stion 3
Define the law of moments. It is applicable to a certain condition of the acting forces.
Name the condition.

Answers

Answer 1

Answer:

algebraic sum of moments of all the forces acting on the body about the axis of rotation is zero, the body is in equilibrium. According to the principle of moments, in equilibrium: Sum of anticlockwise Moments = Sum of clockwise moments.

Condition:

For an object to be in equilibrium, it must be experiencing no acceleration.

Hope it may helpful to you


Related Questions

How much pressure is created when you apply a
50.0N force on a syringe plunger that has a diameter of 0.4​

Answers

Pressure
= Force/Area

Area = π(d^2)/4
= π(0.4^2)/4
=0.126 m2
Pressure
= 50/0.126
= 396.825 Pa

I’ve tried my hardest n just keep blowing my head please help!!

Answers

Answer:

Forces

Explanation:

1) A Force

2) Balanced

3) Unbalanced

4) Any object moving at a constant speed, Any object in 0 motion, A balanced see-saw (no net torque/forces)

5) Any object accelerating, Someone pushing a box

Calculate the wavelength (in m) of the note middle "C" (frequency = 256 Hz) in air at room temperature and pressure.

Answers

hi you need to stop it get some help okay hope that worked

The wavelength (in m) of the note middle "C" (frequency = 256 Hz) in the air at room temperature and pressure will be 1171875 m.

What is wavelength?

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The relationship between the wave's wavelength, time, and speed is given as;

[tex]\rm \lambda = \frac{c}{v} \\\\ \rm \lambda = \frac{3 \times 10^8}{256} \\\\ \lambda=1171875 \ m[/tex]

Hence the wavelength (in m) of the note middle "C" (frequency = 256 Hz) in the air at room temperature and pressure will be 1171875 m.

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2. Box A has 2x the mass of Box B. Compare the inertia of the 2 bodies.

Answers

Box A has 2x the mass of Box B so Box A has more inertia as compared to Box B.

Relationship between inertia and mass

More the mass of an object, there is more inertia of the body. Thus, if mass of two bodies is same their inertia will also be same. Hence, inertia of A and B will be same as mass of both A and B are same.

So we can conclude that Box A has 2x the mass of Box B so Box A has more inertia as compared to Box B.

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what’s is the vertical colum of the elements in the periodic table called

Answers

it is called groups or families.

Answer:

groups or families

Explanation:

The vertical column of the periodic table are called groups or famileis because of their similar chemical behavior.

The three types of cones in the human eye are

a

red, yellow, green


b

red, green, blue


c

red, blue, cyan


d

yellow, cyan, magenta

Answers

Answer:

the answer is B I hope it helps out

curd is made from milk... t or f​

Answers

Explanation:

Curd is made from milk . ( True )

Curd is made by bacterial fermentation of milk.

Answer:

very true

curd is made from warm milk and a bacterial youghurt starter and it aslo has been used for many years

pleaseee pretty please put me as brainliest

Question 3 of 10
Which statement describes the law of conservation of energy?
A. Energy can only change from nuclear energy to chemical energy
B. There is only one form of energy.
C. The total energy in a system can only increase.
D. When an energy transformation happens, no energy is destroyed
or created.

Answers

D. When an energy transformation happens, no energy is destroyed or created.
This is the correct answer because the law of conservation of energy is energy cannot be created nor destroyed

Answer: D

Explanation: not A because energy can also change from chemical to mechanical or nuclear to mechanical. Not B because there are many types of energy eg, mechanical, nuclear, chemical... Not C because The total energy of a system is constant(conservation of energy).

If a→=3i^-2j^-k^ and b→=i^+4j^+k^, find a unit vector n^ normal to the plane containing a→ and b→ such that a→, b→ and n^, in this order, form a right-handed system.​

Answers

The unit vector normal to the plane is ; n = [tex]\frac{i}{\sqrt[3]{6} } - \frac{2j}{\sqrt[3]{6} } + \frac{7k}{\sqrt[3]{6} }[/tex]

Given data :

The unit vectors

a→=3i^-2j^-k^  and  b→=i^+4j^+k^

Determine the unit vector normal to the plane

The unit vector normal to the plane is calculated as

n = [tex]\frac{a*b}{|b*b|}[/tex]  ---- ( 1 )

where ; a→ * b→ =  2i - 4j + 14k  and  |b * b| = [tex]\sqrt{216}[/tex]  

back to equation ( 1 )

n = ( 2i - 4j + 14k ) / [tex]\sqrt{216}[/tex]

  = [tex]\frac{i}{\sqrt[3]{6} } - \frac{2j}{\sqrt[3]{6} } + \frac{7k}{\sqrt[3]{6} }[/tex]

Hence we can conclude that The unit vector normal to the plane is ; n = [tex]\frac{i}{\sqrt[3]{6} } - \frac{2j}{\sqrt[3]{6} } + \frac{7k}{\sqrt[3]{6} }[/tex]

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Definition law of moments

Answers

When an object is balanced (in equilibrium) the sum of the clockwise moments is equal to the sum of the anticlockwise moments.

A man is pushing a large box with a force of 44 newtons. He slides over a floor that has a sliding frictional force of 12 Newtons. What is the acceleration?

Answers

I’m sorry I was not texting lol but 12 subduing and I got a phone call back to you later on for your birthday 17 wyd

Suppose a horse leans against a wall as in the figure below.
1.2 m
14 m
1
0.35 m
(0)
(a)
Calculate the force exerted on the wall assuming that force is horizontal and using the data in the schematic representation of the situation. Note that the force exerted on
the wall is equal in magnitude and opposite in direction to the force exerted on the horse, keeping it in equilibrium. The total mass of the horse and rider is 575 kg. Take the
data to be accurate to three digits.

Answers

The force the horse and the rider exerts on the wall is equal to the weight combined acting in the opposite direction:

Force

Given Data

mass of horse and rider = 575kgForce  acting on wall = ??

When a body of mass rests on a surface, it exerts a force equal to the weight of the mass but opposite in direct on the mass/object

hence the force is computed as

Force = mass * acceleration

Force = 575 * 9.81

Force = 5640.75N

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the dimensions of a cuboidal block are 2.5 m * 2m * 1.2m its weight 900 n what is the minimum presseure exerted by the block on the surface of its support.?​

Answers

Answer:

your answer is here 180

Explanation:

900/2.5 * 2 = 180

Answer:

The answer is 180 Pa.

Explanation:

Given;

Here, weight = thrust = 900 N,

dimensions are 2.5 m × 2 m × 1.2 m

To Find;Pressure exerted by the block on the surface of its support.Formula;Pressure = Thrust ÷ Area

We know that, Pressure is inversely proportional to area. For the minimum pressure the area must be more.

So, if the block is resting with 2.5 m × 2 m surface on the support, the pressure will be minimum.

Pressure = 900 N ÷ 2.5 × 2.0 m² = 180 Pa

Thus, The pressure exerted by the block on the support is 180 Pa.

Objects change their speed and/or direction only when

Answers

Answer:

When an external force acts upon them

true or false
a)we should play inside our classroom..........
b)curd is made from milk........
c) wa.........t.............​

Answers

Answer:

a) we should play inside our classroom

Explanation:

Lactose intolerance does not mean a kid is allergic to milk, but they will probably feel bad after drinking milk or eating dairy products

What would be the potential difference of the capacitor if it is connected to a battery of 3v?

Answers

Answer: 3V

Explanation:

If the capacitor is connected to a 3V battery:

[tex]\bold{V = \frac{Q}{C} }[/tex]

The potential difference is also 3V on the capacitor

Most patients are likely to express their fears, anxieties, or uncertainties to who

Answers

Most patients being likely to express their fears, anxieties, or uncertainties to their healthcare provider is False.

Who is a Patient?

This refers to an individual who is a recipient of healthcare services provided by healthcare professionals.

Due to the stigma associated with mental health, a patient would less likely express fears and anxieties to the healthcare professionals.

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Conceptual Example 14 provides useful background for this problem. A playground carousel is free to rotate about its center on frictionless bearings, and air resistance is negligible. The carousel itself (without riders) has a moment of inertia of 105 kg·m2. When one person is standing at a distance of 1.57 m from the center, the carousel has an angular velocity of 0.512 rad/s. However, as this person moves inward to a point located 0.507 m from the center, the angular velocity increases to 0.795 rad/s. What is the person's mass?

Answers

For one person standing at a distance of 1.57 m from the center, the carousel has an angular velocity of 0.512 rad/s, the person's mass  is mathematically given as

m = 24.2 kg

What is the person's mass?

Generally, the equation for the conservation  angular momentum  is mathematically given as

(I + m * r0^2) * w0 = (I + m * r^2) * w^2

Therefore

(105 + m * 1.78^2) * 0.517 = (105 + m * 0.524^2) * 0.841

m = 24.2 kg

In conclusion, the mass  

m = 24.2 kg

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Hello, please help!
Physics teacher asked us to answer and give explanation to why:
Can light bend around corners?
THNX SO MUCH

Answers

Answer:

Yes, light can bend around corners.

Explanation: In fact, light always bends around corners to some extent. This is a basic property of light and all other waves. The amount of light that bends around a corner depends on the exact situation.

Thanks for asking the question!!

BRAINLIEST
1. What does the percent difference between GPE and KE tell you about the efficiency of energy transformations in this experiment?

2. Use a computer or graphing calculator to graph the percent difference in data table 1 versus mass, and the percent difference in data table 2 versus change in height (Δh). Based on your results that you see plotted for the two rounds of experiments, how would you adjust the mass and height so that the design of the system leads to GPE and KE values that are as close as possible? Explain why you think this design would achieve the desired result.

btw are my datas in the graph right? i added the gpe ke and %diff

Answers

The percent difference between GPE and KE in the experiment illustrates that the higher the percentage, the more efficient the energy transfer.

What is energy transformation?

It should be noted that energy transformation simply means the process of changing energy from one form to another form.

In this case, the percent difference between GPE and KE in the experiment illustrates that the higher the percentage, the more efficient the energy transfer.

Also, the mass and height should be adjusted in such a way that the design of the system leads to GPE and KE values that are as close as possible.

Learn more about energy transformation on:

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The experiment's percent difference between GPE and KE shows that the efficiency of energy transfer increases with percentage.

Thus, It should be emphasized that the term "energy transformation" simply refers to the act of altering energy's form.

The experiment's percent difference between GPE and KE in this instance demonstrates that the more significant the percentage, the more effectively energy is transferred.

The experiment's percent difference between GPE and KE in this instance demonstrates that the more significant the percentage, the more effectively energy is transferred.

Thus, Energy is capable of changing its forms. For instance, your body stores chemical energy from the food you eat until you can use it as kinetic energy when working or playing.

Learn more about Energy, refer to the link:

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#SPJ6

Balance the equation with the correct coefficients.

C2H2 +
02 →
CO2 +
H2O

Answers

Answer:

(2) C2H2 + (5) O2= (4) CO2 + (2) H2O

Explanation:

A revolving door continues to rotate even after the person pushing it exits. Is it Newton's first law of motion, Newton's second law of motion. or Newton's third law of motion?​

Answers

Answer:

Newton's third Law

Explanation:

Newton’s first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

What is the centripetal acceleration of 30 kg child standing 5 meters from the center of a
rotating carousel? The carousel is rotating at a linear velocity of 20 m/s.

Answers

Answer:

80m/s2

Explanation:

m=30kg. r = 5meter v = 20m/s2 a= ? centripetal acceleration = v*v/r

20*20/5=80m/s2

centripetal acceleration=80 m/s2


A heat engine exhausts 6000 J of heat while performing 2000 J of useful work.
Determine the efficiency of the engine

Answers

Answer:

Explanation:

The efficiency can be calculated by:

[tex]\eta = \frac{Q_{E}-Q_{W}}{Q_{E}}=\frac{6000-2000}{6000}=\frac{2}{3}[/tex]

or we can say it becomes approximately 66.7%

Which phrase describes the heating element of a toaster oven?

1 a conductor surrounded by an insulator
2 an insulator, which stops the flow of electricity
3 a resistor, which converts some electric energy to thermal energy
4 a conductor, which carries electric currents

Answers

Answer:3

Explanation:

Answer Is:3.a resistor, which converts some electric energy to thermal energy

Explanation:

I Took Quiz Got 100%

A toy car, with mass of 6 Kg, is pushed with a force of 10 N. If the toy car is in the grass with a coefficient of friction of 0.1 then what is the acceleration?

How far does it get pushed in 10 s?

Answers

Fy=ma

Fn-mg=ma
Fn-6(10)=6a
Fn=6a+60

Fx=ma

10-Ff=ma
10-(Fn)(0.1)=6a
0.1Fn=-6a+10
Fn=-6a+10/0.1

(substitute)
-6a+10/0.1=6a+60
-6a+10=0.6a+6
-6.6a=-4
a≈0.61m/s^2

Use Kinematics to find x in 10s

x=Vt+1/2at^2
x=0+1/2(0.61)(10)^2
x≈30.3m

I hate physics :p hope this is accurate

The density of lead is 30.2g/cm^3.what is the value in kilograms per meter cube?

Answers

Answer:
11300 kgm3

Hope this helps

2 moles of a monatomic ideal gas is placed under a piston in a cylindrical container. The piston can move freely up and down without friction and its diameter is 20 cm. A 50 kg weight i placed on the top of the piston. The initial temperature of the gas is 0°C. A. Calculate the absolute pressure in the container. B. Calculate the volume of the gas. D. Calculate the amount of work done by the gas during its expansion.​

Answers

The absolute pressure in the container when the monatomic ideal gas is placed under a piston is 1.17 × 10⁵ pa

How to calculate pressure?

The absolute pressure in the container will be:

= Po + mg/A

= 1.013 × 10⁵ + (50 × 9.8)/(π × 0.1²)

= 1.17 × 10⁵ pa

The volume of the gas will be:

= nRT/P

= 2 × 8 × 3.14 × (0 + 273)/(1.17 × 10⁵)

= 0.0388m³

The amount of work done by the gas during its expansion will be:

= 1.17 × 10⁵ × (0.053 - 0.0388)

= 1661J

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What is electrical power and how is it measured?

Answers

Answer:

power is measured in watts and its the messure of work over time.

Explanation:

Can someone help with this

Answers

Hi there!

A.

We can use the work-energy theorem to solve.

Initially, both blocks have gravitational potential energy, which is then converted to kinetic energy.

Recall:
[tex]U = mgh \\[/tex]

U = Potential Energy (J)
m = mass (kg)
g = acceleration due to gravity (m/s²)

h = height (m)

And at the end, block 2 has both kinetic and potential energy. Kinetic is defined as:
[tex]KE = \frac{1}{2}mv^2[/tex]

v = velocity (m/s)

We can do a summation of initial and final forces.

Initial:
[tex]E_i = m_2g\frac{h}{2} + m_1gh[/tex]

Final:
[tex]E_f = \frac{1}{2}m_2 v^2 + m_2g\frac{3h}{2} + \frac{1}{2}m_1 v^2[/tex]

Set the two equal (no energy loss in this situation) and solve for velocity.

[tex]m_2g\frac{h}{2} + m_1gh = \frac{1}{2}m_2 v^2 + m_2g\frac{3h}{2} + \frac{1}{2}m_1 v^2\\\\m_2g\frac{h}{2} + m_1gh - m_2g\frac{3h}{2} = \frac{1}{2}m_2 v^2 + \frac{1}{2}m_1 v^2\\\\v^2 = \frac{gh(\frac{m_2}{2} + m_1 - \frac{3m_2}{2})}{\frac{1}{2}m_2 + \frac{1}{2}m_1}\\\\v = \sqrt{\frac{gh(\frac{m_2}{2} + m_1 - \frac{3m_2}{2})}{\frac{1}{2}m_2 + \frac{1}{2}m_1}}\\\\v = \boxed{3.704 \frac{m}{s}}[/tex]

**This can be solved in a simpler way using a summation of forces.

B.

Now, we can do a summation of forces to solve. First, we must solve for the acceleration of the system now that we have found the velocity. Use the kinematic equation:
[tex]v_f^2 = v_i^2 + 2ad[/tex]

Initial velocity is 0 m/s, so:
[tex]v_f^2 = 2ad\\\\a = \frac{v_f^2}{2d} = \frac{(3.704^2)}{2(2.10)} = 3.267 \frac{m}{s^2}[/tex]

Now, we can use a summation of forces for any block. We can do block 1:
[tex]\Sigma F = m_1g - T[/tex]

Using Newton's Second Law:
[tex]m_1a = m_1g - T\\\\T = m_1g - m_1a \\T = m_1 (g - a) = 4.10(9.8 - 3.267) = \boxed{26.828 N}[/tex]

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