What is the length of AB?

Answer:

5 packages

Step-by-step explanation:

One package of blackberries cost $3

Let x represent the number of packages that will cost $15

1 = $3

x= $15

3x= 15

Divide both sides by the coefficient of x which is 3

3x= 15/3

x= 5

Hence 5 packages of blackberries will cost $15

Answer:

-177

Step-by-step explanation:

12(-14) -3(3)

-168-9

-177

Answer:

-177

Step-by-step explanation:

Plug in -14 for x and 3 for y:

12(-14) - 3(3)

Note that when you multiply a positive and a negative number, your answer will be negative.

Multiply:

12 * -14 = -168

-3 * 3 = -9

Combine the terms:

-168 + (-9) = -168 - 9 = -177

-177 is your answer.

~

Answer:

I am going with B.1,3,9,27

Step-by-step explanation:

A,C and D the patterns are from addition ie. A +8, C+3 and D +1 but B it's ×3

Answer:

The pouch would be able to hold 12.8 pencils :)

Step-by-step explanation:

because 3/8 is 37.5 and if you do that divided by 48 and add a decimal infront of the eight you will get your answer

Answer:

7 & 13 are constants

8 & 3 are coefficients

Step-by-step explanation:

Answer:

The additional wells for maximum amount of oil per day is 3 wells.

Step-by-step explanation:

Given;

initial number of wells, n = 6

total production, T = 1800

average production per well, = 1800/6 = 300 barrels per day

Let the additional well = y

total number of wells after optimization = 6 + y

new production per well = 300 - 25y

new total production = (6+y)(300-25y)

t = 1800 - 150y + 300y - 25y²

t = 1800 + 150y - 25y²

dt / dy = 150 -50y

for maximum value, dt/dy = 0

150 - 50y = 0

50y = 150

y = 150 / 50

y = 3

Therefore, the additional wells for maximum amount of oil per day is 3 wells.

33 additional wells should be drilled, reaching 39 wells, to obtain the maximum amount of oil per day.

Given that an oilfield contains 6 wells that produce a total of 1,800 barrels of oil per day, and for each additional well that is drilled, the average production per well decreases by 25 barrels per day, to determine how many additional wells should be drilled to to obtain the maximum amount of oil per day, the following calculation must be performed:

Therefore, 33 additional wells should be drilled, reaching 39 wells, to obtain the maximum amount of oil per day.

Learn more in https://brainly.com/question/13581736

Answer:

2, 4, 6, 8, 10, 12, 14

Step-by-step explanation:

8+8=16

6+10=16

4+12=16

2+14=16

Answer:

(x/2,(y/2)

Step-by-step explanation:

(16/2,24/2)

(8,12)

Answer:sorry this probably is t the most helpful but the closest i could get was 399 lbs. it’s is st$497.7 for one and $$497.8.

Step-by-step explanation:

Answer:

2c^2

Step-by-step explanation:

c3-c1=c2

d2-d2=0

8/4=2

Answer:

J(-5,2), A(-5,4), and N(-1,1)

Step-by-step explanation:

Answer

50

Step-by-step explanation:

60 is supplementary to 120 so 60+70=130

and a triangle adds up to 180 so 180-130 would be 50

Answer:

Equivalent

Step-by-step explanation:

A set is a well defined collection of objects.

Two sets are said to be equal if they have the same elements.

Two sets are said to be equivalent if they have the same number of elements.

Given sets are [tex]\{0,9\}\,,\,\{8,1\}[/tex]

These sets are not equal as both the sets have different elements.

Order of both the sets is 2 (number of elements in both sets is 2)

So,

these two sets are equivalent.

Answer:

x ≤ 2

Step-by-step explanation:

-3x+12≥6

-3x≥6

3x≤6

x ≤ 2

Answer:

x ≤ 2 is the correct answer!

Step-by-step explanation:

Hope this helps!

Answer:

grew by 6

Step-by-step explanation:

Answer:

a , b , d , e

Step-by-step explanation:

Answer:-0.560

Step-by-step explanation:

Step-by-step explanation:

Find the table attached

a) Given

F(x) = 6/x-2

When x = -4

F(-4) = 6/-4-2

F(-4) = 6/-6

F(-4) = -1

F(x) = 6/x-2

When x = -3

F(-3) = 6/-3-2

F(-3) = 6/-5

F(-3) = -1.2

F(x) = 6/x-2

When x = -2

F(-2) = 6/-2-2

F(-2) = 6/-4

F(-2) = -1.5

F(x) = 6/x-2

When x = -1

F(-1) = 6/-1-2

F(-1) = 6/-3

F(-1) = -2.0

F(x) = 6/x-2

When x = 0

F(0) = 6/0-2

F(0) = 6/-2

F(0) = -3

F(x) = 6/x-2

When x = 1

F(1) = 6/1-2

F(1) = 6/-1

F(1) = -6

F(x) = 6/x-2

When x = 2

F(2) = 6/2-2

F(2) = 6/0

F(2) = infty

F(x) = 6/x-2

When x = 3

F(3) = 6/3-2

F(3) = 6/1

F(3) = 6

F(x) = 6/x-2

When x = 4

F(4) = 6/4-2

F(4) = 6/2

F(4) = 3

b) Given

r(x)=6x+12/x^-4

When x = -4

r(-4) = 6(-4)+12/(-4)^-4

r(-4) = -24+12/(1/256)

r(-4) = -12(256)

r(-4) = -3072

When x = -3

r(-3) = 6(-3)+12/(-3)^-4

r(-3) = -18+12/(1/81)

r(-3) = -6(81)

r(-3) = -486

When x = -2

r(-2) = 6(-2)+12/(-2)^-4

r(-2) = -12+12/(1/16)

r(-2) = -0(16)

r(-2) = 0

When x = -1

r(-1) = 6(-1)+12/(-1)^-4

r(-1) = -6+12/(1)

r(-1) = -6+12

r(-1) = 6

When x = 0

r(0) = 6(0)+12/(0)^-4

r(0) = 0+12/0

r(0) = 12/0

r(0) = infty

When x = 1

r(1) = 6(1)+12/(1)^-4

r(1) = 6+12/1

r(1) = 18(1)

r(1) = 18

When x = 2

r(2) = 6(2)+12/(2)^-4

r(2) = 12+12/1/16

r(2) = 24(16)

r(2) = 384

When x = 3

r(3) = 6(3)+12/(3)^-4

r(3) = 18+12/1/81

r(3) = 30(81)

r(3) = 2430

When x = 4

r(4) = 6(4)+12/(4)^-4

r(4) = 24+12/1/256

r(4) = 36(256)

r(4) = 9216

We want to construct tables of values for the two given functions.

The tables are:

a)

[tex]\left[\begin{array}{ccc}x&y\\-4&-7/2\\-3&-4\\-2&-5\\-1&-8\\0&NaN\\1&4\\2&1\\3&0\\4&-1/2\end{array}\right][/tex]

b)

[tex]\left[\begin{array}{ccc}x&y\\-4&3,048\\-3&954\\-2&180\\-1&6\\0&0\\1&18\\2&204\\3&990\\4&3,096\end{array}\right][/tex]

A table will be something like:

[tex]\left[\begin{array}{ccc}x&y\\-4&\\-3&\\-2&\\-1&\\0&\\1&\\2&\\3&\\4&\end{array}\right][/tex]

Where the values of x go from -4 to 4.

To complete the tables, we just need to evaluate the functions in each one of the x-values at the left, and the outcome will be placed at the right.

a) f(x) = 6/x - 2

Now we just need to evaluate the function in all the given points:

f(-4) = 6/(-4) - 2 =  -3/2 - 4/2 = -7/2

f(-3) = 6/-3 - 2 = -4

f(-2) = 6/-2 - 2 = -5

f(-1) = 6/-1 - 2 = -8

f(0) is undefined, as we can't divide by zero, here we can write NaN (Not a number).

f(1) = 6/1 - 2 = 4

f(2) = 6/2 - 2 = 1

f(3) = 6/3 - 2 = 0

f(4) = 6/4 - 2 = -1/2

Now we put all of these in the correspondent place of the table:

[tex]\left[\begin{array}{ccc}x&y\\-4&-7/2\\-3&-4\\-2&-5\\-1&-8\\0&NaN\\1&4\\2&1\\3&0\\4&-1/2\end{array}\right][/tex]

b) We do the same thing, here we have:

r(x) = 6*x + 12/x^-4 = 6*x + 12*x^4

Now we evaluate this in the given values:

r(-4) = 6*(-4) + 12*(-4)^4 = 3,048

r(3) = 6*(-3) + 12*(-3)^4 = 954

r(-2) = 6*(-2) + 12*(-2)^4 = 180

r(-1) = 6*(-1) + 12*(-1)^4 = 6

r(0) = 6*0 + 120^4 = 0

r(1) = 6*1 + 12*1^4 = 18

r(2) = 6*2 + 12*2^4 = 204

r(3) = 6*3 + 12*3^4 = 990

r(4) = 6*4 + 12*4^4 = 3,096

Now we place these values in the correspondent place on the table:

[tex]\left[\begin{array}{ccc}x&y\\-4&3,048\\-3&954\\-2&180\\-1&6\\0&0\\1&18\\2&204\\3&990\\4&3,096\end{array}\right][/tex]

These are our two tables.

If you want to learn more, you can read.

https://brainly.com/question/8629807

When y=20 , x is −5.

Answer:

Depends on the formula given

Answer:

1) if the manufacturer's assumptions are correct, it would reed to replace 0.62% of its batteries free.

2) a standard deviation of 6.0843 results in a 1.07% replacement rate

3) using the revised standard deviation for battery life, 91.9% of the manufacturer's batteries don't get free replacement but qualifies for the prorated credit

Step-by-step explanation:

based on the given data;

x will represent the random variable such that the lifetime of its auto batteries, is normally distributed with a mean of 45 months and a standard deviation of 5.6 months

so

x → N( U = 45, ∝ = 5.6)

Under the warranty, if a battery fails within 31 months of purchase, the manufacturer replaces the battery at no charges to the consumer.

if the battery fails after 31 months but within 54 months, the manufacturer provides a prostrated credit towards the purchase of anew battery

1) If the manufacturer's assumptions are correct,

p(x < 3) = p( [x-u / ∝ ] < [ 31-45 / 5.6] )

= p( z < -2.5 )

using the standard normal table,

value of z = 0.0062 ≈ 0.62%

so if the manufacturer's assumptions are correct, it would reed to replace 0.62% of its batteries free.

2)

The company finds that it is replacing 1.07% of its batteries free of charge. It suspects that its assumption standard deviation of the life of its batteries is incorrect, so a standard deviation of ? results in a 1.07%

so lets say;

p ( x < 31 ) = ( 1.07%) = 0.0107

p ( [x-u / ∝ ] < [ 31-45 / ∝] ) = 0.0107

now from the standard table

-2.301 is 1.07%

so

( 31 - 45 / ∝ ) = -2.301

-14 / ∝ = -2.301

∝ = -14 / - 2.301

∝ = 6.0843

therefore a standard deviation of 6.0843 results in a 1.07% replacement rate

3)

Using the revised standard deviation for battery life, what percentage of the manufacturer's batteries don't free replacement but do qualify for the prorated credit?

p( 31 < x < 54 ) = p ( [31 - u / ∝ ] < [ x-u / ∝]  < [ 54 - 45 / ∝] )

= p ( [31 - 45 / 6.0843 ] < [ x-u / ∝]  < [ 54 - 45 / 6.0843] )

= p ( -2.301 < z < 1.4792 )

= p(Z < 1.5) - p(Z < -2.3)

= 0.9393 - 0.0108

= 0.919 ≈ 91.9%

therefore using the revised standard deviation for battery life, 91.9% of the manufacturer's batteries don't get free replacement but qualifies for the prorated credit

Answer:

4,000 -x3

Step-by-step explanation:

x times 3 is equal to the decrease so therefore you take the decrease away form 4/oo

Answer:

3y-x=4,000

Step-by-step explanation:

Answer:

[tex]\frac{3}{5}[/tex] or 0.6

Step-by-step explanation:

This problem requires the slop formula which is [tex]\frac{y2-y1}{x2-x1}[/tex]

You start with the first point which is (-1,1). This will be x1 and y1.

The next point is (4,4). This will be x2 and y2.

You plug these values into your equation which gives you [tex]\frac{4-1}{4-(-1)}[/tex]

To solve, you evaluate, [tex]\frac{4-1}{4-(-1)}[/tex]  = [tex]\frac{3}{5}[/tex] or 0.6

Answer:

Top left

Step-by-step explanation:

If an x value (domain) leads to more than one y-value (range), it is not a function. In other words, if each input value leads to only one output value, it is a function. It's still a function if the y-value leads to multiple x-values.

Answer:

56x-48x=104-40

8x=24

X=3

Step-by-step explanation:

the answer is 8                      

]explanation subtract 56-48 and 104-40 you should get 8x=64

divide 8/8 and 64/8 and the answer is 8            

Answer:

The proportion can be used to show that the slope of JL is equal to the slope of MP is  [tex]\frac{0-4}{-4-(-7)}[/tex] =  [tex]\frac{-4-8}{-1-(-10)}[/tex]  ⇒ G

Step-by-step explanation:

The rule of the slope of a line is [tex]m=\frac{y2-y1}{x2-x1}[/tex] , where (x1, y1) and (x2, y2) are two points on the line

∵ The coordinates of the point J are (-7, 4)

∵ The coordinates of the point L are (-4, 0)

∴ x1 = -7 and y1 = 4

∴ x2 = -4 and y2 = 0

→ Substitute them in the rule above to find the slope of LJ

∴ [tex]m_{JL}=\frac{0-4}{-4-(-7)}[/tex]

∵ The coordinates of the point M are (-10, 8)

∵ The coordinates of the point P are (-1, -4)

∴ x1 = -10 and y1 = 8

∴ x2 = -1 and y2 = -4

→ Substitute them in the rule above to find the slope of MP

∴ [tex]m_{MP}=\frac{-4-8}{-1-(-10)}[/tex]

∵ The slope of JL = the slope of MP

∴  [tex]\frac{0-4}{-4-(-7)}[/tex] =  [tex]\frac{-4-8}{-1-(-10)}[/tex]

The proportion can be used to show that the slope of JL is equal to the slope of MP is  [tex]\frac{0-4}{-4-(-7)}[/tex] =  [tex]\frac{-4-8}{-1-(-10)}[/tex]

x = 33°

Then :-

m∠1 = 33° ( angle x and angle 1 are corresponding angles on a transversal )

m∠1 + m∠2 = 90° ( angle 1 and angle 2 are complementary angles )

33 + ∠2 = 90

∠2 = 90 - 33

m∠2 = 57°

m∠1 + m∠3 = 180° ( angle 1 and angle 3 are a linear pair )

33 + ∠3 = 180°

∠3 = 180 - 32

m∠3 = 147°

Answer:

A but im not sure

Step-by-step explanation:

Answer:

56

Step-by-step explanation:

Multiply it out 2×2×2×7 = 56