What can you multiply 4 by to get 120?

Answers

Answer 1

Answer:30

Step-by-step explanation:

30+30+30+30 just do 120/4

Related Questions

If the difference of a number and eight is tripled, the result is six more than the number. Find the number. Round your answer to the nearest integer, if necessary.

Answers

The number that is six less than the product of three and the difference of the number and eight is; 15

How can the required number in the word problem be found?

The verbal expression of the equation in the word problem is presented in mathematical form as follows;

(x - 8) × 3 = x + 6

Expanding the left hand side gives;

3•x - 3×8 = x + 6

3•x - 24 = x + 6

3•x - x = 24 + 6 = 30

2•x = 30

x = 30/2 = 15

The number, x = 15

Learn more about finding the solutions to word problems here:

https://brainly.com/question/13818690

#SPJ1

what is the solution to -3/8x-11=4

Answers

Answer: -40

Step-by-step explanation:

Answer:

-1/40

Step-by-step explanation:

-3/8x -11+11=4+11

-3/8x=15

-3/8x x=15x

-3/8=15x

15x/15= -3/8/15

x=-1/40

Hope this helps!^^

If an arrow is shot upward on the moon with a velocity of 58 m/s, its height in meters after t seconds is given by y=58t−.83t2.

(a) Find the average velocity over the given time intervals:
(1) [1,1.5]
(2) [1,1.1]
(3) [1,1.01]
(4) [1,1.001]

(b) Find the instantaneous velocity after one second (to the nearest hundredth).

(1) m/s
(2) m/s
(3) m/s
(4) m/s
(b) m/s

Answers

The 58 m/s initial velocity of the arrow with height, y = 58•t - 0.83•t², gives;

(1) 55.925 m/s

(2) 56.257 m/s

(3) 56.3317 m/s

(4) 56.33917 m/s

(b) 56.34 m/s

How can the average and instantaneous velocity be calculated?

Initial velocity of the arrow = 58 m/s

Height of the arrow is; y = 58•t - 0.83•t²

The above kinematic equation can be analyzed as follows;

(1) The height at t = 1 is found as follows;

y = 58 × 1 - 0.83 × 1² = 57.17

Height at t = 1.5 s. is y = 58×1.5 - 0.83×1.5² = 85.1325

Average velocity = ∆y/∆t

Which gives;

Average velocity = (85.1325-57.17)/(1.5-1) = 55.925

The average velocity in the interval [1, 1.5] is therefore;

55.925 m/s

(2) [1, 1.1]

Height at t = 1.1 s. is y = 58×1.1 - 0.83×1.1² = 62.7957

Which gives;

Average velocity = (62.7957-57.17)/(1.1-1) = 56.257

The average velocity is 56.257 m/s

(3) [1, 1.01]

Height at t = 1.01 s. is y = 58×1.01 - 0.83×1.01² = 57.733317

Which gives;

Average velocity = (57.733317-57.17)/(1.01-1) = 56.3317

The average velocity is 56.33 m/s

(4) [1, 1.001]

Height at t = 1.01 s. is y = 58×1.001 - 0.83×1.001² = 57.22633917

Which gives;

Average velocity = (57.22633917-57.17)/(1.001-1) = 56.33917

The average velocity is 56.33917 m/s

(b) The equation for the instantaneous velocity is found as follows;

v = dy/dt = 58 - 2×0.83•t

After 1 second, we have;

t = 1

v = 58 - 2×0.83 × 1 = 56.34

The instantaneous velocity at t = 1 seconds is 56.34 m/s

Learn more about kinematics here:

https://brainly.com/question/14511323

#SPJ1

Solve
4x + 8y = 16 for X.

Solve for x

Answers

Answer:

x = 4 - 2y

Step-by-step explanation:

4x + 8y = 16

or, x + 2y = 4

or, x = 4 - 2y

Answer:4-2y

Step-by-step explanation:

Doug says the area of the figure is 20 square units. What is the correct area of
the figure? What mistake might Doug have made?
5 units
5 units

Answers

Answer:

The correct area is 25 square units.

His mistake was that he found the perimeter instead of the area.

Step-by-step explanation:

Area = Length x Width

Area= 5 x 5= 25

His mistake:

Perimeter = length + length + width + width

Perimeter = 5 + 5+ 5+ 5 = 20

Being... Great.... might be 78?! nah she prolly not im jk

Answers

Answer:

Step-by-step explanation:

233% = 2.33

2 2/3 = 2.6

All work and the answer is provided in the screenshot that is attached! :)

Have a great day!

select two points that lie on the same line throught (0,0), then select an equation that describes the relationship between the coordinates x and y

Answers

Two collinear points on a line are given in the table below:

x, y

0 0 (0,0)

2 1 (2,1)

Select the points that lie on the line. and the relationship between the coordinates x and y.

(4,2)

(4, 3)

(7,2)

4/8, 2/8

Answer:

(4,2) and ([tex]\frac{4}{8}[/tex],[tex]\frac{2}{8}[/tex]) are lie on the line, and y = [tex]\frac{1}{2}[/tex] x , is showing the relationship of x and y coordinates of given line.

Given that

The co-ordinates of line is (0,0) and (2,1).

To find

The points that lie on the line, and The relationship between the coordinates x and y.

So, according to the question

We have,

The X and Y co-ordinates of line (0,0) and (2,1).

For finding any point that lie on line, first we have to find the slope of given line,

So, we know that

slope (m) = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Where,

x₁ = 0 and x₂ = 2

y₁ = 0 and y₂ = 1

Now, putting the values, we will get

(m) = [tex]\frac{1-0}{2-0}[/tex] = [tex]\frac{1}{2}[/tex]

m = [tex]\frac{1}{2}[/tex]

We know that, the equation of line

y-y₁ = m(x- x₁ )

y-0 = [tex]\frac{1}{2}[/tex] (x- 0)