The right hand rule for the direction of propagation of the electromagnetic waves is to point the fingers of your right hand toward the e vector, curl your fingers towards the b vector, and the thumb will point the direction of propagation. Therefore, the option c is correct.
The right-hand rule is a rule used for understanding the direction of a magnetic field concerning the direction of electric current in a wire. The rule relates to the direction of the magnetic field produced by current-carrying wires. Also, it relates to the direction of the force exerted on a wire placed in a magnetic field. The right-hand rule for the direction of propagation of electromagnetic waves is as follows:Point the fingers of your right hand toward the E vector. Curl your fingers towards the B vector. The thumb will point the direction of propagation of the electromagnetic waves. It is used to understand the direction of the electric field and magnetic field concerning the direction of electromagnetic waves.The direction of propagation of an electromagnetic wave is the direction in which the wave travels. Electromagnetic waves have a transverse wave nature, meaning that the direction of their oscillations is perpendicular to the direction of propagation. The oscillations of the electromagnetic wave are given by the electric and magnetic fields, and their direction is perpendicular to the direction of the wave's propagation.Option C is correct.Learn more about electromagnetic waves: https://brainly.com/question/25847009
#SPJ11
You have a concave mirror. A candle is located 22 cm from the mirror. The image of the candle appears at a distance 7.0 cm from the mirror. What is the focal length of the mirror?
I will give you an example to know how to do it, watch and learn.
Question:
The image of a candle flame placed at a distance of 30 cm from a mirror is formed on a screen placed in front of mirror at a distance of 60 cm from its pole. What is the nature of the mirror. Find its focal length. If the height of flame is 2.4 cm , find the height of image.
Given :-
u = - 30 cm
v = 60 cm
h = 2.4 cm
Solution :-
Using mirror formula,
1/f = 1/v - 1/u
⇒ 1/f = 1/60 - (1/- 30)
⇒ 1/f = 1/60 + 1/30
⇒ 1/f = 3/60
⇒ 1/f = 1/20
⇒ f = 20 cm
Magnification, M = v/u = Height of image/height of object
⇒ v/u = 60/-30
⇒ v/u = h'/2.4
⇒ h' = - 60/30 × 2.4
⇒ h' = - 4.8 cm
Hence, The required height of the image is - 4.8 cm
The image formed by the mirror is inverted.
Now thats how you do it. get the idea?
Hope it helps :)
If you have a concave mirror. A candle is located 22 cm from the mirror. The image of the candle appears at a distance of 7.0 cm from the mirror. Then the focal length of the mirror is 5.31 cm.
To find the focal length of the concave mirror, we can use the mirror formula:
1/f = 1/u + 1/v
where:
f = focal length of the mirror
u = object distance (distance of the candle from the mirror)
v = image distance (distance of the candle's image from the mirror)
We are given that:
u = -22 cm (negative sign indicates that the object is in front of the mirror)
v = -7.0 cm (negative sign indicates that the image is formed behind the mirror)
Plugging in the values, we get:
1/f = 1/-22 + 1/-7.0
Simplifying, we get:
1/f = (-7.0 + (-22)) / (-22 × -7.0)
1/f = 29 / 154
f = 5.31 cm (rounded to two decimal places)
Therefore, the focal length of the concave mirror is 5.31 cm.
To learn about Snell's law click:
brainly.com/question/10112549
#SPJ2
1. Find FG between the earth and a football player 100 kg in mass. Fgrav =980 N
2. What is the radius of the moon when an astronaut of madd 70kg is having a gravitational force
117 N when standing in the surface of the moon
3. Determine the mass of Jupiter if a gravitational force on a scientist whose weight when in earth is 686 N, is Fgrav = 1823 N
Object X of mass m0 travels to the right with a velocity v0. Object Y of mass 2m0 moves to the left at 2v0, as shown in the figure. The objects collide and then stick together. What is the change in kinetic energy of the two-object system from immediately before the collision to immediately after the collision?
ATTACHMENT OF DIAGRAM BELOW. Ignore my calculations
The kinetic energy decreases by 3movo^2
Does the kinetic energy increase for an inelastic collision?In an inelastic collision, kinetic energy is not conserved. Some of the initial kinetic energy of the system is converted into other forms of energy, such as heat, sound, or deformation energy, and is not available to do work on the system.
In fact, the total kinetic energy of the system usually decreases in an inelastic collision. This is because the objects involved in the collision stick together or deform upon impact, resulting in a loss of kinetic energy. The amount of energy lost depends on the specific properties of the objects and the nature of the collision.
Learn more about kinetic energy:https://brainly.com/question/26472013
#SPJ1
2. A disc speeds up from rest at a constant rate of 2. 5 rad/s^2.
a. What is the final angular speed of the disc after 18 secs. ? (45 rad/s)
b. How many revolutions will the disc go through during this time period?
(64. 5 revs)
C. WHat is the linear speed of a point at the end of the disc after 18 secs. (The radius
of the disc is 50 cm. (22. 5 m/s)
I
a. The final angular speed of the disc after 18 seconds is 45 rad/s.
b. The disc goes through approximately 64.5 revolutions during this time period.
c. The linear speed of a point at the end of the disc after 18 seconds is 22.5 m/s.
a. The angular acceleration of the disc is constant at 2.5 [tex]rad/s^2[/tex].
Using the formula for angular velocity with constant angular acceleration, we have:
ωf = ωi + αt
Where:
ωi = initial angular velocity (0, since the disc starts from rest)
α = angular acceleration (2.5 [tex]rad/s^2[/tex])
t = time (18 s)
ωf = 0 + 2.5 × 18
ωf = 45 rad/s
Therefore, the final angular speed of the disc after 18 seconds is 45 rad/s.
b. To find the number of revolutions the disc goes through during this time period, we need to first find the total angle rotated by the disc. Using the formula for angular displacement with constant angular acceleration, we have:
θ = ωit + 1/2 α[tex]t^2[/tex]
Where:
ωi = initial angular velocity (0, since the disc starts from rest)
α = angular acceleration (2.5 [tex]rad/s^2[/tex])
t = time (18 s)
θ = 0 + 1/2 × 2.5 × [tex]18^2[/tex]
θ = 405 rad
One revolution is equal to 2π radians,
so the number of revolutions is given by:
N = θ / 2π
N = 405 / 2π
N ≈ 64.5 revolutions
Therefore, the disc goes through approximately 64.5 revolutions during this time period.
c. The linear speed of a point at the end of the disc is given by:
v = rω
Where:
r = radius of the disc (50 cm = 0.5 m)
ω = angular velocity (45 rad/s)
v = 0.5 × 45
v = 22.5 m/s
Therefore, the linear speed of a point at the end of the disc after 18 seconds is 22.5 m/s.
for such more question on angular speed
https://brainly.com/question/24158647
#SPJ4
A small squishy ball is thrown against the side of a large cube of concrete. While the objects are in contact with each other, which experiences the larger force?
the correct option is b. The large cube of concrete exerts a larger force on the small squishy ball.
It tends to be described as a connection that influences an article's movement on the off chance that there is no resistance. The straightforward meaning of force, then again, is the push or pull that any article gets. Force is a vector amount, consequently, it has a magnitude and a bearing.
Nonetheless, gravity is a force in a more broad sense since it represents the connection that happens when two masses are near each other. Gravitational effects are on a very basic level brought about by the extension of spacetime and the movement of things through the extended spacetime. The impact, by and by, is by all accounts the consequence of utilizing force.
to know more about force click here:
https://brainly.com/question/13191643
#SPJ4
the complete question is:
1) A small squishy ball is thrown against the side of a large cube of concrete. While the objects are in contact with each other, which experiences the larger force? a. The small squishy ball exerts a larger force on the large cube of concrete b. The large cube of concrete exerts a larger force on the small squishy ball C. Neither object exerts a force on the other while they are in contact. d. The small squishy ball and the large cube of concrete exert equal force on each other.
Work is done only when..... _ causes an object to _
Work is characterized as the resultant action when a force moves an object in the force's direction.
What does force mean in science?It is clear what the word "force" means. The terms "push" and "pull" are perfectly acceptable at this level to describe forces. An object does not have a force inside of it or within it. Another object applies a force to the first.
In what ways do forces differ?When two items come into contact with one another physically and interact, these kinds of forces are involved. Frictional, tensional, normal, air resistance, applied, and spring forces are examples of the several types of contact forces.
To know more about Force visit:
https://brainly.com/question/13191643
#SPJ9
a hoop with a moment of inertia of 0.1 kg m2 spins about a frictionless axle with an angular velocity of 5 rad/s. at what radius from the center of the hoop should a force of 2 n be applied for 3 seconds in order to accelerate the hoop to angular speed of 10 rad/s?
Tthe radius from the center of the hoop at which a force of 2 N should be applied for 3 seconds in order to accelerate the hoop to angular speed of 10 rad/s is 0.25 m.
Given data:
Initial angular velocity ω1 = 5 rad/s
Final angular velocity ω2 = 10 rad/s
Force applied F = 2 N
Time taken t = 3 seconds
Moment of inertia I = 0.1 kg m²
Formula used: τ = Iα Where,τ = torque
I = moment of inertiaα = angular acceleration
Let's calculate the torque required to change the angular speed: Initial torque τ1 = Iω1
Final torque τ2 = Iω2
Change in torque Δτ = τ2 - τ1 = I(ω2 - ω1)
We know that τ = F × r where,
F is the force applied
r is the distance from the center of mass where the force is applied
Let's calculate the distance r: Δτ = τ = F × rr = Δτ / F = I(ω2 - ω1) / F
Substitute the values, r = 0.1 × (10 - 5) / 2 = 0.25 m
Therefore, the radius from the center of the hoop at which a force of 2 N should be applied for 3 seconds in order to accelerate the hoop to angular speed of 10 rad/s is 0.25 m.
To know about angular speed, refer here:
https://brainly.com/question/28439806#
#SPJ11
A cup of hot chocolate with a temperature of 40°c is placed inside a
refrigater at 5°c .An identical cup of hot chocolate at 90°c is placed on a table in a
room at 25°c. A third identical cup of hot chocolate at 80°c is placed on an
outdoor table, where the surrounding air has a temperature at 0°c, for which
of the three cups has the most energy been transferred as heat when
equilibrium has been reached?
Al The first cup has the largest energy transfer
B/ The second cup has the largest energy transfer
c/ The third cup has the largest energy transfer
O The same amount of energy is transferred as heat for all three cups
Answer:
The answer is c
Explanation:
The third cup has the largest energy transfer
Suppose you are driving through a valley whose bottom has a circular shape. If your mass is M, what is the magnitude of the normal force Fn exerted on you by the car seat as you drive past the bottom of the hill A) Fn < Mg B) Fn = Mg C) Fn > Mg
The right response is (c) Fn > Mg
When you are driving through a circular valley, the direction of the net force acting on you is constantly changing. At the bottom of the valley, your velocity vector is horizontal and your acceleration vector is pointing upwards.
According to Newton's second law, F = ma, where F is the net force, m is your mass, and a is your acceleration. Therefore, the net force acting on you is greater than your weight (Mg) and is equal to the sum of the normal force and the force of gravity.
Thus, the correct answer is (c) Fn > Mg. The normal force is greater than your weight to provide the additional force required to maintain the circular motion.
To learn more about Newton's second law refer to:
brainly.com/question/13447525
#SPJ4
vegetables donot burn if we use oil while frying it why?
Explanation:
This is because the oil is an unsaturated fat (liquid at room temperature) and when heated to such high temperature becomes saturated.
A battery of EMF 1. 5V has terminal pd of 1. 25V when a resistor of 25 ohm is joined to it. Calculate the current flowing, internal resistance and terminal pd when resistance of 25 ohm is replaced by 10 ohm
Using Ohm's law, we can find the current flowing in the circuit: I = V / R where I is the current, V is the voltage, and R is the resistance.
When a resistor of 25 ohms is connected to the battery, the terminal pd is 1.25 V. This means that the voltage drop across the internal resistance of the battery is: 1.5 V - 1.25 V = 0.25 V. Using Ohm's law, we can find the internal resistance of the battery: 0.25 V / I = R_internal. Substituting the given values, we get: R_internal = 0.25 V / (1.5 V / 25 ohm) = 4.17 ohm. The current flowing in the circuit is: I = 1.25 V / 25 ohm = 0.05 A. When the resistance is replaced by 10 ohms, the current flowing in the circuit is: I = 1.5 V / 35 ohm = 0.043 A. Using the same approach as before, the terminal pd can be calculated as: 1.5 V - 0.043 A * (R_internal + 10 ohm) = V_terminal. Substituting the value of R_internal, we get: V_terminal = 1.5 V - 0.043 A * (4.17 ohm + 10 ohm) = 1.34 V. Therefore, when the resistance is replaced by 10 ohms, the current flowing in the circuit is 0.043 A, the internal resistance of the battery is 4.17 ohm, and the terminal pd is 1.34 V.
To learn more about Ohm's Law click the link below
brainly.com/question/1247379
#SPJ4
algol is a binary system consist of a 3.7 msun main-sequence star and a 0.8 msun subgiant (a sub giant is just a small red giant). why is this surprising? 1 the two stars in a binary system should both be at the same stage of their lives. 2 a star with a mass of 3.7 msun is too big to be a main-sequence star. 3. it doesn't make sense to find a subgiant in a binary star system. 4 in a binary system, the more massive star should be more evolved than its companion.
The correct answer is 4. In a binary system, the more massive star should be more evolved than its companion.
In the case of Algol, the 0.8 m sun subgiant is more evolved than the 3.7 m sun main-sequence star, which is surprising and not what we would expect based on our understanding of stellar evolution. This discrepancy is believed to be due to the fact that the two stars did not form together as a binary system, but rather the less massive star was captured by the more massive star after it had already evolved off the main sequence. The more massive star evolves more quickly and will reach later stages of evolution (such as a red giant phase) before the less massive star
Learn more about the star:
https://brainly.com/question/30287384
#SPJ11
Which of the following descriptions best describes all of the factors that need to be considered when determining an object’s terminal velocity?(1 point) Responses the object’s weight, length, and width the object’s weight, length, and width air density and the object’s drag coefficient air density and the object’s drag coefficient the object’s weight and area it presents, as well as air density the object’s weight and area it presents, as well as air density the object’s weight and area it presents
The object’s weight and area it presents, as well as air density.
The correct option is C.
What is velocity and example?Velocity may be defined as the rate that a thing travels in a certain direction. as the speed of a car driving north on a highway or the pace at which a rocket takes off. the proportion between the distance travelled in a simple machine by the point where the effort being applied to the distance moved in the same time by the place where the load is applied.
Who first defined velocity?Galileo Galilei, an Italian physicist, is recognized with being the initial person to calculate speed by dividing it by the distance travelled and the time required. Galileo defined speed as the amount of distance travelled in a given amount of time.
To know more about Velocity visit:
https://brainly.com/question/17127206
#SPJ1
The complete question is -
Which of the following descriptions best describes all of the factors that need to be considered when determining an object’s terminal velocity?
A) The object’s weight, length, and width
B) Air density and the object’s drag coefficient
C) The object’s weight and area it presents, as well as air density
D) The object’s weight, length, width, and area it presents, as well as air density and the object’s drag coefficient
a rock is thrown upward with a velocity of 11 meters per second from the top of a 44 meter high cliff, and it misses the cliff on the way back down. when will the rock be 10 meters from ground level? round your answer to two decimal places.
The rock will be 10 meters from the ground level after 2.63 seconds when the rock is thrown upward with velocity of 11m/s .
When the rock is thrown upward with a velocity of 11 m/s from the top of the 44 m high cliff, it will take approximately 4.00 seconds for the rock to reach the top of its trajectory and start heading back down.
The velocity of the rock on its way back down will be 11 m/s in the opposite direction. After 2.63 seconds, the rock will have travelled a distance of 10 m from the ground level.
#SPJ11
For more reference of velocity from ground https://brainly.com/question/27526920
During a tug of war game, both teams apply a force of 75 N. What is the net force?
The net force is 0 N. This is because the forces from each team are equal but opposite in direction, so the net force is the difference between the two forces, which is 0 N.
What is force ?Force is an interaction between two or more objects that results in a change in the motion of one or more of the objects. It is a vector quantity, meaning it has both magnitude and direction. Force can be divided into two categories: contact forces, which occur when two objects physically touch one another, and non-contact forces, which occur when objects interact without direct physical contact. Examples of contact forces include friction, tension, normal force, and air resistance. Examples of non-contact forces include gravitational force, electric force, and magnetic force.
To learn more about force
https://brainly.com/question/25239010
#SPJ9
Princess Leia once fell out of the spaceship. She came back with the Force. From the farthest spot (zero speed) back to the spaceship was 10 meters, and it took 5 second. She weighed 50 kg. Assume constant force during this trip. Find the force needed. (It is not much, but to get a force while floating in space is magic.)
The force needed to propel Princess Leia from a stationary position 10 meters back to the spaceship in 5 seconds would be 100 Newtons. This force can be determined by using the formula F = m x a, where m is the mass of the object and a is the acceleration.
The force required to propel Princess Leia from a stationary position 10 meters back to the spaceship in 5 seconds would be equal to the work done divided by the time taken, or 50 kg x 10 m/5 s = 100 Newtons. This is the force that is needed to move her 10 meters in 5 seconds, taking into account her 50 kg mass.
To explain this in a little more detail, the force required is determined by the formula F = ma, where F is force, m is mass and a is acceleration. Since the acceleration is constant in this scenario, the force applied is equal to the mass multiplied by the acceleration, or F = m x a. This means that to move the 50 kg mass of Princess Leia from zero speed to 10 meters in 5 seconds, a force of 100 Newtons is required.
To illustrate this with an example, if you were to pick up a 50 kg weight and move it 10 meters in 5 seconds, you would need to exert 100 Newtons of force. This is the same force required to move Princess Leia in the same way in space, taking into account her 50 kg mass.
Know more about force here:
https://brainly.com/question/13191643
#SPJ11
What would be the weight of a 60-kg astronaut on a newly discovered planet that is found to have density 2/3 ρᴇ and radius 2Rᴇ , where ρᴇ and Rᴇ are the density and radius of Earth, respectively?
A) 200N
B) 600N
C) 800N
D)1800N
The weight of the astronaut on the newly discovered planet is approximately 1800N, which is option D.
How is acceleration due to gravity calculated?The weight of an object is given by the formula W=mg, where g is the gravitational acceleration and m is the mass of the object. The gravitational acceleration on the surface of a planet can be calculated using the formula [tex]g = GM/R^2[/tex], where M is the mass of the planet, R is its radius, and G is the gravitational constant.
In this case, we are given that the planet has density 2/3 ρᴇ and radius 2Rᴇ. The mass of the planet can be calculated using the formula M = (4/3)π[tex]R^3[/tex]ρ, where ρ is the density of the planet. Substituting the given values, we get:
M = (4/3)π(2Rᴇ[tex])^3[/tex](2/3ρᴇ) = (32/27)πρᴇRᴇ[tex])^3[/tex]
The gravitational acceleration on the surface of the planet can be calculated as:
g = GM/R^2 = G[(32/27)πρᴇRᴇ^3]/(2Rᴇ[tex])^2[/tex] = (4/3)Gπρᴇ
The weight of the astronaut on the planet can be calculated as:
W = mg = 60[(4/3)Gπρᴇ] = (80/3)Gπρᴇ
Substituting the value of G and ρᴇ, we get:
W = (80/3)([tex]6.67 * 10^-^1^1[/tex])([tex]5.5 * 10^3[/tex])π ≈ 1818.9 N
To know more about acceleration visit:-
brainly.com/question/12550364
#SPJ1
Answer it quickly please
The coefficient of the kinetic friction of the sand paper would be = 0.5. That is option C.
How to calculate the coefficient of the kinetic friction of sand paper?To calculate the coefficient of the kinetic friction of the sand paper the slope of the sandpaper line is obtained. This is because slope of kinetic friction and normal force = coefficient of kinetic friction.
To calculate the slope = Y2 - Y1/ X2 - X1
Where Y2 = 3.3
Y 1 = 1.0
X2 = 6.9
X1 = 2
Slope = 3.3-1.0/6.9-2
= 2.3/4.9
= 0.5
Therefore the coefficient of the kinetic friction of the sand paper which is the slope of kinetic friction and normal force for the sandpaper line would be = 0.5.
Learn more about slope here:
https://brainly.com/question/29044610
#SPJ1
if a lot of material (from the accretion disk) makes it onto the white dwarf (before it can all fuse away), what will happen? a. the winds from the white dwarf will blow all the material off. b. the white dwarf will have enough mass to collapse. c. the white dwarf will turn into a red giant. d. the white dwarf will transfer the mass back to the companion star e. the material will sink to the core of the white dwarf and the star will return to the main sequence.
Option b is correct. If enough material from the accretion disk makes it onto the white dwarf then it will cause the white dwarf to collapse and produce a Type Ia supernova.
A white dwarf is a remnant of low or medium-mass stars that have stopped producing energy through nuclear fusion. White dwarfs are not planets; instead, they are the small cores of stars that have collapsed under the weight of their own gravity. They are the densest form of matter apart from black holes and neutron stars.
If a lot of material from the accretion disk makes it onto the white dwarf (before it can all fuse away), the material will accumulate on the surface of the white dwarf, increasing its mass.
The white dwarf will have a mass greater than the Chandrasekhar limit (1.4 solar masses). This can lead to a catastrophic event known as a Type Ia supernova, in which the white dwarf collapses and explodes. hence correct option is b.
Learn more about white dwarf:
https://brainly.com/question/846970
#SPJ11
A one-piece cylinder has a core section protruding from the larger drum and is free to rotate around its central axis. A rope wrapped around the drum of radius 1. 39 m exerts a force of 3. 34 N to the right on the cylinder. A rope wrapped around the core of radius 0. 48 m exerts a force of 8. 52 N downward on the cylinder. What is the magnitude of the net torque acting on the cylinder about the rotation axis? Answer in units of N ∗ m
The magnitude of the net torque acting on the cylinder about the rotation axis is 8.73 Nm.
τ1 = F1 * r1
where F1 is the force on the drum, and r1 is the radius of the drum. Substituting the given values:
τ1 = 3.34 N * 1.39 m = 4.64 Nm
The torque due to the force on the core is given by:
τ2 = F2 * r2
where F2 is the force on the core, and r2 is the radius of the core. Substituting the given values:
τ2 = 8.52 N * 0.48 m = 4.09 Nm
The net torque is the sum of the two torques:
τnet = τ1 + τ2
τnet = 4.64 Nm + 4.09 Nm = 8.73 Nm
Magnitude is a term used in physics to describe the size or amount of a physical quantity, such as length, mass, force, or energy. It is often represented by a numerical value and a unit of measurement. In physics, the magnitude of a vector is the length of the vector, and it is a scalar quantity. For example, the magnitude of the force acting on an object is the amount of force, irrespective of its direction.
Magnitude is also used to describe the intensity of phenomena such as earthquakes, sound waves, and light waves. The Richter scale, for example, is a measure of the magnitude of an earthquake, while the decibel scale is used to measure the magnitude of sound waves. In summary, magnitude is an important concept in physics that allows us to quantify the size or amount of physical quantities and phenomena.
To learn more about Magnitude visit here:
brainly.com/question/29766788
#SPJ4
how much work dose billy perform if he pushes the 800N stalled car a distence of 25m?
Answer:
20,000 J
Explanation:
Work = Force multiplied by Displacement
The work done on a object can only be calculated when the applied force is causing an object to move in the direction the force is being applied towards.
The given information:
Billy applies a form of 800N on a staller car and the total distance it was pushed was 25 meters.
To calculate the work done, substitute the given information into the formula for work.
Work = (800 N) × (25 m)
Work = 20,000 J
Note: Remember the SI unit for Work is Joules (J).
A car traveling at 28. 5 m/s E skids to a stop in 2. 58 s. Determine the skidding displacement of the car (assume uniform acceleration). 27
The car's displacement when sliding is 73.66 metres.
We can use the kinematic equation for displacement with constant acceleration to solve for the skidding displacement of the car:
d = vi * t + 0.5 * a * t^2
where d is the displacement, vi is the initial velocity, t is the time, and a is the acceleration.
First, we need to find the acceleration of the car. We can use the equation for average acceleration:
a = (vf - vi) / t
where vf is the final velocity (which is 0 since the car comes to a stop), vi is the initial velocity (28.5 m/s to the east), and t is the time (2.58 s).
a = (0 - 28.5 m/s) / 2.58 s
a = -11.05 m/s^2
The negative sign indicates that the acceleration is in the opposite direction to the initial velocity.
Now we can substitute the values into the first equation:
d = vi * t + 0.5 * a * t^2
d = (28.5 m/s) * (2.58 s) + 0.5 * (-11.05 m/s^2) * (2.58 s)^2
d = 73.66 m
Therefore, the skidding displacement of the car is 73.66 meters.
To learn more about displacement refer to:
brainly.com/question/13683145
#SPJ4
What is physical significance of dimension of physical quantity
The dimension of a physical quantity is the power to which the fundamental units must be raised to, to represent it. Mass, length, time, temperature, electric current, luminous intensity and amount of substance are the fundamental quantities
Temperature is a measure of the degree of hotness or coldness of an object or substance. It is a fundamental concept in physics, chemistry, and engineering and is one of the most commonly measured physical parameters in scientific and industrial applications. The temperature of an object or substance is related to the average kinetic energy of its particles. In other words, the faster the particles are moving, the higher the temperature.
Temperature is measured using a variety of devices, including thermometers, thermocouples, and pyrometers. The most common unit of temperature is the Celsius (°C) scale, which is based on the freezing and boiling points of water. Another commonly used scale is the Fahrenheit (°F) scale, which is used primarily in the United States.
To learn more about Temperature visit here:
brainly.com/question/11464844
#SPJ4
A 15-cm-long aluminum tank is filled with ethyl alcohol. A high-frequency ultrasound wave travels horizontally through one wall of the tank and then through the alcohol. There are 275 times more cycles of the wave in the alcohol than in the aluminum wall. How thick is the wall of the tank?
The aluminium wall measures about 0.273 centimetres in thickness.
Let's assume that the frequency of the ultrasound wave is denoted by f and the thickness of the aluminum wall is denoted by x. We know that the speed of the ultrasound wave in aluminum is greater than that in ethyl alcohol. Since the wavelength of the wave is constant, we can use the formula:
f1 x1 = f2 x2,
where f1 and f2 are the frequencies of the ultrasound wave in aluminum and ethyl alcohol, respectively, and x2 is the thickness of the alcohol.
We are given that the ratio of the number of cycles in the alcohol to that in the aluminum wall is 275. Therefore:
f2 = 275 f1.
We also know that the speed of the ultrasound wave in aluminum is approximately 5 times that in ethyl alcohol. Therefore:
x1 = 5 x2.
Substituting these values into the equation gives:
275 f1 x2 = f1 (5 x2),
which simplifies to:
x2 = (1/55) x1.
Finally, we substitute the length of the aluminum tank (15 cm) for x1 to get:
x2 = (15 cm) / 55 = 0.273 cm.
Therefore, the thickness of the aluminum wall is approximately 0.273 cm.
To learn more about wavelength refer to:
brainly.com/question/13533093
#SPJ4
1. The speed of a bobsled is increasing because it has an acceleration of 2. 4 m/3. At a given instant in time, the forces resisting the motion, including kinetic friction and air resistance, total 450 N. The combined mass of the bobsled and its riders is 270 kg. (a) What is the magnitude of the force propelling the bobsled forward? (b) What is the magnitude of the net force that acts on the bobsled?
(a) The magnitude of the force propelling the bobsled forward is 648 N. (b) The magnitude of the net force acting on the bobsled is 198 N.
Use Newton's second law of motion, which states that force equals mass times acceleration (F = ma). Rearranging the formula, we get F = ma, where F is the force, m is the mass, and a is the acceleration.
So, the force propelling the bobsled forward is,
F = ma = (270 kg)(2.4 m/s^2) = 648 N
The net force acting on the bobsled can be calculated by subtracting the forces resisting the motion from the force propelling the bobsled forward. So, the net force acting is,
Net force = Force propelling forward - Forces resisting motion
Net force = 648 N - 450 N
Net force = 198 N
To know more about force, here
brainly.com/question/13570504
#SPJ4
a water skier is pulled behied a boat by a rope the rope has a tension of 650 N and is at an angle of 27. what is the y compoent of the tension
A 46.4 kg wolf is running at 12.2 m/s what is the wolfs kinetic energy
The 46.4 kg wolf moving at a speed of 12.2 m/s has a kinetic energy of 3,456.98 J.
What establishes an object's entire amount of kinetic energy?The amount of work done on an item and its acceleration following a moment of inertia caused by external forces are two aspects that affect the overall kinetic energy of an object.
The formula: gives the kinetic energy (KE) of an item.
KE = (1/2) × mass × velocity²
where velocity is measured in meters per second (m/s) and mass is measured in kilograms (kg).
Plugging in the following numbers will allow us to determine the wolf's kinetic energy:
KE = (1/2) × 46.4 kg × (12.2 m/s)²
= (1/2) × 46.4 kg × 148.84 m²/s²
= 3,456.98 joules (J)
To know more about kinetic energy visit:-
https://brainly.com/question/26472013
#SPJ1
A spacecraft is orbiting a planet at a distance of 10,000 km from the planet's center. The spacecraft's speed is constant at 20,000 km/hr. Suddenly, the spacecraft's engines fail and it begins to free fall towards the planet's surface. Assuming that the planet has a uniform density and a radius of 5,000 km:
1. What is the gravitational acceleration experienced by the spacecraft as it falls towards the planet's surface?
2. What is the maximum velocity that the spacecraft can reach just before impacting the planet's surface?
3. What is the kinetic energy of the spacecraft just before impacting the planet's surface?
The gravitational acceleration experienced by the spacecraft would be 13.33 m/s^2.
The maximum velocity the spacecraft can reach would be 1633.5 m/s.
The kinetic energy of the spacecraft would be KE = 1/2mv^2
Gravitational acceleration problemThe gravitational acceleration experienced by the spacecraft as it falls toward the planet's surface can be calculated using the formula
g = G*M/r^2Thus:
g = (6.67 x 10^-11 N m^2/kg^2) * (4/3 * pi * (5000 km)^3 * 5500 kg/m^3) / (10000 km)^2 = 13.33 m/s^2.
The maximum velocity that the spacecraft can reach just before impacting the planet's surface can be calculated using the formula
v = sqrt(2gh)The height from which the spacecraft falls is equal to the distance from the planet's surface to the spacecraft's initial position, which is 10,000 km - 5000 km = 5000 km.
Thus, v = sqrt(2 * 13.33 m/s^2 * 5,000,000 m) = 1633.5 m/s.
The kinetic energy of the spacecraft just before impacting the planet's surface can be calculated using the formula
KE = 1/2mv^2More on gravitational acceleration can be found here: https://brainly.com/question/30429868
#SPJ1
Determine the total resistance for the current
The total flow of electricity from the source is equivalent to the sum of the currents through each path. To calculate the total impedance in a parallel circuit, use the method below : 1/Rt Equals 1/R1 + 1/R2 + 1/R3 +...
How do you find total resistance of a current?IT = VT/RT or I total = V total / R total or the total current = the total voltage / the total resistance.
Current still flows along the other routes even if one of the parallel ones is blocked.
R_total = R1 + R2 +... + Rn The sum of all individual resistances makes up the system's overall resistance. Take the example issue below as an
example. A resistor with a 100 ohm electrical resistance value is linked to a resistor with a 200 ohm electrical resistance value.
To learn more about resistance, visit -
https://brainly.com/question/28135236
#SPJ1
halfway through her swing, when the golf club is parallel to the ground, does the acceleration vector of the club head point (a) straight down, (b) parallel to the ground, approximately toward the golfer's shoulders, (c) approximately toward the golfer's feet, or (d) toward a point above the golfer's head? explain.
The acceleration vector of the club head point straight down(a)
Acceleration is a vector, and it may have a direction other than the acceleration of gravity.
The club head accelerates due to the forces exerted by the golfer, which include a torque applied by the golfer's hands, which generates angular acceleration that causes the club to rotate.
The acceleration vector points down because the club head is still at the beginning of the downswing.
As the club head approaches the ball, it begins to move away from its initial position and pick up velocity, resulting in a more complicated acceleration profile.
To summarise, during the downswing, halfway through the swing, the acceleration vector of the golf club head points straight down.
To know more about Acceleration:https://brainly.com/question/460763
#SPJ11