-by-step explanation:

I can explain on phone

Answer:

862 m (nearest whole number)

Step-by-step explanation:

General form of an exponential function: [tex]\sf y=ab^x[/tex]

where:

If b > 1 then it is an increasing function

If 0 < b < 1 then it is a decreasing function

If the mountain is losing elevation at a rate of 5% every millennium , then it as every millennium passes, it will be 95% of the height it was in the previous millennium (as 100% - 5% = 95%)

Given:

Substituting these values into the formula:

[tex]\sf \implies y=1300(0.95)^8[/tex]

[tex]\sf \implies y=862.4467607...[/tex]

[tex]\sf \implies y=862 \ m \ (nearest \ whole \ number)[/tex]

Answer: A

Step-by-step explanation:

The radius of the circle is 7, and the center is at (6,-2), so if we substitute into the formula for the general equation of a circle, we get answer choice A.

Answer:

positive

Step-by-step explanation:

if you subtract a negative number, it’s the same as adding a positive number. If you add 2 positive numbers, you get a positive number, so the expression is positive.

Answer:

2.65

Step-by-step explanation:

5.60-2.95 = the sum of the money left.

Answer:

x = 52

Step-by-step explanation:

I have included a chart to identify which angles are congruent (only alternate exterior/interior and corresponding). Basically if they are not alternate exterior/interior or corresponding, then they add up to = 180 degrees.

So since these angles are same side interior, they add up to = 180 degrees. We can write this as: A + B = 180

A + B = 180

2x + 76 = 180

2x = 104

x = 52

I hope this helps!

Answer: x=52

Step-by-step explanation:

uh i just knew

Answer:

x = 30.9

Step-by-step explanation:

[tex]x = \frac{1}{2} (138 - 76.2) = \frac{1}{2} (61.8) = 30.9[/tex]

Answer:

12) x= 21

13) x = 1

14) x = 9

15) x = 1

Step-by-step explanation:

Here, we are being asked to solve the given equations and check our work.

To check the work, we need to substitute the found value of x into the equation to check if it makes a true and correct statement.

12) Solve for x:

[tex]\sf 12)\ \dfrac{2}{3}x + 2 = 16\ \textsf{[subtract 2 from both sides]}\\\\\implies \dfrac{2}{3}x + 2 - 2 = 16 - 2\\\\\implies \dfrac{2}{3}x = 14\ \textsf{[multiply both sides by 3]}\\\\\implies 3\left(\dfrac{2}{3}\right)x = 14(3)\\\\\implies 2x = 42\ \textsf{[divide both sides by 2]}\\\\\implies \dfrac{2x}{2}=\dfrac{42}{2}\\\\\implies \boxed{\sf x = 21}[/tex]

Check your work:

[tex]\sf \dfrac{2}{3}x + 2 = 16\ \textsf{[substitute 21 for the value of x]}\\\\\implies \dfrac{2}{3}(21) + 2 = 16\ \textsf{[multiply]}\\\\\implies \dfrac{42}{3} + 2 = 16\ \textsf{[divide]}\\\\\implies 14 + 2 = 16\ \textsf{[add]}\\\\\implies 16 = 16\ \checkmark \textsf{[true statement]}[/tex]

13) Solve for x:

[tex]\sf 13)\ \dfrac{x}{2} + \dfrac{x}{3} = \dfrac{5}{6}\ \textsf{[multiply both sides by 6 - LCM of 2, 3, and 6]}\\\\\implies 6\left(\dfrac{x}{2} + \dfrac{x}{3}\right) = 6\left(\dfrac{5}{6}\right)\ \textsf{[multiply]}\\\\\implies \left(\dfrac{6x}{2} + \dfrac{6x}{3}\right) = \dfrac{30}{6}\ \textsf{[divide]}\\\\\implies 3x+2x=5\ \textsf{[combine like terms]}\\\\\implies 5x = 5\ \textsf{[divide both sides by 5]}\\\\\implies \dfrac{5x}{5}=\dfrac{5}{5}\\\\\implies \boxed{\sf x = 1}[/tex]

Check your work:

[tex]\sf \dfrac{x}{2} + \dfrac{x}{3} = \dfrac{5}{6}\ \textsf{[substitute 1 for the value of x]}\\\\\implies \dfrac{1}{2} + \dfrac{1}{3} = \dfrac{5}{6}\ \textsf{[rewrite the fractions with a common denominator of 6]}\\\\\implies \dfrac{1\times3}{2\times3} + \dfrac{1\times2}{3\times2} = \dfrac{5}{6}\ \textsf{[multiply]}\\\\\implies \dfrac{3}{6} + \dfrac{2}{6} = \dfrac{5}{6}\ \textsf{[add]}\\\\\implies \dfrac{5}{6} = \dfrac{5}{6}\ \checkmark \ \textsf{[true statement]}[/tex]

14) Solve for x:

[tex]\sf 14)\ \dfrac{x-1}{6} - \dfrac{x+1}{8} = \dfrac{1}{12}\ \textsf{[multiply both sides by 24 - LCM of 6, 8, and 24]}\\\\\implies 24\left(\dfrac{x-1}{6} - \dfrac{x+1}{8}\right) = 24\left(\dfrac{1}{12}\right)\ \textsf{[multiply]}\\\\\implies \left(\dfrac{24x-24}{6}\right) - \left(\dfrac{24x+24}{8}\right) = \dfrac{24}{12}\ \textsf{[divide]}\\\\[/tex]

[tex]\sf\\\implies (4x-4)-(3x+3)=2\ \textsf{[distribute the negative sign]}\\\\\implies (4x-4)+(-3x-3)=2\ \textsf{[combine like terms]}\\\\\implies x - 7 = 2\ \textsf{[add 7 to both sides]}\\\\\implies x - 7 + 7 = 2 + 7\\\\\implies \boxed{\sf x = 9}[/tex]

Check your work:

[tex]\sf 14)\ \dfrac{x-1}{6} - \dfrac{x+1}{8} = \dfrac{1}{12}\ \textsf{[substitute 9 for the value of x]}\\\\\implies \dfrac{9-1}{6} - \dfrac{9+1}{8} = \dfrac{1}{12}\ \textsf{[simplify]}\\\\\implies \dfrac{8}{6} - \dfrac{10}{8} = \dfrac{1}{12}\ \textsf{[rewrite the fractions with a common denominator of 24]}\\\\\implies \dfrac{8\times4}{6\times4} - \dfrac{10\times3}{8\times3} = \dfrac{1\times2}{12\times2}\ \textsf{[simplify]}\\\\[/tex]

[tex]\sf\\\implies \dfrac{32}{24}-\dfrac{30}{24}=\dfrac{2}{24}\ \textsf{[subtract]}\\\\\implies \dfrac{2}{24}=\dfrac{2}{24}\ \textsf{[reduce]}\\\\\implies \dfrac{1}{12}=\dfrac{1}{12}\ \checkmark\ \textsf{[true statement]}[/tex]

15) Solve for x:

[tex]\sf \dfrac{1}{4}+\dfrac{x+1}{8}=\dfrac{1}{2}\ \textsf{[multiply both sides by 8 - LCM of 2, 4, and 8]}\\\\\implies 8\left(\dfrac{1}{4}+\dfrac{x+1}{8}\right)=8\left(\dfrac{1}{2}\right)\textsf{[multiply]}\\\\\implies \left(\dfrac{8}{4}+\dfrac{8x+8}{8}\right)=\dfrac{8}{2}\ \textsf{[divide]}\\\\\implies 2 + x + 1 = 4\ \textsf{[add]}\\\\\implies x + 3 = 4\ \textsf{[subtract 3 from both sides]}\\\\\implies x + 3 - 3 = 4 - 3\\\\\implies \boxed{\sf x = 1}[/tex]

Check your work:

[tex]\sf \dfrac{1}{4}+\dfrac{x+1}{8}=\dfrac{1}{2}\ \textsf{[substitute 1 for the value of x]}\\\\\implies \left(\dfrac{1}{4}+\dfrac{1+1}{8}\right)=\dfrac{1}{2}\ \textsf{[simplify]}\\\\\implies \left(\dfrac{1}{4}+\dfrac{2}{8}\right)=\dfrac{1}{2}\ \textsf{[reduce]}\\\\\implies \left(\dfrac{1}{4}+\dfrac{1}{4}\right)=\dfrac{1}{2}\ \textsf{[add]}\\\\\implies \dfrac{2}{4}=\dfrac{1}{2}\ \textsf{[reduce]}\\\\\implies \dfrac{1}{2}=\dfrac{1}{2}\ \checkmark\ \textsf{[true statement]}[/tex]

Answer:

7

Step-by-step explanation:

[tex]\dfrac{9 + 5}{2} \\\\\\= \dfrac{14}{2} \\\\\\= \dfrac{2 \times 7}{2} \\\\\\= \dfrac{7}{2 \div 2} \\\\\\= \dfrac{7}{1} \\\\\\= 7[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{9+5}{2}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{14}{2}[/tex]

[tex]\\ \rm\Rrightarrow 14\div 2[/tex]

[tex]\\ \rm\Rrightarrow 7[/tex]

Done!

Answer:

P'Q' ⇔ 8 cm

A'B' ⇔ 6 cm

M'N' ⇔ 12 cm

Step-by-step explanation:

A dilation with a scale factor of 4 is applied to the three line segments PQ, AB and MN.

The length of PQ is given as: 2 cm.

The length of line segment AB is given as: 1.5 cm

The length of line segment MN is given as: 3 cm.

Now as there is a dilation with a scale factor of 4 to all the line segments this means that the resulting image will have length 4 times the length of these line segments.

PQ → P'Q'

⇒ Length of P'Q'= 8 cm.   ( since 4×2=8)

AB → A'B'

⇒ Length of A'B'= 6 cm.   ( since 1.5×4=6)

MN → M'N'

⇒ Length of M'N'= 12 cm.   ( since 4×3=12)

Hence,

P'Q' ⇔ 8 cm

A'B' ⇔ 6 cm

M'N' ⇔ 12 cm

As no points are shown so only steps can be provided to solve

So if A(x,y) is dilated by scale factor 4 then 4 is multiplied with A(x,y)

So new coordinates are (4x,4y)

So

if length of segment was x then after dilation new length is 4x

Answer:

Ricky it is 1,202

And for Pedro 1202 + 276 = 1478

Step-by-step explanation:

The computation is shown below:

Let us assume the ricky be x,

So, pedro be x + 276

Now the equation is,

x + x + 276 = 2680

2x + 276 = 2680

2x = 2680-276

2x = 2404

x = 1,202

For Ricky it is 1,202

And for Pedro 1202 + 276=1478

Answer:

10sr2 or 14.1421356

Step-by-step explanation:

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

if the triangle is an Isosceles triangle, then it's other two angles measure 45° each.

So, let's use Trigonometry here :

[tex]\qquad \sf  \dashrightarrow \: \cos(45) = \dfrac{10}{x} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \dfrac{1}{ \sqrt{2} } = \dfrac{10}{x} [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 10 \sqrt{2} [/tex]

Therefore, the value of x is 10√2 units

180.....,...........

Step-by-step explanation:

angle A + angle B + angle C = 90+45+45

                                                = 180

Answer:

See below

Step-by-step explanation:

The change of base formula for logarithms is [tex]\log_a(x)=\frac{\log_b(x)}{\log_b(a)}[/tex]. This formula allows us to rewrite a logarithmic expression so that the new expression contains a different base.

Answer:

18.83% (nearest hundredth)

Step-by-step explanation:

Continuous Compounding Formula

[tex]\sf A=P(e)^{rt}[/tex]

where:

Given:

Substituting given values into the formula:

[tex]\sf \implies 1300=420(e)^{6r}[/tex]

[tex]\sf \implies \dfrac{1300}{420}=e^{6r}[/tex]

[tex]\sf \implies e^{6r}=\dfrac{65}{21}[/tex]

Taking natural logs of both sides:

[tex]\sf \implies \ln e^{6r}=\ln \dfrac{65}{21}[/tex]

[tex]\sf \implies 6r\ln e=\ln \dfrac{65}{21}[/tex]

[tex]\sf \implies 6r(1)=\ln \dfrac{65}{21}[/tex]

[tex]\sf \implies 6r=\ln \dfrac{65}{21}[/tex]

[tex]\sf \implies r=\dfrac16 \ln \dfrac{65}{21}[/tex]

[tex]\sf \implies r=0.1883108054...[/tex]

Therefore, the interest rate is 18.83% (nearest hundredth)

Answer:

a, c, d

Step-by-step explanation:

This is because there share the same answer:

12x + 6

hope this helps =)

Using the given exponential functions, it is found that the graph of g(x) will be less than than the graph of f(x) when x < 0.

The given exponential functions, f(x) and g(x), are respectively given by:

When x < 0, one possible value is x = -1, hence evaluating the functions at these values:

[tex]f(-1) = 3^{-1} = \frac{1}{3}[/tex]

[tex]g(-1) = 7^{-1} = \frac{1}{7}[/tex]

[tex]\frac{1}{3} > \frac{1}{7}[/tex], hence, the graph of g(x) will be less than than the graph of f(x) when x < 0.

More can be learned about exponential functions at https://brainly.com/question/25537936

Answer:

A.15.21

Step-by-step explanation:

In rounding of numbers when the next number is greater than 5 u round it on next number by adding one

LCM = 8

[tex]\frac{3}{8}[/tex] < [tex]\frac{6}{8}[/tex]

Finding the LCM is useful to compare the size of 2 different fractions.

LCM

First, let's define LCM. LCM stands for least common multiple. A multiple is a product of 2 numbers. For example, the multiples of 4 include 4, 8, 12, etc. The LCM of 4 and 8 is 8.

Comparing

Using the LCM we can find new fractions with the same denominator. These fractions are [tex]\frac{3}{8}[/tex] and [tex]\frac{6}{8}[/tex]. From this, we can tell that 6/8 is larger than 3/8.

Answer:

7.02ft

Step-by-step explanation:

Answer:

x=−5

y=−2

Step-by-step explanation:

{3x+4y=-23}{x=3y+1}

x=−5

y=−2

Step-by-step explanation:

the third angle in a triangle= 70

The characteristics of this scatter plot

Hence ,this scatter plot has Moderately postive linear relationship without any outliner

Answer:

y=2x+3

Step-by-step explanation:

Because the y-intercept starts at 3 and it goes up by 2 and to the side 1 so it would be y = 2x +3

Answer: y = 2x + 3

Step-by-step explanation:

    We will write the equation in slope-intercept form.

y = mx + b

    The slope can be found with "rise over run" since we have clear points on the graph.

    Start at (0, 3), count up 2 units, and count one unit to the right. This gives us a slope of positive 2.

    Rise / run = 2 / 1 = 2

    The "b" value is where the line hits the y-axis. It hits the y-axis at y-coordinate 3, so our y-intercept is positive 3.

    Final equation:

y = 2x + 3