the velocity of an object must include these two things ________ and _________

will give brainlest

Answers

Answer 1

Answer:

The velocity of an object must include these two things displacement and time.

Explanation:

Hope this helps you. Have a nice day^_^

Please mark as brainliest. It helps a lot. :)


Related Questions

help please this is due in an hour!!!

Answers

[tex]▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ [/tex]

Charge on one electron :

[tex]1.602 \times 10 {}^{ - 19} \: \: coulombs[/tex]

So, charge on ball having 97 electrons is equal to :

[tex]97 \times 1.602 \times 10 {}^{ - 19} [/tex]

[tex]155.394 \times 10 {}^{ - 19} [/tex]

[tex]1.554 \times 10 {}^{ - 17} \: \: coulombs[/tex]

What force prevents a machine from having 100% efficiency? A. Magnetic B. Electric O C. Friction O D. Gravity ​

Answers

Answer:

I believe it would be C ? my apologies if I'm wrong.

2. Starting from rest, a racecar has a displacement of 201 m south while accelerating at

16 m/s?. Calculate the time it takes the car to travel the 201 m.


Help solve please!

Answers

Answer:

Explanation:

Assuming you mean a = 16 m/s²

s = ½at²

t = √(2s/a)

t = √(2(201)/16)

t = 5.012484...

t = 5.0 s


A block of mass 2.52 kg is kept at rest
as it compresses a horizontal massless spring
(k 116 N/m) by 9.73 cm. As the block
is released, it travels 0.537 m on a rough
horizontal surface before stopping.
The acceleration of gravity is 9.8 m/s.
Calculate the coefficient of kinetic friction
between surface and block.

Answers

By Newton's second law, the net vertical force on the block is

F = N - mg = 0

so that the normal force exerted by the surface has magnitude

N = mg = (2.52 kg) (9.80 m/s²) = 24.7 N

Then as the block slides over the surface, it feels a frictional force of

f = µ (24.7 N)

where µ is the coefficient of kinetic friction.

As the block is pushed by the spring to its equilibrium position, friction performs

µ (-24.7 N) (0.0973 m) = -2.40µ J

of work (which is negative because it opposes the block's motion).

In compressing the spring by 9.73 cm = 0.0973 m, we store

1/2 (116 N/m) (0.0973 m)² = 0.549 J

of energy. This energy is released and partially converted to kinetic energy, while the rest is lost to friction.

By the work-energy theorem, the total work performed on the block as the spring pushes it towards the equilibrium position is equal to the change in its kinetic energy:

W = ∆K

0.549 J - 2.40µ J = 1/2 (2.52 kg) v ² - 0

where v is the speed of the block at the equilibrium position. Solving for v, we get

v = 0.891 √(0.549 - 2.40µ) m/s

After the block is released, the only force acting on it as it slides freely is friction. It comes to a stop after 0.537 m, so that friction performs

µ (-24.7 N) (0.537 m) = -13.3µ J

of work.

Using the work-energy theorem again, we have

W = ∆K

-13.3µ J = 0 - 1/2 (2.52 kg) v ²

Substitute the velocity we found in terms of µ, and solve for µ :

-13.3µ J = -1/2 (2.52 kg) (0.891 √(0.549 - 2.40µ) m/s)²

===>   µ = 0.0350

If a material were being designed to demonstrate no thermal expansions, how would the energy plot look like?

Answers

The characteristics of thermal expansion allow finding that the response for a material without thermal expansion is

The length variation is zero In the graph the line is horizontal so there is no change in length with temperature

Thermal expansion is the macroscopic sum of the changes in the length of the bonds when the energy (temperature) changes, it can be written

              ΔL = α L₀ ΔT

Where ΔL is the change in length, α the coefficient of linear expansion, L₀ the initial length and ΔT the change in body temperature

In this case, a material is being designed that the thermal expansion is very small, for this the material must be made up of several compounds where some of them present a contraction with temperature, some examples: water at low temperature, liquefied gases , ceramic tile, quartz, etc.

The thermal expansion measurement processes control the body temperature and measure the change in length, in this case the change in length must be zero, in the attachment we can see a graph of a composite material with these characteristics, an example of this type of material is Invar an alloy of nickel and iron α = 3.7 10⁻⁶ ºC⁻¹

In conclusion, using the characteristics of thermal expansion we can find that the response of material without thermal expansion is

The length variation is zero In the graph the line is horizontal so there is no change in length with temperature

Learn more here:  brainly.com/question/18717902

A dog is running at an initial speed of 10 m/s. He covers 50 m in 4 seconds. What is the acceleration of the dog?

a.
1.25 m/s2

b.
1.04 m/s2

c.
5 m/s2

d.
3.2 m/s2

Answers

D i hope this helps
:))

Helppppppppppppppp please and explain!

Answers

An EM with a short energy has more energy than a longer wavelength. the higher the frequency, the shorter the wavelength and the higher the energy of the wave. yw

You are driving to grandma's house, and you are traveling at an average of 70 mph. How long will it take you to travel 70 miles?
O 1 hour
O 1 second
70 hours
O 70 seconds

Answers

Answer: 1 hour

Explanation: Focus on the units; 70 miles per hour means that each hour, you will travel 70 miles

or you can use the equation time = distance/speed. You have 70miles/ 70mph = 1hour

What is the smallest part of a compound called?
element
O
molecule
O
atom
O
mixture
o

Answers

Answer:

Here is your answer,thanks for using brainly!

Explanation:

B:Molecule

Molecules usually consist of 2 atoms linked together,however some molecules  consist of thousands of atoms!

Here is a list of smalles to largest with the answers provided

Molecules

Atoms

Elements

Mixtures

Hope this helped

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Dont forget to smash that heart at the bottom <3

Have a great day!

We can only tell the earth is rotating almost 960 miles an hour if we

a
look at other people around us as a reference point.



b
look at mountains far away from us as a reference point.

c
use a reference that is not on the earth, like the sun or stars.

Answers

Answer:

C

It is C i have to type this because i need 20 characters.

Which statement describes Kepler’s third law of orbital motion?

Answers

Answer:

The square of orbital period is proportional to the cube of the semi-major axis.

Explanation:

I just took the quick check

A rock is held steady over a cliff and dropped. 1 seconds later, another rock is thrown straight down at a speed of 11.3 m/s, and hits the first rock. How far have the rocks dropped before they collide? How long is the first rock in the air before it gets hit by the second rock?

What is the displacement of the rocks when they collide? __________ (Hint: be careful of sign -- the rocks drop.)
The first rock is in the air for __________ before it is hit.

Answers

Answer:  

4.27s

Explanation:

If "t" represents the time traveled from the time rock 2 is dropped until the collision, then the time traveled for rock 1 = t + 1. And, since rock #1 is dropped making its initial velocity = 0, then:

The distance rock 1 travels is  

x = (0)(t + 1) + 1/2(-9.8)(t + 1)2 = -4.9(t2 + 2t + 1) = -4.9t2 - 9.8t - 4.9

The distance rock 2 travels  

x = -11.3t + 1/2(-9.8)t2 = -11.3t - 4.9t2

For the distances must be equal when the rocks collide:  

-4.9t2 - 9.8t - 4.9 = -11.3t - 4.9t2  

-9.8t - 4.9 = -11.3t  

-4.9 = -1.5t  

t = 3.267 s

Now, the distance they traveled can be found by plugging the 3.267 s back into either equation:

x = -11.3(3.267) - 4.9(3.267)2 = -89.2 m or 89.2 m below where they began

The time the first rock was in the air is t + 1 = 3.267 + 1 = 4.267 s = 4.27 s

Let

First rocks time be x

Second rocks time be x+1

initial velocity=u=11.3m/s

Distance of both rocks be s1 and s2

[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]

Now

[tex]\\ \sf\longmapsto s1=11.3x+5x^2[/tex]

[tex]\\ \sf\longmapsto s2=11.3(x+1)+5(x+1)^2[/tex]

As both collide then

[tex]\\ \sf\longmapsto s1=s2[/tex]

[tex]\\ \sf\longmapsto 11.3x+5x^2=11.3x+11.3+5(x+1)^2[/tex]

[tex]\\ \sf\longmapsto 5x^2=11.3+5x^2+10x+1[/tex]

[tex]\\ \sf\longmapsto 10x+12.3=0[/tex]

[tex]\\ \sf\longmapsto x=1.23s[/tex]

Displacement

[tex]\\ \sf\longmapsto 11.3(1.23)=13.8m[/tex]

Done

What is the pulling force of this train, if its engine provides 4200 kW power and 90 km/h speed?

Answers

Answer:

yes by 30

Explanation:

uhnhuh

two balls are dropped from rest and allowed to fall for 1 s and the other for 3 s, compare the distances they have fallen​

Answers

Answer:
distance traveled by 3 second ball ≈ 45m
distance traveled by 1 second ball ≈ 5m

Explanation:

Since the 2 balls started at rest, their v initial = 0, and since no other force is acting on them except for the gravitational force, they accelerate downwards at 10m/s2.

To calculate the distance traveled by both balls, we apply the second formula of UARM motion:

• Δx = 1/2(a)(t^2) + (v0)(t)

Applying both 1s and 3s in this formula will yield you 5m and 45m respectively.


Hope this helps, brainliest would be appreciated :)

Everytime a train passes Ms. Lindsey's house, one specific item on her dresser rattles. Use physics to explain why this occurs.

Answers

Answer: gravity

Explanation: the moving and sifting around in the train

a father and his son are racing down a mountain. if they're traveling at the same velocity who has more kinetic energy​

Answers

Answer:

I think it's the son

Explanation:

bcs he might love it

Which stament describes Newton’s law of universal gravitation

Mass has little effect on gravity between objects

Gravity pushes objects away from earths center

Gravity does not act between earth and the moon

Every object in the universe attracts every other object
I’ll give brainliest

Answers

every object in the universe attracts every other object

PLEASEEEEEE HELPPPPPPP MEEEEEEEE!!!!!!!!!!!!!

Answers

Answer:

[tex]2 \\ because \\ 2 - 2 = 0 \\ 5 - 5 = 0[/tex]

A train travels meters in the first second of travel, 6 meters again during the second second of travel, and 6 meters again during the third second. Its
acceleration is
O 0 m/s
6 m/s
O 12 m/s/s
18 m/s
O None of the above

Answers

Answer:

0 m/s

Explanation:

there is no acceleration, it's velocity is always 6m/s

so your answer is 0m/s

Say hi :P...................................................................

Answers

HELLOOOOOOOOOOOOOOOOOOOOO

If an athletic field has 440 metre, how many rounds must an athlete do to cover a half marathon, I.e 21km and 200 metre

Answers

Answer:

53

Explanation:

Given:

perimeter of the field = 440 m

Half of the distance of marathon = 21 km and 200 meter

Step-by-Step Explanation:

21 km 200 meter

=

21200 Meter                                   (1km= 1000M)

21200 ÷ 400

= 53

Michael stands upright and allows his right arm to swing back and forth, naturally and without forcing, like a pendulum. He measures the time for 21 oscillations (complete cycles) to be 28.1 s. Assume his arm (length L) behaves as a simple pendulum, with an effective length of 2/3 L. Find the length of his arm, L.

Answers

Answer:

ytdgnrjjksmzjj3hfgbdhehkj jfjbcjbwbjrhrhb jdhbbjhhrhrhhjrjjr jfjnekrj

The length of his arm, L = 0.67 m.

What is time period?

A basic pendulum consists of a point mass hung by a tightly supported, weightless, and inextensible string.

T = 2π√ L/g, where L is the pendulum's length and g is the acceleration brought on by gravity, is the formula for a pendulum's period.

Given in the question  the time for 21 oscillations (complete cycles) to be 28.1 s. Assume his arm (length L) behaves as a simple pendulum, with an effective length of 2/3 L.

T = 2π√ L/g

T = 2π√2l/3g

T = 28.1/21

T = 1.33

2π√2l/3g =  1.33

l = .67 m

The length of his arm, L = 0.67 m.

To learn more about time refer to the link:

brainly.com/question/13764813

 #SPJ5

Which of the following is the best hypothesis

Answers

Answer:

Melting and frezzing are physical changes

In two paragraph of lines each, describe how you
would simplify, for your
grade 10 learners the
following topics
1.1 Electricity and magnetism.

Answers

The question above wants to assess your ability to simplify complex matters. In that case, I can't answer this question for you, but I'll show you how to answer it.

First, you should research electricity and magnetism. This research will make you understand the subject and all its elements. You can do this research in textbooks and digital platforms aimed at children and teenagers since these media usually present subjects in a more simplified way.

After doing this research, you will be able to write a text about electricity and magnetism as follows:

Present the main focus of this subject.Present the elements that make up this subject.Present how this subject applies in the real world.Present the importance of this subject in human life and society.

Remember that you must use simple language, without the use of technical terms, but with common terms.

More information:

https://brainly.com/question/14870576?referrer=searchResults

plz help owo

What characteristic is shared by sunspots, solar flares, and coronal mass ejections? Select the two correct responses.


They are caused by outward fluctuations of the sun's magnetic field.

They appear as dark spots on the sun's surface.

They tend to occur during active periods of the solar cycle.

They appear as bright spots on the sun's surface.

Answers

Answer:

They are caused by outward fluctuations of the sun's magnetic field.

They tend to occur during active periods of the solar cycle.

Explanation:

While sun spots will appear darker than the surrounding surface, flares will tend to appear brighter. CME's are associated with massive flares.

The two correct responses are as follows:

They are caused by outward fluctuations of the sun's magnetic field.They tend to occur during active periods of the solar cycle.

The following information should be considered:

At the time when sunspots should appear darker as compared to the surrounding surface, so flares should be appear brighter. CME's are along with massive flares.Due to this, the above answers are considered.

Learn more: brainly.com/question/16911495

the atmosphere of mercury and mars are very thin.what effects does the thin atmosphere on the temperature on the surface of this planet?

Answers

Answer:

The effects of the thin atmosphere are that the surface of the planet is going to be much hotter and not only that but also more radioactive than a planet with a thicker atmosphere. The thick atmosphere on other planets prevents a lot of radiation from going straight to the surface of the planet.

Explanation:

PLEASE HELP!!
What process is illustrated in the figure?

Answers

Answer: A

Explanation:

For question 51, do you use a=d/t

Answers

No. That won't help. It's not even true.

What is the earths layers?

Answers

Answer (from outermost to innermost): Crust, mantle, outer core, inner core.

12. If the 50kg rock fell from the 20m high cliff, then what would its velocity be just before it
hits the ground?

Answers

Answer:

The velocity is 2.5 before hitting the ground

Explanation:

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2021 edge

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