What is the value of acceleration in the following conditions
when a body comes at its initial position after motion

Answer:  A. He developed the world's first star catalogue.

Explanation: Gan De's contribution to astronomy was the development of the world's first star catalogue , along with his colleague Shi Shen. He also made observations of the planets, particularly Jupiter, and may have been the first to describe one of Jupiter's moons. Unfortunately, all of Gan De's writings have been lost, but fragments of his works' titles and quoted fragments are known from later texts.

The third-largest continent, North America, with an area of 24,346,000 sq km.

Thus, The entire continent of North America, including any associated offshore islands, is located north of the Panama Canal, which connects it to South America.

It features a wide range of climates, from the sweltering heat of the tropics to the dry, icy cold of the Arctic. An icecap is always there, keeping the interior of Greenland permanently cold and climate.

Only briefly each summer do temperatures above zero degrees Fahrenheit rise in the vast, treeless tundra of North America. Low-lying regions in the deep south are constantly hot and wet. The majority of the rest of North America experiences chilly winters and mild summers.

Thus, The third-largest continent, North America, with an area of 24,346,000 sq km.

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The initial temperature of the cold water is 10°C.

Mass of the cold water, m₁ = 400 g = 0.4 g

Mass of the water to which the cold water is added, m₂ = 200 g = 0.2 g

Temperature of the water to which the cold water is added, T₂ = 70°C

Temperature of the mixture, T = 30°C

According to the principle of calorimetry,

m₁T₁ + m₂T₂ = (m₁ + m₂)T

(0.4 x T₁) + (0.2 x 70) = (0.4 + 0.2) x 30

0.4T₁ + 14 = 18

0.4T₁ = 18 - 14

0.4T₁ = 4

Therefore, the initial temperature of the cold water is,

T₁ = 4/0.4

T₁ = 10°C

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The speed of the air during the motion of the helicopter is 188 km/h.

The speed of the helicopter, v₁ = 220 km/h

The speed of wind, v₂ = 32 km/h

The speed of one moving body in comparison to another is referred to as the relative speed.

The relative speed of two bodies travelling in the same direction is determined by the speed differential between them.

The expression for the relative speed is given by,

Relative speed = v₁ - v₂

Therefore, the speed of the air is given by,

v = v₁ - v₂

v = 220 - 32

v = 188 km/h

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Since focal length cannot be negative for a converging lens, we take the positive value: f ≈ 41 cm Option C

To determine the focal length of the lens, we can use the lens formula, which relates the object distance (u), image distance (v), and focal length (f) of a lens. The lens formula is given by:

1/f = 1/v - 1/u

In this case, the object distance (u) is 25 cm and the image distance (v) is 64 cm. We can substitute these values into the lens formula to solve for the focal length:

1/f = 1/v - 1/u

1/f = 1/64 cm - 1/25 cm

To simplify the equation, we can find a common denominator:

1/f = (25 - 64) / (64 * 25)

1/f = -39 / (64 * 25)

Now, we can invert both sides of the equation to solve for the focal length:

f = (64 * 25) / -39

f ≈ -41.03 cm

Since focal length cannot be negative for a converging lens, we take the positive value:

f ≈ 41 cm

Therefore, the correct answer is option C) 41 cm.

It's important to note that in the lens formula, distances are measured with respect to the lens, with positive values indicating distances on the opposite side of the incident light. The negative value obtained for the focal length indicates that the lens is a converging lens, as expected. Option C

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Ohm's law is defined as the applied voltage (V) is directly proportional to the current flow (I) in the circuit. V =IR, where R is the resistance of the circuit that resists the current flow in the circuit, and the unit of resistance is the ohm.

From the given,

1) a) resistors in the circuit are connected in parallel, then the voltage in the circuit remains the same. The voltage across each resistor is 9V.

  b) the current in each resistor is given by, V=IR

I₁ = V/R₁ = 9/10kΩ=0.9mA.

I₂ = V/R₂ = 9/2kΩ = 4.5mA

I₃ = V/R₃ = 9/1kΩ = 9mA.

2) a) the resistances are connected in parallel, the effective resistance is 1/R(eff) = 1/R₁ + 1/R₂

1/R(eff) = 1/(100) + 1/(250)

           = 250+100/25000

          = 350/25000

          = 7/500

R₁(eff) = 500/7

1/R(eff) = 1/R₁ + 1/R₂

            = 1/350 + 1/200

            = 200+350/70000

            = 550/70000

            = 11/1400

R₂(eff) = 1400/11

Thus, the two effective resistances are connected in series,

R(e) = R₁(eff) + R₂(eff)

      = 500/7 + 1400/11

      = (500×11) + (1400×7)/77

      = 5500 + 9800 / 77

      = 15300/77

R(e) = 198 Ω.

B) total current, I = V/R

  I = 24 /198

   = 121mA.

3) a) the resistances are connected in series, the total resistance,

R(eff) = R₁ + R₂

         = 3+3

R(eff) = 6Ω

b)Current, I = V/R

I = 12/6

  = 2A

c)Power, P = I²R = 2×2×6

      P = 24W is the power in each bulb.

d) Power, P = VI = 12×2 = 24 W, is the power in battery.

4) a) the resistances are connected in parallel,

1/R(eff) = 1/R₁ + 1/R₂

           = 1/3 + 1/3

           = 2/3

R(eff) = 3/2Ω

b) In a parallel circuit, the voltage remains unchanged.

Voltage = 12V

c) Current, I = V/R

I₁ = V/R₁ = 12/3 = 4A

I₂ = V/R₂ = 12/3 = 4A.

d) power, P = I²R =4²3=48W.

e) Total current in the circuit, I = I₁+I₂

I = 4 + 4

 = 8A

f) power supplied by a battery, P = VI

P = 12×4 = 48 W.

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If the net work done on a particle is zero, the particle will move with a constant speed.

The principle of work and kinetic energy, often known as the work-energy theorem, states that the change in kinetic energy of a particle is equal to the sum of the entire work done by all of the forces acting on it.

So,

W = ΔKE

Thus, we can say that the kinetic energy of the particle will not change if the net work done on it is equal to zero.

As a result, the state of motion of the particle will not change, and thus the speed of the particle will also remain constant.

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In social psychology, a stereotype is a generalized belief about a particular category of people.

A stereotype can be described as the accepted, condensed, and essentialist opinion  with regards to certain population.

I should be nted hat his can be related to  gender identity, race  as well as ethnicity, country,  however there are other things that an be used frequently used to stereotype groups. Stereotypes are pervasively present in both the larger social structure and culture.

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Plasma lacks a precise form or volume, much like gas. It completes the empty space. Even though it is in the gaseous form, there is a difference because some of the particles are plasma-ionized.

High-energy particles are free to move around and fill the area they inhabit in the state of matter known as gas.

Neutral atoms or molecules often make up gaseous substances like air.

The ionised gas known as plasma, on the other hand, contains both positively and negatively charged particles.

It develops when a gas is subjected to an intense electric field or heated to incredibly high temperatures.

Plasma is a substance that may be found in stars, lightning, and fluorescent lights. It is also an essential component of many modern technology, like plasma TVs and fusion reactors.

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The maximum velocity of the freighter relative to the shore is 4 m/s.

To determine the maximum velocity of the freighter relative to the shore, we need to consider the velocities of the river and the freighter separately and then combine them. Since the freighter needs to travel against the flow of the water, we subtract the velocity of the river from the maximum speed of the freighter relative to the river.

Given that the river flows at 3 m/s relative to the shore, and the maximum speed of the freighter relative to the river is 7 m/s, we can subtract the river's velocity from the maximum speed of the freighter:

Max velocity of freighter relative to shore = Max velocity of freighter relative to river - Velocity of river

Max velocity of freighter relative to shore = 7 m/s - 3 m/s

Max velocity of freighter relative to shore = 4 m/s

This means that the freighter can travel upstream at a maximum speed of 4 meters per second relative to the stationary shore while overcoming the 3 m/s current flowing downstream in the Savannah River.

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Here are five potential-kinetic energy conversions that could be shown in the construction of a device: Pendulum, Roller Coaster, Wind-up Toy, Elastic Slingshot, Windmill.

Pendulum: A pendulum consists of a weight attached to a string or rod, suspended from a fixed point. When the weight is lifted to a certain height, it possesses gravitational potential energy.

As the weight is released, it swings back and forth, converting the potential energy into kinetic energy. At the highest point of each swing, the weight briefly comes to a stop and has maximum potential energy, which is then converted back to kinetic energy as it swings downward.

Roller Coaster: In a roller coaster, potential-kinetic energy conversions occur throughout the ride. When the coaster is pulled up to the top of the first hill, it gains gravitational potential energy.

As the coaster descends, the potential energy is converted into kinetic energy, resulting in a thrilling and high-speed ride. Subsequent hills and loops continue to convert potential energy into kinetic energy and vice versa as the coaster moves along the track.

Wind-up Toy: Wind-up toys typically have a spring mechanism inside. When the toy is wound up, potential energy is stored in the wound-up spring. As the spring unwinds, it transfers its potential energy into kinetic energy, causing the toy to move or perform actions. The kinetic energy gradually decreases as the spring fully unwinds.

Elastic Slingshot: With an elastic slingshot, potential-kinetic energy conversions are evident when the slingshot is stretched. As the user pulls back on the elastic band, potential energy is stored.

Windmill: Windmills harness the kinetic energy of the wind and convert it into other forms of energy. As the wind blows, it imparts kinetic energy to the blades of the windmill. The rotating blades then transfer this kinetic energy into mechanical energy, which can be used for various purposes such as grinding grains or generating electricity.

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According to figure where the point P is located so that the magnitude of the Field at point p= Zero electric field will be [tex]E=\frac{1}{4\pi \epsilon_0s^3} \sqrt{q^2d^2}[/tex].

The electric field is a fundamental concept in physics that describes the force experienced by a charged particle in the presence of other charges. It is a vector field, which means it has both magnitude and direction at each point in space.

The electric field is created by electric charges. A positive charge creates an outward electric field, while a negative charge creates an inward electric field.

The strength or magnitude of the electric field at a given point depends on the magnitude of the charge creating the field and the distance from that point to the charge.

E due to the dipole formed by charges at extreme end,

[tex]E_x=k_p/d^3[/tex] in the x-direction

E due to the charge at center

[tex]E_y=k_q/d^3[/tex]

Net electric field is,

[tex]E=\frac{1}{4\pi \epsilon_0s^3} \sqrt{q^2d^2}[/tex]. as p = 0.

Thus, the answer is  [tex]E=\frac{1}{4\pi \epsilon_0s^3} \sqrt{q^2d^2}[/tex].

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Your question seems incomplete, the probable complete question is:

According to figure below where the point P is located so that the magnitude of the Field at point p= Zero ?

To determine the image characteristics using the 3 principal rays and SALTS (Size, Attitude, Location, Type), we'll consider both lenses and mirrors separately. Here's how you can analyze each case:

Lenses:

Place an object at different distances to the left of a lens with a focal length (f).

a) Object placed beyond 2f:

In this case, the object is placed far beyond twice the focal length of the lens.

Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.

Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.

Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.

The image will be formed on the opposite side of the lens, between the focal point and twice the focal length.

SALTS:

Size: The image will be smaller than the object.

Attitude: The image will be inverted.

Location: The image will be located between the focal point and twice the focal length.

Type: The image will be real.

b) Object placed at 2f:

In this case, the object is placed at twice the focal length of the lens.

Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.

Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.

Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.

The image will be formed on the opposite side of the lens at twice the focal length.

SALTS:

Size: The image will be the same size as the object.

Attitude: The image will be inverted.

Location: The image will be located at twice the focal length.

Type: The image will be real.

c) Object placed between f and 2f:

In this case, the object is placed between the focal point and twice the focal length of the lens.

In this case, the object is placed far beyond twice the focal length of the mirror.

Principal ray 1: A ray parallel to the principal axis will reflect through the focal point on the same side.

Principal ray 2: A ray passing through the focal point on the object side will reflect parallel to the principal axis.

Principal ray 3: A ray passing through the center of curvature will reflect back along the same path.

The image will be formed on the opposite side of the mirror, between the focal point and twice the focal length.

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The maximum speed that the small-mass object attains when it leaves the trebuchet horizontally is approximately 28.3 m/s.

To find the maximum speed that the small-mass object attains when it leaves the trebuchet horizontally, we can apply the principle of conservation of mechanical energy.

Initially, the trebuchet is at rest, so its total mechanical energy is zero. As the small-mass object leaves the trebuchet horizontally, it gains kinetic energy. At this point, all of the potential energy of the system is converted into kinetic energy.

The potential energy of the system can be calculated as the sum of the gravitational potential energies of the two masses:

PE = m1 * g * h1 + m2 * g * h2

Since the trebuchet is released from rest in a horizontal orientation, the initial height h1 is zero. The height h2 can be calculated as the perpendicular distance between the pivot point and the center of mass of the larger mass m2:

h2 = 13.0 cm = 0.13 m

Therefore, the potential energy simplifies to:

PE = m2 * g * h2

The kinetic energy of the small-mass object can be calculated as:

KE = (1/2) * m1 * v^2

where v is the maximum speed of the small-mass object.

Since the total mechanical energy is conserved, we have:

PE = KE

m2 * g * h2 = (1/2) * m1 * v^2

Plugging in the given values, such as g = 9.8 m/s^2, m1 = 0.115 kg, m2 = 68.5 kg, and h2 = 0.13 m, we can solve for v:

(68.5 kg * 9.8 m/s^2 * 0.13 m) = (1/2) * 0.115 kg * v^2

Solving for v, we find:

[tex]v^2 = (68.5 kg * 9.8 m/s^2 * 0.13 m) / (0.115 kg)[/tex]

[tex]v^2 = 800[/tex]

v ≈ 28.3 m/s

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Without knowing the forces exerted by Kari and Sandra, as well as the specific details about the stairs, we cannot determine who did more work. Option D

The amount of work done depends not only on the distance traveled but also on the force applied and the direction of the force. Without information about the force applied by both Kari and Sandra, we cannot determine who did more work.

Work is defined as the product of force and displacement in the direction of the force. In this case, the force exerted by Kari and Sandra while climbing the stairs is unknown.

If Kari and Sandra exerted the same amount of force while moving up the stairs, then the work done would be the same. However, if Sandra exerted a greater force compared to Kari, then Sandra would have done more work.

Additionally, the presence of stairs implies a vertical displacement. If Kari and Sandra were climbing stairs at the same height, the work done would be the same. However, if the stairs had different heights or slopes, the vertical displacement would differ, and that could affect the work done. Option D

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The tension force on object 2 must be one-fourth the tension force on object 1. The correct option is D.

The cross-sectional area is directly proportional to the square of the diameter, or A = πd²/4.

The Young's modulus is a constant for a given material.

Therefore, the change in length is proportional to the tension force and the square of the diameter.

For the two objects to have the same change in length, they must also have the same tension force.

The tension force is inversely proportional to the cross-sectional area, or F = EA/L0.

Therefore, the tension force is inversely proportional to the square of the diameter.

If object 2 has twice the diameter of object 1, then it will have four times the cross-sectional area.

Therefore, the tension force on object 2 must be one-fourth the tension force on object 1.

In other words, T2/T1 = 1/4.

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Answer:

5A

Explanation:

Answer:

Explanation:

Unfortunately, as an AI text-based model, I cannot directly view or interpret images. However, I can still provide you with the information you need to identify Polaris and its position in the night sky.

To locate Polaris using the stars of the Big Dipper (also known as the Great Dipper or Ursa Major), you can follow these steps:

1. Locate the Big Dipper: The Big Dipper is a prominent asterism, or a recognizable pattern of stars, within the constellation Ursa Major (the Great Bear). It is visible in the northern hemisphere during most of the year.

2. Identify the pointer stars: The two stars on the outer edge of the Big Dipper's bowl, farthest from the handle, are called the pointer stars. These stars are named Dubhe and Merak.

3. Extend the line between the pointer stars: Mentally extend an imaginary line that passes through Dubhe and Merak, extending it for approximately five times the distance between the pointer stars.

4. Locate Polaris: The extended line will lead you to Polaris, also known as the North Star. Polaris is relatively bright and appears as the last star in the handle of the Little Dipper (Ursa Minor constellation). It lies almost directly above the North Pole of the Earth and remains nearly fixed in the sky while other stars appear to rotate around it as the Earth rotates.

By following these steps, you should be able to identify Polaris and its position in the night sky, even without an image.

Polaris is positioned directly above the celestial North Pole in the sky, making it a useful navigation tool. The easiest way to locate it is by identifying the Great Dipper constellation and using its two pointer stars, Dubhe and Merak, to lead to the North Star.

The star Polaris, also known as the North Star, is beneficial for navigation due to its fixed position in the sky above the celestial North Pole. The best way to locate it is by first finding the Great Dipper constellation. Two stars in the bowl of this Dipper, named Dubhe and Merak, form a line that leads directly to Polaris.

In the given image, without the benefit of visual reference, it is difficult to identify the specific position of Polaris. However, remember that in actual practice, you would find the two pointer stars of the Great Dipper and follow a line from these stars to locate Polaris.

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Energy conservation refers to the principle that energy cannot be created or destroyed; it can only be converted from one form to another or transferred between different systems.

This principle is based on the law of conservation of energy, also known as the first law of thermodynamics. In order to comment on energy conservation in a diagram.

Energy conservation refers to the practice of reducing energy consumption and using energy resources efficiently in order to minimize waste and environmental impact. It involves making conscious choices and adopting behaviors and technologies that aim to conserve energy and reduce energy-related costs.

Energy conservation is an important aspect of sustainable development and plays a vital role in mitigating climate change and promoting environmental sustainability.

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We can measure the flow rate of various liquid by pouring the liquid down an incline and time how long it takes each one to reach the bottom.

option C.

The flow rate of a liquid is how much fluid passes through an area in a particular time.

Flow rate can be articulated in either in terms of velocity and cross-sectional area, or time and volume. As liquids are incompressible, the rate of flow into an area must be equivalent to the rate of flow out of an area.

Generally, the best equipment to measure the flow rate of a liquid is flow meters. In the absence of flow meters, we can other methods such as the one given in the options.

We can pour the various liquid down an incline and time how long it takes each one to reach the bottom.

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From the distant stars to the smallest particles, light allows us to perceive the world and unravel its mysteries. It is through light that we gather information about our surroundings, explore the cosmos, and make scientific discoveries.

Light not only illuminates our physical environment, but it also carries the stories of the past. When we look at distant objects in space, we are actually observing light that has traveled vast distances over millions or even billions of years. By analyzing the light emitted or reflected by celestial bodies, astronomers can study their composition, temperature, and movement. This information provides invaluable insights into the nature of our universe and its evolution.

Moreover, light plays a crucial role in many areas of scientific research. In fields such as optics, photonics, and quantum mechanics, scientists harness the properties of light to develop advanced technologies. From lasers to fiber optics, these innovations have revolutionized communication, medicine, and countless other industries.

Light is not only a carrier of information, but it also embodies the electromagnetic spectrum, which encompasses various types of radiation, each with its own characteristics and applications. For instance, visible light allows us to see the world around us, while infrared light reveals heat signatures and ultraviolet light exposes hidden details. X-rays and gamma rays, on the other hand, help us explore the microscopic realm and unravel the secrets of atomic and subatomic particles.

Beyond its scientific significance, light has metaphorical and symbolic meanings as well. It is often associated with knowledge, enlightenment, and wisdom. The phrase "seeing the light" is used to describe moments of realization or understanding. Light is a universal symbol of hope, guidance, and truth.

In summary, light is indeed the ultimate source of knowledge. Its ability to illuminate, reveal, and transmit information has profound implications for our understanding of the universe and our place within it. Whether we contemplate the wonders of the cosmos or appreciate the metaphorical significance of light, it remains an awe-inspiring force that continues to inspire and expand our horizons.

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Answer:

both objects are negatively charged.

Answer:

similar or identical traits.

Answer:

To round 52754.1683 to the nearest:

Thousand: 53000

Hundredth: 52754.17

Hundred: 52700

Tenth: 52754.2

Whole number: 52754

Explanation:

The strength of gravity on the moon is approximately 1.6 J/kg.

The change in gravitational potential energy (GPE) is given by the equation:

ΔGPE = m * g * Δh

where ΔGPE is the change in gravitational potential energy, m is the mass of the object, g is the strength of gravity, and Δh is the change in height.

In this case, the astronaut's GPE increases by 880 J as he climbs up the ladder by 5 m. We can rewrite the equation as:

880 J = (110 kg) * g * (5 m)

To find the strength of gravity on the moon (g), we can rearrange the equation:

g = 880 J / (110 kg * 5 m)

g = 1.6 J/kg

Therefore, the strength of gravity on the moon is approximately 1.6 J/kg.

It's important to note that the value of gravity on the moon is significantly lower than that on Earth. The moon has about one-sixth the gravity of Earth, which means objects weigh less on the moon compared to Earth. This lower gravity is due to the moon's smaller mass and smaller radius compared to Earth.

As a result, astronauts experience a different gravitational environment on the moon, which affects their movements and the energy required to perform tasks such as climbing.

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Answer: the type of collision is elastic collision because both momentum and kinetic energy are conserved.

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a.  output voltage is 110 V, the RMS output voltage is approximately 155.56 V, the output (load) current is 15.56 A, the ripple factor is 0.866, and the form factor is 0.866. b. the input active power is 2640 W, the input apparent power is 2640 VA, and the power factor is 1 (or unity).

a. For a single-phase full-bridge uncontrolled (diode) rectifier with a pure resistive load of R = 10 Ohms and neglecting diode volt-drops, we can calculate the following values:

Average Output Voltage:

The average output voltage of a full-bridge rectifier can be calculated as half of the peak input voltage. Since the input voltage is 220 V, the average output voltage will be:

Average Output Voltage = (220 V) / 2 = 110 V

RMS Output Voltage:

The RMS output voltage of a full-bridge rectifier can be calculated as the peak input voltage divided by the square root of 2. In this case, the RMS output voltage will be:

RMS Output Voltage = (220 V) / √2 ≈ 155.56 V

Output (Load) Current:

Since the load is pure resistive, the output (load) current will be the same as the RMS output voltage divided by the load resistance. Therefore:

Output (Load) Current = RMS Output Voltage / R = 155.56 V / 10 Ω = 15.56 A

Ripple Factor:

The ripple factor for a full-bridge rectifier can be calculated as the ratio of the RMS value of the ripple voltage to the average output voltage. In this case, since we are neglecting diode volt-drops, the ripple factor is:

Ripple Factor = √(3/4) ≈ 0.866

Form Factor:

The form factor is the ratio of the RMS value of the output current to its average value. Since the load is purely resistive, the form factor is the same as the ripple factor:

Form Factor = 0.866

b. Now, assuming the load has an inductive nature with L >> R and a load current of 12 Amperes:

Input Active Power:

The input active power can be calculated as the product of the RMS input voltage, RMS input current, and the power factor. In this case, since the load current is flat and equal to 12 Amperes, and we neglect diode losses, the input active power will be:

Input Active Power = (220 V) * (12 A) = 2640 W

Input Apparent Power:

The input apparent power can be calculated as the product of the RMS input voltage and RMS input current. Therefore:

Input Apparent Power = (220 V) * (12 A) = 2640 VA

Power Factor:

The power factor is the ratio of the input active power to the input apparent power. In this case, the power factor will be:

Power Factor = Input Active Power / Input Apparent Power = 2640 W / 2640 VA = 1 (or unity)

Note: Neglecting diode losses implies that we assume the diodes are ideal, without any voltage drops or losses during the rectification process. In practical scenarios, there will be some voltage drops across the diodes, and losses should be taken into account for more accurate calculations.

Therefore, a. For a single-phase full-bridge uncontrolled (diode) rectifier with a pure resistive load of 10 Ohms, neglecting diode volt-drops, the average output voltage is 110 V, the RMS output voltage is approximately 155.56 V, the output (load) current is 15.56 A, the ripple factor is 0.866, and the form factor is 0.866. b. Assuming a load with an inductive nature, L >> R, and a flat load current of 12 A, the input active power is 2640 W, the input apparent power is 2640 VA, and the power factor is 1 (or unity).

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The angles between X, Y, and Z are θx = θy = 63.6, θz = 27.2 with the resultant vector R = i + 2j + 4k.

From the given,

the resultant vector, R = i+2j+4k

Rx = 1

Ry = 2

Rz = 4

R² = Rx² + Ry² + Rz²

   = (1)² + (2)² + (4)²

  = 1+4+16

= 21

R = √21

 = 4.5

Thus, the resultant vector, R is 4.5.

The angles between x, y, and z.

cosθx = Rx/R = 1/4.5

θx = cos⁻¹ (0.22) = 77.1° in X- axis.

cosθy = Ry/R = 2/4.5

θy = cos⁻¹(0.44) = 63.6° in Y-axis.

cosθz = Rz/R = 4/4.5

θz = cos⁻¹(0.88) = 27.2 in Z-axis.

The angles are θx = 77.1°, θy =63.6°, and θz = 27.2° along X, Y, and Z axis.

To learn more about the angle between the resultant vector:

https://brainly.com/question/13954873

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