If a car takes 3500j of total energy to make 1200j of useful energy, how energy efficient is it
Answer: 34%
Explanation: eff = (Eout/Ein) *100(for % form)
1200/3500 * 100 = 34%
What must be the charge of a particle having E = 81 N/C at 49 mm from the said particle? Express in Coulombs. Use k = 9.0 x 109 kg⋅m3⋅s−2⋅C−2
[tex]\text{Given that,}\\\\\text{Electric field strength,}~ E = 81 ~NC^{-1} \\ \\ \text{Distance,}~ d= 49mm = 49 \times 10^{-3} ~m\\ \\\text{Coulomb's constant,}~ k = 9\times 10^9 ~Nm^2 C^{-2}\\\\ \\E= k\dfrac{q}{d^2} \\\\\implies q=\dfrac{Ed^2}{k} = \dfrac{81 \times \left(49 \times 10^{-3}\right)^2}{9\times 10^9} = 2.1609\times 10^{-11} ~C\\\\\\\text{The charge of the particle is}~2.1609\times 10^{-11} ~C[/tex]
A 7 kg ball of clay traveling at 12 m/s collides with a 25 kg ball of clay traveling in the
same direction at 6 m/s. What is their combined speed if the two balls stick together
when they touch?
Answer:
Given:
m1 = 7 kg
V1 = 12 m/s
m2 = 25 kg
V2 = 6 m/s
To find:
Combined speed of two balls stick together after collision V = ?
Solution:
According to law of conservation of momentum,
m1V1 + m2V2 = (m1+m2)V
7×12 + 25×6 = (7+25)V
84 + 150 = 32V
V = 234/32
V = 7.31 m/s
Combined speed of two ball is 7.31 m/s
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A 700-kg car, driving at 29 m/s, hits a brick wall and rebounds with a speed of 4. 5 m/s. What is the car’s change in momentum due to this collision?.
Answer:
Explanation:
Change in car's momentum = 700 * [4.5 - {-29)] = 23,450 kgm/s
what is one type of compact star with a mass similar to the sun but a diameter similar to earth?
Explanation:
neutron star, any of a class of extremely dense, compact stars thought to be composed primarily of neutrons. Neutron stars are typically about 20 km (12 miles) in diameter. Their masses range between 1.18 and 1.97 times that of the Sun, but most are 1.35 times that of the Sun.
The jet engine of an airplane expels hot gas.
A. The airplane is propelled in the same direction as the hot gas.
B. The airplane is propelled in the opposite direction as the hot gas.
C. The airplane is propelled against the outside air.
Answer:
B. The airplane is propelled in the opposite direction as the hot gas.
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Which process describes the warm ocean that transfers heat to the air above it?
O conduction
O convection
O reflection
O radiation
Answer:
convection is the answer
The process that describes the warm ocean that transfers heat to the air above it is known as Convection. Thus, the correct option for this question is B.
What are some characteristics of heat?Some characteristics of heat are as follows:
It has no mass, shape, color, odor, volume, and weight.It is one of the invisible forms of energy.It stimulates the presence of warmth.It gets remarkably transferred from one body to another.This form of energy has the capacity to flow in each and every direction.The process of convection transfers heat with the help of the migration of a fluid (liquid or gas) between areas of different temperatures. It is an approach that signifies the transfer of heat between two bodies by involving currents of moving gas or fluid.
Therefore, convection is the process that describes the warm ocean that transfers heat to the air above it. Thus, the correct option for this question is B.
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Which of the following examples BEST describes the life characteristic of respiration?
A) A cheetah races across the plain.
B) Starfish cells divide and multiply as it gets larger.
C) Humans eliminate some wastes through urine and feces.
D) Humans breathe in oxygen and release carbon dioxide.
Answer:
D if I'm incorrect then sorry.
Explanation:
A capacitor of cylindrical shape as shown in the red outline, few cm long carries a uniformly distributed charge of 7.2 uC per meter of length. By constructing a suitable Gaussian surface around the wire, Find the magnitude and direction of the electric field at points
a)5.5m
b)2.5m
perpendicular from the center of the wire.
(a) The magnitude of the electric field at point 5.5m is 2.35 x 10⁴ N/C.
(b) The magnitude of the electric field at point 2.5m is 5.18 x 10⁴ N/C.
Electric field at a point on the Gaussian surface
The magnitude of the electric field at a point on the cylindrical Gaussian surface is calculated as follows;
E = λ/2πε₀r
where;
λ is linear charge densityε₀ is permitivity of free spacer is the position of the chargeAt a distance of 5.5 m[tex]E = \frac{\lambda}{2\pi \varepsilon _0 r} \\\\E = \frac{7.2 \times 10^{-6}}{2\pi \times 8.85 \times 10^{-12} \times 5.5} \\\\E = 2.35 \times 10^4 \ N/C[/tex]
At a distance of 2.5 m[tex]E = \frac{\lambda}{2\pi \varepsilon _0 r} \\\\E = \frac{7.2 \times 10^{-6}}{2\pi \times 8.85 \times 10^{-12} \times 2.5} \\\\E = 5.18 \times 10^4 \ N/C[/tex]
Thus, the magnitude of the electric field at points of 5.5m is 2.35 x 10⁴ N/C, and the magnitude of the electric field at points of 2.5m is 5.18 x 10⁴ N/C.
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What is the relationship between latent heat and the hydrogen bonds which hold the molecules together?
Answer:
The molecules form strong hydrogen bonds, and water has a correspondingly high latent heat of vaporization. When no strong bonds are present, heating a liquid can easily free the molecules to form a gas, and the latent heat of vaporization is low.
Explanation:
An object moves at a constant speed.
What will happen to this object's motion over time if no new forces are applied
A. it will change direction
B. it will increase speed
C. it will decrease in speed
D. It will maintain a constant speed
If no new force is applied then the motion of the object will maintain a constant speed over time. So, the correct option is (D).
What is Inertia?The inertia of a body is a property that resists efforts to set it in motion or, if it is already in motion, to change its speed or direction. A body's inertia is a passive characteristic which allows it to resist only active agents like forces and torques.
A moving body continues to move not because of its inertia but because there is no external force causing it to slow down, deviate from course, or accelerate. Newton's first law of motion explained the law of inertia that every object at rest or in uniform motion will remain in a straight line unless compelled to change its position by the action of an external force.
If no new force is applied to an object that moves at a constant speed, it will remain in its inertia of motion and the object will continue to move in the same direction with the same speed.
Thus, if no new force is applied then the motion of the object will maintain a constant speed over time. So, the correct option is (D).
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Which of the following is a renewable source of energy?
Tick one box.
A bio-fuel
B coal
C natural gas
D oil
Answer:
A. boi-gas
Explanation:
This may help u
define capacitance of a capacitor and state its SIbunit
Answer: what I know that the unit is farad
Explanation:
A rope is wrapped around a pulley many times. The pulley can be modeled as a solid disk of radius R and mass M, and a mass mA hangs vertically from the pulley. The mass is released from rest. show answer Incorrect Answer 25% Part (a) What is the magnitude of the tangential acceleration of the hanging mass?
The magnitude of the tangential acceleration of the hanging mass is 2mg/MR
Tangential acceleration of the hanging massThe tangential acceleration of the hanging mass around the pulley is determined from the principle of conservation of angular momentum as shown below;
τ = Iα
Where;
I is the moment of inertiaα is the angular velocity[tex]\alpha = \frac{\tau}{I} \\\\\alpha = \frac{mgR}{3/2MR^2} \\\\\alpha = \frac{2mgR}{3MR^2} \\\\\alpha = \frac{2mg}{3MR}[/tex]
Where;
m is the hanging massM is the mass of solid diskThe tangential acceleration is calculated as follows;
[tex]a = \alpha R\\\\a = \frac{2mg}{3MR} \times R\\\\a = \frac{2mg}{3M}[/tex]
Thus, the magnitude of the tangential acceleration of the hanging mass is 2mg/MR
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A cable with 19.0 N of tension pulls straight up on a 1.50 kg block that is initially at rest. What is the block's speed after being lifted 2.00 m ? Solve this problem using work and energy
The final speed of the block, after being lifted 2.00 m is 3.39 m/s
What is speed?Speed can be defined as the rate of change in the distance of a body.
To calculate the speed of the block after being lifted 2.00 m, first, we need to calculate the acceleration of the block using the formula below
Formula:
T-mg = ma......... Equation 1Where:
T = Tension in the cablem = mass of the cablea = accelerationg = acceleration due to gravityRestructuring the formula above,
a = (T-mg)/m............... Equation 2From the question,
Given:
T = 19 Nm = 1.5 kgg = 9.8 m/s²Substitute these values into equation 2
a = [(19)-(1.5×9.8)]/1.5a = 4.3/1.5a = 2.87 m/s²Finally, to calculate the speed of the block, we use the formula below.
v² = u²+2as.......... Equation 3Where:
v = Final speedu = initial speeda = accelerations = distanceFrom the question,
Given:
u = 0 m/sa = 2.87 m/s²s = 2.00 mSubstitute these values into equation 3
v² = 0²+(2×2×2.87)v² = 11.48v = √11.48v = 3.39 m/sHence, The final speed of the block, after being lifted 2.00 m is 3.39 m/s.
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Fill in the blanks with the correct types of energy.
Energy in 1 is Chemical energy, 2 is Thermal energy, 3 is electrical energy the correct answer is option B that is, Chemical, thermal and electrical energy.
Energy ConversionEnergy is the ability to do work.
The conservation of energy state that energy can neither be created nor be distroyed but can be transformed from one form to the other.
According to the question,
CASE 1
The furnance makes use of burning coal to process water to steam in a boiler. The energy involved is Chemical energy.
CASE 2
The steam produce by the boiler is used to power the rotation of the turbine. The energy involved is Thermal energy.
CASE 3
The rotation of the turbine helps the generator to produce electricity. The energy involved is electrical energy.
Therefore, the correct answer is option B that is, Chemical, thermal and electrical energy.
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. A rope is being used to pull a mass of 10 kg vertically upward. Determine the tension on the rope, if starting from rest, the mass acquires a velocity of 4 ms-1 in 8s [g= 10ms-2]
[tex]\text{Given that,}\\\\\text{Mass, m =10 kg}\\\\\text{Time, t = 8 sec}\\\\\text{Velocity, v = 4~m/s}\\\\\text{When a body is moving upwards,}\\\\\text{Tension,}~ T=mg +ma\\\\~~~~~~~~~~~~~~~=mg+m\left(\dfrac{v-u}t \right)\\\\~~~~~~~~~~~~~~~=10(10)+10\left(\dfrac{4-0}8\right)\\\\~~~~~~~~~~~~~~~=100+10\left(\dfrac 12\right)\\\\~~~~~~~~~~~~~~~=100+5\\\\~~~~~~~~~~~~~~~=105~N[/tex]
.
A
saloon car starting from rest will accelerates
to velocity of 48 km/h in 10 seconds. calculate
the
aceleration-
What’s the answer ?
Answer:
47
Explanation:
48km:1hr (10sec×60min=600hr)
¥ :600hr
1hr÷¥=1. 48×600÷1=2800
2800÷60=47
47 will be the acceleration
[tex]\text{Initial velocity,}~ u = 0 ~ ms^{-1}\\\\\text{Final velocity,}~ v = 48~kmh^{-1} = \dfrac{48\times 1000}{3600} ms^{-1} = 13.33 ms^{-1}\\ \\\text{Time,}~ t = 10~ sec\\\\\text{Acceleration,}~ a = \dfrac{v-u}{t} = \dfrac{13.33-0}{10} = \dfrac{13.33}{10} = 1.33 ~ ms^{-2}\\\\\text{Hence the acceleration of the car is}~ 1.33 ~ms^{-2}.[/tex]
How far back into the universe are we able to see? Explain.
Answer:
About 46 billion light years Because space expands so what we didn’t see before is what we could see now. An example could be how everyone thought Pluto was a regular sized planet but once you get a look at the bigger picture and compare it to other thing in space we now know Pluto is a dwarf planet.
A plant is sitting on a table.
What, if any, forces are acting on the plant? (If there are forces acting on the
plant, include what direction they are acting.)
1 - Gravity (down)
11- Static Friction
111 - Normal (support) Force (up)
IV - Air Resistance to the left)
V - Applied Force (to the right)
#1
Yes gravity is acting downwards
#2
No static friction as its at rest#3
Normal reaction is applied upwards#4
No air resistance$5
No Applied force
a=5i+4j-6k ,b=-2i+2j+3k ,c=4i+3j+2k. find the vector perpendicular to a and c
Answer:
Explanation:
You can use the cross product. Let the vector that perpendicular to a and c is [tex]\vec{d}[/tex], so:
[tex]\vec{d}=\vec{a}\times\vec{c}=\left|\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\5&4&-6\\4&3&2\end{array}\right] \right|=(8+18)\hat{i}-\hat{j}(10+24)+\hat{k}(15-16)=26\hat{i}-34\hat{j}-\hat{k}[/tex]
To check that c is perpendicular with a and b, do the dot product between c and a and also c and b and if the result is zero, you're true.
[tex]\vec{d}.\vec{a}=(26*5)-(34*4)+(6)=0[/tex] (c perpendicular to a)
[tex]\vec{d}.\vec{c}=(4*26)-(34*3)-(2*1)=0[/tex] (d perpendicular to c)
why do badminton players use rubber shoes while playing
Badminton shoes are specifically designed for badminton footwork and movement. Rubber that is anti-slip and wear-resistant is ideal for the soles of badminton shoes, while the midfoot area requires excellent shock-absorption and resilience
Answer:
It's the perfect shoe to wear on the fields they play on like so they don't slip
explain how a deflection magnetometer can be used to find the horizontal component of the Earth's magnetic field
Which statement best describes the circular flow model?
What is the force of the drag for a 65 kg bicyclist, initially at rest at the top of a hill coasts down the hill, reaching a speed of 15.5 m/s at the bottom of the hill. The distance is 60M. neglect any friction impeding the motion and the rotational energy of the wheels.
Height is 19M
Intial GPE is 12350J
KE is 7808J and loss is 4542 J
what property of light is suggested by the formation of shadows
Answer:
The reflection and rectilinear propagation of light helps in the formation of shadows and also tells light doesn't penetrate opaque materials.
how does the gravitational pull of the blue supergiants impact the direction of your star?
Answer:
Blue supergiants represent a slower burning phase in the death of a massive star. Due to core nuclear reactions being slightly slower, the star contracts and since very similar energy is coming from a much smaller area (photosphere) then the star's surface becomes much hotter.
Explanation:
I know this may not be the answer youre looking for, but hopefully this can help somehow!
A car travels at a speed of 40 m/s for 29.0 s;
what is the distance traveled by the car?
Answer: 1160 m
Explanation:
Speed = distance / time. Plug in 40 m/s for speed and 29 s for time in order to get the distance, 1160 m.
The figure (Figure 1) shows a pV diagram for 4.00×10−3 mole of ideal H2 gas. The temperature of the gas does not change during segment bc. What volume does this gas occupy at point c?
The volume that the gas will occupy based on the temperature given will be 0.80 liters.
How to calculate the volume?From the information, it was stated that the figure shows a pV diagram for 4.00×10−3 mole of ideal H2 gas and that the temperature of the gas does not change during segment bc.
Therefore, the volume will be:
= (0.20) × (2.0/0.50)
= 0.20 × 4
= 0.80
In conclusion, the volume is 0.80 liters.
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Three identical 6.67-kg masses hang at rest from three identical springs, numbered as in the figure. Each spring has an unstretched length of 0.23 m and a spring constant of 8.13 kN/m. How long, L , is spring 2?
[Hint: Draw some FBDs and apply Newton's second law. Remember to account for both the spring's stretch and its unstretched length.]
The length of the spring 2 due to arrangement of the equal masses is determined as 0.238 m.
Extension of the spring 2
The extension of the spring 2 is determined from the net force acting on spring 2.
F(net) = Kx
Net force on spring 2 = sum of forces acting downwards - sum of forces acting upwards.
Net force on spring 2 = (force on 2 + force on 3) - (force on 1)
F(net) = (m₂ + m₃)g - (m₁)g
F(net) = (6.67 + 6.67)9.8 - (6.67)9.8
F(net) = 130.732 - 65.366
F(net) = 65.366 N
x = F/k
x = (65.366)/(8130)
x = 0.00804 m
The length of spring 2 = x + 0.23 m
= 0.00804 m + 0.23 m = 0.238 m
Thus, the length of the spring 2 due to arrangement of the equal masses is determined as 0.238 m.
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