Use this equation: N2 + 3H2 → 2NH3, for the following problems:

1. If 2.5 moles of N2 react, how many grams of NH3 can be produced?




2. If 10.0 moles of NH3 are produced, how many grams of H2 would be required?




Use this equation: B2O3 + 3Mg → 3MgO + 2B, for the following problems:

3. How many grams of boron can be obtained from 8 moles of B2O3?




4. How many grams of magnesium are required to produce 4 moles of boron?




Use this equation: S8 + 12O2 → 8SO3, for the following problems:

5. How many grams of oxygen is needed to produce 7.5 moles of sulfur trioxide?




6. How many grams of sulfur trioxide can be produced from 2 moles of octasulfur?

The percentage purity of the calcium carbonate is  44%. The percentage purity gives the amount of pure CaCO3 in the sample.

In excess titration or back titration, we neutralize the excess titrand left in a system.

We have the reaction;

CaCO3 + 2HCl ----> CaCl2 + H2O + CO2

Number of moles of HCl = 0.2254 M * 20/1000 L = 0.0045 moles

The reaction of the excess acid is according to the reaction;

HCl + NaOH ----> NaCl + H2O

Number of moles of NaOH = 0.1041 M * 20/1000 = 0.0021 moles

Since the reaction is 1:1, 0.0021 moles of HCl reacted also

Number of moles of HCl that reacted with CaCO3  =  0.0045 moles - 0.0021 moles = 0.0024 moles

If 2 moles of HCl reacts with 1 mole of CaCO3

0.0024 moles of HCl reacts with 0.0024 moles * 1/2

= 0.0012 moles

Mass of pure CaCO3 present = 0.0012 moles * 100 g/mol = 0.12g

Percent purity of the sample =  0.12g/0.2719 g * 100/1

= 44%

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Answer:

[tex]5{Fe}^{ + 2} +1{MnO_4}^{ - 1} + 8 {H}^{ + } \rightarrow 5{Fe}^{ + 3} + 1{Mn}^{ + 2} + 4H_2O[/tex]

Explanation:

To balance any redox reaction the primary factor is to identify the species undergoing oxidation and reduction.

Below are the steps to identify species undergoing oxidation and reduction:

let's calculate oxidation number,

given reaction

[tex]{Fe}^{ + 2} +{MnO_4}^{ - 1} \rightarrow {Fe}^{ + 3} + {Mn}^{ + 2}[/tex]

Of reactant,

[tex]Fe = +2, {MnO_4}^{ - 1} \\ Let \: oxidation \: of \: Mn \: is \: x \: and \: Oxygen -2 \\ {MnO_4}^{ - 1} \rightarrow \: x + 4 \times ( - 2) = - 1 \\ {MnO_4}^{ - 1} \rightarrow \: x + - 8 = - 1 \\ {MnO_4}^{ - 1} \rightarrow \: x = + 8 - 1 \\ {MnO_4}^{ - 1} \rightarrow \: x = + 7 \\ \fbox{ Mn \: +7, O \: -2}[/tex]

Of product,

[tex]\fbox{Fe \: +3, \: Mn \: +2}[/tex]

Now calculate the change in oxidation number

[tex]Fe = +3-(+2) = +1 \\ Mn = +2-(+7) = -5[/tex]

now balance the increase in oxidation number and decrease in oxidation number,

thus we require 5 Fe for 1 MnO4-,

Now putting these numbers as their coefficient,

[tex]5{Fe}^{ + 2} +1{MnO_4}^{ - 1} \rightarrow 5{Fe}^{ + 3} + 1{Mn}^{ + 2}[/tex]

now balance oxygen atom on product side by adding water,

since there are 4 oxygen atoms in reactants 4 water molecules will be there on product side.

[tex]5{Fe}^{ + 2} +1{MnO_4}^{ - 1} \rightarrow 5{Fe}^{ + 3} + 1{Mn}^{ + 2} + 4H_2O[/tex]

now balance Hydrogen atom on reactant side by adding H+ ion, since there are 4 water molecules on product 8 H+ ion will be in reactants!

[tex]5{Fe}^{ + 2} +1{MnO_4}^{ - 1} + 8 {H}^{ + } \rightarrow 5{Fe}^{ + 3} + 1{Mn}^{ + 2} + 4H_2O[/tex]

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Confirming the balanced reaction, by checking number of atoms and charge on reactant vs Product side.

Total number of Fe on reactant and product = 5

Total number of Mn on reactant and product= 1

Total number of Oxygen on reactant and product = 4

Total number of hydrogen on reactant and product= 8

Total charge on reactant side= 5×(+2)-1+8=17

Total charge on product side = 5×(+3)+1×(+2)=17

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

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Mass of 1.5 mole of electron is 0.8229 mg

mass of electron = 9.11 * 10^-31 kg

mass of 1 mole of any substance ( Avagadro number ) = 6.022 * 10^23 /mol

1.5 moles of electron  = 1.5 * 6.022 * 10^23 = 9.033 * 10^23 /mol

mass of 1.5 mole of electron = 9.033 * 10^23 * 9.11 * 10^-31

mass of 1.5 mole of electron = 8.229 * 10^-7 kg

mass of 1.5 mole of electron = 8.229 * 10^-4 g

mass of 1.5 mole of electron = 0.8229 mg

Hope it helps.....

For a gas made up of homonuclear diatomic molecules escapes through a pinhole 0.378 times as fast as He gas, the chemical formula of the gas  is mathematically given as

N2(nitrogen gas)

Generally, the equation for the rate to molar relationship  is mathematically given as

\frac{r1}{r2}=\frac{mm2}{mm1}

Thereofore

\frac{r}{r2}=0.378

Hence

0.378=\sqrt{\frac{4.00268}{Mx2}}

Mx2=28.013g/mol

In conclusion,The name of gas with a molar mass of 28.013g/mol is N2

Therefore, the chemical formula of the gas. is N2

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mol = 6.78 x 10²⁵ : 6.02 x 10²³ = 112.62

MM Al₂(SO₄)₃ = 2.27 + 3.32+12.16 =342 g/mol

mass = 112.62 x 342 = 38516.04 g = 38.5 kg

The total mass of 6.78*[tex]10^{25}[/tex] molecules of [tex]Al_{2}(SO_{4})^3[/tex] is (b) 38.5 Kg.

Hence, the total weight of 6.78*[tex]10^{25}[/tex] molecules of [tex]Al_{2}(SO_{4})^3[/tex] is (b) 38.5 Kg.

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Answer:

c. energy from splitting energy

Explanation:

Answer:

[tex]{\rm Ba^{2+}} \, (aq) + {\rm {SO_4}^{2-}}\, (aq) \to {\rm BaSO_{4}}\, (s)[/tex].

Explanation:

Make use of the fact that calcium sulfate [tex]{\rm CaSO_{4}}[/tex] and magnesium sulfate [tex]{\rm MgSO_{4}}[/tex] are much more soluble in water than barium sulfate [tex]{\rm BaSO_{4}}[/tex].

When sulfate ions [tex]{\rm {SO_{4}}^{2-}}[/tex] are added to dilute solutions containing [tex]{\rm Ba^{2+}}\, (aq)[/tex], [tex]{\rm Ca^{2+}}\, (aq)[/tex], and [tex]{\rm Mg^{2+}}\, (aq)[/tex], precipitation would be visible only in the solution with [tex]{\rm Ba^{2+}}\, (aq)\![/tex]. Barium sulfate would be the precipitate.

[tex]{\rm Ba^{2+}} \, (aq) + {\rm {SO_4}^{2-}}\, (aq) \to {\rm BaSO_{4}}\, (s)[/tex].

This ionic equation is balanced as it conserves both the atoms and the charges on the ions.

Answer:

car hornsss

Explanation:

they loud asl

Explanation:

Zn + Sn3(PO4)4 = Zn3(PO4)2 + Sn - Balanced Chemical Equation

4.3 is limiting

is the answer

if you like my answer please like comment and mark me as brilliant

Taking into account the definition of a system of linear equations and molar mass, the molar masses of elements A and B are 26.778 [tex]\frac{g}{mole}[/tex] and 17.998[tex]\frac{g}{mole}[/tex] respectively.

A system of linear equations is a set of two or more equations of the first degree, in which two or more unknowns are related.

Solving a system of equations consists of finding the value of each unknown so that all the equations of the system are satisfied. That is to say, the values ​​of the unknowns must be sought, with which when replacing, they must give the solution proposed in both equations.

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

The molar mass of a compound (also called Mass or Molecular Weight) is the sum of the molar mass of the elements that form it (whose value is found in the periodic table) multiplied by the number of times they appear in the compound.

Being the molar masses of the compounds:

and considering the definition of molar mass of a compound, the system of equations to be solved is

[tex]\left \{ {{3mA + mB=98.33\frac{g}{mole} } \atop {mA + 2mB=62.77\frac{g}{mole} }} \right.[/tex]

where mA and mB are the molar masses of elements A and B respectively.

There are several methods to solve a system of equations, it is decided to solve it using the substitution method, which consists of clearing one of the two variables in one of the equations of the system and substituting its value in the other equation.

Isolating the variable mB from the first equation:

mB= 98.33 [tex]\frac{g}{mole}[/tex] - 3mA

and substituting in the second equation, you get:

mA + 2× (98.33 [tex]\frac{g}{mole}[/tex] - 3mA)=62.77[tex]\frac{g}{mole}[/tex]

Solving:

mA + 2× 98.33 [tex]\frac{g}{mole}[/tex] - 2×3mA=62.77[tex]\frac{g}{mole}[/tex]

mA + 196.66 [tex]\frac{g}{mole}[/tex] - 6mA=62.77[tex]\frac{g}{mole}[/tex]

mA - 6mA=62.77[tex]\frac{g}{mole}[/tex] - 196.66 [tex]\frac{g}{mole}[/tex]

(-5)mA= - 133.89 [tex]\frac{g}{mole}[/tex]

mA= (- 133.89 [tex]\frac{g}{mole}[/tex] )÷ (-5)

mA= 26.778 [tex]\frac{g}{mole}[/tex]

Remember that mB= 98.33 [tex]\frac{g}{mole}[/tex] - 3mA, replacing the value of mA:

mB= 98.33 [tex]\frac{g}{mole}[/tex] - 3×(26.778 [tex]\frac{g}{mole}[/tex])

mB= 80.334 [tex]\frac{g}{mole}[/tex]

mB= 17.998 [tex]\frac{g}{mole}[/tex]

Finally, the molar masses of elements A and B are 26.778 [tex]\frac{g}{mole}[/tex] and 17.998[tex]\frac{g}{mole}[/tex] respectively.

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Answer:

the sun i think because the sun has the greatest gravitational pull

Explanation:

hello

the answer is b

O or oxygen has 16 molar mass and C or carbon has 12

so CO2 or carbon dioxide=(2×O)+C=(2×16)+12=46

Answer:

a

Explanation:

because they all are gasses

The calculated percentage purity of the original sample of calcium carbonate is 44%.

In the back titration of the excess acid, we neutralize the excess titrand left in a system.

We have the reaction equation;

CaCO3 + 2HCl ----> CaCl2 + H2O + CO2

To get the moles of HCl = 0.2254 M * 20/1000 L = 0.0045 moles

The reaction involving the excess acid occurs thus;

HCl + NaOH ----> NaCl + H2O

Number of moles of NaOH = 0.1041 M * 20/1000 = 0.0021 moles

We have a  1:1 hence 0.0021 moles of HCl reacted also

Number of moles of HCl that reacted with CaCO3 initially = 0.0045 moles - 0.0021 moles = 0.0024 moles

Given the stoichiometry of the reaction,  0.0012 moles of CaCO3 reacted.

Hence;

Mass of pure CaCO3 in the sample= 0.0012 moles * 100 g/mol = 0.12g

Percent purity of the sample = 0.12g/0.2719 g * 100/1

= 44%

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Answer:

C. can be turned on and off

Explanation:

An electromagnet becomes magnetic when it is part of a complete electric circuit. A switch is a part of an electric circuit that completes or break the circuit turning the circuit on and off.

(*) Sorry for my late answer but I hope this helps others that are looking for this.

I got 100%  ;)

Answer:

1043.5 g of air  to the nearest tenth.

Explanation:

4P + 5O2 ---> 2P2O5

4*31 g P reacts with 5*32 g oxygen

124 g   ..   ..   .   ....  .   160g oxygen

186 g   ..   ..   ..   ..   ..   (160*186)/124 g oxygen

-  so the mass of air required =  [(160*186)/124] / 0.23

= 240 / 0.23

= 1043.5 g of air.

Answer:

Si, Sn, Cs

Explanation:

                       Atomic no.          Atomic radius

Silicon Si_______14___________0.117
Tin         Sn______50___________0.140
cesium Cs______55___________0.262

Silicon is the smallest among these

Answer:

b.exothermic and entropy is decreasing

The simplest way to make the color gray is by mixing white and black colors, but it can also be created by mixing colors such as red and green.

This is considered a neutral and cool color that can be naturally found in elements such as rocks.

This would not be a neutral gray as it will resemble a little bit the original colors.

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Answer:

c

Explanation:

lol

expect what to have?!?!?!?

Explanation:

36.5 g of HCl occupies 2.24×10-2m3 . ∴ 73 g of HCI at STP will occupy 2.24×10-236.5×732=4.48×10-2m3.

Answer:

Lim reag = NO        .07 mole of O2 left over

Explanation:

From the equation, you need twice as many moles of NO as O2

  2 x moles O2 =     2 * .503 moles = 1.06 moles of NO needed....you do not have enough so this is the limiting reagent    O2 will be left over

    1/2 * .866 = .433  moles of O2 used    .503 - .433 = .07  mole O2 leftover

Answer:

A hot glowing body of ignited gas that is generated by something on fire.

Factors that will increase product formation are;

The position of chemical equilibrium is affected by the following factors:

When equilibrium is altered by an external factor, the reaction shifts to annul the effect of that change.

For the reversible exothermic synthesis, low temperature and high pressure will shift the reaction farthest toward the products.

For the reaction of the 2.0g piece of Mg with HNO3. increasing the surface area of magnesium metal as well as increasing the concentration of HNO3 would produce the GREATEST reaction rate.

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Answer:

i believe 223

Explanation:

T2 + 500k = 223 C*