What phase of the moon would someone
on Earth see when the moon is at
Positions A through F?

Answer:

Explanation:

The picture is cut off so the wrecking ball and its path are not shown. It would be better if the whole picture is available.

Based on the written info, at the bottom of the path, the wrecking ball is moving at 10m/s.

The centripetal acceleration = velocity^2 / radius

= 10^2 / 25

= 100 / 25

= 4m/s^2

The centripetal force = mass * centripetal acceleration

= 600*4

= 2400N

As the ball is moving horizontally at the bottom, net vertical force is zero.

So Tension force in cable = Wrecking ball weight + Centripetal force

= 600*g + 2400

= 6000 + 2400; assuming g is 10m/s^2

= 8400N

Hi there!

We can use Ohm's law to solve:
[tex]V = IR[/tex]

V = Potential Difference (V)
I = Current (A)
R = Resistance (Ω)

We can rearrange the equation to solve for resistance:

[tex]R = \frac{V}{I}[/tex]

Plug in the given values to solve.  

[tex]R = \frac{10}{2} = \boxed{5 \Omega}[/tex]

In a vacuum all colors of light travel with same speed and this is the reason a white ray travels through the vacuum without going through any dispersion..

Speed of light is the distance per time light waves propagate through different materials. The value for the speed of light in a vacuum is now defined as exactly 299,792,458 metres per second.

Therefore, In a vacuum all colors of light travel with same speed and this is the reason a white ray travels through the vacuum without going through any dispersion

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Answer:

A,B,C

Explanation:

because that is true

For E = 200 gpa and i = 65. 0(106) mm4,  the slope of end a of the cantilevered beam  is mathematically given as

A=0.0048rads

Generally, the equation for the   is mathematically given as

[tex]A=\frac{PL^2}{2EI}+\frac{ML}{EI}[/tex]

Therefore

A=\frac{10+10^2+3^2}{2*240*10^9*65*10^6}+\frac{10+10^3*3}{240*10^9*65*10^{-6}}

A=0.00288+0.00192=0.0048rads

A=0.0048rads

In conclusion,  the slope is

A=0.0048rads

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The value of slope of end a of the cantilevered beam when E = 200 gpa and i = 65. 0(106) mm4 is 0.0048 rads.

The formula used to find the slope at the end of the cantilevered beam is,

[tex]A=\dfrac{PL^2}{2EI}+\dfrac{ML}{EI}[/tex]

Here, (M) is the momentum, (EI) is flexural rigidity, (P) is concentrated load and (L) is the length of the beam.

Concentrated load is 10 KN and uniform load is 3 kN/m. E = 200 gpa and i = 65. 0(106) mm4.

[tex]A=\dfrac{10+10^2+3^2}{2\times240\times10^9\times65\times10^6}+\dfrac{10+10^3\times3}{240\times10^9\times65\times10^{-6}}\\A=0.00288+0.00192A=0.0048 \rm\; rads[/tex]

Thus, the value of slope of end a of the cantilevered beam when E = 200 gpa and i = 65. 0(106) mm4 is 0.0048 rads.

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[tex]\text{Density,}\\\\~~~~~~~~\rho = \dfrac mV\\\\\\\implies V = \dfrac m{\rho}\\\\\\\implies V = \dfrac{7 \times 10^{-3}~ \text{kg}}{\tfrac{5.6 \times 10^{-3}~ \text{kg}}{ 10^{-6} ~\text{m}^3} }\\\\ \\\implies V = \dfrac{7 \times 10^{-3}~ \text{kg}}{5.6 \times 10^{-3} \times 10^6~~ \text{kg}~ \text{m}^{-3}}\\\\\\ \implies V = 1.25 \times 10^{-6}~ \text m^3\\\\\\\implies V =0.00000125~ \text m^3\\\\\text{Hence the volume of the coin is 0.00000125}~ \text m^3[/tex]

Answer:

D. P=1.2 kw, T=6kwh

Explanation:

P = A × V

P = 120×10

= 1200 watts or 1.2 kw

T = Watts × hr

1000

= 1200 × 5

1000

= 6 kwh

Answer:

Rolling friction

Explanation:

Option B is correct

Answer:

Temporary? You have two options

If you have a positively charged object, bring it close to the LEFT side of the ball (not touching it!).

If you have a negatively charged object, bring it close to the RIGHT side of the ball (again, not in contact).

Either way, the electron cloud will migrate towards the right side of the of your sphere.

Another option is to have a capacitor large enough to house the sphere inside it, and polarize it by attaching it to a DC source making sure that the negative plate of it is to the right of the sphere.

If all the mass of fuel and oxygen is burned to form gases of combustion, the downward velocity of these gases would be 12,505 m/s.

The principle of conservation of linear momentum states that, the total momentum of an isolated system is constant.

The downward velocity of thes gases is calculated as follows;

v1(m1 + m2) = v2(m2)

305(1000 + 25) = v2(25)

312,625 = 25v2

v2 = 312,625/25

v2 = 12,505 m/s

Thus, If all the mass of fuel and oxygen is burned to form gases of combustion, the downward velocity of these gases would be 12,505 m/s.

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The destructive interference formula for diffraction grating problems is [tex]d sin \theta = (n+\frac{1}{2})\lambda[/tex].

Destructive interference happens when the maxima of two waves are 180° out of phase a positive displacement of one wave is canceled exactly by a negative displacement of the other wave.

The formula for brighter patches resulting from constructive interference and darker patches resulting from destructive interference in a diffraction grating is:

[tex]\rm d sin \theta = n \lambda[/tex]

The grating spacing is denoted by d, the angle of light is denoted by a the fringe order is denoted by n, and the wavelength is denoted by [tex]\rm \lambda[/tex].

The destructive interference formula is now based on the fact that destructive interference occurs between the fringes.

Hence the destructive interference formula for diffraction grating problems is [tex]d sin \theta = (n+\frac{1}{2})\lambda[/tex].

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Answer:

A. dsin  =

Explanation:

Answer:

C: Net Torque divided by Moment of Inertia

Explanation:

Torque = Moment of Inertia x Angular Acceleration.

According to Newton's second law for rotational motion, an object's angular acceleration equals the net torque multiplied by the moment of inertia, not divided by it. The correct answer is (A)

Mathematically, it can be expressed as:

Angular acceleration (α) = (Net torque (τ) / Moment of inertia (I))

Where:

α = angular acceleration (measured in rad/s²)

τ = net torque (measured in Nm or kgm²/s²)

I = moment of inertia (measured in kgm²)

This equation shows that the angular acceleration of an object is equal to the net torque applied to it divided by its moment of inertia. So, the correct answer is (A) net torque multiplied by the moment of inertia.

To summarize, Newton's second law for rotational motion states that the angular acceleration of an object is directly proportional to the net torque applied to it and inversely proportional to its moment of inertia. The moment of inertia represents an object's resistance to changes in its rotational motion, while the net torque represents the total rotational force acting on the object.

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Answer: KE = 172.872 J

PE = 307.328 J

Explanation:

For KE: acceleration = change in velocity / time → 9.8 = final velocity - 0 (because initial velocity is zero) / 6s → final velocity after 6s = 58.8 m/s.

Now, plug this into: KE = 1/2(m)(v^2) → KE = 1/2(.1)(58.8^2) = 172.872 J.

For PE: Find the velocity after 10 s: acceleration = change in velocity / time → 9.8 = final velocity - 0 (because initial velocity is zero) / 10s → final velocity after 10s = 98 m/s.

Now, find the total height: (v final)^2 = (v initial)^2 + 2*a*d → 98^2 = 0^2 + 2*9.8*d → d = total height = 490 m.

Now, find the change in height after 6 s: (v final)^2 = (v initial)^2 + 2*a*d → 58.8^2 = 0^2 + 2*9.8*d → d = change in height after 6 s → 176.4 m

Now, subtract the change in height from the total height to get its height after 6s: 490-176.4=313.6m

PE = m*g*h → Pe=.1*9.8*313.6 = 307.328 J :)

Answer:

amplitude

Explanation:

When we increase the volume of a sound, the amplitude of the wave is increased. The frequency of a wave is related to its pitch. If the pitch is high, then the frequency of the wave is high. This means that the wave will looked squashed on an oscilloscope trace.

[tex]\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{l}{g}}[/tex]

[tex]\\ \rm\rightarrowtail T^2=4\pi^2\dfrac{l}{g}[/tex]

[tex]\\ \rm\rightarrowtail g=\dfrac{4\pi ^2\ell}{T^2}[/tex]

[tex]\\ \rm\rightarrowtail g=\left(\dfrac{2\pi\sqrt{l}}{T}\right)^2[/tex]

Answer:

-18,750N

Explanation:

90x1000

-------------

3600

u=25m/s

v=0m/s

v^2=u^2+2as

v=0

=625+(2×a×20)

625+40a

-625=40a

a= -15.625 m/s^2

F=ma

=(1200)(-15.625)

= -18,750N

The half life is the time taken for half the number of radioactive atoms originally present to remain. This is  the time that corresponds to exactly half of the original number of radioactive isotopes remaining in the system.

The half life is the time taken for half the number of radioactive atoms originally present to remain. We can plot the number of atoms against the time taken in a graph.

We can obtain the half life of the radioactive isotope from the graph by noting the time that corresponds to exactly half of the original number of radioactive isotopes remaining in the system.

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Answer:

Current for 12 ohms = 2.5

Explanation:

Ohm's Law:

Voltage = IR

Current = V/R

Resistance = V/I

Therefore, current = 30V/12 Ohms

30/12 = 2.5

So current for 12 ohms = 2.5

I hope this helps :>

For the electric field is measured for points at distances r,Electric field  is mathematically given as

E=19.9*10^{-5}c/m^3

Generally, the equation for the  electric field uniform charged is mathematically given as

[tex]E=\frac{lr}{3e0}[/tex]

Therefore

E=lr/3E0=3Ee0/r

Therefore

E=3*6*10^4*8.85*10^{-12}

E=19.9*10^{-5}c/m^3

In conclusion, E=19.9*10^{-5}c/m^3

E=19.9*10^{-5}c/m^3

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CQ

Complete question attached below

Answer:

What is your name?

Explanation:

no bro I don't know I am New of this app so I don't know

The electric potential energy of the charge will be =3.5*10^8 J  

Electric potential energy is the energy that is needed to move a charge against an electric field.

F=Force experienced by the charge = 3.6*10^-4 N

q1 = magnitude of charge producing the electric field

q2 = magnitude of charge experiencing the electric force

r1 = distance between the two charges

Electric force experienced by the charge is given using coulomb's law as

[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]

[tex]3.6\times 10^{-4}=\dfrac{9\times 10^9 q_1q_2}{(9.8\times 10^{-5})^2}[/tex]

[tex]q_1q_2=3.84\times 10^{-22}[/tex]

Electric potential energy of the charge can be given as

[tex]U=\dfrac{kq_1q_2}{r}[/tex]

[tex]U=\dfrac{(9\times 10^9)q_1q_2}{(9.8\times 10^{-5})^2}[/tex]

[tex]U=3.5\times 10^{-8}\ J[/tex]

Thus Electric potential energy of the charge can be given as [tex]U=3.5\times 10^{-8}\ J[/tex]

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The maximum value of the current depend on the frequency of the ac voltage source because it increases as the frequency increases.

The peak current of an ac source is the amplitude current flowing in the ac circuit.

The magnitude of the peak  current is calculated as follows;

I₀ = i/(sin ωt)

I₀ = i/(sin 2πft)

where;

i = I₀ x sin 2πft

From the equation above, as the frequency of the of the ac voltage source increases, the value of the ac current (i) increases.

Thus, the maximum value of the current depend on the frequency of the ac voltage source because it increases as the frequency increases.

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Answer:

the Moon is smaller in diameter than the United States

however. The United States is 2,545 km / 1,582 mi from north to south, and thus, the Moon is smaller across than the United States is wide.

Answer:

The moon is smaller than the earth.

Explanation:

Moon's Diameter is 2,159.1 mi

Earth's Diameter is 7,917.5 mi

Answer:

4500 N

Explanation:

F = ma

   = 1500 kg * 3 m/s^2 = 4500 N

edited to correct units !

What's the relationship

[tex]\\ \rm\Rrightarrow T=2\pi \sqrt{\dfrac{l}{g}}[/tex]

[tex]\\ \rm\Rrightarrow T^2g=4\pi ^2\ell[/tex]

[tex]\\ \rm\Rrightarrow\ell=\dfrac{T^2g}{4\pi^2}[/tex]

4A can be correct

The correct option is: 2A cm

In a simple harmonic motion, the particle moves back and forth around a mean position. The distance covered by the particle in one time period depends on the amplitude of the oscillation.

The time period (T) of a simple harmonic motion can be expressed in terms of the frequency (f) as:

T = 1/f

The frequency (f) of a simple harmonic motion can be related to the angular frequency (ω) as:

ω = 2πf

Therefore, the time period (T) can also be expressed in terms of the angular frequency (ω) as:

T = 2π/ω

The displacement of the particle at any time (t) during the simple harmonic motion can be expressed as:

x = A cos(ωt)

where x is the displacement, A is the amplitude, and cos(ωt) is the cosine function.

The particle moves from its initial position to its maximum displacement (+A), then back to its initial position, and finally to its maximum displacement in the opposite direction (-A), before returning to its initial position again. Therefore, the distance covered by the particle in one time period is twice the amplitude (2A).

Therefore, the correct option is:

2A cm

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Answer:

30 cm to 1 mm

Explanation:

30 cm to 1 mm

The forward force you exert on the fish and your backward action will allow you to reach the shore.

Newton's third law of motion states that for every action, there is an equal and opposite reaction.

Fa = -Fb

Let's assume the fish is held in the hook, this will give you the opportunity to throw the fish forward while still holding it.

When the the fish is thrown forward, you will move backwards with an equal force based on Newton's third law. Your backward momentum towards the shore will help to maintain equal linear momentum between you and the fish.

Thus, this forward force of the fish and your backward action will allow you to reach the shore.

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Answer:

I don't know

Explanation:

you need then search here

Answer:

An isotope is one of two or more species of atoms of a chemical element with the same atomic number and position in the periodic table and nearly identical chemical behavior but with different atomic masses and physical properties. In medicine, for example, cobalt-60 is extensively employed as a radiation source to arrest the development of cancer. Other radioactive isotopes are used as tracers for diagnostic purposes as well as in research on metabolic processes.

Hope this helps! Please let me know if you need more help, or if you think my answer is incorrect. Brainliest would be MUCH appreciated. Have a wonderful day!

Those isotopes which are unstable due to the presence of extra neutrons in their nuclei and emit various types of radiations are called radioactive isotopes. The radiations emitted are in the form of alpha particles, beta particles and gamma rays.

For eg :- carbon,hydrogen and chlorine.