The vertices of △ABC are A(2, −3), B(−3, −5), and C(4, 1). If (x,y)--> (x-4, y-1), give the vertices of △A′B′C′.

Let x be the amount raised by each club member. Since there are 60 members, the amount raised by them would be

Now, we know the school contributed $1,000. Now, the amount raised is:

Since this amount has to be at least $5,000, we have that the inequality that shows the amount of money that each glee club member needs to raise to help pay for the trip is:

Answer: Option A

Answer: Cumulative frequency distribution

Step-by-step explanation: Not entirely sure but I believe you are looking for this definition based on the question. Hope this helps :)

Using first equation

y=x-6

substitute x = 5 into the equation

y = 5-6

y = -1

Or

Using second equation

-2x+3y=-13​

substitute x = 5 into the equation

-2(5) + 3y = -13

-10 + 3y = -13

3y = -13 + 10

3y = -3

y = -3/3

y = -1

16) We know that the triangles are similar because the three angles are equal in both triangles:

The angles in K are opposite by the vertex, so they are equal.

We also know that angles L and N are equal too.

By the rule of the sum of the angles in a triangle, we know that the third angle has to be equal.

Also, the side opposite to the angle N and L in each triangle have the same measure, so we can conclude that the triangles are similar.

y = 2x - 12

For the given figure, we will prove the triangles BGH and BDH are congruent.

So, the proof will be as follows:

Statement Reason

1) m∠F = m∠FEG = m∠FGE Given

2) ΔFGE is an equilateral triangle from (1), the definition of an equilateral Δ

3) FG = GE from (2), the definition of equilateral Δ

4) FG = ED Given

5) m∠ GEH = m∠DEH Given

6) EH = EH Reflexive property

7) ΔGEH ≅ Δ DEH SAS postulate

8) GH = DH from (7) CPCTC

9) m∠GHE = m∠DHE from (7) CPCTC

10) m∠GHB = m∠DHB Definition of supplementary angles

11) HB = HB Reflexive property

12) ΔBGH ≅ ΔBDH SAS postualte

13) ΔAGB is an isosceles Δ Given

14)AG = AB Definition of isosceles Δ

15) ΔBCD is an isosceles Δ Given

16) CB = CD Definition of isosceles Δ

17) CB = AG Given

18) m∠CDB = m∠CBD Definition of isosceles Δ

19) m∠ABG = m∠AGB Definition of isosceles Δ

20) m∠CDB = m∠AGB Given

21) m∠ABG = m∠CBD Transitive property

22) Δ AGB ≅ ΔCBD AAS postualte

EXPLANATION :

The cost of a 12 nights camp accommodation is 6720.

We need to divide the cost by 12 to get the cost per day.

Now, we are asked to find the cost of 7 nights and 4 nights.

We just need to multiply the daily rate by the number of nights.

a. 7 nights :

7 x 560 = 3920

b. 4 nights :

4 x 560 = 2240

ANSWER :

a. 3920

b. 2240

To question 16, we see that for every change of plus 2 drinks, they pay an additional value of $2.50. It means that each drink does cost half of this value.

This way, the equation that will give the value of the total cost will be:

Where X stands for the number of drinks, and 1.25 is the value of a single drink.

From the solution presented above, we are able to conclude that the rate of change represents the value of a unitary drink, in the present situation.

Using the law of cosines, the missing angles are:

A = 34.1°, B = 44.4°, C = 101.5°

The law of cosines is used to solve a triangle when given the lengths of the three sides of a triangle, and it is expressed by the formula:

c² = a² + b² - 2ab × Cos C.

Given the following:

Find C by substituting the values into the law of cosines formula:

7² = 4² + 5² - 2 × 4 × 5 × Cos C

49 = 16 + 25 - 40 × Cos C

49 = 41 - 40Cos C

49 - 41 = -40Cos C

8/-40 = Cos C

-0.2 = Cos C

C = Cos^(-1)(-0.2)

C = 101.5°

Find B using the Law of Sines:

sin B/b = sin C/c

Substitute

sin B/5 = sin 101.5/7

(sin B)(7) = (sin 101.5)(5)

sin B = (sin 101.5)(5)/7

sin B = 0.69995

B = Sin^(-1)(0.69995)

B = 44.4°

Find the measure of angle A using the triangle sum theorem:

A = 180 - 101.5 - 44.4

A = 34.1°

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Parallel lines has the same slope. In our case, the slope is -5. Then, the searched line has the form:

where b is the y-intercept.

We can find b by substituting the given point (3,2) into the las equation. Then, we have

which gives

Therefore, the parallel lines is given by

Given the following question:

We are given the repeating decimal of 0.45

We will use the formula:

The probability that the sample proportion will differ from the population proportion by less than 0.03 exists 0.9909.

A probability is a numerical representation of the likelihood or chance that a specific event will take place. Both proportions ranging from 0 to 1 and percentages ranging from 0% to 100% can be used to describe probabilities.

Let the true proportion exists 0.07

number of samples exists 492 then we get

√(0.07)(1−0.07)/492 ≈ 0.01150291586

Since the true value of the population proportion exists 0.07, the value of p^ must fall between 0.04 and 0.10 in order for the error of estimation to be less than 0.03.

Therefore, the probability that the sample proportion will differ from the population proportion by less than 0.03 exists 0.9909.

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SOLUTION

Given the question in the question tab, the following are the solution steps to answer the question.

STEP 1: Get the total number of visitors on saturday

STEP 2: Get the proportion/probability of the people who went to the Youth Wing on Saturday

STEP 3: Get the expected number of people to visit the Youth Wing on Sunday

Hence, the expected number of people to visit the Youth Wing on Sunday is approximately 382 people

Answer:

x = -9

6x + 42 = -12

6x = -54

x = -9

The expression that we can replace in the second equation is 4 - y, doing that, we will get the solutions:

x = -8 and y = 12

Here we have the system of equations:

x=4−y

3x+2y=15

Notice that x is already isolated on the first equation, so we can substitute that in the second equation. Then we will get:

3x+2y=15

3*(4 - y) + 2y = 0

So the expression that could be substituted for x in the second equation is 4 - y.

And now we get:

12 - 3y + 2y = 0

12  = y

And the value of x is:

x = 4 - y = 4 - 12 = -8

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Answer: 126

Step-by-step explanation:: 90 ÷ 10 = 9 (10%) 9 × 4 = 36 (40%) 90 + 36 = 126

two lines are parallel if their slope is equal

equation of line is

y=mx+c

where m=slope

for y=2x-5

m=2

for -x+2y=-5

2y=-5+x

y=-5/2+x/2

m=1/2

lines are nor parallel becuase m (slope) is not equal

now we will test for perpendicularity

perpendicular lines have slopes that are reciprocal of each other

first line , m=2

second line, m=1/2

2 and 1/2 are reciprocals

therefore, the lines are perpendicular

The value of a in the equation (3x869)+(19x528)+428(3)(1049)=a is 1359555

From the question, the equation to evaluate is given as

(3x869)+(19x528)+428(3)(1049)=a

Rewrite the above equation to make it legible

So, we have the following equation

(3 x 869) + (19 x 528) + 428(3)(1049) = a

Evaluate the products in the expression

So, we have the following equation

2607 + (19 x 528) + 428(3)(1049) = a

Evaluate the other products in the expression

So, we have

2607 + 10032 + 428(3)(1049) = a

Remove the brackets in the equation

So, we have the following equation

2607 + 10032 + 1346916 = a

Evaluate the sum

1359555 = a

Rewrite as

a = 1359555

Hence, the solution to the equation is 1359555

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The rate at which the base of the triangle is changing is equal to,

dB = -6.3 cm/minutes.

From the data given in the question.

The rate of increase in the area of the triangle, dA = 4.5 cm/minute

The rate of increase in the altitude of the triangle, dH = 3.5 cm/minute

The Area of the triangle, A = 87 square centimeters

The altitude of the triangle, H = 7.5 centimeters

The equation for the area of a triangle is equal to

A = 0.5×B×H

Plug in A and H to solve for B at that point:

87 = 0.5×B×7.5

B = 23.2

Differentiate the equation for the area of a triangle to find the rate of change of the area of a triangle (dA):

dA = 0.5× dB× H + 0.5×B × dH.

Plug in known variables to solve for the rate of change of the base dB

dA = 0.5 × dB × H + 0.5 × B × dH

4.5 = 0.5 × dB × 7.5 + 0.5 × 23.2 × 3.5

The rate at which the base of the triangle is changing is equal to,

dB = -6.3 cm/minutes.

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Since the speed of the turbopropeller plane was 200 mph faster than the speed of the car, the speed of the turbopropeller plane is equal to 70 mph.

In order to solve this word problem, we would assign variables to the distance and speed of both Mattie's car and the turbopropeller plane, and then translate the word problem into algebraic equation as follows:

Translating the word problem into an algebraic equation, we have;

v₂ = v₁ + 200

Since Mattie and the turbopropeller plane travled at the same time, we have:

Time = distance/speed

Time = d₁/v₁ = d₂/v₂

Time = 140/v₁ = 540/v₁ + 200

Cross-multiplying, we have:

140(v₁ + 200) = 540v₁

140v₁ + 28,000 = 540v₁

Next, we would rearrange the equation by collecting like terms as follows:

540v₁ - 140v₁ = 28,000

400v₁ = 28,000

Speed of plane, v₁ = 28,000/400

Speed of plane, v₁ = 70 mph.

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1) Considering that the slant height of those pyramids is 4 and 6, we can find the scale factor by dividing their slant heights:

So we can state that the bigger pyramid is larger than the 1st pyramid by a scale factor of 1.5.

2) For the Volume of the Pyramid, we can write out the formula below:

Since the scale factor is 1.5 Then we can state that

the Volume of the smaller one is by similarity 1.5 or 3/2 times smaller than the larger one.

3) Hence, the answers are:

1.k=1.5

2. 32 m³

Statement Problem: Shane is a building engineer and is determining the length of an access ramp needed to reach a step 1.5 feet off the ground. He knows the length of the ramp, r, in feet, can be expressed with the equation below.

First, Shane finds that sin(4.5°) ≈ 0.08. Using his calculator, he then calculates the length of the ramp as shown below.

What could Shane do to make his calculation more accurate?

Solution:

The length of the ramp, r, in feet is expressed using the sine ratio;

Hence, Shane's calculation would be more accurate if he uses sin (4.5 degrees) in his calculator instead of 0.08

CORRECT OPTION: A

The resulting sample space of the given situation is S = {PQ, QP, PR, RP, QR, RQ}

Sample space:

Sample space refers the collection or a set of possible outcomes of a random experiment. The sample space is represented using the symbol, “S”.

Given,

Patty, Quinlan, and Rashad want to be club officers. The teacher who directs the club will place their names in a hat and choose two without looking. The student whose name is chosen first will be president and the student whose name is chosen second will be vice president.

Here we need to find the sample space for the event.

Let us consider,

P represents Patty

Q represents Quinlan

R  represents Rashad

And through the question we have know that, the teacher drawn two card at a time,

So we have consider that the teacher is going to draw out of the hat one first, without replacement, and then draw another one.  

The first chosen one will be the president, and that could be P, Q or R, Now, the chosen second one is the Vice president, and already one has already being drawn, that could only be two fellows.

Therefore, the total of likely outcomes is PQ,QP, PR, RP, QR, RQ, one paired up with either of the two remaining in the hat.

So, the resulting sample space is

S = {PQ, QP, PR, RP, QR, RQ}

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The variable expression is;

Here, we want to select an option that represents the phrase

The quotient of a number x and 8 means that we divide x by 8

That means we have a fraction, with x as the numerator and 8 as the denominator

We have this as;

5 more than this quotient means that we are to add 5 to the result

We have this as;

For the right triangle shown in the picture, recall the trigonometric identity of the cosine function:

Isolate a from the equation:

Substitute for c=6.3 and B=43.8°:

Use a calculator to evaluate the expression:

Scatter plot with x axis labeled variable x and y axis labeled variable y. Points go from lower left to upper right.

Answer:

[tex]x=\frac{-m-n+p}{-y+1}[/tex]

Step-by-step explanation: