The length of a cell phone is
1.4
1.4 inches and the width is
4.4
4.4 inches. The company making the cell phone wants to make a new version whose length will be
1.96
1.96 inches. Assuming the side lengths in the new phone are proportional to the old phone, what will be the width of the new phone?

B) Note that in the prompt above, you can use translation to map the line y= 2x -4 onto the line y = 2x + 4.

While you can use axial symmetry in the y -  axis to map the line  y = x onto the line y = -x.

Axial symmetry is symmetry around an axis; an item is axially symmetric if it retains its appearance when rotated around an axis.

A baseball bat with no brand or other design, or a plain white tea saucer, for example, looks the same when rotated by any angle around the line traveling longitudinally through its center, indicating that it is axially symmetric.

A transformation in which the coordinate system's origin is shifted but the orientation of each axis remains constant

So for B) you can use a translation to map the line y = 2x -4 onto the line y = 2x + 4 by shifting the first line 4 units upwards along the y - axis....

mathematically, that would be:

y = 2x - 4 + 4

y = 2x


For C) you can use axial symmetry on the y -  axis to achhieve the mapping of y = x onto y = -x by reflection.

The polar opoppsite of y = x  is y = -x.

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The present age of the Father is 35 and the age of the Son is 15 years after solving the given problem.

By examining the given problem we can solve it in the following way:

Present age:

Let x = Son's present age

x + 20 = Father's present age

5 years ago:

x - 5 = Son's age 5 years ago

x + 20 -5 = father's age 5 years ago

Father's age 5 years ago = 3( Son's age 5 years ago )

x + 20 - 5 = 3 (x - 5)

x + 15 = 3x - 15

2x = 30

x = 15

x = 15, Son's present age

x + 20 = 35 = father's present age.

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No, 4xy³ and -5x³y are not like terms because they cannot be added or subtracted

Algebraic expressions are defined as expressions that are composed of terms, their coefficients, their variables, constants and factors.

These algebraic expressions are also identified with the presence of arithmetic operations, such as;

It is important to note that like terms are terms an algebraic expression have like variables but not always coefficients. These terms also can be added or subtracted.

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Answer:

-15 and -2

Step-by-step explanation:

Two negatives multiply to be a positive. We know -15 • -2 = +30

Combine (add) them and you get -17.

The left side of Green's theorem for this vector field and rectangular path is 32.28 ay.

To evaluate the left side of Green's theorem, we need to compute the line integral of the vector field F along the boundary of the region enclosed by the rectangular path C.

First, let's parameterize the rectangular path C as follows:

r(t) = (x(t), y(t)), where 2.8 ≤ x ≤ 8 and 2.1 ≤ y ≤ 7.5.

The boundary of the rectangular path C is composed of four line segments:

From (2.8, 2.1) to (8, 2.1): r(t) = (t, 2.1), where 2.8 ≤ t ≤ 8.

From (8, 2.1) to (8, 7.5): r(t) = (8, t), where 2.1 ≤ t ≤ 7.5.

From (8, 7.5) to (2.8, 7.5): r(t) = (t, 7.5), where 8 ≤ t ≤ 2.8 (note the reverse order).

From (2.8, 7.5) to (2.8, 2.1): r(t) = (2.8, t), where 7.5 ≥ t ≥ 2.1 (note the reverse order).

We can now evaluate the line integral of F along each of these line segments using the parameterization r(t) and the definition of the line integral:

∫_C F · dr = ∫_(C1) F · dr + ∫_(C2) F · dr + ∫_(C3) F · dr + ∫_(C4) F · dr,

where the dot product F · dr is given by:

F · dr = (x dx + y dy) · (dx ax + dy ay) = x dx^2 + y dy^2.

Let's evaluate each of the line integrals separately:

∫_(C1) F · dr = ∫_(2.8)^8 (t ax + 2.1 ay) · dt = (8 - 2.8) ax + 2.1 (0) ay = 5.2 ax

∫_(C2) F · dr = ∫_(2.1)^7.5 (8 ax + t ay) · dt = 8 (7.5 - 2.1) ay + 8 (0) ax = 46 ay

∫_(C3) F · dr = ∫_(8)^2.8 (t ax + 7.5 ay) · (-dt) = (8 - 2.8) ax + 7.5 (0) ay = -5.2 ax

∫_(C4) F · dr = ∫_(7.5)^2.1 (2.8 ax + t ay) · (-dt) = 2.8 (2.1 - 7.5) ay + 2.8 (0) ax = -13.72 ay

Therefore, the line integral of F along the boundary of the rectangular path C is:

∫_C F · dr = ∫_(C1) F · dr + ∫_(C2) F · dr + ∫_(C3) F · dr + ∫_(C4) F · dr = 5.2 ax + 46 ay - 5.2 ax - 13.72 ay = 32.28 ay.

So the left side of Green's theorem for this vector field and rectangular path is 32.28 ay.

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If A and B are mutually exclusive, then the correct answer is c. P(A ∩ B) = 0. This is because mutually exclusive events cannot occur at the same time, meaning the intersection of the events is empty. Therefore, the probability of A and B occurring together is zero.

To explain further, if A represents the event of flipping heads on a coin and B represents the event of flipping tails on the same coin, then these events are mutually exclusive because both cannot occur at the same time. The probability of flipping heads or tails on a coin is 1, but the probability of flipping heads and tails simultaneously is 0. Therefore, P(A ∩ B) = 0.

It is important to note that if A and B are mutually exclusive, then P(A) + P(B) = 1, which is answer choice d. This is because one of the events must occur, but not both. Therefore, the total probability of either A or B occurring is 1. However, this does not directly answer the question about the probability of the intersection of A and B.

Overall, when working with mutually exclusive events, it is important to recognize that they cannot occur at the same time and therefore have no intersection, which makes the probability of A and B occurring together equal to 0.

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If A and B are mutually exclusive events, this signifies that they cannot both happen simultaneously. Therefore, the probability of both events occurring, expressed as P(A ∩ B), is equal to 0.

If A and B are mutually exclusive, it means that events A and B cannot occur at the same time. In terms of probability, we express this statement as: the probability that both A and B occur, denoted by P(A ∩ B), is equal to 0. Hence the correct answer is: c. P(A ∩ B) = 0.

This is fundamental in the study of probability and is crucial for understanding more complex concepts such as conditional probability and independence of events.

It's important to note that answers a, b and d are incorrect. Answer a, P(A) + P(B) = 0, implies that neither event can happen which contradicts the definition of mutually exclusive events. Answer b, P(A ∩ B) = 1, implies that A and B must always occur together, which is the exact opposite of what mutual exclusivity means. Answer d, P(A) + P(B) = 1, would be correct if A and B were exhaustive events, which means that either event A or event B is certain to occur.

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The probability of rolling a single six-sided die and getting a 2, 3, 4, or 5 is:
4/6 or 2/3

To determine the probability of the given outcome or event using the theoretical method, follow these steps:

1. Identify the total number of possible outcomes when rolling a single six-sided die. In this case, there are 6 possible outcomes (1, 2, 3, 4, 5, or 6).

2. Identify the number of successful outcomes, which are the outcomes that meet the criteria of the event. In this case, the successful outcomes are rolling a 2, 3, 4, or 5. There are 4 successful outcomes.

3. Calculate the probability by dividing the number of successful outcomes by the total number of possible outcomes. In this case, the probability is:

Probability = (Number of successful outcomes) / (Total number of possible outcomes)
Probability = 4/6

4. Simplify the fraction if possible. In this case, you can simplify 4/6 to 2/3.

The probability of rolling a single six-sided die and getting a 2, 3, 4, or 5 is 2/3.

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If the approximate areas of Colorado and Hawaii are listed as Colorado: 2.7 x 105 square kilometers. The amount  larger is Colorado is: 2.417 x 10^5.

The first step is to divide the area of Hawaii by the area of Colorado and before we do that we must ensure that both of these figures have the same exponent.

So,

2.7 x 10^5 square km - 2.83 x 10^4 square km

2.83 x 10^4 = 0.283 x 10^5

Hence,

2.7 x 10^5 - 0.283 x 10^5

= 2.417 x 10^5

Therefore  Colorado is 2.417 x 10^5 square kilometers larger than Hawaii.

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The volume of the solid enclosed by the paraboloid z = x² + y² and the plane z = 9 is V = 36π[tex]V = 36π[/tex] cubic units.

The solid is enclosed by the paraboloid z = x² + y² and the plane z = 9 is a region in 3D space that has a finite volume. To find the volume of this solid, we can use a method called triple integration.

We need to determine the limits of integration for each variable. Since the paraboloid is symmetric about the z-axis, we can integrate over one quadrant and multiply by four to get the total volume. In this case, we can integrate from 0 to 3 for both x and y, and from x² + y² to 9 for z.

The triple integral for the volume is then: [tex]V = 4 * ∫∫∫ z dz dy dx[/tex] Limits: 0 to 3 for x 0 to 3 for y x² + y² to 9 for z. Solving this integral gives us:[tex]V = 36π[/tex]

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The values of x and y are given as follows:

x = y = 5.

The Pythagorean Theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the lengths of the other two sides.

The theorem is expressed as follows:

c² = a² + b².

In which:

The diagonal length of the rectangle is the hypotenuse of a right triangle of sides 6 and 8, hence:

d² = 6² + 8²

d² = 100

d = 10.

The segments x and y are each half the length of the diagonal, and the two diagonals have the same length for a rectangle, hence:

x = y = 5.

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Answer:

The answer is D.2

Step-by-step explanation:

Can Ihave brainliest bc you said it was worth 13 but it's worth 7 :l

This means that there are 3 students who scored within that range. Therefore, the correct answer is C. 3.

The histogram displays the test scores for the 19 students in the geometry class. To determine how many students scored from 110 to 119 points, we need to look at the height of the bars in that range.

A histogram is a graphical representation of data that displays the frequency or distribution of a set of continuous or discrete variables. It consists of a series of bars, where each bar represents a specific category or range of values, and the height of the bar corresponds to the frequency or count of observations falling within that category or range.

Based on the histogram, we can see that the bar representing the range from 110 to 119 points has a height of 3. This means that there are 3 students who scored within that range. Therefore, the correct answer is C. 3.

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The slope of the graph is 50, and it represents the rate of change of the total cost of the gym membership per month.

To write an equation for C, the total cost of the gym membership, we can use the slope-intercept form of a linear equation, which is y = mx + b. In this case, y represents the total cost, m represents the slope, x represents the number of months, and b represents the y-intercept (the initial cost of joining the gym).

From the graph, we can see that the initial cost of joining the gym is $700 (the y-intercept), and the monthly fee is $50 (the slope of the line connecting the dots). So, the equation for C is:

C = 50t + 700

where t is the number of months.

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Answer:

(3,1)

Step-by-step explanation:

The measure of the missing angle which is named ∠PQR = 84°

The first step to solving the problem is to identify the nature of the triangle.

Note that the information states that:

Side PQ and QR are equal,
This means that it is an isosceles triangle because only isosceles triangles have two equal sides.

Another property of isosceles triangles that will help determine the m∠PQR is that the angles at the base of those equal sides are always equal.

Since that is true, then,

∠PQR = 180 - (QPR x 2 )

We know ∠QPR is 48°, so


∠PQR = 180 - (48x 2 )

∠PQR = 180 - 96

Thus,

∠PQR = 84°

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Full Question:

Although part of your question is missing, you might be referring to this full question:

See attached image.

The correct expansion of (3x – 2)(2[tex]x^2[/tex]  + 5) is 3x *  2[tex]x^2[/tex] + 3x * 5 + (–2) * 2[tex]x^2[/tex]  + (–2) * 5. Thus option A is the most appropriate option as the answer the above question

The expansion of the given algebraic expression follows the distributive rule of multiplication that is (a + b)(c + d) = ac + ad + bc + bd.

Thus the first term of the first expression which is 3x is multiplied by the the second expression and we get 3x • 2[tex]x^2[/tex] + 3x • 5 + (–2)

Then the second term that is -2 is multiplied by the second expression and we get 5 + (–2) • 2[tex]x^2[/tex]  + (–2) • 5

Then we add both expressions and get the answer 3x * 2[tex]x^2[/tex] + 3x * 5 –2 * 2[tex]x^2[/tex]  –2 * 5.

After further simplification of the above expression we get, 6[tex]x^3[/tex] + 15x - [tex]4x^2[/tex] - 10.

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Since f(-1) is positive and f(5) is negative, by the IVT, there must exist at least one value c in the interval [-1, 5] where f(c) = 0. This means that the function f(x) = x² - 4x has a zero on the interval [-1, 5].

Yes, we can use the Intermediate Value Theorem (IVT) to say that there is a zero of the function f(x) = x² - 4x on the interval [-1, 5].

The IVT states that if f(x) is a continuous function on the closed interval [a, b] and if k is any number between f(a) and f(b), then there exists at least one value c in the interval [a, b] such that f(c) = k.

In this case, we can evaluate f(-1) and f(5) to determine the sign of f(x) at the endpoints of the interval:

f(-1) = (-1)² - 4(-1) = 5

f(5) = 5² - 4(5) = -5

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Answer:

x+15 dollars

Step-by-step explanation:

x could be any number, but if you add 15 to x, it would be x+15. Since you don't know what x is, you can't do anything else.

We have shown that if b = 0(mod a) and c = 0(mod b), then c = 0(mod a).

The statement "If b = 0(mod a) and c = 0(mod b), then c = 0(mod a)" is true.

To prove this, we need to show that if b is a multiple of a and c is a multiple of b, then c is a multiple of a.

Suppose that b = ak and c = bk' for some integers k and k'. Then, we have:

c = bk' = (ak)k' = a(kk')

Since k and k' are both integers, their product kk' is also an integer. Therefore, we can write c = a(kk'), which shows that c is a multiple of a.

Hence, we have shown that if b = 0(mod a) and c = 0(mod b), then c = 0(mod a).

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To prove that the product of two odd integers is odd, we can follow these steps and justifications:

1. Let x and y be two odd integers.
(We start by assuming x and y are odd integers.)

2. x = 2a + 1 and y = 2b + 1, where a and b are integers.
(Since x and y are odd, they can be expressed in this form, as the sum of an even integer (2a or 2b) and 1.)

3. Find the product of x and y: xy = (2a + 1)(2b + 1).
(To show that their product is odd, we multiply x and y.)

4. Expand the product: xy = 4ab + 2a + 2b + 1.
(Using the distributive property to multiply and simplify.)

5. Factor out a 2: xy = 2(2ab + a + b) + 1.
(We factor out a 2 from the even terms to emphasize the structure of the expression.)

6. Let c = 2ab + a + b, where c is an integer.
(We introduce a new variable, c, to represent the sum of the even terms.)

7. Therefore, xy = 2c + 1, where c is an integer.
(Substituting c back into the expression for xy.)

8. The product xy is an odd integer.
(Since xy is in the form of an even integer (2c) plus 1, it is an odd integer.)

In conclusion, the product of two odd integers (x and y) is also an odd integer, as we have proven through these steps and justifications.

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The increasing functions in this problem are given as follows:

B and D.

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The function that has the greatest x-intercept is the function h(x)

The x-intercept of a function is the x-value of the function when the y-value is 0, which is the set of points at which the graph of the function intersects the x-axis.

The x-intercept of each function are found as follows;

f(x) = 3·x - 9 = 0

x = 9/3 = 3

g(x) = |x + 3| = 0

(x + 3) > 0 and |x + 3| = x + 3 = 0

x = 0 - 3 = -3

|x + 3| < 0 and |x + 3| = -(x + 3) = 0

x = -3

h(x) = 2·x - 16 = 0

x = 16/2 = 8

x = 8

j(x) = -5·(x - 2)² = 0

The x-intercept is x = 2

The function that has the greatest x-intercept is therefore the function h(x) = 2·x - 16

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The dimensions of the box that minimize the amount of material used are a base side length of 25 cm and a height of 25 cm.

Let x be the side length of the square base and h be the height of the box. Since the box has a square base, the volume of the box is V = x²h. We want to minimize the amount of material used, which is given by the surface area of the box, A = x² + 4xh.

Using the volume constraint, we can solve for h in terms of x: h = V / x² = 62,500 / x². Substituting this into the expression for A, we get A = x² + 4x(62,500 / x²) = x² + 250,000 / x.

To minimize A, we take its derivative with respect to x and set it equal to zero: dA/dx = 2x - 250,000 / x² = 0. Solving for x, we get x = 25 cm. Substituting this back into the expression for h, we get h = 25 cm.

Therefore, base side length is 25 cm and height is 25 cm.

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Answer: 5y^2 +3y+12

Step-by-step explanation:

6y^2+3y+1

y^2-11

equals

5y^2+3y+12

The length of the remaining piece of wooden beam after the cut out in terms of polynomial y is 5y² + 3y + 12

Length of the wooden beam = 6y² + 3y + 1

Length cut out from the wooden beam= y² - 11

Length of the remaining piece of beam = Length of the wooden beam - Length cut out from the wooden beam

= (6y² + 3y + 1) - (y² - 11)

= 6y² + 3y + 1 - y² + 11

= 5y² + 3y + 12

Hence, 5y² + 3y + 12 is the remaining length of the wooden beam.

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The value of x in the right triangle with acute angles 8x and 4x + 6 is 7

From the question, we have the following parameters that can be used in our computation:

The right triangle with acute angles 8x and 4x + 6

The sum of acute angles in a right triangle is 90

Using the above as a guide, we have the following:

8x + 4x + 6 = 90

So, we have

12x = 84

Divide by 12

x = 7

Hence, the value of x is 7

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It will take God approximately 32 days to use up all the gas in his tanker and need a refill.

If God filled his gas tanker with 19/5/9 tank of gas and uses 1 5/6 gallons of gas each day, we can calculate how many days it will take for him to need a refill.

First, we need to convert the mixed number 19/5/9 to an improper fraction:

19/5/9 = (19 * 9 + 5) / 9 = 176/9

So God has 176/9 tanks of gas in his tanker.

Next, we can calculate how much gas God uses each day:

1 5/6 = (6 * 1 + 5) / 6 = 11/6

So God uses 11/6 gallons of gas each day.

To find out how many days it will take for God to need a refill, we can divide the amount of gas in his tanker by the amount of gas he uses each day:

(176/9) / (11/6) = (176/9) * (6/11) = 32

Therefore, it will take God approximately 32 days to use up all the gas in his tanker and need a refill.

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Answer:

Sure, I can help you with that. Here are the steps on how to solve the problem:

1. Let x be the height of the balloon on the left and y be the height of the balloon on the right.

2. Using the tangent function, we can write the following equations:

```

tan(38) = x/700

tan(26) = y/1050

```

3. Solve the first equation for x:

```

x = 700tan(38)

```

4. Substitute this value of x into the second equation:

```

y/1050 = tan(26)

y = 1050tan(26)

```

5. Subtract the two equations to find the difference between the heights of the two balloons:

```

y - x = 1050tan(26) - 700tan(38)

```

6. Evaluate this expression using a calculator and round your answer to the nearest tenth:

```

y - x = 266.51 meters

```

Therefore, the balloon on the right is 266.51 meters higher than the balloon on the left.

Step-by-step explanation:

The value of E(Z)=[tex]=e^{\frac{2}{3} }[/tex]

To find the pdf of Z, we need to use the transformation formula for pdfs:

[tex]f_Z(z) = f_X((g)^{(-1)}z ) * |(\frac{d}{dz}) (g)^{-1} (z)|,[/tex]

where [tex]g(x) = e^x[/tex] and [tex](g)^{-1} (z) = ln(z)[/tex] since [tex](e)^{(ln(z)} = z[/tex].

So, we have:

[tex]f_Z(z) = f_X(ln(z)) * |\frac{d}{dz} ln(z)|[/tex]

[tex]=\frac{1}{3z} (for 0 < z < e^2)[/tex]

To find E[Z], we can use the definition of expected value:

[tex]E(Z) = \int\limits {0^{e^{2} } } z f_Z(z) dz \,[/tex]

[tex]E(Z) = \int\limits {0^{e^{2} } } z (\frac{1}{3z} ) dz \,[/tex]

[tex]= (\frac{1}{3} ) \int\limits {0^{e^{2} } } dz \,[/tex]

[tex]= (\frac{1}{3} ) {e^{2} -0 }[/tex]

[tex]=e^{\frac{2}{3} }[/tex]

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The probability that a fruit picked at random weighs between 443 grams and 492 grams is approximately 0.3695 or 36.95%.

To find the probability that a fruit picked at random weighs between 443 grams and 492 grams, we need to standardize these values using the formula:

z = (x - μ) / σ

where x is the weight of the fruit, μ is the mean weight (438 grams), σ is the standard deviation (17 grams), and z is the standardized score.

For the lower end of the range (443 grams), we have:

z = [tex]\frac{(443 - 438)}{17} = 0.29[/tex]

For the upper end of the range (492 grams), we have:

z = [tex]\frac{(492 - 438)}{17} = 3.18[/tex]

Using a standard normal distribution table or calculator, we can find the probability that a standardized score falls between these values.

The probability of a z-score between 0.29 and 3.18 is approximately 0.3695.

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To determine the partial fraction expansion for a rational function, we need to express it as a sum of simpler fractions. However, the general process for finding the partial fraction expansion of a rational function is as follows:

1. Factor the denominator of the rational function into linear and/or quadratic factors.
2. Write the rational function as a sum of fractions, one for each factor of the denominator. For each linear factor, use a constant numerator. For each quadratic factor, use a linear numerator.
3. Solve for the constants using algebraic manipulation and equating the numerators of the partial fractions with the original numerator of the rational function.
4. Write the partial fraction expansion as the sum of the fractions found in step 2 with the constants found in step 3.

For example, if the rational function is (3x^2 + 5x + 2)/(x^2 + 4x + 3), we would first factor the denominator as (x + 3)(x + 1). Then we would write the partial fraction expansion as:

(3x^2 + 5x + 2)/(x^2 + 4x + 3) = A/(x + 3) + B/(x + 1)

To solve for A and B, we would equate the numerators:

3x^2 + 5x + 2 = A(x + 1) + B(x + 3)

Expanding and equating coefficients, we get:

3 = B + A
5 = 3B + A

Solving for A and B, we get:

A = 1
B = 2

Therefore, the partial fraction expansion of (3x^2 + 5x + 2)/(x^2 + 4x + 3) is:

(3x^2 + 5x + 2)/(x^2 + 4x + 3) = 1/(x + 3) + 2/(x + 1)

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(a) 248 to decimal
Since it's already in decimal form, there's no need for conversion.
Answer: 248

(b) 2416 to decimal (assuming it's a hexadecimal number)
Step 1: Identify the place values of the hexadecimal number (from right to left): 1, 16, 256
Step 2: Multiply the digits by their place values and sum them up: (2 * 256) + (4 * 16) + (1 * 1) = 512 + 64 + 1 = 577
Answer: 577

(c) 2c16 to decimal (assuming it's a hexadecimal number)
Step 1: Identify the place values of the hexadecimal number (from right to left): 1, 16, 256
Step 2: Convert the letter "c" to its decimal equivalent: C = 12
Step 3: Multiply the digits by their place values and sum them up: (2 * 256) + (12 * 16) + (1 * 1) = 512 + 192 + 1 = 705
Answer: 705

(d) 00110011101000112 to hexadecimal
Step 1: Group the binary digits into sets of four from right to left: 0011 0011 1010 0011
Step 2: Convert each group of four binary digits into their corresponding hexadecimal values:
      0011 = 3
      0011 = 3
      1010 = A
      0011 = 3
Step 3: Combine the hexadecimal values: 33A3
Answer: 33A3

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