Let x represent Mikhail's age.
Since Gabrielle is 8 years older than Mikhail, it means that Gabrielle's age is
x + 8
If the sum of their ages is 104, it means that
x + x + 8 = 104
2x = 104 - 8
2x = 96
x = 96/2
x = 48
Mikhail's age is 48
y varies inversely as x. y=12 when x=7. Find y when x=2
We write as an inverse proportion first then make an equation by multiplying by k:
[tex]y=\frac{k}{x}\Rightarrow k=x\times y[/tex]Find the value of k:
[tex]k=7\times12=84[/tex]Then, when x = 2, y is:
[tex]y=\frac{84}{2}=42[/tex]Answer: y = 42
multiply decimals 3.76 × 4.8=this is how the problem needs worked
18.048
Explanation:[tex]\begin{gathered} 3.76\text{ }\times\text{ 4.8} \\ \\ To\text{ make it easy, we remove the decimal points while multiplying:} \\ 376\text{ }\times\text{ 48} \end{gathered}[/tex][tex]\begin{gathered} We\text{ count the numbers of decimal points:} \\ 2\text{ decimal point in 3.46} \\ 1\text{ decimal point in 4.8} \\ \text{Total decimal points = 3} \\ We\text{ count 3 decimal points in our result} \end{gathered}[/tex]The result is 18.048
can u pls help me with this question and this is homework
the probability is:
[tex]\frac{15+5}{50}=\frac{20}{50}=\frac{2}{5}[/tex]so the answer is 2/5
Factor the given polynomial by finding the greatest common monomial Factor 6x^3y+9xy^3
Answer:
(3xy)(2x² + 3y²)
Step-by-step explanation:
Hello!
The greatest common factor for the coefficients is 3, as both terms have a coefficient with the greatest factor of 3.
The greatest common factor for the x-terms is x, as both terms has x to a minimum of the first power.
The greatest common factor for the y terms is y as both terms has y to a minimum of the first power.
Factor out 3xy:6x³y + 9xy³3xy(2x²) + 3xy(3y²)(3xy)(2x² + 3y²)The factored form is (3xy)(2x² + 3y²).
Kyle has a container of flour in the shape of a cylinder.
Answer:
Part A:
The volume of a cylinder is given below as
[tex]\begin{gathered} V_{cylinder}=\pi\times r^2\times h \\ r=\frac{d}{2}=\frac{10in}{2}=5in \\ h=8in \end{gathered}[/tex]By substituting the values , we will have
[tex]\begin{gathered} V_{cyl\imaginaryI nder}=\pi r^2h \\ V_{cyl\mathrm{i}nder}=\pi\times5^2\times8 \\ V_{cyl\mathrm{i}nder}=\pi\times200 \\ V_{cyl\mathrm{i}nder}=628.3in^3 \end{gathered}[/tex]Hence,
The volume = 628.3in³
Part B:
To determine the weight of the flour in ounces, we will use the relation below
[tex]\begin{gathered} 0.13ounce=1in^3 \\ x=628.3in^3 \\ cross\text{ multiply, we will have} \\ x=0.13\times628.3 \\ x=81.679 \\ x\approx81.7ounces \end{gathered}[/tex]Hence,
The weight = 81.7 ounces
Which of the equations below could be the equation of this parabola?
10-
(0,0)
Vertex
-10
O A. y--/2²2
O B. x=2²
O c. y-1/2x²
O D. x=-12²
10
The equation of this parabola is Y = -1/2 X². So option C is correct.
What is an Equation ?An equation is a mathematical term, which indicates that the value of two algebraic expressions are equal. There are various parts of an equation which are, coefficients, variables, constants, terms, operators, expressions, and equal to sign.
Given that,
The graph of parabola,
the vertex (0, 0)
Y - 0 = 4a (X - 0)²
Y = 4aX²
It can be seen in the graph it is downward parabola so value a should be less than zero
So possible equation could be Y = -1/2 X²
Hence, the equation is Y = -1/2 X²
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Jalisa needs to purchase a cover for her oval-shaped pool. The pool's length and width measurements, as marked by dotted lines, are 30 feet and 13 feet.If Jalisa wants the pool cover to extend one foot from the pool's edge, as shown in the drawing, what will be the area of therectangular pool cover?A. 390 square feetOB. 434 square feetOC 480 square feetD. 86 square feet
She wants to cover the pool with a rectangular pool cover that extends one foot from the pool edges in every direction.
The length of the pool is 30ft and the width is 13ft, if the pool cover must extend 1ft over the pool's edge, then you have to add 2ft to the length and 2ft to the width, as shown below:
So, the length of the pool cover will be equal to the length of the pool plus two feet:
[tex]length=30ft+2ft=32ft[/tex]And the width of the pool cover will be equal to the width of the pool plus two feet:
[tex]width=13ft+2ft=15ft[/tex]Once you determined the width and length of the rectangular pool cover, you can calculate its area:
[tex]\begin{gathered} A=wl \\ A=15*32 \\ A=480ft^2 \end{gathered}[/tex]The area of the rectangular pool cover is 480 square feet (option C)
help with this functions and equations question. please answer correctly
The distance D(t) Maya travels in her racecar and the times taken, given in the table indicates the average rate of change of distance over the specified times are;
(a) 30.3 meters per second
(b) 25.4 meters per second
What is the average rate of change of a function?The average rate of change of a function, over an interval, gives the rate at which the function changes per unit of the interval.
The average rate of change of the distance is given by the equation;
[tex] \displaystyle {Average \: rate \: of \: change = \frac{The \: sum \: of \: distance \: traveled }{The \: sum \: of \: the \: time taken } }[/tex]
The following values are obtained from the given table;
(a) At time t = 0 seconds, distance traveled, D(0) = 0 meters
At time t = 5 seconds, distance traveled, D(5) = 151.5 meters
Which gives the average rate of change as follows;
[tex] \displaystyle {Average \: rate \: of \: change = \frac{(151.5 - 0) \: m }{(5 - 0 ) \: s} = 30.3 \: m/s }[/tex]
The average rate of change for distance driven is 30.3 meters per second(b) The table gives that at time, t = 7 seconds, distance traveled, D(7) = 205.1 meters and that at time t = 9 seconds, distance traveled, D(9) = 255.9 meters, which gives;
[tex] \displaystyle {Average \: rate \: of \: change = \frac{(255.9 - 205.1) \: m }{(9 - 7) \: s} = 25.4 \: m/s }[/tex]
The average rate of change of distance between the points in time of 7 seconds and 9 seconds is 25.4 meters per secondLearn more about the average rate of change of a function here:
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Using everyday knowledge, indicate whether the if-then statements are correct forward-only or both forward and reverse.
Statement 1: If Bob is Sally’s spouse, then Sally is Bob’s spouse.
Statement 2: If the light is red Northbound, then the traffic is stopped.
Find the length of the third side. If necessary, write in simplest radical form.
4
4√5
Theoretical Probabilities. Use the theoretical method to determine the probability ofthe following outcomes and events. State any assumptions that you make. Drawing a king from a standard deck of cards
Recall that the theoretical probability that an event occurs is given by the following quotient:
[tex]\frac{\text{favorable cases}}{total\text{ cases}}.[/tex]We know that in a standard deck there are 52 cards from which 4 are kings, therefore:
[tex]\text{Probability of drawing a king=}\frac{4}{52}.[/tex]Answer:
[tex]\frac{4}{52}\text{.}[/tex]Teresa has a bookcase with 8 shelves. There are n books on each shelf. Using n, write an expression for the total number of books.
Answer:
8*n
Step-by-step explanation:
You solve this question by multiplying the number of shelves by the number of books to find the total number of books on the shelves.
Solve for the remaining angles and side of the one triangle that can be created. Round to the nearest hundredth:A = 100"a = 3.5, b = 3
Given:
• A = 100 degrees
,• a = 3.5
,• b = 3
Let's solve for the remaining angles and side of the triangle.
Here, we are given one angle and two sides.
To solve, apply the Law of Sines:
[tex]\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}[/tex]• To solve for measure of angle B, we have:
[tex]\begin{gathered} \frac{\sin A}{a}=\frac{\sin B}{b} \\ \\ \frac{\sin100}{3.5}=\frac{\sin B}{3} \\ \\ \sin B=\frac{3\sin 100}{3.5} \\ \\ \sin B=\frac{2.954}{3.5} \\ \\ \sin B=0.844 \end{gathered}[/tex]Take the sine inverse of both sides:
[tex]\begin{gathered} B=\sin ^{-1}(0.844) \\ \\ B=57.58^0 \end{gathered}[/tex]Therefore, the measue of angle B is = 57.58 degrees.
• To solve for angle C, apply the Triangle Angle Sum Theorem.
m∠A + m∠B + m∠C = 180
m∠C = 180 - m∠A - m∠B
m∠C = 180 - 100 - 57.68
m∠C = 22.32
The measure of angle C is 22.32 degrees.
• To find the length of c, apply the Law of Sines:
[tex]\begin{gathered} \frac{\sin A}{a}=\frac{\sin C}{c} \\ \\ \frac{\sin100}{3.5}=\frac{\sin 22.32}{c} \\ \\ c=\frac{3.5\sin 22.32}{\sin 100}\tan ^{-1}\tan ^{-1} \\ \\ c=\frac{1.329}{0.9848} \\ \\ c=1.35 \end{gathered}[/tex]The length of side c is 1.35 units.
ANSWER:
• B = 57.58,°
,• C = 22.32,°
,• c = 1.35
A football team is losing by 14 points near the end of a game. The team scores two touchdowns (worth 6 points each) before the end of the game. After each touchdown, the coach must decide whether to go for 1 point with a kick (which is successful 99% of the time) or 2 points with a run or pass (which is successful 45% of the time). If the team goes for 1 point after each touchdown, what is the probability that the coach’s team wins? loses? ties? If the team goes for 2 points after each touchdown, what is the probability that the coach’s team wins? loses? ties? Can you develop a strategy so that the coach’s team has a probability of winning the game that is greater than the probability of losing
His football team is losing 14 points near the end of the game. The team scores two touchdowns with each worth 6 points (total = 12 points).
After each touchdown, the coach must decide whether to go for 1 point with each kick(99% successful) or 2 points with a run or pass(45% successful).
Note
Two touchdown = 12 points
So, it remaining 2 point to level up and more than 2 points to win the game
a.
If the team goes for 1 point after each touchdown, the probability that the coach's team loses? wins? ties? can be computed below
[tex]undefined[/tex]Can you help me resolve this using the quadratic formula?
a) Time taken to hit the ground = 1.674 seconds
b) Height at 1 second = 12 m
Explanation:The equation representing the height of the water balloon after t seconds is:
[tex]h(t)=-16t^2+25t+3[/tex]a) At the ground, h(t) = 0
[tex]\begin{gathered} 0=-16t^2+25t+3 \\ \\ 16t^2-25t-3=0 \\ \\ Using\text{ the quadratic formula} \\ t=\frac{-(-25)\pm\sqrt{(-25)^2-4(16)(-3)}}{2(16)} \\ \\ t=\frac{25\pm\sqrt{817}}{32} \\ \\ t=-0.111975,\text{ 1.67448} \end{gathered}[/tex]Since time cannot be negative:
Time taken to hit the ground = 1.674 seconds
b) Height at t = 1 second
[tex]\begin{gathered} H(t)=-16t^2+25t+3 \\ \\ H(1)=-16(1^2)+25(1)+3 \\ \\ H(1)=-16+25+3 \\ \\ H(1)=12\text{ m} \end{gathered}[/tex]Height at 1 second = 12 m
Consider the graph of the linear function shown.What is the approximate average rate of change of this function from = -2 to r = 2?lesleso3-Yes
The average rate of change of this function from x = -2 to x = 2 can be gotten by finding the slope of the line using both x coordintes;
From the graph, when x1 = -2, y1 = 2.5
Also when x2 = 2, y2 = 0.5
Using the formula for calculating slope expressed as;
m = y2-y1/x2-x1
Substitute the given values
m = 0.5-2.5/2-(-2)
m = -2.0/2+2
m = -2/4
m = -1/2
Hence average rate of change of this function from x = -2 to x = 2 is -1/2. Option C is correct.
Use the given instructions to answer question 17 to question 20.
Given
The boxplot.
And, the total number of students in the class is 60.
To find:
a) The percentage of students who received one or more moving violation.
b) The number of parking violations received by at least 50% of students.
c) How many students received two or more parking violation.
Explanation:
a) From the figure,
The percentage of students who received one or more moving violation is,
[tex]Percentage\text{ of students}=75\%[/tex]Because the number of students having minimum moving violation is 0, and the number of students having maximum moving violation is 4.
b) The number of parking violation received by at least 50% of students is,
[tex]\begin{gathered} Number\text{ }of\text{ }parking\text{ }violation\text{ received by at least 50}\%\text{ of students } \\ is\text{ }2\text{ }or\text{ }more. \end{gathered}[/tex]c) The number of students who received two or more parking violation is,
[tex]\begin{gathered} Number\text{ of students}=75\%\times60 \\ =\frac{75}{100}\times60 \\ =45 \end{gathered}[/tex]Hence, the number of students who received two or more parking violation is 45.
2+2 is what i need help???
We have the following problem given:
[tex]2+2=4[/tex]Then the final answer for this case would be 4
Subtract the expressions. (10y - 2) - (8y + 3)
SOLUTION
We want to solve the expression
[tex]\mleft(10y-2\mright)-(8y+3)[/tex]Now, use the minus sign to multiply the other part
That is
[tex]-(8y+3)[/tex]We have
[tex]\begin{gathered} (10y-2)-(8y+3) \\ 10y-2-8y-3 \\ \text{collecting like terms } \\ 10y-8y-2-3 \\ 2y-5 \end{gathered}[/tex]Hence the answer is 2y - 5
Determine an algebraic model of a function that satisfies the following key features.
Solution:
Given the conditions;
[tex]As\text{ }x\rightarrow-\infty,y\rightarrow\infty\text{ and }x\rightarrow\infty,y\rightarrow\infty[/tex]When;
[tex]x\rightarrow-\infty,y\rightarrow\infty[/tex]Then, the degree of the polynomial is even.
Then, given three x-intercepts, it means one of the root could have been repeated.
Thus, the model function is;
[tex]f\lparen x)=\left(x+1\right)\left(x-3\right)\left(x^2\right)[/tex]The days high temperature in Detroit , Michigan was recorded as 41 degrees F . Use the formula C = 5/9 ( F- 32) to write 41 degrees F as degrees celsius
Step 1
Given;
Step 2
[tex]\begin{gathered} C=\frac{5}{9}(F-32) \\ F=41 \\ C=\frac{5}{9}(41-32) \\ C=\frac{5}{9}(9) \\ C=5^{\circ}C \end{gathered}[/tex]Answer;
[tex]5^{\circ}C[/tex]Line AB is tangent to circle C at B and line AD is tangent to circle C at D. What is the lenghth AB.
Answer:
Explanation:
The Two Tangent Theorem states that if we draw two lines from the same point which lies outside a circle, such that both lines are tangent to the circle, then their lengths are the same.
To be able to find AB we have to 1st of all find the value of x by equating both lengths together since both AB and AD are equal as shown below;
[tex]\begin{gathered} 2x^2+3x-1=2x^2-4x+13 \\ 2x^2-2x^2+3x+4x=13+1 \\ 7x=14 \\ x=\frac{14}{7}=2 \end{gathered}[/tex]S
can someone please help me find the answer to the following?
We are given a tangent and a chord of a circle. The angle ABC form by the intersection of the tangent and the chord is half the arc they both intersect, therefore, we must find the major arc of the circle, we can do that with the fact that the total arc of the circle is 360, therefore:
[tex]\begin{gathered} \text{arcAB}=360-50 \\ \text{arcAB}=310 \end{gathered}[/tex]Therefore, the angle is:
[tex]\begin{gathered} \angle ABC=\frac{1}{2}\times310 \\ \angle ABC=155 \end{gathered}[/tex]Angle ABC is 155 degrees.
On number 9, you have to figure out the value of X. I attempted to solve the equation and got the answer of 46. Am I correct?
From the number line given, we have the miles increasing from x all the way to 184. Similarly, we have the hours increasing all the way from 4 to 16.
To find out the value of x, we need to set up an equation that uses the ratio of both miles and hours. This is shown below;
[tex]\frac{x}{4}=\frac{184}{16}[/tex]We now cross multiply and we have;
[tex]\begin{gathered} x=\frac{4\times184}{16} \\ x=\frac{184}{4} \\ x=46 \end{gathered}[/tex]ANSWER:
[tex]x=46[/tex]Write the equation as an exponential equationlog_9(2x – 7) = 2x – 3
I really am struggling with this, could I have some help?
We are to find f(x) - g(x):
We will subtract the expressions of g(x) from f(x)
[tex]\begin{gathered} f(x)-g(x)=x^2\text{ + 1 - (2x - 5)} \\ \end{gathered}[/tex]Expanding the parenthesis using distributive property:
[tex]\begin{gathered} f(x)-g(x)=x^2\text{ + 1 - (2x) -(-5)} \\ mu\text{ltiplication of same signs gives positive sign} \\ m\text{ ultiplication of opposite signs give negative sign} \\ \\ f(x)-g(x)=x^2\text{ + 1 -2x + 5} \end{gathered}[/tex]collect like terms:
[tex]\begin{gathered} f(x)-g(x)=x^2\text{ -2x + 5 }+\text{ 1} \\ f(x)-g(x)=x^2\text{ - 2x + 6} \end{gathered}[/tex]For the data shown in the scatter plot, which is the best estimate of r?The answer choices are .94 .-45 .-94 .45
Pearson's correlation coefficient, r, measures the linear relationship between two variables. The correlation coefficient can take a range of values from +1 to -1.
• A value of 0 indicates that there is no association between the two variables.
,• A value ,greater than 0, indicates a ,positive association., That is, as the value of one variable increases, so does the value of the other.
,• A value ,less than 0, indicates a ,negative association,; that is, as the value of one variable increases, the value of the other decreases.
Graphically,
In this case, you can see that as the value of a variable x increases, the value of the variable y other decreases. Then, the correlation coefficient of these two variables is negative.
Also, you can see that the values of the variables do not completely fit a line but are very close to one.
Therefore, the best estimate of r is -.94.
round 6.991 to two decimal places
Since 6.99 < 6.991 < 7.00, and the number 6.991 is nearer to 6.99 than to 7.00, then 6.991 rounded to two decimal places, is:
[tex]6.99[/tex]i need help with this equation please there are two more possible answers that were cut off they are 17,2% and 19,5%
Consider that the experimental probability of an event is based upon the previous trials and observations of the experiment.
The experimental probability of occurrence of an event is given by,
[tex]\text{Probability of an event}=\frac{\text{ Number of outcomes that favoured the event}}{\text{ Total number of trials or outcomes}}[/tex]As per the problem, there are a total of 1230 trials of rolling a dice.
And the favourable event is getting a 2.
The corresponding experimental probability is calculated as,
[tex]\begin{gathered} P(\text{ getting a 2})=\frac{\text{ No. of times 2 occurred}}{\text{ Total no. of times the dice is thrown}} \\ P(\text{ getting a 2})=\frac{172}{1230} \\ P(\text{ getting a 2})\approx0.13984 \\ P(\text{ getting a 2})\approx13.98\text{ percent} \end{gathered}[/tex]Thus, the required probability is 13.98% approximately.
Theref
Please help me out here. I really don’t understand
Step-by-step explanation:
you have both points : (1, 1) and (5, 5).
so, we don't need to do any triangle calculations to get the height of the main triangle.
all we need to do is calculate the distance between these 2 points.
2 points in a coordinate grid create a right-angled triangle.
the direct distance is the Hypotenuse (the side opposite of the 90° angle). and the legs are the x- and the y-coordinate differences (one up or down the other left or right).
and we can use Pythagoras
c² = a² + b²
c being the Hypotenuse a and b being the legs.
so, how long are these legs here ?
the x-difference is 5 - 1 = 4.
also the y-difference is 5 - 1 = 4
so,
distance² = 4² + 4² = 16 + 16 = 32
distance = sqrt(32) = sqrt(16×2) = 4×sqrt(2) =
= 5.656854249...
the distance of P to the line RQ is 5.656854249...