Verify that the function satisfies the hypotheses of the mean value theorem on the given interval 4

The main interaction between the urinary system and the circulatory system is both of the following parts of the human body work for the kidney.

The human body is the collection of many systems like the cardiovascular system for the heart, the urinary system for filtering the body, the circulating system for movement, and so on. All these functions help the body to regulate the smooth functioning of the body.

When the blood enters the kidney through arteries they go through the tiny capillaries that are seen in the urinary system. The blood entered into the kidney later moves to nephrons, where the blood is purified with the help of filters.

The waste that is obtained after the purification of the blood is then transferred to the vital substance that absorbs the bloodstream. It helps the body to manage and control the level of pressure in the blood.

Here the job of the heart is to simultaneously send the oxygenated blood all around the body and send the unwanted, discharged waste to the kidney where it helps to observe the required elements from the waste and transpose it to the urinary system.

The main work of the circulating system is to transpose the oxygenated blood to every part of the cell and provide them with sufficient nutrients.

From this system it is understandable that the similarities between circulatory and urinary system is both of the parts functions to remove waste from the body.

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The relationship between the magnitude of the force of tension and the force of friction is; Ff = (r/R)Ft

We are given;

mass of spool = M

Radius = R

moment of inertia = I.

Now, the spool is not moving and as such;

r < R which means there is net torque = 0

Thus;

Ff × R = Ft × r

>> Ff = (r/R)Ft

Finally, the angular acceleration is expressed as;

α = a/R

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Answer:ocean

Explanation:

edge2022

Answer: ocean

Explanation:

The mean cost for the replacement of these brake pads for four different vehicles is equal to $148.75.

A mean can be defined as a terminology that is used to connote a ratio of the sum of the total number of a data set to the frequency of the data set.

Mathematically, the mean cost for the replacement of these brake pads for four different vehicles would be calculated as follows:

Mean cost = [120 + 235 + 98 + 142]/4

Mean cost = 595/4

Mean cost = $148.75.

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The type of growth that is best illustrated by the rabbit population is; exponential growth.

Looking the graph giving illustrated by the rabbit population seen online, it is clear that the number of individual in that population continually increase until a maximum point was reached. Thereafter, there was a slight decline in the population.

Finally, the maximum point reached on the graph is the carrying point and the value from the graph is about 0.4 million and we can say that this depicts an exponential growth model.

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Answer:

The probability that it will be a hybrid is 21.4%.

Probability is the ratio of number of occurrences to total number of possible occurrences.

Given a total number of 280 cars. The number of hybrid cars is gotten by using the ratio.

Number of hybrid cars = (3/14) * 280 = 60 cars

Probability of picking a hybrid car = Number of hybrid car/total number of cars  = 60 cars / 280 cars = 21.4%

Therefore the probability that it will be a hybrid is 21.4%.

Explanation:

;-

Answer:

Not enough information to answer

Answer:  light from other galaxies is red.

Explanation: Astronomers have observed that light from the distant object in the universe is shifted towards the frequency of red color which indicates that those object are receding or moving away from the planet earth.This phenomena was termed as Red shift .Same thing goes for galaxies which are very far away from the planet earth.

Where as if galaxies were moving towards the the planet earth their light would have shifted toward the frequency of blue color termed as blue shift.

The markup percentage to the variable cost using the variable cost method is 40%.

The markup percentage to the variable cost using the variable cost method can be obtained by dividing the addition of the target profit and total fixed cost by the total variable cost as follows.

We know that:

Total fixed cost

= Fixed overhead costs + Fixed selling and administrative costs

= $120,000 + $50,00

= $170,000

The markup percentage to the variable cost

= (Target profit + Total fixed cost) / Total variable cost

= ($100,000 + $170,000) / $675,000

= $270,000 / $675,000

= 0.40, or 40%.

Hence, the markup percentage to the variable cost using the variable cost method is 40%.

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Answer:

44%

Explanation:

The variable cost method determines price by adding a mark up to variable cost. The mark up is set to cover a fixed cost plus target profit on top of variable cost.

markup=(target profit+total fixed cost)/total variable cost

Answer:

h>=48

Explanation:

let h be height

h >= 48

A company's prospectus is any legal document that provides information and full details of the company.

The question is incomplete, so I will list the information is a company's prospectus, instead.

The information include:

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Answer:

the information that is not included in a company's prospectus is the company's guaranteed earning potential.

Explanation:

In a company's prospectus, its assets, net worth, and annual revenue are included in the document but not their guaranteed earning potential.

When activated phospholipase c cleaves an inositol phospholipid, Both inositol 1,4,5-trisphosphate (IP3) and diacylglycerol are retained in the membrane.

When G protein  is said to be stimulated,  it is known to often activates phospholipase C.

Note that phospholipase C. is siad to hook up to a phospholipid known as phosphatidylinositol 4,5- biphosphate that is often seen in the plasma membrane lipid bilayer. The outcome of thses two hookup is the production of two products known as inositol 1,4,5 triphosphate (IP3) and diacylglycerol (DAG).

See options below

hen activated phospholipase C cleaves an inositol phospholipid, what happens to the small signaling molecules the enzyme produces? Choose one:

A. Both inositol 1,4,5-trisphosphate (IP3) and diacylglycerol are released into the cytosol.

B. Inositol 1,4,5-trisphosphate (IP3) remains in the membrane, while diacylglycerol is released into the cytosol.

C. Both inositol 1,4,5-trisphosphate (IP3) and diacylglycerol are retained in the membrane.

D. Inositol 1,4,5-trisphosphate (IP3) is released into the cytosol, while diacylglycerol is retained in the membrane.

E. Both inositol 1,4,5-trisphosphate (IP3) and Ca2+ are released into the cytosol.

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The relative frquency of n in a population from the given premise of the allele is; It could be less frequent than N.

Relative frequency is also called experimental probability and in an event , it is defined as the ratio of the number of outcomes in which a specified event occurs to the total number of trials. Though this not in a theoretical sample space but in an actual experiment.

In this question, long nose (N) is dominant to the allele for a short nose (n) and so the relative frequency will definitely be less frequent than N.

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Answer:

The correct answer is that the males have a significantly high outlier.

Step-by-step explanation:

If you look at the box plots show the long tails t6hat signify the Q3 outlier.

Answer:

healthy fish populations

Explanation:

i just took the test and get it right

Answer:

i had this question it was 225

The detail in the given excerpt titled The Fellowship of the Ring that identifies as a fantasy is called; Bilbo has a magic ring

This novel titled "The Fellowship of the Ring" written by J.R.R. Tolkien has repetitive elements that define it as a fantasy novel.

These fantasy words include imagined worlds, mythical creatures and the supernatural. Since Bilbo was going to be eleventy-one 111 has these elements, then Bilbo belongs to the hobbits community which are mythical and fanatical creatures besides the age he is about to reach is unnatural even for a Hobbit.

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Answer:

B

Explanation:

2022

An obstacle which was faced by the union pacific railroad workers but not the central pacific workers is: B. conflict with American Indians.

The union pacific railroad workers can be defined as a group of young Civil War veterans and Irish immigrants that were saddled with the responsibility of providing railroad related services to commuters.

Unlike the central pacific workers, an obstacle which was directly faced and experienced by the union pacific railroad workers is conflict with American Indians (Native Americans) because the American Indians wanted to reclaim the jobs and way of life that was being taken away from them.

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I know I am a week late but for the future people the answer is A,C,D,F.

I got it right on edge.

The other aswer to the second question is B.

Got it right on edge, Have a good day <3.

With regards to vapor pressure curves, we can say that 1-butene has higher vapor pressures at lower temperatures than 1-heptene.

With regards to boiling points, 1-pentyne has a lower boiling point than 1-octyne.  

With regards to vapor pressure curves, we can say that 1-butene has higher vapor pressures at lower temperatures than 1-heptene.

Now, these supposed differences in boiling points and vapor pressures arise due to thedifferences in the chain lengths of the molecules.

Larger molecules have stronger intermolecular forces of attraction than smaller molecules. Thus, more energy is required to move larger molecules into the vapor phase from the liquid state.

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An example of hyperbole that were written in chapter 5 of "The Watsons go to Birmingham" include the following:

Hyperbole can be defined as a figure of speech (figurative language) that connotes an unintentional or deliberate exaggeration (overstatement) of a situation, an event or thing by a writer of a literary work.

Two (2) examples of hyperbole that were written in chapter 5 of "The Watsons go to Birmingham" include the following:

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Answer:

In a process called diffusion, oxygen moves from the alveoli to the blood through the capillaries (tiny blood vessels) lining the alveolar walls.

Explanation:

By nature hair is negetively charged, the net charge on the air is the subtraction of the positive charge from the hairs negetive charge,

Static electricity is a phenomenum whereby charges which are imobile by nature and mearnt to be tranfered from one surface to another.  The direction of the charge transfer is away from the positive charge.

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Answer:

BCC has more solid uses . Here are the most common two : 1 . When you do n't want the primary recipient to know . • A good example could be when you 're having problems with an employee . When sending them an email , you can BCC your supervisor or HR in the email so that they get a copy of your correspondence . In this case , the other team members will receive it , but your fellow employee will not see that other parties have been included in the correspondence .

Explanation:

a. Probability that the length of stay in the ICU is one day or less is:0.2614.

b. Probability that the length of stay in the ICU is between two and three days is:0.1426

c. Probability that the length of stay in the ICU is more than five days is:0.2198.

a. Probabilty of one day or less.

Using this formula

P(X≤1)=1-e^-ux

Since mean is 3.3 the decay parameter is:

u=1/3.3

Hence:

P(X≤1)=1-e^-1/3.3

P(X≤1)=1-e^-0.3030

P(X≤1)=1-0.7385991

P(X≤1)=0.2614

b. Probability of two and three days.

P(X≤2)=1-e^-ux

P(X≤2)=1-e^-2/3.3

P(X≤2)=1-e^-0.60606

P(X≤2)=1-0.54549589

P(X≤2)=0.45450

P(X≤3)=1-e^-ux

P(X≤3)=1-e^-3/3.3

P(X≤3)=1-e^-0.909091

P(X≤3)=1-0.402890

P(X≤3)=0.59711

Hence:

P(2≤X≤3)=0.59711-0.45450

P(2≤X≤3)=0.1426

c. Probability of more than 5 days.

P(X≤5)=e^-ux

P(X≤5)=e^-5/3.3

P(X≤5)=e^-1.515152

P(X≤5)=0.219775

P(X≤5)=0.2198 (Approximately)

Inconclusion the probability that the length of stay in the ICU is one day or less is:0.2614.

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