supppose object a has double the specific heat and triple the mass of object b. if the same amount of heat is applied to both objects, how will the temperature changes of a be related to the temperature change of b?

a) t = 4.08 s

b) Response = 20.39m

c) t = 0.991 and 3.087 seconds.

Initially, the vertical speed was 20 m/s.

(a) how long is the ball in the air?

The ball is tossed upward, rises to its highest point, and then hits the ground again.

Consequently, the end height will be equal to the starting height.

h = h o = Om

Use the equation s= ut + -at.

2764 – An = 14

Put a negative sign for g because the ball is being thrown upwards and g is acting downwards.

Om = t - 0.5 * 9.81 m/s * 20 m/s

0 = 20 *t - 0.5 * 9.81 *t

20 *t=0.5*9.81 *t

20 = 0.5 * 9.81 *t

20 0.5*9.81

Answer (a): t = 4.08 s

(b) what is the greatest height reached by the ball?

Vertical velocity for the ball decreases to zero when it reaches its highest point.

Use the equation 2-u=295

-2ghmas for - u

(20m/s - (Om/s)2) = -2 * 9.81 m/s2 *

02 – 20= -2*9.81 *

-20% = -2 *9.81 *

202 = 2 * 9.81 *  

b) RESPONSE: H = 20.39m

(c) when is the ball 15 m above the ground?

The ball will be 15 meters above the earth on two separate occasions.

1. When climbing

2. When descending

Use the equation s= ut + -at.

2,264 – fn = 4

0.5 * 9.81 m/s * 15m = 20 m/s*t

15 = 20 *t - 0.5 * 9.81 *t

15 = 20t – 4.9057

4.905 – 20t + 15 = 0

Calculator-based quadratic equation solution

(c) t = 0.991 and 3.087 seconds.

Hence the answers are,

a) t = 4.08 s

b) RESPONSE: Hmar = 20.39m

c) t = 0.991 and 3.087 seconds.

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The distance travelled by Arthur is 7 km and his displacement is 5 km.

The distance travelled by Arthur during the entire motion is determined by summing the entire path covered during the motion.

Distance = 3 km + 4 km

Distance = 7 km

The displacement of Arthur during the entire motion is obtained by calculating the length of the shortest path between the initial and final position.

d = √(a² + b)

where;

d = √(3² + 4²)

d = 5 km

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The current drawn by the electric frying pan is 27.295 A.

Power of toaster, P1 = 1800 W

Power of electric frying pan, P2 = 1400 W

Power of lamp, P3 = 75 W

Three devices are in parallel combination. So their Voltage difference is the same.

∆V = 120 Volt

Current is drawn by frying pan, I1 = P1/∆V = 1800/120 = 15 A

Current drawn by an electric frying pan, I2= 1400/120 = 11.67 A

Current drawn by frying pan, I3 = P3/120 = 75/120 = 0.625 A

Total current frying pan= (15 + 11.67 + 0.625) = 27.295 A

Electric current refers to the float of electricity in an electronic circuit, and to the amount of strength flowing via a circuit. it is measured in amperes (A). the bigger the price in amperes, the greater electricity is flowing inside the circuit.

The current is the charge of glide of price across a cross-segment every day to the direction of the float of the current. The S.I. unit of modern is coulomb consistent with 2d which is called ampere and denoted by means of A.

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The magnitude and direction of the net force are:

A: the net force is 3N in the downward direction,

B: the net force is zero,

C: The net force is 5N in the downward direction,

D: The net force is 4N in the right direction.

The net force of an object can be described as the vector sum of all the forces acting on an object. The net force is a single force that shows the same effect as the original forces on the particle's motion.

The net force becomes the resultant force. The net force has the same effect on the rotational motion as all original forces together by the object.

The mathematical expression can be written for the net force as:

[tex]\vec F_{net} = \vec F_{x} + \vec F_{y}[/tex]

For figure (A), the net force is equal to :

F = (2N - 2N) + (2N - 5N) = - 3N

So the magnitude of the force is 3N in the downward direction.

For figure (B), the net force is equal to :

F = (2N - 2N) + (5N - 5N) =  0

So the magnitude of the net force is equal to zero.

For figure (C), the net force is equal to :

F = (5N - 5N) + (5 N) = 5 N

So the magnitude of the net force is 5N in the downward direction.

For figure (D), the net force is equal to :

F = (2N - 2N) + (7N - 3N) = 4N

So the magnitude of the net force is 4N towards the right direction.

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a) The amount of work done is equal to the amount of energy used.

b) Power is the rate of energy use/work done .

c) The greater the work done. The greater the power needed.

d)  The two factors that affect the amount of work done are force and displacement .

 Energy is the ability to perform work. Work and energy are related in that an increase in work results in an increase in energy, and vice versa. Power is defined as the rate at which work is completed or the amount of work completed per unit of time. Power is also defined as the rate at which  energy is supplied to the system.

Power depends mainly on the amount of work done as well as the time  taken by the body to perform the work.

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The cat will have slipped till the distance of 9.90 seconds in 3 seconds.

The acceleration of the cat is 2.2m/s², the initial velocity of the cat is 0m/s and the time take the cat takes to come down is 3 seconds.

Now, using equation of motion,

S = Ut + 1/2at²

Where,

U is initial velocity of the body,

t is the time period of the body,

S is the displacement of the body,

a is the acceleration of the body.

Putting all the values,

S = 1/2at²

S = 1/2(2.2)(3)²

S = 9.90 meters.

The distance to which the cat will fall is 9.90 meters.

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Answer:

F=ma

F=6kg×5m/s^2

F=30kgm/s^2

F=30newton

A car with a mass of 1,060.0 kg accelerates from 0 to 88.0 km/h in 10.0 sec .The net force (in n) on the car during its deceleration is F = 7812.5 N.

Given

m= 1000 kg

u= 0 m/s

V = 90 km/h = 25m/s

t = 10 sec

a)by equation of motion :

v = u+at

25 = 0+ ax10

a = 2.5 m/c2

( b )By newton's law;

F= m*a

F=100X 2.5

F =2500N

( C )

u= 25m/s

V = 0

S = 40m

by equation of motion ;

v² = u²+2as

0=25²+80a

a=-7.8125 m/s²

by newton's law

F= m*a

F= 1000X 7.8125

F = 7812. 5N

A higher level motion control operation than velocity control is the control of acceleration and deceleration. Given that torque is the result of inertia and rate of altered speed, the system's forces will be affected by the rate of acceleration or deceleration. Any force calculation of this kind must take into account the actuator's or motor's inertia because it can significantly affect the torque needed. Control performance will also be impacted by the acceleration or deceleration profiles used. A motor needs linear acceleration in order to transition smoothly from one velocity to the next until the desired speed is reached. The rates of change, on the other hand, depend on both position and velocity when acceleration follows a non-linear, curved profile.

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The speed with which they threw the bundle is  14 m/s.

We know that the speed of the bundle can be obtained from the use of the equations of kinematics. Now we can use the equation of the upward motion under gravity here.

Using;

v^2 = u^2 - 2gh

v = final velocity

u = initial velocity

g = acceleration due to gravity

h = height

Now;

v = 0 m/s at the maximum height

u^2 = 2gh

We now have;

u = √2gh

u = √ 2 * 9.8 * 10

u = 14 m/s

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The final speed of the rocket, given it started with a speed of 120 m/s and slows down at a rate of 22 m/s² for 4 seconds is 208 m/s

From the question given above, the following parameters were obtained:

The final speed of the rocket can be obtained as follow:

v = u + at

v = 120 + (22 × 4)

Clear bracket

v = 120 + 88

v = 208 m/s

Thus, we can conclude from the calculation above that the final speed of the rocket is 208 m/s

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The orbital speed of the second satellite with same centripetal force is 2.1 x 10⁴ m/s.

We need to know about centripetal force to solve this problem. The centripetal force is a force caused by moving objects in a circular motion. The magnitude of the centripetal force depends on tangential speed, mass and radius. It can be written as

Fc = m . v² / r

where Fc is the centripetal force, m is mass, v is tangential speed and r is the radius.

From the question above, we know that

Fc 1 = Fc 2 = Fc

m1 = m2 = m

v1 = 1.31 x 10⁴ m/s

r1 = 3.88 x 10⁶ m

r2 = 9.96 x 10⁶ m

Hence, the ratio of centripetal force is

Fc2 / Fc1 = (m2 . v2² / r2) / (m1 . v1² / r1)

v1² / r1 = v2² / r2

(1.31 x 10⁴)² / 3.88 x 10⁶ = v2² / 9.96 x 10⁶

v2² = 4.41 x 10⁸

v2 = 2.1 x 10⁴ m/s

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The components of the final displacement (in m), from  the initial to final point, along the north and west directions is given as:

88m west and 50m north

The displacement of an object is a vector whose length is the shortest distance from the initial to the final position of a point P undergoing motion.

we will find the components of each vector in x and y:

For Vector 1:

Fx = 52m

Fy = 0m

for  Vector 2:

Fx = 40m*cos31.1

Fy = 40m * cos 31.1

For  Vector 3:

Fx = 0m

Fy = 25m

we will then find the components of the final displacement acting in x and y:

For west direction:

Rx = 52m + 40m*cos31.1 + 0

Rx = 90m

For north direction:

Ry = 0 + 40m*sin31.1 + 25m

Ry = 12m.

In conclusion, displacement is a vector quantity that refers to how far out of place an object is. Displacement is known to be  the object's overall change in position.

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Knowing only this information, the kinematic variable we can calculate is  Vavg = 6.3 m/s. Option B - average velocity

velocity is the directional velocity of an object in movement as an illustration of its rate of trade in function as found from a selected body of reference and as measured by means of a specific standard of time.

The average velocity is defined because of the alternate in function or displacement (∆x) divided by the point durations (∆t) in which the displacement takes place. The common pace may be tremendous or negative relying upon the sign of the displacement.

As it is given that the player is not moving in a straight line then distance and Displacement will not same.

We know average velocity is the ratio of total displacement to the time and if both are known then it can find easily.

Hence average speed can't be found

Vavg = 63/(60-50)  m/s

Vavg = 6.3 m/s

Instantaneous velocity is the velocity at a certain point of time that can't be found because there is only given initial &  final locations

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The magnitude of the resulting spring force when the material is stretched from its equilibrium position is -0.02522 N.

The spring force is a spring or a stretchy material is given by the formula,

F = -1/2Kx²

Where z

F is the spring force,

K is the spring constant,

x is the compression or extension in the material,

The negative sign represent that the force is restoring in nature.

We know, in our case,

The extension in the material is 2.71cm.

1 cm = 1/100m

So,

2.71 cm = 2.71/100m

The spring constant is 68.7N/m.

Now, putting all the values,

F = 1/2Kx²

F = -1/2(68.6)(2.71/100)²

F = -0.02522N.

So, the spring force is 0.02522N.

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The velocity of the car is 46.48 m/s.

What is velocity?

velocity is directional speed of a object in motion as an induction of it's rate of change in position observed from a particular frame of reference and as measured by a particular standard of time.

Sol- The linear momentum of a body is defined as the product of its mass and its velocity, given by-

P = mv

According to the question the momentum of the truck is-

Pr=2250×25 kgm /s

Pr=56250 kgm/s

Now we can see the momentum of the car and the truck must be same that is Pc=Pr

1210×v =56250 kgm/s

v= 56250/1210

v= 46.48 m/s

Thus the velocity of the car is 46.48m/s .

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Formulas for projectile motion:

Maximum height of projectile, h = [tex](u sin(\alpha )^{2}[/tex] / 2g

Horizontal range of projectile, R = [tex]u^{2}[/tex] sin(2α) / g

where u is the initial velocity, α is the angle of projection, and g is the acceleration due to gravity.

Given:

Angle of projection, α = 64°

Maximum height of projectile, h = 34 m.

To find: Initial velocity (u), and horizontal distance travelled (R).

Rearrange 'h' equation for 'u',

u sin(α) = [tex]\sqrt{2gh}[/tex]

⇒ u = [tex]\frac{\sqrt{2gh} }{sin(\alpha )}[/tex]

Substitute given values.

⇒ u = [tex]\sqrt{2*(9.8m/s^{2}*34m }[/tex] / sin(64°)

⇒ u = 25.81 / 0.899 m/s

∴ u = 28.71 m/s

This is the velocity with which the ball was thrown.

The distance travelled by the ball can be calculated by using the equation,

R = [tex]u^{2}[/tex] sin(2α) / g

Substitute the given values.

⇒ R = ([tex]28.71^{2}[/tex]× sin (2×64°)) / 9.8

⇒ R = 649.53 / 9.8

∴ R = 66.27 m.

This is the distance travelled by the ball.

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Wind speeds of above 56 kilometers per hour (35 miles per hour) are common during blizzards. These winds reduce visibility by causing a lot of snow to blow around in the air and close to the ground.

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A lighthouse is located on a small island 3 km away from the nearest point p on a straight shoreline is the beam of light moving along the shoreline when it is 1 km from p is 83.78 km/min

3*10/9*8pi = dx/dt

80pi/3 = dx/dt

dx/dt = 83.78 km/min

Thus, the beam of light is sweeping along the shore at the rate of 83.78 km/min when the beam is 1 km from the point P and light makes four revolutions per minute.

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As a result of the law of  conservation of momentum, the man will acquire a speed of 3 .  10⁻³ m/s

The law of conservation of momentum states thta:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Where:

u₁ , u₂ = initial velocity of object 1 and object 2

v₁ , v₂ = final velocity of object 1 and object 2

Since both the man and the shove are initially at rest, hence u₁ , u₂ = 0.

Therefore,

m₁v₁ + m₂v₂ = 0

Parameters given:

m₁ = 95 kg

m₂ = 74 gram =  74 . 10⁻³ kg

v₂ = 4 m/s

Plug these parameters into the equation:

95 . v₁ + 74 . 10⁻³ . 4 = 0

v₁ = 3 .  10⁻³ m/s

Hence, the man acquire a speed of 3 .  10⁻³ m/s, which is very small.

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Answer: D. 24.5 N

Explanation:

Fgrav = mg

Fgrav = 2.5(9.8)

Fgrav = 24.5 N

They will go off in opposite directions with the same force.

What is Newton's third law?

Newton's third law states that if object A exerts a force on object B, then object B must apply a force to object A that is equal in magnitude and directed in the opposite direction. This law illustrates a symmetry in nature whereby forces always occur in pairs and whereby no body can exert a force without also being subjected to one.

Newton's Third Law states that for every action, there is an equal but opposite reaction. If two people are standing on a scooter and push off each other (following the Law), it should come to the conclusion that they could go off in opposite with the same force.

Person is exiting for (describe in Newton's third law) against the wall that then has an effect on the person pushing them bac

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If a person standing on a scooter board pushes off of a wall, what happens? Can this

situation be explained in terms of Newton's Third Law (action-reaction)?

The equation for calculating the electrical force between two charges is: F = Kq₁q₂ / d²

Considering the options given in the question, we can obtain the equation for calculating electrical force as shown.

Coulomb's law states as follow:

F = Kq₁q₂ / d²

Where

With the above equation, we can easily determine the force between two charges.

For example find the force between two charges of charge 1 C and 2 C which are 1.5 m apart.

We can obtain the force as follow:

F = Kq₁q₂ / d²

F = (9×10⁹ × 1 × 2) / (1.5)²

F = 18×10⁹ / 2.25

F = 8×10⁹ N

Thus, we can see clearly that the equation F = Kq₁q₂ / d² can be use to calculate the force between t two charges.

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Two protons and two neutrons are both present in the particle that an unstable nucleus releases.

The nuclear process known as  "alpha decay" results in the parent nucleus emitting an alpha particle. The alpha particle, represented by the Greek letter and physically similar to the helium atom's nucleus, is made up of two protons and two neutrons.

What statement about deterioration is true? It brings down the atomic number of the nuclide by 2. The daughter nuclide, which frequently doesn't undergo further decay since the parent nuclide is unstable, is created during radioactive decay.

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Velocity is the rate at which an object changes position.

___________________________________________

Velocity is a vector quantity that refers to "the rate at which an object changes its position."

Hope this helps!

Want to learn more? Visit below for more information about velocity.

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The Time it takes a signal to travel the length of the cable of 12 km if the speed of light in the cable and the vacuum are the same is  4×10⁻⁵ s.

Time is the measured or measurable period during which an action, process, or condition exists or continues.

To calculate how long it will take a signal to travel a distance the same as the lenght of the cable, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the time its takes a signal to travel the length of the cable is 4×10⁻⁵ s.

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The vertical component of the velocity after the given interval of time will be:

B: -9.8 m/s

D: -19.6 m/s

F: -29.4 m/s

H: -39.2 m/s

A projectile can be described as any object upon which the only force is gravity. The projectile travels with a parabolic trajectory because of the influence of gravity. No horizontal forces are acting upon projectiles so there is no horizontal acceleration.

The horizontal velocity of a projectile is constant and the vertical acceleration is caused by gravity. The vertical component of the velocity of a projectile changes by 9.8 m/s each second while the horizontal motion of a projectile is independent of its vertical motion.

Given, the initial horizontal velocity, vₓ = 18 m/s

The initial vertical velocity, Vy = 0 m/s

The time interval = 1 sec

The vertical component of the velocity is calculated as;

[tex]V_y = V_{0y} -gt[/tex]

[tex]V_y = 0- (9.8) (1)\\V_y = -9.8 m/s[/tex]

The vertical component when t = 2 sec and horizontal velocity, Vx = 18 m/s

[tex]V_y = 0- (9.8) (2)\\V_y = -19.6 m/s[/tex]

The vertical component of velocity when t = 3sec:

[tex]V_y = 0- (9.8) (3)\\V_y = -29.4 m/s[/tex]

The vertical component of velocity when t = 4sec:

[tex]V_y = 0- (9.8) (4)\\V_y = -39.2 m/s[/tex]

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For the same spring, the value of spring constant must be same. The relation between the force and the spring constant is given by Hooke's law

so,  20 N force stretch 4 cm.

For the same spring, the value of spring constant must be same. The relation between the force and the spring constant is given by Hooke's law as :

F=kx

where

F = Force

k = is spring

constant  

x = stretches

here

10/ 2 = 20/ x

x -= 4 cm .

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In consideration of Henry's law the molar mass of organic compound is 0.24 grams.

What is molar mass?

The mass of a sample of a chemical compound divided by the quantity, or number of moles in the sample, measured in moles, is known as the molar mass of that compound. What is the mass of water in grammes and how much Equis paper with a 12.5% sodium chloride content weighs at 55 degrees Celsius, according to Sol-One of three? His issue informs us that pure water has a specific gravity of 118 torr at 55 degrees Celsius. Therefore, the first task at hand is to determine the mole fraction of, I suppose, the thermal fractions of both water and sodium chloride.

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Since the magnetic force and velocity are orthogonal, the velocity only changes in direction but not in magnitude . Circular motion is the end consequence. The force is in the opposite direction from the right-hand rule and has a negative charge.

Uniform In circular motion, an object moves in two dimensions with a constant speed in a fixed circular direction; however, because the object's direction changes at every point, the velocity also changes, and the direction at each point is always the tangent.

In physics, magnetic force is referred to as an object's maximal size and direction. Both vector and scalar values use magnetic force as a common factor. We understand that by definition

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Answer: The velocity simply changes in direction, not magnitude, as the magnetic force and velocity are orthogonal.

Explanation: The velocity simply changes in direction, not magnitude, as the magnetic force and velocity are orthogonal. The resultant motion is circular. The force has a negative charge and is directed in the opposite direction from the right-hand rule.

Uniform In a circular motion, an item moves in two dimensions with a constant speed in a fixed circular direction; yet, because the object's direction varies at each point, the velocity also alters, and the direction at each point is consistently the tangent.

As an object's maximum size and direction, the magnetic force is referred to in physics. Magnetic force is a factor that is present in both scalar and vector values. We comprehend that by nature.

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The root square method of the gas at 273 K is given as 493.15 for N2 and 461.3 for O2

We have to know that the root square method is dependent on the direct proportionality to the square root of absolute temperature as well as inverse of molar mass.

We have 1 j = 1 kgm²/s²

Vrms = √3rt/Mm

R = gas constant

T = temperature = 273

Mm is the molar mass

The molar mass of N₂ is = 0.02800 kg / mol

The mo;lar mass of o₂ = 0.03200 kg / mol

We have to solve first for N₂

= √3 (8.32447 * 273 / 0.028000

= √243,198.247

= 493.15

For 02

Vrms = √3 * 8.31447 * 273  / 0.03200

= √212798.466

= 461.3

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