Linear equations are usually organized in slope-intercept form, which looks like this:
[tex]y=mx+b[/tex]
m is the slope of the lineb is the y-intercept (the value of y when the line passes through the y-axis)To find the equation of a line in slope-intercept form:
Determine the slope of the linePlug the slope into the general formDetermine the y-intercept by solving for b Plug b back into the equationSolving the QuestionWe're given:
m = [tex]\dfrac{1}{2}[/tex](4,1) falls on the lineFirst, plug the given slope into the slope-intercept form equation:
[tex]y=mx+b\\\\y=\dfrac{1}{2}x+b[/tex]
Now, determine the y-intercept.
[tex]y=\dfrac{1}{2}x+b[/tex]
⇒ Plug in the given point (4,1) and solve for b:
[tex]1=\dfrac{1}{2}(4)+b\\1=2+b\\b=-1[/tex]
⇒ Therefore, the y-intercept is -1. Plug this back into our original equation:
[tex]y=\dfrac{1}{2}x-1[/tex]
Answer[tex]y=\dfrac{1}{2}x-1[/tex]
{2x+3y=−7, 7x+9y=−14
Answer as an ordered pair (x,y).
Answer:
Step-by-step explanation:
2x + 3y = -7
7x + 9y = -14
-3(2x+3y= -7) = -6x - 9y = 21
-6x - 9y = 21
7x + 9y = -14
add columns (y values cancel)
1x + 0y = 7
x = 7
plug 7 into the x value in either equation to find y
2(7) + 3y = -7
14 + 3y = -7
3y = -21
y = -7
(x,y) = (7,-7)
Select the two values of x that are roots of this equation.
x² + 34-3=0
. A. X=
-3+2/3
2
B. X=
-3-3
N
I X =
C. x.-3+27
=
1/21
2
O
D. *= -3-V21
=
2
Answer:
A. x=3 2.3
B . x=8
C. x=i do not know.
D. x=26
Step-by-step explanation:
A. -3+2/3=2
-3+2/3=-2 1/3
-2 1/3+3 2/3.=2
B. -3-3n=1
-3-3=-6n
-6n+8=1
C i do not understand.
D. -3-v21=2
21√5
Decimal Form:
1.0796532
or -24=2
-24+26=2
1. Select the three rational numbers.
A. 5/1
B. 7/0
C. -0.02
D. 4.17(the 7 repeats)
E. 3.14 (pi)
F. 3.14 (pi squared)
Answer:
A. 5/1
C. -0.02
D. 4.177777....
Step-by-step explanation:
Rational numbers can be written as a ratio of numbers, such as 5/1. As decimals, the numbers either
*** "terminate" the decimal has a certain number of digits and then stops, such -0.02, this can be written as a ratio -2/100 which is -1/50
OR
*** "repeats" , such as 4.17777... which can also be written as a ratio, 4.1777... = 188/45
7/0 is undefined and the pi numbers are irrational, the digits of the decimal do not repeat and do not ever end, therefore NOT rational.
What is the solution to the equation?
Answer: Your answer is X=-63
Hope this helps!
find the equation of the tangent to the circle whose equation is given below at the point (1,2)
(x-3)^2 + (y+2)^2 = 20
give answer in form ax+by+c=0 where abc are integers
Answer:
[tex]x-2y+3=0[/tex]
Step-by-step explanation:
Equation of a circle: [tex](x-h)^2+(y-k)^2=r^2[/tex]
(where (h, k) is the centre, and r is the radius)
Given equation: [tex](x-3)^2+(y+2)^2=20[/tex]
Therefore, the centre is (3, -2) and the radius is √20
To find the equation of the tangent
The tangent of a circle is perpendicular to the radius at the point.
Therefore, first find the gradient (slope) of the line that passes through the centre of the circle and the given point.
[tex]\textsf{let}\:(x_1,y_1)=(1,2)[/tex]
[tex]\textsf{let}\:(x_2,y_2)=(3,-2)[/tex]
[tex]\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-2-2}{3-1}=-2[/tex]
If two lines are perpendicular to each other, the product of their gradients will be -1.
Therefore, the gradient of the tangent is:
[tex]m_t \cdot-2=-1\implies m_t=\dfrac12[/tex]
Now use the point-slope formula of a linear equation to find the equation of the tangent:
[tex]\implies y-y_1=m_t(x-x_1)[/tex]
[tex]\implies y-2=\dfrac12(x-1)[/tex]
[tex]\implies 2y-4=x-1[/tex]
[tex]\implies x-2y+3=0[/tex]
Write an exponential expression with 5 as the base and 8 as the exponent?
Answer:
y=[tex]5^{8}[/tex]
Step-by-step explanation:
An exponential equation is in the form y=[tex]a^{x}[/tex] where a is the base and x is the exponent.
If 5 is the base then it would replace a, and if it 8 was the exponent it will replace x.
Solve the system of equations.
−4x+3y=−2y=x−1
Step-by-step explanation:
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support me
Help me out please simple
A straight line is 180 degrees in measure
The straight line is made up of three angles
--> angle 1
--> angle 2
--> angle with a little square on it
(angle with a little square means it is 90 degrees in measure)
Let's set up an equation
[tex]angle1 + angle2 + 90 = 180\\angle1 + 87 + 90 = 180\\angle1 = 3[/tex]
Thus angle 1 is 3 degrees or the second choice
Hope that helps!
List three numbers that are less than -7
Answer:
Step-by-step explanation: first one way that you can answer this question is to use a numberline, so you start at zero and go to the left of the numberline and the numbers behind -7 would be -8,-9, and or ,-10 they are all less than negative seven
A=bh (b=8, h=5) what does A equal to evaluate this problem using the equation below
Answer:
40
Step-by-step explanation:
Factor completely
X^6-125y^6
Lillian spent 18 minutes practicing her spelling words. How many seconds did she practice?
Answer:
1080 seconds.
Step-by-step explanation:
There are 60 seconds in a minute. As provided in the question, Lillian spent eighteen minutes, so 18x60=1080.
Answer:
1,080 seconds
Step-by-step explanation:
Use the order of operations to find the value of the expression. 12
÷
2
×
3
−
(
7
−
5
) HELP KME OUT
Answer:
16
Step-by-step explanation:
12 divided by 2 x 3 - (7 - 5)
6 x 3 - 2
18 - 2
16
Answer:
answer 16
Step-by-step explanation:
12 ÷ 2 x 3 - ( 7 - 5 ) is it right?
---------------------------------------------
Solving from left to right
12 ÷ 2 x 3 - ( 7 - 5 )
6 x 3 - (+2)
18 - 2
16
What is a major difference between parallel lines and perpendicular lines?
Answer:
Parallel lines never intersect. Perpendicular lines are lines that intersect.
Step-by-step explanation:
Hope this helps.
Answer:
Perpendicular lines meet at a 90 degree angle while parallel lines will never touch
Step-by-step explanation:
find the second derivative of the parametric equation x(t)=sin t and y(t)=cos t
Presumably you mean the second derivative of y with respect to x, d²y/dx².
Compute the first derivative. By the chain rule,
[tex]\dfrac{dy}{dx} = \dfrac{dy}{dt} \times \dfrac{dt}{dx} = \dfrac{\frac{dy}{dt}}{\frac{dx}{dt}}[/tex]
Differentiate the two parametric equations with respect to t :
[tex]x = \sin(t) \implies \dfrac{dx}{dt} = \cos(t)[/tex]
[tex]y = \cos(t) \implies \dfrac{dy}{dt} = -\sin(t)[/tex]
Then the first derivative is
[tex]\dfrac{dy}{dx} = \dfrac{-\sin(t)}{\cos(t)} = -\tan(t)[/tex]
Now, dy/dx is a function of t, so we can denote it by, say, dy/dx = f(t). Then by the chain rule, the second derivative will be
[tex]\dfrac{d^2y}{dx^2} = \dfrac{df}{dx} = \dfrac{df}{dt} \times \dfrac{dt}{dx} = \dfrac{\frac{df}{dt}}{\frac{dx}{dt}}[/tex]
Differentiating f(t) :
[tex]f(t) = -\tan(t) \implies \dfrac{df}{dt} = -\sec^2(t)[/tex]
Then the second derivative is
[tex]\dfrac{d^2y}{dx^2} = \dfrac{-\sec^2(t)}{\cos(t)} = \boxed{-\sec^3(t)}[/tex]
and since y = cos(t), we can go on to say
[tex]\dfrac{d^2y}{dx^2} = -\dfrac1{y^3}[/tex]
For the following pairs, indicate which do not comply with the rules for setting up hypotheses, and explain why. (Select all that apply.)
(a) H0: ? = 15, Ha: ? = 15
This pair complies.This pair does not comply because ? is not a population characteristic.This pair does not comply because both hypotheses use an equal sign.This pair does not comply because the two hypotheses use different numbers.
(b) H0: p = 0.5, Ha: p > 0.6
This pair complies.This pair does not comply because p is not a population characteristic.This pair does not comply because both hypotheses use an equal sign.This pair does not comply because the two hypotheses use different numbers.
(c) H0: ? = 121, Ha: ? < 121
This pair complies.This pair does not comply because ? is not a population characteristic.This pair does not comply because both hypotheses use an equal sign.This pair does not comply because the two hypotheses use different numbers.
(d) H0: ? = 123, Ha: ? = 125
This pair complies.This pair does not comply because ? is not a population characteristic.This pair does not comply because both hypotheses use an equal sign.This pair does not comply because the two hypotheses use different numbers.
(e) H0: p? = 0.2, Ha: p? ? 0.2
This pair complies.This pair does not comply because p? is not a population characteristic.This pair does not comply because both hypotheses use an equal sign.This pair does not comply because the two hypotheses use different numbers.
It can be inferred that H0: ? = 15, Ha: ? = 15 doesn't comply because both hypothesis use an equal sign.
How to illustrate the hypothesis?From the information, H0: p = 0.5, Ha: p > 0.6 doesn't comply because the two hypothesis use different numbers.
Furthermore, H0: ? = 121, Ha: ? < 121 shows that the pair complies. Also, H0: ? = 123, Ha: ? = 125 doesn't comply as they use the equal sign and different numbers.
Lastly, H0: p? = 0.2, Ha: p? ? 0.2 doesn't comply because p is not a population characteristic.
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Critical Thinking: I am a 7-digit number. All my digits are non-zero and distinct, My ones digit is four times the tens digit. • The sum of the ones and tens digits is equal to the sum of the lakhs and ten lakhs digits. • The sum of the ten thousands and thousands digits is equal to the double of the hundreds digit. • The ten lakhs digit is greater than the lakhs digit , and the ten thousands digit is greater than the thousands digit. Find which number I am.
Answer:
3286714
Step-by-step explanation:
Let the digits of the number be :
ABCDEFGOur given conditions :
G = 4F [ones digit is four times the tens digit]G + F = B + A [sum of the ones and tens digits is equal to the sum of the lakhs and ten lakhs digits]C + D = 2E [sum of the ten thousands and thousands digits is equal to the double of the hundreds digit]A > B and C > D [ten lakhs digit is greater than the lakhs digit , and the ten thousands digit is greater than the thousands digit]Solving :
Condition 1 : G is either 1 or 2 and F is either 4 or 8For now, let G be 1 and F be 4 Now G + F = A + BThen A + B = 5 [but not 1 + 4] ⇒ A can be 3 and B can be 2Now C + D = 2E and our remaining numbers are 5,6,7,8,9C and D can be 8 and 6, then their mean would be 7, which is ESolution :
So, the number is :
ABCDEFG3286714Mr. Turner has two Algebra 1 classes. With one class, he lectured and the students took notes. In the other class, the students worked in small groups to solve math problems. After the first test, Mr. Turner recorded the student grades to determine if his different styles of teaching might have impacted student learning.
Class 1: 80, 81, 81, 75, 70, 72, 74, 76, 77, 77, 77, 79, 84, 88, 90, 86, 80, 80, 78, 82
Class 2: 70, 90, 88, 89, 86, 86, 86, 86, 84, 82, 77, 79, 84, 84, 84, 86, 87, 88, 88, 88
1. Analyze his student grades by filling in the table below. Which class do you think was the lecture and which was the
small group? Why?
Q1 Q2 IQR Mean Median MAD
Class 1 76.25 81.75 5.5 79.35 79.50 3.12
Class 2 84 88 4 84.60 86 3.85
What is Q1, Q3, IQR, Mean, Median and the MAD?The first step is to arrange the grades in the classes in ascending order.
Class 1: 70, 72, 74, 75, 76, 77, 77,77, 78, 79, 80, 80, 80, 81, 81, 82, 84, 86, 88, 90
Class 2: 70, 77, 79, 82, 84, 84, 84, 84, 86, 86, 86, 86, 86, 87, 88, 88, 88, 88, 89, 90
Q1 for class 1= 1/4(n + 1) = 21/4 = 5.25 = 76.25
Q2 for class 2 = 1/4(n + 1) = 5.25 = 84
Q3 for class 1= 3/4(n + 1) = 15.75 = 81.75
Q3 for class 2 = 3/4(n + 1) = 15.75 = 88
IQR for class 1 = Q3 - Q1 = 81.75 - 76.25 = 5.50
IQR for class 2 = Q3 - Q1 = 88 - 84 = 4
Mean for class 1 = sum of grades / total number of grades = 1587 / 20 = 79.35
Mean for class 2 = sum of grades / total number of grades= 1692 / 20 = 84.6
Median for class 1 = (n + 1) / 2 = 21/2 = 10.5 = 79.50
Median for class 1 = (n + 1) / 2 = 21/2 = 10.5 = 86
MAD = [tex]\frac{1}{n}[/tex]∑ l x - m(x) l
Where: n = number of observations
x = number in the data set
m = mean
Mean absolute deviation for class 1 = 62. 3/ 20 = 3.12
Mean absolute deviation for class 2. = 77/ 20 = 3.85
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What is the mode of the data set?
78, 82, 91, 78, 92, 77, 80, 74, 81
The mode is 78
Step-by-step explanation:Mode: The digit that has been repeated the most in a specific data.
To determine the mode of the data, let's arrange the data in ascending order.
Arranging the data in ascending form, we get:
⇒ 74, 77, 78, 78, 80, 81, 82, 91, 92In the ascending data, we can see that: (Refer to underlined and bolded text)
74 has been repeated once77 has been repeated once78 has been repeated twice80 has been repeated once81, has been repeated once82 has been repeated once91 has been repeated once92 has been repeated onceSince 78 has been repeated the most, 78 is the mode of the data.
A circle has an area between 100-150 square inches,what are some possible lengths for a diameter of this circle
Answer:
it would range between 11.28379... to 13.819765...
Step-by-step explanation:
the circle's area formula is pi * radius^2
so you make to equation, plugging the 100 and 150 into the circle's area
you get square root of (100/pi) which gets 11.28379... for the area of 100
you do the same with 150 to get square root of (150/pi) which gets 13.819765...
those are the diameter of the circle since the diameter is double the radius which i already multiplied afterwards. so if you need the radius divide the number ive given you
-1/2 (-3 / 2x + 6x + 1) -3 x
Answer: here
Step-by-step explanation:
−21−24
Answer: negative 21 Negative 224
-21-24
solve for x ~
[tex]46x - 23x = 2[/tex]
thankyou ~
Answer: x = 2/23
Step-by-step explanation:
[tex]46x-23x=2[/tex]
[tex]\mathrm{Add\:like\:terms:}\:46x-23x=23x[/tex]
[tex]23x=2[/tex]
[tex]\mathrm{Divide\:both\:sides\:by\:}23[/tex]
[tex]\frac{23x}{23}=\frac{2}{23}[/tex]
[tex]$$Simplify[/tex]
[tex]\bold{x=\frac{2}{23}}[/tex]
Answer:
x = 2/23Step-by-step explanation:
Inthis question we are given with one equation that is 46x - 23x = 2 and we have asked to find the value of x or solve for x .
So , from here we are solving :
[tex] \longmapsto \: 46x - 23x = 2[/tex]
Step 1 : Taking 23x common at left hand side :
[tex] \longmapsto \: 23x(2 - 1) = 2[/tex]
Step 2 : Subtracting 1 with 2 :
[tex] \longmapsto \:23x = 2[/tex]
Step 3 : Transposing 23 to right hand side :
[tex] \longmapsto \: \red{ \boxed{x = \frac{2}{23} }}[/tex]
Therefore, value of x is 2/23Verifying the answer :
We are verifying our answer by substituting the value of x in the given equation .
[tex] \longmapsto \: 46(\frac{2}{23}) - 23( \frac{2}{23} ) = 2[/tex]
Now , calculating :
[tex] \longmapsto \: \cancel{46}(\frac{2}{ \cancel{23}}) - \cancel{23}( \frac{2}{ \cancel{23}} ) = 2[/tex]
[tex] \longmapsto \: 4 - 2 = 2[/tex]
[tex] \longmapsto \: 2 = 2[/tex]
[tex] \longmapsto \: L.H.S = R.H.S[/tex]
[tex] \longmapsto \: Hence, \: Verified . \: [/tex]
Therefore , our value for x is correct .#Keep Learning9. To stitch a shirt, 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain? (Hint : convert data in cm.)
Answer:
1 Shirt and 185cm remaining cloth
Step-by-step explanation:
2m and 15cm = 215cm
40m = 400cm
400/215=1.860465116
A shirt cant be in decimal so we remove the decimals, and take the as the answer. For the decimals, they are the remaining cloth.. to calculate the amount of remaining cloth we do:
1.860465116-1
=860465116
215*860465116=185cm
HELP MEEEEEE PLESEEE
Answer:
648 cubic centimeters
Step-by-step explanation:
6×9×12=648
Answer:
648 cubic centimeters
Step-by-step explanation:
All you need to do is multiply all of the measures that they show you.
6 x 9 x 12 which equals 648
Which expression is approximately equal to 5 5/8 x 4 5/6?
[tex]\huge\text{Hey there!}[/tex]
[tex]\mathsf{5 \dfrac{5}{8}\times 4\dfrac{5}{6}}\\\\\mathsf{= \dfrac{5\times6+5}{8}\times\dfrac{4\times6+5}{6}}\\\\\mathsf{= \dfrac{45}{8}\times \dfrac{29}{6}}\\\\\mathsf{= \dfrac{45\times29}{8\times6}}\\\\\mathsf{= \dfrac{1,305}{48}}\\\\\mathsf{= \dfrac{1,305\div3}{48\div3}}\\\\\mathsf{= \dfrac{435}{16}\approx 27 \dfrac{3}{16}}\\\\\huge\textbf{Therefore, your answer is: \boxed{\mathsf{27\dfrac{3}{16}}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
A plant nursery receives shipments of soil in containers as shown below
( a picture of a cube that has 3 numbers - The heigh = 1 1/4 the base =2 . The width= 1 1/2
Part a- what is the volume of the soil in each container in cubic yards
(I put my answer as 3 3/4 which is right I think )
Part b - if a cubic yard of soil weighs 2000 pounds of soil does each container hold?
***I need help with part b pls
The volume of the three-dimensional figure is 3.75 yd³, and it can hold 7500 pounds of soil
What is volume?Volume is the amount of space occupied by a three dimensional shape or object.
The volume of the three dimensional shape is:
Volume = length * width * height = 1 1/4 * 1 1/2 * 2 = 3.75 yd³
1 yd³ = 2000 pounds
3.75 yd³ = 2000 pounds * 3.75 yd³ = 7500 pounds
The volume of the three-dimensional figure is 3.75 yd³, and it can hold 7500 pounds of soil
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Please hurry
What is the surface area of this figure? Enter your answer in the box.
Answer:
692ft3
Step-by-step explanation:
Surface area of the rectangular prism;
SA = lw(2) + wh(2) + hl(2)
SA = 15(5)(2) + 5(8)(2) + 8(15)(2)
SA = 150 + 80 + 240 =
SA = 470ft3
Surface area of the triangular prism
SA = (S1 + S2 + S3) l + bh
SA = (9 + 9 + 11) 5 + 11(7)
SA = (29) 5 + 11(7)
SA = 145 + 77
SA = 222ft3
Add both the SA's
470ft + 222ft = 692ft3
Solve the simultaneous equations
4x + 5y = 4
2x - y = 9
Show clear algebraic working.
Answer:
[tex]x= \dfrac 72, ~~y= -2[/tex]
Step by step explanation:
[tex]4x+5y=4~~~...(i)\\\\2x-y=9~~~...(ii)\\\\\text{Multiply eq (ii) by 2 to isolate x:}\\\\4x-2y=18~~~.....(iii)\\\\(iii)-(i):\\\\4x-2y-4x-5y=18-4\\\\\implies -7y=14\\\\\implies y = -\dfrac{14}7 = -2\\\\\text{Substitute}~ y=-2~ \text{in equation (iii):}\\\\4x-2(-2) = 18\\\\\implies 4x +4 = 18\\\\\implies 4x = 18-4\\\\\implies 4x = 14\\\\\implies x = \dfrac{14}4 = \dfrac 72\\\\\text{Hence}~ (x,y) =\left(\dfrac 72 , -2 \right)[/tex]
Step-by-step explanation:
4x+5y=4 (equation 1)
2x-y=9 (equation2)
solving equation 1 and 2 and multiplying equation 2 by 2
4x+5y=4
4x-2y=18
- + -
________
7y= -14
y= -2
putting the value of y in equation 2
2x-y=9
2x+2=9
2x=7
x=3.5
help me find Find AB
The distance of AB is 42.04 units, BC is 35.77 units and CA is 34.5 units.
We have,
The length along a line or line segment between two points on the line or line segment.
The coordinates of A are (-18, -18)
coordinates of B are (20, 0)
coordinates of C are (-12, 16)
The formula for distance is Distance=√(x₂-x₁)²+(y₂-y₁)²
Distance AB=√(20-(-18))²+(0-18)²
=√(20+18))²+(0-18)²=√38²+18²
AB=√1444+324
=√1768
=42.04 units
Distance BC=√(-12-20)²+(16)²
=√(-32)²+(16)²=√1024+256
=√1280
=35.77
Distance CA=√(-12-(-18))²+(16+18)²
=√(6)²+(34)²
=√36+1156=34.5
Hence, the distance of AB is 42.04 units, BC is 35.77 units and CA is 34.5 units.
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complete question:
PLease help me find the distance between AB BC and CA please help
Please help me with this thanks! God bless you